Can anyone help please?
Answer:
A'(-3, 12)B'(9, 6)C'(-6, -6)Step-by-step explanation:
Dilation about the origin multiplies each coordinate value by the dilation factor.
For dilation factor k, the new coordinates are ...
(x, y) ⇒ (kx, ky)
Your dilation factor is 3, so the transformation is ...
(x, y) ⇒ (3x, 3y)
A(-1, 4) ⇒ A'(-3, 12)
B(3, 2) ⇒ B'(9, 6)
C(-2, -2) ⇒ C'(-6, -6)
Please help me asap !!!!!!!!
Answer:
Step-by-step explanation:
So what you want to do is devide 7 and 480
HELP!!!! PLZ!!!!!!!!!!!!!!!!!
Answer: A
Cause 10 divided by 1 is 10
Diane is 25 years older than her son Craig. The sum of their ages is 105. How old are Diane and Craig?
Answer:
Let Craigs age = x
Therefore Dianes age = 25 + x ( since she's 25 years older)
Dianes + Craigs age = (25 + x) + x = 105 (They said both of their ages sums up to 105)
25 + 2x = 105
2x = 80
x = 40
Craigs age is 40 years old.
Dianes age is 65 years old.
Answer:
40 and 65
Step-by-step explanation:
Craig is 40.
Diane is 65.
40+25=65.
Diane is 25 years older than Craig.
40+20=105
How large a sample must be obtained to be 94% confident that the true mean IQV is within 2 points of the sample mean
A sample size of 200 must be obtained to be 94% confident that the true mean IQ is within 2 points of the sample mean, assuming a population standard deviation of 15.
To determine the sample size required to be 94% confident that the true mean IQ (µ) is within 2 points of the sample mean, we will use the following terms:
Confidence level (94%)
Margin of error (E) - 2 points
Population standard deviation (σ) - we need this value to calculate the sample size.
Z-score (Z) - the number of standard deviations away from the mean, corresponding to the given confidence level.
Since the standard deviation of the population (σ) is not provided, I will assume a typical value for IQ scores, which is 15.
If you have a different value, you can plug it into the formula.
Steps to determine the sample size (n):
Find the Z-score (Z) corresponding to the 94% confidence level. You can use a Z-score table or calculator. For 94% confidence level, the Z-score is approximately 1.88.
Determine the margin of error (E), which is given as 2 points.
Use the sample size formula:
\(n = (Z^2 * \sigma ^2) / E^2\)
\(n = (1.88^2 * 15^2) / 2^2\)
n = (3.5344 * 225) / 4
n = 797.52 / 4
n = 199.38.
Round up the value of n to the nearest whole number, as you cannot have a fraction of a sample.
In this case, n = 200.
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Polygon JKLM is drawn with vertices J(-4,-3), K(-4,-6), L(-1,-6), M(-1,-3). Determine the image coordinates of L’ if the pre-image is reflected across y=-3.
A. L’(-3,6)
B. L’(-1,6)
C. L’(-1,0)
D. L’(1,0)
Given vertices of polygon JKLM are J(-4,-3), K(-4,-6), L(-1,-6), M(-1,-3). To determine the image coordinates of L', if the pre-image is reflected across y = -3. So the right option is (C) L’(-1,0)
we need to follow the below steps:
Step 1: Plot the points in the coordinate plane.
Step 2: Draw the line of reflection, y = -3. It is a horizontal line.
Step 3: Find the reflection image of point L(-1, -6) about y = -3.
So, let's plot these points in the coordinate plane.
Here is the graph of the polygon:graph{JKLM(-4,-3)(-4,-6)(-1,-6)(-1,-3)}
As we can see in the above graph, the line of reflection y = -3 is a horizontal line passing through the point (-1,-3).
Now, we need to find the image of the point L(-1,-6) reflected across the line y = -3.
Let's draw a line of reflection and points.
Here is the graph:
graph{JKLM(-4,-3)(-4,-6)(-1,-6)(-1,-3)l_ref(y=-3,-7,0)}
To find the image of point L across the line of reflection y = -3, we follow the below steps:
Step 1: Draw a perpendicular line from L to the line of reflection. It intersects the line of reflection at L1.
Step 2: Find the distance between point L and L1.
Step 3: Draw a line through L1 parallel to the line of reflection.
Step 4: The intersection of the line in Step 3 with y = -3 is the image of L across the line of reflection.
Let's apply these steps to find the reflection image of point L. Here is the graph:graph{JKLM(-4,-3)l_ref(y=-3,-7,0)L(-1,-6)L1(-1,-3)L2(-7,-3)L1L--L2--(1,-3)L-(-1,-3)L'(-1,0)}
Step 1: Draw a perpendicular line from L to the line of reflection. It intersects the line of reflection at L1. So, here the perpendicular line is drawn as L1(-1, -3)
Step 2: Find the distance between point L and L1. The distance between L and L1 is 6 units. So, the distance between L' and L1 is also 6 units.
Step 3: Draw a line through L1 parallel to the line of reflection. Let's draw a line through L1 parallel to the line of reflection. The parallel line is L2 : y = -3
Step 4: The intersection of the line in Step 3 with y = -3 is the image of L across the line of reflection. Let's find the point where L2 intersects y = -3: -1 + 6 = 5. So, the point L' is (-1, 0).
Hence, the correct option is C. L’(-1,0).
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What is the value of the expression 2 to the fourth power + 3 to the second power
The answer is 25.
2^4 + 3^5 = 25.
Answer:
The person above me is correct :))
Step-by-step explanation:
Which of the following is true with respect to the following functions: f(x) = 3|x+14 | g(x)= x³ + 3x-14 h(x)=3* +1 i(x) = log4(x - 1) OA. All four functions have curves. OB. g(x) is the only function whose graph has end behaviors that go in the same direction. O C. The graphs of g(x) and f(x) both have end behaviors that go in the same direction. OD. (x) is the only function with a horizontal asymptote.
The answer choice which represents a true statement with respect to the functions is; Choice C; The graphs of g(x) and f(x) both have end behaviors that go in the same direction.
Which statement is true about the functions?It follows from the task content that the functions given are;
f(x) = 3|x+14|
g(x)= x³ + 3x-14
h(x)=3*x +1
i(x) = log4(x - 1).
From the functions given above, it follows that the range of f(x) is all positive real numbers and has an ending behaviour as function g(x) as their ending behaviour indicates ascending slope (positiv slope).
Hence, The graphs of g(x) and f(x) both have end behaviors that go in the same direction.
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What is true about the sum of the two polynomials 6s 2t 2st 2 4s 2t 3st 2?.
The sum of the two polynomials 6s^2t^2 + 2st^2 + 4s^2t + 3st^2 is
6s^2t^2 + 2st^2 + 4s^2t + 3st^2 = (6+4)s^2t^2 + (2+3)st^2 = 10s^2t^2 + 5st^2
The polynomials are being added term by term, and the coefficient of each term is being added.
The coefficient of s^2t^2 in the sum is 10, which is the sum of the coefficients of s^2t^2 in the original polynomials (6 and 4).
The coefficient of st^2 in the sum is 5, which is the sum of the coefficients of st^2 in the original polynomials (2 and 3).
So the sum of the polynomials is 10s^2t^2 + 5st^2, this is the final result.
It's important to note that the polynomials have to be in the same order of terms (same exponent) to obtain the correct result when adding them.
Each of the following sets of dimensions represents the dimensions of a right rectangular prism. All of them have the same volume except length: ; width: 10; height: 3 length: 1; width: 5; height: 7 length: 2; width: 5; height: 3 length: 4; width: 2 ; height: 3
The first and third rectangular prisms have the same volume of 30 cubic units.
The second rectangular prism has a volume of 350 cubic units, and the fourth rectangular prism has a volume of 24 cubic units.
How do we calculate?The volume of each of the rectangular prisms can be calculated as follows:
1. length: 1; width: 10; height: 3
volume = 1 x 10 x 3 = 30
2. length: 5; width: 10; height: 7
volume = 5 x 10 x 7 = 350
3. length: 2; width: 5; height: 3
volume = 2 x 5 x 3 = 30
4. length: 4; width: 2; height: 3
volume = 4 x 2 x 3 = 24
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A parallelogram is a quadrilateral with two pairs of parallel sides.
A quadrilateral is a parallelogram _[blank]_.
Which answer correctly fills in the blank in the previous sentence?
A) because it has only four sides and two of them are parallel
B) if it has two pairs of parallel sides and is a polygon
C) if it has only two pairs of parallel sides
D) if and only if it has two pairs of parallel sides
Answer:
C
Step-by-step explanation:
The quadrilateral is a parallelogram if and only if it has two pairs of parallel sides option (D) is correct.
What is parallelogram?In two-dimensional geometry, it is a plane shape having four sides, in which two pairs of sides are parallel to each other and equal in length. The sum of all angles in a parallelogram is 360°.
It is given that:
A parallelogram is a quadrilateral with two pairs of parallel sides.
As we know,
The quadrilateral can be defined as the four-sided polygon in geometry having four edges and four corners.
The quadrilateral, has:
Two pairs of congruent sides.
It has one pair of opposite congruent angles.
The diagonals of a kite are perpendicular.
One diagonal is bisected.
The top and bottom angles are bisected but does not have congruent diagonals.
A quadrilateral is a parallelogram if and only if it has two pairs of parallel sides.
Thus, the quadrilateral is a parallelogram if and only if it has two pairs of parallel sides option (D) is correct.
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what do the nodes in a radial distribution function represent?
In a radial distribution function, the nodes represent the distances between atoms in a crystalline material.
The radial distribution function (RDF) is a measure of the probability of finding an atom at a given distance from a reference atom. It provides information about the arrangement and spatial distribution of atoms in a material.
The nodes in the RDF graph correspond to specific distances from the reference atom. These distances represent the separation between atoms and are typically measured in terms of interatomic distances or bond lengths. The heights or values of the RDF at these nodes indicate the likelihood of finding an atom at that particular distance from the reference atom.
By analyzing the nodes in the radial distribution function, researchers can gain insights into the atomic structure, coordination, and bonding characteristics of a material, which are essential for understanding its physical and chemical properties.
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A number line going from negative 5 to positive 5. From positive 2 to positive 5 is positive 3.
David added 2 and –3 using the number line tool. Which of the following errors did he make?
He started at 2 instead of zero.
He moved right 2 units for positive 2.
He moved right 3 units for negative 3.
He started at zero instead of 2.
The correct statement is :David started at 0 instead of 2
What is a number line in math?A number line is a horizontal line that has equally spread number increments. The numbers included on the line will determine how the number on the line can be answered. The question that goes with the number determines how it will be used, for example, plotting a point.
Given here: In a number line the interval (-5,5) is marked and 2 to 5 is 3
The right steps are
Add 3 to 2 to obtain the required number as there are 3 spaces between 2 and 5
Thus 2+3=5 which is the required answer
but David addes 2-3=-1 which is incorrect.
Hence, David started at 0 instead of 2
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how many significant digits are there in the number 2.25x10 using significant digits
Answer:
3
Step-by-step explanation:
2.25×10=22.5
If there is 0 in front of the number:eg(02.25) 0 does not count but it counts if it comes after nonzero digits.
Leo is visiting New York City to see the Empire State building. He knows that the Empire State building is 1,484 feet tall. When he spots it, he stops and has to look up at an angle of 84.7 degrees to see the top. How far away from the base of the Empire State building is he?
single die is rolled twice. Find the probability of getting a 3 the first time and a 3 the second time. Express the probability as a simplified fraction. Group of answer choices
Probability refers to the measure of the likelihood or chance of an event occurring, expressed as a value between 0 and 1, where 0 represents impossibility and 1 represents certainty.
To find the probability of getting a 3 on both rolls of a single die, we can multiply the probabilities of each event.
The probability of getting a 3 on the first roll is 1/6, since there is only one outcome out of six possible outcomes (numbers 1-6) that is a 3.
Similarly, the probability of getting a 3 on the second roll is also 1/6.
To find the probability of both events occurring, we multiply the probabilities together:
(1/6) * (1/6) = 1/36
Therefore, the probability of getting a 3 on the first roll and a 3 on the second roll is 1/36.
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The z-score associated with the 97.5 percent confidence interval is a) 2.160 b) 1.900 c) 2.241 d) 2.744 e) 1.960 f)None of the above
In this question, the z-score associated with the 97.5 percent confidence interval is option e) 1.960.
In statistics, the z-score is used to determine the number of standard deviations a particular value is away from the mean in a normal distribution. The z-score is commonly used in confidence interval calculations, where it corresponds to a certain level of confidence.
The 97.5 percent confidence interval corresponds to a two-tailed test, meaning we need to find the z-score that captures 97.5 percent of the area under the normal distribution curve, with 2.5 percent of the area in each tail.
Looking up the z-score in a standard normal distribution table or using statistical software, we find that the z-score associated with the 97.5 percent confidence interval is approximately 1.960.
Therefore, the correct answer is e) 1.960. This z-score is used when constructing a 97.5 percent confidence interval, which means there is a 97.5 percent probability that the true population parameter lies within the interval calculated using this z-score.
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please help will mark brainliest
Answer:
see below
Step-by-step explanation:
2* (4*8) = (2*4) * 8
This is the associative property of multiplication
Find the indicated length
Answer:
MP= 23
Step-by-step explanation:
I don't know the second one
PLEASE HELP THIS IS SUPER URGENT
Answer:
have no idea lol im terrible at math
An ordered pair is
a) the output (y) value of the relation
b) the input (x) value of the relation
с) a set of points that pair input values with output values
d) x and y values written in the form (x, y)
plzz help
Answer:
B
Step-by-step explanation:
The m to the y can’t equal to m so it’s b
compute σ(n) and µ(n) for each n value below. (a) n = 105 (b) n = 15! (c) n = 79^79
The σ(n) and µ(n) for each n value is (a) Therefore, 105σ(n) of 105 is -1. (b) Hence the sum of divisor of 15! is 1. (c)Therefore,μ(79^79) = μ(79)^79 = (-1)^79 = -1
(a) Compute σ(n) and µ(n) for n = 105σ(n) of 105:
Here we need to find the sum of divisors of 105:Sum of divisors = (1 + 3 + 5 + 7 + 15 + 21 + 35 + 105) = 192μ(n) of 105.
Let us first write down the prime factorization of 105 which is given by105 = 3 × 5 × 7So μ(105) will be given by:μ(105) = (-1)3 = -1
Therefore, 105σ(n) of 105 is -1
(b) Compute σ(n) and µ(n) for n = 15!σ(n) of 15!:
Here we need to find the sum of divisors of 15!:We know that if n = p1^a1 . p2^a2 . … pk^ak
then the sum of divisors will be given by{(1 - p1^(a1+1))/(1 - p1)} . {(1 - p2^(a2+1))/(1 - p2)} … {(1 - pk^(ak+1))/(1 - pk)}
Hence sum of divisors of 15! = {1 + 2 + 4 + 8 + 16 + 32 + 64 + 128} × {1 + 3 + 9 + 27 + 81 + 243 + 729} × {1 + 5 + 25 + 125 + 625} × {1 + 7 + 49 + 343} × {1 + 11 + 121} × {1 + 13 + 169} × {1 + 17 + 289} × {1 + 19 + 361} = 5585458640832840072960000μ(n) of 15!:15! = 2^11 . 3^6 . 5^3 . 7^2 . 11 . 13So μ(15!) = (-1)24 = 1
Hence the sum of divisor of 15! is 1.
(c) Compute σ(n) and µ(n) for n = 79^79σ(n) of 79^79:Here we need to find the sum of divisors of 79^79 which is given by(1 + 79 + 79^2 + ... + 79^79) = (79^80 - 1)/(79 - 1)
Hence σ(79^79) = (79^80 - 1)/78μ(n) of 79^79:Let us first write down the prime factorization of 79 which is given by79 = 79So μ(79) will be given by:μ(79) = (-1)1 = -1
Therefore,μ(79^79) = μ(79)^79 = (-1)^79 = -1
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3. Concert tickets cost R150 each. How many tickets can be bought with R860?
Answer:
At most 5 tickets could be bought.
12 of 18
Save & EXIT
Properties of Operations: Tutorial
Activity
Question 1
Gretchen and her friend Hayley bought three bags of apples and three bunches of bananas from the fruit vendor. Gretchen and Hayley want to
find the total number of pieces of fruit that they bought. Gretchen thinks she should multiply 3 by the number of apples in each bag, X, and add it
to 3 times the number of bananas in each bunch, y, to find the total number of pieces of fruit. Hayley thinks Gretchen should add the number of
apples in each bag, x, to the number of bananas in each bunch, y, and then multiply that sum by 3.
Part A
Write an expression based on Gretchen's method to find the total number of pieces of fruit.
PEE
B
U X X
Font Sizes
AA-
Which property can you apply to Hayley’s expression to show that it is equivalent to Gretchen’s expression
Answer:
3x+3y and distributive property
Step-by-step explanation:
It is given that
Gretchen buys three bags of apples = 3X
Hayley buys three bunches of bananas = 3Y
As it is also mentioned that it first it is multiplied and then it is added
So, the expression for determining the total number of fruit pieces is
3X + 3Y
And, this expression denotes the distributive property in which we multiplied the each variable and then added it
The density of an object is calculated using the formula D=m/v where m
is the object's mass and V is its volume. Gold has a density of 19.3 g/cm^3”. What is
the volume of an amount of gold that has a mass of 96.5 g?
*If y’all can do this and show all the work that would be awesome! I have to show work to my teacher in order for her to grade it and I have a D in her class so please help!*
first answer = brainliest
Answer:
A=28.26 in²
Step-by-step explanation:
We are given the formula for the area of a circle which is:
\(A=\pi r^2\)
Which means:
Area = π*radius of circle²
The radius of a circle is the length from the center of the circle to the edge of the circle.
The image tells us the radius of the circle is 3 in and the questions asks us to use 3.14 for π, therefore...
A=3.14*3²
A=3.14*9
A=28.26 in²
Answer:
28.26 in²Step-by-step explanation:
We know that:
Area of circle = πr²Radius = 3 in.π = 3.14Solution:
πr² = Area of circle=> 3.14 x 3² = Area of circle=> 3.14 x 9 = Area of circle=> 28.26 in² = Area of circleHence, the area of the circle is 28.26 in².
Express the confidence interval 64.4 % < p < 82.4 % in the form of ˆ p ± M E .
The expression of the confidence interval $64.4 \% < p < 82.4 \%$ in the frequency distribution form of ˆ$p±ME$ is given below.
.The data have a mean (M) of 1150 and a standard deviation (SD) of 150, which correspond to a normal distribution.
The midpoint is given by, ˆ$p=\frac{64.4+82.4}{2}=73.4\%$.Now, subtracting the lower limit from the midpoint gives,$73.4\%-64.4\%=9.0\%$Similarly, subtracting the midpoint from the upper limit gives, $82.4\% -73.4\% =9.0\%$ Therefore, the margin of error is given by $ME=9.0\%$Hence, the confidence interval in the form of ˆ$p±ME$ is $\boxed{73.4\%±9.0\%}$.
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If 400 m long fencing wire is required to surround a square flower garden 2 times, find length of the garden. -Maths Links Book 6 Approved by CD
Answer:
garden=400/2
=200
4× side = perimeter=200
So, =200/4
=50 m.
Step-by-step explanation:
Answer:
Length of garden is 50 m.
Step-by-step explanation:
Fence required for 1 time,
→ 400 ÷ 2
→ 200 m
Perimeter of square formula is,
→ P = 4 × L
Now length of the garden will be,
→ P = 4 × L
→ 200 = 4L
→ 4L = 200
→ L = 200/4
→ [ L = 50 m ]
Hence, length of garden is 50 m.
Jim plays on his community basketball team, the Raging Rabbits. During their big game against the Porcupines, the Rabbits score 36 points in the first half. They add to their score in the second half. In all, the Rabbits score 81 points. Use an equation for to find the number of points the Rabbits score in the second half. points
Answer:
Step-by-step explanation:
41+x=81
x=40
The rabbits score 40 points in the second half.
Answer:
55
Step-by-step explanation:
For each of the following assertions, state whether it is a legitimate statistical hypothesis and why:
a. H: δ>100
b. H: x=45
c. H: s<.20
d. H: δ1/δ2 <1
e. H: X-Y=5
f. H: גּ<.01
where λ is the parameter of an exponential distribution used to model component lifetime
a. H: δ>100 is a legitimate statistical hypothesis because it is a statement about a population parameter (δ) and it is testable using statistical methods.
b. H: x=45 is a legitimate statistical hypothesis because it is a statement about a population parameter (x) and it is testable using statistical methods.
c. H: s<.20 is a legitimate statistical hypothesis because it is a statement about a population parameter (s) and it is testable using statistical methods.
d. H: δ1/δ2 <1 is a legitimate statistical hypothesis because it is a statement about a population parameter (δ1 and δ2) and it is testable using statistical methods.
e. H: X-Y=5 is a legitimate statistical hypothesis because it is a statement about a population parameter (X and Y) and it is testable using statistical methods.
f. H: גּ<.01 is a legitimate statistical hypothesis because it is a statement about a population parameter (λ) and it is testable using statistical methods, with the parameter being the rate parameter of an exponential distribution used to model component lifetime.
Here are the answers for each assertion:
a. H: δ>100 - This is a legitimate statistical hypothesis because it states a specific direction for the population parameter (delta).
b. H: x=45 - This is not a legitimate statistical hypothesis because it refers to a sample statistic (x) rather than a population parameter.
c. H: s<.20 - This is not a legitimate statistical hypothesis because it refers to a sample statistic (s, sample standard deviation) instead of a population parameter.
d. H: δ1/δ2 <1 - This is a legitimate statistical hypothesis because it specifies a relationship between two population parameters (delta1 and delta2).
e. H: X-Y=5 - This is not a legitimate statistical hypothesis because it refers to sample statistics (X and Y) rather than population parameters.
f. H: λ<.01 - This is a legitimate statistical hypothesis because it states a specific direction for the population parameter (lambda) related to the exponential distribution for component lifetime.
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