When completing the sum 5.8×3.87 Dominica forgot to put the decimal point in her answer. She wrote 22446. What should she have written?

Answer:

Point Form:

( − 46 /3 , − 44 /3 )

Equation Form:

x = − 46 /3 ,  y = − 44 /3

Step-by-step explanation:

Combine  1 /2 and  x .

y = x /2 − 7

2 x − y = − 16

Replace all occurrences of  y  in  2 x − y = − 16  with  x /2 − 7 .

y = x /2 − 7

2 x − ( x /2 − 7 ) = − 16

 Simplify  

2 x − ( x /2 − 7 ) .

y = x /2 − 7

3 x /2 + 7 = − 16

Solve for  

x

in the second equation.

y = x /2 - 7

x = − 46 /3

Replace all occurrences of  x  in  y = x /2 − 7 with  − 46 /3 .

y = − 46 /3 /2 − 7

x = − 46 /3

Simplify  − 46 /3 /2 − 7 .

y = − 44 /3

x = − 46 /3

The solution to the system of equations can be represented as a point.

( − 46 /3 , − 44 /3 )

The result can be shown in multiple forms.

Point Form:

( − 46 /3 , − 44 /3 )

Equation Form:

x = − 46 /3 ,  y = − 44 /3

Answer:

Step-by-step explanation:

6x-5x+7x=34

x+7x=34

8x=34

x=\(\frac{34}{8}\)

Answer:

X= 5 2/3

Step-by-step explanation:

Combine Like terms

6x=34

Inverse Operation

x=35/6

Simplify

X=5 2/3

Answer:

63/9000 = 0.007 = %0.7

Step-by-step explanation:

,&,;=;#,÷,÷

The given array is 10 2 66 71 12 34 8 52. Selection sort is a simple algorithm that is used to sort an array in ascending or descending order.

Selection sort is performed by selecting the smallest (or largest) element from the unsorted subarray and placing it at the beginning of the array. Then, repeat this process until the entire array is sorted. Here's how to use selection sort to sort the given array in ascending order:                                                                                                                                       Step 1: Initialize the minimum value as the first element of the array.                                                                                                    Step 2: Compare this value with all of the other values in the array. If any value is less than the minimum value, assign that value to the minimum value.                                                                                                                                                              Step 3: Swap the minimum value with the first element of the unsorted subarray.                                                                                      Step 4: Repeat steps 1-3 for the remainder of the array until the entire array is sorted.                                                                            The sorted array is 2 8 10 12 34 52 66 71.                                                                                                                                                    The selection sort algorithm is a simple, easy-to-understand algorithm that sorts an array in ascending or descending order. This algorithm works by repeatedly selecting the smallest (or largest) element from the unsorted subarray and placing it at the beginning of the array. Then, the algorithm moves on to the next element of the unsorted subarray and repeats the process. This process is repeated until the entire array is sorted. One of the benefits of the selection sort algorithm is that it is easy to understand and implement. However, it is not very efficient, particularly for large arrays. This is because the algorithm has to scan the entire unsorted subarray for every element in the sorted subarray. As a result, the algorithm has a time complexity of O(n^2). Selection sort is not the best choice for sorting large arrays, but it can be useful for sorting small arrays or for educational purposes. The selection sort algorithm is a simple, easy-to-understand algorithm that can be used to sort an array in ascending or descending order. However, it is not very efficient for large arrays and has a time complexity of O(n^2).                                                                                                                         The algorithm that defines a two-dimensional array:                                                                                                                       Step 1: Start                                                                                                                                                                                           Step 2: Declare a two-dimensional array of m rows and n columns, where m and n are integers.                                                       Step 3: Initialize the array by assigning values to its elements. This can be done using nested loops that iterate over the rows and columns of the array.                                                                                                                                                   Step 4: Display the elements of the array. This can be done using nested loops that iterate over the rows and columns of the array.                                                                                                                                                                                         Step 5: End                                                                                                                                                                                                 The algorithm that finds the smallest element in a one-dimensional array:                                                                                      Step 1: Start                                                                                                                                                                                            Step 2: Declare an array of n elements, where n is an integer.                                                                                                                                                                                                           Step 3: Initialize the array by assigning values to its elements. This can be done using a loop that iterates over the array and reads in values from the user.                                                                                                                                               Step 4: Set the minimum value to the first element of the array.                                                                                                       Step 5: Compare the minimum value with each of the other elements in the array. If any element is less than the minimum value, assign that element to the minimum value.                                                                                                                     Step 6: Display the minimum value.                                                                                                                                                        Step 7: End                                                                                                                                                                                                 The given array is: 10 2 66 71 12 34 8 52                                                                                                                                                        Insertion sort is a simple algorithm that is used to sort an array in ascending or descending order. Insertion sort is performed by iterating over the array and inserting each element into its proper position in the sorted subarray. Here's how to use insertion sort to sort the given array in ascending order:                                                                                                  Step 1: Iterate over the array starting from the second element. This is because the first element is already considered sorted.                                                                                                                                                                                                     Step 2: Compare the current element with the elements in the sorted subarray. If any element is greater than the current element, move that element to the right to make room for the current element.                                                                              Step 3: Insert the current element into its proper position in the sorted subarray.                                                                                     Step 4: Repeat steps 1-3 for the remainder of the array until the entire array is sorted.                                                                    The sorted array is 2 8 10 12 34 52 66 71Q5.                                                                                                                                          The algorithm reads 2 integer numbers and finds their sum.                                                                                                                     Step 1: Start                                                                                                                                                                                            Step 2: Read the first integer number from the data medium and assign it to variable a.                                                                                           Step 3: Read the second integer number from the data medium and assign it to variable b.                                                                       Step 4: Add the values of a and b and assign the result to variable c. c = a + b                                                                                               Step 5: Display the value of c.                                                                                                                                                                 Step 6: End

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A definite integral is said to be improper if one or both of the limits of integration are infinite, or if the integrand function has a vertical asymptote within the interval of integration.

In other words, an improper integral is one that cannot be evaluated using the usual techniques of integration, such as the fundamental theorem of calculus, because it involves infinite limits or a function that is not integrable over the interval.

For example, the definite integral of f(x) = 1/x from 1 to infinity is an improper integral because the upper limit of integration is infinity, which is not a finite number. Similarly, the definite integral of f(x) = ln(x) from 0 to 1 is an improper integral because the lower limit of integration is 0, and the function has a vertical asymptote at x=0.

To evaluate improper integrals, we use limit processes to determine whether the integral converges (has a finite value) or diverges (has an infinite value). If the integral converges, we can find its value by taking the limit of a related integral as one or both of the limits of integration approach infinity or zero.

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Answer:

c

Step-by-step explanation:

Answer:

The answer would be 1/r^42.

Step-by-step explanation:

\(x^{-|y|} =\frac{1}{x^{|y|} } ,(x^{y} )^{z}=x^{y*z}\)

Answer:

10 shirts have to be purchased.

Step-by-step explanation:

The Cactus Company equation: 15 (base fee) + 7x (7 being the price, x being the number of shirts purchased).

The Flower Company equation: 35 (base fee) + 5x (5 being the price, x being the number of shirts purchased).

Our final equation: 15+7x = 35 + 5x

                                    -5x            -5x

                                15+2x = 35

                                -15         -15

                                2x = 20

                                  /2    /2

                                  x = 10

The probability P(X=2, Y+Z ≤ 3) is 13. Random variables are variables in probability theory that represent the outcomes of a random experiment or event.

To find the probability P(X=2, Y+Z ≤ 3), we need to sum up the joint probabilities of all possible combinations of X=2, Y, and Z that satisfy the condition Y+Z ≤ 3.

Step 1: List all the possible combinations of X=2, Y, and Z that satisfy Y+Z ≤ 3:

X=2, Y=1, Z=1

X=2, Y=1, Z=2

X=2, Y=2, Z=1

Step 2: Calculate the joint probability for each combination:

For X=2, Y=1, Z=1:

f(2, 1, 1) = (2+1) * 1 = 3

For X=2, Y=1, Z=2:

f(2, 1, 2) = (2+1) * 2 = 6

For X=2, Y=2, Z=1:

f(2, 2, 1) = (2+2) * 1 = 4

Step 3: Sum up the joint probabilities:

P(X=2, Y+Z ≤ 3) = f(2, 1, 1) + f(2, 1, 2) + f(2, 2, 1) = 3 + 6 + 4 = 13

They assign numerical values to the possible outcomes of an experiment, allowing us to analyze and quantify the probabilities associated with different outcomes.

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His answer was correct:

(200*0.09)=18

18*16=288

200+288=488

Answer:

Was it right?? Im doing this problem rn

Step-by-step explanation:

Answer:

\(15\) months

Step-by-step explanation:

Given that company \(A\) charges  \(\$75\) upfront and \(\$20\) per month and company B does not charge the upfront fee but charges \(\$35\) per month.

Let after \(n\) months both the company charges the same amount.

Total charges by the company \(A=\$ (75+n\times 20)\) and total charges by the company \(B=\$ (n\times 35)\).

Now, from the given condition both the charges are equal, so

\(75+n\times 20=n\times 35 \\\Rightarrow 75= 35 n - 20 n\\\Rightarrow 75= 15 n \\\Rightarrow n= \frac {75}{5} \\\Rightarrow n= 15\)

Hence, after \(15\) months both the company charges the same amount.

Answer:

X = 101

Step-by-step explanation:

Add 11 to 90

90 + 11 = 101

Answer:

Yea, I'm pretty sure it is

Step-by-step explanation:

Answer:

The answer is 69

Step-by-step explanation:

Use the Pythagorean theorem (but instead of adding subtract) :)

Answer:

75 bicycles each month to break even.

Step-by-step explanation:

To break even, the total revenue of the store must be equal to its total expenses. Let's first calculate the total variable cost, which is the cost directly associated with each bike sold:

Total variable cost per bike = $60

Total fixed cost = $4500

Now let's calculate the contribution margin per bike, which is the difference between the selling price and the variable cost:

Contribution margin per bike = $120 - $60 = $60

To break even, the total contribution margin must be equal to the total fixed cost:

Contribution margin x number of bikes sold = Fixed cost

$60 x number of bikes sold = $4500

Number of bikes sold = $4500/$60

Number of bikes sold = 75

Therefore, the store needs to sell 75 bicycles each month to break even.

If he doesn't pay off his balance by the end of the month, he owes $414.275 on credit card after one month.

A credit card is a payment card given to customers (cardholders) that enables the user to pay a merchant for goods and services based on the cardholder's accumulated debt (i.e., promise to the card issuer to pay them for the amounts plus the other agreed charges).

A revolving account is opened by the card issuer, which is typically a bank or credit union, and a line of credit is given to the cardholder. From this line of credit, the cardholder can borrow money to pay for purchases or to get a cash advance.

Consumer and business credit cards fall under one of two credit card categories. Most cards are plastic, but some are metal (stainless steel, gold, palladium, titanium), and a few metal cards have gemstone inlays on them.

We need to add principal and interest

$365 + 13. 5%×$365

= $414.275

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To solve the initial value problem using the method of Laplace transforms, we'll first take the Laplace transform of both sides of the differential equation.

Taking the Laplace transform of each term, we get:

Ly'' + 2Ly' - 3Ly = 0

Using the properties of Laplace transforms and the initial value theorem, we can write the transformed equation as:

\(s^2Y(s) - sy(0) - y'(0) + 2sY(s) - 2y(0) - 3Y(s) = 0\)

Substituting the initial conditions y(0) = 2 and y'(0) = 18, we have:

\(s^2Y(s) - 2s - 18 + 2sY(s) - 4 - 3Y(s) = 0\)

Grouping similar terms, we obtain:

\((s^2 + 2s - 3)\)Y(s) = 24 + 2s

Now, we can solve for Y(s) by dividing both sides by (\(s^2 + 2s - 3)\)

Y(s) = (24 + 2s) /\((s^2 + 2s - 3)\)

To find the inverse Laplace transform and obtain the solution y(t), we need to factor the denominator of the expression on the right-hand side:

s^2 + 2s - 3 = (s + 3)(s - 1)

We can rewrite the expression for Y(s) as:

Y(s) = (24 + 2s) / [(s + 3)(s - 1)]

Now, we need to perform partial fraction decomposition to simplify the expression. We write:

Y(s) = A / (s + 3) + B / (s - 1)

Multiplying both sides by (s + 3)(s - 1) to clear the denominators, we get:

24 + 2s = A(s - 1) + B(s + 3)

Expanding and collecting like terms, we have:

24 + 2s = (A + B)s + (3B - A)

To match the coefficients on both sides of the equation, we equate the coefficients of s and the constants:

A + B = 2 (coefficient of s)

3B - A = 24 (constant term)

Solving this system of equations, we find A = 5 and B = -3.

Now, we can rewrite Y(s) as:

Y(s) = 5 / (s + 3) - 3 / (s - 1)

Taking the inverse Laplace transform of Y(s), we can use the table of Laplace transforms or known formulas to find the solution y(t):

y(t) = 5e^(-3t) - 3e^t

Therefore, the solution to the initial value problem is:

\(y(t) = 5e^(-3t) - 3e^t\)

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If the population of the small town is currently 8,500 people, then 4.06 years will it take for the population to reach 5,500 people.

To find the number of years it will take for the population of the small town to reach 5,500 people from the current 8,500 people, we can use the formula for exponential decay which is:

P(t) = P₀e^(kt)

Where:
P₀ = initial population
P(t) = population after time t
k = growth/decay constant

To solve for the number of years it will take for the population to reach 5,500 people, we need to use the exponential decay formula and solve for t when P(t) = 5,500, P₀ = 8,500, and k is negative since the population is decreasing.

P(t) = P₀e^(kt)

5500 = 8500e^(kt)

Divide both sides by 8500.5500/8500 = e^(kt)

Take the natural logarithm of both sides to isolate k.

ln(5500/8500) = ln(e^(kt))

ln(5500/8500) = kt

Divide both sides by k.

ln(5500/8500)/k = t

Approximately, t ≈ 4.06

Therefore, it will take approximately 4.06 years for the population of the small town to reach 5,500 people.

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The drug that enhances the benefits of exposure therapy and helps relieve the symptoms of PTSD and OCD is D-cycloserine.

D-cycloserine is an antibiotic that has been found to facilitate the extinction of fear conditioning, which is the basis of exposure therapy. It works by targeting the NMDA receptor in the brain, which is involved in the formation of new memories.

Exposure therapy is a type of psychotherapy that involves gradually exposing the individual to the feared stimulus in a safe and controlled environment. This allows the individual to learn that the feared stimulus is not actually dangerous and can help to reduce the symptoms of PTSD and OCD.

Studies have shown that adding D-cycloserine to exposure therapy can enhance the effectiveness of the treatment and improve the long-term outcomes. It has been found to be particularly effective in the treatment of PTSD and social anxiety disorder.

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Answer:

v = \(-\frac{32}{3}\)

Step-by-step explanation:

7v = 4v - 32

7v - 4v = -32

3v = -32

v = \(-\frac{32}{3}\)

Answer:

10.68

Step-by-step explanation:

7v=4v-32

-4v  -4v

----------------

3v=-32

v=10.67

So then you'd plug that into the thing:

7(10.67)=4(10.67)-32

74.69=42.68-32

10.68

Therefore , the solution of the given problem of parallelogram comes out to be  the necessary point is (6,1).

In Euclidean geometry, a simple square containing two sets of equal distances is referred to be a parallelogram. In a particular kind of quadrilateral known as a parallelogram, both pair of opposite ends were straight and equal. There are four types of parallelograms, two of which are mutually exclusive. Rhombuses, equilateral triangles, squares, and rectangles are the four different shapes. If a quadrilateral has two sets of parallel sides, it is a parallelogram.

Here.

Therefore, AC and BD will be the diagonals.

The midpoint of a parallelogram is where its diagonals meet, therefore

The diagonals' junction point will be either AC or BD.

So, according to the mid-point theorem, the midpoint of AC is

A(1,−5) and C (11,7)

Consequently,

=> x = 1 + 11/2 = 6, and

=>Y = 7 - 5 /2 = 1

So the necessary point is (6,1).

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Therefore, the product of the radical expression (7 - sqrt(2))(8 + sqrt(2)) is 54 - sqrt(2).

To find the product of the given radical expression, we can use the FOIL method, which stands for First, Outer, Inner, Last.

(7 - sqrt(2))(8 + sqrt(2))

= 7(8) + 7(sqrt(2)) - (sqrt(2))(8) - (sqrt(2))(sqrt(2))

= 56 + 7sqrt(2) - 8sqrt(2) - 2

= 54 - sqrt(2)

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Answer:

The amount she saves is 25% of her income

Step-by-step explanation:

She is paid $11 per hour

She works 9 hours per day

and for 24 days per month

So, she works 9(24) hours per month

= 216 hours per month

Now, she is paid $11 hourly, so for 216 hours,

she will have 11(216) = $2376

Total income = $2376 per month

Saving = $594 per month

As a percentage, we divide the savings by the total income,

savings/(total income) = 594/2376 = 1/4 = 0.25

Hence we get 25%

Answer:

Step-by-step explanation:

.6(2k-3)=3(4k+5) foil

1.2K-1.8=12k+15 subtract 1.5k from both sides

-1.8=10.8k+15 subtract 15 from both sides

-16.8=10.8k divide by 10.8

k= -1.5

a) U is subspace of R^3.

b) The set {(3, -2, 0), (0, 1/2, 1)} is a basis for U.

c) 2.

a) To show that U is a subspace of R^3, we need to verify the following three conditions:

i) The zero vector (0, 0, 0) is in U.

ii) U is closed under addition.

iii) U is closed under scalar multiplication.

i) The zero vector is in U since 0 + 2(0) - 3(0) = 0.

ii) Let (x1, y1, z1) and (x2, y2, z2) be two vectors in U. Then we have:

x1 + 2y1 - 3z1 = 0 (by definition of U)

x2 + 2y2 - 3z2 = 0 (by definition of U)

Adding these two equations, we get:

(x1 + x2) + 2(y1 + y2) - 3(z1 + z2) = 0

which shows that the sum (x1 + x2, y1 + y2, z1 + z2) is also in U. Therefore, U is closed under addition.

iii) Let (x, y, z) be a vector in U, and let c be a scalar. Then we have:

x + 2y - 3z = 0 (by definition of U)

Multiplying both sides of this equation by c, we get:

cx + 2cy - 3cz = 0

which shows that the vector (cx, cy, cz) is also in U. Therefore, U is closed under scalar multiplication.

Since U satisfies all three conditions, it is a subspace of R^3.

b) To find a basis for U, we can start by setting z = t (where t is an arbitrary parameter), and then solving for x and y in terms of t. From the equation x + 2y - 3z = 0, we have:

x = 3z - 2y

y = (x - 3z)/2

Substituting z = t into these equations, we get:

x = 3t - 2y

y = (x - 3t)/2

Now, we can express any vector in U as a linear combination of two vectors of the form (3, -2, 0) and (0, 1/2, 1), since:

(x, y, z) = x(3, -2, 0) + y(0, 1/2, 1) = (3x, -2x + (1/2)y, y + z)

Therefore, the set {(3, -2, 0), (0, 1/2, 1)} is a basis for U.

c) Since the basis for U has two elements, the dimension of U is 2.

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The distance from the sun to the other focus is 5.01 × 10⁹ m.

(a) The distance from the center of an ellipse to a focus is an where a is the semi major axis and e is the eccentricity. Thus, the separation of the foci ( in the case of Earth's orbit ) is;

2ae = 2(1.50 × 10¹¹)(0.0167) = 5.01 × 10⁹ m.

(b) To express this in terms of solar radii, we set up a ratio;

(5.01 × 10⁹)/(6.96 × 10⁸) = 7.2

Thus, we can conclude that the distance from the sun to the other focus is 5.01 × 10⁹ m.

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Complete question is;

The Sun's center is at one focus of Earth's orbit. How far from this focus is the other focus, (a) in meters and (b) in terms of the solar radius, 6.96 × 10⁸ m? The eccentricity is 0.0167, and the semimajor axis is 1.50 × 10¹¹ m.

Answer:

II and III

Step-by-step explanation:

Parallel lines have the same gradient, they will have the same coefficient in front of x

II: 2x + 3y = 6 needs to be rearranged to 3y = -2x + 6 and then y = -2/3x + 2: the gradient is -2/3

III: y - 8 = -2/3(x - 3) needs to expanded so y - 8 = -2/3x + 2 and then y = -2/3x + 10: again, the gradient is -2/3

The two lines are parallel because both gradients are -2/3

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If the speed and the charge of a particle moving across a magnetic field are each doubled, the deflecting force will be:

d. The deflecting force will be quadrupled.

The deflecting force experienced by a charged particle moving across a magnetic field is given by the equation F = qvBsinθ, where F is the deflecting force, q is the charge of the particle, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.

If both the speed (v) and charge (q) of the particle are doubled, the deflecting force (F) can be calculated by substituting the new values into the equation:

F' = (2q)(2v)Bsinθ = 4(qvBsinθ) = 4F

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Answer:

La madre de Marta tiene 45 años.

Step-by-step explanation:

X = edad de mamá de Marta

15 = 1/3 X

(15)(3) = X

45 = X