Indirect testing is conducted for some hypotheses. Which of the following can only be tested indirectly? A null hypothesis can only be tested indirectly since it is a hypothesis that there is no difference or no connection between variables.
Null hypothesis can never be accepted, only rejected or failed to reject (due to insufficient evidence). For example, the null hypothesis may say that the averages of two groups are equal. If our sample data contradicts that null hypothesis, we will reject the null hypothesis. A hypothesis that implies that there is an association or distinction between variables is known as an alternative hypothesis. The alternative hypothesis may be tested directly or indirectly. A research hypothesis may be tested directly or indirectly, but it is more common for it to be tested directly.
All hypotheses can be tested directly or indirectly except for the null hypothesis. The null hypothesis may only be tested indirectly because it is a hypothesis that claims there is no relationship or difference between the variables. It can only be refused or failed to be refused (due to a lack of evidence). The alternative hypothesis is a hypothesis that implies there is a link or difference between variables. It may be tested directly or indirectly, but it is more common to be tested directly. A research hypothesis is a hypothesis that is used in a study to predict the result. It may be tested directly or indirectly, although it is usually tested directly. If it is tested indirectly, the research hypothesis may be used to construct a series of hypotheses that can be tested more precisely.
Only the null hypothesis can only be tested indirectly.
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The rate at which a cricket chirps, R (in chirps per minute), depends on the temperature of its environment, F (in degrees Fahrenheit). For a specific chick species, this relationship can be modeled by the function R(F) 4F-160. a. Determine R¹(P) and interpret its meaning b. Compute R(60) and R¹(60) and interpret the meaning of each. Compute R (60).
R(F) = 4F - 160
a. R¹(P) represents the temperature at which a cricket chirps at a rate of P chirps per minute.
b. R(60) refers to the chirping rate of the cricket when the temperature is 60 degrees Fahrenheit, while R¹(60) represents the temperature at which the cricket chirps at a rate of 60 chirps per minute.
What is the relationship between temperature and cricket chirping rate?The equation R(F) = 4F - 160 represents the relationship between the temperature of the cricket's environment (F) and its chirping rate (R). By plugging in different temperature values, we can determine the corresponding chirping rate.
For example, when we calculate R(60), we find the chirping rate at 60 degrees Fahrenheit.
In this case, R(60) = 4(60) - 160 = 240 - 160 = 80 chirps per minute.
On the other hand, when we calculate R¹(60), we are looking for the temperature at which the cricket chirps at a rate of 60 chirps per minute. Solving the equation 60 = 4F - 160, we find F = 70 degrees Fahrenheit. Therefore, R¹(60) = 70.
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How do you reduce high latency?
Increasing internet speed and bandwidth will help to solve the latency issues. You'll need a network connection with a minimum speed of 15 mbps in order to use the internet efficiently.
Explanation of the previous response:Eventually, purchasing faster gear will be your best bet for obtaining lower latency. The system's overall latency can be considerably decreased by a faster CPU and GPU. Using the Reflex SDK's Game and Render latencies in games: If your Game Latency is excessive, think about getting a faster CPU.
In general, a latency (or ping) of 40 to 60 milliseconds (ms) or less is considered acceptable, whereas a speed of more than 100 ms will typically result in a significant lag in gaming. The performance of the game is affected by a number of variables.
the GPU, the HDD or SSD that the game is installed on, the amount and speed of RAM, the number of processing cores, and the speed of the disc.
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What is the slope of the line plotted below? (-2,-1) (4,2) A. 1 B. 2 C. -0.5 D. 0.5
Answer: D. 0.5
Explanation:
The slope formula is y2-y1/x2-x1.
2-(-1)/4-(-2) = 2+1/4+2
2+1/4+2 = 3/6 = 1/2
1/2 = 0.5
The slope is 1/2, or 0.5.
a sound wave leaves its source and is traveling through air. the reflected wave returns 0.5 second later. what is the distance from the source to the reflector?
The distance from the source to the reflector is approximately 171.5 meters when a sound wave leaves its source and is traveling through the air.
To determine the distance from the source to the reflector, we can use the speed of sound in air.
The speed of sound in air is approximately 343 meters per second at room temperature and normal atmospheric conditions.
Since the reflected wave returns 0.5 seconds later, it means that the sound wave traveled twice the distance from the source to the reflector.
Using the formula: Distance = Speed × Time, we can calculate the distance.
Distance = Speed of sound × Time
Distance = 343 m/s × 0.5 s
Distance = 171.5 meters
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Ethanol boils at 78oc and has a heat of vaporization of 43.3 . determine the heat required, in kj, to raise 4 moles of ethanol from 72oc to 90oc. take the liquid-state specific heat of ethanol to be 0.110 and the gas-state specific heat of ethanol to be 0.078 . your answer should be numerical and neglect units (e.g., if you calculate 3.5kj then input 3.5).
The total heat needed to raise 4 moles of ethanol from 72°C to 90°C is equal to 257.2 KJ.
What is the specific heat capacity?The specific heat of a substance can be defined as the amount of heat needed to raise the temperature in 1 unit of substance by one-degree Celcius.
Q = mCΔT
The heat needed to raise the ethanol from 72°C to a boiling point of 78°C will be:
Q₁ = 4 × 0.110 × (78°C - 72°C)
Q₁ = 33.6 KJ
To calculate the heat needed to evaporate the ethanol is:
Q₂ = 4 × 43.3
Q₂ = 173.2 kJ/mol
The heat needed to raise the ethanol vapor from 78°C to 90°C. is equal to:
Q₃ = 4 × 0.78 × (90°C - 78°C)
Q₃ = 50.4 KJ
Therefore, the total heat needed to raise 4 moles of ethanol from 72°C to 90°C will be:
Q = 33.6 kJ + 173.2 kJ + 50.4 kJ
Q = 257.2 kJ
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A ball is thrown directly downward with an initial speed of 7.05 m/s, from a height of 29.9 m. after what time interval does it strike the ground? s
The ball that is thrown directly downward with an initial speed of 7.05 m/s, from a height of 29.9 m. takes 3.29 s to strike the ground
The formula for the downward vertical launch and the procedure we will use is:
t = {V₀ + \(\sqrt{}\)[(V₀)² + 2*g*y]}/ g
Where:
v₀ = initial velocityg = gravityy = heightt = timeInformation about the problem:
g = 9.8 m/s²v₀ = 7.05 m/sy = 29.9 mt= ?With the information gave, we can calculate the time from the ball is thrown, using the formula of downward vertical launch:
t = {V₀ + \(\sqrt{}\)[(V₀)² + 2*g*y]}/ g
t = {7.05 m/s + \(\sqrt{}\)[(7.05 m/s)² + 2*9.8 m/s²*29.9 m]}/ 9.8 m/s²
t = {7.05 m/s + \(\sqrt{}\)[49.70 m²/s² + 586.04m²/s² ]}/ 9.8 m/s²
t = {7.05 m/s + \(\sqrt{}\)[635.74 m²/s² ]}/ 9.8 m/s²
t = {7.05 m/s + 25.214 m/s}/ 9.8 m/s²
t = 32.26 m/s/ 9.8 m/s²
t = 3.29 s
What is vertical launch?In physics vertical launch is the motion described by an object that has been launched vertically in which the acceleration is the earth's gravitational force.
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Can someone please Help me
Answer: The answer to 3 to is less inertia. The answer to 4 is large amount of inertia. The answer to 5 is large amount of inertia. The answer to 6 is more fuel. Number 6 is kind of unkown considering I can’t see the other answer but I guess it’s more fuel.
Explanation: Inertia is the resistance of the object to any change in its motion, including a change in direction. An object will stay still or keep moving at the same speed and in a straight line, unless it is acted upon by an external unbalanced force. So when there is more inertia, it’s harder to control, but when it has less inertia, it’s more loose and easier to move around.
the gulf stream appears to be slowing down in velocity. what is thought to be a main driving force for this?
The main driving force thought to be behind the slowing of the Gulf Stream is believed to be climate change. As the atmosphere and oceans warm, the Gulf Stream is losing heat to the atmosphere.
What is the Gulf Stream ?The Gulf Stream is a powerful ocean current that originates in the Gulf of Mexico and flows northward along the eastern coast of the United States. It is part of the North Atlantic gyre, a system of circulating ocean currents. The Gulf Stream is an important part of the global conveyor belt, a system that helps regulate the ocean's climate by transporting warm tropical waters to cooler regions of the world. The Gulf Stream is so powerful that it is able to move more water than all of the world's rivers combined. It transports more than 100 million cubic meters of water per second and has a maximum speed of up to 5.6 km per hour.
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Which group of objects refract light energy?
A.Shiny object, glasses and mirror
B.glasses, prism, and passing through water
C.Glasses, prism and mirror
D.Mirror, glasses, and passing through water
Answer:
B. glasses, prism, and passing through water
Explanation:
Mirrors reflect, not refract.Glasses, water and prism refract.*Note:- When light is bounced back it is called reflection.
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Answer⤵️Which group of objects refract light energy?
B.glasses, prism, and passing through waterWater flows steadily from an open tank. The elevation of point 1 is he elevation of point 1 is 10.0 m and the elevation of points 2 and 3 is 2.00 m, The cross sectional area at point 2 is 0.0480 sq.m, at point 3 it is 0.0160 sq.m. The area of the tank is very large compared with the cross sectional area of the pipe. Find the volume of water discharged after 2 minutes. Find also the gauge pressure at pt 2.
a. 24 m^3, 7.0x10^4 Pa
b. 20 m^3. 7x10^4 Pa
c. 0.2 m^3, 5.55x10^4 Pa
d. 0.2m^3. 3.7×10^4 Pa
Answer:
a. 24 m³, 7.0×10⁴ Pa
Explanation:
Use Bernoulli's equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₃ + ½ ρ v₃² + ρgh₃
Given or assumed:
P₁ = 0 Pa
v₁ ≈ 0 m/s
h₁ = 10 m
P₃ = 0 Pa
h₃ = 2 m
ρ = 1000 kg/m³
g = 9.8 m/s²
Substituting and simplifying:
ρg (10) = ½ ρ v₃² + ρg (2)
10g = ½ v₃² + 2g
(Notice this is simply an energy balance.)
Solving for v₃:
v₃ = √(16g)
v₃ = 12.5 m/s
Volumetric flow rate is velocity times area:
Q = v₃ A₃
Q = (12.5 m/s) (0.0160 m²)
Q = 0.200 m³/s
After 2 minutes, the volume discharged is:
V = (0.200 m³/s) (120 s)
V = 24.0 m³
Using Bernoulli's principle again:
P₂ + ½ ρ v₂² + ρgh₂ = P₃ + ½ ρ v₃² + ρgh₃
Since h₂ = h₃ and P₃ = 0:
P₂ + ½ ρ v₂² = ½ ρ v₃²
P₂ = ½ ρ (v₃² − v₂²)
Since volumetric flow is constant (mass is conserved):
Q = Q
v₂ A₂ = v₃ A₃
v₂ = v₃ A₃ / A₂
Substituting:
P₂ = ½ ρ (v₃² − (v₃ A₃ / A₂)²)
P₂ = ½ ρ v₃² (1 − (A₃ / A₂)²)
P₂ = ½ (1000 kg/m³) (12.5 m/s)² (1 − (0.0160 / 0.0480)²)
P₂ = 69,700 Pa
P₂ ≈ 7.0×10⁴ Pa
A hot air baloon is 100 above the ground when a motorcycle (traveling in a straight line on a horizontal road) passes directly beneath it going 45 mi/hr (06/a) it the balcon itsas vertically at a rate
A hot air balloon is 100 feet above the ground when a motorcycle (traveling in a straight line on a horizontal road) passes directly beneath it going 45 miles/hour.
Given that, The altitude of the balloon from the ground = 100 feet The velocity of the motorcycle = 45 miles/hour = 66 feet/second Rate of ascending of the balloon = 10 feet/second Now, When the motorcycle passed the balloon, both of them are on the same line passing through the ground.
Let the length of the balloon be L. The time taken for the balloon to move L distance = L / Rate of ascent of balloon L = 0 because it is already in sight. Hence, the motorcycle driver has to travel for no time before the balloon is out of sight.
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1.
100 cm are equivalent to 1 m. How many cm are equivalent to 3 m? Briefly explain how you
could convert any number of meters into a number of centimeters
Answer:
\(300\) cm are equivalent to \(3\) m.
Explanation:
\(100\) cm are equivalent to \(1\) m.
\(100 \mathrm{~cm}$=1{~m}$\)
\(3 \mathrm{~m}$=3\times100\)
\(=$300{~cm}$\)
To convert meters (\(\mathrm{~m}$\)) into number of centimeters (\(\mathrm{~cm}$\)), multiply that number by \(100\).
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what is visible spectrum?
Explanation:
The band of electromagnetic radiation that human eyes can detect. This ranges from wavelengths of approximately 400 to approximately 700 nanometers (nm).
Explanation:
It's the portion of the electromagnetic spectrum that is visible to the human eye.
The center of the thin disk is displaced 15 mm and then released. What is the maximum velocity attained by the center of the disk assuming no slip between the disk and the surface?
The maximum velocity is v= √10gh/7
The energy that an object has due to its location in a gravitational field is known as gravitational potential energy. When an object is close to the surface of the Earth, when the gravitational acceleration can be assumed to remain constant at roughly 9.8 m/s2, gravitational potential energy is most frequently used.
For the situation of the maximum velocity of the sphere when it hits the ground, the loss in gravitational potential energy is equal to the gain in translational kinetic energy and rotational kinetic energy.
mgh = mv² x I / 2.
mgh = 0.5 mv² + 0.5 (2/5 mR²)
The no-slip condition results in:
v=Rω
mgh = 0.5 mv + 0.2 mv
⟹v= √10gh/7
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_____ in the uterus has to occur for a woman to confirm her suspicions that she is pregnant.
Fertilization
Implantation
Ovulation
Conception
The four vectors a1=[1,2,2],a2=[2,0,0],a3=[3,−3,0],a4=[1,1,1] span R3 (in other words, their span equals R3 ). Exactly one of the four vectors has the property that the span changes when you take it away. Which one? a1 a2 a3 a4
Vector a3 = [3, -3, 0] is the one that, when removed, causes a change in the span. To determine which vector causes a change in the span when removed, we can check if any of the vectors can be expressed as a linear combination of the remaining vectors.
Let's consider each vector one by one:
Vector\(a_1\)= [1, 2, 2]:
To check if a1 can be expressed as a linear combination of the remaining vectors, we solve the equation:
\(c_2 * a_2 + c_3 * a_3 + c_4 * a_4 = a_1\)
Solving this equation, we find that a1 cannot be expressed as a linear combination of \(a_2, a_3, and a_4.\)
Vector a_2 = [2, 0, 0]:
We check if \(a_2\)can be expressed as a linear combination of the remaining vectors:
\(c_1 * a_1 + c_3 * a_3 + c_4 * a_4 = a_2\)
Solving this equation, we find that \(a_2\) cannot be expressed as a linear combination of \(a_1, a_3,\) and \(a_4.\)
Vector \(a_3\) = [3, -3, 0]:
We check if a_3 can be expressed as a linear combination of the remaining vectors:
\(c_1 * a_1 + c_2 * a_2 + c_4 * a_4 = a_3\)
Solving this equation, we find that \(a_3\) can be expressed as a linear combination of a_1 and a_4:
\(3 * a_1 + (-3) * a_4 = a_3\)
Therefore, \(a_3\)can be expressed as a linear combination of the remaining vectors.
Vector a_4 = [1, 1, 1]:
We check if a4 can be expressed as a linear combination of the remaining vectors:
\(c_1 * a_1 + c_2 * a_2 + c_3 * a_3 = a_4\)
Solving this equation, we find that\(a_4\) cannot be expressed as a linear combination of\(a_1, a_2, and a_3.\)
Based on the above analysis, we can conclude that vector \(a_3\) = [3, -3, 0] is the one that, when removed, causes a change in the span.
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Show that the steady-state response of an SDF system to a cosine force, p(t) = p_0 cos omega t, is given by u(t) = p_0/k [1 - (omega/omega_n)^2] cos omega t + [2 zeta (omega/omega_n)] sin omega t/[1 - (omega/omega_n)^2]^2 + [2 zeta (omega/omega_n)]^2 Show that the maximum deformation due to cosine force is the same as that due to sinusoidal force.
The steady-state response of an SDF system to a cosine force is derived and shown to have the same maximum deformation as that due to a sinusoidal force.
SDF systemTo derive the steady-state response of an SDF (single-degree-of-freedom) system to a cosine force, we start with the equation of motion:
\(m u'' + c u' + ku = p_0 cos(\omega t)\)
where
m is the mass c is damping coefficient and k is spring constant of the system respectively, u is the displacement of the system from its equilibrium position, and p_0 is the amplitude of the cosine force.Assuming that the system has reached a steady state, we can take the derivative of the displacement with respect to time and substitute it back into the equation of motion to get:
\(-k u = p_0 cos(\omega t) - c \omega u' - m \omega^2 u\)
Next, we make the assumption that the displacement of the system is also a cosine function with the same frequency as the forcing function, i.e., \(u(t) = A cos(\omega t + \phi)\). Substituting this into the equation above and simplifying, we get:
\(A = p_0 / [k (\omega_n^2 - \omega^2)^2 + (2 \zeta \omega_n \omega)^2]^{0.5}\phi = -tan^-1[2 \zeta \omega_n \omega / (\omega_n^2 - \omega^2)]\)
where
\(\omega_n = (k/m)^{0.5}\) is the natural frequency of the system, \(\zeta = c / (2 m \omega_n)\) is the damping ratio, and A and phi are the amplitude and phase angle of the steady-state response, respectively.Therefore, the steady-state response of the SDF system to a cosine force can be expressed as:
\(u(t) = A cos(\omega t + \phi) = p_0/k [1 - (\omega/\omega_n)^2] cos(\omega t) + [2 \zeta (\omega/\omega_n)] sin(\omega t)/[1 - (\omega/\omega_n)^2]^2 + [2 \zeta (\omega/\omega_n)]^2\)
To show that the maximum deformation due to cosine force is the same as that due to sinusoidal force, we need to compare the maximum amplitudes of the steady-state responses of the system to both types of forces.
For a sinusoidal force of the same amplitude, \(p(t) = p_0 sin(\omega t)\), the steady-state response can be expressed as:
\(u(t) = p_0/k [1 / (\omega_n^2 - \omega^2)] sin(\omega t)\)
The maximum amplitude of the steady-state response due to a cosine force occurs when \(cos(\omega t + \phi) = 1\), i.e., at t = 0.
Therefore, the maximum amplitude is \(A = p_0 / [k (1 - (\omega/\omega_n)^2)^2 + (2 \zeta \omega/\omega_n)^2]^{0.5}\).
Similarly, the maximum amplitude of the steady-state response due to a sinusoidal force occurs when \(sin(\omega t) = 1\), i.e., at \(t = pi/2\omega\).
Therefore, the maximum amplitude is \(A = p_0 / [k (\omega_n^2 - \omega^2)^2 + (2 \zeta \omega_n \omega)^2]^{0.5}\).
Comparing these two expressions, we can see that they are the same, since \((1 - (\omega/\omega_n)^2)^2 = (\omega_n^2 - \omega^2)^2\).
Therefore, the maximum deformation due to a cosine force is the same as that due to a sinusoidal force.
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The graph shows the amplitude of a passing wave over time in seconds (s).
What is the approximate frequency of the wave shown?
Answer:
Option B. 0.3 Hz
Explanation:
From the question given above, the following data were obtained:
Period (T) = 3 s
Frequency (f) =?
Frequency is related to the period according to the following equation:
Frequency (f) = 1 / period (T)
f = 1/T
With the above formula, we can obtain the frequency wave as illustrated below:
Period (T) = 3 s
Frequency (f) =?
f = 1/T
f = 1/3
f = 0.3 Hz
Therefore, the frequency of the wave is 0.3 Hz
Answer:
The answer is 0.3 Hz
Explanation:
I took AP EX quiz.
22. Choose all of the following statements that are true about the vector (S) in the spin space in the state x(t)):
(I) The vector (S) can be thought to be precessing about the z axis at an angle 2a.
(II) The vector (S) can be thought to be precessing about the z axis with a frequency w = Bo
(III) All the three components of vector ($) change as it precesses about the z axis.
(a) (I) and (II) only
(b) (I) and (III) only
(c) (II) and (III) only
(d) (I), (II) and (III)
23. Choose a three dimensional coordinate system in the spin space with the z axis in the vertical di- rection. Draw a sketch showing the precession of ($) about the z axis when the state of the system starts out in a 1)2 + b ). Show the angle that (S) makes with the z axis and the precession frequency explicitly.
Show the projection of ($) along the z, y and z axes at two separate times. Explain in words why the projection of ($) along the z direction does not change with time but those along the r and y directions change with time.
The correct answer is (c) (II) and (III) only.
(I) The statement that the vector (S) can be thought to be precessing about the z axis at an angle 2a is incorrect. Precession about the z axis occurs at an angle a, not 2a.
(II) The statement that the vector (S) can be thought to be precessing about the z axis with a frequency w = Bo is true. The precession frequency is indeed to the external magnetic field strength (Bo).
(III) The statement that all three components of the vector (S) change as it precesses about the z axis is true. The x, y, and z components of the vector (S) change as it precesses due to the magnetic field interaction.
23. A sketch cannot be drawn in this text-based format, but I can describe the precession of the vector (S) about the z axis.
The projection of the vector (S) along the z axis will not change with time because the z component of (S) remains constant during precession. This is because the z component corresponds to the expectation value of the spin along the z direction, which is conserved in a system with rotational symmetry around the z axis.
On the other hand, the projections of (S) along the x and y axes will change with time as the vector (S) precesses. This is because the x and y components of (S) correspond to the expectation values of the spin along the x and y directions, which vary as the system precesses around the z axis.
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what is the momentum of a 2000 kg mass moving at 3 meters per second
Answer:
6000 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 2000 × 3
We have the final answer as
6000 kg.m/sHope this helps you
How is energy transferred during the water cycle? Question 1 options: Water gains energy during evaporation and releases it during condensation in the atmosphere Water gains energy during evaporation and condensation in the lithosphere. Water gains energy in condensation and releases it in evaporation. Water releases energy during evaporation and condensation.
Answer:
Water gains energy during evaporation and releases it during condensation in the atmosphere
Explanation:
In the water cycle, heat energy is gained or lost by water as it undergoes various processes in the cycle.
In evaporation, water molecules gains energy because the molecules of water vibrate faster and become more energetic. Hence they are able to escape into the atmosphere from the surface of the liquid.
In condensation, the molecules of gaseous water looses energy and becomes liquid.
Hence, water gains energy during evaporation and releases it during condensation in the atmosphere.
Answer:
K12 HE HE
Explanation:
1) An astronaut has a mass of 40Kg. Calculate his weight on earth if Gravity (g) = 10m/s^2.
2) The same astronaut goes to the International Space Station. Here the gravitational pull is equal to .5 m/s^2. Calculate his weight.
3) Our astronaut friend is assigned to study a neutron star. He travels to the surface using a special suit. Here the gravitational force is terrible at 150m/s^2 What is the astronaut’s weight?
Answer:
The formula is W=mg.
1.) W=40×10=400.
2.)W=40×5=200.
3.)W=40×150=6000.
what is the pressure exerted by the light on a mirror located at the same distance from the source, assuming normal incidence and total reflection?
The pressure exerted by light on a mirror located at the same distance from the source, assuming normal incidence and total reflection is very small, approximately 10^-5 pascals.
When light is incident on a surface, it exerts a radiation pressure that is equal to the power of the light divided by the speed of light. This pressure is very small for everyday objects, but it can be significant for objects with very low mass, such as mirrors. In the case of a mirror that is perpendicular to the incident light, all of the light is reflected back in the opposite direction. This means that the total force on the mirror is twice the radiation pressure, but since the pressure is so small, the force is also very small. Therefore, the pressure exerted by light on a mirror located at the same distance from the source, assuming normal incidence and total reflection is approximately 10^-5 pascals.
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5 ptsIn a Central Texas grassland, the producers incorporate 12,000 kJ of energy from the sun into their tissues. About how much energy would be incorporate into the tissues of herbivores?12,000 kJ1,200 kJ10,800 kJ1,080 kJ
In a Central Texas grassland, if producers incorporate 12,000 kJ of energy from the sun into their tissues, about 1,200 kJ of energy would be incorporated into the tissues of herbivores.
1. The energy transfer between trophic levels in an ecosystem follows the 10% rule. This means that, on average, only 10% of the energy stored in one trophic level is passed on to the next trophic level.
2. In this case, the producers (plants) in the Central Texas grassland have incorporated 12,000 kJ of energy from the sun into their tissues. These producers represent the first trophic level.
3. The herbivores, which are the primary consumers, feed on the producers and make up the second trophic level. To determine how much energy is incorporated into the tissues of the herbivores, you need to calculate 10% of the energy stored in the producer level.
4. To find 10% of 12,000 kJ, you simply multiply 12,000 kJ by 0.10 (10% as a decimal).
5. Calculation: 12,000 kJ * 0.10 = 1,200 kJ
So, about 1,200 kJ of energy would be incorporated into the tissues of herbivores in the Central Texas grassland ecosystem.
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A slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the bottom of the stairs (just before it stops moving) IF the Height of the stairs is 2 meters, the weight of the slinky is 4.41 Newtons, its spring constant is 0.84 N/m, and the distance the slinky is initially stretched (to get it going) is 0.25 meters??
Answer:
8.79 J
Explanation:
Given that a slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the bottom of the stairs (just before it stops moving) IF the Height of the stairs is 2 meters, the weight of the slinky is 4.41 Newtons, its spring constant is 0.84 N/m, and the distance the slinky is initially stretched (to get it going) is 0.25 meters??
Total energy = mgh
Total energy = 4.41 × 2 = 8.82 J
Elastic potential energy = 1/2 × Ke^2
Elastic potential energy = 1/2 × 0.84 × 0.25^2
Elastic potential energy = 0.02625
Also,
Total energy = P.E + K.E
Substitute them into the formula above
8.82 = 0.02625 + K.E
K.E = 8.82 - 0.02625
K.E = 8.79375
K.E = 8.79 J
Therefore, the KINETIC ENERGY of the slinky at the bottom of the stairs is 8.79 Joules approximately
2. Look again at the image. Let's now assume that it depicts a girl hugging her father before he
leaves for a tour of duty overseas. How could you use science to study the impact of her father's
departure on her family? (2 points)
Assume for the moment that it shows a young child embracing her mother before he departs for a tour of service abroad. How would you employ science to analyse her effects.
What subjects does science study?What in physics is an energy?
The definition of energy is ability to do work," which is the capacity to apply a force that causes an item to move. organismal biology the study of sentient creatures Social science is the study of people and society.
How does science benefit you as a learner?photo of How might science be used for research,Students who study science get the chance to learn more about how and how things work. Children can learn about the environment they live in through science.
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Answer: The science I would use to study the impact of the father’s departure from her family would be interpretive sociology.
Explanation: The reason I chose this science is because it focuses on the cause of people’s actions.
could you help me answer these question? thank you!
The isotope that is best for the preservation of food is technetium.
Which isotope is better for the irradiation of food?We know that a radioactive isotope is one that does decay after some time. This implies that the radioactive isotope would undergo the process of spontaneous disintegration and gradually disappears as it is converted to the daughter nucleus which may not be radioactive.
In this case, we know that what is being irradiated is food hence we have to look at the various options of the isotopes that we have and then look at the one that has the shortest half life.
The reason why we must go this way is that the isotope that has the shortest half life is more likely to be completely decayed in a short time before the food is consumed thereby posing no threat to the consumer.
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Which statement about the mass of a falling object is correct? A.It decreases as the object falls. B.It increases as the object falls. C.It is equal to the weight of the object. D.It stays the same as the object falls.
Answer:
D.It stays the same as the object falls.
Al tomar 5 medidas de masa para monedas de 25 centavos, obtuvimos masas de 12.45 g, 12.32 g, 12.54 g, 12.30 g y 12.50 g. Se te pide ofrecer el error relativo para el valor promedio de las 5 medidas. ¿Cuál es el error relativo si la masa teórica es 12.0 g?
a) 3.2%
b) 5%
c) 2.8%
d) 3.5%
Alguien me podria ayudar con esta pregunta??? :,D
Answer:
Explanation:
∑ m / 5 = (12.45 + 12.32 + 12.54 + 12.30 + 12.50) / 5 = 12.42
Δm = 12.42 - 12.0 = 0.42
ε·100% = Δm·100% / m = 0.42·100% / 12 ≈ 3.5 %
Answer:
d) 3.5%
Iron nail sinks in water but iron ship floats on
water. Why?
Answer: The weight of the water displaced by the ship is equal to its weight, so it floats.
Explanation:
Hope this helped you! Please brainliest if possible, if I am wrong, tell me! :D