Which is the correct sequence of transfers in a typical coal fired power plant?

Which Is The Correct Sequence Of Transfers In A Typical Coal Fired Power Plant?

Answers

Answer 1

To find

Which is the correct sequence of transfers in a typical coal fired power plant?

Explanation

The coal is heated which converts the chemical energy to heat.This heat works as thermal energy which helps in rotation of the turbine which is the kinetic energy. This kinetic energy then works as a mechanical energy which prioduces electricity which is the electric energy

Conclusion

The correct sequence is

A. chemical-thermal-kinetic-mechanical-electrical


Related Questions

An ac series circuit contains a resistor of 20 ohms, a capacitor of 0.75 microfarads of 120 x 10-3 H. If an effective (rms) voltage of 120 V is applied, what is the effective (rms) current when the circuit is in resonance

Answers

Answer:

The effective (rms) current when the circuit is in resonance is 6 A

Explanation:

Given;

resistance of the resistor, R = 20 ohms

capacitance of the capacitor, C = 0.75 microfarads

inductance of the inductor, L =  0.12 H

effective rms voltage, \(V_{rms}\) = 120

At resonance, the impedance Z = R, Since the capacitive reactance (Xc) is equal to inductive reactance (XL).

The effective (rms) current, = \(V_{rms}\) / R

                                              = 120 / 20

                                              = 6 A

Therefore, the effective (rms) current when the circuit is in resonance is 6 A

How much power does it take to lift 30.0 N 10.0 m high in 10.00 s?

Answers

Answer:

60w

Explanation:

The power required is 30 Watt.

Let us recall that power is defined as the rate of doing work. Hence, we can write as follows;

Power = Work done/ time taken

Now;

work done =  Force × distance

Force = 30.0 N

Distance = 10.0 m

work done = 30.0 N × 10.0 m = 300 J

The power expended = 300 J/10.00 s = 30 Watt

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. Dan drags a box across the floor. He uses 95 N of force and moves the box 12 m. How much work does he do? 0.13 J 1,140 J 7.9 J 107 J

Answers

Answer:

\(1140\:\mathrm{J}\)

Explanation:

Work is given by \(W=F\Delta x\), where \(F\) is force and \(\Delta x\) is displacement.

Plugging in given values, we get:

\(W=95\:\mathrm{N}\cdot12\:\mathrm{m}=\fbox{$1140\:\mathrm{J}$}\).

keli learned that an air mass is a very large body of air with similar temperature humidity and pressure and the air mass are constantly in motion she knows that you're messing depending on the temperature and moisture content tent of region where they form she looked up more information about what makes them move what are the major causes for moving & Masten North America choose two that apply.

Answer choices
A. changing humidity
B. low temperature
C. jet storm
D. prevailing westerlies​

Answers

jet stream and prevailing westerlies

Air masses from the tropics and the equator are warm as they form over lower latitudes. The major causes for moving air masses North America exists jet storm.

What is meant by air mass?

An air mass is a volume of air that in meteorology is identified by its temperature and humidity. Many hundreds or thousands of square miles are covered by air masses, which adjust to the properties of the land underneath them. Latitude and their continental or maritime source regions are used to categories them.

Warmer air masses are referred to as tropical, whilst colder air masses are referred to as polar or arctic. Superior and maritime air masses are moist, whereas continental and superior air masses are dry. Air masses with various densities are divided by weather fronts. Once an air mass has left its original location, nearby plants and bodies of water can quickly change the way it behaves. Classification systems address both the properties and modification of an air mass.

Air masses from the tropics and the equator are warm as they form over lower latitudes. They move poleward along the southern edge of the subtropical ridge and are drier and hotter than those that originate over seas. Trade air masses are another name for tropical maritime air masses. The Caribbean Sea, southern Gulf of Mexico, and tropical Atlantic Oceans, east of Florida via the Bahamas, are the origins of maritime tropical air masses that have an impact on the United States.

Monsoon air masses are moist and unstable. Rarely do dry superior air masses touch the ground. A trade wind inversion, which is a warmer and drier layer over the more moderately moist air mass below, is typically created over maritime tropical air masses when they are located above them.

Therefore, the correct answer is option C. jet storm.

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Determine the magnitude and direction of the electric field at a point midway between a –8.0 µC and a +5.8 µC charge 6.0 cm apart. Assume no other charges are nearby.

Answers

The magnitude and direction of the electric field is equal to 3.45 x10^13 N/m and the direction in towards the negative charge.

Electric field

To calculate the electric field of a point it is necessary to use the following expression:

                                             \(E = k\frac{Q}{d^{2}}\)

Thus, calculating the field formed by each charge we have:

 –8.0 µC

   

                                    \(E = 9 \times 10^{9} \times \frac{8}{36\times 0.0001}\)

                                      \(E = 2\times 10^{13} V/m\)

+5.8 µC

                                   \(E = 9 \times 10^{9} \times \frac{5.8}{36\times 0.0001}\)

                                    \(E = 1.45 \times 10^{13} N/m\)

The direction of the electric field of the negative charge is towards the charge (attracted) and of the positive charge is repelled.

So, we can add the two values ​​of field found, since the two are directed towards the negative charge, so that :

                                       \(E = 2 \times 10^{13} + 1.45 \times 10^{13}\)

                                       \(E = 3.45 \times 10^{13} N/m\)

So, the magnitude of eletric field is equal to 3.45 x10^13 N/m and the direction in towards the negative charge.

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Engine 1 has an efficiency of 0.18 and requires 5500 J ofinput heat to perform a certain amount of work. Engine 2 hasan efficiency of 0.26 and performs the same amount of work. How much input heat does the second engine require?

Answers

Answer:

The input energy to  engine 2  is \(E_2 = 3807.7\ J\)

Explanation:

From the question we are told that

     The efficiency of engine one is  \(\eta_1 = 0.18\)

     The input energy required is \(E = 5500 \ J\)

       The efficiency of engine 2 is \(\eta_2 = 0.26\)

       

Generally the workdone by the engine 1  is mathematically represented as

       \(W_1 = E * \eta_1\)

=>     \(W_1 = 5500 * 0.18\)

=>     \(W _ 1= 990 \ J\)

Generally the workdone by engine 2  is mathematically represented as  

        \(W _2= E_1 * \eta_2\)

=>     \(W _2 = E_1 * 0.26\)

=>     \(W_2 =0.26E_1\)

From the question we are told that \(W_1 = W_2\)

So  

       \(990 =W_2 =0.26E_1\)

=>     \(E_2 = 3807.7\ J\)

         

Convert 25miles/hour to kilometers/hour. Show your work

Answers

Using the conversion factor that we have seen in the solution, the value obtained is 40.25 kilometers per hours

How do you convert miles/hour to kilometers per hour?

To convert miles per hour (mph) to kilometers per hour (kph), you need to multiply the speed value in mph by a conversion factor of 1.61, which is the number of kilometers in one mile.

Given that;

1 miles/hour = 1.61 kilometer per hour

25 miles per hour = 25 * 1.61/1

= 40.25 kilometers per hours

Hence the value that we get is 40.25 kilometers per hours

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The convert unit of  25 miles per hour is equivalent to 40.2335 kilometers per hour

Convert units calculation.

Unit conversion is the process of converting a value expressed in one unit of measurement to another unit of measurement that is equivalent in terms of its value or quantity. This is done by using a conversion factor, which is a numerical factor that relates the two units of measurement.

To convert miles per hour (mph) to kilometers per hour (km/h), we need to multiply the speed in mph by 1.60934, which is the conversion factor from miles to kilometers.

So, to convert 25 mph to km/h:

25 mph × 1.60934 = 40.2335 km/h

Therefore, 25 miles per hour is equivalent to 40.2335 kilometers per hour.

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from rest a skier skies decencing on the 30 degree slope .the coefficient of kinectic friction is 0.10
1 ;calculate the:
*acceleration of the skier
*speed of skier after 6.0s

Answers

Given:

Slope, θ= 30 degrees

Coefficient of kinetic friction, μ = 0.10

Let's find the following.

(a) Acceleration of the skier.

To find the acceleration of the skier, apply the formula:

\(mg\sin \theta-\mu mg\cos \theta=ma_{\text{net}}\)

Since we are to find acceleration, rewrite the equation for a:

\(a_{\text{net}}=g\sin \theta-\mu g\cos \theta\)

Where:

g is the acceleration due to gravity = 9.8 m/s²

μ = 0.10

θ= 30 degrees

Thus, we have:

\(\begin{gathered} a_{net}=9.8\sin 30-0.10\ast9.8\cos 30 \\ \\ a_{\text{net}}=4.9-0.85 \\ \\ a_{\text{net}}=4.05m/s^2 \end{gathered}\)

Therefore, the acceleration of the skier is 4.05 m/s².

Compare the weight of a 60 kg person on the earth with the weight of the same person on
the moon. Then, describe a quick (but very costly) way for dieters
at NASA to lose weight.

Answers

Answer:

Explanation:

The formula for weight is

W = mg, where

W = the weight of the object or person

m = mass of the object or person

g = acceleration due to gravity

Now, we're given the mass of the person to be 60 kd, and thus, the weight of that person would be

W = 60 * 9.81

W = 588.6 N

On the surface of the moon, the weight of the person would be

W = 60 * 1.625

W = 97.5 N

Therefore, the weight of the person on both surfaces are 588.6 and 97.5 respectively

HELP PLEASE DUE IN 3 MINUTES

HELP PLEASE DUE IN 3 MINUTES

Answers

Answer:

africa

Explanation:

África África ooo

The answer is Pangaea

Make a poem about waves with 12 Lines and 3 Stanzas.

Answers

In a ocean full of storms

A new wave was born

Deep into that darkness flooding

Suddenly, I heard some pummeling

By the grave I saw the winds

And the sun just shined

Answer:

a friendly face that comes with waves,

the waves of all the memorial days,

and with these days we smile with pride,

as for the waves we used to ride,

given up the day has passed,

how it went away like an hour glass,

as if we knew the world was right,

just like the waves, oh so bright,

the time has come the days have passed,

the waves ashore the waves alast,

as if the friendly face was right,

the waves that rode, oh goodnight.

Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next

Answers

Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

There are two correct answers:

A) A corporation leader makes direct payment to the candidate.

D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.

Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.

Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.

I hope this helps! Let me know if you have any other questions.


3. How many atoms are there in 1 kg of gold, if its atomic mass is 197 u?

Answers

Answer:

Let’s calculate the molar quantity of gold first.

(1000×g)/(196.97×g×mol^-1) = 5.077 mole

So we know that 1 mole of anything = 6.02214076×10^23 of individual objects.

So we can multiply this value by our molar quantity of gold.

5.077 × 6.02214076×10^23 = 3.057 × 10^24 atoms of gold.

Therefore, 1 kg of a gold bar has 3.057 × 10^24 atoms

Explanation:

A force of 255 N is applied to a stationary car of mass 500 kg for 18.3 s, the distance traveled by the car is

Answers

Answer:

170 m

Explanation:

force = ma

here a acceleration is unknown

but a = velocity/time = distance/(time)^2

255 = 500*d/(18.3)^2

d = 170 m

Why are most measures of speed an average?

Answers

Answer:

The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction.

Explanation:

2 ways in which a weather satellite can orbit the earth

Answers

Answer:

The two most common types of orbit are "geostationary" and "polar."

Answer:2 ways in which a weather satellite can orbit the earth

Explanation:

Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.

A.)What is the amplitude of the wave ? Include correct units.
B.)Use the graph to determine the time of one wave. Use it to find the frequency.
C.)If the speed of the wave is 25 m/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.

Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.A.)What

Answers

(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

What is the amplitude of the wave?

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

v is the speed of the wavef is the frequency of the wave

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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5.40 * 104 NS
6. A wooden ball with a mass of 0.45 kg is at rest when it is tapped by a wooden mallet that applies an
average force of 83 N to the ball. After contact with the mallet, the ball moves forward at 1.3 m/s. How
long was the mallet in contact with the ball?
A. 7.0 milliseconds
B. 3.7 milliseconds
C. 2.4 milliseconds
D. 0.59 milliseconds

5.40 * 104 NS6. A wooden ball with a mass of 0.45 kg is at rest when it is tapped by a wooden mallet

Answers

Answer:

A. 7.0 milliseconds

Explanation:

We know the formula: Force = [mass( final velocity - initial velocity )] / time

using the formula:

83 = 0.45 (  1.3 - 0 ) / time

time = ( 0.45 * 1.3 )/ 83

time  = 0.585/83

time = 7.0 milliseconds

The time for the mallet in contact with the ball is 7 milliseconds.

To find the time , the given values are,

Mass = 0.45 kg

Force = 83 N

Final velocity = 1.3 m/s, Initial velocity = 0 m/s.

What is Force?

According to Newton's second law of motion, Force is equal to mass that is multiplied by the acceleration.

F = m.a

where, F - Force

m - Mass

a - Acceleration

Here,  Acceleration = ( Final velocity - Initial Velocity) / ( Time )

Acceleration can be defined as the change in velocity with respect to time.

Force = [mass( final velocity - initial velocity )] / time

Substituting the given values in the formula,

83 = 0.45 (  1.3 - 0 ) / Time

Time = ( 0.45 * 1.3 )/ 83

Time  = 0.585/83

Time = 7.0 milliseconds

Hence, Option A is the correct answer.

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6. As distance increases, gravitational force *
(10 Points)
increases
decreases

Answers

It decreasessssssssss

Please help me! I don’t understand these types of problems.

Please help me! I dont understand these types of problems.

Answers

Answer:

60 m

Explanation:

also if u ever get stuck just look up displacment caculator it can help . Please give me brainlist

The small amount of missing mass that occurs when _____ atoms fuse to form helium
atoms is converted into energy in the form of heat and light.

nitrogen

hydrogen

barium

Ochromium

Answers

Answer:

hydrogen

Explanation:

Atomic fusion occurs when 2 or more atoms combine to create a new element.

Helium

Before figuring out what elements create helium, we need to understand its properties. Helium is the second element on the periodic table. It has 2 protons and usually 2 electrons in the base state.

There are technically ions but base helium will have 2 electrons, especially because it is a noble gas.

Fusion

In most cases, including this one, when 2 atoms fuse together you can add their protons together to find the atomic number of the new element. Since helium only has 2 protons, the elements fused to form helium must both have 1 proton.

The element with 1 proton is hydrogen. So, 2 hydrogen atoms fuse to form helium.

Real World Applications

Fusion can be seen across the universe. One of the most common examples of hydrogen fusing to become helium is in stars. Due to the heat within stars, 2 hydrogen atoms can fuse together to create helium. This process also creates energy in the form of heat and light that the star is made of.

The tires of a car make 73 revolutions as the car reduces its speed uniformly from 94.0 km/h to 60.0 km/h. The tires have a diameter of 0.84 m.

Part C: If the car continues to decelerate at this rate, how far does it go? Find the total distance.
Express your answer to three significant figures and include the appropriate units.

The tires of a car make 73 revolutions as the car reduces its speed uniformly from 94.0 km/h to 60.0
The tires of a car make 73 revolutions as the car reduces its speed uniformly from 94.0 km/h to 60.0

Answers

If the car continues to decelerate at this rate then the total distance of car is 324.91 meters.

What is decelerate?

When an object slows down, it undergoes deceleration, which is the opposite of acceleration. There are usually two ways that acceleration slows down. The first occurs when an object slows down by itself. Gravity, friction, or momentum loss could be to blame. The second is when the object is subjected to an external force, such as when a car driver applies the brakes or a pilot deploys the air brakes in an airplane. A journey that is both safe and successful requires deceleration, which is an essential component of movement.

When the vehicle revs at 73, then :

                       d₁ = R × θ

                        = 0.42×73×2× π

                               = 192.6 m

Using 2nd kinematic equation for distance traveled in next 16 sec:

                              θ₁ = wi × t + (1/2)× α ×t²

             θ₁ = 39.69 × 16 + (1/2) × (-2.5) × 16²

                                 = 315.04 rad

                 d₂ = R× θ₁

                        = 0.42× 315.04

                               = 132.31 m

So total stopping distance = 192.6 + 132.31

                                            = 324.91 m

Therefore, the total distance is 324.91 m.

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which characteristic of nuclear fission makes it hazardous?

Answers

Answer:The radioactive waste

Explanation:Fission is the splitting of a heavy unstable nucleus into two Lighter nuclei

7. Cellular respiration that uses oxygen is called ​

Answers

Answer:

Cellular respiration that uses oxygen is called ​Cellular respiration

Explanation:

Without oxygen, it's call fermentation.

An astronaut weights 8x10^2

Answers

Answer:

800

Explanation:

10^2 = 100
8 x 100  = 800

. Johnathan road his bicycle up a hill at a velocity of 17.15 m/s. Johnathan and his bicycle had
a combined mass of 88 kg. What was the height of the hill?

Answers

The height of the hill is 15 m.

What is the  height of the hill?

The height of the hill is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy at the bottom of the hill = Potential energy at the top of the hill

mgh = ¹/₂mv²

gh = ¹/₂v²

h = ( v² ) / ( 2g )

where;

v is the velocity of Johnathang is acceleration due to gravity

h = ( v² ) / ( 2g )

h = ( 17.15² ) / ( 2 x 9.8 )

h = 15 m

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Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!


Here is a function machine.



Input : multiply by 6. Subtract 80: output



The input is the same as the output. Find the input.


Also can you please show me an easy to work out these type of questions

Answers

Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

3) Little bunny FooFoo was hopping through the forest with a velocity of 1.5 m/s. The good
fairy came down for the 3rd time so FooFoo accelerated at 8.0 m/s2 for 0.5 seconds. What
was FooFoo's new velocity?
A) 5.5 m/s
B) 2.7 m/s
C) 2.5 m/s
D) 17.5 m/s
4) A car initially moving at 32 m/s slows to a stop in 15 seconds. What is the car's average

Answers

(3) FooFoo's new velocity is determined as 5.5 m/s.

option A is the correct answer.

(4) The average acceleration of the car is 2.13 m/s².

What is the final velocity of FooFoo?

The final velocity of the FooFoo is calculated by applying the following kinematic equation as shown below.

v = u + at

where;

v is the final velocity of the FooFoou is the initial velocity of the FooFooa is the acceleration of the FooFoot is the time of motion of the FooFoo

The given parameters include the following;

the initial velocity of FooFoo, u = 1.5 m/sthe acceleration of FooFoo, a = 8 m/s²the time of motion of FooFoo, t = 0.5 s

The final velocity of FooFoo is calculated as follows;

v = 1.5 + ( 8 ) ( 0.5 )

v = 5.5 m/s

The average acceleration of the car is calculated as follows;

v = u - at

where;

v is the final velocity of the car when it stops = 0u is the initial velocity of the car, u = 32 m/st is the time of motion of the car, t = 15 s

0 = 32 - 15a

15a = 32

a = 32 / 15

a = 2.13 m/s²

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The missing question is below:

4) A car initially moving at 32 m/s slows to a stop in 15 seconds. What is the car's average acceleration of the car?

A 15 kg block rest on a surface of a smooth plane incline at an angle 30 degree to the horizontal. A light in extensible string passing over a small Smooth Pulley at the top of the plane connect to the block to another 13/kg block hanging freely. find the acceleration of the resulting motion and the tension in the string.

If the coeficient of kinetic friction between the plane and the 15kg mass is 0.25. find the acceleration of the resulting motion

Answers

The acceleration of the system is 2.77 m/s² and the tension in the string is 127.4 N, given the provided values.

Given: Mass of the first block (m1) = 15 kgMass of the second block (m2) = 13 kgAngle of the plane (θ) = 30°Coefficient of kinetic friction (μk) = 0.25, Acceleration of the resulting motion (a) = ? Tension in the string (T) = ?First, we need to resolve the weight of the first block into its components perpendicular to and along the plane. Then we can use the component parallel to the plane to find the force of friction acting on the first block. We can then use the net force acting on the first block to find its acceleration. Finally, we can use the acceleration of the first block to find the tension in the string.Resolving the weight of the first block into components parallel to the plane: m1gsinθ = 15 x 9.8 x sin30° = 73.5 N. Perpendicular to the plane: m1gcosθ = 15 x 9.8 x cos30° = 127.5 N. Finding the force of friction acting on the first block: μk = coefficient of kinetic friction = 0.25f = force of friction acting on the first block N = normal force acting on the first block N = perpendicular force acting on the first block = 127.5 Nf = μkN = 0.25 x 127.5 = 31.88 NThe net force acting on the first block:F = maF = m1aF = m1g sinθ - fF = 15 x 9.8 x sin30° - 31.88F = 73.5 - 31.88F = 41.62 N. Acceleration of the first block: a = F/m1a = 41.62/15a = 2.77 m/s². Finding the tension in the string: The tension in the string is the force acting on the second block. We can use the weight of the second block and the acceleration of the first block to find the tension.T - m2g = m1aT = m2g + m1aT = 13 x 9.8 + 15 x 2.77T = 127.4 NTherefore, the acceleration of the resulting motion is 2.77 m/s² and the tension in the string is 127.4 N.

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27 1 point
A student has tested several types of wood for density. The best way of presenting this information graphically would be to use which item?
Scatterplot
Pie Chart
Line Graph
Bar Graph
Previous
Search

Answers

The best way of presenting the information on density graphically would be to use a D, bar graph.

What is a bar graph?

A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.

A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.

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