Which one of the following pairs cannot be mixed together to form a buffer solution?
a)C5H5N, C5H5NHCl
b)HC2H3O2, NaOH (C2H3O2- = acetate)
c)KOH, HI
d)NH2CH3, HCl
e)NaClO, HNO3

Answer:

Earth's thin outer shell is broken into big pieces called tectonic plates. These plates fit together like a puzzle, but they're not stuck in one place. They are floating on Earth's mantle, a really thick layer of hot flowing rock. The flow of the mantle causes tectonic plates to move in different directions.

Explanation:

Answer:

London Dispersion Only

Explanation:

BF3 is non polar and nonpolar molecules only have london disperion forces

Only Ag2CO3 will precipitate from the solution.

When Na2CO3 is added to the solution, it will react with the Ag^+ and Pb^2+ ions to form precipitates of Ag2CO3 and PbCO3. The Mn^2+ ion concentration is not high enough to form a precipitate with Na2CO3.

First, let's calculate the initial concentration of Ag^+ and Pb^2+ ions in the solution:

Ag^+: 0.00050 M

Pb^2+: 0.00050 M

Next, we need to calculate the concentration of Na2CO3 after it is added to the solution. Since we added 10.00 ml of 1.0*10^-6 M Na2CO3 to a total volume of 500 ml, the final concentration of Na2CO3 is:

[Na2CO3] = (10.00 ml / 500 ml) * 1.010^-6 M

[Na2CO3] = 2.010^-8 M

Now we can use the Ksp values to determine which precipitates will form.

For Ag2CO3:

Ksp = [Ag^+]^2[CO3^2-]

8.110^-12 = (2x)^2 (2x)

8.110^-12 = 4x^3

x = 2.0*10^-4 M

Since the concentration of CO3^2- is higher than the solubility product, Ag2CO3 will precipitate.

For PbCO3:

Ksp = [Pb^2+][CO3^2-]

7.410^-14 = (0.00050 M)(2x)

x = 9.210^-11 M

Since the concentration of CO3^2- is lower than the solubility product, PbCO3 will not precipitate.

Therefore, the only precipitate that will form is Ag2CO3.

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When the crystals of potassium permanganate are preserved in water, the purple-coloured crystals of potassium permanganate break further into smaller particles that populate the distance between the molecules of water imparting a purple colour to the water. This is an example of diffusion.

Diffusion is the process of movement of solvent from higher concentration to lower concentration through a semipermeable membrane. So, we can form the decision that it cannot occur through a thick membrane from which small molecules cannot pass through.

Osmosis is the direction of solvent particles from a solution that is diluted to a more concentrated one. In contrast, diffusion is the movement of particles from a higher concentration region to a part of lower concentration.

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Answer:

b

Explanation:

google lol ur welcome

B: Oceanic crust is thinner and more likely to sink.

The factor that  doesn’t change the resistance of a wire is pressure. option A.

Resistance is a conductor's capacity to thwart the passage of current. It is controlled by the interplay of the applied voltage and the electric current passing through it. The amount of opposition any object applies to the flow of electric current is referred to as resistance.

The ohm, a unit of measurement for resistance, is represented by the Greek letter omega. According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them.

Hence option A is correct.

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missing part;

The pressure

The length of the resistor.

The thickness of the resistor.

The temperature of the conductor.

These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Option B)

A colloid is a type of mixture in which particles are dispersed throughout a medium, creating a homogeneous appearance. Unlike solutions, where the particles are completely dissolved, and suspensions, where the particles settle out, colloids have particles that are larger than those in solutions but smaller than those in suspensions. One characteristic of colloids is that they can scatter light due to the size of the particles. This scattering of light is known as the Tyndall effect. Examples of colloids include milk, fog, and aerosol sprays. These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Therefore option B) is correct

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Note Complete Question

which is an example of a colloid?

a mixture that settles out,

b mixture that scatters light,

c mixture that is separated by filtration,  

d salt and water mixture?

The correct ionization equation for a weak acid is as follows: HA + H₂O ⇌ A + H₃O⁺ (option A).

A weak acid is an acid that partially dissociates into its ions in an aqueous solution or water. In contrast, a strong acid completely dissociates into its ions in water.

The conjugate base formed when a a weak acid dissociates is a weak base. Examples of weak acids are as follows:

The reaction arrow for a weak acid ionizing in water is a double arrow, indicating that both the forward and reverse reactions occur at equilibrium.

Therefore, HA + H₂O ⇌ A + H₃O⁺ is the ionization reaction that represents a weak acid.

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Answer:

1234567i9812345678912121212121

The systematic name of the compound is 2,2,3,3-tetramethylbutane.

The parent chain in this compound consists of four carbon atoms, indicated by the central chain of Cs in the diagram you provided. The prefix "but" in the name indicates that there are four carbon atoms in the parent chain.

The four methyl groups are attached to different carbon atoms in the parent chain. We can indicate the position of each methyl group by numbering the carbons in the parent chain. In this case, we can number the carbons starting from the left side of the parent chain, so that the first methyl group is attached to the second carbon, the second methyl group is attached to the third carbon, the third methyl group is attached to the second-to-last carbon, and the fourth methyl group is attached to the last carbon. This gives us the substituent groups 2,2,3,3-tetramethyl-.

Finally, we combine the parent chain name and the substituent groups to get the full name: 2,2,3,3-tetramethylbutane.

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The performance of a laboratory technician in a blood bank is crucial as it directly impacts the quality of the blood products and patient safety. If there are five problems with a technician's work performance in the first year of work, it can have serious consequences for the blood bank's operations.

Some of the potential problems that may arise include:

Improper labeling of blood products: This can result in confusion and incorrect transfusions.

Mishandling of blood products: This can lead to contamination, spoilage, or improper storage, which can affect the quality of the blood products.

Failure to follow standard operating procedures: This can result in errors, deviations from protocols, and potential safety hazards.

Poor communication skills: This can result in misunderstandings, delays, and errors in documentation.

Inadequate training or knowledge: This can lead to mistakes, misinterpretation of test results, and failure to recognize potential problems.

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Answer:

F

Explanation:

A carousel can be made to rotate using different sources of energy.  One may decide to use electric energy, manual effort, water energy or heat energy as in a candle carousel.

When the candle is lit, heat energy is supplied and warm air rises heating up the air near the carousel eventually causing it to start rotating.

Hence heat from the candle leads to a current of warm air that rises up, causing the carousel to start rotating.

The number of the grains of rice that we have from the question here is  16214 grains

In this case, we know that we have to rely on the information that we have in the question so as to be able to obtain the mass of the rice that we need in this case and that is what we are going to set out to do in this question.

We know that;

Mass of the Rice = 786 grams - 332 grams

= 454 g

If 1000 grains of rice have a mass of 28 g

x grains of rice have a mass of 454 g

x = 1000 * 454/28

x = 16214 grains

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Answer:

true

Explanation:

Answer:70L

Explanation:

The volume occupied by 100g of oxygen gas at STP is 70L.

1 mole of a gas at STP occupies 22.4 L volume.

The same goes for oxygen gas, \(O_2\). 1 mole of \(O_2\) occupies 22.4L volume.

Now the molar mass of \(O_2\) is = 32g

So the number of moles of \(O_2\) in 100g is

n = 100/32

n = 3.125 moles

Volume occupied by 3.125 moles or 100g of \(O_2\) is

V = 3.125 × 22.4 L

V = 70 L volume is occupied by 100g of oxygen gas.

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Answer:

See below

Explanation:

It is a problem if a computer code has errors or mistakes because if they do, then the whole script will go wrong and chances are that your computer will not work. Each KB of data is crucial to letting the computer function properly. If one of the data is wrong, then the computer code won't work.

Answer:

It will not achieve the desired separation

Explanation:

Chromatography is a separation method that involves the use of a stationary phase and a mobile phase. The stationary phase is immobile, in the particular instance of this question, the stationary phase is paper. The mobile phase is the appropriate solvent, in this case, a salt-water solution.

If the level of solvent is above the dye spots, it will introduce error into the separation. The solvent (if volatile) may evaporate without drawing up and separating the solute. Secondly, the solvent may simply dissolve the spots without achieving any meaningful separation of the components in the system. This second reason is particularly why the salt solution must be below the dye spots in this chromatographic separation.

Answer:

The given substance is cast iron.

Explanation:

Given data:

Mass of substance = 50 g

Heat absorbed = 23000 J

Initial temperature = 250°C

Final temperature = 1250°C

Which metal is this = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 1250°C -  250°C

ΔT = 1000°C

23000 j = 50 g ×c ×1000 °C

23000 J = 50,000 g. °C×c

c = 23000 J /50,000 g. °C

c = 0.46 J/g.°C

The given substance is cast iron.

Answer:

Water is attracted to other substances. Adhesion and cohesion are water properties that affect every water molecule on Earth and also the interaction of water molecules with molecules of other substances.

Answer: it’s 8.3

Explanation: on edge

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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Heat is most accurately described as "the energy transferred between objects at different temperatures" (C). Until they reach thermal equilibrium, or the same temperature, heat is a type of energy that flows freely from a hotter to a colder item.

Heat can be transferred through conduction, convection, or radiation. The temperature differential between the items and the thermal conductivity of the materials involved determine how much heat is transported.

Temperature,  a measurement of the average kinetic energy of the particles in an item, is not the same as heat. Internal energy is the entire amount of energy held by an object's particles, which includes both their kinetic and potential energies.

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a. C3H6, the degree of unsaturation is 0

b. C3H4, the degree of unsaturation is 1.

c.  C4H6, the degree of unsaturation is 2 .

To determine the degree of unsaturation for each molecular formula, calculate the number of double bonds or rings and subtract it from the number of atoms of carbon and hydrogen (which should be even).

For a. C3H6, the degree of unsaturation is 0. There are 3 carbons and 6 hydrogens, both of which are even, so no double bonds or rings are present. The possible structures would be linear alkanes, such as propane (C3H8).

For b. C3H4, the degree of unsaturation is 1. There are 3 carbons and 4 hydrogens, which is an odd number, so one double bond or ring is present. The possible structures would be alkenes, such as propene (C3H6).

For c. C4H6, the degree of unsaturation is 2. There are 4 carbons and 6 hydrogens, which is an even number, so two double bonds or rings are present. The possible structures would be alkynes, such as propyne (C3H4).

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0.5 moles of lithium chloride are dissolved in .05 liters of water. 10M  is the molarity of the solution.

The total amount of moles of solute found within a specific number of litres of the solution, or moles per litre of a solution, is known as molar concentration or molarity. Please explain the difference amongst the terms "solute" and "solvent" before we continue.

'Solution' for making it simpler to comprehend the topics that will follow. Solutes are simply substances that exist in solutions because a solution is defined as a homogenous mixture that comprises one or more solutes.

Molarity = moles/volume of solution in liter

              = 0.5/ .05

               = 10M

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The reaction becomes spontaneous at approximately 2667 Kelvin.

To determine the temperature at which a nonspontaneous reaction becomes spontaneous, we can use the equation ΔG = ΔH - TΔS, where ΔG is the change in Gibbs free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.

In this case, we are given ΔH = 144 kJ/mol and ΔS = 54 J/K mol. To convert ΔH to J/mol, we multiply by 1000, giving us ΔH = 144,000 J/mol.

To find the temperature at which the reaction becomes spontaneous, we set ΔG to zero, as this is the condition for equilibrium. Thus, we have 0 = ΔH - TΔS.

Rearranging the equation, we have TΔS = ΔH, and substituting the given values, we get T * 54 J/K mol = 144,000 J/mol.

Dividing both sides by 54 J/K mol, we find that T = 144,000 J/mol / 54 J/K mol = 2667 K.

Therefore, the reaction becomes spontaneous at approximately 2667 Kelvin.

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The following applies to the above equation:

Brønsted-Lowry acid is the any chemical species that acts as a donor of protons while Brønsted-Lowry base is any chemical species that acts as a proton acceptor.

In the following equation: HCOOH(aq) + PO43-(aq) = HCOO-(aq) + HPO42-(aq)

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Answer:

There are 8 electrons in the last level. Because of the octet rule.

Answer: The bond angle remains 120

Explanation: