23. How many different outfits can be put together using 3 different pairs of pants, 2 shirts and 2 pairs of shoes
There are 12 different outfits that can be put together using the given 3 different pairs of pants, 2 shirts, and 2 pairs of shoes.
There are 12 different outfits that can be put together using 3 different pairs of pants, 2 shirts, and 2 pairs of shoes.
How to solve the problem:
To find out the number of different outfits that can be put together using the given 3 different pairs of pants, 2 shirts, and 2 pairs of shoes, we will simply multiply the number of options for each category together.
Number of options for pants = 3
Number of options for shirts = 2
Number of options for shoes = 2
Number of different outfits that can be put together
= 3 × 2 × 2
= 12
Therefore, there are 12 different outfits that can be put together using the given 3 different pairs of pants, 2 shirts, and 2 pairs of shoes.
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i am bad in fraction math. can you please help me. with proper explanation. Thank you!
Answer:
1 - 8/9 + 4/9 = 9/9 -8/9 +4/9 = (9-8+4)/9 = 5/9
Step-by-step explanation:
Answer:
The answer is 5/9.
Step-by-step explanation:
First, you have to make all the denorminator of the fractions the same by multultiplying :
\(1 - \frac{8}{9} + \frac{4}{9} \)
\( = \frac{1}{ 1} - \frac{8}{9} + \frac{4}{9} \)
\( = \frac{1 \times 9}{1 \times 9} - \frac{8}{9} + \frac{4}{9} \)
\( = \frac{9}{9} - \frac{8}{9} + \frac{4}{9} \)
Next, you have to make it into 1 fraction and simplify :
\( \frac{9}{9} - \frac{8}{9} + \frac{4}{9} \)
\( = \frac{9 - 8 + 4}{9} \)
\( = \frac{5}{9} \)
x2y4(x2 - 16) - 9y4(x4 - 16) how do i simply this?
Answer:
The simplified expression is given as
\(8x^2y^4(17x^2-2)\)
Step-by-step explanation:
step one:
Given the expression
\(x^2y^4(x^2 - 16) - 9y^4(x^4 - 16)\)
step two:
First, let us open the bracket we have
\(x^2y^4(x^2 - 16) - 9y^4(x^4 - 16)\\\\x^4y^4-16x^2y^4-9x^4y^4+144x^4y^4\\\\\)
step three:
collect like terms we have
\(x^4y^4-16x^2y^4-9x^4y^4+144x^4y^4\\\\x^4y^4-9x^4y^4+144x^4y^4-16x^2y^4\\\\-8x^4y^4+144x^4y^4-16x^2y^4\\\\136x^4y^4-16x^2y^4\\\\\\\)
step four:
we can now factor out \(8x^2y^4\)we have
\(8x^2y^4(17x^2-2)\)
Rick has 10 kids to babysit. If he gives each kid goldfish, He will have given out a total of
100 goldfish. How much goldfish did each kid get?
How do I convert this to an algebraic expression?
Answer:
10
Step-by-step explanation:
answer 10 10x10= 100 100/10=10
Claire has a hot tub with a diameter of 7 feet. She wants to purchase a cover to protect the hot tub. What is the area of the cover? Use Pi = 3. 14 and round the answer to the nearest square foot.
Answer:
38 square feet
Step-by-step explanation:
How do we find the area of a circle?
❖ The area of a circle is πr², where r = radius. For this case, we're going
to approximate pi as 3.14.
How do we find the radius given diameter?
❖ We are given the diameter of Claire's hot tub as 7 feet. The diameter
is 2x the radius, so we divide 7 by 2 to get the radius, which is 3.5
feet.
Solving
\(3.14*3.5^2\) \(3.14 *12.25\) \(38.465\) 38.465 ≈ 38Therefore, the answer is 38 square feet. Have a lovely rest of your day/night, and good luck with your assignments! ♡
10. Using the Maclaurin Series for ex (ex = 0 + En=ok" ) xn n! E a. What is the Taylor Polynomial T3(x) for ex centered at 0? b. Use T3(x) to find an approximate value of e.1 Use the Taylor Inequality
The Taylor Polynomial T3(x) for ex centered at 0 is 1 + x + x^2/2 + x^3/6. Using T3(x) to approximate the value of e results in e ≈ 2.333, with an error bound of |e - 2.333| ≤ 0.00875.
The Taylor Polynomial T3(x) for ex centered at 0 is found by substituting n = 0, 1, 2, and 3 into the formula for the Maclaurin Series of ex. This yields T3(x) = 1 + x + x^2/2 + x^3/6.
To use this polynomial to approximate the value of e, we substitute x = 1 into T3(x) and simplify to get T3(1) = 1 + 1 + 1/2 + 1/6 = 2 + 1/3. This gives an approximation for e of e ≈ 2.333.
To find the error bound for this approximation, we can use the Taylor Inequality with n = 3 and x = 1. This gives |e - 2.333| ≤ max|x| ≤ 1 |f^(4)(x)| / 4! where f(x) = ex and f^(4)(x) = ex. Substituting x = 1, we get |e - 2.333| ≤ e / 24 ≤ 0.00875. This means that the approximation e ≈ 2.333 is accurate to within 0.00875.
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Directions: Using the digits 0-9, no more than once each, fill in the boxes to make the statement true:
The equation \(\frac{5-3-2}{1+4+6+7+8+9}\) = 0 is true
What is fraction?
In arithmetic, a number expressed as a quotient, in which a numerator is divided by a denominator.
Using digits 0 to 9, no more than once each.
we want to place them in such a way that the division will be zero.
As we know that a quotient is equal to zero iff the numerator is equal to zero and the denominator other than zero.
So if we put some numbers on the numerator in such a way by adding them gives 0.
So, 5 - 3 - 2 = 0
Use all the other numbers in the denominator.
\(\frac{5-3-2}{1+4+6+7+8+9}\) = 0
which is true.
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a machine that drills holes for wells drilled to a depth of feet in one day ( hours). at this rate, how many hours will it take until the drill reaches its final depth of feet?
The number of hours it will take until the drill reaches its final depth of y feet would be (y * 24) / x.
To find the number of hours it will take for the drill to reach its final depth, we need to determine the drilling rate per hour.
Let's assume the drill can drill to a depth of x feet in one day (24 hours). Therefore, the drilling rate per hour would be:
Drilling rate per hour = Depth drilled in one day (feet) / Number of hours in one day
Now, we can calculate the drilling rate per hour:
Drilling rate per hour = x feet / 24 hours
To find the number of hours it will take to reach the final depth of y feet, we can set up the following proportion:
Drilling rate per hour = Depth drilled (feet) / Number of hours
We can rearrange this proportion to solve for the number of hours:
Number of hours = Depth drilled (feet) / Drilling rate per hour
Substituting the values we have:
Number of hours = y feet / (x feet / 24 hours)
Simplifying this expression:
Number of hours = (y * 24) / x
Therefore, the number of hours it will take until the drill reaches its final depth of y feet would be (y * 24) / x.
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two customers took out home equity loans.
Cathy took out a 10-year loan for $20,000 and paid %5.20 annual simple interest
Steven took out a 15-year loan for 20,000 and paid %4.80 annual simple interest
what is the difference that Cathy and Steven paid for their loans?
The difference in the amount paid by Cathy and Steven is $4000.
What is the difference in the amounts?
Simple interest is when the interest that is paid on the loan of a customer is a linear function of the loan amount, interest rate and the duration of the loan.
Simple interest = amount borrowed x interest rate x time
Simple interest of Cathy = $20,000 x 0.052 x 10 = $10,400
Simple interest of Steven = $20,000 x 0.048 x 15 = $14,400
Difference in interest = $14,400 - $10,400 = $4000
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pls i need help its 8952 divided by 3.2
Answer:
2797.5
Step-by-step explanation:
Nicole drove 275 miles in 5 hours. At the same rate, how long would it take her to drive 605 miles?
Answer:
i think its 12 hours
Step-by-step explanation:
use calculator
According to the graph, what is the factorization of x2 - 6x + 5?
A. (x + 5)(x+1)
B. (x - 5)(x+ 1)
C. (x - 5)(x - 1)
D. (x + 5)(x - 1)
The factorization of x2 - 6x + 5 is (x - 1)(x -5)
How to determine the factorization?From the graph, the zeros of the function are:
x = 1 and x = 5
Set the zeros to 0
x - 1 = 0 and x - 5 = 0
Multiply the zeros
(x - 1)(x -5) = 0
Hence, the factorization of x2 - 6x + 5 is (x - 1)(x -5)
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A house was valued at $110,000 in the year 1993. The value appreciated to $145,000 by the year
2006.
A) What was the annual growth rate between 1993 and 2006?
Round the growth rate to 4 decimal places.
7 =
B) What is the correct answer to part A written in percentage form?
7 =
%.
C) Assume that the house value continues to grow by the same percentage. What will the value
equal in the year 2010?
value = $
Round to the nearest thousand dollars.
The annual growth rate between 1993 and 2006 was 2.23%. If the house value continues to grow at the same rate, it will be worth approximately $161,000 in 2010.
A) The annual growth rate between 1993 and 2006 is 0.0223 or 2.23%.
B) The correct answer to part A in percentage form is 2.23%.
C) The value of the house in the year 2010 will be approximately $161,000.
A) To calculate the annual growth rate, use the formula: (final value / initial value)^(1/years) - 1
Step 1: Calculate the number of years: 2006 - 1993 = 13 years
Step 2: Calculate the growth rate: (145000 / 110000)^(1/13) - 1 = 0.0223
B) Convert the growth rate to percentage: 0.0223 * 100 = 2.23%
C) To find the house value in 2010, use the formula: initial value * (1 + growth rate)^(years)
Step 1: Calculate the number of years: 2010 - 2006 = 4 years
Step 2: Calculate the house value: 145000 * (1 + 0.0223)^4 ≈ 161000
Summary:
The annual growth rate between 1993 and 2006 was 2.23%. If the house value continues to grow at the same rate, it will be worth approximately $161,000 in 2010.
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1. take away five from twelve times f. 2. one-half of the sum of k and six 3.x squared minus the sum of 5 4.the sum of the product of a and b, and three times c 5.twenty-four times the product of x and y, plus g.
The expressions formed are,
12f -5(k+6)/2x²-x+5ab+3c24xy+gFormation of expressions in 1, 2 and 3:
In 1, twelve times f is, 12f
Taking away 5, it becomes (12f-5)
In 2, sum of k and 6 is, (k+6)
One-half of the above quantity is, (k+6)/2
In 3, sum of 5 with x is, (x+5)
Now, x squared minus the above expression indicates (x²-x+5)
Formation of expressions in 4 and 5:
In 4, product of a and b, is ab and 3 times c is 3c
Sum of the expressions evaluated in the previous statement = ab+3c
In 5, 24 times the product of x and y is, 24xy
Adding, g in the above computed expression, we get, 24xy+g
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The distance from the center of the circle to any point on the edge of the circle. Responses a) Radius b) Circumference c) Diameter d) Tangent Line
Answer:
B. Radius
The line from the center of a circle to the edge is called a radius. The radius can be used in pi and a lot of other things
Can anyone help me with this geometry test please like I will do anything!! I will give brainlist!!
Also NO links!!
Answer:
It c
Step-by-step explanation:
8/x-12=-8/x
What is the domain restriction from left side of equation?
The domain restriction in the left side of the equation is x = 12.
What is the domain restriction from left side of equation?Here we have the equation:
8/(x - 12) = -8/x
The domain restrictions are the values of x such that we will have a zero in one of the denominators (this is because we can't divide by zero)
Then we need to remove these values.
We can see that in the left side of the equation, when x = 12 the denominator becomes zero, so that is the domain restriction.
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Point N is on line segment \overline{MO} MO . Given MN=2x, NO=x-2, and MO = 2x+9, determine the numerical length of \overline{MN}. MN .
Answer:
22
Step-by-step explanation
Express the answers to the following operations with the proper number of significant figures. (a) 8.370×1.3 ×10 (b) 4.265/2.0 (c) (1.2588×10 ^3)×(1.06×10 ^−2) (d) (1.11) ^1/2
The answers, rounded to the appropriate number of significant figures, are as follows:
(a) 1.088 ×\(10^2\)
(b) 2.132
(c) 1.3331 ×\(10^1\) and
(d) 1.05.
Let's calculate the answers to the given operations using the appropriate number of significant figures.
(a) 8.370×1.3×10
To perform this multiplication, we multiply the decimal numbers and add the exponents of 10:
8.370 × 1.3 × 10 = 10.881 × 10 = 1.0881 × \(10^2\)
Since the original numbers have four significant figures, we round the final answer to four significant figures:
1.088 × \(10^2\)
(b) 4.265/2.0
For division, we divide the decimal numbers:
4.265 ÷ 2.0 = 2.1325
Since both numbers have four significant figures, the answer should be rounded to four significant figures:
2.132
(c) (1.2588×\(10^3\))×(1.06×\(10^-^2\))
To multiply these numbers, we multiply the decimal numbers and add the exponents:
(1.2588 × \(10^3\)) × (1.06 × \(10^-^2\)) = 1.333128 × \(10^1\)
Since the original numbers have five significant figures, we round the final answer to five significant figures:
1.3331 × \(10^1\)
(d) \((1.11)^(^1^/^2^)\)
To calculate the square root, we raise the number to the power of 1/2:
\((1.11)^(^1^/^2^)\)= 1.0524
Since the original number has three significant figures, the answer should be rounded to three significant figures:
1.05
It's important to note that the significant figures in a result are determined by the original data and the operations performed. The final answers provided above reflect the appropriate number of significant figures based on the given information and the rules for significant figures.
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Describe how to find the average rate of change of a function y = f(x) between x = a and x = b
If f(3x - 1) = -6x + 3, find f f (2).
Therefore, function of x f(f(2)) = f(-3) = 9
Function (X) calculationTo find function of f f (2) we need to find the function f(2).
Given f(3x - 1) = -6x + 3
Let 3x -1 = 2 we will get
3x =3
x =1
Therefore, let input x =1
f(3x - 1) = -6x + 3
f(3(1) - 1) = -(1) + 3
Therefore, we need to find function of f(-3) and get f f (2).
f f (2). =f(-3) =9
f(3x - 1) = -6x + 3
f(-3) = -6(-1) + 3 =9
Therefore, if f(3x - 1) = -6x + 3, function of f(f(2)) = f(-3) = 9
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If the zero conditional mean assumption holds, we can give our coefficients a causal interpretation. True False
True. If the zero conditional mean assumption holds, the coefficients can be given a causal interpretation.
True. If the zero conditional mean assumption, also known as the exogeneity assumption or the assumption of no omitted variables bias, holds in a regression model, then the coefficients can be given a causal interpretation.
The zero conditional mean assumption states that the error term in the regression model has an expected value of zero given the values of the independent variables. This assumption is important for establishing causality because it implies that there is no systematic relationship between the error term and the independent variables.
When this assumption is satisfied, we can interpret the coefficients as representing the causal effect of the independent variables on the dependent variable, holding other factors constant. However, if the zero conditional mean assumption is violated, the coefficients may be biased and cannot be interpreted causally.
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What is the average rate of change of the function f(x) = 2x^2 + 8 over interval [1, 4]?
The average rate of change of f(x) = 2x^2 + 8 over interval [1, 4] is:
R = 10
How to get the average rate of change?For a function f(x) we define the average rate of change on an interval [a, b] as:
r = ( f(b) - f(a))/(b - a)
In this case the function is:
f(x) = 2x^2 + 8
And the interval is [1, 4]
Evaluating the function in these values we will get:
f(4) = 2*4^2 + 8 = 2*16 + 8 = 40
f(1) = 2*1^2 + 8 = 10
Then the average rate of change will be:
R = (40 - 10)/(4 - 1) = 30/3 = 10
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The school band has 36 members including 5 clarinets and 2 french horns what is the probability
The probability question you asked is incomplete, so I will make an assumption based on the information provided. If you are asking about the probability of selecting a clarinet or a French horn player from the school band,
we can calculate it as follows:
1. Calculate the total number of members in the band: 36.
2. Calculate the total number of clarinets: 5.
3. Calculate the total number of French horns: 2.
4. Add the number of clarinets and French horns together: 5 + 2 = 7.
5. Divide the total number of clarinets and French horns by the total number of band members: 7 / 36.
6. Simplify the fraction if needed.
- In decimal form, the probability would be 0.1944 (rounded to four decimal places) or 19.44% (rounded to two decimal places).
The probability of selecting a clarinet or a French horn player from the school band is approximately 0.1944 or 19.44%.
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(PLEASE HELP!!)
The stem-and-leaf plot displays data collected on the size of 15 classes at two different schools.
Bay Side School Seaside School
8, 6, 5 0 5, 8
8, 6, 5, 4, 2, 0 1 0, 1, 2, 5, 6, 8
5, 3, 2, 0, 0 2 5, 5, 7, 7, 8
3 0, 6
2 4
Key: 2 | 1 | 0 means 12 for Bay Side and 10 for Seaside
Part A: Calculate the measures of center. Show all work. (2 points)
Part B: Calculate the measures of variability. Show all work. (1 point)
Part C: If you are interested in a smaller class size, which school is a better choice for you? Explain your reasoning. (1 point)
A. The measures of center shows that the mean is 41.3 and the median is 5.
B. The measure of variability shows that the range is 8 and IQR is 5.
C. Based on the given data, if you are interested in a smaller class size, Bay Side School would be a better choice for you.
How to explain the informationPart A: For Bay Side School:
Mean: We sum up the class sizes and divide by the total number of classes.
Class sizes: 8, 6, 5, 8, 6, 5, 4, 2, 0, 5, 3, 2, 0, 0, 3
Sum = 8 + 6 + 5 + 8 + 6 + 5 + 4 + 2 + 0 + 5 + 3 + 2 + 0 + 0 + 3 = 62
Mean = 62 / 15 = 4.13
Class sizes in ascending order: 0, 0, 2, 2, 3, 3, 4, 5, 5, 5, 6, 6, 8, 8, 8
Median = (5 + 5) / 2 = 5
For Seaside School:
Mean: We sum up the class sizes and divide by the total number of classes.
Class sizes: 5, 8, 1, 0, 2, 5, 6, 8, 5, 7, 7, 8, 0, 6, 4
Sum = 5 + 8 + 1 + 0 + 2 + 5 + 6 + 8 + 5 + 7 + 7 + 8 + 0 + 6 + 4 = 72
Mean = 72 / 15 = 4.8
Median: We need to arrange the class sizes in ascending order and find the middle value.
Class sizes in ascending order: 0, 0, 1, 2, 4, 5, 5, 5, 6, 6, 7, 7, 8, 8, 8
Median = 6
Part B: In order to calculate the measures of variability, we will find the range and interquartile range (IQR) for each school's class sizes.
For Bay Side School:
Range: The range is the difference between the largest and smallest values.
Range = 8 - 0 = 8
IQR: The IQR is the difference between the third quartile (Q3) and the first quartile (Q1).
Q1 = median of the lower half of the data = (2 + 2) / 2 = 2
Q3 = median of the upper half of the data = (6 + 8) / 2 = 7
IQR = Q3 - Q1 = 7 - 2 = 5
For Seaside School:
Range: The range is the difference between the largest and smallest values.
Range = 8 - 0 = 8
IQR: The IQR is the difference between the third quartile (Q3) and the first quartile (Q1).
Q1 = median of the lower half of the data = (2 + 5) / 2 = 3.5
Q3 = median of the upper half of the data = (7 + 8) / 2 = 7.5
IQR = Q3 - Q1 = 7.5 - 3.5 = 4
C Based on the given data, if you are interested in a smaller class size, Bay Side School would be a better choice for you.
Considering both the measures of center and measures of variability, Bay Side School offers a smaller average class size (mean) and a smaller range of class sizes (IQR) compared to Seaside School. Therefore, if you prefer smaller class sizes, Bay Side School would be the better choice for you.
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Line segment JM has endpoints with coordinates 0 and 25 on a number line. Points K and L are on segment JM. K has a coordinate of 5 and point L has a coordinate of 12. Find the probability that a point on JM is placed first on JL and a second point is not placed on KL.
Answer:
D. 216/625Step-by-step explanation:
The length of the segment JM is 25 units.The segment JL is between 0 and 12, so is 12 units.The segment KL is between 5 and 12, so is 7 units.The probabilities for each point:
P(point on JL) = 12/25P(point not on KL) = 1 - 7/25 = 18/25Required probability:
P = 12/25*18/25 = 216/625Correct choice is D
if Michael has a farm with 2000 sheep each weighing 120kg how many kg altogether do the sheep way
The graph of g(x)=3|x|-4 maps a person's path from their house to school and then from school to their friend's house. At what point is the school located?
Answer:
\(x=0, g(x) =-4\)
Step-by-step explanation:
Given that:
Graph of \(g(x)=3|x|-4\) represents the path of a person from their house to school and then from school to their friend's house.
First of all let us learn about the graph of an absolute function.
An absolute function first decreases and then starts increasing from one point.
At that point, value of \(x=0\).
As per the problem statement given, the location of the school can only be the point that we have discussed above.
Given that the equation is:
\(g(x)=3|x|-4\)
Let us put the value of \(x=0\)
\(g(x)=3|0|-4\\\Rightarrow g(x)=-4\)
Therefore, the location of the school is:
(0, -4) or \(x=0, g(x) =-4\)
Find the possible dimensions of the sports field given if the width is at least 50yards. need help asap
Answer: (If I'm right can I get marked brainiest?)
100
2
+
50
2
=
12500
;
√
12500
=
111.80
yards
Step-by-step explanation:
A football field is a rectangle, so a diagonal line creates 2 right triangles. The formula for the length of the sides of a right triangle is
a
2
+
b
2
=
c
2
For this problem, we know
a
and
b
, so we just have to find
c
.
100
2
+
50
2
=
c
2
=
12500
The length of the diagonal is
√
12500
, which is 111.80 yards.
The possible dimensions of the sports field are width 70 yards, length 7-3x yards.
What are dimensions?Dimensions in mathematics are the measure of the size or distance of an object or region or space in one direction.
Given that, the width is at least 50 yards and area is (490-210x)
We can conclude the shape of the sports field is rectangular.
We need to find the Greatest Common factor between 490 and 210, this way:
490 = 2 × 5 × 7 × 7
210 = 2 × 5 × 3 × 7
Then the greatest common factor is 2 × 5 × 7 = 70
This GCF is also equal to 70 yards (given in option), therefore it's one of the dimensions of the sports field.
Now, we calculate the other side of the sports, this way:
Second dimension of the sports field = (490-210x)/70
= 7-3x
Hence, The possible dimensions of the sports field are width 70 yards, length 7-3x yards.
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sin(180+0) =
a. sin 0
b. -sin 0
c. cos 0
please explain thoroughly and in basic concepts I’m really bad at math thank you!
b.
because if you use math it tells you b