Which of the following combinations would result in the largest attraction
between particles?
Large charges close together
Small charges close together
Large charges far apart from each other
OSmall charges far apart from each other

Answer: We can translate the given chemical equation as:

"potassium permanganate combined with zinc chloride produces zinc permanganate and potassium chloride". The best option to answer the question is the first one.

Explanation:

The question requires us to choose, among the options given, the correct "translation" for the following chemical equation:

To solve this problem, we can separate the compounds into their cations and anions, and then analyze the metal (cation) name and anion name. Keep in mind that the name of the compound is formed by cation/metal name + anion name.

1) Let's start with KMnO4, which is formed by the cation K+ (potassium) and anion (MnO4)- (permanganate). The name of KMnO4 is potassium permanganate.

2) Next, let's analyze ZnCl2, which is formed by the cation Zn2+ (zinc) and anion Cl- (chloride). The name of ZnCl2 is zinc chloride.

3) Now, let's check Zn(MnO4)2, which is formed by Zn2+ (zinc) and (MnO4)- (permanganate). The name of Zn(MnO4)2 is zinc permanganate.

4) At last, let's analyze KCl, which is formed by K+ (potassium) and Cl- (chloride). The name of KCl is potassium chloride.

Therefore, we can translate the given chemical equation as:

"potassium permanganate combined with zinc chloride produces zinc permanganate and potassium chloride". The best option to answer the question is the first one.

The first two chemical equations are reversible while the other two are irreversible.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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Answer:

the empirical formula is \(H_2NO_2\)

Explanation:

The empirical formula is

The following information is given

It contains 29.17 mass percentage of N

4.20 mass percentage of H

And, 66.63 mass percentage of 0

Now based on the above information, the empirical formula is \(H_2NO_2\)

hence, the same is to be considered and relevant too

Considering the definition of empirical formula,  the empirical formula is H₂N₁O₂= H₂NO₂

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers small as possible.

Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass % O.

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 29.17 grams of N, 4.20 grams of H and 66.63 grams of O.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Therefore the H: N: O mole ratio is 2: 1: 2

Finally, the empirical formula is H₂N₁O₂= H₂NO₂

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According to the electron sea model, the melting points of metals are not as extreme as the boiling points. Therefore, the given statement is correct is true.

The Electron Sea Model's whole hypothesis relies around the behavior of atoms throughout this bonding. The movement of unpaired electrons between positively charged metal ions in a mesh is known as metallic bonding.

According to the electron sea model, the melting points of metals are not as extreme as the boiling points. This is because the cations and electrons are - in a metal. It does not take much energy for a solid to become liquid. But metallic bonds are very - , so it does require a lot of energy to separate atoms from the cations in their sea of electrons. This statement is true.

Therefore, the given statement is correct is true.

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The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M.

Given reaction obeys the rate law, rate=k[A]²[B].

Here, the initial concentration of A= 0.10 M,

initial concentration of B = 0.05 M, and

rate constant, k = 2.0 × 10⁻⁴ M⁻¹s⁻¹

We have to find the concentration of A, after 30 seconds.

To find the concentration of A, we need to know the rate at 0.10 M and 0.05 M. Therefore, we have to calculate the rates at these concentrations.

rate1 = k[A]²[B]

= (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.10 M)²(0.05 M)

= 1.0 × 10⁻⁷ M/srate2

= k[A]²[B] = (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.09 M)²(0.04 M)

= 6.48 × 10⁻⁸ M/s

Using the integrated rate law for a second-order reaction: [A] = [A]₀ - kt where [A]₀ = initial concentration of A, k = rate constant, and t = time in seconds.

We know [A]₀ = 0.10 M and k = 2.0 × 10⁻⁴ M⁻¹s⁻¹.

Substituting the values in the above equation, we get: [A] = [A]₀ - kt= 0.10 M - (2.0 × 10⁻⁴ M⁻¹s⁻¹)(30 s)≈ 0.0934 M

Therefore, the concentration of A in the vessel after 30 seconds is 0.0934 M.

This question requires us to calculate the concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We are given the initial concentration of A and B and the rate constant of the reaction. To find the concentration of A after 30 seconds, we need to calculate the rates at the initial concentrations of A and B.

Using the integrated rate law for a second-order reaction, we can find the concentration of A at any given time. We substitute the given values in the formula and solve for [A]. We get the concentration of A as 0.0934 M after 30 seconds. This calculation is based on the assumption that no other reaction is important.

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B]. We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M. This calculation assumes that no other reaction is important.

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Light energy is connected to carbon dioxide consumption by a plant at the molecular level through the process of photosynthesis.

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Electrons stay in between the nuclei of the two hydrogen atoms because they are attracted to the positive charge of the nuclei.

Electrons are negatively charged species, so they are attracted towards the positive charge of a nucleus.

In hydrogen atom, when both the two hydrogen atoms get close to each other then the electrons of each atom will get attracted to both the nuclei. And if both the hydrogen atoms come close to each other they will repel each other.

The energy of the two hydrogen atoms becomes less when  they are together than when they are far apart.

Thus, the electrons tend to stay in between the nuclei of the two hydrogen atoms.

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The statements that describe the changes that occur when an ionic solid dissolves in water are an ionic solid is converted into ions when it dissolves in water and the ions of an ionic solid are hydrated by water molecules.

When an ionic solid dissolves in water, the ionic solid dissociates into its constituent ions. The positive ions are attracted to the negative pole of the water molecule while the negative ions are attracted to the positive pole of the water molecule. Consequently, the individual ions are surrounded by water molecules, forming a hydration sphere.

The following statements are correct regarding the changes that occur when an ionic solid dissolves in water:

1. An ionic solid is converted into ions when it dissolves in water.

2. The ions of an ionic solid are hydrated by water molecules.

3. Dissolution is an exothermic process that releases energy.

4. The solubility of an ionic solid in water is dependent on temperature and pressure.

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Answer:

1 Zn + 2 HCl ⇒ 1 H₂ + 1 ZnCl₂

Hope this helps!!!

Answer:

For every 5 psu increase in salinity, the freezing point decreases by 0.28 degrees Celsius (0.5 degrees Fahrenheit); thus, in polar regions with an ocean salinity of about 32 psu, the water begins to freeze at -1.8 degrees Celsius (28.8 degrees Fahrenheit).

Explanation:

Freezing increases salinity, while melting decreases salinity.

took the test lol

Answer:

\(3Ca(OH)_{2} + 2H_3PO_4 ==> Ca_3(PO_4)_2 + 6H_2O\)

Explanation:

The chemical equation represented as:

\(2H_3PO_4 (aq)+ 3Ca (OH)_2 (aq) ----- > Ca(PO_4)_2 (s)+ 6H_2O (l)\)

A chemical equation is defined as a symbolic representation of a chemical reaction in the form of symbols and chemical formulas. Coefficients that are used in front of reactants and products to balance the equation to show that matter is conserved.

Representation of chemical reactions by symbols and formulas of substances is called chemical equation. In this equation A and B are called reactants and C and D are called products while the arrow shows the direction of the chemical reaction.

For the above given information,

\(2H_3PO_4 (aq)+ 3Ca (OH)_2 (aq) ----- > Ca(PO_4)_2 (s)+ 6H_2O (l)\)

Phosphoric      Calcium                               Calcium          Water

acid                hydroxide                            phosphate

Where, Aqueous phosphoric acid and aqueous calcium hydroxide are reactants and solid calcium phosphate and water are products.

Thus, the chemical equation represented as:

\(2H_3PO_4 (aq)+ 3Ca (OH)_2 (aq) ----- > Ca(PO_4)_2 (s)+ 6H_2O (l)\)

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Answer:a mouse

Explanation:

Answer: a mouse

Explanation:

The time taken for half of the radioactive nuclei in a sample to decay is called the half-life of the nuclide. This value is indeed characteristic of a specific nuclide and is not dependent on the number of nuclei present.

The statement is true. The half-life of a radioactive nuclide refers to the time it takes for half of the radioactive nuclei in a sample to decay. It is a fundamental property of a specific nuclide, meaning that each nuclide has its own unique half-life value. The half-life is constant for a given nuclide and is not influenced by the number of nuclei present in the sample.

The concept of half-life is crucial in understanding radioactive decay and its applications in various fields like radiometric dating, nuclear physics, and medical imaging. The half-life allows scientists to predict how long it will take for a given amount of radioactive material to decay by half. Regardless of the initial amount of radioactive nuclei, the proportion that decays remains the same for each half-life interval.

This property makes the half-life a reliable measure for determining the rate of decay and estimating the age or activity of a radioactive substance.

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Malonic acid completely dissolves but partially dissociates in aqueous solutions.

Malonic acid (propanedioic acid) is a dicarboxylic acid. The molecular formula of malonic acid is C3H4O4, and it has a molar mass of 104.07 g/mol. It is a white crystalline solid, soluble in water and other polar solvents.

Malonic acid dissolves in aqueous solutions to produce a homogeneous solution. Although malonic acid does not completely dissociate in water, it partially dissociates into H+ and Hmal in the presence of water. Malonic acid is a weak acid; thus, only a few molecules of malonic acid ionize in an aqueous solution.

Hence, it only partially dissociates. Therefore, it can be said that Malonic acid completely dissolves but partially dissociates in aqueous solutions.

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Explanation:

the option 2 is correct

metals tend to have lower ionizatiin energy than non metals

Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

500kg, 42m, 675g, and 10m/s are all examples of a: continuous data.

A numerical data can be defined as a data set that is expressed in numbers only or a data set consisting of numbers rather than words. A numerical data is also known as a quantitative data.

Generally, numerical data are classified into two (2) main categories and these are;

In conclusion, mass (500 kg), height (42m), mass (675g), and speed (10m/s) are all examples of a: continuous data.

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Answer:  1. The chemical formula of the negative polyatomic ion present in an aqueous nitric acid solution is nitrate, which has a chemical formula of NO3-.

2. The solubility of sulfur dioxide (SO2) in water is negatively affected by an increase in water temperature. This means that as the temperature of water increases, the solubility of SO2 in water decreases. This is because the solubility of gases in water generally decreases with increasing temperature, due to the decrease in gas molecules' ability to dissolve in water. Therefore, when water temperature increases, the amount of SO2 that can dissolve in the water decreases, resulting in less acidic rainfall.

Explanation:

Answer:

Diffusion in gases

When chemical substances such as perfume are let loose in a room, their particles mix with the particles of air. The particles of smelly gas are free to move quickly in all directions. They eventually spread through the whole room from an area of high concentration to an area of low concentration.

Explanation:

6.375 moles of O2 are required to form 4.25mol \(CaCO_{3}\) if the net balanced equation given is,

                Ca (solid) + C (solid) + 3/2 O2 (gas) ⟶\(CaCO_{3}\) (solid).

The balanced equation is,

  Ca (solid) + C (s) + 3/2 O2 (g)  ⟶ \(CaCO_{3}\) (solid).

A balanced equation is defined as a chemical equation in which mass is conserved and there are equal numbers of atoms of each element on both sides of the equation. This equation has an equal number of atoms of each element on both sides of the chemical equation. The mass of the reactants is said to be equals to the mass of the products.

The number of moles of a substance can be expresses as the ratio of its given mass in a chemical reaction to the mass of one mole of that substance. One mole of any substance is equals to Avogadro's number, that is 6.023 × 1023. It is generally used to express concentration units such as mole per liter or molecular weight.

1 mole of \(CaCO_{3}\) is formed by 3/2 moles of O2.

4.25 moles of \(CaCO_{3}\) will be formed by,

    =   3/2 * 4.25

    = 6.375 mole

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From the following balanced equation,

Ca(s) + C(s) + 3/2 O2(g) ⟶\(CaCO_{3}\) (s) how many moles of O2 are required to form 4.25mol CaCO3?

ANSWER

Temperature will remain the same

EXPLANATION

When water reaches it boiling point at 100 degrees Celcius, the molecules of water will start moving independently and collide with each other.

At 100 degrees Celcius, it has attained an equilibrium between the liquid and vapor phase. Therefore, when energy is added to it, the temperature will remain the same and there will be a phase change.

Hence, the temperature will remain the same.

After the refrigerant liquid has been recovered from the appliance, any remaining vapor is removed by the recovery system. Hence option D is correct.

The recovery system uses a vacuum pump to draw out the vapor and store it in a recovery cylinder. The recovery cylinder is then transported to a facility where the refrigerant can be recycled or disposed of properly.

Purgaing the vapor into the atmosphere is not an option, as it would release harmful greenhouse gases into the environment. Isolating the vapor in the appliance would not be effective, as the vapor would eventually escape.

Pumping the vapor into the appliance receiver would also not be effective, as the receiver is not designed to hold vapor.

Therefore, option D is correct.

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Answer:

Temperature

Explanation:

i GUESS that's the ans lol sry I needed points

The mixture contains a concentration of monoprotic acetic acid of

(8.36 M). (0.0083592 mol/1000 mL = 8.36 M) = 0.258 M x 32.40 mL/1000 L.

Monoprotic acids include benzoic acid (C6H5CO2H), acetic acid (CH3CO2H or HOAc), nitric acid (HNO3), and hydrochloric acid (HCl).

H2SO4 and H3PO4 are examples of polyprotic acids that contain two or three hydrogen ions. Although it is alluring to believe that polyprotic acids are more powerful than monoprotic acids since they include several hydrogen ions, this is not the case.

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The mass of the hydrogen peroxide is 238 g.

Hydrogen peroxide at room temperature stays in liquid form. It has a bitter taste and is colorless. It is an important regent used in pharmaceutical and other industries. It also has medical use. It can be used as an antiseptic.

The number of miles in the hydrogen peroxide is n.

n = 7 mol

The molar mass of hydrogen peroxide is,

The molar mass of hydrogen peroxide = Molar mass of hydrogen + Molar mass of oxygen

= 2 × 1 + 2× 16

= 34 g/mole

The molar mass of hydrogen peroxide is 34 g/mole.

The mass of the hydrogen peroxide is,

\(Number \: of \: moles = \frac{ Mass }{ Molar \: mass}\)

\(n = \frac{m}{M} \)

m = n × M

m = 7 × 34

m = 238 g.

Therefore, the mass of the hydrogen peroxide is 238 g.

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Answer:

Answer: About 71 percent of the earth's surface is covered by water.

--Submitted by Robert Gagosian, Woods Hole Oceanographic Institute

Answer:

9

Explanation:

Two isotopes of the FAKE element Sz, Average mass of  Seabreezium is equal to 199.77625 amu.

Given that Two isotopes of of Sz is given as :

Seabreezium-71 75%

Seabreezium - 76 25%

Now,

Isotopes of Seabreezium is given as:

Now,

 1st isotope = 71 75% of 271

                    = 194.44amu

  2nd isotope = 76 25% of 269

                       = 205.11 amu

Now,

Average Mass of Seabreezium = 205.11 + 194.44/2

 Average Mass of Seabreezium = 199.77625 amu

Thus, from the above conclusion we can say that, Average mass of  Seabreezium is equal to 199.77625 amu.

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