Which has the greatest number of hydrogen atoms? group of answer choices 1020 hydrogen atoms 100 g of a substance that is 2% h by mass 100 g of water 20 g of hydrogen gas

Iron ore, coke and limestone are three important raw materials for the production of iron. Iron ore is used for the production of iron, while coke is used for heating the iron ore and limestone is added as a flux to remove impurities from the iron during the smelting process.

Iron ore: Iron ore is a mineral that is mined and extracted from the ground. Iron is the most important raw material used in steel production. Iron ore is used to make steel. Iron ore is used to make iron and steel. Iron ore is melted down with coke, which is a carbon-rich fuel, in a blast furnace to create pig iron. The pig iron is then converted into steel in a steelmaking plant.Coke: Coke is a fuel made from coal that has been heated in the absence of air. Coke is used to heat the iron ore and create the high temperatures needed for the smelting process. Coke is an important raw material for the production of steel.

Coke is also used to produce other materials, such as chemicals and fertilizer.Limestone: Limestone is a sedimentary rock composed primarily of calcium carbonate. Limestone is used as a flux in the steelmaking process. The purpose of adding limestone to the blast furnace is to remove impurities from the iron, such as sulfur and phosphorus.

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Observing the formation of a silver mirror on the surface of a test tube when using Tollens' reagent indicates the presence of a reducing sugar.

Tollens' reagent is an aqueous solution of silver nitrate, sodium hydroxide, and ammonia used to test for the presence of aldehydes. The test is known as the Tollens' test, and it is based on the fact that aldehydes can be oxidized to carboxylic acids by silver ions.

In the presence of Tollens' reagent, the silver ions are reduced to metallic silver, which forms a silver mirror on the surface of the test tube when they are exposed to a reducing sugar.

Observing the formation of a silver mirror on the surface of a test tube when using Tollens' reagent indicates the presence of reducing sugar.

Reducing sugars are monosaccharides and disaccharides that can donate electrons to other molecules, resulting in their reduction.

Tollens' reagent is an oxidizing agent, and reducing sugars are oxidized by it to carboxylic acids.

As a result, the silver ions in Tollens' reagent are reduced to metallic silver, which forms a silver mirror on the surface of the test tube.

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Answer:

C

Explanation:

Answer:

8

Explanation:

Answer:

40

Explanation:

Ed 2020

Answer:

Explanation:

Potassium : Paramagnetic : Praseodymium

Potassium is a silvery-white metal that is soft enough to be cut with a knife with little force.

The reaction quotient, q, for this system when [h2] = 0. 200 m, [i2] = 0. 100 m, and [hi] = 3. 00 m is 450.

The reaction quotient, or Q, is a measure of the relative concentrations of the reactants and products in a chemical reaction. It is defined as the product of the concentrations of the products divided by the product of the concentrations of the reactants. In general, Q is used to determine whether a reaction is at equilibrium or not. If Q is equal to the equilibrium constant, K, then the reaction is at equilibrium. If Q is greater than K, then the reaction will proceed in the forward direction to reach equilibrium, while if Q is less than K, then the reaction will proceed in the reverse direction to reach equilibrium.

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The classification of each molecule according to its functional group is as follows:

1. alcohol: H₃C–CH₂–OH

2. alcohol: H–C–CH₂–CH₃

3. amine: H₃C–NH–CH₂–CH₃

4. ketone: H₃C–CH₂–C–NH₂

5. carboxylic acid: H–C–CH₂–CH₂–C–OH

6. halide: H₃C–CH–CH₂–CH₃

7. aldehyde: H₃C–CH₂–O–CH₃

8. ketone: H₃C–CH₂–C–NH₂

What is a functional group?

A functional group is a specific group of atoms within a molecule that determines its chemical behavior and properties. It imparts characteristic reactivity and functional properties to the molecule. Functional groups often participate in chemical reactions, influencing the overall behavior and functionality of the compound.

1. The molecule H₃C–CH₂–OH has the hydroxyl functional group (-OH) attached to a carbon atom, indicating it is an alcohol.

2. The molecule H–C–CH₂–CH₃ has the alkyl group (-CH₂–CH₃) attached to a carbon atom, indicating it is also an alcohol.

3. The molecule H₃C–NH–CH₂–CH₃ has the amino group (-NH₂) attached to a carbon atom, indicating it is an amine.

4. The molecule H₃C–CH₂–C–NH₂ contains the carbonyl group (C=O), making it a ketone.

5. The molecule H–C–CH₂–CH₂–C–OH has the carboxyl group (-COOH) attached to a carbon atom, indicating it is a carboxylic acid.

6. The molecule H₃C–CH–CH₂–CH₃ contains the halogen (Br) attached to a carbon atom, making it a halide.

7. The molecule H₃C–CH₂–O–CH₃ contains the carbonyl group (C=O) at the end of the carbon chain, indicating it is an aldehyde.

8. The molecule H₃C–CH₂–C–NH₂ contains the carbonyl group (C=O), making it a ketone.

These classifications are based on the presence of specific functional groups in each molecule, which determine their chemical properties and reactivity.

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To find the molarity of the solution, we first need to calculate the number of moles of LiNO3 present in the solution, using its given mass and molar mass.

The molar mass of LiNO3 can be calculated by adding the atomic masses of lithium (Li), nitrogen (N), and three oxygen (O) atoms:

Molar mass of LiNO3 = 6.94 g/mol (Li) + 14.01 g/mol (N) + 3 x 16.00 g/mol (O) = 68.94 g/mol

Next, we can calculate the number of moles of LiNO3 by dividing its mass by its molar mass:

Number of moles of LiNO3 = 1.66 g / 68.94 g/mol = 0.0241 mol

Finally, we can calculate the molarity of the solution by dividing the number of moles of solute by the volume of the solution in liters:

Molarity = Number of moles / Volume of solution in liters

The volume of the solution is given as 455 mL, which is equivalent to 0.455 L. Therefore, we can calculate the molarity as:

Molarity = 0.0241 mol / 0.455 L = 0.053 mol/L

Therefore, the molarity of the solution is 0.053 mol/L or 0.053 M (molar).

Option (b) is correct. The equation for the rate of formation of 1-iodobutane from the reaction of 1-chlorobutane with NaI by SN2 mechanism is K [BuCl] [NaI].

SN2 mechanism is also called bimolecular nucleophilic substitution reactions.  In this reaction the nucleophile attacks and the leaving group leaves is simultaneous. so the bond making between the nucleophile and the electrophilic carbon occurs at the same time as the bond breaking between the electrophilic carbon and the halogen.  It is a type of nucleophilic substitution where a lone pair of electrons on a nucleophile attacks an electron deficient electrophilic center and bonds to it resulting in the expulsion of a leaving group. This reaction is stereospecific. The rate determining step of SN2 mechanism include both the alkyl halide as well as nucleophile as both will be present in the transition step and a 5 membered unstable intermediate will be involved.

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The complete question is,

What is the equation for the rate of formation of 1-iodobutane from the reaction of 1chlorobutane with NaI by an sn2 mechanism?

a. Rate = k[BuCl]

b. Rate= k [BuCl] [NaI]

c. Rate = k[NaI]

d. Rate =  K [ Bucl]2

Answer:

Which combination are you talking about?

Hydrophobic interactions are more powerful than other weak intermolecular forces. If the interacting molecules are in an aqueous solvent, the hydrophobic interaction is relatively strong.

An intermolecular forces is an attractive force that exists between the positive components (or protons) of one molecule and the negative components (or electrons) of another molecule. This force influences a substance's physical and chemical properties. The boiling point of a substance is proportional to the strength of its intermolecular forces; the stronger the intermolecular forces, the higher the boiling point.

We can compare the intermolecular forces of different substances by comparing their boiling points. This is because the heat absorbed by the substance at its boiling point is used to break these intermolecular forces and convert the liquid to vapor. Intermolecular forces are responsible for the majority of matter's physical and chemical properties.

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The maximum amount of NADPH that can be produced from 2 glucose molecules is 12. In glycolysis, one molecule of glucose is converted into two molecules of pyruvate.

This process generates two molecules of NADH. Each NADH molecule can then be converted into NADPH through the action of the enzyme NADP+-dependent dehydrogenase.

Therefore, from one glucose molecule, we can produce 2 NADPH molecules. Since we start with 2 glucose molecules, we can double this amount. Thus, the maximum amount of NADPH that can be produced from 2 glucose molecules is 2 x 2 = 4 NADPH molecules.

In addition to glycolysis, glucose can also enter the pentose phosphate pathway (PPP) where it is converted into ribose-5-phosphate and NADPH. In the oxidative phase of the PPP, each glucose molecule generates 2 NADPH molecules. Therefore, from 2 glucose molecules, the PPP can produce an additional 2 x 2 = 4 NADPH molecules.

Adding up the NADPH produced from both glycolysis and the PPP, we have a total of 4 NADPH + 4 NADPH = 8 NADPH molecules.

Therefore, the correct answer is b) 12, as we can produce a maximum of 12 NADPH molecules from 2 glucose molecules through the combined actions of glycolysis and the pentose phosphate pathway.

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In IR spectroscopy, vibrational frequency is directly proportional to the energy of the vibrational mode, which in turn is proportional to the strength of the chemical bond and the masses of the atoms involved in the bond.

In infrared (IR) spectroscopy, vibrational frequency is directly proportional to the energy of the vibrational mode. Specifically, the vibrational frequency of a molecule is directly proportional to the strength of the chemical bond and the masses of the atoms involved in the bond. As the vibrational frequency increases, the energy of the bond also increases. This is because the bond becomes stiffer and requires more energy to vibrate. Therefore, IR spectroscopy can be used to identify the types of chemical bonds present in a molecule by measuring the vibrational frequencies of the bonds.

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Sodium metal is  the excess reagent and after the completion of  the reaction 16.8g of it is left.

In a chemical reaction, the reactant which is present in excess and don't get fully used up in the reaction is called excess reagent.

            no. of moles (n)/stoichiometry coefficient.

       The reactant with greater value will be the excess reagent.

                  \(2Na+Cl_2\) ⇒  \(2NaCl\)

         where given mass of Na is 20g    molecular weight=23g

                     given mass of \(Cl_{2}\) is 10g    molecular weight=71g

        n=given mass/ molar mass                         n=given mass/ molar mass  

        =20/23                                                            =10/71

         S.C=2                                                              S.C.=1

        so n/S.C value is 0.43                                   so n/S.C value is 0.14

Since value is high, Na is                                   Since value is lower, \(Cl_{2}\)      excessive reagent.                                             is limiting reagent.      

          according to the equation, 71g of \(Cl_{2}\)  react with 23g of Na

                                                         1g ≡ 23/71

                                                       10g ≡ 23/71 *10

                                                              =3.2g of Na

         the amount of Na left is 20-3.2 =16.8g

Hence Na is the excess reagent with 16.8g of it remains.

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The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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Answer:

Isn't the sand's temperature higher?

Explanation:

I don't really have a good explanation but over time the trend line in temperature for sand is higher than for water

Answer:

its d injus took the test

Explanation:

Decreasing the temperature in order to increase molecule collisions would not increase the rate of dissolving.

This is defined as causing a solute to pass into a solution through the aid of the solvent.

Increasing the temperature will increase molecule collisions and the rate of dissolving which was why option D is chosen as the most appropriate choice.

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The amount of aluminum that can be formed by the passage of 305 C (coulombs) through an electrolytic cell containing a molten aluminum salt is 0.0286 g

Faraday's law of electrolysis states that the amount of substance produced during electrolysis is directly proportional to the amount of electricity passed through the cell. The relationship can be expressed by the equation:

moles of substance = (current in amperes x time in seconds) / (Faraday's constant x charge on one mole of the substance)

where Faraday's constant is 96,485.3 C/mol and the charge on one mole of aluminum is 3 x 96500 C (since aluminum has a 3+ charge in the electrolyte). To find the mass of aluminum produced, we need to first calculate the number of moles of aluminum produced, and then multiply by its molar mass (27 g/mol).

So, the number of moles of aluminum produced is:

moles of aluminum = (305 C / (3 x 96500 C/mol)) x (1 A / 1 C) x (1 s / 1 s)

moles of aluminum = 0.001059 mol

Finally, the mass of aluminum produced can be calculated by multiplying the number of moles by the molar mass:

mass of aluminum = 0.001059 mol x 27 g/mol

mass of aluminum = 0.0286 g

Therefore, approximately 0.0286 grams of aluminum can be formed by the passage of 305 C through an electrolytic cell containing a molten aluminum salt.

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A 12.0 g sample of mgcl2 that was dissolved in water has a purity of 99.0% (measured as a mass percentage). All of the chloride ions in the solution had to be precipitated using 0. 2500mol of Silver nitrate.

The essential electrolyte chloride ion, found in all body fluids and responsible for maintaining acid/base balance, transmitting nerve impulses, and controlling fluid in and out of cells, is a chlorine anion that makes up the negatively charged portion of some salts, such as sodium and hydrogen chloride ions.

The precipitation reaction that is occurring in this situation is:

Mgcl2 + 2AgNo3 = Mg(No3)2 + 2AgCl.

As a result, the following mass of magnesium chloride is consumed for the 0.2500 moles of silver nitrate (take into account their 2:1 molar ratio):

11.90 g of MgCl2 per m

Therefore, the purity of the silver nitrate sample is:

Purity = 11.90g/12.00g*100

Purity = 99%

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Students are conducting an experiment to see what colors different salts turn when they are burned. Jack dares Rebecca to taste the other salts to see if they taste like regular table salt. She agrees and her mouth starts burning. Rebecca needs to learn how to behave in the class.

When you add salt to a fire, the flame's color will alter. This isn't because the salt is burning; rather, it happens because the flame's heat affects the energy of the salt's electrons, which causes photons of light to be released. When salt is "burned," a golden flame is frequently visible.

High blood pressure is known to increase the risk of stroke and other health issues, and it is also known to increase the chance of burning in salt. High salt consumption has also been linked in several studies to deteriorating brain function. So, if this occurs, plan for brain surgery and a dedicated teacher to assist the student with wiping and peeling bananas.

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Chemotaxis refers to the release of chemicals that dispatch white blood cells and platelets to areas of injury.

The term chemotaxis is derived from two words chemo, meaning a chemical substance and taxis meaning movement of an organism in response to a stimulus such as light or the presence of food.

The release of chemicals in case of injury is an example of positive chemotaxis which leads to the healing of the wound.

Neutrophils, which are a type of white blood cell that help in healing damaged tissues and resolving infections, migrate to places where there is an infection or tissue injury.

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Well most water on Earth is in the oceans, which is made of salt water.

hope this helps, good luck! :)

We are only able to use 1/4 of the water on Earth because most of the water on earth is marine or salt water.

Truly, the earth is made up of a very large percentage of water. In fact, there is only a small fraction of land that is available on earth.

However, 3/4 of this water supply is marine or salt water. Salt water is unfit for drinking, neither can it be used for domestic or industrial use.

The implication of this is that we have only 1/4 of the water supply available to us as fresh water which can be used for drinking, industrial and domestic purposes.

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The elements Bromine(Br) and Sulphur(S) undergo changes in oxidation number in the given reaction.

Given reaction:

\(2H_2SO_4(aq) + 2NaBr(s) - > Br_2(l) + SO_2(g) + Na_2SO_4(aq) + 2H_2O(l)\)

The elements that undergo changes in oxidation number are:

Bromine (Br):

In NaBr, the oxidation number of Br is -1.

In \(Br_2\), the oxidation number of Br is 0.

Sulfur (S):  

In \(H_2SO_4\), the oxidation number of S is +6.

In \(SO_2\), the oxidation number of S is +4.

All other elements in the reaction (H, O, Na) maintain a consistent oxidation number throughout the reaction.

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i cant understand your question define briefly

Answer:

The number of outer shell electrons determines the group number of the element. The number of occupied principle quantum shells (energy levels) determines the period of the element. The proton number determines the element itself and its position.

Explanation:

The estimated age of the rock is approximately 1.58 x 10^10 years.

To estimate the age of the rock based on the mass ratio of 208Pb to 232Th, we can use the concept of radioactive decay and the half-life of 232Th.

The ratio of 208Pb to 232Th in the rock represents the amount of 208Pb that has been formed through the radioactive decay of 232Th over time. Since one 208Pb atom is the final decay product of one 232Th atom, the mass ratio can be used to determine the fraction of 232Th that has decayed.

Given that the mass ratio of 208Pb to 232Th is 0.28/1.00, we can calculate the fraction of 232Th that has decayed as follows:

Fraction of 232Th decayed = (1 - mass ratio of 208Pb/232Th) = (1 - 0.28/1.00) = 0.72

The fraction of 232Th that has decayed corresponds to the fraction of the original amount of 232Th present in the rock. Using the concept of half-life, we can relate this fraction to the age of the rock.

Since the half-life of 232Th is 1.39 x 10^10 years, we can calculate the number of half-lives that have passed using the fraction of 232Th decayed:

Number of half-lives = log(base 0.5) (fraction of 232Th decayed)

Number of half-lives = log(base 0.5) (0.72) ≈ 1.14

The number of half-lives represents the time elapsed, and each half-life is equal to 1.39 x 10^10 years.

Therefore, the age of the rock can be estimated as:

Age of the rock = Number of half-lives x Half-life of 232Th

= 1.14 x 1.39 x 10^10 years

≈ 1.58 x 10^10 years

The estimated age of the rock is approximately 1.58 x 10^10 years.

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Answer: What kingdom is an organism with these characteristics: Eukaryotic, Multicellular,. Heterotrophic, Reproduce Sexually, and Most have the ability to move on their ...

Missing

please brainleast

Explanation:

Eubacteria is a category of organisms that is heterotrophic eukaryotes, that can reproduce sexually or asexually.

Living entities have the ability to reproduce, grow, and maintain homeostasis. Organisms are categorized by taxonomy into specific classes, such as multicellular organisms like animals, plants, and fungi, or single-celled organisms like bacteria, archaea, and protists.

Whether its a prokaryote or perhaps a eukaryote can make up an organism. Bacteria and archaea are the two distinct domains that represent prokaryotes. Eubacteria is a category of organisms that is heterotrophic eukaryotes, that can reproduce sexually or asexually.

Therefore, Eubacteria is a category of organisms that is heterotrophic eukaryotes, that can reproduce sexually or asexually.

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Answer:

[C] If people brush their teeth twice a day, then they will get fewer cavities.

Explanation:

C is the only correct option because the hypothesis is not an opinion (unlike the rest of the options), and the hypothesis is able to be tested, and accurate data is able to be collected.

Answer: Helium has the smallest radius.

Explanation: Helium has the smallest atomic radius. Due to nuclear charges and stuff ect-