Which is likely to have the highest temperature

A red hot horseshoe

A spark from a firework

An ice cube

Answers

Answer 1

A. A red hot horseshoe is likely to have the highest temperature.

The temperature of an object is a measure of its average kinetic energy, which is related to the motion of its particles. The red hot horseshoe indicates that it has been heated to a high temperature, causing the metal to glow red. This implies that the horseshoe has absorbed a significant amount of thermal energy and its particles are vibrating rapidly, indicating a high temperature.

A spark from a firework, while hot and capable of causing burns, is typically short-lived and relatively small in size. It is formed by the rapid combustion or explosion of materials within the firework. While it can have a high temperature during its brief existence, it is unlikely to retain a consistently high temperature like the red hot horseshoe.

An ice cube, on the other hand, is at or near its freezing point, which is typically 0 degrees Celsius (32 degrees Fahrenheit). It represents the solid state of water and has a relatively low temperature compared to the red hot horseshoe. Therefore, the red hot horseshoe is likely to have the highest temperature among the given options, indicating significant thermal energy and particle motion. Therefore, Option A is correct.

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Related Questions

Does anyone understand this?

A cannon is recovered from a shipwreck. Why does the buoyant force on the cannon stay the same as long as it is fully under water? Explain your reasoning. (3 points)

Answers

The buoyant force on the cannon stays the same as long as it is fully under water because the buoyant force is determined by the volume of fluid that the cannon displaces and not by the weight or mass of the cannon itself.

Archimedes' Principle states that the buoyant force on an object in a fluid is equal to the weight of the fluid that the object displaces. This means that as long as the cannon remains fully submerged in the water and does not change its volume, the amount of water it displaces and thus the buoyant force on the cannon will also remain the same.

In other words, the buoyant force is dependent on the fluid's density and the volume of the object, not its weight. So, as long as the volume of the cannon and the density of the fluid surrounding it remain constant, the buoyant force will also stay constant.

The buoyant force on the cannon will stay the same as long as it is fully under water.

The buoyant force on an object is equal to the weight of the fluid displaced by the object. The buoyant force is always directed upwards, and it opposes the force of gravity. As long as the cannon is fully under water, the amount of water displaced by the cannon will stay the same. This means that the buoyant force on the cannon will also stay the same.

The buoyant force on an object depends on the density of the fluid, the volume of the object, and the acceleration due to gravity. The density of water is constant, so the buoyant force on the cannon will only change if the volume of the cannon changes or if the acceleration due to gravity changes.

Neither of these factors change. The volume of the cannon does not change as it is being recovered from the shipwreck. The acceleration due to gravity also does not change, as it is the same on Earth's surface as it is underwater.

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what will happen if the load is slided towards the fulcrum? ​

Answers

Answer:

The force exerted by the load will decrease.

Explanation:

Hope this helped!

An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.

Answers

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Which statement describes a primary difference between an electromagnetic wave and a mechanical wave

Answers

The primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

Difference between an Electromagnet and Mechanical Wave

A primary difference between an electromagnetic wave and a mechanical wave is the medium through which they propagate.

Electromagnetic waves can propagate through a vacuum or empty space without requiring a material medium. They are generated by the oscillation and interaction of electric and magnetic fields.

Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves can travel through space, air, or other materials, as they do not rely on physical particles to transmit energy.

On the other hand, mechanical waves require a physical medium to propagate. They are disturbances that travel through a material medium, transferring energy from one location to another. Mechanical waves rely on the interaction and displacement of particles within the medium to transmit energy.

Examples of mechanical waves include sound waves, water waves, seismic waves, and waves on a string. These waves cannot travel through a vacuum as they depend on the physical presence and interaction of particles within the medium.

In summary, the primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

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a b) what is the Change of density due to a rise in temperature OF 500k. The Coefficient of linear expansion of the material is 12x10-6​

Answers

The coefficient of linear expansion of a metal rod is 12 * 10 ^ 1 - 6/100 The value in per ^O Fplease mark as brainliest

Two arrows are fired horizontally with the same speed of 30.0 m/s. Each arrow has a mass of 0.100 kg. One is fired due east and the other due south. Find the magnitude and direction of the total momentum of this two-arrow system. Specify the direction with respect to due east.

Why do we have to do square root of the Momentum, also at the last to find the direction why we do Tan^-1. Please explain.

Answers

Answer:

P = P1 + P2     where P is a vector quantity

P1 = P2 = .10 kg * 30.0 m/s = 3 kg-m/sec

P = (p1^2 + p2^2)^1/2      add vectors and find magnitude of resultant

p = (3.0^2 + 3.0^2)^1/2 = 4.24      length of resultant vector

Since vectors are at right angles p is the length of the hypotenuse

tan θ = 3.0 / 3.0 = 1      where theta is measured with respect to the positive x-axis and will be below that axis

θ = tan^-1 1 = 45 deg      (45 degrees below positive x-axis)

One can find the value of tan θ from the length of the x-y vectors and from tan θ obtain θ

what are all the kinds of kinematic equations ​

Answers

There are four (4) kinematic equations, which relate to displacement, D, velocity, v, time, t, and acceleration, a. Kinematic Equations Formula Questions

v=v0+at. v = v 0 + at.
d=12(v0+v)t d = 1 2 ( v 0 + v ) t or alternatively vaverage=dt. v average = d t.
d=v0t+(at22)
v2=v20+2ad.


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An 5kg object is released from rest near the surface of a planet. The vertical position of the object as a function of time is shown in the graph. All frictional forces are considered to be negligible. What is the closest approximation of the weight of the object.
a) 300N
b) 30N
c) 5N
d) 150N

An 5kg object is released from rest near the surface of a planet. The vertical position of the object

Answers

Answer:

The correct option is b: 30 N.

Explanation:

First, we need to find the acceleration due to gravity (a):

\( y_{f} - y_{0} = v_{o}t - \frac{1}{2}a(\Delta t)^{2} \)   (1)

Where:

\(y_{f}\): is the final vertical position (obtained from the graph)

\(y_{0}\): is the initial vertical position (obtained from the graph)

v₀: is the initial speed = 0 (it is released from rest)

Δt: is the variation of time (from the graph)

From the graph, we can take the following values of height and time:

t₀ = 0 s → \(t_{f}\) = 5 s

y₀ = 300 m → \(y_{f}\) = 225 m

Now, by entering the above values into equation (1) and solving for "a" we have:

\( a = 2\frac{y_{0} - y_{f}}{(t_{f} - t_{0})^{2}} = 2\frac{300 m - 225 m}{(5 s - 0)^{2}} = 6 m/s^{2} \)

Finally, the weight of the object is:

\( W = ma = 5 kg*6 m/s^{2} = 30 N \)

Therefore, the correct option is b: 30 N.

I hope it helps you!                                                                                                            

statics and strength of materials

statics and strength of materials

Answers

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

What is the force P?

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ is the area of segment ABA₂ is the area of segment BC

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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radioactivity is characterized by order kinetics, so the rate of decay in a particular sample the number of nuclei present.

Answers

Since the decay rate is dependent upon the number of radioactive atoms, in terms of chemical kinetics, one can say that radioactive decay is a first order reaction process.

What is radioactivity ?

Radioactive decay is the loss of elementary particles from an unstable nucleus, ultimately changing the unstable element into another more stable element. There are five types of radioactive decay: alpha emission, beta emission, positron emission, electron capture, and gamma emission. Each type of decay emits a specific particle which changes the type of product produced. The number of protons and neutrons found in the daughter nuclei (the nuclei produced from the decay) are determined by the type of decay or emission that the original element goes through.

Also, radioactive decay is an exponential decay function which means the larger the quantity of atoms, the more rapidly the element will decay. Mathematically speaking, the relationship between quantity and time for radioactive decay can be expressed in following way:

dN/dt=−λN

or more specifically

dN(t)/dt=−λN

or via rearranging the separable differential equation

dN(t)/N(t)=−λdt

by Integrating the equation

ln⁡N(t)=−λt+C

with

C is the constant of integration.N(t) is the amplitude of N after lapse of time t.λ is the decay rate constant.

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Cells store waste in ________.
A
DNA

B
vacuoles

C
chloroplasts

D
ribosomes

Answers

Answer:

B vacuoles

Explanation:

why do some object remain hot for a long period of time and some object remain hot for short period of time ? urgent​

Answers

Some object remains hot for a long period of time because they have low thermal conductivity and some object remain hot for a short period of time because they have high thermal conductivity.

What is thermal conductivity?

Thermal conductivity is a property of a substance to allow heat to flow through it easily.

Thermal conductivity is a measure of how well a substance will conduct heat or not.

Objects that have high thermal conductivity gain heat easily and also lose heat easily. Hence, they get hot quickly and also get cold quickly.

Objects that have low thermal conductivity gain heat slowly and also lose heat slowly. Hence, they get hot slowly and also get cold slowly.

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In hiking, what fitness component is required of you

Answers

It’s strength, endurance and flexibility. Hope this helps

An air jet is flying with a constant speed at an angle of 30° above the horizontal as indicated in the figure below. The weight ⃗ of jet has magnitude W = 86 500 N and its engine provide a forward thrust ⃗ of magnitude T = 103 000 N. In addition, the lift force ⃗ (directed perpendicular to the wings) and the force ⃗ of air resistance (directed opposite to the motion) act on the jet. Determine the magnitude of ⃗ and ⃗ . (5)

Answers

To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

which of the following conditions are required for electricity to flow through a simple circuit? (choose all that apply)

Answers

Correct options are Option A and D, In series connections, the flow of electrons follow the same path as the current remains constant in all the elements of the circuits. And the total resistance of the circuit increases as more resistors are added to the circuit in serial manner.

There are both active and passive components in a circuit. The flow of current and potential drop across the passive devices will also be determined based on the connections between them.

Similar to how the voltage drop will remain the same even if the passive devices are connected in parallel, the current flow through each device will vary. Similar to this, if the passive devices are wired in series, the potential drop will change but the current flow will remain constant.

Due to the constant current flowing through all of the circuit's components in series connections, electrons follow the same route. And as more resistors are added to the circuit, its overall resistance rises.

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Complete question -

Which of the following statements accurately describes a series circuit? Select all that apply.

The flow of electrons follow the same path.

The flow of electrons split and follow different paths.

Different amounts of charge will be dropped across each resistor in the circuit.

The total resistance of the circuit increases as more resistors are added to the circuit.

The total resistance of the circuit decreases as more resistors are added to the circuit.

A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s. What speed does it have when it slides back down to its starting point?

Answers

A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s, Speed it will have when it slides back down to its starting point is 2.36 m/s

What is Friction?

The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab). The electromagnetic attraction between charged particles in two contacting surfaces, according to scientists, is what causes it.

using work energy theorem ,

change in kinetic energy = work done by frictional force

\(\frac{1}{2}\) m(\(x^{2}\)-\(y^{2}\)) =  μmghcos30°

where mass is m=200g

x is speed with which it slides back

y is speed at top of metal ramp=3.8 m/s

μ is coefficient of kinetic friction=0.3

g is gravity = 9.8m/\(s^{2}\)

h is height to which hockey puck is reached on metal ramp=1.18m

Substituting the values and solving for speed x,

x=2.36m/s

speed  it will have when it slides back down to its starting point is 2.36m/s

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A particle is moved along the x-axis by a force that measures 10/(1+x)^2 pounds at a point x feet from the origin. Find the work (in ft-lb) done in moving the particle from the origin to a distance of 9 feet.

Answers

Answer:

9 ft*lb

Explanation:

super simple but you just have to understand that the integral is going with the curve

work = integral a to b of f(x)dx = integral 0 to 9 of 10/(1+x)^2dx = 9ft*lb

A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?

Answer in kg

Answers

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Which of the following situations would cause the greatest decrease in the
motion of molecules in a system?

Answers

A

Explanation:

hindi ako sure kung tama ba yan

The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is 14900 N and acts as shown in the figure. In flight the engine produces a thrust of 61500 N that is parallel to the ground. The rotational axis in the figure is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to (a) the weight and (b) the thrust.

The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is

Answers

We have that for the Question, it can be said that With respect to this axis, the magnitude of the torque due to the weight and ,the thrust is

TW=19740N-mTT=130387.39N-m

From the question we are told

The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is 14900 N and acts as shown in the figure. In flight the engine produces a thrust of 61500 N that is parallel to the ground. The rotational axis in the figure is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to (a) the weight and (b) the thrust.

a)

Generally the equation for the Torque due to weight  is mathematically given as

\(TW=Engine weight*2.50*sin32\\\\TW=14900*2.50*sin32\)

TW=19740N-m

b)

Generally the equation for the Torque due to thrust  is mathematically given as

\(TT=Engine thrust*2.50*cos32\\\\TT=61500*2.50*cos32\\\\\)

TT=130387.39N-m

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Man-made climate change is an example
of...

Answers

Humans are increasingly influencing the climate and the earth's temperature by burning fossil fuels, cutting down forests and farming livestock. This adds enormous amounts of greenhouse gases to those naturally occurring in the atmosphere, increasing the greenhouse effect and global warming.

I got this from a book please do not copy it will be plagiarism. If helped mark me the brainiest!!!

Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides her bike at a constant speed for another
km. That part of her trip takes her 2 h. What is her average speed?

Answers

Answer:

Nicki's Average Speed is 6 km

Explanation:

If Nicki rides her bike at a constant speed for 1 hour, that means that Nicki will stay at a constant rate for another 2 hours.

Thus your answer: 6 km

plz plz helo me with this plz multi choice plz ASAP​

plz plz helo me with this plz multi choice plz ASAP

Answers

Answer:

Explanation:

#2 and for 2 i think that its the first one which says that there have to be a potential difference

#3 the answer is not at all

A car accelerates at a rate of 8.8 m/s2 with a force from the tires of 11,968 N.
What is the mass of the car?

Answers

Answer:

1360 kg

Explanation:

The mass of the car can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question we have

\(m = \frac{11968}{8.8} \\ \)

We have the final answer as

1360 kg

Hope this helps you

Answer:

\(\displaystyle 1360\:kg.\)

Explanation:

\(\displaystyle am = F_{net} \\ \\ \frac{11968}{8,8} = \frac{8,8m}{8,8} \\ \\ \boxed{1360 = m}\)

I am joyous to assist you at any time.

What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact

Answers

Answer:

The characteristics that determine how easily two substances change temperature are:

specific heat of the material that makes up the substancesarea in contact between the two substances

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

A 2.5 kg sledge hammer hit a cement block with a force of 6.0 Newtons.

How does the force the sledge hammer exerted on the cement block compare with the force the cement block exerted on the sledge hammer?

Responses

The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.

HURRY HURRY HURRY !!!The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.

The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.

Answers

When a 2.5 kg sledgehammer hit a cement block with a force of 6.0 Newtons. The force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.

What are opposite forces?

This refers to forces that act on an object in opposite directions. The net force is gotten by solving for the difference between the two forces.

When the opposing forces are equal or balanced, the net force is zero.  The sledgehammer hits with a force and the cement block is receiving the impart as a stationary object.

Obviously, the force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.

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A magnet is located above circular current. What is the direction of the magnetic force on the magnet

Answers

The magnet is attracted to the ring since the north pole of the current loop is above the ring and the south pole is below the ring.

The gravitational attraction between two objects increases if

Answers

Answer:

they are closer!!

Explanation:

Hope this helped!! :D

HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?

Answers

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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(05.04 HC)

Larry finds a lens and shows it to his friends, Mirez and Sherly. All three look through it. Larry looks at the window across the room with the lens and says the window looks upside down. Mirez said that he must be using it incorrectly, because when he looks at his thumb through the lens, it is definitely not upside down. Sherly says that she thinks it is broken, because when she looks through it, everything just looks blurry.

Using your understanding about image formation, explain each of their observations.

Answers

The explanation of each of their observations can be found below.

Explanation of observationsLarry observed the window appearing upside down when viewed through the lens. This is because the lens creates an inverted image of the object being viewed. The light rays from the object are refracted by the lens and converge at a point behind the lens to form an inverted real image.

Mirez observed that his thumb appeared normal when viewed through the lens. This is because the lens he used is a convex lens and it can create both real and virtual images, depending on the position of the object relative to the lens. For objects placed closer than the focal length of the lens, convex lenses produce virtual images that are upright, magnified, and on the same side of the lens as the object.

Sherly observed that everything appeared blurry when viewed through the lens. This might be because the lens is either scratched or dirty, which can cause aberrations in the image formation. Also, the lens might not be properly focused or the object is placed too far or too close to the lens, causing the image to be out of focus.

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