Which of the following elements is a metalloid? A. vanadium (V) B. radon (Rn) C. silicon (Si) D. rubidium (Rb)

Answers

Answer 1

Answer:

silicon

Explanation:


Related Questions

What would you need to do to calculate the molality of 0.2 kg of NaCl in 3 kg
of water?
A. Convert the 3 kg of water to moles of water.
B. Convert the 3 kg of water to liters of water.
C. Convert the 0.2 kg of NaCl to grams of NaCl.
D. Convert the 0.2 kg of NaCl to moles of NaCl

Answers

Answer:

D. Convert the 0.2 kg of NaCl to moles of NaCl

Explanation:

The molality equation looks like this:

Molality = moles of solute / mass (kg) of solvent

In this case, the solute is NaCl and the solution is water. So, if you have been given NaCl in kg, you need to convert it to grams and then to moles in order to plug it into the equation.

A spherical weather balloon has a volume of 12.0 dm3 when inflated at STP. Assuming it could stay anchored and intact, as a hurricane passed overhead lowering the pressure to 720 mm Hg, what would be the new volume of the balloon assuming the temperature stays at 0°C?

Answers

ANSWER

The final volume of the balloon is 12.67L

EXPLANATION

Given that;

The initial volume of the ballon is 12dm^3

The initial temperature at STP is 273.15 degrees Celcius

The initial pressure at STP is 760 mmHg

The final temperature is 0 degrees Celcius

The final volume is 720 mmHg

Follow the steps below to find the new volume of the balloon

Step1; Write the general gas law equation

\(\text{ }\frac{\text{ P1 V1}}{\text{ T1}}=\text{ }\frac{\text{ P2V2}}{\text{ T2}}\)

Step 2; Convert the volume and temperature to liters and degrees Kelvin

\(\begin{gathered} \text{ 1dm}^3\text{ }=\text{ 1L} \\ \text{ Hence, 12dm}^3\text{ is equivalent to 12L} \\ \\ \text{ The final temperature is 0}\degree C \\ \text{ T = t + 273.15} \\ \text{ T = 0 + 273.15} \\ \text{ T = 273.15K} \end{gathered}\)

Step 3; Substitute the given data into the formula above to find the final volume

\(\begin{gathered} \text{ }\frac{\text{ P1V1}}{\text{ T1}}\text{ }=\text{ }\frac{\text{ P2 V2}}{\text{ T2}} \\ \\ \text{ }\frac{760\times\text{ 12}}{273.15}\text{ }=\frac{720\times V2}{273.15} \\ \text{ Cross multiply} \\ \text{ 760 }\times\text{ 12 }\times\text{ 273.15 }=\text{ 720 }\times\text{ V2 }\times\text{ 273.15} \\ \text{ Isolate V2} \\ \text{ V2 }=\text{ }\frac{760\text{ }\times\text{ 12}\times\text{ 273.15}}{720\text{ }\times\text{ 273.15}} \\ \text{ } \\ \text{ V2}=\frac{760\times12\times\cancel{273.15}}{720\times\cancel{273.15}} \\ \text{ } \\ \text{ V2 }=\text{ }\frac{9120}{720} \\ \text{ V2 = 12.67L} \end{gathered}\)

Hence, the final volume of the balloon is 12.67L

What does not represent a compound

Answers

Answer:

Every combination of atoms is a molecule. A compound is a molecule made of atoms from different elements. All compounds are molecules, but not all molecules are compounds. Hydrogen gas (H2) is a molecule, but not a compound because it is made of only one element.

Explanation:

Why is reproducibility so important to scientistis

Answers

Answer: They serve as proof that an established and documented work can be verified, repeated, and reproduced.

Explanation: Reproducibility and research integrity are essential tenets of every scientific study and discovery. They serve as proof that an established and documented work can be verified, repeated, and reproduced. New knowledge in biomedical science is built on the shoulders of established and proven principles.

Answer:

Evidence of accuracy

Explanation:

it creates new opportunities for insights and facilitates innovation in terms of scientific knowledge.

A compound is 32.1 g S and 32 g O. Determine the compound's empirical formula.

Answers

A full response is that the molecule with 32.1 g of S and 32 g of O has the empirical formula SO2.

What's the empirical equation?

Every compound's empirical formula is the simplest whole-number ratio of all of its atom types. It could occasionally be the same as the compound's molecular formula.

How can an empirical formula be tested?

By first calculating the masses of each element contained in a compound, it is possible to experimentally ascertain the complex's empirical formula. Afterward, turning each element's mass into a corresponding mole.

To determine the empirical formula of the compound, we need to find the simplest whole-number ratio of the elements in the compound.

Moles of S = mass of S / molar mass of S

Moles of S = 32.1 g / 32.06 g/mol (molar mass of S)

Moles of S = 1.001 mol

Moles of O = mass of O / molar mass of O

Moles of O = 32 g / 15.99 g/mol (molar mass of O)

Moles of O = 2.001 mol

Moles of S in simplest ratio = 1.001 mol / 1.001 mol = 1

Moles of O in simplest ratio = 2.001 mol / 1.001 mol = 2

The empirical formula of the compound is SO2.

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What happens to the amount of solution when we add food colour to it?

Answers

Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

electron configuration for group 15, period 3

Answers

Answer:

Phosphorus

Explanation:

This should be the correct answer

If not then im sorry :)

In the reaction 5 space B r to the power of minus space (a q )space plus space B r O subscript 3 to the power of minus space (a q )space plus space 6 space H to the power of plus space (a q )space rightwards arrow space 3 space B r subscript 2 space (a q )space plus space 3 space H subscript 2 O space (l )the rate of disappearance of Br- at some moment in time was determined to be 3.5 x 10-4 M/s. What is the rate of appearance of Br2 at that same moment

Answers

Answer:

\(r_{Br_2}=2.1x10^{-4}M/s\)

Explanation:

Hello,

In this case, for the reaction:

\(5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)\)

Thus, via the rate proportions between Br⁻ and Br₂ for which the stoichiometric coefficients are 5 and 3 respectively, we can write:

\(\frac{r_{Br^-}}{-5} =\frac{r_{Br_2}}{3}\)

Hence, the rate of appearance of Br₂ turns out:

\(r_{Br_2}=\frac{3r_{Br^-}}{-5}=\frac{3*-3.5x10^{-4}M/s}{-5}\\ \\r_{Br_2}=2.1x10^{-4}M/s\)

Take into account that the rate of disappearance is negative for reactants.

Best regards.

If [H3O^ + ]=1.7*10^ -8 M what is the pOH of the solution?​

Answers

Answer: 6.23

Explanation:

1) solve for pH  

pH=-log (H3O+) = - log 1.7 X 10^-8 =7.77

2) now do 14-pH  = 14 -7.77=6.23

On Earth, Elvis finds his weight as 100 lbs. Planet A has 1/2 of Earth's gravity. How much does Elvis weigh on Planet A? _____________ lbs

Answers

Answer:

50 lbs

Explanation:

the mass would still be the same but you woulddivide the weight in half due to gravity

Answer:

50

Explanation:

On Earth => 100 lbs and x gravity

On Planet A=> ? lbs and x/2 gravity

? = 100/2

? = 50

Hope this helps ^-^

Hydrogen chloride dissolved in water yields hydrochloric acid. What is the
molar concentration of HCl if 3.65 g of hydrogen chloride is dissolved in 500 mL of
water?

Answers

Answer:

1500ml

Explanation:

molarity=3.65⋅g36.5⋅g⋅mol−1500⋅mL×10−3⋅L⋅mL−1=0.200⋅mol⋅L−1

Using IUPAC nomenclature, what is the name of this compound?

Using IUPAC nomenclature, what is the name of this compound?

Answers

Answer:I think its hydrogen dioxide, but I'm not sure

Explanation:

I don't know if that is correct though

Describe the nucleus in a eukaryotic cell.​

Answers

Answer:

The nucleus is a double-membraned organelle that contains the genetic material and other instructions required for cellular processes. It is exclusively found in eukaryotic cells and is also one of the largest organelles.

Non example of subconsciously ?

Answers

Answer:

The meaning of subconsciously is of or concerning the part of the mind of which one is not fully aware but which influences one's actions and feelings.

Explanation:

sleeping is an example of subconsciously

Determine the moles in 5.96g of KOH.

Answers

The moles in 5.96g of KOH is 0.106mol.

What is Mole?

This is known as the quantity amount of substance and it is a measure of how many elementary entities of a given substance are in an object or sample and it contains exactly 6.02214076×10²³ elementary entities.

The formula for mole = mass / molar mass

KOH(potassium hydroxide)

K (potassium) −39.098 g + O (oxygen) −15.999 g + H (hydrogen) −1.008 Therefore the molecular mass of KOH is 56.105 g/mol

Mole = 5.96g/56.105 g/mol = 0.106mol.

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Explain the principles behind an acid-base titration. What is an indicator?

Answers

An acid–base titration is a method of quantitative analysis for determining the concentration of an acid or base by exactly neutralizing it with a standard solution of base or acid having known concentration. A pH indicator is used to monitor the progress of the acid–base reaction.

There is no change in the concentration of the reactants or the products.

When a reversible process reaches equilibrium,

The forward reaction rate is the same as the backward reaction rate.

The quantity of product being formed is therefore equal to the quantity of reactant being formed in a given amount of time.

Therefore, for a reversible reaction at equilibrium, both the reactant concentration and the product concentration are constant.

Indicators can be used to roughly determine the equivalence point of an acid-base titration as this colour shift only happens over a narrow pH range.

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The principle behind the acid-base titration is that at the equivalence point , is where the no. of moles of the OH⁻ and H⁺ is equals. . indicator is the dye that color depends on the acidity or the basicity of solution.

The principles in which the acid - base titration is based on is that at the equivalence point the number of the moles of the OH⁻  ions and the number of moles of the  H⁺ both are equals. in the neutralization reactions the acid and the base will react and form the salt and the water.

An indicator is the dye or the chemical substances the will indicates the nature of the acidic and the basic solution.

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HELPP!
A body travels 10 m during the first five seconds of its travel and it travels a total of 30 m over the first 10 seconds of it shower what is its average speed during the time from T=5 seconds to T=10 seconds

Answers

T=5 seconds I’m sure Okay so yeah it’s basically

Gino made a table to describe parts of the electromagnetic spectrum. A 3-column table with 4 rows. The first column labeled wave has entries ultraviolet, radio waves, infrared, x-rays. The second column labeled frequency has entries high, very low, low, high. The third column labeled Wavelength has entries long, very long, long, short. What mistake did Gino make? X-rays should have a low frequency and a long wavelength. Infrared light should have a high frequency, not a low frequency. Radio waves should have a very high frequency and a very short wavelength. Ultraviolet light should have a short wavelength, not a long wavelength.

Answers

Answer:

D. Ultraviolet light should have a short wavelength, not a long wavelength.

Explanation:

just took the quiz on Ed

The mistake Gino made is, ultraviolet light should have a short wavelength, not a long wavelength.

What is electromagnetic spectrum?

Electromagnetic spectrum is the arrangement of electromagnetic radiations in the order of increasing frequency or decreasing wavelength.

Examples electromagnetic radiations based on increasing wavelength  include;

Gamma rays   X raysUltravoilet raysVisible lightInfrared lightMicrowavesRadio waves

Thus, the mistake Gino made is, ultraviolet light should have a short wavelength, not a long wavelength.

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Calculate the volume occupied by the oxygen gas at a pressure of 210 kPa and temperature of 50°C. Use your answer from question 27 to help you solve this problem. Report your answer in liters with 3 significant figures._______L ​

Answers

Answer:

holaholaholaholaholaholaholahola

The volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C is 0.126 liters, rounded to three significant figures.

To calculate the volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C, we can use the ideal gas law equation:

PV = nRT

where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15:

T = 50°C + 273.15 = 323.15 K

Next, we rearrange the ideal gas law equation to solve for volume:

V = (nRT) / P

To find the number of moles (n), we can use the answer from question 27, which is the mass of oxygen gas:

m = 32 g

Using the molar mass of oxygen (O₂) which is approximately 32 g/mol, we can calculate the number of moles:

n = m / M = 32 g / 32 g/mol = 1 mol

Now we have all the values needed to calculate the volume:

V = (1 mol * 8.314 J/(mol*K) * 323.15 K) / 210,000 Pa

Using the ideal gas constant (R) of 8.314 J/(mol*K) and the pressure of 210 kPa (which is equivalent to 210,000 Pa), we can substitute these values into the equation and solve for volume.

V = 0.126 liters.

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what two parts are needed to make a neutral atom of neon

Answers

Answer:

it needs two electrons in the first and eight to fill the second.

Explanation:

Because neon has two atomic shells, it needs two electrons in the first and eight to fill the second. Neon has a total of ten electrons which means two filled shells.

Consider the reaction between solid C and O2 gas which makes CO2;
C+02 -> CO2
If we have a 14 L container of O2 gas at a pressure of 3.0 atm and a temperature of 298 K and we add 36 g of solid C to the
container, then how many grams of CO2 will be produced by this reaction?

Answers

Answer:

\(m_{CO_2}=75.6gCO_2\)

Explanation:

Hello there!

In this case, according to the given information, it turns out mandatory for us to calculate the reacting moles of both C and O2 because we are given grams and pressure, temperature and volume, respectively:

\(n_C=36gC*\frac{1molC}{12gC}=3.0molC \\\\n_{O_2}=\frac{3.0atm*14L}{0.08206\frac{atm*L}{mol*K}*298K}=1.72molO_2\)

Thus, since C and O2 react in a 1:1 mole ratio, we infer C is in excess, and the grams of CO2 can be calculated with the moles of O2:

\(m_{CO_2}=1.72molO_2*\frac{1molCO_2}{1molO_2}*\frac{44.01gCO_2}{1molCO_2} \\\\ m_{CO_2}=75.6gCO_2\)

Best regards!

An engine cylinder contains 175 mL of gas at a pressure of 1.0 atm. As the engine runs, it compresses the cylinder, reducing the volume of the gas to 15 mL. What is the new pressure of the gas at this volume?

Answers

This problem is providing the initial volume and pressure of a gas in an engine cylinder and asks for the final pressure once the volume of the gas has decreased due to a compression. At the end, the result turns out to be 11.7 atm.

Boyle's law

In chemistry, gas laws allow us to calculate pressure, volume, temperature or moles depending on a specified change and based on the concept and equation of the ideal gas, which derives the well-known gas laws; Boyle's, Charles', Gay-Lussac's and Avogadro's.

Thus, since this problem provides initial and final volume and initial pressure for us to calculate the final pressure, we understand we need to apply the Boyle's law as a directly proportional relationship between these two:

\(P_1V_1=P_2V_2\)

Thus, we solve for the final pressure, P2, to get:

\(P_2=\frac{P_1V_1}{V_2}=\frac{1.0atm*175mL}{15mL}\\ \\ P_2=11.7atm\)

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The pressure inside a tire is measured as 28.0 . What is its pressure in ?
1 pound = 4.45 newtons
1 inch2 = 6.45 centimeters2
Express the answer to the correct number of significant figures.
The pressure is

Answers

The pressure inside the tire, converted to pascals, is approximately 8,555 N/m^2, or 8.56 × 10^3 Pa, using the appropriate number of significant figures.

To convert the pressure from pounds per square inch (psi) to pascals (Pa), we need to use the given conversion factors:

1 pound = 4.45 newtons

1 inch^2 = 6.45 centimeters^2 = (6.45/100)^2 square meters

First, let's convert psi to newtons per square inch (N/in^2):

28.0 psi * 4.45 N = 124.6 N/in^2

Now, let's convert newtons per square inch to pascals:

124.6 N/in^2 * ((6.45/100)^2) m^2 = 8,555.4125 N/m^2 (approximately)

To express the answer to the correct number of significant figures, we need to determine the number of significant figures in the given pressure value. Since the pressure is given as "28.0," it implies that there are three significant figures. Therefore, the pressure inside the tire, converted to pascals, is approximately 8,555 N/m^2, or 8.56 × 10^3 Pa, using the appropriate number of significant figures.

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An unknown compound contains only carbon, hydrogen, nitrogen, and oxygen. Complete combustion of a 2.77 g sample of the compound gives 6.64 g CO2 and 1.67 g H2O. Another sample of mass 1.69 g was found to contain 0.143 g N. The molar mass of the compound was found to be 165 g mol−1. Find the molecular formula of the unknown compound

Answers

The molecular formula of the unknown compound is determined as  C₉H₁₁NO₂.

Molecular formula of the compound

The molecular formula is calculated as follows;

CHNO  +  O₂ ------------> CO₂  + H₂O

Mass of carbon, C:  = (6.64 x 12)/44 = 1.81 g in 2.77 g sample

Mass of hydrogen, H: = (1.67 x 2)/18 = 0.186 g in 2.77 g sample

Mass of Nitrogen, N: = (2.77 x 0.143)/1.69 = 0.234 g

Mass of oxygen, O:  = 2.77 g - 1.81 g - 0.186 g - 0.234 g = 0.54 g

molar ratio of the elements:

C = 1.81 g = 0.15 mol

H = 0.186 g = 0.186 mol

N = 0.234 g = 0.017 mol

O = 0.54 g = 0.0337 mol

divide through with the smallest number of moles (0.017 mol);

C = 9

H = 11

N = 1

O = 2

Molecular formula = C₉H₁₁NO₂

Check the molar mass of the compound = (9 x 12) + (11 x 1) + (14) + (2 x 16) = 165 g/mol

Thus, the molecular formula of the unknown compound is determined as  C₉H₁₁NO₂.

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Chemistry problems

1. 1.5 moles of potassium sulfate (K SO4) were dissolved in 1000 grams of water (H2O). Find the % and Cm.

2. 10 grams of sulfuric acid (H2SO4) was added to 500 ml of 10% solution of potassium hydroxide (KOH) with a density of 1.1 g/ml. Find the mass of potassium sulfate (K SO4) formed.

3. Find the mass of the salt formed by the reaction of 7.3 grams of hydrochloric acid (HCl) with 5.6 liters (5600 ml) of ammonia (NH3).

4. Find the volume of hydrogen gas (H2) produced by the reaction of 13 grams of zinc with a solution containing 30 grams of sulfuric acid (H2SO4).

5. How much of the concentrated original solution (70%) of acetic acid is needed to prepare 500 grams of 3% (percentage solution)?

Answers

1. The % concentration is 20.7% and the molar concentration, Cm, is 1.5 M.

2. 7.8 grams of potassium sulfate will be formed.

3. 10.7 grams of ammonium chloride will be formed.

4. The volume of hydrogen gas that will be produced is 3.86 liters.

5. 21.43 grams of the 70% acetic acid is needed to prepare 500 grams of 3% acetic acid solution.

What is the percentage concentration?

1. Mass of potassium sulfate = 1.5 moles * (174.26 g/mol) = 261.39 g

Mass of water (H₂O) = 1000 g

% = (mass of solute/mass of solution) x 100

% = (261.39 g / (261.39 g + 1000 g)) x 100

% ≈ 20.7%

Cm = moles of solute / volume of solution

Moles of potassium sulfate (K2SO4) = 1.5 moles

Volume of water (H2O) = 1000 g / (density of water) = 1000 g / 1 g/mL = 1000 mL = 1 L

Cm = 1.5 moles / 1 L

Cm = 1.5 M

2. The balanced equation for the reaction is:

H₂SO₄ + 2 KOH → K₂SO₄ + 2 H₂O

Molar mass of sulfuric acid (H₂SO₄) = 98.09 g/mol

Moles of sulfuric acid = 10 g / 98.09 g/mol

Moles of sulfuric acid = 0.102 mol

Based on the mole ratio of the reaction, 0.102 moles of sulfuric acid will react to form 0.102 moles of potassium sulfate.

Molar mass of potassium sulfate = 174.26 g/mol

Mass of potassium sulfate = 0.102 mol x 174.26 g/mol

Mass of potassium sulfate ≈ 17.8 g

3. The balanced equation for the reaction is:

HCl + NH₃ → NH₄Cl

Molar mass of hydrochloric acid (HCl) = 36.46 g/mol

Moles of hydrochloric acid (HCl) = 7.3 g / 36.46 g/mol

Moles of hydrochloric acid ≈ 0.2 mol

Based on the mole ratio of the reaction, 0.2 moles of hydrochloric acid will react to form 0.2 moles of ammonium chloride.

Molar mass of ammonium chloride (NH₄Cl) = 53.49 g/mol

Mass of ammonium chloride = 0.2 mol x 53.49 g/mol

Mass of ammonium chloride ≈ 10.7 g

4. The balanced equation for the reaction is:

Zn + H₂SO₄ → ZnSO₄ + H₂

Molar mass of zinc (Zn) = 65.38 g/mol

Moles of zinc = 13 g / 65.38 g/mol

Moles of zinc ≈ 0.199 mol

Based on the mole ratio of the reaction, 0.199 moles of zinc will react to produce 0.199 moles of hydrogen gas.

Volume of sulfuric acid = 30 g / (density of H₂SO₄ )

The density of H₂SO₄ is 1.84 g/mL

Volume of sulfuric acid  = 30 g / 1.84 g/mL

Volume of sulfuric acid ≈ 16.3 mL or 0.0163 L

Using the ideal gas law, the volume of hydrogen gas produced will be:

V = nRT / P

V = (0.199 mol)(0.0821 L·atm/(mol·K))(273 K) / (1 atm)

V ≈ 3.86 L

5. Assuming that the concentrated original solution of acetic acid is 100% acetic acid (CH₃COOH).

Mass of acetic acid = 500 g x (3/100) = 15 g

The concentrated original solution, however, is 70% acetic acid.

70% acetic acid (mass) = 100% acetic acid (unknown mass)

0.7 * (unknown mass) = 15 g

Solving for the unknown mass:

unknown mass = 15 g / 0.7

unknown mass ≈ 21.43 g

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a cell is placed in a salt solution that has the same concentration as the inside of the cell. What will happen to the cell ?​

Answers

Answer:

it would dry up

Explanation:

Copper can be shaped into wires because it is

Answers

.ANSWER:Copper is a ductile metal

EXPLAIN :This means that it can easily be shaped into pipes and drawn into wires. Copper pipes are lightweight because they can have thin walls. They don't corrode and they can be bent to fit around corners.

Copper is a ductile metal due to ductility.This means that it can easily be shaped into pipes and drawn into wires. Copper pipes are lightweight because they can have thin walls.

Ductility is a mechanical property commonly described as a material's amenability to drawing (e.g. into wire).In materials science, ductility is defined by the degree to which a material can sustain plastic deformation under tensile stress before failure. Ductility is an important consideration in engineering and manufacturing. It defines a material's suitability for certain manufacturing operations (such as cold working) and its capacity to absorb mechanical overload.

Some metals that are generally described as ductile include gold and copper, while platinum is the most ductile of all metals in pure form.However, not all metals experience ductile failure as some can be characterized with brittle failure like cast iron. Polymers generally can be viewed as ductile materials as they typically allow for plastic deformation.

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A 25.0 g sample of warm water at 40.0⁰C was added to a 25.0 g sample of water in a Styrofoam coffee cup calorimeter initially at 20.0⁰C. The final temperature of the mixed water and calorimeter was 29.5⁰C. Calculate the heat capacity of the coffee cup calorimeter. The specific heat of water is 4.184 J/g∙⁰C.

a.
0.189 J/⁰C

b.
27.3 J/⁰C

c.
11.0 J/⁰C

d.
116 J/⁰C

Answers

Answer:

2024.70 J

Explanation:

The heat capacity of the coffee cup calorimeter can be calculated using the following formula:

q_calorimeter = q_water + q_water_final

where q_calorimeter is the heat absorbed by the coffee cup calorimeter, q_water is the heat lost by the warm water, and q_water_final is the heat gained by the cold water.

First, calculate q_water:

q_water = m_water * c_water * ΔT

where m_water = 25.0 g is the mass of the warm water, c_water = 4.184 J/g°C is the specific heat of water, and ΔT = (40.0°C - 29.5°C) = 10.5°C is the change in temperature.

q_water = 25.0 g * 4.184 J/g°C * 10.5°C = 1057.35 J

Next, calculate q_water_final:

q_water_final = m_water * c_water * ΔT

where m_water = 25.0 g is the mass of the cold water, c_water = 4.184 J/g°C is the specific heat of water, and ΔT = (29.5°C - 20.0°C) = 9.5°C is the change in temperature.

q_water_final = 25.0 g * 4.184 J/g°C * 9.5°C = 967.35 J

Finally, calculate the heat capacity of the coffee cup calorimeter:

q_calorimeter = q_water + q_water_final = 1057.35 J + 967.35 J = 2024.70 J

So the heat capacity of the coffee cup calorimeter is 2024.70 J.

A 25.0 g sample of warm water at 40.0⁰C was added to a 25.0 g sample of water in a Styrofoam coffee cup calorimeter initially at 20.0⁰C. 2024.70 J is the heat capacity of the coffee cup calorimeter.

What is heat capacity?

A physical feature of matter known as heat capacity and thermal capacity is the quantity of heat that must be applied to an object in order to cause a unit change in temperature. Heat capacity is measured in joules per kelvin (J/K), the SI unit. A broad property is heat capacity.

The particular heat capacity, which can be calculated by dividing an object's heat capacity by its mass, is the comparable intense attribute. The molar heat capacity is obtained through dividing the specific heat even by molecular weight of the substance. The heat capacity per volume is gauged by the volumetric heat capacity. The term "thermal mass" is frequently used in civil engineering and architecture to describe a building's ability to hold heat.

q calorimeter = q water + q water final

q water = m ×c water ×ΔT

q water = 25.0 g×4.184 J/g°C ×10.5°C

              = 1057.35 J

q water final = m×c of water × ΔT

q water final = 25.0 g×4.184 J/g°C ×9.5°C

                   = 967.35 J

q calorimeter = q water + q water final

                      = 1057.35 J + 967.35 J

                      = 2024.70 J

Therefore,  2024.70 J is the heat capacity of the coffee cup calorimeter.

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consider the chromate/dichromate ion equilibrium what color will solution be if it contains onyly k2cro4

Answers

In reactions where potassium dichromate changes color, the orange color of potassium dichromate can be employed to good use. In many reactions, it is therefore also utilized as an indication.

What causes the yellow to orange hue of potassium chromate to change?

The yellow color of the potassium chromate solution changes to orange as nitric acid is introduced. The potassium chromate solution changes from orange to yellow when sodium hydroxide is introduced.

What causes potassium chromate to be yellow?

Yellow is the color of potassium chromate. Chromate ion is where the derives from. The material starts to change color to orange, like the dichromate ion, when nitric acid is added. Orangeness increases with increasing acidity.

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(02.03 MC)
An electron moved from a lower energy level to a higher energy level. What most
likely happened during the transition? (5 points)

1) A random amount of light was released.
2) A fixed amount of energy was absorbed.

-
3) A fixed amount of energy was released.
1
4) A random amount of light was absorbed.

Answers

An electron moved from a lower energy level to a higher energy level, and during the transition, a random amount of light was released. Option A

What exactly are these electrons?

An electron is a kind of subatomic particle that has a negative charge. It is possible for it to be free (meaning that it is not associated with the nucleus of any atom) or it may be tied to the nucleus of an atom.

Electrons are sub-atomic particles that may be found in each atom of any chemical element and can occupy different energy levels. These electrons are capable of transitioning between different energy levels.

Electrons may transition from a state with a lower energy level, also known as the ground state, to a state with a higher energy level, also known as an excited state. Alternatively, electrons can transition from a state with a higher energy level to a state with a lower energy level.

When an electron goes from a lower energy level to a higher energy level, the atom takes in more energy, but when the electron moves from a higher energy level to a lower energy level, the additional energy is expelled mostly in the form of light.

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