When phosphate is added to adp to form the energy-storing molecule atp, this is known as ________ and, since water is also produced, this reaction is also considered a ________ reaction.

0.01 M NaCl solution will have the highest freezing point

Freezing point will be given by the formula:

ΔT(f) = iK(f).m

where, m = molality

Sucrose is non-electrolyte and so i = 1

NaCl → Na+ + Cl−

Thus i = 2

Na2SO4 → 2Na+ + SO4^2−

Thus i = 3

The highest freezing point will be of the solution having the lowest ΔT(f) value.

As option B has least value of both i and m, 0.01M NaCl has lowest

ΔT(f) = K(f) × (0.02)

Therefore, 0.01 M NaCl solution will have the highest freezing point.

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Answer:

0.01 M NaCl is the answer

Answer: 90 degrees.

Explanation:

To find the empirical formula from a molecular formula, you should divide the Subscripts by the Some integer in order to get the smallest whole number.

Part-A

The empirical formula of \(Al_{2}Br_{6}\)is \(AlBr_{3}\), we get it by dividing both subscript (i.e. 2&6) by 2.

Part-B

The empirical formula of C8H10 is

Simplest ratio of CH = 8:10 = 4:5

Hence, empirical formula =C4H5

Part-C

The empirical formula of C4H8O2 is C2H4O, we get it by diving all subscripts \(\frac{4}{2} : \frac{8}{2} :\frac{2}{2}=2:4:1\) by 2.

Part- D

molecular formula= P4O10

simplest ratio of

\(\frac{P}{O}= \frac{2}{5} \\ empirical formula = p_{2}O_{5}\)

Part -E

The empirical formula of C6H9CL2 is C3H2CL,we get it by diving all subscripts\(\frac{6}{2}:\frac{4}{2}:\frac{2}{1} =3:2:1\) by 2

Part-F

The empirical formula of B3N3H6is BNH2, we get it by diving all subscripts \(\frac{3}{3} :\frac{3}{3} :\frac{6}{3} = 1:2:3\) by 2.

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Answer:

24 mol Cu

General Formulas and Concepts:

Chemistry

Explanation:

Step 1: Define

RxN: 2Cu (s) + O₂ (g) → 2CuO (s)

Given: 12 moles O₂

Step 2: Stoichiometry

\(12 \ mol \ O_2(\frac{2 \ mol \ Cu}{1 \ mol \ O_2} )\) = 24 mol Cu

Step 3: Check

We are given 2 sig figs.

Our final answer is in 2 sig figs, so no need to round.

The heat of the reaction is 90.83 kJ/mol.

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.

It is a measure of how much energy it takes to raise the temperature of a substance. It is the amount of heat necessary to raise one mass unit of that substance by one temperature unit.

It is given by the formula -

                                                  Q = mcΔT

where, Q = amount of heat

m = mass

c = specific heat

ΔT = Change in temperature

Heat of formation is the opposite of heat of reaction.

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(a) The percent recovery of methane in the retentate stream is 90.1%.

(b) The actual area of the membrane is 33,295 ft², which is the correct value.

(c) The permeance of CH₄ is not provided in the given information. The selectivity of the membrane (a₁₂) is 19.3.

(a) The percent recovery of methane can be calculated using the formula:

% Recovery = (Flow rate of methane in retentate / Flow rate of methane in feed) * 100

The flow rate of methane in the retentate can be calculated by multiplying the flow rate of the feed (20 MSCFD) by the percentage of methane in the retentate (93%) and subtracting the flow rate of methane in the permeate (which is negligible in this case):

Flow rate of methane in retentate = 20 MSCFD * 93% - negligible

Similarly, the flow rate of methane in the feed can be calculated by multiplying the flow rate of the feed (20 MSCFD) by the percentage of methane in the feed (93%):

Flow rate of methane in feed = 20 MSCFD * 93%

Finally, using the formula above, we can calculate the percent recovery of methane.

(b) The area of the membrane can be calculated using two approximations: linear driving force (LDF) and log-mean driving force (LMDF). However, in this case, the actual area of the membrane is given as 33,295 ft². Therefore, the calculated area using these approximations is not required.

(c) The permeance of CH₄ can be calculated using the formula:

Permeance of CH₄ = Permeance of CO₂ / Selectivity (a₁₂)

However, the permeance of CO₂ is provided as 5.5 x 10⁻² ft³(STP)/(ft²·hr·psi), but the permeance of CH₄ is not given. The selectivity of the membrane (a₁₂) is provided as 19.3.

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Answer:

sunlight

Explanation:

it is the sunlight

Outgoing shortwave radiation depends on factors such as the angle of the Sun's rays, albedo, cloud cover, and atmospheric gases. These factors collectively determine the amount of solar radiation that is reflected, absorbed, and re-emitted by the Earth's surface, influencing the outgoing shortwave radiation.

Outgoing shortwave radiation depends on several factors. Firstly, it is influenced by the solar radiation received by the Earth's surface. The amount of solar radiation reaching the Earth is determined by the angle of the Sun's rays, which changes throughout the day and across different seasons. This means that outgoing shortwave radiation will vary depending on the time of day and the time of year.

Another important factor is the albedo, which refers to the reflectivity of different surfaces on Earth. Surfaces with high albedo, such as ice and snow, reflect more solar radiation back into space, resulting in lower outgoing shortwave radiation. Conversely, surfaces with low albedo, such as dark soil and vegetation, absorb more solar radiation, leading to higher outgoing shortwave radiation.

The presence of clouds also plays a role in outgoing shortwave radiation. Clouds can either reflect incoming solar radiation back into space or absorb and re-emit it as longwave radiation. The type and thickness of clouds, as well as their altitude, can affect the amount of outgoing shortwave radiation.

Finally, atmospheric gases such as water vapor, carbon dioxide, and ozone can also influence outgoing shortwave radiation. These gases absorb and re-emit some of the incoming solar radiation, impacting the amount of radiation that escapes back into space.

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In the titration of a weak monoprotic acid with a strong base, the pH of the titration solution halfway to the endpoint will be:

C. greater than the pKa of the weak acid.

During the titration of a weak acid with a strong base, the pH of the solution changes as the titrant is added. At the halfway point to the endpoint, the moles of strong base added are approximately equal to half the moles needed to reach the equivalence point.

Since the weak acid is partially neutralized, the concentration of its conjugate base increases, making the solution more basic. As a result, the pH at the midpoint of the titration will be greater than the pKa of the weak acid.

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Answer:

nu

Explanation:

It has five naturally occurring stable isotopes. The most common stable isotope of zinc is Zn-64. Zn-64 has such a long half-life that it radioactive properties are virtually non-existant. ... Zinc is a hard metal, but becomes very malleable above 100 degrees Celsius.

Answer:

Examine the units: If the density is 1 g/mL, how many mL do you need to make 250 g?

X mL * 1 g/mL = 250 g

Solve for X

x mL = 250 g / 1 g/mL = 250 mL

Hope this helps :)

The volume of water = 250 L

\(density = \frac{mass}{volume}\)

Given, density = 1.0 g/L = 0.001 kg/L

           mass = 250 g = 0.25 kg

Putting the values in the equation

\(0.001 = \frac{0.25}{volume}\)

\(volume = \frac{0.25}{0.001}\)

\(volume = 250 L\)

Hence, the volume of the water is 250 L.

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During the reaction given above, electrons are transferred from Cu(s) to Ag+ (aq) (option 1).

An ionic equation is a chemical equation in which the dissolved ionic compounds are written as separated ions.

According to this question, a balanced ionic equation is given as follows: Cu(s) + 2Ag+ (aq) → Cu²+ (aq) + 2Ag(s)

Based on the above equation, electrons are transferred from solid copper to silver ion, making copper the reducing agent while silver ion is the oxidizing agent.

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Answer:

where is the question?

The molecular formula of diazomethane is CH₂N₂, and the main reason for its instability is precisely the fact that it can very easily evolve nitrogen, as nitrogen's triple bond is one of the strongest covalent bonds in nature, and the energy released in its formation is more than enough to compensate the energy lost in the breaking of C-N bonds. The Lewis structure of diazomethane with the formal charges is attached below.

To obtain the molecular formula of diazomethane, we can imagine that we have 100 g of it. Now we can calculate the number of moles (n) for each of the elements, using their respective masses (m) and molar masses (M = 12 g/mol for carbon, 1 g/mol for hydrogen, and 14 g/mol for nitrogen):

n = m/M

n(C) = 28.57 g / 12 g/mol

n(C) = 2.38 mol

n(H) = 4.80 g / 1 g/mol

n(H) = 4.80 mol

n(N) = 66.64 g / 14 g/mol

n(N) = 4.76 mol

We now divide each of these numbers with the smallest of them (2.38) to calculate the molar ratio of the elements:

carbon: 2.38 / 2.38 = 1

hydrogen: 4.80 / 2.38 = 2

nitrogen: 4.76 / 2.38 = 2

Now we use these numbers to get the empirical formula of diazomethane: CH₂N₂.

The molar mass of the empirical formula is:

12 g/mol + 2 * 1 g/mol + 2 * 14 g/mol = 42 g/mol

Since this value is equal to the molar mass given to us, that means that CH₂N₂ is also the molecular formula of diazomethane.

The potential energy involved in intermolecular forces is intermolecular potential energy.

Intermolecular potential energy is the energy possessed by the random motion of molecules. The molecules in every matter exert forces on each other. It involves the forces between molecules. Intermolecular potential energy depends on the magnitude of the intermolecular forces and the position the molecules have relative to each other at any time.

According to postulates of kinetic theory, molecules move randomly and exert forces on each other. Also, there are present molecular attractions and repulsions among them. Molecules are dislocated at every instant of time. Hence as they have any internal forces exerting on each other it means it is a kind of potential energy generated by their randomness.

Therefore intermolecular potential energy is developed by molecules by virtue of their relative change in position.

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The acid that is the best choice for preparing a pH = 2.00 buffer is HC2H3O2.

Let's understand this in detail:

A buffer is a chemical solution that can resist changes in pH when an acid or base is added. A pH buffer is a solution containing a weak acid and its conjugate base or a weak base and its conjugate acid.

A pH is a scale that measures the acidity or basicity of a solution. On a scale of 1 to 14, the pH range is from acid to base. Acidic solutions have a pH of less than 7, neutral solutions have a pH of 7, and basic solutions have a pH of more than 7.

An acid is a chemical that has a sour taste and reacts with a base or metal to form salt and water. The acid that is the best choice for preparing a pH = 2.00 buffer is HC2H3O2. This is because the dissociation constant Ka of HC2H3O2 is low, and pH value of 4.76. This means that its pKa value is 4.76. Hence, at pH 2, HC2H3O2 will behave as a weak acid, and its conjugate base will be its conjugate base, C2H3O2–.

The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([A–]/[HA])

where pKa is the dissociation constant, and [A–] and [HA] are the conjugate base and acid concentrations, respectively.

The example of always having rice available at every meal, passed down through generations, is an example of food selection based on cultural tradition and historical practices.

Food selection is influenced by various factors, including cultural traditions, historical practices, availability, and personal preferences. In this case, the consistent presence of rice in every meal within the family is an indication of food selection based on cultural tradition and historical practices. Rice has likely been a staple food in the family's culture for generations, and its inclusion in meals reflects the cultural significance and importance placed on rice as a dietary component.

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a)The concentration of NaOH in g/dm³ is approximately 18.18 g/dm³, and b)The concentration in mol/dm³ is approximately 0.4545 mol/dm³.

a)To calculate the concentration of NaOH in g/dm³ (grams per cubic decimeter) and mol/dm³ (moles per cubic decimeter), we need to know the amount of NaOH used in the reaction and the volume of the NaOH solution.

From the given information, we have:

Volume of NaOH solution = 27.5 cm³

Volume of HCl solution = 25.0 cm³

Molarity of HCl solution = 0.5 M

Since the reaction between NaOH and HCl is a 1:1 stoichiometric ratio, the moles of NaOH used can be determined from the moles of HCl used:

Moles of HCl = Molarity × Volume = 0.5 M × 25.0 cm³ = 12.5 mmol (millimoles)

Since the moles of NaOH used is also equal to the moles of HCl, we have:

Moles of NaOH = 12.5 mmol

b)To calculate the concentration of NaOH in g/dm³, we need to convert moles to grams using the molar mass of NaOH, which is approximately 40 g/mol:

Mass of NaOH = Moles × Molar mass = 12.5 mmol × 40 g/mol = 500 g

Now, we can calculate the concentration in g/dm³:

Concentration of NaOH (g/dm³) = Mass of NaOH / Volume of NaOH solution

= 500 g / 27.5 cm³

≈ 18.18 g/dm³

To calculate the concentration of NaOH in mol/dm³, we can use the same approach:

Concentration of NaOH (mol/dm³) = Moles of NaOH / Volume of NaOH solution

= 12.5 mmol / 27.5 cm³

≈ 0.4545 mol/dm³

Therefore, the concentration of NaOH in g/dm³ is approximately 18.18 g/dm³, and the concentration in mol/dm³ is approximately 0.4545 mol/dm³.

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Explanation:

I know only one.You are in form.....

Answer:

How do electrons enter the electron transport chain?

All of the electrons that enter the transport chain come from NADH and FADH 2​start subscript, 2, end subscript molecules produced during earlier stages of cellular respiration: glycolysis, pyruvate oxidation, and the citric acid cycle.

Explanation:

i hope it helped u :)

After 14.4 seconds, 12.5g of a 50g nitrogen sample are still present.

Half-life is the length of time that it takes for half of an unstable nucleus to go through its decay. The half-life of each chemical varies. Because carbon-10's half-life is so short (19 seconds), it is not possible to find this isotope in nature.

The Foundational Elements. A half-life is the duration needed for something to reduce in quantity by half. The phrase is most frequently used in reference to radioactive decay, which takes place when unstable atomic particles shed energy.

\(N(t) = N_0 (1/2)^(t/t_1/2})\)

N(t) = quantity of the substance remaining

N₀ = initial quantity of the substance

t = time elapsed

t1/2 = half life of the substance

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Answer:

the answer is b because the solid dissolved

Explanation:

There are 3 significant figures in 20600.

Answer:

I think its b, but ik not completely sure.

Answer:

I think the second one...

Answer:

The answer you're looking for is A

Explanation:

A is the answer

Explanation:

The aqueous solution of 1.25 M \(C_6H_{12}O_6\) should have the highest boiling point among the given options.

In this case, we need to compare the molality of solute particles in the given aqueous solutions to determine which one should have the highest boiling point.

Let's analyze the options:

0.50 M \(Ca(NO_3)_2\): Calcium nitrate Ca(NO_3)_2 dissociates into three ions in solution (\(Ca^{2+}\) and two \(NO^{3-}\)), resulting in a total of three solute particles.

0.75 M NaCl: Sodium chloride (NaCl) dissociates into two ions in solution (Na+ and Cl-), resulting in a total of two solute particles.

0.75 M \(K_2SO_4\): Potassium sulfate dissociates into three ions in solution (two K+ and one \(SO_4^{2-}\)), resulting in a total of three solute particles.

1.00 M LiBr: Lithium bromide (LiBr) dissociates into two ions in solution (Li+ and Br-), resulting in a total of two solute particles.

1.25 M \(C_6H_{12}O_6\): Glucose (\(C_6H_{12}O_6\)) does not dissociate into ions in solution and remains as individual molecules.

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The oxidation number of chromium is +6. In the reaction, it is reduced, meaning its oxidation number decreases. The final oxidation number of chromium is +3.

In the reaction represented by the Cr₂O₇²⁻ ion, the element chromium (Cr) is reduced. Its oxidation number changes from +6 to +3.

In the Cr₂O₇²⁻  ion, each oxygen (O) atom has an oxidation number of -2. The overall charge of the ion is 2-, which means the total oxidation numbers of all the atoms should add up to -2. Since there are seven oxygen atoms, their total oxidation number is (-2) × 7 = -14.

To determine the oxidation number of chromium (Cr), we can set up the following equation;

2(Cr) + 7(-2) = -2

Simplifying the equation, we have;

2Cr - 14 = -2

By solving for Cr, we get;

2Cr = 12

Cr = 6

Initially, the oxidation number of chromium is +6. In the reaction, it is reduced, meaning its oxidation number decreases. The final oxidation number of chromium is +3.

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The curve represents saturation. Below the curve, the water is unsaturated. Above the curve, water is supersaturated. This means that more solute is present than the water can contain.

The line of the solubility curve indicates that the solution is saturated. A saturated solution is defined as a solution in which 100 g of solute is dissolved in 100 g of water. Simulations below this line indicate unsaturated solutions.

The difference between unsaturated and saturated solutes can be determined by adding very small amounts of solute to the solution. In unsaturated solutes, solutes will dissolve, and solutes in saturated solutes will not dissolve. In saturated solutes, crystals will form very quickly around the added solute.

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