which of the following has a particles in most irregular pattern​

(a) The projectile remains in the air for approximately 20 seconds.

(b) The horizontal distance from the firing point to where it strikes the ground is approximately 7,200 meters.

(c) The magnitude of the vertical component of its velocity as it strikes the ground is approximately 0 m/s.

(a) To calculate the time of flight, we can use the equation for vertical motion under constant acceleration:

\(\[y = y_0 + v_{0y}t - \frac{1}{2}gt^2\]\)

Where:

-y is the vertical displacement (equal to -36.0 m, as it is below the initial height)

-\(\(y_0\)\) is the initial vertical position (36.0 m)

- \(\(v_{0y}\)\) is the initial vertical velocity (0 m/s, since it starts from rest vertically)

- g is the acceleration due to gravity (-9.8 m/s^2, assuming no air resistance)

- t is the time of flight

By substituting the given values, we can solve for \(t\). Rearranging the equation, we get:

\(\[-36 = 36t - \frac{1}{2} \cdot 9.8 \cdot t^2\]\)

This is a quadratic equation, which can be solved using the quadratic formula. The positive root of the equation gives the time of flight, which is approximately 20 seconds.

(b) To find the horizontal distance traveled by the projectile, we can use the equation for horizontal motion:

\(\[x = v_{0x}t\]\)

Where:

- x is the horizontal distance

-\(\(v_{0x}\)\) is the initial horizontal velocity (360 m/s, assuming no air resistance)

- t is the time of flight

Substituting the given values, we get:

\(\[x = 360 \cdot 20 = 7200\] meters\)

Therefore, the horizontal distance from the firing point to where it strikes the ground is approximately 7,200 meters.

(c) At the moment the projectile strikes the ground, its vertical velocity will be solely due to the acceleration of gravity. Therefore, the magnitude of the vertical component of its velocity is given by:

\(\[|v_{y}| = |v_{0y} - gt|\]\)

Substituting the known values:

\(\[|v_{y}| = 0 - 9.8 \cdot 20 = 0\] m/s\)

Thus, the magnitude of the vertical component of its velocity as it strikes the ground is approximately 0 m/s.

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The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:1. Width of the slit. 2. Distance between slits. 3. Distance between slits and screen. 4. Wavelength of the incident light. 5. Refractive index of the medium.

The factors that can change the pattern observed on a screen during Young's double-slit experiment are given below:

1. Width of the slit. The width of the slit can influence the diffraction pattern that is observed on a screen. When the width of the slit decreases, the central maximum of the diffraction pattern becomes broader, and the intensity of the secondary maxima reduces.

2. Distance between slits. The distance between the slits in the double-slit experiment also affects the pattern on the screen. The distance between the slits is equal to the spacing between the maxima. If the spacing between the slits decreases, the distance between the maxima decreases, and vice versa.

3. Distance between slits and screen. The distance between the slits and the screen is also a factor that can affect the diffraction pattern. When the distance increases, the spacing between the maxima becomes wider, and the intensity of the maxima decreases.

4. Wavelength of the incident light. The wavelength of the incident light is another factor that affects the diffraction pattern on the screen. When the wavelength increases, the spacing between the maxima increases, and vice versa.

5. Refractive index of the medium. The refractive index of the medium in which the light travels can also influence the diffraction pattern observed on a screen.

When the refractive index of the medium changes, the position of the maxima changes as well. These are the factors that can change the pattern observed on a screen during Young's double-slit experiment.

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The sets of two charges experiencing the strongest attraction are charges of +2 C and -2 C, separated by 1 m and charges of +2 C and +2 C, separated by 1 m. Options A and C.

The strength of the attraction between two charges depends on the magnitudes of the charges and the distance between them, as described by Coulomb's law.

F = \(kq_1 q_2/ r^2\)

where

Using this formula, we can calculate the force between each pair of charges and compare the results:

Charges of +2 C and -2 C, separated by 1 m.

   F = (9 x \(10^9\)) x (2) x (2) / (\(1^2\)) = 3.6 x \(10^{10\) N

Charges of +1 C and -3 C, separated by 1 m.

     F = (9 x \(10^9\) ) x (1) x (3) / (\(1^2\)) = 2.7 x \(10^{10\) N

Charges of +2 C and +2 C, separated by 1 m.

     F = (9 x \(10^9\)) x (2) x (2) / (\(1^2\)) = 3.6 x \(10^{10\) N

Charges of +1 C and +3 C, separated by 1 m.

     F = (9 x \(10^9\)) x (1) x (3) /  (\(1^2\)) = 2.7 x \(10^{10\) N

Therefore, options A and C have the strongest attraction, as they have the largest force of 3.6 x \(10^{10\) N between their charges of the same magnitude but opposite sign.

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Reflection is the process of thinking about something and analyzing it in relation to one's own experiences and perspectives.

In the context of the law of acceleration, this means considering how this law affects our everyday lives and the decisions we make.

One way that the law of acceleration relates to my life is through my use of technology. The law of acceleration states that an object's acceleration is directly proportional to the net force acting on it and inversely proportional to its mass.

This means that as technology becomes more advanced and lighter in weight, it also becomes faster and more efficient. This directly affects my daily life, as I rely on technology for communication, entertainment, and work.

Another way that the law of acceleration relates to my life is through my experiences with transportation. Whether I am driving a car, riding a bike, or taking public transit, the law of acceleration is at play. Understanding how acceleration works allows me to make informed decisions about how to safely and efficiently get from one place to another.

Overall, the law of acceleration is a fundamental principle that affects many aspects of our daily lives. By reflecting on how it relates to my own life, I can better understand the world around me and make more informed decisions.

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Answer:

For every action, there is an equal and opposite reaction

Explanation:

Newton's Third Law of Motion states "To every action, there is an equal and opposite reaction; action and reaction forces act on different bodies".

a) The scale would show an apparent weight of 961.0N  ; b) Scale would show an apparent weight of 435.8N.

Rate at which velocity of any object changes with time is called acceleration and it is vector quantity.

a. When the elevator starts to accelerate upwards at 3.0m/s², apparent weight of the person on scale will be:

Apparent weight = (mass of the person) x (acceleration due to gravity + acceleration of the elevator)

= 75kg x (9.81m/s² + 3.0m/s²)

= 75kg x 12.81m/s²

Apparent weight = 961.0N

Therefore, scale would show an apparent weight of 961.0N.

b. When the elevator starts to accelerate downwards at 4.0m/s², apparent weight of the person on the scale will be:

Apparent weight = (mass of the person) x (acceleration due to gravity - acceleration of the elevator)

= 75kg x (9.81m/s² - 4.0m/s²)

= 75kg x 5.81m/s²

Apparent weight = 435.8N

Therefore, scale would show an apparent weight of 435.8N.

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For long-distance CW (Continuous Wave) and SSB (Single Sideband) contacts on VHF (Very High Frequency) and UHF (Ultra High Frequency) bands, the commonly used antenna polarization is horizontal polarization.

Horizontal polarization refers to the orientation of the electromagnetic waves' electric field component, which is parallel to the Earth's surface.

This polarization is typically preferred for long-distance communication because it helps minimize the effects of signal reflections and interference caused by natural and man-made obstacles.

When communicating over long distances, horizontal polarization helps in achieving better ground wave propagation and reduces the impact of signal absorption by vegetation, buildings, and other objects. It also helps in reducing multipath interference, where signals can bounce off various surfaces and reach the receiver through different paths, causing signal degradation.

While horizontal polarization is generally favored for long-distance VHF and UHF communication, it's important to note that there can be exceptions or variations in specific situations. Factors such as terrain, antenna height, atmospheric conditions, and local regulations can influence the choice of antenna polarization.

Therefore, it's always advisable to consult local hams and reference sources for the most accurate and up-to-date information regarding antenna polarization in your specific location.

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Answer:

Yeah it's right there from the one next to the exclamation point

Answer:

its not there

Explanation:

its literally not there

Answer:

Explanation:

The mass of the person can be found by using the formula

\(m = \frac{p}{v} \\ \)

p is the momentum

v is the velocity

From the question we have

\(m = \frac{52}{0.8} \\ \)

We have the final answer as

Hope this helps you

Answer:

D. Electrons mover from one to another

Explanation:

Static electricity occurs when electrons are transferred from one object to another.

The wavelength of the incident light is approximately 9.23 x 10^(-8) m, or 92.3 nm and the next set of bright fringes appears at an angle of approximately 0.384 degrees.

(a) To find the wavelength of the incident light, we can use the formula for the fringe spacing in a double-slit interference pattern:

λ = (d * m) / D

where λ is the wavelength of light, d is the slit separation, m is the order of the fringe, and D is the distance between the slits and the screen.

Given that the distance between the central bright fringe and adjacent bright fringes (m = 1) is 1.37 cm (or 0.0137 m), the slit separation is 0.240 mm (or 0.000240 m), and the screen distance is 2.60 m, we can rearrange the formula and solve for the wavelength (λ):

λ = (d * m) / D

λ = (0.000240 m * 1) / 2.60 m

λ = 9.23 x 10^(-8) m

Therefore, the wavelength of the incident light is approximately 9.23 x 10^(-8) m, or 92.3 nm.

(b) To determine the angle at which the next set of bright fringes appear, we can use the small-angle approximation:

θ = (m * λ) / d

Here, θ represents the angle between the central maximum and the first-order maximum, m is the order of the fringe, λ is the wavelength, and d is the slit separation.

Since we want to find the angle for the next set of bright fringes (m = 2), we can substitute the values:

θ = (2 * 9.23 x 10^(-8) m) / 0.000240 m

θ ≈ 0.384 degrees

Therefore, the next set of bright fringes appears at an angle of approximately 0.384 degrees.

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Answer:

The point at which the electrical potential is zero is x = +0.33 m.

Explanation:

By definition the electrical potential is:

\( V_{E} = \frac{K*q}{r} \)

Where:

K: is Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

r: is the distance

The point at which the electrical potential is zero can be calculated as follows:

\( V_{1} + V_{2} = 0 \)

\( K(\frac{q_{1}}{r_{1}} + \frac{q_{2}}{r_{2}}) = 0 \)    (1)

q₁ is the first charge = +3 mC

r₁ is the distance from the point to the first charge  

q₂ is the first charge = -6 mC

r₂ is the distance from the point to the second charge    

By replacing r₁ = 1 - r₂ into equation (1) we have:

\(K(\frac{q_{1}}{1 - r_{2}} + \frac{q_{2}}{r_{2}}) = 0\)   (2)

By solving equation (2) for r₂:

\(r_{2} = \frac{q_{1}}{q_{1} - q_{2}} = \frac{3 mC}{3 mC - (-6 mC)} = +0.33 m\)

Therefore, the point at which the electrical potential is zero is x = +0.33 m.

I hope it helps you!  

Since the two charges are placed on the x-axis. Then, the electric potential is zero at the distance of 0.66 m from the second point charge on the x-axis.

The electric potential at any point is the amount of work needed to move a unit positive charge from infinity to that point.

Given data-

The magnitude of a point charge is, Q = + 3 C.

The magnitude of the second point charge is, Q' = -6 C.

The distance between the two charges is, x = 1.0 m.

The expression for the net electric potential due to both the charges is,

\(V = \dfrac{k \times Q}{x} +\dfrac{k \times Q'}{x-y}\)

here,

k is the Coulomb's constant.

y is the distance from the second point charge on the x-axis, where the net potential is zero.

Now, for zero net electric potential due to both the charges we have,

\(0 = \dfrac{k \times Q}{x-y} +\dfrac{k \times Q'}{y}\\\\\\-\dfrac{k \times Q'}{y}=\dfrac{k \times Q}{x-y}\)

Solving as,

\(-\dfrac{(-6)}{y}=\dfrac{3}{1-y}\\\\6-6y=3y\\\\y =0.66\;\rm m\)

Thus, we can conclude that the electric potential is zero at the distance of 0.66 m from the second point charge on the x-axis.

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The several forms of businesses that exists in our current world include;

A business refers to a commercial activity that an individual or organization engage in which may involve other activities which support the main activity of the business.

When the word business is heard, what usually comes to mind is the activity that occurs in stores which involves buying and selling of produce and goods.

However, several forms of businesses exists such as;

In conclusion, the sole aim of a business is to make profit whether it involves commercial activities or not.

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Answer:

V = 0.87 volt

Explanation:

Given that,

Charge, \(q=7.3\times 10^{-17}\ C\)

Electric potential energy, \(U=6.4\times 10^{-17}\ J\)

We need to find the value of electric potential at a point. The relation is as follows :

\(V=\dfrac{U}{q}\)

Where

V is electric potential

So,

\(V=\dfrac{6.4\times 10^{-17}}{7.3\times 10^{-17}}\\\\V=0.87\ V\)

So, the value of the electric potential at a point is equal to 0.87 Volts.

Answer:

Aluminium

Explanation:

The heat capacity for Aluminium is greatest and so it retains heat longer hence its the best conductor of heat.

The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is 1166.67kg.

The word "force" has a clear definition. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

The vector sum of the forces exerted on a particle or object is known as the net force. The original forces' impact on the motion of the particle is replaced by the net force, which is a single force.

Force ( F ) is 2100N

Acceleration ( a ) is 1.8m/s²

Mass(m)= ?

According to formula;

Force = mass × acceleration

F= m × a

2100 = m × 1.8

2100 / 1.8 = m

Therefore, m = 1166.6kg.

Thus, The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is  1166.67kg.

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a). The charge on the coin was produced by transferring about 1.6 x \(10^{10}\) electrons. b). This finding suggests that the transferred electrons only slightly reduce the mass of the coin.

a).One electron possesses a charge of -1.6 × \(10^{-19}\) C. We can use the formula: to calculate the number of electrons transported.

Q = ne

where e is the charge on one electron, n is the number of electrons, and Q is the total charge.

n = Q/e = (-2.6 × \(10^{-9}\) C)/(-1.6 ×\(10^{-19}\) C) 1.6 × \(10^{10}\) electrons.

b) The average mass of an electron is 9.11 × \(10^{-31}\) kg. You can calculate the transferred electrons' overall mass as follows:

m = n x me

where me is the mass of one electron, me is the mass of the transferred electrons, and n is the number of electrons.

The formula for m is (1.6 × \(10^{10}\)) × (9.11 × \(10^{-31}\) kg) 1.46 × \(10^{-20}\) kg.

The mass of a coin at rest is 2.5 g, or 2.5 × \(10^{-3}\) kg. The mass change as a percentage is thus:

(m/m0 - 1) x 100% of m/m0 equals [(1.46 × \(10^{-20}\) kg)/(2.5 × \(10^{-3}\) kg) - 1] × 100% ≈ -5.8 × \(10^{-17}\)%.

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Using this data the quantity which is trying to find is average speed.Thus, option C is correct.

Average speed is defined as the total distance traveled in total time taken it means that we can calculate the average speed obtained by an object.

Mathematically,

Average Speed = Total distance travelled/Total time taken

It's S.I unit is meter/second

Average speed is a scaler quantity it means that it has only magnitude not direction. MKS is refers to meter, kilogram, seconds. It forms the base of international systems of units though SI has since been redefined by different fundamental constants.

Therefore, Using this data the quantity which is trying to find is average speed.Thus, option C is correct.

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The raising and lifting the ball by kicking is a B) Scoop

Answer:

the last one

Explanation:

its the sun when the earth turns towards the sun it gives us heat not solar radiation.

The approximate image distance (di) of the passing moon when reflected off the highly reflective coating on the spherical convex mirror is approximately 0.0286 km, or 28.6 meters.

To determine the image distance of the passing moon when reflected off the highly reflective coating on the spherical convex mirror (the large moon with a diameter of 70.0 km), we can use the mirror equation:

1/f = 1/do + 1/di,

where f is the focal length, do is the object distance, and di is the image distance.

Since we are dealing with a convex mirror, the focal length (f) is positive. For a spherical convex mirror, the focal length is half the radius of curvature (R). However, the radius of curvature is not given in the information provided, so we cannot directly calculate the focal length.

However, we can make use of the fact that a convex mirror always produces a virtual image. In this case, the image distance (di) will be negative, indicating a virtual image formed behind the mirror.

Given:

Diameter of large moon = 70.0 km

Distance of passing moon = 1.00 × 10? km

Since the distance of the passing moon is much greater than the diameter of the large moon, we can approximate the object distance (do) as the distance of the passing moon (1.00 × 10? km).

Substituting these values into the mirror equation:

1/f = 1/do + 1/di,

we can rearrange the equation to solve for the image distance (di):

1/di = 1/f - 1/do.

Since a convex mirror has a positive focal length and we have a virtual image, the term 1/f will be positive and 1/do will be negative.

Substituting the values and performing the calculations:

1/di = 1/f - 1/do

= 1/2f - 1/do

≈ 1/2f (assuming 1/do is negligible compared to 1/2f)

Now, we need to determine the approximate value of 1/2f. Since we don't have the radius of curvature or focal length information, we cannot calculate an exact value. However, we can make an estimation based on the given information.

Assuming the large moon is roughly spherical, we can consider its diameter of 70.0 km as the approximate diameter of its curvature. The radius of curvature (R) would be half the diameter, or 35.0 km.

Since the focal length (f) of a spherical convex mirror is half the radius of curvature, we can estimate the focal length as 17.5 km.

Substituting this estimated value into the equation:

1/di ≈ 1/2f

= 1/(2 * 17.5 km)

≈ 1/35.0 km^-1

= 0.0286 km^-1.

Therefore, the approximate image distance (di) of the passing moon when reflected off the highly reflective coating on the spherical convex mirror is approximately 0.0286 km, or 28.6 meters.

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Answer:

Bananas go through a process called ‘negative geotropism’ so they can reach the sun

The car's deceleration is 3 miles per hour per second (mph/s).

To calculate the acceleration, you can use the following formula:

Acceleration = (Final Velocity - Initial Velocity) / Time

Given the initial velocity (u) as 50 mph, the final velocity (v) as 35 mph, and the time (t) as 5 seconds:

Initial Velocity (u) = 50 mph

Final Velocity (v) = 35 mph

Time (t) = 5 seconds

Acceleration = (35 mph - 50 mph) / 5 seconds

Acceleration = (-15 mph) / 5 seconds

Acceleration = -3 mph/s

The negative sign indicates deceleration.

Therefore, the car's deceleration is 3 miles per hour per second (mph/s).

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The magnitude of the force the garbage exerts on the floor of the service elevator is 109.8 N.

To find the magnitude of the force exerted by the garbage on the floor of the elevator, we need to use Newton's second law of motion, which states that the force exerted on an object is equal to its mass multiplied by its acceleration. In this case, the mass of the garbage is 9 kg and the acceleration is 1.4 m/s2. Therefore, the force exerted by the garbage on the floor of the elevator can be calculated as follows:
Force = Mass x Acceleration
Force = 9 kg x 1.4 m/s2
Force = 12.6 N/kg x 9 kg
Force = 109.8 N
Therefore, the magnitude of the force the garbage exerts on the floor of the service elevator is 109.8 N.

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Use newton's second law: net force = m*a

in this case, m is 20kg and a is g. The net Force would be 196 Newtons

The correct unit used to measure the electric potential difference is Volts.

Joules is used to measure energy.

Newtons is used to measure forces.

Centimeters is used to measure distance.

Therefore the correct option is the first one.

Answer:

a plumber

Explanation:

A hollow metal cylinder has inner radius a, outer radius b, length l, and conductivity σ. the current i is radially outward from the inner surface to the outer surface, the electric field is zero.

In a hollow metal cylinder with inner radius "a," outer radius "b," length "l," and conductivity "σ," if a current "i" is flowing radially outward from the inner surface to the outer surface, the following information can be derived:

1. Electric Field: The electric field inside a conductor in electrostatic equilibrium is zero. Therefore, the electric field inside the hollow metal cylinder is zero.

2. Current Density: The current density "J" can be defined as the current per unit area perpendicular to the direction of current flow. In this case, since the current is flowing radially outward, the current density is also radially outward and is constant throughout the cylinder.

3. Ampere's Law: Ampere's law states that the line integral of the magnetic field around a closed loop is equal to the product of the enclosed current and the permeability of free space. Since the current is radially outward, the magnetic field lines are concentric circles around the axis of the cylinder.

4. Resistance: The resistance "R" of the hollow metal cylinder can be determined using the formula:

R = (ρ * l) / (A)

where ρ is the resistivity of the material (which is the reciprocal of conductivity σ), "l" is the length of the cylinder, and "A" is the cross-sectional area of the cylinder.

Please note that if the cylinder is not in electrostatic equilibrium and there are time-varying currents, additional considerations such as displacement current and magnetic fields induced by changing electric fields would come into play.

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Answer:

A. a total solar eclipse

Explanation:

During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth

The direction of the net electric field at point P is the vector sum of the electric fields of the two charges.

To determine the direction, use the law of cosines to calculate the angle between the two electric fields and add it to the direction of the first electric field. The angle is measured counterclockwise from the x-axis.

The electric field at any point due to a point charge is given by E = kq/r2, where k is the Coulomb’s constant, q is the charge and r is the distance from the charge. By summing the electric fields of the two charges, we can obtain the net electric field at point P.

This net electric field is the vector sum of the two electric fields, and its direction can be determined by using the law of cosines to calculate the angle between the two electric fields and adding it to the direction of the first electric field. The angle between the two electric fields is measured counterclockwise from the x-axis, and thus the direction of the net electric field at point P is the sum of this angle and the direction of the first electric field.

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