When weight is below 150 lbs. the servo motors wait 1 second then servo #1 moves fully to the left and after two seconds Servo #2 moves half-way to the left after 2 seconds it reset to original position.
When weight is above 150 lbs. and less than 4 lbs. the servo motors wait 1 second then servo #1 moves fully to the right and after two seconds Servo #2 moves half-way to the right after 2 seconds it reset to original position.When weight is above 4 lbs. the servo motors wait 1 second then servo #1 and Servo #2 do not move, and servo #3 moves fully to the right, after 2 seconds it reset to the original position.
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In the AC resistor circuit of Figure Q2.1, the voltage of the AC power source is
U = 100 sin(120pi x t) V .
what are
(a) the peak voltage of the AC power source
(b) the frequency of the alternating current in the circuit
(c) the instantaneous voltage of the power source at t = 20 ms
(d) the peak voltage across each resistor
(e) the instantaneous resistor voltages at t = 20 ms,
(f) to sketch the waveform of voltage in the first two periods
Answer:
(a) 100 V
(b) 60 Hz
(c) 95.106 V
(d) 25 V, 75 V
(e) 23.776 V, 71.329 V
(f) see attached
Explanation:
(a)The peak value of the sine function is 1, so the peak value of U is ...
100·1 = 100 V.
__
(b)The argument of the sine function is 2πft, so f = 120πt/(2πt) = 60 Hz.
__
(c)When t=0.020, the voltage is ...
U = 100sin(120π·0.020) = 100 sin(2.4π) ≈ 95.106 V
__
(d)The resistors are in the ratio of 1 : 3, so divide the source voltage in that ratio.
The peak voltage across the 5Ω resistor is 1/4 of 100 V, or 25 V.
The peak voltage across the 15Ω resistor is 3/4 of 100 V, or 75 V.
__
(e)The same fractions as in (d) apply to the instantaneous voltage.
The voltage on the 5Ω resistor is 1/4·95.106 V ≈ 23.776 V
The voltage on the 15Ω resistor is 3/4·95.106 V ≈ 71.329 V
__
(f)See attached.
. An ideal vapor compression refrigeration cycle operates with a condenser pressure of 900 kPa. The temperature at the inlet to the compressor is -5oC. If this device operates using R134a as the working fluid, calculate the actual COP of this device as well as the maximum theoretical COP.
Answer:
Actual COP = 5.368
Maximum theoretical COP = 6.368
Explanation:
Given - An ideal vapor compression refrigeration cycle operates with a condenser pressure of 900 kPa. The temperature at the inlet to the compressor is -5oC.
To find - If this device operates using R134a as the working fluid. Calculate the actual COP of this device as well as the maximum theoretical COP.
Proof -
Given that,
An ideal vapor compression refrigeration cycle operates with a condenser pressure of 900 kPa.
From Refrigerant 134-a Table
At T1 = -5°C
h1 = 247.505 KJ/kg
S1 = 0.93434 KJ/kg
At P2 = 900 KPa
S1 = S2
h2 = 274.679 Kj/Kg
h3 = h4 = 101.61 KJ/g
So,
Compressor work (Wc) = h2 - h1
= 274.679 - 247.505
= 27.174
⇒Compressor work (Wc) = 27.174 KJ/kg
Now,
Heat out (Qout) = h2 - h3
= 274.679 - 101.61
= 173.069
⇒Heat out (Qout) = 173.069 KJ/kg
Now,
Heat input (Qin) = h1 - h4
= 274.505 - 101.61
= 145.895
⇒Heat input (Qin) = 145.895 KJ/kg
So,
Actual COP at the refrigerator is -
(COP)R = (Qin)/(Wc)
= (145.895)/ (27.174)
= 5.368
⇒Actual COP = 5.368
Now,
Maximum theoretical COP is -
(COP) = (Qout)/(Wc)
= (173.069)/ (27.174)
= 6.368
⇒Maximum theoretical COP = 6.368
How does concurrent engineering speed up product development?
A. The product and process are designed using computer-aided design.
B. The product and process are designed in series.
C. The product and process are designed in separate spaces.
D. The product and process are designed simultaneously.
Answer:
The product and process are designed simultaneously
Explanation:
PENN
Feature Engineering
When would binning be an appropriate feature engineering step?
a. When we want to create defined groups from a continuous feature
b. When we want to transform categorical features into continuous features
c. When we want to remove low-quality features
d. When we want to create a new feature by combining existing ones
The appropriate feature engineering step for binning would be:
a. When we want to create defined groups from a continuous feature.
Binning is a useful technique in feature engineering when we want to convert a continuous feature into discrete or categorical groups. It involves dividing the range of values of a continuous feature into bins or intervals and assigning each value to a corresponding bin. This allows us to create defined groups or categories based on the values of the continuous feature.
Binning can be beneficial in various scenarios. For instance, it can help simplify complex data patterns, handle outliers or noise, and capture non-linear relationships between the feature and the target variable. Binning can also be used to address issues related to model complexity, data sparsity, or limited sample sizes.
By transforming a continuous feature into discrete groups, binning can enable models to capture patterns and make predictions based on the created categories. It allows for a more interpretable representation of the data and can improve the performance of certain machine learning algorithms, especially those that work better with categorical or ordinal data.
In summary, binning is an appropriate feature engineering step when we want to create defined groups or categories from a continuous feature. It can help simplify complex data patterns, handle outliers, and capture non-linear relationships, ultimately enhancing the modeling and prediction capabilities of machine learning algorithms.
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Consider the one time pad encryption scheme for binary strings of length 3. This is defined as follows: Gen: k< (0,1)3 Enc(k, m1 m2 m3): For i in 1 to 3: cm, k₁ = m, +k, mod 2 (where k, is the ith bit of k). Dec(k, C1C2C3): For i in 1 to 3: m₁ = c, k = c +k, mod 2 (where k, is the ith bit of k).
(a) For ciphertext = 101, list out all key / message pairs, (k, m), such that Enc(k, m) = c
(b) what is Pr [Enc(k,111)=101]?
K < {0,1}³
List of all key/message pairs, (k, m), such that Enc(k, m) = 101:Enc(k, m) = 101, k = 100
m = 001, k₁ = 1, k₂ = 0, k₃ = 0Enc(k, m) = 101, k = 011
m = 110, k₁ = 0, k₂ = 1, k₃ = 1
Enc(k, m) = 101, k = 111
m = 010, k₁ = 1, k₂ = 1, k₃ = 1(
What is Pr[Enc(k, 111) = 101]?Since k is chosen uniformly at random, and there are 8 possible keys, each key is chosen with probability 1/8. Now we'll find the number of keys k such that Enc(k, 111) = 101. For each of the three bits, there are two possible values. If we know the value of k at two positions, we can determine the value of k at the third position to get the desired ciphertext. As a result, there are 2² = 4 keys that have the desired property, namely, k = 011, 101, 110, or 000. Each of these keys is equally likely to be chosen, therefore, the probability is 4/8 or 1/2.Pr[Enc(k, 111) = 101] = 1/2
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The three main principles in engineering design are:
The three main principles in engineering design are: strategic balance, top management approach and team work.
What does principles in engineering design means?The principles are fundamental concepts that engineers use to develop effective solutions to complex problems. These principles are based on scientific and mathematical principles as well as practical considerations related to the materials, technologies and resources available to the engineer.
The engineering design process involves several stages, including problem identification, research, concept development, prototyping and testing. Throughout each stage, engineers apply various principles to ensure that their designs meet the needs and requirements of the intended users.
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What would be the most likely scale factor to use for an n-gauge model train setup? (An n-gauge layout uses locomotives that are typically about five centimeters long, on a train platform that may be one meter by one meter.)
A. 1:100
B. 1:500
C. 100:1
D. 500:1
Hi,
I'm paying for this monthly and I'm receiving this upgrade message.
I'm here if you need help with a math question
Selecting the range before you enter data saves time because it confines the movement of the active cell to the selected range (T/F).
Its True the range before you enter data saves time because it confines the movement of the active cell to the selected range .
What is data
Data is information that has been collected and organized in a meaningful way. Data can be quantitative (numbers) or qualitative (descriptive and subjective information). Data can come from surveys, experiments, observations and other sources. Data is a valuable asset and is used to inform decisions, create insights, and uncover trends and patterns. Data can be structured (structured in a way that makes it easy to search, sort, and analyze) or unstructured (not organized in a conventional way). Data can be used to identify problems, generate and test hypotheses, and measure the success of different strategies. Data is a key component of any organization and is used to help inform decisions, gain insights, and improve operations.
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). in a system with threads, is there one stack per thread or one stack per process when user-level threads are used? what about when kernel-level threads are used? please explain.
When user-level threads are utilized in a system with threads, there is normally one stack per thread. This is due to the fact that user-level threads lack direct kernel.
Support and are exclusively handled by the user-level thread library. The implementation of each thread creates a distinct execution environment with its own stack, program counter, and register set. Nonetheless, each thread has its own stack pointer inside the process-wide stack when kernel-level threads are employed, where there is normally one stack per process. This is so because kernel-level threads are directly supported and managed by the kernel of the operating system. Being a distinct kernel-level context with its own program counter, register set, and stack pointer, each thread is implemented.
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The top surface of an L = 5mmthick anodized aluminum plate is irradiated with G = 1000 W/m2 while being simultaneously exposed to convection conditions characterized by h = 50 W/m2 ⋅ K and T[infinity] = 25°C. The bottom surface of the plate is insulated. For a plate temperature of 400 K as well as α = 0.14 and ε = 0.76, determine the radiosity at the top plate surface, the net radiation heat flux at the top surface, and the rate at whic
Answer:
\(J=1963W/m^2\)
\(q_{rad}=963w/m^2\)
\(\triangle T= -0.378k/s\)
Explanation:
From the question we are told that:
\(L=5mm => 5*10^{-3}\\Irradiation G=1000W/m^2\\h=50W/m^2\\T_{infinity} = 25C.\\Plate\ temperature\ T_p= 400 K\\\alpha=0.14\\E=0.76\)
at Temp=400K
\(E=2702kg/m^2,c=949J/kgk\)
Generally the equation for Radiosity is mathematically given by
\(J=eG+\in E_p\)
\(J=(1-\alpha)G+\in \sigma T^4\)
\(J=(1-0.14)1000+0.76 (5.67*10^_{8}) (400)^4\)
\(J=1963W/m^2\)
Generally the equation for net radiation heat flux \(q_{rad}\) is mathematically given by
\(q_{rad}=J-G\\q_{rad}=1963-1000\)
\(q_{rad}=963w/m^2\)
Generally the equation for and the rate of plate temp \(\triangleT\) is mathematically given by
\(\triangle T= -\frac{q_{con} +q_{rad}}{Ecl}\)
\(\triangle T= \frac{45(400)-(30+273+963)}{(2702*949*0.005)}\)
\(\triangle T= -0.378k/s\)
what does mean setbacks with MRT station?
A face milling operation is being planned on a copper alloy (Cu 65-Zn 35) in the milling machine. The workpiece has dimensions as 12 inches in length, 4 inches in width. The cutter has dimensions as 2 inches in diameter and 4 cutting teeth. The milling operation on the copper alloy is recommended with cutting conditions of a cutting speed of 300 ft/min and a feed per tooth of 0.020 in/tooth/rev. It is also required that a width of cut or a radial depth of cut must be taken in each pass using a 75% of cutter diameter workpiece/cutter engagement. Calculate:a) the required spindle speed, N:b) the required feed rate, v: c) the required width of cut or radial depth of cut in each pass, w:d) the required total cutting time, t:
a) The required spindle speed (N) is approximately 573 RPM. b) The required feed rate (v) is approximately 45.84 in/min. c) The required width of the cut or radial depth of cut in each pass (w) is 1.5 inches. d) The required total cutting time (t) is approximately 0.2617 minutes or around 15.7 seconds.
a) To calculate the required spindle speed (N), we can use the following formula:
N = (12 × Cutting Speed) / (π × Cutter Diameter)
N = (12 × 300) / (π × 2)
N = 3600 / (6.2832)
N ≈ 573 RPM
b) To calculate the required feed rate (v), we can use the following formula:
v = Feed per Tooth × Number of Teeth * Spindle Speed
v = 0.020 × 4 × 573
v ≈ 45.84 in/min
c) To calculate the required width of the cut or radial depth of the cut in each pass (w), we can use the following formula:
w = 75% of Cutter Diameter
w = 0.75 × 2
w = 1.5 inches
d) To calculate the required total cutting time (t), we can use the following formula:
t = (Length of Workpiece) / (Feed Rate)
t = 12 / 45.84
t ≈ 0.2617 minutes, or approximately 15.7 seconds.
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what are advantages of using sinusoidal Voltages
Answer:
The advantages of using a pure sine wave for your appliances and machinery are as follows: Reduces electrical noise in your machinery.
translates to no TV lines and no sound system hum.
Cooking in microwaves is quicker.
Explanation:
The smoothest signal is a sine wave, and sine waves are the basis of all functions.
Every other continuous periodic function is a basis function, which means that it can be described in terms of sines and cosines.
For instance, using the Fourier series, I can describe the fundamental Sinusoidal frequency and its multiples in terms of the triangle and square waves.
What are baselines in geodetic control networks?
Baselines in geodetic control networks are a critical component of modern surveying and mapping. Baselines are defined as the straight-line distance between two points in a geodetic survey, which is used to create a reference system for all other measurements.
The baseline is then used to calculate distances and angles between other points, which can be used to create maps and survey data. Baselines are typically measured using a variety of methods, including satellite-based Global Positioning Systems (GPS), which provide highly accurate measurements. Geodetic control networks are used for a wide range of applications, including construction, mining, land management, and environmental studies.
By providing accurate, reliable data about the earth's surface, these networks are essential for effective management of natural resources and development projects. In summary, baselines in geodetic control networks are the fundamental building blocks that allow surveyors and mapping professionals to create accurate and reliable data about the earth's surface.
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Given the truss shown, with the dimensions and loads provided, find the force carried in members bc, bi, ij, de, dg, gh, and eg.
The two supports at A and D apply these reaction forces to the truss in order to maintain its stability.
What are a Truss' member troops consist of?
A truss is made up of several components that are typically joined together by pins. On the joint, there are loads or forces at work. This causes internal loadings, such as tensile or compressive force, on its members. One approach to figuring out these member forces uses the method of joints. This approach treats the joint as a location where forces are being applied to it. The system won't move unless the sum of forces acting along the x and y axes is equal to zero.
In a truss, how many forces are there?
Basic trusses are constructed from only two-force elements, with frictionless pins acting as the joints.
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Which of the following is the most common type of power in agriculture around the world?
Answer:
wheat and rice
Explanation:
because it is very common type of power in agriculture around the world
Sketch (and please upload a screenshot of your paper or digital board) a distance protection system with the following characteristics: -> (2.5) There are three buses in the system (G, H, R) and two transmission lines, one connecting G to H and another one connecting H to R. The relay to be configured is at bus G and it has a CT and a VT properly connected at the bus. Draw a mho-type characteristic zone 1 distance for GH at ~80% reach, and a zone 2 distance at 120% reach on the same R-X diagram. -> (2.5) Mark with a fault that would trip with enough delay the zone 2 but would not trip the zone 1. -> (2.5) Add a directional module and mark with a load value that generally would trip the zone 1 setting, but that after adding the directional module it will be marked as safe operation (will not trip).
The distance protection system in the power system consists of three buses (G, H, R) and two transmission lines.
What are the characteristics and configurations of the distance protection system in a power system with three buses (G, H, R) and two transmission lines?In the given distance protection system:
1. Three Buses: The system consists of three buses named G, H, and R.
2. Transmission Lines: There are two transmission lines. One line connects bus G to bus H, and the other line connects bus H to bus R.
3. Relay Configuration: The relay to be configured is located at bus G. It is equipped with a Current Transformer (CT) and a Voltage Transformer (VT) properly connected at the bus.
4. Mho-Type Characteristic Zones:
- Zone 1 for GH: Draw a mho-type characteristic zone 1 distance on the R-X diagram. This zone should have a reach of approximately 80% and is centered at the origin (0, 0).
- Zone 2 for GH: Draw a mho-type characteristic zone 2 distance on the same R-X diagram. This zone should have a reach of 120% and is centered at the origin (0, 0).
5. Fault Condition: Mark a fault on the R-X diagram that would cause a delay in tripping the zone 2 but would not trip the zone 1. This fault condition demonstrates a scenario where the fault is located closer to bus H, causing zone 1 to operate before zone 2.
6. Directional Module: Add a directional module to the relay. Mark a load value on the R-X diagram that would generally trip the zone 1 setting. However, after adding the directional module, this load value should be marked as safe operation, indicating that it will not trip the relay.
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help protect the lower legs and feet from heat hazards like molten metal and welding sparks
Answer:
i think its called leggings thats wut my shop teacher told me
Explanation:
what is the purpose of security education, training, and awareness (seta)?
The purpose of security education, training, and awareness (SETA) is to equip individuals with the knowledge and skills necessary to protect themselves and their organizations from security threats.
By providing education and training on topics such as cybersecurity, physical security, and emergency response, individuals can identify potential risks and take appropriate actions to mitigate them. SETA programs also raise awareness about the importance of security and instill a culture of vigilance within organizations. Ultimately, the goal of SETA is to create a safer and more secure environment for all individuals and organizations.
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binary classification algorithm
Answer:
What is this exactly?
Explanation:
If your asking for the definition, binary classification is the task of classifying the elements of a set into two groups on the basis of a classification rule.
What does the "exhaustion" in generalization concept of the entity type modeling mean? Write an explanation using the example COMPANY and their subtypes: HOTEL COMPANY, INSURANCE COMPANY.
Answer: In the generalization concept of the entity type modeling, exhaustion means that every entity must belong to at least one subtype. Exhaustion refers to the completeness of the subtype. It guarantees that all of the superclass entities are covered by subtypes.
In other words, it ensures that all instances of the superclass are covered by at least one subtype of the generalization. An example of how the exhaustion rule works in the company entity type modeling:
Consider the company entity, which can have two subtypes: Hotel Company and Insurance Company. There are no other subtypes. The exhaustion rule implies that every company must be either a Hotel Company or an Insurance Company or both. In this case, each company is identified as being one or both of the subtypes, ensuring that all companies are accounted for and that there are no company instances that are not part of the subtype. Therefore, in entity type modeling, exhaustion is an important feature that guarantees that no instance of the superclass is left out.
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Should you prefer rooftop solar panels?
The rooftop solar is a form of solar energy that can be installed on the roof of a home or business. It is cost-effective, environmentally friendly, and provides many benefits to homeowners and businesses.
The rooftop solar has many advantages over other forms of solar energy. One of the main advantages is that it provides 100% clean electricity from renewable sources. In addition, it can be combined with other sources such as wind power and geothermal power for even more benefits.
There are also many uses for rooftop solar panels in homes and businesses. One example is using it to heat water for hot water systems or heating swimming pools.
For me Bluebird Solar Private Limited is the best website in India for rooftop solar panels in India.
3. In Question 2, taking actual 2009 sales of $48,000 as the forecast for 2010, what sales would you forecast for 2011, 2012 and 2013 using exponential smoothing and a weigh α based on actual values of (a) 0.4; (b) 0.8?
Using α = 0.4, the forecasted sales for 2011, 2012, and 2013 would all be $48,000, which is the same as the actual sales in 2009.
Using α = 0.8, the forecasted sales for 2011, 2012, and 2013 would also be $48,000.
In both cases, the forecasts for 2011, 2012, and 2013 remain the same as the actual sales in 2009 due to the zero difference between the actual and forecasted sales values.
To forecast sales for 2011, 2012, and 2013 using exponential smoothing, we need to apply the formula:
Forecast for the next period = Previous period's forecast + α * (Actual value - Previous period's forecast)
Given that the actual 2009 sales are $48,000 and are considered the forecast for 2010, we can calculate the forecasts for subsequent years using different values of α.
(a) For α = 0.4:
- Forecast for 2011 = $48,000 + 0.4 * ($48,000 - $48,000) = $48,000
- Forecast for 2012 = $48,000 + 0.4 * ($48,000 - $48,000) = $48,000
- Forecast for 2013 = $48,000 + 0.4 * ($48,000 - $48,000) = $48,000
Using α = 0.4, the forecasted sales for 2011, 2012, and 2013 would all be $48,000, which is the same as the actual sales in 2009.
(b) For α = 0.8:
- Forecast for 2011 = $48,000 + 0.8 * ($48,000 - $48,000) = $48,000
- Forecast for 2012 = $48,000 + 0.8 * ($48,000 - $48,000) = $48,000
- Forecast for 2013 = $48,000 + 0.8 * ($48,000 - $48,000) = $48,000
Using α = 0.8, the forecasted sales for 2011, 2012, and 2013 would also be $48,000.
In both cases, the forecasts for 2011, 2012, and 2013 remain the same as the actual sales in 2009 due to the zero difference between the actual and forecasted sales values.
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Multiply. Write the answer in simplest form. 1 3/10×1/8
9514 1404 393
Answer:
13/80
Explanation:
The product is ...
(1 3/10)×(1/8) = (13/10)×(1/8) = (13×1)/(10×8) = 13/80
What braking system would be the most unsafe for a car going over 200mph?
Answer:
Deactivated Anti-Lock Braking System
Explanation:
Well this actually depends on the vehicles braking function
I'd say in this case not sure if ABS coz it prevents the vehicle from slipping while braking...
On the otherside ESP is inportant for it stability
Discuss any three determinants of demand for ocean transport as a mode of
transport.
(Note: One mark for the determinant and three marks for the explanation)
Price of transportation, availability of shipping routes, and seasonal demand are three determinants of demand for ocean transport.
The price of transportation: The price of transportation is one of the most important determinants of demand for ocean transport. If the price of shipping goods by sea is cheaper than other modes of transport such as air and road, then there will be a higher demand for ocean transport.Availability of shipping routes: The availability of shipping routes is another important determinant of demand for ocean transport. If there are more shipping routes available, then there will be a higher demand for ocean transport.Seasonal demand: Seasonal demand is another determinant of demand for ocean transport. If there is a high demand for goods during certain seasons, such as the holiday season, then there will be a higher demand for ocean transport during those periods.Overall, these three determinants play a vital role in determining the demand for ocean transport as a mode of transportation.
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A bolt and nut clamp 4 thin materials, of the geometry and tolerances shown. The bolt must always protrude from the bottom of the nut. Assuming all parts arrive where 93.3% (30) meet the tolerances shown, what is the minimum protrusion would you expect for the same share, 93.3% (30), of assembled parts? OA: -0.22 OB:- 40 O C: 0.64 OD: 0.85 O E: 1.15
Therefore, the minimum protrusion we would expect for 93.3% (30) of assembled parts is 2.65 mm.
To answer this question, we need to first understand what is meant by "protrusion". Protrusion refers to the amount of the bolt that extends beyond the bottom of the nut once the clamp is fully assembled.
Given that 93.3% (30) of the parts meet the tolerances shown, we can assume that there will be some variation in the assembled parts. In other words, not all assembled parts will be exactly the same.
To determine the minimum protrusion we would expect for this share of assembled parts, we need to consider the worst-case scenario, which is when all the tolerances stack up against us.
The tolerances shown in the diagram indicate that the thickness of the four materials can vary by up to ±0.1mm, and the height of the nut can vary by up to ±0.05mm. This means that the total height of the assembled parts can vary by up to ±0.4mm (4 x 0.1mm), and the height of the nut can vary by up to ±0.05mm.
To calculate the minimum protrusion, we need to consider the case where the nut is at its maximum height tolerance (+0.05mm), and the four materials are at their minimum thickness tolerance (-0.1mm each, for a total of -0.4mm). This would result in the total height of the assembled parts being -0.35mm (i.e., lower than the nominal height of the clamp).
To ensure that the bolt always protrudes from the bottom of the nut, we need to add the height of the nut to the total height of the assembled parts. In this worst-case scenario, the total height would be:
-0.35mm (total height of assembled parts) + 3mm (height of nut) = 2.65mm
Therefore, the minimum protrusion we would expect for 93.3% (30) of assembled parts is 2.65mm.
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true/false: unlike brittle materials, tough materials are less likely to fracture because the mechanical work done on the material is split between plastic deformations and crack propagation.
An unknown relative passes away and bequeaths upon you a small tract of land in Amherst. You decide to build a two-story storage facility to make the best of your bequest. But your self-storage dream is in jeopardy due to a 10 meter thick layer of soft clay (N<4) on the site. You put on your best geotechnical engineer hat, hire a driller to pull up some samples, and send them off to a lab for a consolidation test. The report indicates that the clay is a dark grey, slightly sweet, kaolinite blend with a cy = 1x10-7 mº/s, single-drained, and an ultimate settlement of 0.73 meters. It does not make financial sense to install deep foundations, so you are interested in how long it will take to consolidate the clay layer using a passive load.
How long will it take for settlements of 25, 50, and 65 cm to occur?
If you need to build within the next 12 months and have at least 65cm of settlement to be viable, does it make sense to proceed?
Answer: It does make sense, because I've been involved in these careers and have a long family line of them. And other questions?
Explanation: