which obsevation would be evidence that heat was transferred by radiation?

Answer:

Velocity includes direction.

Explanation:

Velocity is a vector, so it has direction and magnitude.

Answer:

Relative density is proportional to the frequency of a material's density to its water density. Because both have had the same proportions, their proportion is also dimensionless.

Explanation:

The dimension of relative density:-

Relative Density of a Substance (R.D.) = Substance Density / Water Density.

Therefore, R.D. Is just a ratio or a number. There are no units or dimensions to it.

For example:- The density of iron is 8.5 GM's/cm^3 & the density of water is 1 gm/cm^3 (in cgs units).

Tension:-   Surface tension is the propensity of the new worlds and infographics to reduce to the particle size which is least appropriate. Atmospheric pressure helps insects (e.g. water striders) can travel or move and on a water surface, typically object is sensed rather than water.

Answer:

has any one finished the lab yet?????

Explanation:

A lens with a diameter of 100 cm has a theoretical resolution limit of about 0.011 arcseconds for visible light observations.

The resolution of a telescope or lens is determined by its aperture size and the wavelength of the observed light. The theoretical limit of resolution is given by the Rayleigh criterion, which states that the smallest angular separation between two objects that can be resolved is approximately equal to the wavelength of the observed light divided by the aperture diameter.

For a lens of diameter 100 cm, the resolution can be estimated as:

resolution = wavelength / aperture diameter

Assuming a typical visible light arcseconds of 500 nm (5 x 10^-7 m), we can convert this to arcseconds using the formula:

1 radian = 206265 arcseconds

Therefore, the resolution in arcseconds is:

resolution = (wavelength / aperture diameter) * (180 / pi) * 3600 * 206265

resolution = (5 x 10^-7 m / 100 m) * (180 / pi) * 3600 * 206265

resolution ≈ 0.011 arcseconds

So a lens with a diameter of 100 cm has a theoretical resolution limit of about 0.011 arcseconds for visible light observations.

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Answer:

D is the answer

Explanation:

But do u know if im right test it out then surprise

The electromagnetic waves described in the reading are different in two ways, and that is Frequency and velocity. Hence, option D is correct.

A magnetic field and an electric field vibrate together to produce electromagnetic waves, often known as EM waves. In other terms, magnetic and electric fields that are oscillating make up electromagnetic waves (EM).

When a magnetic field and an electric field interact, electromagnetic waves are created. The term "electromagnetic waves" is used to describe them. An electromagnetic wave has an electric field and a magnetic field that are perpendicular to one another. They are likewise perpendicular to the EM wave's direction.

The wavelength and frequency of electromagnetic waves vary. Electromagnetic waves with longer wavelengths have lower frequencies, whereas those with shorter wavelengths have higher frequencies. Waves at higher frequencies carry more power. A wave's wavelength and frequency together determine its speed.

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Answer:

D. The speed of the combined vehicles is less than the initial speed of the truck.

Explanation:

Ik this is late

Answer: D. The speed of the combined vehicles is less than the initial speed of the truck.

Explanation:

Newton's Law of Cooling is described by the first-order linear differential equation dt/dT = k(T - Ts), where T(t) is the temperature of the object at time t, Ts is the surrounding environmental temperature, and k is the constant of proportionality.

The temperature of an object, governed by Newton's Law of Cooling

(i) To find the temperature of the object as a function of time, we first solve the differential equation dt/dT = k(T - Ts). This is a separable differential equation, and the solution can be obtained by rearranging and integrating:

dt/dT = k(T - Ts)

dt = k(T - Ts) dT

∫ dt = ∫ k(T - Ts) dT

t = k * ∫ (T - Ts) dT

t = k * (T^2/2 - Ts*T) + C

Now, we apply the initial condition T(0) = T0. At t=0, the temperature of the object is T0:

T(0) = T0

k * (\(T0^2\)/2 - Ts*T0) + C = T0

C = T0 - k * (\(T0^2\)/2 - Ts*T0)

C = T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2

C = T0 - k * (\(T0^2\) - 2 * Ts * T0) / 2

So, the equation becomes:

t = k * (\(T^2\)/2 - Ts*T) + (T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2)

(ii) Now, we can find the temperature of the object after 5 minutes (t = 5 minutes). We'll use the initial condition T(0) = T0 and the formula obtained in part (i):

t = 5 minutes = 5/60 hours = 1/12 hours

T(t) = Ts + (T0 - Ts) * exp(-kt)

T(1/12) = Ts + (T0 - Ts) * exp(-k * (1/12))

This equation gives us the temperature of the object after 5 minutes, considering the given initial temperature T0 and the surrounding environmental temperature Ts.

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A star's path through your sky depends on your latitude and the star's position in relation to Earth's celestial sphere. Latitude plays a significant role in determining which stars and constellations are visible at different times of the year. At higher latitudes, you will see a smaller portion of the sky, while at lower latitudes, you can observe more stars and constellations.

The star's position is determined by two coordinates: right ascension and declination. Right ascension measures the star's eastward distance from the vernal equinox along the celestial equator, while declination measures the star's north or south position relative to the celestial equator. These coordinates help determine the path a star takes across the sky.
As Earth rotates on its axis, stars appear to move in circular paths around the celestial poles. Stars closer to the poles will have smaller circular paths and may never set, becoming circumpolar stars. Stars closer to the celestial equator have larger paths and may rise and set, following a more diagonal path across the sky.

In summary, a star's path through your sky depends on your latitude and the star's position in the celestial sphere, determined by its right ascension and declination. These factors affect the visibility and motion of stars as they appear to travel across the night sky.

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Is more readily compacted than other states. has particles that can wiggle but cannot move has particles that travel freely from place to place will grow to entirely fill a closed container Plasma and gas have a lot in common in terms of characteristics.

The exterior of the nucleus is surrounded by negatively charged electrons. Scientists may find it challenging to monitor them because of how quickly they rotate.

The negatively charged components of an atom are known as electrons. All of an atom's electrons combine to form a negative charge that counteracts the positive charge of the protons in the atomic nucleus. In comparison to all the other components of the atom, electrons are quite tiny.

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Answer:

D. Is compressed more easily than other states

E. Has particles that can wiggle but cannot move

F. Has particles that move freely from place to place

G. Will expand to completely fill a closed container

Explanation:

Edge2023

Answer:

El coeficiente de roce estático entre las dos superficies es 0.131.

Explanation:

El coeficiente de roce estático entre dos superficies (\(\mu_{s}\)), sin unidad, es igual a la fuerza de resistencia (\(F\)), en newtons, dividida por el peso del cuerpo a mover (\(W\)), en newtons.

\(\mu = \frac{F}{m\cdot g}\) (1)

Donde:

\(m\) - Masa, en kilogramos.

\(g\) - Aceleración gravitacional, en metros por segundo al cuadrado.

Si sabemos que \(F = 45\,N\), \(m = 35\,kg\) y \(g = 9.807\,\frac{m}{s^{2}}\), entonces el coeficiente de roce estático es:

\(\mu = \frac{45\,N}{(35\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}\)

\(\mu = 0.131\)

El coeficiente de roce estático entre las dos superficies es 0.131.

Answer:

We know that a solar electrical panel converts sunlight to electricity by means of solar cells and then, the electricity can be used as any electrical current.

I am not familiar with solar heating panels but assume that a liquid is heated by sunlight and then circulated thru the area that needs heating - it converts heat from sunlight to usable heat. The heat energy could also be stored and delivered at a different time (accumulated during the day and delivered at night). This is somewhat similar to a company freezing water at night when electricity is cheaper and then using the cooled water during the day for cooling.

The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.

Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.

The distance traveled with the wind in 3 hours is 408 miles.

Therefore, we can write the equation as:

3(x + y) = 408

Divide both sides by 3:

x + y = 136  .... (1)

The distance traveled against the wind in 4 hours is also 408 miles.

Therefore, the equation can be written as:

4(x - y) = 408

Divide both sides by 4:

x - y = 102  .... (2)

Now we can solve these two equations using the elimination method.

Add equations (1) and (2):

x + y + x - y = 136 + 1022x = 238x = 119 mph

Therefore, the speed of the plane in still air is 119 mph.

Now, substitute this value of x in equation (1):

119 + y = 136y = 17 mph

Therefore, the speed of the wind is 17 mph.

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The correct question is:

A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?

The audibility threshold, also known as the hearing threshold, is the lowest sound intensity that can be heard by an individual. It varies for different frequencies and for different individuals.

For sounds at 8000Hz, the average audibility threshold is around 10dB.

This means that an individual can typically hear sounds at this frequency if they are at least 10dB in intensity.

For sounds at 1000Hz, the average audibility threshold is around 0dB.

This means that an individual can typically hear sounds at this frequency if they are at least 0dB in intensity.

It is important to note that these are average values and individual thresholds may vary. Factors such as age, hearing loss, and environmental noise can all affect an individual's audibility threshold.

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Answer:

1.) Check the explanation for the answer

2.) 10 MJ

Explanation:

Given that a coal power plant station generates electricity at night when it is not needed. Some of this energy is stored by pumping water up to a mountain lake. When there is high demand for electricity, the water is allowed to flow back through a turbine to generate electricity.1- Write down the forms of initial and final energy transfer.

Solution.

The initial conversion will be :

Chemical energy is converted to mechanical energy.

The final conversion will be :

Mechanical energy is converted to electrical energy. While the electrical energy is converted to light energy.

2- On one occasion, 2000 kg of water is pumped up through a vertical height of 500 m. Calculate the gravitational potential energy. (g= 10 m/s^2)

The gravitational potential energy can be calculated by using the formula

Energy = mgh.

Where

M = mass

H = height

g = acceleration due to gravity

Substitute all the parameters into the formula

Potential Energy = 2000 × 500 × 10

Potential energy = 10000000 Joule

Potential energy = 10 MJ

A halo around the sun or moon is often an indication that cirrostratus clouds are present.

Cirrostratus clouds are high-level clouds that form above 20,000 feet (6,000 meters). They are composed of ice crystals and have a thin, often transparent appearance. When these clouds are present, they can create a halo effect around the sun or moon.

The halo is formed when light from the sun or moon is refracted, or bent, as it passes through the ice crystals in the cirrostratus clouds. This refraction causes the light to spread out and create a ring or halo-like appearance around the sun or moon.

The presence of a halo is often an indication of thin, high-level cloud cover, typically preceding an approaching warm front or an area of moisture. It can also be a sign of changing weather conditions.

It is worth noting that halos can also be formed by other cloud types, such as altostratus or thin, wispy cirrus clouds, depending on the specific atmospheric conditions.

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Answer:

See explanation

Explanation:

Nuclear energy refers to energy trapped in the nucleus of atoms. Nuclear energy holds the greatest promise for large scale electricity generation. For instance, the amount of energy released by a given mass of uranium is 2.5 million times the energy released by combustion of an equal mass of carbon.One gram of uranium produces the same energy as 1 ton of coal, 17000 cubic feet of natural gas, 5000 pounds of wood and 149 gallons of oil.

Nuclear energy does not pollute the atmosphere as fossil fuels do. However, the challenges of effective control of the nuclear reactor and disposal of radioactive waste still remain a serious concern.

However, exploitation of nuclear energy as a source of electricity remain expensive and it is not quite easy to set up a nuclear power plant. Not many countries can afford to pay for the services of experts who operate nuclear energy plants talk more of providing the required equipment.

Answer:

The drawdown in a confined aquifer under transient conditions can be estimated using the Theis solution for the non-equilibrium radial flow of water. This solution is given by:

s = Q / (4πT) * W(u),

where s is the drawdown, Q is the pumping rate, T is the transmissivity, and W(u) is the well function (also called the Theis function) which depends on the variable u, where:

u = r²S / (4Tt),

where r is the distance from the pumping well and t is the time since pumping began.

Given T = 2500 m²/day, S = 1.0 x 10-3, and Q = 500 m³/day, we can calculate the drawdown at 10 m (r1 = 10 m) and 50 m (r2 = 50 m) for t = 150 days.

For (i) r1 = 10 m:

u1 = r1²S / (4Tt) = (10 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.000667

s1 = Q / (4πT) * W(u1) = 500 m³/day / (4π * 2500 m²/day) * W(0.000667).

For (ii) r2 = 50 m:

u2 = r2²S / (4Tt) = (50 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.01667

s2 = Q / (4πT) * W(u2) = 500 m³/day / (4π * 2500 m²/day) * W(0.01667).

Explanation:

Unfortunately, the well function W(u) cannot be evaluated directly without more specialized knowledge or tools. The well function is related to the exponential integral function, which requires numerical computation. You would typically use a table of values, a calculator with this function, or a computer program to evaluate it. After obtaining W(u), multiply it by the remaining fraction to find the drawdowns.

The height (y) of the pistol is 94 meters. To explain, we can use the fact that the horizontal and vertical motions are independent of each other.

To explain, we can use the fact that the horizontal and vertical motions are independent of each other. Since the bullet is fired horizontally, its initial vertical velocity is zero. We can use the equation for vertical motion:

\(y = (1/2)gt^2\)

where y is the vertical displacement, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time of flight.

The time of flight can be calculated using the horizontal distance and the horizontal velocity:

\(t = d/v\)

where d is the horizontal distance (196 m) and v is the horizontal velocity (356 m/s).

Substituting the values, we get:

\(t = 196 m / 356 m/s ≈ 0.551 seconds\)

Plugging this value into the equation for vertical motion, we find:

y = (1/2)(9.8 m/s^2)(0.551 s)^2 ≈ 94 meters.

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Copernican heliocentrism was a novel concept that fundamentally altered the geocentric view of the universe.

The father of modern astronomy is Nicolaus Copernicus, a Polish astronomer and mathematician. The heliocentric hypothesis of the solar system, which he initially put forth, states that Earth and other planets rotate around the sun.

Nicolaus Copernicus created the Copernican heliocentrism astronomical theory, which was first presented in print in 1543. This theory put the Sun in the center of the cosmos, stationary, and had Earth and the other planets orbit it at uniform speeds in circular orbits modified by epicycles.

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Answer:

A) Sue is lifting the bucket by a force of 49.035 newtons.

B) The bucket has an acceleration of 8.207 meters per square second on the Moon.

Explanation:

A) According to the First Newton's Law, a system is at equilibrium when it is either at rest or travelling at constant velocity. In this case, Sue must exert an external force on the bucket, whose magnitude is equal to the weight of the bucket but direction is opposed to it. By Second Newton's Law, we find that:

\(\Sigma F = F - m\cdot g = 0\) (1)

Where:

\(F\) - Lifting force, measured in newtons.

\(m\) - Mass of the bucket, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

If we know that \(m = 5\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the lifting force is:

\(F = m\cdot g\)

\(F = (5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)

\(F = 49.035\,N\)

Sue is lifting the bucket by a force of 49.035 newtons.

B) By the Second Newton's Law, we have the following model:

\(\Sigma F = F-m\cdot g = m\cdot a\) (2)

Where \(a\) is the net acceleration of the bucket, measured in meters per square second.

If we know that \(F = 49.035\,N\), \(m = 5\,kg\) and \(g = 1.6\,\frac{m}{s^{2}}\), then the net acceleration of the bucket is:

\(a = \frac{F}{m} -g\)

\(a = \frac{49.035\,N}{5\,kg}-1.6\,\frac{m}{s^{2}}\)

\(a = 8.207\,\frac{m}{s^{2}}\)

The bucket has an acceleration of 8.207 meters per square second on the Moon.

(a) The force applied by Sue in lifting the bucket at a constant velocity is 49 N.

(b) The acceleration of the bucket when lifted on the moon is 8.2 m/s².

The given parameters;

The force applied by Sue in lifting the bucket at a constant velocity is calculated as;

\(F = m(a + g)\)

\(F= mg\\\\F = 5 \times 9.8\\\\F = 49 \ N\)

The acceleration of the bucket when lifted on the moon with the calculated force is;

\(F = m(a + g)\\\\a+g = \frac{F}{m} \\\\a = \frac{F}{m} - g\\\\a = \frac{49}{5} - 1.6\\\\a = 8.2 \ m/s^2\)

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A = p + n (2) where n is the number of neutrons. When using atomic mass units (a.m.u.), the mass of each nucleon (proton or neutron) is 1 a.m.u, so the mass number also corresponds to the mass number.

some knee pads for soccer

The effect of collision during a soccer game can be minimized by wearing a shin protection gear called the shin guard.

The protection gear is usually worn in other to palliate the effect of collison during sporting activities.

As for football, the most vulnerable part of the body which is usually prone to damage during collision is the shin or knee.

Therefore, players often wear shin protection gear in other to minimize the risk of damage during collision.

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Answer:

Place the convex lens on a 'V' stand. . ii) Light a candle and take it far away from the lens along the principal axis. iii) Adjust the screen on the other side of the lens to get a clear image on it. iv) Measure the distance between the 'V' stand and the screen which gives a rough idea of the focal length of the lens.

When broken, tempered glass shatters into thousands of tiny pebbles, effectively eliminating the risk of human injury from sharp edges.

Tempered glass is a type of soda-lime glass that has been heat-treated to make it more durable. During the heat-tempering process, the exterior of the glass is force-cooled, causing it to solidify quickly while the centre cools more slowly. As the inside of the glass cools, it pulls on the stiff, compressed outer layer, causing tension in the centre.

Tempered glass is also known as safety glass because when it breaks, it breaks into relatively dull cube-shaped pieces rather than long, thin shards. For this reason, tempered glass is also used in passenger car windows and shower doors.

Hence, tempered glass plays an vital role in safety measures.

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I expect that they will add, and their effect at every location will be the sum of their individual effects at that location.

For example:

If they're acting at the same point and in opposite directions, the effect will be the same as a single force at that point, with strength equal to their difference, and in the direction corresponding to whichever one is stronger.