When we react a weak acid with a strong base of equal amounts and concentration, the component of the reaction that will have the greatest effect on the pH of the solution is: Select the correct answer below:_________
a. the reactant acid
b. the reactant base
c. the conjugate acid of the strong base
d. the conjugate base of the weak acid

Answer:

56.96 grams

Explanation:

To find the mass of 1.78 moles of O2, we need to use the molar mass of O2, which is the mass of one mole of O2.

The chemical formula for O2 is O-O or simply O2. The molar mass of O2 is the sum of the atomic masses of two oxygen atoms, which can be found on the periodic table.

The atomic mass of oxygen (O) is approximately 16.00 g/mol. So the molar mass of O2 is:

Molar mass of O2 = 2 x atomic mass of O

= 2 x 16.00 g/mol

= 32.00 g/mol

Therefore, the mass of 1.78 moles of O2 is:

Mass = number of moles × molar mass

= 1.78 mol × 32.00 g/mol

= 56.96 g

So the mass of 1.78 moles of O2 is 56.96 grams.

A. The patch's area in square kilometers (km²) is 1.61×10⁻⁹ km²

B. The cost of the patch to the nearest cent is 734 cents

We can convert 16.1 cm² to km² as illustrated below:

Conversion scale

1 cm² = 1×10⁻¹⁰ km²

Therefore,

16.1 cm² = 16.1 × 1×10⁻¹⁰

16.1 cm² = 1.61×10⁻⁹ km²

Thus, 16.1 cm² is equivalent to 1.61×10⁻⁹ km²

We'll begin by converting 16.1 cm² to in². This can be obtained as illustrated below:

1 cm² = 0.155 in²

Therefore,

16.1 cm² = 16.1 × 0.155

16.1 cm² = 2.4955 in²

Finally, we shall the determine the cost in centas fo r llow:

1 in² = 294 cent

Therefore,

2.4955 in² = 2.4955 × 294

2.4955 in² = 734 cents

Thus, the cost of the patch is 734 cents

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The Microscope part and their right descriptions are as follows

Iris Diaphragm: A. Increases or decreases the light intensity

Objective Lens System: B. After light passes through the specimen, it next enters this lens system

Stage: C. Platform that supports a microscope slide

Adjustment Knob: D. Causes stage (or objective lens) to move upward or downward

Condenser: E. Concentrates light onto the specimen

Other parts of a microscope and their description that you should know about includes;

Eyepiece - The lens that you look through to see the image of the specimen.

Body tube - The tube that connects the eyepiece to the objective lenses.

Arm - The part of the microscope that supports the body tube and connects it to the base.

Base - The part of the microscope that supports the arm and provides stability.

Illuminator - The light source that provides light for the microscope.

Stage clips - The clips that hold the microscope slide in place on the stage.

Revolving nosepiece - The part of the microscope that holds the objective lenses and allows them to be rotated into place.

The above answer is in response to the full question below;

Match the names of the microscope parts in column A with the descriptions in column B. Place the letter of your choice in the space provided.

1. Iris diaphram

2. Objective lens system

3. Stage

4. Adjustment knob

5. Condenser

Increases or decreases the light intensity

2. After light passes through the specimen, it next enters this lens system

3. Platform that supports a microscope slide

4. Causes stage (or objective lens) to move upward or downward

5. Concentrates light onto the specimen

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The net ionic equation for the reaction of magnesium metal with aqueous iron(II) nitrate is as follows:

How to write net ionic equation?

Ionic equation is a chemical equation that show only ions that participate in a chemical reaction.

In other words, the ions that react together in solution and form new substances. The other ions that don't participate are called spectator ions.

According to this question, magnesium metal with aqueous iron(II) nitrate as follows:

2Mg(s) + 2Fe(NO₃)₂(aq) → 2Fe(s) + 2Mg(NO₃)₂(aq)

The net ionic equation for the reaction of magnesium metal with aqueous iron(II) nitrate is:

A net ionic equation is a chemical equation that shows only ions that participate in a chemical reaction. In other words, the ions react together in solution and form new substances.

The other ions that remain in the solution and do not form products are known as spectator ions.

The net ionic equation of the reaction of magnesium metal with aqueous iron(II) nitrate is given below as follows:

Molecular equation: 2 Mg (s) + 2 Fe (NO₃)₂(aq) → 2 Fe(s) + 2 Mg(NO₃)₂(aq)

Net ionic equation:  2 Fe²⁺ ---> 2 Fe(s)

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Answer:

6116g

Explanation:

2SO2(g) + O2(g) + 2H2O(ℓ) −→ 2H2SO4(ℓ)

We want to find the mass in grams of SO2 that is needed to react with 1527 g of O2. First we must convert the grams of O2 to moles of O2 then to moles of SO2 and then to grams of SO2

So first lets find the molar mass of O2

The mass of oxygen according to a periodic table is 15.999

Using this the mass of O2 would be 15.999(2) = 31.988g

Next we need to identify the mole ratio of O2 to SO2

Looking at the equation for 1 mole of O2 there are two moles of SO2

Next we need to find the molar mass of SO2

Again the mass of oxygen is 15.999g and the mass of Sulfur is 32.066

So the mass of SO2 would be 15.999(2) + 32.066 = 64.064g

Now that we have found all the needed conversions :

We can now use dimensional analysis to calculate the answer.

Kindly check the attached image to see the table. ( sorry if its a bit blurry )
Explanation : The conversions are used to cancel out the units to get to the final unit which is gSO2.

Once the units are cancelled out except for the gSO2 we mutliply and divide based off of what the table says to do.
Here first we divide 1527 by 31.988. We than multiply by 2. Finally we multiply by 64.064 to get the final answer which is 6116gSO2

Answer:

MgS is the formula and Magnesium sulfide is compound name

Explanation:

Answer:

MgS

Explanation:

Answer:

pH=10.88

Explanation:

Hello,

In this case, since potassium hydroxide is completely dissociated as shown below:

\(KOH\rightarrow K^++OH^-\)

For which we understand it is a base, more specifically, a strong base; it means that the concentration of the OH⁻ equals the concentration of the potassium hydroxide, that is 0.000765M, for that reason we can directly compute the pOH:

\(pOH=-log([OH^-])=-log(0.000765)=3.12\)

Finally, since the pOH and the pH are related by:

\(pOH+pH=14\)

The pH turns out:

\(pH=14-3.12\\pH=10.88\)

Best regards.

Answer:

1.06 °C

Explanation:

From the question given above, the following data were obtained:

Mass of gold (M₉) = 10 g

Specific heat capacity of gold (C₉) = 0.129 J/gºC

Initial temperature of gold (T₉) = 24 °C

Mass of water (Mᵥᵥ) = 118 g

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Initial temperature of water (Tᵥᵥ) = 1 °C

Equilibrium temperature (Tₑ) =?

The equilibrium temperature of the system can be obtained as follow:

Heat loss by the gold = heat gained by the water

M₉C₉(T₉ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Cᵥᵥ)

10 × 0.129 (24 – Tₑ) = 118 × 4.184 (Tₑ – 1)

1.29(24 – Tₑ) = 493.712 (Tₑ – 1)

Clear bracket

30.96 – 1.29Tₑ = 493.712Tₑ – 493.712

Collect like terms

30.96 + 493.712 = 493.712Tₑ + 1.29Tₑ

524.672 = 495.002Tₑ

Divide both side by 495.002

Tₑ = 524.672 / 495.002

Tₑ = 1.06 °C

Therefore, the temperature of the system is 1.06 °C

The amount of heat of the system is measured by a device called a calorimeter. The final temperature of the system will be 1.06 degrees celsius.

The equilibrium temperature is the temperature that follows the law of thermodynamics and is said to be the system that has alike temperatures.  

Given,

Mass of Ag \(\rm (M_{g})\) = 10g

Specific heat capacity of Ag \((\rm C_{g})\) = \(\rm 0.129 J/g^{\circ}C\)

The initial temperature of Ag \((\rm T_{g})\) = \(24 ^{\circ}\;\rm C\)

Mass of water \((\rm M_{w})\) = 118 g

Specific heat capacity of water \((\rm C_{w})\) = \(4.184 \rm \;J/g^{\circ}\;\rm C\)

The initial temperature of water \((\rm T_{w})\) = \(1 ^{\circ}\;\rm C\)

Equilibrium temperature = \((\rm T_{e})\)

The equilibrium temperature can be shown as, heat loss by the gold = heat gained by the water:

\(\rm \rm M_{g}C_{g}(T_{g} - T_{e}) = M_{w}C_{w}(T_{e}-C_{w})\)

Substituting values in the equation:

\(\begin{aligned} 10 \times 0.129 (24 - \rm T_{e}) &= 118 \times 4.184 (\rm T_{e} - 1)\\\\\rm 1.29(24 - T_{e}) &= 493.712 (\rm T_{e} - 1)\\\\524.672 &= 495.002 \;\rm T_{e}\end{aligned}\)

Now divide both the sides by 495.002:

\(\begin{aligned} \rm T_{e} &= \dfrac{524.672 }{495.002}\\\\\rm T_{e} &= 1.06 \;^{\circ}\rm C\end{aligned}\)

Therefore, the final temperature of the system is 1.06 degrees celsius.

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Answer:

1.43 moles N₂

Explanation:

To determine the moles of nitrogen gas (N₂), you need to multiply the given value by the molar mass. The molar mass is a ratio comparing the mass (g) of nitrogen gas per 1 mole. It is important to arrange this ratio in a way that allows for the cancellation of units (grams should be in the denominator). The final answer should have 3 sig figs to match the given value.

Molar Mass (N₂): 2(14.007 g/mol)

Molar Mass (N₂): 28.014 g/mol

 40.0 grams N₂                1 mole
-------------------------  x  ------------------------  =  1.43 moles N₂
                                    28.014 grams

Answer:

Explanation:

To determine the mass of NaCl in 1.25L of 0.1035M solution, we can use the formula:

mass = concentration x volume x molar mass

where concentration is in molarity (M), volume is in liters (L), and molar mass is in grams per mole (g/mol).

The molar mass of NaCl is 58.44 g/mol.

Plugging in the given values, we get:

mass = (0.1035 M) x (1.25 L) x (58.44 g/mol)

mass = 7.3188 g

So, there is approximately 7.3188 grams of NaCl in 1.25L of 0.1035M solution.

Answer:

1. Percentage yield = 57.2%

2. Percentage error = 74.9%

Explanation:

From the question given above, the following data were obtained:

Actual yield = 5.06 g

Experimental yield = 8.85 g

Percentage yield =?

Percentage error =?

1. Determination of the percentage yield.

Actual yield = 5.06 g

Experimental yield = 8.85 g

Percentage yield =?

Percentage yield = Actual yield /Experimental yield × 100

Percentage yield = 5.06 / 8.85 × 100

Percentage yield = 57.2%

2. Determination of the Percentage error.

Actual yield = 5.06 g

Experimental yield = 8.85 g

Percentage error =?

Percentage error = |Experimental – Actual| / Actual yield × 100

Percentage error = |8.85 – 5.06| / 5.06 × 100

Percentage error = 3.79 / 5.06 × 100

Percentage error = 74.9%

The most typical solution is a 0.25 molar (M) HCl solution, which has exactly 0.25 moles of HCl in it. Per litre of this solution, 0.25 moles of HCl are present. Calculating the mass of HCl required to produce one litre of 0.25 M HCl solution is the first step in making this solution.

The molar mass of HCl (36.46 g/mol) must be multiplied by 0.25 moles to get this. As a result, we get 9.115 grammes of HCl in total mass. This quantity of HCl needs to be dissolved in one litre of water in order to make the solution.

This will result in a solution of 0.25 M HCl, or exactly 0.25 moles of HCl. It's critical to understand that a solution's concentration It's crucial to understand that a solution's concentration and its solute content are two different things.

For instance, an HCl solution at 0.5 M does not contain twice as much HCl as one at 0.25 M. It has twice as much solute in the same amount of solution, though. As a result, 0.5 moles rather than 0.25 moles of HCl are present in a 0.5 M solution.

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By using inferential control, the difficult-to-measure controlled variables are approximated from certain simple process variables before being used in feedback control.

The two types of flow meters that are frequently used to measure the density rate of flow or velocity of a flowing fluid are the venturi meter and the orifice meter. They are also referred to as variable heading meters.

An element of a physical or chemical amount that is typically monitored and managed throughout the operation of a sewage, wastewater, or industry treatment facility. Process variables like flow, level, tension, temp, turbidity, chlorine, & oxygen concentrations are frequently used.

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Answer:

\(\color{Blue}\huge\boxed{Answer} \)

B.the electrons become delocalized and form a "sea"

No, a molecule with a \(C_2\)axis perpendicular to the \(C_n\)axis does not necessarily have a mirror plane perpendicular to the \(C_n\)axis.

The presence of a \(C_2\)axis perpendicular to the \(C_n\)axis implies that the molecule possesses rotational symmetry around the \(C_n\)axis. However, the presence of a mirror plane is determined by the presence of an additional symmetry element in the molecule.

A mirror plane is a symmetry element that divides the molecule into two halves, with one half being the mirror image of the other. In order for a mirror plane to be present perpendicular to the \(C_n\)axis, there needs to be an additional symmetry element that produces the reflection symmetry.

While a molecule with a \(C_2\) axis perpendicular to the \(C_n\)axis has rotational symmetry, it does not necessarily possess reflection symmetry. For example, consider a molecule with a \(C_2\)axis perpendicular to a \(C_3\)axis.

The rotational symmetry is evident, as the molecule can be rotated by 120 degrees around the \(C_3\) axis and still appear the same. However, this molecule does not possess a mirror plane perpendicular to the \(C_3\)axis.

The presence of a mirror plane perpendicular to the \(C_n\)axis depends on the specific molecular geometry and arrangement of atoms. It is possible for a molecule to possess both rotational symmetry and a mirror plane perpendicular to the \(C_n\)axis, but it is not a general rule.

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Answer:

A

Explanation:

Arsenic is in the same group as Nitrogen - group 5. They all have 5 valence electrons in their outermost shell. To achieve its most stable state - 8 valence electrons (octet rule - elements are most stable when the entire shell is filled) - arsenic needs to gain 3 electrons. Since electrons have a negative charge, the charge of an As ion would be -3.

Try observing the periodic table and how many valence electrons that each element has. From there, you can determine the charges of the elements lithium and strontium. You can guess, I'll help you with those once you attempt to find the charge of those ions.

You would recover 36.525g of NaCl after evaporating all of the water.

To find the grams of NaCl that would be recovered after evaporating all the water, we can use the following formula:

mass = moles * molar mass

Where:

Moles = Molarity * Volume

Molarity = 0.250 M

Volume = 2500.0 mL = 2.5 L

Molar mass of NaCl = 58.44 g/mol

mass = 0.250 M * 2.5 L * 58.44 g/mol

mass = 36.525 g

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The specific heat capacity of the zinc metal, given that 2.40×10¹ g of zinc metal at 2.10×10¹ °C is added to the water is 0.27 J/gºC

First, we shall obtain the heat absorbed by the water when the zinc metal was added. This is shown below:

Q = MCΔT

= 5.60×10¹ × 4.184 × -2.1

= -492.0384 J

Now, we shall determine the specific heat capacity of the zinc metal. Details below:

Q = MCΔT

492.0384 = 2.40×10¹ × C × 76

492.0384 = 1824 × C

Divide both sides by 1824

C = 492.0384 / 1824

= 0.27 J/gºC

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Answer:

Its 15.1

Explanation:

Answer:

15.1

Explanation:

Balance Equation: Na2CO3 + Ca(OH)2 = 2NaOH + CaCO3

Stoichiometry:

20gNa2CO3/1 x 1mNa2CO3/105.985gNa2CO3 x 2mNAOH/1mNA2CO3 x 39.996gNaOH/1mNaOH = 15.1 grams of NaOH

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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There are approximately 0.16 moles of gas present in the lungs.

To solve this problem, we can use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas:

PV = nRT

where R is the gas constant.

First, we need to convert the temperature to Kelvin:

T = 37°C + 273.15 = 310.15 K

Next, we can plug in the given values:

P = 1.0 atm

V = 4.0 L

T = 310.15 K

We also need to find the value of R, which depends on the units we are using for pressure, volume, and temperature. In this case, we are using atmospheres, liters, and Kelvin, so we can use the value:

R = 0.08206 L·atm/K·mol

Now we can rearrange the ideal gas law to solve for the number of moles:

n = PV/RT

n = (1.0 atm)(4.0 L)/(0.08206 L·atm/K·mol)(310.15 K)

n = 0.1638 mol

Therefore, there are approximately 0.16 moles of gas present in the lungs.

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Answer:we need the pic bro

Explanation:

Positive aspect of fossil fuels is They provide energy for cars, trains and heat.

1) They can be recycled and reused . this point is wrong because fossil fuels are non renewable resources and are in limits in supply . so, fossil fuels cannot be recycled.

2) They provide energy for cars, trains, and heat. This is statement is true.

3) They are ecologically friendly. this statement is wrong. The fossil fuels are not eco-friendly . they produce the pollution to the environment and severely damage our environment.

4) They do not need processing to produce energy.  they need geological process of millions years.

Thus, Positive aspect of fossil fuels is They provide energy for cars, trains and heat.

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Glucose is a carbohydrate and monosaccharide sugar molecule that is the energy source for organisms. The simplified model of a glucose molecule will show six carbon atoms, six oxygen atoms, and twelve hydrogen atoms.

Glucose is one of the monosaccharide sugar that is the most abundant energy source with a molecular formula of C₆H₁₂O₆. It consists of carbon, hydrogen, and oxygen atoms with a molecular mass of 180.156 g/mol.

It is a sugar-containing aldehydic group with a six-carbon making it aldohexoses. It is found in honey and fruits that are the source of the energy and regulates metabolic and cellular reactions.

Therefore, the molecular structure of glucose contains six carbon, twelve hydrogens, and six oxygen atoms.

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Answer:

a liquid

Explanation:

Answer: the answer is A

Explanation:

just finished this on acellus

Acetone is the name of the following compound and can also be referred to as 2-propanone.

ketone, any of a class of organic compounds characterized by the presence of a carbonyl group in which the carbon atom is covalently bonded to an oxygen atom.

Acetone, an organic compound, is chemically described as \(CH_3COCH_3\), and can also be referred to as 2-propanone.

Acetone is a hydrocarbon derivative, more specifically a ketone in its simplest form because of its particular functional group.

Hence, acetone is the name of the following compound and can also be referred to as 2-propanone.

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Answer:

Empirical formula of a compound means that it provides simplest ratio of whole number.

Explanation:

Mass of boron and chlorine is 9.224% and 90.74%

The percent difference between the first two trials is 8.3% and final outcome would be an average molarity of 0.108 M.

To calculate the percent difference between the first two trials, use the formula:

% Difference = |(Value 1 - Value 2) / ((Value 1 + Value 2) / 2)| x 100%

% Difference = |(0.104 M - 0.113 M) / ((0.104 M + 0.113 M) / 2)| x 100%

% Difference = |-0.009 M / 0.1085 M| x 100%

% Difference = 8.3%

The percent difference between the first two trials is 8.3%.

To find the average molarity, add the three calculated concentrations together and divide by the number of trials:

Average Molarity = (0.104 M + 0.113 M + 0.108 M) / 3

Average Molarity = 0.108 M

Based on the lab procedures guidelines, the average molarity would be the most accurate representation of the unknown concentration of HCI. Therefore, the average molarity of 0.108 M would be the final result.

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56.5

Explanation:

the degradation would be 28.25 times 2

The reduction half-reactions for O, P, and Cu:

• O: O2 + 4 e- → 2 O2-

• P: HPO42- + 2 H+ + 2 e- → H3PO4

• Cu: Cu2+ + 2 e- → Cu+

To write the reduction half-reactions for O, P, and Cu, we need to determine the oxidation numbers for each element. The guidelines for assigning oxidation numbers are:

Using these guidelines, we can determine the oxidation numbers for O, P, and Cu:

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