. Which of the following could be the graph of the equation y=-2x?
A.
B.
C.

Answer:

Step-by-step explanation:

Given equation:

Solve:

Answer:

\(\huge\boxed{867}\)

Step-by-step explanation:

6 tens is the equivalent of 6 * 10, or 60

8 hundreds is the equivalent of 8 * 100, or 800

7 ones is the equivalent of 7 * 1, or 7.

Simply add these numbers to get that 60 + 800 + 7 = 867

Hope it helps :)

The net electric force that the two charges would exert on an electron placed at a point on the x-axis at x = 0.200 m is -2.40

Let's start by finding the distance between the electron and each point charge. The distance between the electron and the positive charge at the origin is:

r₁ = 0.200 m

The distance between the electron and the negative charge at x = 0.800 m is:

r₂ = 0.800 m - 0.200 m = 0.600 m

Now we can use Coulomb's law to find the magnitude of the electric force between each point charge and the electron. The force exerted by the positive charge is:

F₁ = k * q₁ * qe / r₁²

where qe is the charge of the electron, which is -1.60 x 10⁻¹⁹ C (negative because it is an electron). Plugging in the values, we get:

F₁ = (9.0 x 10⁹ N*m²/C²) * (4.00 x 10⁻⁹ C) * (-1.60 x 10⁻¹⁹ C) / (0.200 m)

F₁ = -1.44 x 10⁻¹⁴ N

The negative sign indicates that the force is attractive, since the electron is negative and the point charge is positive.

Similarly, the force exerted by the negative charge is:

F₂ = k x q₂ x qe / r₂²

Plugging in the values, we get:

F₂ = (9.0 x 10⁹ N*m²/C²) * (-6.00 x 10⁻⁹ C) * (-1.60 x 10⁻¹⁹ C) / (0.600 m)²

F₂ = 1.20 x 10⁻¹⁴ N

The positive sign indicates that the force is repulsive, since the electron is negative and the point charge is also negative.

Now we can find the net electric force on the electron by adding the two forces together:

Fnet = F1 + F2

Fnet = (-1.44 x 10⁻¹⁴ N) + (1.20 x 10⁻¹⁴ N)

Fnet = -2.40

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Complete Question:

A 4.00 n C point charge is at the origin, and a second − 6.00 n C point charge is on the x-axis at x = 0.800 m.

Find the net electric force that the two charges would exert on an electron placed at a point on the x-axis at x = 0.200 m.

Multiply both sides by \(x^{-3}\) to get a homogeneous equation.

\((2xy^2 - x^3) \, dy + (y^3 - 2yx^2) \, dx = 0 \\\\ \implies \left(2\dfrac{y^2}{x^2} - 1\right) \, dy + \left(\dfrac{y^3}{x^3} - 2\dfrac yx\right) \, dx = 0\)

Substitute \(y=vx\) and \(dy = x\,dv + v\,dx\). This makes the equation separable.

\((2v^2 - 1) (x\,dv + v\,dx) + (v^3 - 2v) \, dx = 0\)

\(x (2v^2 - 1) \,dv + (2v^3 - v) \, dx + (v^3 - 2v) \, dx = 0\)

\(x (2v^2 - 1) \,dv + (3v^3 - 3v) \, dx = 0\)

Separate the variables.

\(x (2v^2 - 1) \, dv = (3v - 3v^3) \, dx\)

\(\dfrac{2v^2-1}{3v-3v^3} \, dv = \dfrac{dx}x\)

\(\dfrac13 \dfrac{1 - 2v^2}{v(v-1)(v+1)} \, dv = \dfrac{dx}x\)

Expand the left side into partial fractions.

\(\dfrac{1-2v^2}{v(v-1)(v+1)} = \dfrac av + \dfrac b{v-1} + \dfrac c{v+1} \\\\ \dfrac{1-2v^2}{v(v-1)(v+1)} = \dfrac{a(v^2-1) + bv(v+1) + cv(v-1)}{v(v-1)(v+1)} \\\\ 1-2v^2 = (a+b+c) v^2 + (b-c) v - a\)

Solve for the coefficients \(a,b,c\).

\(\begin{cases} a + b + c = -2 \\ b-c = 0 \\ -a = 1 \end{cases} \implies a=-1, b=c=-\dfrac12\)

Thus our equation becomes

\(\left(-\dfrac1{3v} - \dfrac1{6(v-1)} - \dfrac1{6(v+1)}\right) \, dv = \dfrac{dx}x\)

Integrate both sides.

\(\displaystyle \int \left(-\dfrac1{3v} - \dfrac1{6(v-1)} - \dfrac1{6(v+1)}\right) \, dv = \int \dfrac{dx}x\)

\(\displaystyle -\frac13 \ln|v| - \frac16 \ln|v-1| - \frac16 \ln|v+1| = \ln|x| + C\)

Solve for \(v\) (as much as you can, anyway).

\(\displaystyle -\frac16 \left(2\ln|v| + \ln|v-1| + \ln|v+1|\right) = \ln|x| + C\)

\(\displaystyle \ln\left|\frac1{\sqrt[6]{v^2(v^2-1)}}\right| = \ln|x| + C\)

\(\displaystyle \frac1{\sqrt[6]{v^4-v^2}} = Cx\)

\(\sqrt[6]{v^4-v^2} = \dfrac Cx\)

\(\left(\sqrt[6]{v^4-v^2}\right)^6 = \left(\dfrac Cx\right)^6\)

\(v^4-v^2 = \dfrac C{x^6}\)

Put the solution back in terms of \(y\).

\(\left(\dfrac yx\right)^4-\left(\dfrac yx\right)^2 = \dfrac C{x^6}\)

\(y^4 - x^2y^2 = \dfrac C{x^2}\)

\(\boxed{x^2y^4 - x^4y^2 = C}\)

which is about as simple as we can hope to get this.

Answer:

Sorry but the photo is not clear

Answer:

5 : 30

Step-by-step explanation:

30/6 = 5

1 * 5 = 5

5 : 30

Hope it helps

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Thank you

Answer:

More people died in Auschwitz than the British and American losses of World War Two combined. About 60 million Reichmarks - equivalent to £125m today - was generated for the Nazi state by slave labour at Auschwitz. Nazis at Auschwitz offered some non-Jewish female prisoners the option of 'light work

Step-by-step explanation:

Answer:

Y(0,13)

X(13,0)

The simplified radical expression is given as follows:

\(\sqrt{363} - 3\sqrt{27} = 2\sqrt{3}\)

The radical expression for this problem is given as follows:

\(\sqrt{363} - 3\sqrt{27}\)

The first step in simplifying the expression is obtaining the prime factors of 363 and of 27, hence:

Hence the radicals are simplified as follows:

Hence the simplified expression is:

\(\sqrt{363} - 3\sqrt{27} = 11\sqrt{3} - 3 \times 3\sqrt{3} = (11 - 9)\sqrt{3} = 2\sqrt{3}\)

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In math in general, a ratio is a way of comparing two (sometimes more than 2) different values.

To put it more simply, a ratio tells you how how many of x you would have for y. For example, ratio 2 : 3 means, every time you have two of x, there would be three of y. That implies that, if you multiply x by 2, you must multiply y by 2, and so on.

The ratio of x : y is 5 : 2. This means everytime x occurs 5 times, y occurs 2 times. Hence, if you have both x and y that would be seven in all (5 + 2 = 7).

In all, x would be represented by 5/7 (5 out of 7), and y would be represented by 2/7 (2 out of 7).

Simply put;

Now, you have the sum total of x and y given as 49. So, rather than having x + y = 7, we now have x + y = 49.

That means the total has increased by a factor of 7 (total is 49/7 = 7)

Therefore, the value of x would also increase by a factor of 7, and that is 5 x 7, which equals 35.

The new ratio (when the total is 49) is now;

That is, the new ratio is now,

35 : 14

Answer:

-129

Step-by-step explanation:

2x+5=0

x=-5/2 [By the remainder theorem]

f(-5/2)=8(-5/2)^3+4(-5/2)^2+13(-5/2)+3

=-125+25-65/2+3

=-129.

The total length of the nylon rope that Jamie will use would be 15.3 feet of nylon rope.

Within this scenario specifically, one side of the right-angled triangle comprises the height of the tent (standing at 6.5-feet), and the other forms as the measure from the center of the tent to where Jaime stakes the ropes stretching outwards in another direction (with a calculated measure of 4-feet). Subsequently, we will refer to the extent of the nylon rope as R.

The Pythagorean theorem formula is:

R ² = 6.5 ² + 4 ²

R ² = 42. ²25 + 16

R ² = 58.25

R = 7. 63 ft

There are two ropes so the length would be :

= 7. 63 + 7. 63

= 15. 3 ft

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Answer:

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \(\pi\), and a confidence level of \(1-\alpha\), we have the following confidence interval of proportions.

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which

z is the z-score that has a p-value of \(1 - \frac{\alpha}{2}\).

Out of 100 people sampled, 42 had kids.

This means that \(n = 100, \pi = \frac{42}{100} = 0.42\)

99% confidence level

So \(\alpha = 0.01\), z is the value of Z that has a p-value of \(1 - \frac{0.01}{2} = 0.995\), so \(Z = 2.575\).  

The lower limit of this interval is:

\(\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 2.575\sqrt{\frac{0.42*0.58}{100}} = 0.293\)

The upper limit of this interval is:

\(\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 + 2.575\sqrt{\frac{0.42*0.58}{100}} = 0.547\)

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

Answer:

None of these

Step-by-step explanation:

We can estimate f'(9) by finding the slope of the secant through the two points closest to (9, f(9)).

\(\frac{f(10)-f(8)}{10-8}=\frac{16-10}{2}=3\)

Answer:

35.6 m/s

Step-by-step explanation:

P = kS²

1760 = k× 35²

1760=1225k

1760/1225 = k

1.44 = k

P=1.44×S²

1820= 1.44 × s²

1820/1.44 = s²

√1820/1.44 = s

s= 35.6 m/s

Answer:F

Step-by-step explanation:

Answer:

  -33.3%

Step-by-step explanation:

The percentage loss is the same for 2 crates as for 1 crate.

  % loss = (loss/cost) · 100%

  % loss = (N100 -N150)/(N150) · 100% = -1/3 · 100% ≈ -33.3%

The percentage loss is 33.3%.

_____

Additional comment

In the above, the minus sign indicates a percentage change that is a loss. If the sign were positive, it would indicate a percentage profit.

Answer:

jamie has 144 pictures. -hope this helps

Step-by-step explanation:

Answer:

0.15 = 15% probability that it came from Site 3

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

\(P(B|A) = \frac{P(A \cap B)}{P(A)}\)

In which

P(B|A) is the probability of event B happening, given that A happened.

\(P(A \cap B)\) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Being recalled

Event B: Recalled from site 3.

Probability of being recalled:

5% of 60%(from site 1)

7% of 30%(from site 2)

9% of 10%(from site 3).

So

\(P(A) = 0.05*0.6 + 0.07*0.3 + 0.09*0.1 = 0.06\)

Probability of being recalled, being from site 3.

9% of 10%.

\(P(A \cap B) = 0.09*0.1 = 0.009\)

If a randomly selected cell phone has been recalled, what is the probability that it came from Site 3?

\(P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.009}{0.06} = 0.15\)

0.15 = 15% probability that it came from Site 3

Answer:

\(\frac{5}{12}\)

Step-by-step explanation:

The given problem is a subtraction problem between fractions. The first step in a problem like this is to convert both fractions to a common denominator. In other words, multiply both the numerator and denominator of a fraction by the same value such that the denominator of one of the fractions is the same as the other fraction. The numerator of a fraction is the value over the fraction bar, whereas the denominator is the value under it. Multiplying any fraction by a number over itself is the same as multiplying it by one, thus, the equation will remain true, and be equivalent to the original expression.

\(\frac{13}{12}-\frac{2}{3}\)

Convert to a common denominator,

\(\frac{13}{12}-(\frac{2}{3}*\frac{4}{4})\)

\(\frac{13}{12}-\frac{8}{12}\)

Now perform the subtraction, subtract one numerator from the other, remember, do no perfrom any more operations with the denominators,

\(\frac{5}{12}\)

The Venn diagram for (D ⋃ E) ⋃ F will be the ovarlapped region of D,E and F.

To represent the sets D, E, and F in the Venn diagram, we first construct three overlapping circles. Then, beginning with the innermost operation and moving outward, we shade the regions corresponding to the set operations in the expression.

We shade the area where the circles for D and E overlap because the equation (D ⋃ E)  denotes the union of the sets D and E. All the elements in D, E, or both are represented by this area.

The union of (D ⋃ E) with F is the next step. This indicates that we darken the area where the circle for F crosses over into the area that we shaded earlier. All the components found in sets D, E, F, or any combination of these sets are represented in this region.

The final Venn diagram should include three overlapping circles, with (D ⋃ E) ⋃ F shaded in the area where all three circles overlap.

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The monthly income of the first person is $600.

Given that, the average monthly income of three persons is RS 3,600.

The income of the first is 1/5 of the combined income of the other two.

Here, Let income of the first be A, let income of the second be B and let Income of the third be C.

A+B+C=3600 -----(i)

Income for the first person = 1/5(B+C) -----(ii)

Substitute equation (ii) in equation (i), we get

(B+C)/5 +B+C =3600

B+C+5B+5C=3600×5

6B+6C=18000

6(B+C)=18000

B+C=3000 ------(iii)

Substitute (iii) in equation (i), we get

A=$600

Therefore, the monthly income of the first person is $600.

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The Equivalent ratio to 8/2 is 4/1, 24/6, 32/8 and 48/12.

We have,

Cylinder and prism.

Here we have to find the equivalent ratio to 8/2.

First simplifying the given ratio as

8/2

= (4 x 2)/2

= 4 /1

Now, some more ratios equivalent to 8/2.

1. 8/2 x 3/3 = 24/ 6

2. 8/2 x 4/4 = 32/8

3. 8/2 x 6/6= 48/12

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By conducting mathematical operations, we know that John's gross pay will be $1,012 if he works 44 hours a week.

A mathematical "operation" is the process of calculating a value utilizing operands and a math operator.

The supplied operands or integers must adhere to a set of predefined rules that are connected to the symbol of the math operator.

The order of operations refers to the rules that specify how to solve an expression including many operations.

Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction are all referred to as PEMDAS (from left to right).

So, we know that:

John earns $22 per hour for the first 40 hours of a week.

After every additional hour, he earns 1.5 times $22 each hour.

22 * 1.5 = $33

So, John's gross pay if he worked 44 hours will be:

22*40 + 33*4

880 + 132

$1,012

Therefore, by conducting mathematical operations, we know that John's gross pay will be $1,012 if he works 44 hours a week.

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b) Because it REFLECTING which means that is going across

Answer:

D is correct

Step-by-step explanation:

because the ponit started in quadrant 1 and the only thing that could change is the y-axis and the y-axis aloney went down and quadrant 4 is the only quadrant above 1 so that the answer

The law of cosine helps us to know the third side of a triangle. The value of third side c is 20.87.

The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. It is given by the formula,

\(c =\sqrt{a^2 + b^2 -2ab\cdot Cos\theta}\)

where

c is the third side of the triangle

a and b are the other two sides of the triangle,

and θ is the angle opposite to the third side, therefore, opposite to side c.

Given, in ΔABC, a = 32, b = 21 and the angle between a and b is 40°, therefore, the value of ∠C=40°.

Now, the value of the third side of the triangle using the cosine law can be written,

\(c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}\\\\c=\sqrt{32^{2}+21^{2}-2(32 \times 21)\cdot \cos 40^o}\\\\c=\sqrt{1,024+441-1,029.5637}\\\\c=20.867 \approx 20.87\)

Hence, the value of third side c is 20.87.

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Answer:

A). The amount in 20 years

=$ 13574.45

B).36.83%

Step-by-step explanation:

A)

The both deposit the sum of $2500 each year that is the sum total of $5000.

Rate = 5 %

Years= 20

Then compounded annually so number of times = 20

A = P(1+r/n)^(nt)

= 5000(1+ (0.05/20))^ (20*20)

= 5000(1+0.0025)^(400)

= 5000(1.0025)^(400)

= 5000(2.71489)

= 13574.45

The amount in 20 years =$ 13574.45

B) let's calculate the percentage of the actual balance they contributed.

= 5000/13574.45

= 0.3683333

= 36.83%

The measure of other two angles in the given quadrilateral are 10° and 25°.

A quadrilateral is a polygon with four sides four angles and four vertices. Whenever we name a quadrilateral, we need to keep in mind the order of the vertices.

Given that, two angles of a quadrilateral measure 130° and 195°.

The other two angles are in a ratio of 2:5.

So, the other two angles are 2x and 5x

Now, 130°+195°+2x+5x=360°

325°+7x=360°

7x=360°-325°

7x=35°

x=5

So, 2x=10° and 5x=25°

Therefore, the measure of other two angles in the given quadrilateral are 10° and 25°.

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