Answer:
C
Explanation:
Winter in North
Summer in south
Two objects attract each other with a gravitational force of magnitude 1.00 3 1028 N when separated by 20.0 cm. If the total mass of the two objects is 5.00 kg, what is the mass of each
Answer:
The mass of each object is 2kg and 3 kg.
Explanation:
Given that,
Gravitational force,\(F=1\times 10^{-8}\ N\)
The distance between masses, d = 20 cm = 0.2 m
The total mass of the two objects, M + m = 5 kg
M = 5-m
The formula for the gravitational force is :
\(F=G\dfrac{Mm}{d^2}\\\\1\times 10^{-8}=6.67\times 10^{-11}\times \dfrac{(5-m)m}{(0.2)^2}\\\\\frac{1\times10^{-8}}{6.67\times10^{-11}}=\frac{(5-x)x}{(0.2)^{2}}\\\\\frac{1\times10^{-8}}{6.67\times10^{-11}}\cdot(0.2)^{2}\\\\5.99=(5-x)x\\\\x=2\ kg\ and\ 3 \ kg\)
So, the mass of each object is 2kg and 3 kg.
Callisto is a moon of Jupiter
(mass= 1.90 x 1027 kg), which orbits
the planet with a period of 16.9 days.
What is the radius of its orbit?
[?] x 10¹ m
Coefficient (green)
Exponent (yellow)
Enter
8.27 x 1013 meres is the orbital radius.
Additional details:-Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution
The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.
6.67 x 10⁻¹¹ N/m²kg
2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7
What distinguishes Callisto, a huge moon orbiting Jupiter, from all other large moons in the solar system?The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.
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A ball has the energy to move 30 m/s with the mass of 5. What is the energy
PIUDICITIS CONSECulvely and Circle your aliswers. Lilyo
proper significant digits.
53. When you turn on your CD player, the turntable accelerates from zero to 41.8 rad/s in
3.0 s. What is the angular acceleration?
or
Answer:
The angular acceleration of CD player is \(13.93\ rad/s^2\).
Explanation:
Initial angular speed of a CD player is 0 and final angular speed is 41.8 rad/s. Time to change the angular speed is 3 s.
It is required to find the angular acceleration. The change in angular speed of the CD player divided by time taken is called its angular acceleration. It can be given by :
\(a=\dfrac{\omega_f-\omega_i}{t}\\\\a=\dfrac{41.8-0}{3}\\\\a=13.94\ rad/s^2\)
So, the angular acceleration of CD player is \(13.93\ rad/s^2\).
A person is sitting at the very back of a canoe of length L, when the front just bumps into the dock. show answer No Attempt 50% Part (a) If the canoeist gets up and walks to the front of the canoe and there is no friction between the boat and the water, how far will they be from the dock
The distance of the canoeist from the dock is equal to length of the canoe, L.
Conservation of linear momentumThe principle of conservation of linear momentum states that the total momentum of an isolated system is always conserved.
v(m₁ + m₂) = m₁v₁ + m₂v₂
where;
v is the velocity of the canoeist and the canoe when they are together
u₁ is the velocity of the canoeu₂ velocity of the canoeistm₁ mass of the canoem₂ mass of the canoeistDistance traveled by the canoeistThe distance traveled by the canoeist from the back of the canoe to the front of the canoe is equal to the length of the canoe.
Thus, the distance of the canoeist from the dock is equal to length of the canoe, L.
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A cannon is evaluated at an angle of 45 degree. It fires a ball with a speed of 300 m/s. What is the horizontal range of the ball
Answer:
The horizontal range of the cannonball is 9180.4 meters.
Explanation:
The horizontal range of a cannonball can be calculated using the following formula:
range = (speed * speed * sin (2 * angle)) / acceleration due to gravity
In this case, we are given that the cannon is fired at an angle of 45 degrees and that the speed of the ball is 300 m/s. We can plug these values into the formula to calculate the horizontal range of the ball:
range = (300 * 300 * sin (2 * 45)) / 9.8
= (90000 * sin (90)) / 9.8
= (90000 * 1) / 9.8
= 9180.4 m
Which formula below correctly states Coulomb's Law?
A. F = kqq/r2
B. F = kqq/r
C. F = qq/kr2
D. F = kr2/qq
\(A. \: \: \: \: F = kqq/r^ 2 \\B. \: \: \: \: F = kqq/r \\C. \: \: \: \: F = qq/kr^ 2 \\D. \: \: \: \: F = kr^2 /qq \\ \)
ANSWER:-F is directly proportional to the product of the charges
\(F∝qq\)
F is inversely proportional to the square of the distance between them
\(F∝ \frac{1}{ {r}^{2} } \)
from above 2 equation:-
we get:-
\(F∝ \frac{qq}{ {r}^{2} } \)
To remove proportionality sign we use constant for this case we r using constant k
\(F = \frac{Kqq}{ {r}^{2} } \)
So your answer is :-
OPTION A.
\(F = \frac{Kqq}{ {r}^{2} } \)
Which gas in Earth's atmosphere has increased over time due to burning fossil fuels?
BER
oxygen
O nitrogen
water vapor
O carbon dioxide
Answer:
The carbon dioxide levels have increased due to burning fossil fuels
Explanation:
Correct on edge 2021 hope this helps!✌️
The gas in Earth's atmosphere that has increased over time due to burning fossil fuels is carbon dioxide.
What is meant by global warming ?Global warming is defined as the phenomenon of heating up of the earth's surface in a long term due to the increased amount of emission of green house gases in the earth's atmosphere.
Here,
When more fossil fuels and the materials like coal are burned for the purpose of energy production, it will result to the production of an increased amount of carbon dioxide. This leads to the emission of huge amount of carbon dioxide in the earth's atmosphere. Since, carbon dioxide is a green house gas, the release of higher amount of carbon dioxide will lead to an increased concentration of green house gases. This causes an increase in the temperature of the atmosphere, resulting in the increased heating of the surface of earth. This uneven heating up of earth's surface is called global warming. This is the result of higher release of carbon dioxide in the earth's atmosphere.
Hence,
The gas in Earth's atmosphere that has increased over time due to burning fossil fuels is carbon dioxide.
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As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air acts as an ideal gas, calculate the work done per mol of the air.
A. -80.35 J
B. 80.35 J
C. -811.93 J
D. 811.93 J
(please show calculation)
can use this formula W=nRT ln(p1/p2)
Answer:
B.-80.35 J
i dont know the calculation
Two equally charged, 3.33 g spheres are placed with 4.665 cm between their centers. When released, each begins to accelerate at 268.36 m/s2. What is the magnitude of the charge, in micro-Coulombs, on each sphere?
Given,
Mass of each sphere = m = 3.33g = 3.33 x 10^-3 kg
Distance between sphere = d = 4.665 cm = 4.665 x 10^2 cm
Acceleration = a = 268.36 m/s^2.
Force on the sphere is given by the below formula,
\(\begin{gathered} F=K\frac{(q1)(q2)}{d^2} \\ Where, \\ F=Force \\ K=Constant=9\times10^9\frac{Nm^2}{C^2} \\ q1=q2=q=Charge \\ d=Distance\text{ }between\text{ }spheres \end{gathered}\)\(\begin{gathered} We\text{ }can\text{ }write\text{ }Force\text{ }as, \\ F=ma \\ Where, \\ m=mass \\ a=acceleration \\ So, \\ F=ma=K\frac{(q1)(q2)}{d^2}=K\frac{q^2}{d^2} \\ \therefore q=d\sqrt[\placeholder{⬚}]{\frac{ma}{K}}=4.665\times10^{-2}\times\sqrt[\placeholder{⬚}]{\frac{3.33\times10^{-3}\times268.36}{9\times10^9}}=46.484\times10^{-8}C \\ \end{gathered}\)Result:- So the charge on the each sphere is 46.484 x 10^-8 C.
21. If € = 8.0 V, at what rate is the emf providing energy to the circuit shown?
15 2
10 22
12 V
+
1022.
a. 8.4 W
b. 7.6 W
C.5.6 W
d. 11 W
e. 2.0 W
Answer:
c. 5.6 W
Explanation:
We can write the Kirchoff's voltage law (KVL) equations for the circuit using i1 for the clockwise current in the left loop, and i2 for the clockwise current in the right loop. Then the circuit equations are ...
i1 (10 +10) -i2(10) = 12
-i1(10) +i2(10 +15) = 8
Using Cramer's rule to find i2, we have ...
i2 = (12(-10) -8(20))/((-10)(-10) -(25)(20)) = -280/-400 = 0.7
The power supplied by the Emf is ...
(8 V)(0.7 A) = 5.6 W . . . . . matches choice C
A uniform solid cylindrical log begins rolling without slipping down a ramp that rises 28.0° above the horizontal. After it has rolled 4.20 m along the ramp, what is the magnitude of the linear acceleration of its center of mass?
Answer:
3.07 m/s
Explanation:
Given:
Angle, \(\Theta = 28^{\circ}\)Length = 2.40 mThe acceleration of its center of mass will be:
= \(\frac{2}{3}g Sin \Theta\)
By putting the above given values, we get
= \(\frac{2}{3}\times 9.8 Sin 28^{\circ}\)
= \(\frac{2}{3}\times 9.8\times 0.46\)
= \(\frac{9.0167}{3}\)
= \(3.07 \ m/s^2\)
Thus the solution above is appropriate.
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which particles are elctrically neutral
Explanation:i think its nuetrons
if a 0.08kg cell phone falls of a table at 15 m/s then what is its kinetic energy right before it hits the ground?
The Kinetic energy of the cell phone of mass 0.08 kg is 9 J.
What is kinetic energy?Kinetic energy is the energy of a body in motion.
To calculate the kinetic energy of the cell phone, we use the formula below.
Formula:
K.E = mv²/2............. Equation 1Where:
K.E = Kinetic energy of the cell phonem = Mass of the cell phonev = Velocity of the cell phoneFrom the question,
Given:
m = 0.08 kgv = 15 m/sSubstitute these values into equation 1
K.E = 0.08×15²/2K.E = 9 JHence, the Kinetic energy of the cell phone is 9 J.
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A uniform door weighs 70.0 N and is 1.20 m wide and 2.60 m high. What is the magnitude of the torque due to the door’s own weight about a horizontal axis perpendicular to the door and passing through a corner?
Given,
The weight of the door, W=70.0 N
The height of the door, h=2.60 m
The width of the door, l=1.20 m
The torque is the product of the force and the distance between the axis and the point where the force is being applied.
The center of mass of the rectangle will be at its geometric center.
The distance between the horizontal axis passing through the corner of the door and the center of mass of the door is,
\(d=\sqrt[]{(\frac{h}{2})^2+(\frac{l}{2})^2}\)On substituting the known values,
\(\begin{gathered} d=\sqrt[]{(\frac{2.60}{2})^2+(\frac{1.20}{2})^2} \\ =1.43\text{ m} \end{gathered}\)Thus the required torque is given by,
\(\tau=Wd\)On substituting the known values,
\(\begin{gathered} \tau=70.0\times1.43 \\ =100.1\text{ Nm} \end{gathered}\)Thus the torque due to the door's own weight about a horizontal axis perpendicular to the door and passing through a corner is 100.1 Nm
identify a theorist, summarize their theory and explain the aspects of that theory thsat relate to the biological perspective
Answer:
the theorist that I chose is John Watson. He focused on the behaviors of a person on the outside. “He believed that a person’s physical responses provided the only insight into internal actions.”[ CITATION Goo15 \l 1033 ] He believed that behaviors are learned, as with the rat white and “Albert”. He taught “Albert” to fear the rat by making a sound any time the rat was shown. “Through learning, an initially neutral stimulus, the white rat, had become a stimulus for fear.”[CITATION Car17 \p 41 \l 1033
Explanation:
this is the answer
The biologist who had summarized the theory to explain the aspects of the theory is john watson.
Who was john watson?
John B. Watson was a trailblazing psychologist who made significant contributions to the growth of behaviorism. Watson thought that the main focus of psychology should be on observable behavior in science. He is famous for his studies on the process of conditioning.
Watson is particularly well-known for the Little Albert experiment, in which he showed how a young kid may be taught to fear a stimulus that was previously neutral. Additionally, his studies shown that this phobia might extend to other similar things.
Therefore, The biologist who had summarized the theory to explain the aspects of the theory is john watson.
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9kg-ball is moving at 12m/s. What is the kinetic energy from this motion?
Answer:
ke=648J
Explanation:
ke=1/2mv²
m=9kg
v=12m/s
1/2(9)(12)²
=648J
a plane wall is 250mm thick and it's wall area is 4.5m^2. if the thermal conductivity is 9.35w/m°c and surface temperature are steady at 150°c and 40°c. calculate the heat flow across the plane wall and the temperature gradient in the flow direction
The temperature gradient in the flow of direction is 294525 W.
What is Temperature gradient?A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.
Q= T/( L/ KA)
Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)
= 294525 W
Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.
Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.
Therefore, The temperature gradient in the flow of direction is 294525 W.
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An artillery shell is fired with an initial velocity of 300 m/s at 55.5° above the horizontal. To clear an avalanche, it explodes on a mountainside 47.0 s after firing. What are the x- and y-coordinates of the shell where it explodes, relative to its firing point?
The x-coordinate of the shell where it explodes, relative to its firing point, is approximately 7688.1 meters, and the y-coordinate is approximately 9507.8 meters.
Is initial velocity always 0?If an automobile is at rest, its beginning velocity is 0.The starting velocity of an automobile that stops after using the brakes will be greater than zero, but the ultimate velocity will be zero.
The kinematic equations of motion can be used to resolve this issue.We can break down the initial velocity into its x- and y-components:
Vx = V0 cosθ = (300 m/s) cos(55.5°) ≈ 163.3 m/s
Vy = V0 sinθ = (300 m/s) sin(55.5°) ≈ 247.2 m/s
Next, we can use the equations of motion to find the shell's position after 47.0 seconds. The x-coordinate is given by:
x = Vx t = (163.3 m/s)(47.0 s) ≈ 7688.1 m
The y-coordinate is given by:
y = Vy t + (1/2)gt²= (247.2 m/s)(47.0 s) + (1/2)(9.81 m/s²)(47.0 s) ≈ 9507.8 m
where g is the acceleration due to gravity.
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How much impulse is imparted on a 0.14 kg baseball initially traveling at 32 m/s when it is struck by a baseball bat and begins to travel in the opposite direction at 49 m/s
ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:
Impulse = Change in momentum
The momentum of an object is given by the product of its mass and velocity:
Momentum = mass × velocity
In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.
Therefore, the change in momentum is given by:
Change in momentum = (mass × final velocity) - (mass × initial velocity)
Change in momentum = mass × (final velocity - initial velocity)
Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))
Change in momentum = 0.14 kg × (49 m/s + 32 m/s)
Change in momentum = 0.14 kg × 81 m/s
Change in momentum = 11.34 kg·m/s
So, the impulse imparted on the baseball is 11.34 kg·m/s.
In the electric of capacitance 4 ,3 and 2 microfaradas, respectively, are connected in senes to a battery of 260 V , calculate the charge?
The total charge in the circuit is 240 microcoulombs.
To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.
In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.
To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.
Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.
Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.
Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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A package is dropped from an air balloon two times. In the first trial the distance between the balloon and the surface is Hand in the second trial 4H. Compare the FINAL VELOCITY'S for the packages right as they hit the
ground (or right before)?
Answer:
The final speed of the second package is twice as much as the final speed of the first package.
Explanation:
Free Fall Motion
If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:
\(v=gt\)
And the distance traveled downwards is:
\(\displaystyle y=\frac{gt^2}{2}\)
If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:
\(\displaystyle t=\sqrt{\frac{2y}{g}}\)
Replacing into the first equation:
\(\displaystyle v=g\sqrt{\frac{2y}{g}}\)
Rationalizing:
\(\displaystyle v=\sqrt{2gy}\)
Let's call v1 the final speed of the package dropped from a height H. Thus:
\(\displaystyle v_1=\sqrt{2gH}\)
Let v2 be the final speed of the package dropped from a height 4H. Thus:
\(\displaystyle v_2=\sqrt{2g(4H)}\)
Taking out the square root of 4:
\(\displaystyle v_2=2\sqrt{2gH}\)
Dividing v2/v1 we can compare the final speeds:
\(\displaystyle v_2/v_1=\frac{2\sqrt{2gH}}{\sqrt{2gH}}\)
Simplifying:
\(\displaystyle v_2/v_1=2\)
The final speed of the second package is twice as much as the final speed of the first package.
If you lift one load up one story, how much more work do you do lifting one load up
three stories?
Answer:
Explanation:
alot
What type of bone is the thigh
Answer:
hich graph represents this system?
y = 2 x + 1. y = negative 4 x + 7.
On a coordinate plane, a line goes through (0, 7) and (1, 3) and another goes through (1, 3) and (2, 5).
On a coordinate plane, a line goes through (negative 4, 0) and (0, 7) and another line goes through (negative 4, 3) and (0, 1).
On a coordinate plane, a line goes through (0, negative 4) and (1, 3) and another goes through (0, 2) and (1, 3).
On a coordinate plane, a line goes through (0, 7) and (8, 5) and another line goes through (0, 1) and (8, 5).
Explanation:
asdfgh
Answer:
the thigh bone is a femur
the femur is a long bone so therefore the type of bone is a long bone !
Explanation:
Please help I'm almost done.
Type the numerical answer only. No degree symbol or the word 'degree'. *
17. Find the m/B
Your answer
▸
A
75
B
No doorge symbol or the word 'degree'
C
Press Alt and 0176 on your keyboard. Please take note that this technique only functions on keyboard shortcut with a 10-key numeric pad.
What are keyboard shortcut?Using a keyboard shortcut, you can quickly insert the degree sign in Word documents if your keyboard has a number pad.To begin, position the cursor where you want the degree sign to appear on your page.After then, use your keyboard shortcut Alt+0176. Remember that while holding down the Alt key, you must enter the correct digits. To enter numbers instead of using the keys on your keyboard, use the numeric pad.Holding down the ALT key, type 0 1 7 6 on the numeric keypad of the keyboard. With NumLock turned on, enter 0176 with the leading zero. Hold down the NumLock key while starting to type the 0176 numbers if there isn't a numeric keypad.To learn more about keyboard shortcut from the given link
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A roller-coaster car with a mass of 900 kg starts at rest from a point 22 m above the ground. At point B, it is 8 m above the ground. [Express your answers in kilojoules (kJ).]
If the initial kinetic energy was zero and the work done against friction between the starting point and point B is 30,000 J (30 kJ), what is the kinetic energy of the car at point B?
Answer: 317.52
Explanation:
I'm just better
A 25kg ball is thrown into the air. When thrown it is going 10 m/s. Calculate how high it travels.
Answer:
5m
Explanation:This is the number
Nitroball is similar to volleyball with no more than 3 touches per side?
Group of answer choices
True
False
Answer:
True!
Explanation:
Prove the formular for calculating attraction
The formula for calculating attraction is F=GMmr².
Gravitational attractionGravitational attraction is the force of attraction that occurs on all bodies
which have a mass as a result of the force of gravitational force.
The Force is directly proportional to the product of their masses and
inversely proportional to the square of the distance between them.
Gravitational attraction = F=GMmr².
where F is the Force, G is gravitational constant, M and m are masses and r²
is square of the distance between the masses.
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