Answer: B, Companies passed on production and transportation costs to consumers
Explanation:
A higher oil price occurred when companies passed on production and transportation costs to consumers.
Cause of high price of oilThe oil producing companies spend so much money in producing crude oil from the reservoirs to the surface. They also spend money in processing and transporting the crude oil to the end users or consumers.
The final price of the oil depends on the total amount spent by these companies in producing the hydrocarbons.
Thus, a higher oil price occurred when companies passed on production and transportation costs to consumers.
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The design of a new road includes a straight stretch that is horizontal and flat but that suddenly dips down a steep hill at 18°. The transition should be rounded with what minimum radius so that cars traveling 95 km/h will not leave the road
Answer:
74.7 m
Explanation:
You want the minimum radius of curvature of a vertical circular arc so that vehicles traveling 95 km/h making the transition from horizontal to an 18° down grade will not leave the road.
AccelerationThe acceleration due to gravity on the vehicle at the point it is traveling 18° down is ...
g·cos(18°) ≈ (9.8 m/s²)·0.95106 ≈ 9.32 m/s²
RadiusThe radius of an arc and the speed of travel are related to the normal acceleration by ...
r = v²/a
where v is the speed along the arc, and 'a' is the normal acceleration required to make an object follow the circular curve.
The speed of 95 km/h can be translated to m/s by ...
(95 km/h) · (1000 m/(1 km)) · (1 h)/(3600 s) = 95/3.6 m/s ≈ 26.389 m/s
RadiusUsing the above relation to find the radius, we get ...
r = (26.389 m/s)²/(9.32 m/s²) ≈ 74.72 m
The minimum radius of the vertical circular arc should be 74.7 meters to prevent vehicles from becoming airborne.
__
Additional comment
In actual roadway design, factors of sight distance and stopping distance come into play. Sight distance over this crest would be about 25 m. It would need to be more than 6 times that distance for the roadway to be safe at 95 km/h.
An 18° down grade is about 3 times the usual maximum for roadway design, which will severely increase stopping distance. The vertical arc described here would leave the car with no normal force on the roadway at the end of the arc, so braking would be impossible. Passengers would be feeling weightless, too.
Roadway curves are generally parabolic (not circular), so they have a constant rate of change of slope with horizontal distance.
what will happen if the 9 base sequence aactgctc had a mutation in the gene
If the 9 base sequence "aactgctc" had a mutation in the gene, it would result in a change in the nucleotide sequence.
The specific nature and consequences of the mutation would depend on the type of mutation that occurred.
Mutations can include substitutions, insertions, or deletions of nucleotides.
Substitutions replace one nucleotide with another, potentially altering the amino acid sequence during protein synthesis.
Insertions or deletions can shift the reading frame, leading to a frameshift mutation and potentially changing the entire amino acid sequence downstream.
The functional impact of the mutation would depend on its location within the gene and the resulting changes in the protein's structure or function.
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If the x-component of vector A in the figure below is 3cm and the y component of A is 4cm, then what is the vector quantity of A?
Question 9 options:
25 cm - 37 degrees
7 cm - 37 degrees
7 cm - 53 degrees
5 cm - 53 degrees
Answer:
5 cm - 53 degrees
Explanation:
\( \sqrt{ {4}^{2} + {3}^{2} } = 5cm\)
\( \tan ^{ - 1} (4 \div 3) \) = 53°
Light and Reflection
Diagram Skills
E
STI
500
Mirrot
Flat Mirrors
1. The point of a 20.0 cm
D
pencil is placed 25.0 cm
from a flat mirror. Its
eraser is 15.0 cm from
the mirror. Three of the
light rays from the
pencil's point hit the
mirror with incident
angles of 0°, 20°, and
50° at points A, B, and C as shown.
a. Use a protractor to draw the reflected rays from points A, B, and C.
b. Where do reflected rays or their extensions intersect?
Mirror
B
c. What is the distance between the pencil's head and its image?
d. Would a person's eye located at point D perceive one of the reflected rays
drew? Will the person be able to see the image? Explain.
e. What if the eye is located at point E?
f. Draw incident rays from the eraser of the pencil to point A and to poin
The law of reflection allows to find the results for the questions about ray reflection in a plane mirror are:
a) Attachment we see a diagram of the incident and reflected rays, incident and reflected angles are equal.
b) The extension of the reflected rays is what forms the image.
c) The image's distance is 20 cm behind the flat mirror.
d) The point D (normal for an angle of 50º) cannot perceive the rays coming from point A, B, C
e) the Rays at points A, B, C cannot perceive in the point E.
f) attachment we see the rays that come out from the pencil eraser.
g) The image is behind the mirror at 15 cm.
The geometric interaction describes the interaction of light rays with surfaces, looking for where the rays are directed, it is described by two phenomenological laws:
Refraction. Establishes a relationship between incident rays and those transmitted by material means. Reflection. It establishes that the angle of incidence and reflection of the rays is the same.\(\theta_i = \theta_{r}\)
From these two general laws, geometric optics establishes a relationship for the formation of the image, called the constructor's equation.
\(\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\)
Where f is the focal length, p and q are the distance to the object and the image, respectively.
In this exercise, the medium is a mirror, which is why it must comply with the law of reflection.
a) In the attachment we see a diagram of the incident and reflected rays for the three points.
According to the law of reflection, the incident and reflected angles are equal.
b) From the diagram we can see that the extension of the reflected rays is what forms the image, which is called virtual and is located behind the mirror.
c) In the diagram we see two rays to form the image, we see that the distance to the object is equal to the distance to the image.
From the constructor's equation a plane mirror has an infinite radius.
p = -q
Therefore the image's distance is 20 cm behind the flat mirror. Therefore the distance to the object and the image are the same, the negative sign indicates that the image is behind the mirror.
d) A person located at point D (normal for an angle of 50º) cannot perceive the rays coming from point A, B, C since their angle of reflection is not equal to the incident angle.
To perceive a ray it must have an angle of incidence of 25º.
e) Point E is located very far from the pencil, so the incident angle increases as does the reflected angle.
the Rays at points A, B, C cannot perceive.
f) In the attachment we see the rays that come out from the pencil eraser, they indicate that the distance to the plane mirror is 15.0 cm,
g) The image is behind the mirror at 15 cm.
In conclusion using the law of reflection we can find the results for the questions are:
a) Attachment we see a diagram of the incident and reflected rays, incident and reflected angles are equal.
b) The extension of the reflected rays is what forms the image.
c) The image's distance is 20 cm behind the flat mirror.
d) The point D (normal for an angle of 50º) cannot perceive the rays coming from point A, B, C
e) the Rays at points A, B, C cannot perceive in the point E.
f) attachment we see the rays that come out from the pencil eraser.
g) The image is behind the mirror at 15 cm.
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EMERGENCY! PLS HELP
An isotope of Cesium-137 has a half-life of 30 years. If 6 grams of Cesium-137 decays over a period of 90 years, how many grams of Cesium would remain?
Answer:
0.75 grams
Explanation:
Today we have 6 grams
In 30 years, 3 grams remain
In 60 years 1.5 grams remain
in 90 years 0.75 grams remain
mathematically It would look like this
m = 6(0.5⁽ⁿ/³⁰⁾) where n is number of years
Why can't cars be constructed that can magnetically levitate in Earth's magnetic field?
a. The current needed would be excessive.
b. The current within the car must flow in a complete circuit, about half Of which would exert forces against levitation.
c. Magnetic forces are always very weak.
d. Earth's magnetic field is in the wrong direction.
What is the best description of realistic fiction o texts that are written in first person about a period in an author's life?
An autobiography, like a memoir, is the writer's recounting of his or her life and is written in the first person, making the writer the protagonist of the narrative.
What phrase best sums up a realistic piece of fiction?Contemporary/Realistic: In order to accurately portray our environment and society, realistic fiction develops fictional people and circumstances. Growing up and dealing with social and personal issues are the main themes. Characters in this genre are depicted as they learn about both themselves and others.
Which of these two realistic fiction subgenres predominates?Historical and contemporary fiction make up realistic fiction's two subgenres. Unlike current fiction, which takes place in the present or recently past, historical fiction takes place at a period that is far enough back in history to be deemed history.
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Answer: the answer is b
Explanation:
edge
A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?
The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.
If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.For such more question on magnitude
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When floating a ping-pong ball with a hairdryer, which two forces are balanced?
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
There are two forces which are being balanced :
(Ⅰ) The force of gravity which is pushing the ping-pong ball downwards.
(Ⅱ) The force of the air that's coming from hairdryer which is pushing ping-pong ball upwards.
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
Heyyy! Okay riddle of the day
no looking up the answers. If you don’t know move on.
Here’s the riddle: what time is it when an elephant sits on a fence?
Answer:
Time to get a new fence...?
C'mon that's pretty cringe lol
Please give brainliest
have a nice day :D
Define reflection of sound?
A car accelerates uniformly from rest tona speed of 30.0 mi/h in 12.0s. Find the distance the car travels during this time? Find the constant acceleration of the car?
Answer:
2.5 mi/s^2
Explanation:
please see paper for work!
What do you mean is a variable velocity and uniform velocity
Answer:
Uniformly accelerated rectilinear motion (MRUA), also known as uniformly varied rectilinear motion (MRUV), is one in which a mobile moves along a straight path being subjected to a constant acceleration.
Explanation:
A rocket rises vertically, from rest, with an acceleration of 3.2 m/s2 until it runs out of fuel at an altitude of 850 m . After this point, its acceleration is that of gravity, downward.
Answer:
v = 73.75 m/s
Explanation:
It is given that,
A rocket rises vertically, from rest, with an acceleration of 3.2 m/s² until it runs out of fuel at an altitude of 850 m.
Let us assume we need to find the velocity of the rocket when it runs out of fuel.
Let v is the final speed. Using the third equation of kinematics as :
\(v^2-u^2=2as\)
u = 0
\(v=\sqrt{2as} \\\\v=\sqrt{2\times 3.2\times 850}\\\\v=73.75\ m/s\)
So, the velocity of the rocket when it runs out of the fuel is 73.75 m/s
The throwing back by a wall or barrier of a sound wave without absorbing
it. *
1 point
Answer:Reflection
Explanation:
The throwing back of a sound wave without absorbing it is called reflection
In acoustic reflection of sound is termed as echo i.e. sound arrived at the listener after a particular delay depending upon the position of barrier to the observer.
The reflection of sound is used in many devices like megaphone, trumpets, etc. It is also used in auditorium such that the ceiling of the auditorium is curved for multiple reflections of sound so that sound can be reached at every corner of the auditorium.
How many significant digits are in34,000twofivethreefour
There are two significiant figures in 34000
The significiant figures are 3 and 4
A fishing boat uses an ultrasound of frequency 4.0×10²Hz to detect a fish blow it. two echo's of the ultrasound are received after 0.09s coming from the shoal of the fish and the other after 0.12s coming from the sea bed .if the sea bed is 64m below the ultrasound transmitter and the receiver, calculate; a. the speed of the ultrasound in water b. the wavelength of ultrasound in water. c. the depth of the fish below the boat.
a. the speed of the ultrasound in water is 1480 m/s
b. the wavelength of the ultrasound in water is 37 m
c. the depth of the fish below the boat is 89.76 m
How to calculate?a.
v = fλ
v = fλ = (4.0 x 10^2 Hz)(λ)
the speed of the ultrasound in water is given as :
v = v_water = 1480 m/s
substitute v_water into the equation above and solve for λ:
λ = v_water / f = (1480 m/s) / (4.0 x 10^2 Hz) = 37 m
Therefore, the speed of the ultrasound in water is 1480 m/s and the wavelength is 37 m.
c. The depth of the fish below the boat ia found using,
d = v_water * t / 2
The first echo came back after 0.09 s:
d = (1480 m/s) * (0.09 s) / 2 = 64.32 m
This is the depth of the sea bed, which is already known to be 64 m. So the fish must be deeper than the sea bed, and the second echo must have come from the fish. The second echo came back after 0.12 s:
d = (1480 m/s) * (0.12 s) / 2 = 89.76 m
So the depth of the fish below the boat is 89.76 m
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1. A material emits electrons when the electromagnetic radiation with a frequency equal to or less than the material's threshold frequency strikes the material.
True
False
2. In a particle model to show energy transfer, which of the following is correct?
a. Energy jumps are best described of electrons in packages known as photons
b. In energy transfers, electrons can absorb or emit energy
c. Photons carry energy from one location or object to another
d. All of the above are correct of particle models
1) The photoelectric effect is the phenomena by which, the metals release electrons when they are exposed to electromagnetic radiation with the suitable frequency. The photoelectrons are the electrons that are released in this process.
So, the statement is true.
2) In a particle model, energy transfer can be done through many ways such as:
The energy jumps between the particles in the form of photons.
Electrons can absorb or emit energy during energy transfer.
The energy is transferred between different objects in the form of photons.
So, all of them are true.
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1. Which of the following are quantitative observations? (Select all that apply) a) The sky is blue b) The toy car is about 3 inches long c) It is 250,000 miles from the earth to the moon. d) The wooden cart has a mass of 18.654 g. e) When at rest, the pendulum points toward the center of the earth.
Answer: las respuestas correctas son b, c y d.
indican cantidad
Answer the following:
1. Is sound a mechanical or electromagnetic wave?
2. Is sound a transverse or longitudinal wave?
3. What part of your ear receives the sound waves and turns them into electrical energy that
travels to your brain?
4.Label a compression region and a rarefaction region on the diagram below: I
5. If the speed of sound is constant, what happens to the wavelength when the frequency
increases?
6. Rank the following materials from fastest to slowest speed of sound traveling through it:
liquids, gases, solids.
Answer:
1. Mechanical wave
2. Longitudinal wave
3. The cochlea
4. The diagram is not attached so far
5. the wavelength decreases.
6. slowest through gases, faster through liquids, and fastest through solids. or simply solids>liquids>gases
Explanation:
Greetings!!
1. Waves in water and sound waves in air are two examples of mechanical waves. Mechanical waves are caused by a disturbance or vibration in matter, whether solid, gas, liquid, or plasma.
2. Sound is a longitudinal wave.
3. The cochlea is filled with a fluid that moves in response to the vibrations from the oval window. As the fluid moves, 25,000 nerve endings are set into motion. These nerve endings transform the vibrations into electrical impulses that then travel along the eighth cranial nerve (auditory nerve) to the brain.
4.
5. As the frequency increases, the wavelength decreases.
6. The Speed of Sound: Sound travels at different speeds depending on what it is traveling through. Of the three mediums (gas, liquid, and solid) sound waves travel the slowest through gases, faster through liquids, and fastest through solids.
Hope it helps!!!!
Minerals are naturally occurring inorganic solids that possesses an orderly internal structure and a definite chemical composition. This orderly internal structure or regular pattern is called its
A) hardness.
B) cleavage furrow.
C) specific gravity.
D) crystal structure.
Answer:
The answer is D) crystal structure.
Explanation:
A swimmer heading directly through a 200m wide river reaches the opposite shore in 6 min 40s. She is washed downstream 480 m. How fast can you swim in calm water?
Answer :v=480m400s=1.2ms
2002+4802=H2
The hypotenuse H=520m
A quicker way to get the length of the hypotenuse is to recognize that this is a simple 5–12–13 triangle where the sides are multiples of 5, 12, and 13:
5(40) = 200m, 12(40)= 480m, 13(40)= 520m
We know that the swimmer travelled 520 m in 400 seconds, so her average speed was:
VR=520m400sec= 1.3ms
hope i got it right!! xx
Explanation:
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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3. Two people push on a car with a force of 5150 N, and the car moves a distance of 8.0m. What is the
work done on the car?
A. 643.7J
B. 1.65 x 105 J
C. 5163 J
D. 4.12 x 104 J
bolo mot
The accepted measurement of the volume of a liquid
sample is 15.20 mL. If the student's measurement is
14.80 mL. What is the percentage of error?
A-(4.25%
B-(1.75%)
C-(3.50%)
D-(2.63 %)
Answer:
D-(2.63 %)
Explanation:
Percentage Error
Is the difference between the approximate and the exact or accepted value of a measurement, as a percentage of the exact or accepted value.
The formula is:
\(\displaystyle \delta=\left |\frac{va-ve}{ve} \right |\cdot 100\%\)
The accepted value of the volume of a liquid sample is va=15.20 ml and the student's measurement is ve=14.80 ml. The percentage of error is:
\(\displaystyle \delta=\left |\frac{15.20-14.80}{15.20}\right |\cdot 100\%\)
\(\displaystyle \delta=\left |\frac{0.4}{15.20}\right |\cdot 100\%\)
\(\delta=2.63\%\)
Correct choice: D-(2.63 %)
an airbubble at the bottom of a lake 90 m deep has a volume of 1.5 cm³. what will be the volume just below the surface if atmospheric pressure is equivalent to a height of 10m of water
The volume of the air bubble just below the surface of the lake would be 0.000015 m³ = 1.5 cm³.
How do we calculate?V₁ = 1.5 cm³
P₁ = ρg(10) = (1000 kg/m³ * 9.8 m/s² * 10 m)
To convert V₁ to m³:
Volume₁ = 1.5 cm³ * (1 m / 100 cm)³ = 0.000015 m³
we then substitute the values into the equation:
Volume ₂ = 0.000015 m³ * (P₂ / (1000 kg/m³ * 9.8 m/s² * 10 m))
Pressure ₂ = ρg(10) = (1000 kg/m³ * 9.8 m/s² * 10 m)
We then substitute the value of P₂ into the equation for Volume 2:
V₂ = 0.000015 m³ * ((1000 kg/m³ * 9.8 m/s² * 10 m) / (1000 kg/m³ * 9.8 m/s² * 10 m))
Volume₂ = 0.000015 m³
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Dominic has a brain injury. Why is this MOST likely to be a serious injury?
If Dominic has a brain injury, then he must have sustained a serious injury.
Functions of the brainThe brain coordinates all the activities in the body such as speech, locomotion, coordination and intelligence. This makes the brain the master point of control in the body.
Brain injuryWhenever there is an injury to the brain, various parts of the body could be affected. Functions such as speech, locomotion and general coordination may become largely impaired.
Therefore, if Dominic has a brain injury, then he must have sustained a serious injury.
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Um cubo fechado com 1 m3 de um líquido (d=0,8; =21 000 kgf/cm2
) é submetido a um aumento de pressão de
20107 N/m2
. Calcule, no Sistema Internacional, as seguintes grandezas:
a) massa final;
b) peso final;
c) volume final;
d) massa volúmica final;
e) peso volúmico final.
Answer:
a. massa final
Explanation:
eu escolhi isso porque essa é a resposta espero que ajude você pode me dar uma ideia?
Two carts of differing masses travel toward each other on a collision course as shown in the diagram below.
Free response answer A,B,C
Because of the inelastic nature of the contact, some of the kinetic energy was converted into heat or sound. As a result, it is impossible to calculate the system's kinetic energy following the collision.
What is the name of the collision where the two particles continue to move together after the collision?Colliding particles adhere to one another and continue to function together after a collision in a fully inelastic collision. Whenever time two items come into touch with one another, a collision happens. Elastic and inelastic collisions are the two different forms of collision.
This concept states that the overall momentum of a closed system remains constant both before and after a collision. We can state the following mathematically:
(mass of Cart 1) x (velocity of Cart 1 before collision) + (mass of Cart 2) x (velocity of Cart 2 before collision) = (mass of Cart 1) x (velocity of Cart 1 after collision) + (mass of Cart 2) x (velocity of Cart 2 after collision)
With the provided values substituted, we obtain:
(2 kg) x (2.5 m/s) + (1 kg) x (-1 m/s) = (2 kg) x (v) + (1 kg) x (2 m/s)
When we simplify this equation, we obtain:
5.5 kg m/s = 2 kg v + 1 kg (2 m/s)
5.5 kg m/s = 2 kg v + 2 kg m/s
2 kg v = 3.5 kg m/s
v = 1.75 m/s
As a result, Cart 1's velocity after the collision is 1.75 m/s to the left.
B) Using the following formula, we can determine the kinetic energy both before and after the collision:
kinetic energy = 0.5 x (mass) x (velocity)²
The system's kinetic energy is: before the impact.
KE(before) = 0.5 x (2 kg) x (2.5 m/s)²+ 0.5 x (1 kg) x (1 m/s)²
= 6.625 J
After the collision, the kinetic energy of the system is:
KE(after) = 0.5 x (2 kg) x (1.75 m/s)² + 0.5 x (1 kg) x (2 m/s)²
= 5.125 J
As KE(after) is lower than KE(before), some kinetic energy has been lost, proving that the collision was inelastic.
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Two loudspeakers, 3.5 m apart and facing each other, play identical sounds of the same frequency. You stand halfway between them, where there is a maximum of sound intensity. Moving from this point toward one of the speakers, you encounter a minimum of sound intensity when you have moved 0.15 m . Assume the speed of sound is 340 m/s .
a. What is the frequency of the sound?
b. If the frequency is then increased while you remain 0.15 m from the center, what is the first frequency for which that location will be a maximum of sound intensity?
For the given question the answer to the first part is that frequency of sound will be 404.76 Hz. and answer to the second part will be that the initial frequency for which that place will have the highest level of sound intensity
Given, the speed of sound 340 m/s
a) L1 + L2 = 3.5 m
and Ld = | L1 - L2 | = ( 1.75 + 0.21 ) - (1.75 - 0.21 ) = 1.96 - 1.54 = 0.42 m
Ld = λ/2
λ = 2Ld = 2×0.42 = 0.84 m
and finally,
f = v/λ
f = 340/0.84
f = 404.76 hertz
Frequency came out to be 404.76 hertz in this case
b) For the first frequency
0.42 = λ
f = v/λ
f = 340 / 0.42
f = 809.52 Hertz
Frequency came out to be 809.52 Hertz in this case.
To conclude with we can say that the Frequency of the sound in case on came out to be 404.76 hertz which is approximately 405 Hz after applying all the concepts and calculations, in second case first frequency for which that location will be a maximum of sound intensity came out to be 809.52 Hertz after applying all the concepts and calculations.
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