Answer:
A flat/rung raise.
Explanation:
who designs each page or screen with which a user interacts?
Answer:
UI Design
Explanation:
1. A composite with uni-directional fiber reinforcement is made using two unknown constituent materials, Material A which is the fiber and Material B which is the matrix. The elastic modulus of Material A is 150 GPa and the elastic modulus of Material B is 10 GPa. If Material A is 40 % of the overall composite by volume, determine
Answer:
If a gpa a 2.2 that bad
Explanation:
technician a says an intake manifold vacuum leak may cause a high idle speed. technician b says a dirty iac bypass passage will not cause the idle speed to be below specifications. who is correct?
According to the given statement, technician A says that an intake manifold vacuum leak may cause a high idle speed. Technician B says that a dirty IAC bypass passage will not cause the idle speed to be below specifications.
Determine the opinionsWe have to determine who is correct.According to the given statement, technician A is correct. An intake manifold vacuum leak will cause high idle speed. The vacuum leak disrupts the airflow signal that the Powertrain
Control Module (PCM) uses to regulate idle speed. Furthermore, vacuum leaks can cause excessive crankcase ventilation, which can cause fuel dilution and other issues. Technician B is incorrect. The IAC bypass passage regulates idle speed by diverting air around the throttle plate.
A dirty or clogged IAC bypass passage may disrupt the airflow that the PCM uses to regulate idle speed, causing it to be outside of specifications. Thus, we can conclude that only technician A is correct.
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According to a recent study quoted in the textbook, __________________ were the number one skill(s) that college graduates found useful in the business world. Group of answer choices
Answer: According to a recent study quoted in the textbook, communication and interpersonal skills were the number one skill(s) that college graduates found useful in the business world.
Explanation:
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Answer:
thats a really cool design or whatever you got there.
Explanation:
niceeeeeeee :)
What is computer programming
Answer:
Computer programming is where you learn and see how computers work. People do this for a living as a job, if you get really good at it you will soon be able to program/ create a computer.
Explanation:
Hope dis helps! :)
2.24 Carbon dioxide (CO2) gas in a piston-cylinder assembly undergoes three processes in series that begin and end at the same state (a cycle). Process 1-2: Expansion from state 1 where p1 = 10 bar, V1 = 1 m3, to state 2 where V2 = 4 m3. During the process, pressure and pV1.5 volume are related by = constant. Process 2-3: Constant volume heating to state 3 where p3 = 10 bar. Process 3-1: Constant pressure compression to state 1. Sketch the processes on p –V coordinates and evaluate the work for each process, in kJ. What is the net work for the cycle, in kJ?
Answer:
Explanation:
Given that:
From process 1 → 2
\(P_1 = 10 bar \\ \\ V_1 = 1 m^3 \\ \\ V_2 = 4 m^3\)
\(PV^{1.5} = \ constant\)
\(\gamma = 1.5\)
Process 2 → 3
The volume is constant i.e \(V_2 =V_3 = 4m^3\)
\(P_3 = 10 \ bar\)
Process 3 → 1
P = constant i.e the compression from state 1
Now, to start with 1 → 2
\(P_1V_1^{1.5} = P_2V_2^{1.5}\)
\(P_2 = P_1 (\dfrac{V_1}{V_2})^{1.5}\)
\(P_2 = 10 \times (\dfrac{1}{4})^{1.5}\)
\(P_2 =1.25\)
The work-done for the process 1 → 2 through adiabatic expansion is:
\(W = \dfrac{1}{1-\gamma}[P_2V_2-P_1V_1]\)
We know that 1 bar = \(10^5 \ N/m^2\)
∴
\(W = \dfrac{1}{1-1.5}[1.25 \times 10^5 \times 4- 10 \times 10^5 \times 1]\)
\(W =1000000 \ J\)
\(W_{1 \to 2} = 1000 kJ\)
For process 2 → 3
Since V is constant
Thus:
W = PΔV = 0
\(W_{2 \to 3} = 0\)
For process 3 → 1
W = PΔV
\(W _{3 \to 1} = P_3(V_1-V_3)\)
\(W _{3 \to 1} = 10 \times 10^5 (1-4)\)
\(W _{3 \to 1} = 10 \times 10^5 (-3)\)
\(W _{3 \to 1} = -3 \times 10^6 \ J\)
\(W _{3 \to 1} = -3000 \ kJ\)
The net work-done now for the entire system is :
\(W_{net} = W_{1 \to 2} + W_{2 \to 3 } + W_{ 3 \to 1 }\)
\(W_{net} = (1000 + 0 + (-3000)) \ kJ\)
\(W_{net} =-2000 \ kJ\)
The sketch of the processes on p -V coordinates can be found in the image attached below.
A) The work done for each process are :
Process (1 - 2) = 1000 kJ Process (2 - 3) = 0 kJ process (3 - 1) = -3000 kJB) The net work for the cycle = -2000 kJ
Given Data :
For process (1 -2) For process ( 2 - 3 ) process ( 3 - 1 )
P₁ = 10 bar P₃ = 10 bar constant pressure compression
V₁ = 1 m³ constant volume heating
V₂ = 4 m³
PV\(^{1.5}\) = constant
A) Determine work done for each process
Calculate work done for process (1 - 2)
W₁ ₋ ₂ = \(\frac{P_{1}V_{1} - P_{2}V_{2} }{n -1 }\) * 100
= [ ( 10*1 ) - ( 1.25 * 4 ) ] / 1.5 - 1
= [ 10 - 5 ] / 0.5
= 10 * 100 = 1000 kJ
Calculate work done for process ( 2-3 )
given that there is constant volume heating
W₂₋₃ = 0 kJ
Calculate work done for process ( 3-1)
W₃₋₁ = P ( Δ V ) given that p = constant
= 10 * 100 ( -3 )
= - 3000 kJ
B) The net work for the cycle
W₁ ₋ ₂ + W₂₋₃ + W₃₋₁
= 1000 kJ + 0 kJ + - 3000 kJ
= - 2000 kJ
Hence we can conclude that the ) The work done for each process are :
Process (1 - 2) = 1000 kJ Process (2 - 3) = 0 kJ process (3 - 1) = -3000 kJand The net work for the cycle = -2000 kJ
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Attached below is the P-V sketch of the process
A Specimen made from a brittie material with a cross-section area of 0.004m was gradually loaded in tonsion until it yielded at a land of 280 KN and fractured Slightly after the yield point. If the specimon's material observed slashert clashe deformation until fracture, determine the material's toughness in terms of energy cidsor bed, in kj. Take E = 200 Gpa.
Answer:
the material's toughness, in terms of energy absorbed until fracture, is 98 kJ.
Explanation:
Step 1: Calculate the strain at the yield point:
Given that the cross-sectional area of the specimen is 0.004 m², and it yielded at a load of 280 kN (280,000 N), we can calculate the stress at the yield point:
Stress = Load / Cross-sectional area
Stress = 280,000 N / 0.004 m²
Stress = 70,000,000 N/m² (or Pa)
Using Hooke's Law, we know that stress is equal to the modulus of elasticity (E) multiplied by the strain (ε) at the yield point:
Stress = E * Strain
70,000,000 N/m² = 200,000,000,000 N/m² * Strain (converting E from GPa to N/m²)
Strain = 70,000,000 / 200,000,000,000
Strain = 0.00035
Step 2: Calculate the strain energy up to the yield point:
Strain energy (U) = (1/2) * Stress * Strain * Volume
We can assume that the volume remains constant during the test, so:
Strain energy (U) = (1/2) * Stress * Strain * Cross-sectional area * Length
For simplicity, let's assume the length of the specimen is 1 meter (this assumption won't affect the toughness calculation since it is based on energy per unit volume). Substituting the values:
Strain energy (U) = (1/2) * 70,000,000 N/m² * 0.00035 * 0.004 m² * 1 m
Strain energy (U) = 98,000 J (Joules)
Step 3: Convert the strain energy to kilojoules (kJ):
Toughness = Strain energy / 1000
Toughness = 98,000 J / 1000
Toughness = 98 kJ
In developing engine designs, manufacturers use thermocouples to measure the ___________ of components, such as spark plugs and exhaust systems.
Answer: High temperatures
An aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 30 . It has been determined that fracture results at a stress of 237 MPa when the maximum (or critical) internal crack length is 2.78 mm. a) Determine the value of for this same component and alloy at a stress level of 355 MPa when the maximum internal crack length is 1.39 mm.
Answer:
fracture will occur since ( 31.8 Mpa√m ) is greater than the \(K_{Ic\) of the material ( 30 Mpa√m )
Explanation:
Given the data in the question;
To determine whether the aircraft component will fracture, given a fracture toughness of 30 Mpa√m, stress level of 355 and maximum internal crack length of 1.39 mm.
On a similar component, it has been said that fracture results at a stress of 237 MPa when the maximum (or critical) internal crack length is 2.78 mm.
so we first of all solve for the parameter Y in the condition where fracture occurred.
\(K_{Ic\) = 30 Mpa√m
σ = 237 MPa
2α = 2.78 mm = 2.78 × 10⁻³ m
so
Y = \(K_{Ic\) / σ√πα
we substitute
Y = (30 Mpa√m) / (237 MPa)√(π(2.78 × 10⁻³ m / 2 ) )
Y = (30 Mpa) / (237)( 0.06608187 )
Y = 30 / 15.6614
Y = 1.9155
Next we solve for Yσ√πα for the second case;
σ = 355 Mpa, 2α = 1.39 mm = 1.39 × 10⁻³ m
so
Yσ√πα = 1.9155 × 355 Mpa × √( π × (1.39 × 10⁻³ m / 2) )
= 1.9155 × 355 × 0.0467269
= 31.8 Mpa√m
so
( 31.8 Mpa√m ) > \(K_{Ic\) ( 30 Mpa√m )
Therefore, fracture will occur since ( 31.8 Mpa√m ) is greater than the \(K_{Ic\) of the material ( 30 Mpa√m )
pls help me it’s due today
Answer:
C. 14.55
Explanation:
12 x 10 = 120
120 divded by 10 is 12
so now we do the left side
7 x 3 = 21 divded by 10 is 2
so now we have 14
and the remaning area is 0.55
so 14.55
What are the main microsoft ware packages widely used today
Answer:
» Microsoft word ( word processing )
» Microsoft powerpoint ( presentation )
» Microsoft access ( database mamagement )
» Microsoft excel ( spread sheets )
Explanation:
\(.\)
Answer:
Microsoft Teams.
Word.
Excel.
PowerPoint.
Outlook.
OneNote.
OneDrive.
nearly all technology cycles follow a bell-shaped pattern of innovation. true or false
The given statement "Nearly all technology cycles follow a bell-shaped pattern of innovation, known as the technology S-curve, where there is a slow start, rapid growth, and eventual saturation as the technology becomes widely adopted." is true because the innovation now use bell-shaped pattern.
Nearly all technology cycles follow a bell-shaped pattern of innovation, also known as the technology adoption life cycle. This pattern describes the way in which a new technology is introduced, adopted, and eventually replaced by newer technology over time.
The bell-shaped curve consists of five stages: innovators, early adopters, early majority, late majority, and laggards. Each stage is characterized by different levels of adoption and diffusion of the technology.
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The load on a bolt consists of an axial pull of 10 KN together with a transverse shear force of 5 KN. Find the diameter of bolt required according to I. Maximum principal stress theory; 2. Maximum shear stress theory; 3. Maximum principal strain theory, 4. Maximum strain energy theory, and 5 Maximum distortion energy theory. Take permissible tensile stress at elastic limit = 100 MPa and poisson's ratio = 0.3
Answer:
hey. its a big question. solved from *c hegg
Explanation:
Which of the following is a problem that can occur when using an induction coil to harden parts?
O Frictional heat
O Hydrogen embrittlement
Residual stress
Shifting position
Answer:
I would pick last or first.
I'M SO SO SORRY F IT WRONG!!
A problem that can occur when using an induction coil to harden parts is known as Residual stress. Thus, the correct option for this question is C.
What is an Induction coil?An induction coil may be defined as a kind of electrical transformer that is utilized in order to manufacture high-voltage pulses from a low-voltage direct current (DC) supply. It is also known as a spark coil.
An induction coil is a type of electrical device which is significantly used for generating an intermittent source of high voltage through the direct current. When this approach is applied for hardening parts, a problem may occur which is demonstrating the residual stress on the parts which are usually hardened via induction coil.
Therefore, a problem that can occur when using an induction coil to harden parts is known as Residual stress. Thus, the correct option for this question is C.
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The three balls each weigh 0.5 lb and have a coefficient of restitution of e = 0.85. (Figure 1) If ball A is released from rest and strikes ball B and then ball B strikes ball C, determine the velocity of each ball after the second collision has occurred. The balls slide without friction. Assume rightward direction is positive. Express your answers using three significant figures separated by commas.
To determine the velocity of each ball after the second collision has occurred, we'll first analyze the two collisions separately using the conservation of momentum and the given coefficient of restitution (e = 0.85). The masses of the balls are the same (0.5 lb), so we'll use m for their masses. Let's denote the velocities after each collision as vA1, vB1 for the first collision, and vA2, vB2, vC2 for the second collision.
1. Collision between ball A and ball B:
Before the collision:
- Ball A has an initial velocity (vA0) and ball B is at rest (vB0 = 0).
Using the conservation of momentum: m*vA0 = m*vA1 + m*vB1
Coefficient of restitution equation: e = (vB1 - vA1) / (vA0 - 0)
Solve these equations for vA1 and vB1.
2. Collision between ball B and ball C:
Before the collision:
- Ball B has velocity vB1 (calculated earlier) and ball C is at rest (vC0 = 0).
Using the conservation of momentum: m*vB1 = m*vB2 + m*vC2
Coefficient of restitution equation: e = (vC2 - vB2) / (vB1 - 0)
Solve these equations for vB2 and vC2.
3. Combine the results:
After both collisions, ball A will have a velocity of vA1, ball B will have a velocity of vB2, and ball C will have a velocity of vC2. Express your final answer with three significant figures separated by commas.
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Define:
a) Saturated liquid
b) Saturated steam
c) Overheated steam
d) Compressed liquid
e) Critical point
What are the aims of milling in a metallurgical plant
The aims of milling in a metallurgical plant include getting the refined form of the metals for easy use.
What are the aims of milling?Milling is the process by which the non-useful parts of metals are cut away in order to make them useful. Milling is important because it is a step in the refining process that gets the metals in the best shape and form for use.
Miling will ensure that iron ores and other gold extracts from the ground are cleaned up and ready for use in order advanced settings. So, these are the aims of milling in a metallurgical plant.
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1. The amount of friction developed between two
moving parts depends on all of the following factors,
except:
(A) the type of material.
(B) surface finish.
(C) pressure between moving parts.
(D) color pigment found in the parts.
The amount of friction developed between two moving parts depends on all of the following factors, except the color pigment found in the parts.
What is friction?
The force that stops solid surfaces, fluid layers, and material elements from sliding against one another is known as friction. There are various kinds of friction: Dry friction is the force that opposes the relative lateral motion of two in touch solid surfaces. Dry friction is classified as static friction between stationary surfaces and kinetic friction between moving surfaces. Dry friction, with the exception of atom or molecular friction, is caused by the interaction of surface characteristics known as asperities. Fluid friction is the friction that occurs between moving layers of a viscous fluid.
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12. You need to be at the lift controls whenever the lift is in motion A) True B)False
the answer to that would be a) true
Suppose that, instead of the Coulomb force law, one found experimentally that the force
between any two charges q1 and q2 was
Coulomb's law states that an electric field's magnitude is given by the formula E=F/q. where q is the electric charge and F is the Coulombs force applied to the charge. E = F/q = (KQq)/r2q Thus, E=KQ/r2
How does the electrostatic force between the two point charges work? q1 q2 0?If q1q20, then there is an attraction between them since one of them is positively charged and the other is negatively charged.
If q1q2 0 and q1q2 0 what type of force exists between two charges q1 and q2?1 Response. There will be an electrical force of repulsion between q1 and q2 if q1q2 > 0, which indicates that both q1 and q2 are probably charged (either both positively charged or both negatively charged).
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D
Question 7
Commercial photographers attempt to produce images that will blend in and make little impact on
the public.
O True
False
1 pts
A
False. Commercial photographers attempt to produce images that will stand out and make a big impact on the public.
What is photographers?
A photographer often works as a freelancer, getting hired by different customers for specialised tasks. A client who hires a part-time or freelance photographer is expected to adhere to their every demand, as well as to put up a business strategy that makes options and price readily visible and understandable.
Photographers are in charge of the digital and physical development of their photos, as well as any or all editing that may be necessary. Simple cropping, adding/changing colours and shading, modifying sharpness and lighting, or deleting things to tidy up the image are all examples of editing techniques.
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Please Help will give 50 points and brainliest!!!
In a short outline, describe five important attributes, skills, talents, learning areas, or work activities of someone in a “considerable” or “extensive preparation” career (Job Zone Four or Five) in the Architecture and Construction career cluster.
Answer:
They have to make sure that the building is safe, appropriate for city conditions, they are very creative, they can build really well, and can be very focused.
The accuracy of a digital multimeter might be stated by the manufacturer as +0.5 % reading + 1 digit". explain Using numerical example, the meaning of that statement.
The accuracy of a digital multimeter might be stated by the manufacturer as +0.5 % reading + 1 digit".
What is digital multimeter?A digital multimeter has been known an instrument that has been used to measure a plethora of electrical settings. The multimeter able to read voltage, current, resistance, among others.
This allows the user to be able to make sure that the wiring of an object is done properly and will not lead to electrocution or a short circuit.The MIN/MAX feature of a digital multimeter is being used to evaluate an oxygen sensor.
Therefore, The accuracy of a digital multimeter might be stated by the manufacturer as +0.5 % reading + 1 digit".
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What kind of plan or development of road can be done to avoid traffic?
Answer: Breakdown Lanes
Reason: With breakdown lanes when a car needs to stop it can go to the backdown lane and fix its issue.
The end of the industrial robotic arm extends along the path (r = 2 + 2 cos (5t)) m. At the instant ( 0 = 0.8t ) radians. When the arm is located at (t = 0.85) second Determine the velocity and acceleration of the object A at this instant.
Answer:
v = 8.95 rad / s, a = 22.3 rad / s²
Explanation:
This is an exercise in kinematics, where we must use the definitions of velocity and acceleration
v = dr / dt
we perform the derivative
v = 0+ 2 (-sin 5t) 5
v = -10 sin 5t
we calculate for t = 0.85 t,
remember angles are in radians
v = -10 sin (5 0.85)
v = 8.95 rad / s
acceleration is defined by
a = dv / dt
we perform the derivatives
a = -10 (cos 5t) 5
a = - 50 cos 5t
we calculate for t = 0.85 s
a = -50 are (5 0.85)
a = 22.3 rad / s²
what is japan currently making with an electromagnet?
Japan's most recent development is the Linear High-Speed Train, which travels at extremely fast speeds thanks to electromagnetic fields.
Are there magnetic trains in Japan?Japan has led the world in advanced rail technology ever since the Shinkansen bullet train was invented in the 1960s. Japan's most recent development is the Linear High-Speed Train, which travels at extremely fast speeds thanks to electromagnetic fields. A test version of the new technology recently set a world record for a manned vehicle with a speed of 581 kilometers per hour, after fifty years of development.
A brand-new motor known as a superconducting linear motor powers the train. The idea behind this is that magnets work. You probably already know that a magnet's north and south poles attract one another, whereas two poles that are the same (north and north, or south and south) repel one another. Using the attracting and repelling forces generated by coils in the tracks and magnets inside the train, the new technology applies this principle to propel the train forward.
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List 10 uses for surveying in areas other than land surveying. Select all that apply. a. topographic surveying b. satellite surveying c. aerial surveying d. optical tooling e. marketing surveying f. control surveying g. as-built surveying h. statistical surveying i. telephone surveying j. construction surveying k. alignment surveying l. mine surveying m. solar surveying
Answer:
b. satellite surveying
c. aerial surveying
d. optical tooling
e. marketing surveying
f. control surveying
h. statistical surveying
i. telephone surveying
k. alignment surveying
l. mine surveying
m. solar surveying
Explanation:
A Survey is an act of examination of the features of a subject or material under consideration. Land surveying refers to the examination of the natural and man-made features of a piece of land using scientific and mathematical methods.
Land surveying finds application in construction where a survey is made on all the structures found in a constructed property. Topographic surveying deals with examining the natural and man-made feature of a piece of land. As-built survey as the name implies examines the features and location of a building during or recently after construction. These three are examples of land surveys.
Some type of surveying other than land surveying includes satellite, aerial, optical tooling, marketing, control surveying, statistical, telephone, alignment, mine, and solar surveying
A Survey means an examination of a features, subject or material under consideration.
Land surveying refers to the examination of the natural and man-made features of a piece of land using scientific and mathematical methods.
However, some other type of surveying other than land surveying includes satellite, aerial, optical tooling, marketing, control surveying, statistical, telephone, alignment, mine, and solar surveying.
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SN1 reactions usually proceed with ________. A) equal amounts of inversion and retention at the center undergoing substitution B) slightly more inversion than retention at the center undergoing substitution C) slightly more retention then inversion at the center undergoing substitution D) complete inversion at the center undergoing substitution E) complete retention at the center undergoing substitution complete retention at the center undergoing substitution slightly more retention then inversion at the center undergoing substitution complete inversion at the center undergoing substitution equal amounts of inversion and retention at the center undergoing substitution slightly more inversion than retention at the center undergoing substitution
Answer:
equal amounts of inversion and retention at the center undergoing substitution
Explanation:
In an SN1 reaction, the rate determining step is the formation of a carbonation which is flat and planar.
This means that both faces of the carbo cation are equally available for attack by the nucleophile.
Attack on either of the faces may occur equally thereby yielding a racemic mixture.
Starting the vehicle's engine and listening to its operation can
indicate a host of problems, from loose belts to worn main
bearings. True or false