When a tennis racket hits a tennis ball, the time needed for the racket to change the ball's direction by imparting an impulse (the product of the average force on an object and the time interval over which it acts) to it is extremely ____
Answers
When a tennis racket hits a tennis ball, the time needed for the racket to change the ball's direction by imparting an impulse to it is extremely low.
When a tennis ball is served, it is a contact with the racket for a time that is typical 0.005 seconds which is less than a hundredth of a second. The force provided by the racket is extremely high. So, the interval of time for which the force applied need not be high to change its direction.
I = F Δt
F = m a
F = m Δv / Δt
F Δt = m Δv
I = m Δv
I = Impulse
F = Force
m = Mass
a = Acceleration
Δv = Change in velocity
Δt = Change in time
Therefore, when a tennis racket hits a tennis ball, the time needed for the racket to change the ball's direction by imparting an impulse to it is extremely low.
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Related Questions
A snail travels 24.5 cm/hr. The snail accelerates itself to 28.2 cm/hr in 23.4 min. What is the acceleration of the snail? Convert minutes to hours by dividing 23.4 min by 60 before solving the problem.
Answers
The acceleration of the snail is 9.49 cm/hr².
What is acceleration?Acceleration is a vector quantity considered as the rate at which an object's velocity varies. If an object's velocity changes, it is accelerating.
To find the acceleration of the snail, we need to find the change in velocity (Δv) and divide it by the time it took for that change to occur (Δt).
First, convert the time from minutes to hours:
23.4 min ÷ 60 min/hr = 0.39 hr
Now, the change in velocity:
Δv = 28.2 cm/hr - 24.5 cm/hr = 3.7 cm/hr
Finally, we'll divide the change in velocity by the time it took to get the acceleration:
a = Δv / Δt = 3.7 cm/hr / 0.39 hr = 9.49 cm/hr²
So, the acceleration of the snail is 9.49 cm/hr².
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A rocket's orbital maneuver requires a speed increase of 1.05 ✕ 103 m/s. If its engine has an exhaust speed of 2.25 ✕ 103 m/s, determine the required ratio
Mi/Mf of its initial mass to its final mass. (The difference Mi − Mf equals the mass of the ejected fuel.)
Answers
The ratio of the rocket's initial mass to final mass is 1.595
How to find the ratio of the rocket's initial mass to is final mass?Usng the rocket formula, for change in speed
Δv = v㏑(Mi/Mf) where
v = speed of exhaust, Mi = initial mass and Mf = final massGiven that a rocket's orbital maneuver requires a speed increase of 1.05 × 10³ m/s. If its engine has an exhaust speed of 2.25 × 10³ m/s,
So,
Δv = 1.05 × 10³ m/s and v = 2.25 × 10³ m/sMaking (Mi/Mf) subject of the formula, we have
(Mi/Mf) = exp(Δv/v)
So, substituting these into the equation for the rocket speed, we have
(Mi/Mf) = exp(Δv/v)
(Mi/Mf) = exp(1.05 × 10³ m/s/2.25 × 10³ m/s)
(Mi/Mf) = exp(0.467)
(Mi/Mf) = 1.595
So, the ratio of the rocket's initial mass to final mass is 1.595
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You drop a 5 kg ball from a height of 2 m. Just
before it reaches the ground, how much kinetic
energy does it have?
Answers
Answer:
Kinetic energy = 98 N
Explanation:
Given:
Mass = 5 kg
Height = 2 m
Find:
Kinetic energy
Computation:
K(e) = P(e)
So,
P(e) = mgh
So,
K(e) = (5)(9.8)(2)
Kinetic energy = 98 N
a person shouted at the surface of a well abd heard his echo clearly after 0.3seconds calculate the distance between the person and surface of water in the well
Answers
Answer:
Assuming that the sound wave reflected only once off the surface of the water and traveled straight back up to the person, we can calculate the distance between the person and the surface of the water in the well as follows:
Distance = (Speed of sound in air x Time)/2
Where the speed of sound in air is approximately 343 meters per second at standard temperature and pressure, and the time is 0.3 seconds.
Distance = (343 m/s x 0.3 s)/2
Where the speed of sound in air is approximately 343 meters per second at standard temperature and pressure, and the time is 0.3 seconds.
Distance = (343 m/s x 0.3 s)/2
Distance = 51.45 meters
Therefore, the distance between the person and the surface of the water in the well is approximately 51.45 meters.
as you found in part a, your weight will be greater than normal when the elevator is moving upward with increasing speed. for what other motion would your weight also be greater than your normal weight?
Answers
Answer:
1) F = M a accelerating forward would cause a seeming increase weight.
2) F = m v^2 / R a person moving in a circular arc would have an apparent component of weight towards the center of rotation (in addition to his normal vertical component of weight).
As cars travel, oil and gasoline leaks onto the road surface. If a light rain falls, what does this do to the control of the car
Answers
When a light rain falls after oil and gasoline have leaked onto the road surface, it can cause the car to become less responsive and more difficult to control.
This is because the oil and gasoline act as a slippery layer on the road surface, which reduces the friction between the tires and the road. The rainwater can then mix with the oil and gasoline, making the layer even more slippery and reducing the vehicle's grip on the road.
To help mitigate this issue, drivers should be aware of their surroundings and the potential for slippery surfaces, and should adjust their speed and driving accordingly. Additionally, using tires with greater tread, or using more aggressive tires designed for wet and slippery conditions, can also help increase the vehicle's grip on the road.
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Three point charges are located on the x-axis. The first charge, q1 = +10 µC, is at x = -1. 0 m. The second charge, q2 = +20 µC, is at the origin. The third charge, q3 = - 30 µC, is located at x = +2. 0 m. What is the net force on q2?
Answers
The net force on q2 to be 1.08 x 10^-3 N directed towards q1, because the charges on q1 and q3 are oppositely charged and the force between them is attractive, while the force between q2 and the other two charges is repulsive.
We have three point charges located on the x-axis. The first charge, q1, has a charge of +10 µC and is positioned at x = -1.0 m. The second charge, q2, has a charge of +20 µC and is located at the origin (x = 0). The third charge, q3, has a charge of -30 µC and is positioned at x = +2.0 m.
We need to find the net force on q2 due to the other two charges. We can calculate this using Coulomb's law, which gives us a formula to calculate the force between two charges.
Plugging in the values, we get the net force on q2 to be 1.08 x 10^-3 N directed towards q1, because the charges on q1 and q3 are oppositely charged and the force between them is attractive, while the force between q2 and the other two charges is repulsive.
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Plane is flying east at 33m/s an airplane is also being carried due north at 12 m/s by the wind what is the planes resultant velocity
Answers
Answer: 2.75
Explanation: To find velocity you divide distance and time. V = d/t
33/12 = 2.75
Answer:
35.11
Explanation:
The outer core is a liquid because
Group of answer choices
There is more pressure than the Inner Core and the temperatures are cold enough to freeze the Iron (Fe) and Nickle (Ni).
There is more pressure than the Inner Core and the temperatures are hot enough to melt the Iron (Fe) and Nickel (Ni).
There is less pressure than the Inner Core and the temperatures are hot enough to melt the Iron (Fe) and Nickel (Ni).
There is less pressure than the Inner Core and the temperatures are cold enough to freeze the Iron (Fe) and Nickel (Ni).
Answers
Outer core is a liquid because: there is more of pressure than inner core and also temperatures are hot enough to melt Iron (Fe) and Nickel (Ni).
What is pressure?The quantity of force applied per area is referred to as pressure.
The outer core is liquid despite sharing a composition with the solid inner core of Earth because it does not experience enough pressure to maintain solidity.
The outside core is liquid even though its composition is similar to that of the inner core because it is not under enough pressure to be solid. Additionally, oxygen and sulphur may be present in the outer core. Life on Earth would be different without the outer core.
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If an air parcel contains the following, what is the mixing ratio of this parcel? Mass of dry air =2 {~kg} Mass of water vapor =10 {~g}
Answers
Given that the mass of dry air is 2 kg and the mass of water vapor is 10 g. Therefore, the mixing ratio of the air parcel is 0.005.
To calculate the mixing ratio of an air parcel, we need to determine the mass of water vapor per unit mass of dry air. The given values are the mass of dry air, which is 2 kg, and the mass of water vapor, which is 10 g. First, we need to convert the mass of water vapor to the same units as the mass of dry air. Since 1 kg is equal to 1000 g, we can convert the mass of water vapor to kg:
Mass of water vapor = 10 g = 10/1000 kg = 0.01 kg
Now, we can calculate the mixing ratio:
Mixing ratio = Mass of water vapor / Mass of dry air
Mixing ratio = 0.01 kg / 2 kg
Mixing ratio = 0.005
Therefore, the mixing ratio of the air parcel is 0.005.
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If a train approaches you (sitting in the bench ) at a velocity of 35 m/s, what frequency will you hear as it sounds its whistle at 188 Hz? speed of sound= 345 m/sA) 188 HzB) 170.7 HzC) 209.2 HzD) 202.7 Hz
Answers
Given:
The speed of the train is,
\(v_s=35\text{ m/s}\)The actual frequency of the whistle is,
\(f=188\text{ Hz}\)The speed of sound in air is,
\(v=345\text{ m/s}\)To find:
The frequency heard by the observer
Explanation:
The apparent frequency when the train approaches the observer is given by,
\(\begin{gathered} f_{apparent}=f\frac{v}{v-v_s} \\ =188\times\frac{345}{345-35} \\ =188\times\frac{345}{310} \\ =209.2\text{ Hz} \end{gathered}\)Hence, the frequency heard by you is 209.2 Hz.
the best way to study warm (1000 k) young stars forming behind an interstellar dust cloud would be to use a. blue light b. ultraviolet light c. x-rays d. infrared light
Answers
The best way to study warm (1000 K) young stars forming behind an interstellar dust cloud would be to use infrared light. So option d is correct.
Interstellar dust clouds can block or scatter shorter-wavelength light, such as blue light and ultraviolet light, making it difficult to observe objects behind them. However, longer-wavelength infrared light can penetrate through the dust cloud with less scattering and absorption, allowing us to study the objects hidden behind the dust.
Infrared light is particularly effective for studying warm objects, as they emit most of their radiation in the infrared range. By using infrared telescopes and detectors, astronomers can observe the thermal radiation emitted by the young stars and study their formation and evolution processes.Therefore option d is correct.
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From which evidence can a forensic expert extract DNA?
Answers
Answer:
The biological material used to determine a DNA profile include blood, semen, saliva, urine, feces, hair, teeth, bone, tissue and cells.
Explanation:
Answer:
bone
Explanation:
A 50.5 N object is in free fall.
What is the magnitude of the net force
which acts on the object?
Answers
Answer:
-49.49
Explanation:
If there’s no air resistance then the only thing acting on the object is the force of gravity which is mass times gravity. And to get mass all we have to do is divide 50.5/10 then times that by -9.8 since that’s the force of gravity.
Answer: The answer would be 50.5 N.
Explanation: It’s because there’s no air resistance.
The frequency of the first harmonic in a pipe is measured. An adjustment [1 mark] is then made which causes the speed of sound in the pipe to increase. What is true for the frequency and the wavelength of the first harmonic when the speed of sound has increased? Frequency Wavelength А increase unchanged B unchanged increase C increase increase D unchanged unchanged
Answers
When the speed of sound in the pipe increases, the frequency and wavelength of the first harmonic will both increase. Therefore, the correct answer is C (increase, increase).
When an adjustment is made which causes the speed of sound in the pipe to increase, the frequency of the first harmonic also increases while the wavelength remains unchanged. This is because the frequency of a wave is directly proportional to its speed, and the wavelength is inversely proportional to its speed. Thus, when the speed of sound increases, the frequency of the first harmonic increases while the wavelength remains constant.
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what is the repulsive force between two pith balls that are 10.3 cm apart and have equal charges of 34.0 nc?
Answers
The repulsive force between two pith balls is F = 9.8 × 10^(-4) N
It can be calculated using Coulomb's law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. The formula for Coulomb's law is:
F = k × q1 × q2 / r^2
where k is the Coulomb constant (9 × 10^9 N × m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them. With the given charges of 34.0 nC and a separation of 10.3 cm, we can calculate the repulsive force as follows:
F = (9 × 10^9 N × m^2 / C^2) × (34.0 × 10^(-9) C)^2 / (0.103 m)^2
F = 9.8 × 10^(-4) N
The resulting force will be a positive value, indicating repulsion.
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Let's say an apple weighs exactly 8N on the surface of the Earth (which corresponds to a distance of 6400 km from the center of the Earth). Now imagine an astronaut brings the apple on a spaceship. What is the weight of this apple at a vertical distance of 6400 km above the surface of the Earth? Hint: the radial distance of the apple from the center has doubled. What does this do to the force of gravity according to Newton's law of universal gravitation? O The weight stays the same O The weight is 2N O The weight is 1N O The weight is 0.5N
Answers
The weight of this apple at a vertical distance of 6400 km above the surface of the Earth is equal to 2N
The acceleration due to gravity above the surface of the Earth decreases as we move away from it. The acceleration due to gravity g' above the surface of the earth at height h is given by the equation
g' = g( 1 + h/R)⁻²,
where R is the radius of the earth = 6400 km
Given: height of apple, h = 6400km
weight of the apple at the surface of the earth = 8N
mg = 8N
using the formula of acceleration due to gravity given above,
weight of an apple at 6400 km above the surface of the earth
mg' = mg( 1 + h/R)⁻²
mg' = 8( 1+ 6400/ 6400)⁻²
mg' = 2N
Therefore, the weight of this apple at a vertical distance of 6400 km above the surface of the Earth is equal to 2N.
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The probability of finding a certain quantum particle in the section of the x axis between x = 4 nm and x=7 nm is 48 % . The particle's wave function psi(x) is constant over this range. What numerical value can be attributed to psi(x) , in units of n m⁻¹/² ? (a) 0.48 (b) 0.16 (c) 0.12 (d) 0.69 (e) 0.40
Answers
The numerical value that can be attributed to psi(x), the wave function of the quantum particle, in units of nm⁻¹/², is 0.40. The correct option is (e).
In quantum mechanics, the probability density of finding a particle in a specific region is proportional to the square of the absolute value of its wave function, psi(x). If the wave function is constant over a given range, the probability density is also constant within that range.
Here, the probability of finding the particle between x = 4 nm and x = 7 nm is given as 48%. Since the probability density is constant, we can equate it to 48% or 0.48. According to the properties of probability densities, the integral of the probability density function over a certain range should be equal to the probability of finding the particle in that range. Therefore, we can set up the following equation:
∫[psi(x)]² dx = 0.48
Since psi(x) is constant, we can pull it out of the integral:
psi(x)² ∫dx = 0.48
Since psi(x)² is constant, the integral of dx over the range x = 4 nm to x = 7 nm is simply the difference in the limits:
psi(x)² (7 nm - 4 nm) = 0.48
3 psi(x)² = 0.48
Dividing both sides by 3 gives:
psi(x)² = 0.16
Taking the square root of both sides, we obtain:
psi(x) = 0.40
Therefore, the numerical value that can be attributed to psi(x), in units of nm⁻¹/², is 0.40, which corresponds to option (e).
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a new package moving system in the new, improved post office consists of a large circular disc (i.e. a turntable) which rotates once every 3.0 seconds at a constant speed in the horizontal plane. packages are put on the outer edge of the turntable on one side of the room and taken off on the opposite side. the coefficient of static friction between the disc surface and a package is 0.80 while the coefficient of kinetic friction is 0.60. if this system is to work, what is the maximum possible radius of the turntable?
Answers
The maximum possible radius of the turntable in the new package moving system in the new, improved post office is 11.2 m.
The maximum possible radius of the turntable in the new package moving system in the new, improved post office is determined by the coefficients of static and kinetic friction between the disc surface and a package. The coefficient of static friction is 0.80 and the coefficient of kinetic friction is 0.60. The radius of the turntable should be large enough so that when the turntable rotates once every 3.0 seconds, the package does not slide due to the centripetal force. Thus, the maximum possible radius of the turntable is given by the following equation:
R = (v2/μkg) + (μs/μk),
Where R is the maximum possible radius of the turntable, v is the velocity of the turntable, μk is the coefficient of kinetic friction, μs is the coefficient of static friction, and g is the acceleration due to gravity. Substituting the given values into the equation, we obtain R = 11.2 m.
Therefore, the answer obtained is 11.2 m.
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When an obstacle is less than ______ away, the sonar system's beeping becomes a continuous tone.
Answers
When an obstacle is less than a specific distance away, the sonar system's beeping becomes a continuous tone.
This distance depends on the specific sonar system being used and its settings. In general, the continuous tone indicates that the obstacle is close enough to require immediate attention or action to avoid potential hazards.When an obstacle is less than a certain distance away, typically around 2-3 feet, the sonar system's beeping becomes a continuous tone. This indicates that the obstacle is very close and immediate action is required to avoid a collision.
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This equation goes with which law?
Answers
Answer:
I think that's Newton's second law of motion
Explanation:
f = m(v-u)
________
t
since a = (v-u)t
f = ma
The theory of plate tectonics was created by this evidence.
Sea floor spreading
Ridges in the sea floor moving outward.
Due to the sea floor spreading the continental crust must be moving as well
Answers
The process through which tectonic plates—large slabs of Earth's lithosphere—split away from each other is known as seafloor spreading.
What is seafloor spreading?Mantle convection causes seafloor spreading and other tectonic activity processes. Divergent plates, a form of tectonic activity that results in plates moving away from each other, causing seafloor spreading. Diverge Seafloor spreading results in three major characteristics of the seafloor: the age of the seafloor becomes progressively older as one moves away from mid-ocean ridges, the elevation of the seafloor becomes progressively lower as one moves away from mid-ocean ridges, and the magnetic history of the seafloor bears the striped-pattern of the Earth's magnetic.
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CAN SOMEONE DO THIS FOR ME PLEASE CHECK THE COMMENT FOR THE LINK TO THE ASSESSMENT
Answers
Answer:
yes.................
please help me !!!! i really need it
Answers
Answer:
Prefer Soil more than sand
Explanation:
If you just take the points I will find you and you will not like what I do
Advanced Space Weather Activity
This lesson highlighted different types of space weather. If you were responsible for reporting space weather like Earth's weather is reported, how would you do it? What would you include?
Create any type of weather report to warn people about space weather activity. You can present it like a weather app, radio announcement, television news report, or newspaper weather section. You only need to pick one type of report to submit to your instructor.
Activity Checklist:
Include at least three different types of space weather events.
Include details and warnings for viewers or listeners about space weather outcomes.
Include images to help identify space weather or its effects on Earth.
Pick a weather app, radio announcement, television news report, or newspaper weather section as the format for your report.
Answers
Answer:
Explanation:
here this is a whole slideshow i made
Answer:
Explanation:
Fun homework assignment!
I will provide the info that should allow you to write the space weather report.
Three different types of space weather events:
- Solar flare: strong radiation from the Sun. People should stay inside their spacecrafts.
- Meteorite shower: space rocks zipping by at extreme high speed. Again people should stay inside.
- Man-made space debris: big and small space junk left by human space activities. Slower than meteorite but still need to keep an eye on them.
Effect on Earth:
- Solar flare will affect radio communication and satellite transmission.
- Meteorite shower usually burns up in atmosphere but some may hit ground.
- Space debris also burn up in air but some may land like the recent Chinese rocket.
13. Which cart has the greatest inertia?
1. a 1-kg cart traveling at 4 m/s
2. a 2-kg cart traveling at 3 m/s
3. a 3-kg cart traveling at 2 m/s
4. a 4-kg cart traveling at 1 m/s
Answers
#2. If we have a 9V battery connected to a 100 resistor , what is the current ?
Answers
Answer:
90 mAmps
Explanation:
V=IR
V/R = I
9 v / 100 ohm = .09 amps = 90 mAmps
A charged particle is located at a point on an equipotential line moving at speed v. You later see the same particle at a different point on the same equipotential line. What can you say about its speed at this later instant
Answers
The speed of the charged particle is the same at both points on the same equipotential line, which means that the potential energy remains constant.
An equipotential line is a line that is perpendicular to the electric field at every point of the line. The potential difference between two points on an equipotential line is zero. The work done by the electric field on the charged particle is zero, implying that the potential energy is constant for every point on the equipotential line. Since the electric field at any point on the equipotential line is perpendicular to the equipotential line, it can be concluded that the electric field does not cause any acceleration of the charged particle.
The charged particle moves in a straight line with constant speed due to Newton's first law, since there is no force acting on it as a result of the electric field.The speed of the charged particle is the same at both points on the same equipotential line, which means that the potential energy remains constant. Since potential energy is directly proportional to the square of the speed of the charged particle, its speed will remain constant as it moves along the equipotential line.
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What is the decay constant for Pollonium-212 if the half-life is 299x10^-9 s?
Answers
The radioactive half-life is given by:
\(T_{1/2}=\frac{ln(2)}{\lambda}\)Where:
\(\begin{gathered} T_{1/2}=299\times10^{-9}s \\ so: \\ \lambda=\frac{ln(2)}{299\times10^{-9}} \\ \lambda=2.32\times10^6s \end{gathered}\)2) a) i) A group of quantum states of the hydrogen atom has n=5. How many values / of are possible for states in this group? Explain. Ii) A subgroup of hydrogen atom states in the n=5 group has / =3. How many values of m, are possible for states in this subgroup? Explain. Table lists the quantum numbers for five proposed hydrogen atom states. Which of them are not possible? Explain. (2+2+2) (a) m 3 2 0 hi
Answers
The hydrogen atom will have 5 values for the azimuthal quantum number, l.
i) A group of quantum states of the hydrogen atom has the principal quantum number as,
n = 5.
Therefore, the possible values of the azimuthal quantum number of the hydrogen atom, l will be,
l = 0, 1 ,2, ..., (n - 1) = 0, 1, 2, ..., (5 - 1) values
l = 0, 1, 2, 3, 4
So, the hydrogen atom will have 5 values for the azimuthal quantum number.
ii) Given that,
The principal quantum number of hydrogen atom, n = 5
Azimuthal quantum number of the hydrogen atom, l = 3
Therefore, the possible values of magnetic quantum number, m will be,
m = -l, ..., 0, ...+l
m = -3, -2, -1, 0, 1, 2, 3
So, the hydrogen atom will have 7 values for the magnetic quantum number.
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