Which of these fractions equals 40%

The given statement is false. If the characteristic polynomial of a matrix A factors into a product of linear factors, then A is not necessarily diagonalizable.

By definition, a matrix A having characteristic F is diagonalizable if and only if the following 2 conditions are met-

Hence, we can conclude that the given statement is false. If the characteristic polynomial of a matrix A factors into a product of linear factors, then A is not necessarily diagonalizable.

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The coordinates point C of the given line segment AC is C(0, -2) whose midpoint is at B.

To calculate the midpoint of a line segment, find the average for the coordinates of the endpoints of the line segment. I.e.,

Consider a line segment AC, B is its midpoint.

So, the coordinates of B are (Where we have A(x1, y1) and C(x2, y2))

B(x, y) = \((\frac{x1+x2}{2}, \frac{y1+y2}{2})\)

It is given that, B is the midpoint of a line segment AC.

Where A has coordinates as (-3, 4) and B has coordinates as (-1 1/2, 1).

So, the coordinates of the other end point C of the given line segment are calculated as

B(x, y) = \((\frac{x1+x2}{2}, \frac{y1+y2}{2})\)

⇒ (-1.5, 1) = \((\frac{-3+x2}{2}, \frac{4+y2}{2})\)

⇒ -1.5 = (-3 + x2)/2 and 1 = (4 + y2)/2

⇒ -3 = -3 + x2 and 2 = 4 + y2

⇒ x2 = 0 and y2 = 2 - 4 = -2

Therefore, point C has coordinates as (0, -2).

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We reject the null hypothesis since the p-value is less than the significance level of 0.05.

The null hypothesis in statistics is a claim that presupposes there is no statistically significant distinction among the two or even more variables be compared. The antithesis of the alternative hypothesis, it is frequently denoted as H0 (Ha). While conducting statistical studies, the null is often evaluated to see if there is sufficient proof against it or not. The default assumption is typically the null hypothesis, and it serves as a benchmark for comparison of the statistical analysis's findings. A statistically significant distinction between the variables under comparison is said to exist if the statistical analysis yields sufficient data to refute a null hypothesis.

given

To test the hypothesis, we can utilise a z-test. This is the test statistic:

\(z = (x - E) / σ\)

where x is the observed percentage of patients whose conditions are getting better. x = 820 * 0.52 = 426.4 is the result. Therefore:

z = (426.4 - 393.6) / 0.026 = 1245.98

P(Z > z) = 1 - P(Z z) is the p-value for this one-tailed test, where Z is a normal standard variable. By using a typical table or calculator, we discover:

P(Z > 1245.98) < 0.0001

We reject the null hypothesis since the p-value is less than the significance level of 0.05.

We have enough data to draw the conclusion that the percentage of patients whose conditions are improving is more than 0.48.

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Answer:

C) 4

Step-by-step explanation:

Hi there!

We are given the line y=4/3x+1

We want to find the y intercept of the line perpendicular to that line, that also passes through the point (4,1)

Perpendicular lines have slopes that have a product of -1

We'll first find the slope of y=4/3x+1

The equation is written in slope-intercept form (y=mx+b), where m is the slope and b is the y intercept

4/3 is in the place of where m (the slope) is, so the slope of the line is 4/3

Now to find the slope perpendicular to it, use this formula:

4/3m=-1

Multiply both sides by 3/4

m=-3/4

The slope of the line perpendicular to y=4/3x+1 is -3/4

We can write the equation of the new line in slope-intercept form as well; start by substituting -3/4 as m:

y=mx+b

y=-3/4x+b

Now we need to find b (y intercept)

As the equation includes the point (4,1), we can use it to help solve for b

Substitute 4 as x and 1 as y:

1=-3/4(4)+b

Multiply

1=-3+b

Add -3 to both sides

4=b

The y intercept of the line is 4

Hence, the answer is C

Hope this helps!

Answer:

4

Step-by-step explanation:

If i did it right you would use the formula y-y1=m(x-x1)

Plug in y-1=-3/4(x-4)

-3/4 because perpendicular you need to flip and make negitive.

Distribute  y-1=-3/4x-12/4

move the one over y=-3/4x+4

4 being the y-intercept and -3/4 being the slope

Hope this helps!

The volume of the triangular pyramid, with a base area of 12 and a height of 25, is equal to 100 cubic units.

To calculate the volume of a triangular pyramid, we need the values of the base area and the height. Given that a = 12 and h = 25, we can proceed with the calculation.

The formula for the volume of a triangular pyramid is (1/3) * base area * height. Since we know the base area is equal to a, we can substitute the values into the formula.

Volume = (1/3) * a * h

Plugging in the given values, we have:

Volume = (1/3) * 12 * 25

Simplifying the expression further:

Volume = (1/3) * 300

Volume = 100

Therefore, the volume of the triangular pyramid, with a base area of 12 and a height of 25, is equal to 100 cubic units.

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Answer:

14 f g

Step-by-step explanation:

Multiply  7  by  2 .

Answer:

1-2

Step-by-step explanation:

honestly idek what this stuff is I just need points

Answer:

6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Factors of 24 are: 1, 2, 3, 4, 6, 8, 12

Factors of 30 are: 1, 2, 3, 5, 6, 10, 15

They both share the factor 6 :)

Answer:

3. a. 10:35= 2:7

b.35:45=7:9

c.40:50=4:5

The solution to the equations is

Addition : 2.49 + 6.7 = 9.19  ;  6.7 + 2.49 = 9.19

Subtraction : 9.19 - 6.7 = 2.49  ;  9.19 - 2.49 = 6.7

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the three decimals be represented as set x = { 2.49 , 6.7 , 9.19 }

Now , the addition facts are given by equations ,

2.49 + 6.7 = 9.19  be equation (1)

6.7 + 2.49 = 9.19   be equation (2)

And , the subtraction facts are given by the equations ,

9.19 - 6.7 = 2.49  be equation (3)

9.19 - 2.49 = 6.7  be equation (4)

Hence , the equations are solved

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Answer:

5 drinks: $25.00 4 candies: $18.00 Total: $43.00

inn equation form: $5d+$4.5c=?

Step-by-step explanation:

5*5=25

4.5*4=18

25+18=43

Answer:

answer is on screenshot pls like so i could get points lol

Step-by-step explanation:

Answer:

16π ft²

Step-by-step explanation:

The formula is [ A = πr² ]

A = π(4)²

A = 16π

Best of Luck!

C 16

Step-by-step explanation:

i took the quiz

This question is incomplete

Complete Question

Among the seven nominees for two vacancies on the city council are three men and four women. In how many ways may these vacancies be filled

a) with any two of the nominees?

b) with any two of the women?

c) with one of the men and one of the women?

Answer:

a) 21 ways

b) 6 ways

c) 12 ways

Step-by-step explanation:

We solve this question using combination formula

C(n, r) = nCr = n!/r! (n - r)!

a) with any two of the nominees?

Probability (two of the nominees) = 7C2

= 7!/2! ×(7 - 2)!

= 7!/ 2! × 5!

= 7 × 6 × 5 × 4 × 3 × 2 × 1/2 × 1 ×(5 × 4 × 3 × 2 × 1)

= 21

b) with any two of the women?

We have a total of 4 women

Hence, the probability of any two of the four women, filling the vacancies =

P(any two of the women) = 4C2

= 4!/2! ×( 4 - 2)!

= 4!/ 2! × 2!

= 4 × 3 × 2 × 1/ 2 × 1 ×( 2 × 1)

= 6

c) with one of the men and one of the

Total number of men = 3

Total number of women = 4

= 3C1 × 4C1

= [3!/1! ×(3 - 1)! ] × [4!/1! ×(4 - 1)! ]

= [3!/1! × 2!] × [4!/1! ×3!]

= [3 × 2 × 1/ 1 × 2 × 1] × [4 × 3 × 2 × 1/ 1 × 3 × 2 × 1]

= 3 × [24/6]

= 3 × 4

= 12 ways

The probability for any two of the nominees is 21

The probability for two women is 6

This question is incomplete

Complete Question

Among the seven nominees for two vacancies on the city council are three men and four women. In how many ways may these vacancies be filled

a) with any two of the nominees?

b) with any two of the women?

We have given,

Total number of nominees for two vacancy =7

We solve this question using combination formula

What is the formula for combination?

\(C(n, r) = nCr = n!/r! (n - r)!\)

a) with any two of the nominees?

Total number of nominees(n)=7

We are selecting r nominees r=2

Probability  = 7C2

= \(\frac{7!}{2! (7 - 2)!}\)

= 7!/ 2! × 5!

= 21

b) with any two of the women?

We have a total number of women=4

Out of 4 we have select 2 women

Hence, the probability of any two of the four women is

4C2

= 4!/2! ×( 4 - 2)!

= 4!/ 2! × 2!

= 6

Therefore,probability for two women is 6

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Option D is the correct answer.

From the graph, we can conclude that,

1. The two lines are continuous lines and not broken lines. So, the inequality sign should be either ≤ or ≥.

2. The points on the lines of the shaded region are also included in the solution.

The only option that matches with the above conditions is option D. So, option D is the correct answer.

Let us verify it.

Now, let us consider a point that is inside the shaded region and also on any one line.

Let us take (0, 2).

Plug in 0 for x and 2 for y in each of the options and check which inequality holds true.

Considering the inequalities,

y ≥ 3x - 2

x + 2y ≤ 4

Solving we get,

2 ≥ 3(0) - 2

2 ≥ -2

x + 2y ≤ 4

0 + 2(2) ≤ 4

4 ≤ 4

Here, both inequalities are correct.

So, option D is the correct answer.

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The complete question is =

Which system of linear inequalities is graphed?

A. y < 3x-2

x + 2y ≥ 4

B. y < 3x - 2

x + 2y > 4

C. y > 3x - 2

x + 2y < 4

D. y ≥ 3x - 2

x + 2y ≤ 4

Answer:

The answer is D. x = 0 , 5

x equal to 0 and 5.

Answer:

5x + 6 = 0

5x = - 6

x = - 6/5

-6/5 is the answer

The distance between M and H is given as follows:

x = 21.3.

Similar triangles are triangles that share these two features presented as follows:

The proportional relationship between the side lengths is given as follows:

x/18 = 24/16

Applying cross multiplication, the distance between M and H is obtained as follows:

16x = 24(18)

x = 24 x 18/16

x = 27.

The diagram is given by the image presented at the end of the answer.

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The reasoning presented lacks explicit explanations and logical connections between the steps, making it difficult to fully understand the intended proof strategy.

The given proof aims to show that the Separation Axioms can be derived from the Replacement Schema using a particular construction involving a formula p(x, y). Let's analyze the proof step by step:

Define the formula p(x, y) as x = yo(x).

This formula states that for each x, y pair, x is equal to the unique object y such that y is obtained by applying the operation o to x.

Define the set F as {(x, x) (x)}.

This set F contains pairs (x, x) where x is the unique object obtained by applying the operation (x) to x.

Claim: F(X) = {y (x = X)p(x, y)} = {y: (x = X)x = y^o(x)} = {x: (3x € X)o(x)} = {x X: (x)}.

This claim asserts that F(X) is equivalent to {y (x = X)p(x, y)}, which is further equivalent to {y: (x = X)x = y^o(x)}, and so on.

The proof states that since (x, y) satisfies the functional formula VaVyVz(p(x, y)^(x, z) y = z), it follows that (x, y) is a functional formula.This step emphasizes that the formula p(x, y) satisfies certain properties that make it a functional formula, which is relevant for the subsequent deductions.

Finally, the proof concludes that the Separation Axioms follow from the Replacement Schema, based on the previous steps.

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Answer: a=mx+b

Step-by-step explanation:

Using the following property:

so:

The two colors can be chosen in 3 different ways.

If we have a set of N elements, the number of different sets of K elements (such that the order of the K elements does not matter) is:

\(C(N, K) = \frac{N!}{(N - K)!*K!}\)

In this case, we have 3 colors, so N=3, and we want to choose 2, then K=2.

Replacing that we get:

\(C(3, 2) = \frac{3!}{(3- 2)!*2!} = \frac{3*2*1}{1*2*1} = 3\)

The two colors can be chosen in 3 different ways.

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Answer and Step-by-step explanation:

Solve for x.

First, we divide both sides of the equation by 2.

2(8 - 2x) = 7 - x

Distribute the 2.

16 - 4x = 7 - x

Add 4x to and subtract 7 from both sides of the equation.

9 = 3x

Divide by 3 to both sides of the equation.

x = 3 <-- This is the answer.

#teamtrees #PAW (Plant And Water)

Answer:

x = 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Distributive Property

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

4(8 - 2x) = 2(7 - x)

Step 2: Solve for x

Answer:

me too (help)

Step-by-step explanation:

Answer:

1. About 760 seconds.

Step-by-step explanation:

Using a calculator, I figured 3 x 10^8 and got 300,000,000. Then, I divided 230,000,000,000 by 300,000,000 to get 759.9 seconds.

Answer:

2. About 80,000,000,000 kilometers. (80 billion.)

Step-by-step explanation:

Again using a calculator, I figured 1.5 x 10^11 and got 150,000,000,000. Then, I subtracted 150,000,000,000 from 230,000,000,000 (230,000,000,000 - 150,000,000,000.) And got an answer of 80 billion.

Answer:

1. 7.6*10^2

2. 8*10^10

Step-by-step explanation:

1. (2.3*10^11)/(3*10^8)

0.76*10^3

The answer above isn’t in boundaries of 1-10 but smaller than 10 so you move it a 10th to the right and now you have to take one exponent away because you did that so you end up with:

7.6*10^2 0r 760 secs

2. (2.3*10^11)-(1.5*10^11)

(2.3-1.5) *10^11

0.8 *10^11

The ‘0.8’ isn’t in boundaries of 1-10 but less than 10 so you move it a 10th to the right which will be 8. Now you gotta do the exponent thing (explained earlier). You should end up with:

8*10^10 or 80 billion

1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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The minimum number of aunts that Shamar must have based on the information provided is 10.

It is known that uncles will take a photograph in groups of 10, while aunts will take a photograph in groups of 5. Based on this, the possible number for each are:

Uncles: 10, 20, 30, 40, 50

Aunts: 5, 10, 15, 20, 25

In this case, the minimum number is the LCM or Least Common Multiple and based on the previous list, this number is 10.

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Answer:r=2 cos^4(theta)

Step-by-step explanation:To find the values of theta where the maximum r-values occur on the graph of the polar equation r = 2 cos^4(theta), we need to find where the derivative of r with respect to theta is equal to zero, since the maximum r-values occur at these points.

First, we can simplify the equation by using the identity cos(2theta) = 2cos^2(theta) - 1 and substituting cos^2(theta) = (1 + cos(2theta))/2. This gives:

r = 2 cos^4(theta) = 2(1/2 + 1/2 cos(2theta))^2 = 1 + cos(2theta) + cos^2(2theta)/2.

Next, we can take the derivative of r with respect to theta, using the chain rule:

dr/dtheta = -sin(2theta) - 2cos(2theta)sin(2theta).

Setting this equal to zero and factoring out sin(2theta), we get:

sin(2theta)(-1 - 2cos(2theta)) = 0.

This equation is satisfied when sin(2theta) = 0 or cos(2theta) = -1/2.

When sin(2theta) = 0, we have 2theta = k*pi for some integer k. Therefore, theta = k*pi/2.

When cos(2theta) = -1/2, we have 2theta = 2*pi/3 + 2*k*pi or 2theta = 4*pi/3 + 2*k*pi for some integer k. Therefore, theta = pi/3 + k*pi or theta = 2*pi/3 + k*pi.

These are the values of theta where the maximum r-values occur on the graph of the polar equation r = 2 cos^4(theta).

The width and the length that gives the largest possible areas are 75 meters by 37.5 meters

From the question, we have the following parameters that can be used in our computation:

Number of warehouses = 4

Perimeter of fence = 300 meters

Represent the width with x and the length with y

So, we have the following equations

Area = 4xy

Perimeter = 2(4x + y)

Substitute the known values in the above equation, so, we have the following representation

2(4x + y) = 300

Divide both sides by 2

2x + y = 150

Make y the subject

y = 150 - 2x

Substitute y = 150 - 2x in Area = 4xy

A = 4x(150 - 2x)

This gives

A = 600x - 8x²

Differentiate and set to 0

600 - 16x = 0

So, we have

16x = 600

Divide by 16

x = 37.5

Recall that

y = 150 - 2x

So, we have

y = 150 - 2 x 37.5

Evaluate

y = 75

Hence, the dimensions are 75 meters by 37.5 meters

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Answer:

1.03904 x 10^3

Step-by-step explanation:

multiply to get

10.3904 x 10 ^-7+9

10.3904 x 10^2

write it in scientific notation

1.03904 x 10^3

which is also equal to 1039.04

Answer:

11/320

Step-by-step explanation:

the probability of a senior being chose first is 22 (seniors) divided my total number of students (80) is .275 percent.

multiplied by the probability of a sophomore being chosen 10/80 which equals .125.

multiply those together and you get your probability. 0.034375 or 11/320