Which of the points a(9, 0, 1), b(9, 7, 3), and c(1, 8, 6) is closest to the yz-plane? which point lies in the xz-plane?

A. The minimum chromatic resolving power needed to resolve the two spectral lines is approximately 26,924.

B. The lowest order required to resolve the lines is approximately 477.

To determine the minimum chromatic resolving power and the lowest order required to resolve the two Fraunhofer lines in the solar absorption spectrum, we can use the formula for resolving power and the relationship between wavelength, order, and the number of slits in a diffraction grating.

(a) The minimum chromatic resolving power (R) can be calculated using the formula:

R = λ / Δλ

where λ is the wavelength of the spectral line and Δλ is the minimum separation between the two lines.

Given that the wavelengths of the two lines are 430.790 nm and 430.774 nm, the minimum separation can be found by taking the difference:

Δλ = 430.790 nm - 430.774 nm = 0.016 nm

Substituting this value into the formula, we get:

R = 430.790 nm / 0.016 nm ≈ 26,924

Therefore, the minimum chromatic resolving power needed to resolve these two spectral lines is approximately 26,924.

(b) The lowest order required to resolve the two lines can be determined using the formula:

m = N * Δλ / λ

where m is the order, N is the number of slits in the diffraction grating, Δλ is the minimum separation between the lines, and λ is the wavelength of the lines.

Given that the number of slits is 12,800, we can substitute the values into the formula

m = 12,800 * 0.016 nm / 430.790 nm ≈ 477

Therefore, the lowest order required to resolve these two lines is approximately 477.

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Answer:

Yes.

Explanation:

Even though the initial and final speeds are the same, there has been a change in direction for the object. Thus, there is an acceleration. The object was moving rightward and slowed down to 0 m/s before changing directions and speeding up while traveling leftward.

The maximum net charge that can be placed on the spherical conductor before dielectric breakdown occurs can be found using the formula: Q = 4πε₀r²E where Q is the charge, ε₀ is the electric constant (8.854 × 10^-12 F/m), r is the radius of the conductor, and E is the dielectric strength of the air.

Substituting the given values, we get:

Q = 4π(8.854 × 10^-12)(0.72)^2(3 × 10^6) = 5.05 × 10^-6 C or 5.05 µC (to three significant figures)

The magnitude of the potential of the sphere when it carries this maximum charge can be found using the formula:

V = kQ/r

where V is the potential, k is the Coulomb constant, Q is the charge, and r is the radius of the conductor.

Substituting the given magnitude, we get:

V = (8.98755 × 10^9)(5.05 × 10^-6)/(0.72) = 6.27 kV (to two significant figures)

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The magnitude of the potential of the sphere when it carries the maximum charge is 16.4 kV.

Q_max = 4πε_0R²E_max

Q_max = 4π(8.854 × \(10^{-12}\) F/m)(0.72 m)^2(3 × \(10^{6}\) V/m)

= 4.02 × \(10^{-6}\) C

= 4.02 µC

V = Q/(4πε_0R)

V = (4.02 × \(10^{-6}\) C)/(4π(8.854 × \(10^{-12}\)F/m)(0.72 m))

= 16.4 kV

A charge is a fundamental property of matter that describes the electric force that an object can exert on other objects. It is a scalar quantity that can be positive or negative, and its unit of measurement is the Coulomb (C).

The charge can exist in two types: positive and negative. Positive charges are carried by protons, while negative charges are carried by electrons. The total charge of an isolated system is always conserved, meaning that it cannot be created or destroyed, only transferred or redistributed among objects. Electric charge plays a critical role in a wide range of physical phenomena, including the behavior of atoms and molecules, the functioning of electrical circuits, and the interactions between particles in the universe.

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An optical device is an instrument that uses light for a purpose. The device that can focus light to a point through reflection is mirror.

The reflection is the phenomenon of a light ray going back to the same medium after striking a surface.

The mirror is a one sided polished surface which reflects all the light falling on it. The reflected light after striking the mirror meets at a point forming the image of an object place in front of mirror. A mirror is an optical device that uses reflection phenomenon to focus light.

Thus, the device that can focus light to a point through reflection is mirror.

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Answer: 0.16s

Explanation:

Given the following :

Average spring force by the racquet (F) = 225N

Change in momentum = 35kgm/s

To determine the change in interaction time; that is the momentary for e acting in the tennis ball ( impulse)

Recall:

F = mass(m) × acceleration(a)

Acceleration (a) = change in Velocity with time

a = change in V / time(t)

F = m * change in V / t

Ft = m* change in v

Recall m* change in v = momentum

Ft = change in momentum

225 * t = 35

t = 35 / 225

t = 0.1555555

t = 0.16s

The thickness of the air column above 1 m² of the Earth's surface that would have a weight of about 100,000 N is equal to 8,680.56 meters assuming the density of air remained constant at 1.2 kg/m³.

If the density of air were a constant 1.2 kg/m³ throughout the atmosphere, we can calculate the thickness of the air column that would have a weight of about 100,000 N on an area of 1 m².

The weight of the air column can be calculated using the formula:

Weight = density × volume × gravitational acceleration

We can rearrange the formula to solve for the volume:

\(\text{{Volume}} = \frac{{\text{{Weight}}}}{{\text{{density}} \times \text{{gravitational acceleration}}}}\)

Substituting the given values:

Weight = 100,000 N

Density = 1.2 kg/m³

Gravitational acceleration (g) ≈ 9.8 m/s²

\(Volume = \frac{100000 N}{(1.2 kg/m^3) \times (9.8 m/s^2)}\)

Volume ≈ 8,680.56 m³

Therefore, if the density of air were a constant 1.2 kg/m³, the thickness of the air column above 1 m² of the Earth's surface that would have a weight of about 100,000 N is approximately 8,680.56 meters.

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Answer:

Since the two colliding objects travel together in the same direction after the collision, the total momentum is simply the total mass of the objects multiplied by their velocity.

Explanation:

An object that is emitting light at specific wavelengths or frequencies, such as a gas or plasma, would be most likely to produce an emission-line spectrum.

An emission-line spectrum is a type of spectrum that is produced when an object emits light at specific wavelengths or frequencies. This occurs when electrons in an atom or molecule are excited to higher energy levels and then return to lower energy levels, releasing energy in the form of light.

The emitted light is typically at specific wavelengths or frequencies that are characteristic of the atom or molecule, resulting in a series of bright lines or bands in the spectrum.Examples of objects that are known to produce emission-line spectra include:

- Stars: Some types of stars, such as hot, young stars, emit light at specific wavelengths that are associated with the ionization of gases in their outer atmospheres.

- Nebulae: Large clouds of gas and dust in space can emit light at specific wavelengths due to the presence of ionized atoms and molecules.

- Lasers: Lasers produce highly focused beams of light at specific wavelengths or frequencies, making them useful for a variety of applications, from medical procedures to manufacturing.

In contrast, objects that emit light across a broad range of wavelengths or frequencies, such as a hot solid object like a light bulb filament, would be more likely to produce a continuous spectrum.

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Answer:

Cold temps. . .

Explanation:

Hope it helps!

Given: No. of fans = 5

           Current (I)= 0.8A

           Voltage (V) 220V

To find:   Total power P

Solution:  We know that P=VI

  Therefore for one fan P= 0.8*220

                                         = 176 W

Total Power for 5 fans = 176*5

                                      = 880W

Lock any windows and doors that are open. Head to the centre or basement of the structure. The recommended course of action is to stay as far away from the building's walls and top as you can since radioactive.

If radon gas is allowed to build up in a residence, it not only poses a health concern to uranium miner but also to homeowners. It is typically the biggest source of exposure to natural radiation.

We have been surrounded by radiation throughout our development. Therefore, the low amounts we are exposed each day are something our bodies are built to handle. However, excessive radiation can harm tissues by altering cell structure and DNA. Cancer is only one of the significant health issues this can lead to.

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Answer:

1.6 m/s

Explanation:

Answer:

3m/s2

Explanation:

a = (v-u) / t

a = (25 - 10) / 5

a = 15 / 5

a = 3

When a neuron is at resting potential, the state of the electrical charge is negative inside the neuron compared to the outside

Because of an unequal distribution of ions like potassium (K+) and chloride (Cl-) inside and outside the neuron, the interior of the neuron is negatively charged at resting potential. The membrane of the neuron is selectively permeable, permitting certain ions to pass while preventing others from doing so. A gradient in electrochemistry results from this.

Ion channels, notably the sodium-potassium pump, which actively transfers sodium ions (Na+) out of the neuron and potassium ions (K+) into the neuron, are responsible for maintaining the resting potential. As a result, the neuron produces an excess of negative charge within and an excess of positive charge outside.

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Answer:

1)

Acceleration (a)=change in velocity/ change in time

Velocity (v)=90m/s

Time=0.0005s

a=90/0.0005

The acceleration =180000m/s^2 or 180km/s^2

Force = mass x acceleration

m=40g= 0.04kg

F= 0.04x 180000

F= 7200N or 7.2kN

Explanation:

Answer:

19 km.

..............

Explanation:

.....

Answer:The Distance is 43 and displacement is 5km south

Explanation: To find the distance you add up all the numbers which was 43 and to fine the displacement subtract all the numbers and since all the other numbers were out expect for -5 which was south you would put 5 km south , if the number has a negative on it , it doesnt matter.

The shrinking of integrated circuit device dimensions over six decades led to faster computing, advanced circuit functions, improved power efficiency, and widespread advanced electronic devices.

Increased Computing Speed: As device dimensions have shrunk, the distance between transistors on a chip has decreased, enabling faster electrical signal propagation. This has led to increased clock speeds and faster processing capabilities, allowing for more complex computations and faster data processing.

Enhanced Circuit Functionality: With smaller device dimensions, more transistors can be integrated into a single chip. This has enabled the development of highly sophisticated and complex circuits, such as microprocessors, capable of performing intricate tasks.

The increased number of transistors has also facilitated the integration of various functionalities, such as memory, graphics processing, and communication capabilities, onto a single chip, leading to more versatile and powerful computing devices.

Improved Power Efficiency: Smaller device dimensions have reduced the distance that electrical signals need to travel within a chip. This has minimized the power losses associated with signal propagation, resulting in improved power efficiency. Additionally, the miniaturization of components has allowed for the development of low-power transistors, enabling energy-efficient operation and longer battery life in portable electronic devices.

Proliferation of Advanced Electronic Devices: The million-fold reduction in device dimensions has made it possible to produce smaller, lighter, and more compact electronic devices. This has led to the widespread adoption of smartphones, tablets, wearables, and other portable devices that offer advanced computing, communication, and multimedia capabilities. The miniaturization of integrated circuits has also enabled the development of Internet of Things (IoT) devices, smart sensors, and embedded systems, which have revolutionized various industries and aspects of everyday life.

Increased Integration and System Complexity: Shrinking device dimensions have allowed for greater integration of components and systems on a single chip. This has led to the development of system-on-chip (SoC) solutions, where multiple functions, such as processing, memory, and communication, are combined on a single integrated circuit. The increased integration and system complexity have contributed to the advancement of technologies like artificial intelligence, machine learning, and autonomous systems.

Cost Reduction: The continual shrinking of device dimensions has resulted in increased transistor density on a chip. This has led to higher production yields per wafer, driving down the manufacturing cost per transistor. The cost reduction has made advanced computing and communication technologies more affordable and accessible to a wider range of users, fostering their widespread adoption.

Overall, the million times shrinking of device dimensions in integrated circuits over the past six decades has had a profound impact on computing and communications, revolutionizing the speed, functionality, power efficiency, and size of electronic devices while enabling the development of new technologies and driving economic growth in the digital era.

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Energy transfer will be greater if the amplitude of the wave is greater.

The particles of the medium vibrate until they transfer the energy and after transferring energy, they return back to their equilibrium position.

Thus, options 3 and 4 are correct.

If the net force propelling an object along a straight-line path is doubled, its acceleration would double as well (Option B).

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. The equation for this relationship is F = ma, where F represents the net force, m represents the mass of the object, and a represents the acceleration.

When the net force is doubled (F' = 2F), and the mass remains constant, the equation becomes 2F = ma. Rearranging the equation, we have a = (2F) / m.

As the mass (m) remains the same, the acceleration (a) will be directly proportional to the net force (F). Therefore, doubling the net force will result in double the acceleration.

Hence, Option B, double, is the correct answer.

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Answer:

Because the lever would change with small changes.

Explanation:

When a material that has a rather high thermal expansion coefficients is used, the length of the level arm length changes with corresponding changes in its temperature. This, isn't a good phenomenon, and so as not to interfere, that's why there is a need for materials with lower thermal expansion coefficient.

Answer:

the answer is mass divided by volume

Answer:

Mass divided by volume

Explanation:

Edgen answer 2020-2021

Answer:

where are the answers

Explanation:

Answer:

Energy conversion, also termed as energy transformation, is the process of changing one form of energy into another. Energy conversion occurs everywhere and every minute of the day. There are numerous forms of energy like thermal energy, electrical energy, nuclear energy, electromagnetic energy, mechanical energy, chemical energy, sound energy, etc. On the other hand, the term Energy Transformation is used when energy changes forms from one form to another. Whether the                                                                    energy is transferred or transformed, the total amount of energy doesn’t change and this is known as the Law of Conservation of Energy.

Explanation:

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Answer:

4.44m/s

Explanation:

Given parameters:

Number of laps  = 4

Length of track  = 400m

Time taken  = 6min

Unknown:

Average speed  = ?

Solution:

The average speed is the total distance covered divided by the time taken.

It is mathematically expressed as;

  Average speed  = \(\frac{total distance}{time taken}\)  

Total distance  = number of laps x length of track  = 4 x 400  = 1600m

Now convert the time to seconds;

         60s  = 1 min

             6 minutes will be 6 x 60 = 360s

So;

  Average speed  = \(\frac{1600}{360}\)  = 4.44m/s

Answer:

give brainliest please

Explanation:

T- lymphocytes or T cells

Answer:

10 m/s

Explanation:

Explanation:

The amount of CD is 35 g, and the amount of AC is 40 g.

Explanation:

AB + CD \rightarrow AC + BDAB+CD→AC+BD

The law of conservation of mass states that in any chemical reaction, the total mass of the reactants must be equal to the total mass of the products.

In this reaction, we know the mass of one reactant (AB, 15 g) and the mass of one product (BD, 10 g). In order to have the same total mass on the left side and on the right side of the equation, the mass of AC must be 5 g more than the mass of CD. We see that the only choice that satisfies this condition is:

The amount of CD is 35 g, and the amount of AC is 40 g.

In fact, if we assume these masses are correct, we have:

- on the reactant side: m(AB)+m(CD)= 15g + 35g = 50g

- on the product side: m(AC)+m(BD)= 40g + 10g = 50g

so, we have the same mass on both sides of the equation, and the law of conservation of mass is satisfied.

Answer:

B is  the answer on edge

Explanation:

B: The amount of CD is 35 g, and the amount of AC is 40 g.

You may assume that seawater has a specific gravity of 1.03 and that the subsea wellhead was 5053 feet below the surface of the Gulf.(a)The gauge pressure in the Gulf at a depth of 5053 ft is approximately is 2319 psig.(b) The estimated specific gravity of the drilling mud is approximately 0.976.(c)The calculated mass fraction of barite in the slurry is approximately -0.0071

To solve the given problems, we need to apply principles of fluid pressure and buoyancy. Let's go through each question:

a. Estimate the gauge pressure (psig) in the Gulf at a depth of 5053 ft

To estimate the gauge pressure at a certain depth in a fluid, we can use the formula:

P = ρgh

where:

P is the pressure,

ρ is the density of the fluid,

g is the acceleration due to gravity,

h is the depth.

In this case, the fluid is seawater, and we're given its specific gravity as 1.03. Since specific gravity is the ratio of the density of a substance to the density of a reference substance (in this case, water), we can calculate the density of seawater:

ρ_seawater = ρ_water × SG_seawater

where:

ρ_seawater is the density of seawater,

ρ_water is the density of water (1000 kg/m³),

SG_seawater is the specific gravity of seawater (1.03).

Plugging in the values, we have:

ρ_seawater = 1000 kg/m³ × 1.03 = 1030 kg/m³

Next, we need to convert the depth from feet to meters:

h = 5053 ft × 0.3048 m/ft = 1540.27 m

Now we can calculate the gauge pressure:

P = ρgh = 1030 kg/m³ × 9.8 m/s² × 1540.27 m = 1.6 x 10^7 Pa

To convert the pressure from Pascals (Pa) to pounds per square inch gauge (psig), we can use the conversion factor:

1 psig = 6894.76 Pa

Therefore, the gauge pressure in the Gulf at a depth of 5053 ft is approximately:

P = 1.6 x 10^7 Pa / 6894.76 Pa/psig ≈ 2319 psig

b. Estimate the specific gravity of the drilling mud.

To estimate the specific gravity of the drilling mud, we can use the principle of balancing pressures between the Gulf surface and the wellhead. Since the pressure inside the wellhead is given as 4400 psig, the pressure at the Gulf surface must also be 4400 psig to achieve equilibrium.

Using the same formula as before:

P = ρgh

Let's assume the specific gravity of the drilling mud as SG_mud.

The pressure at the Gulf surface can be calculated as:

P_surface = ρ_seawater × g × h

The pressure difference between the Gulf surface and the wellhead is:

ΔP = P_surface - P_wellhead

Since ΔP = 4400 psig, we have:

4400 psig = ρ_seawater × g × h - ρ_mud × g × h

We can rearrange the equation to solve for SG_mud:

SG_mud = (ρ_seawater × g × h - 4400 psig) / (ρ_seawater × g × h)

Plugging in the known values:

SG_mud = (1030 kg/m³ × 9.8 m/s² × 1540.27 m - 4400 psig) / (1030 kg/m³ × 9.8 m/s² × 1540.27 m)

Calculating the specific gravity of the drilling mud:

SG_mud ≈ 0.976

Therefore, the estimated specific gravity of the drilling mud is approximately 0.976.

c. Calculate the mass fraction of barite in the slurry.

To calculate the mass fraction of barite in the slurry, we need to consider the specific gravity of barite and the specific gravity of the mud (which we estimated to be 0.976).

The formula for calculating the mass fraction is:

mass fraction = (SG_mud - SG_water) / (SG_barite - SG_water)

Given that SG_water is 1 and SG_barite is 4.37, we can substitute these values into the formula:

mass fraction = (0.976 - 1) / (4.37 - 1)

Calculating the mass fraction:

mass fraction ≈ -0.024 / 3.37 ≈ -0.0071

The calculated mass fraction of barite in the slurry is approximately -0.0071.

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