Answer:
The larger share is $450.
Step-by-step explanation:
\(\frac{3}{5} =\frac{3x}{5x} \\\\3x-the smaller share\\5x-the larger share\\3x+5x=8x\\8x-money to split\\8x=720 /:8\\x=90\\5x=5*90=450\)
Find the form of the natural response of systems with the following transfer functions: T(s)= 3s-12/s^3+4s^2+13s
The natural response of the system is given by \(n(t) = A_1 e^{-2t} \sin(3t + \varphi) + A_2 e^{-2t} \cos(3t + \varphi)\),
The transfer function of a system describes the relationship between the input and output signals. It is defined as the Laplace transform of the system's impulse response. In this case, the transfer function is given as \(T(s) = \frac{3s - 12}{s^3 + 4s^2 + 13s}\).
To find the natural response of the system, we perform partial fraction decomposition. By decomposing the transfer function, we obtain \(T(s) = \frac{A}{s} + \frac{Bs + C}{s^2 + 4s + 13}\).
Multiplying both sides by \(s(s^2 + 4s + 13)\), we get \(3s - 12 = A(s^2 + 4s + 13) + (Bs + C)s\).
By substituting specific values of \(s\), we can determine the coefficients \(A\), \(B\), and \(C\).
Solving for \(A\), we substitute \(s = 0\) and obtain \(A = -\frac{12}{13}\).
For \(C\), we substitute \(s = -2\) and find \(C = -\frac{6}{13}\).
Finally, substituting \(s = 2\), we find \(B = \frac{9}{13}\).
Therefore, the transfer function \(T(s)\) can be written as \(T(s) = -\frac{12}{13s} + \frac{9s - 6}{s^2 + 4s + 13}\).
In summary natural response of the system with the given transfer function is characterized by the equation \(n(t) = A_1 e^{-2t} \sin(3t + \varphi) + A_2 e^{-2t} \cos(3t + \varphi)\).
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solving systems equations: substitution
y=6x+5
y=4x+5
Answer:
y=6x+5 →equation 1
y=4x+5 → equation 2
you can either substitute equation 1 in 2 or equation 2 in 1
substituting equation 1 in 2,
y = 4x + 5
6x + 5 = 4x + 5
6x - 4x = 5 - 5
2x = 0
x = 0/2
x = 0
substituting x = 0 in equation 1, (to get y)
y = 6x + 5
y = 6(0) + 5
y = 0 + 5
y = 5
hope it helps you!!
The coefficient of variation is a better measure of stand-alone risk than standard deviation because it is a standardized measure of risk per unit; it is calculated as the
The coefficient of variation is a better measure of stand-alone risk than standard deviation because it is a standardized measure of risk per unit.
The coefficient of variation is a measure of relative risk that compares the standard deviation of a dataset to its mean. It is calculated as the ratio of the standard deviation to the mean, multiplied by 100 to express it as a percentage. The formula for the coefficient of variation (CV) is as follows:
CV = (Standard Deviation / Mean) * 100
The coefficient of variation provides a standardized measure of risk per unit of mean. It is particularly useful when comparing the risk of different datasets or investments that have different scales or units of measurement. By dividing the standard deviation by the mean, the coefficient of variation allows for a comparison of the relative variability or riskiness of different datasets or investments.
In this sense, the coefficient of variation is considered a better measure of stand-alone risk than the standard deviation alone because it takes into account the magnitude of the mean. It provides a way to assess and compare the risk of different datasets or investments in a standardized manner, regardless of their scales or units of measurement.
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Please help me!
A
B
C
D
How can i learned maths hardly?
Learning math can be a challenging task, but with persistence, hard work, and effective study strategies, it is definitely possible to improve your math skills.
Some tips that may help you learn maths quickly and efficientlyStart with the basics: Make sure you have a good foundation in basic math concepts before moving on to more advanced topics. Practice basic arithmetic, fractions, decimals, and percentages until you feel comfortable with them.
Focus on understanding, not just memorizing: Math is not just about memorizing formulas and equations; it's about understanding how and why they work. Focus on understanding the underlying concepts and principles.
Practice regularly: The more you practice, the better you will get. Try to set aside some time each day to practice math problems. This will help you build your skills and improve your understanding.
Use multiple resources: Don't just rely on one textbook or resource. Use multiple resources such as online tutorials, videos, practice problems, and textbooks to get a well-rounded understanding of the topic.
Seek help when needed: Don't hesitate to ask for help if you are struggling with a particular topic. You can reach out to a teacher, tutor, or online community for help.
Stay motivated: Math can be challenging, but it's important to stay motivated and not give up. Keep a positive attitude, celebrate your successes, and remember that every mistake is an opportunity to learn and grow.
Remember that learning math takes time and effort, so don't get discouraged if you don't see immediate results. With persistence and hard work, you can become proficient in math.
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PLEASE HELP 75 POINTS
Answer:
Volume of larger box: 480
Length of small box: 5
Width of small box: 4
Height of small box: 3
Volume of small box: 60
Ratio of small box to large box: 1/8
When multiplying units, use the same principle that you use for multiplying fractions. In addition, ifone unit is in the numerator and the identical unit is in the denominator, they cancel each other out (to essentially equal 1). Any remaining units are used in the answer. ( centimheter) ( centimeter meter )=1 meter = meter You can also multiply several units together at once using the same principle as for fractions containing numbers. ( second centipheters )( centimeter meter )( meters kilopreter )( kilopeter megameter )= second megameter It is very important to note that if a unit appears only once in the numerator but more than once in the denominator, we can only cancel one of the unit expressions in the denominator. Think of this concept in terms of fractions. If the number 4 is in the numerator, and two 45 are in the denominator of different fractions, we only cancel out one of the 45 on the bottom, not both. (54)(43)(41)=(5∗4)(3∗1)=203=0.15 Evaluate the following unit expression. Enter the resulting units as your answer. Do not abbreviate the units and do not use parentheses. Parentheses mean multiplication. ( kilogram )( kilogram grams )( gram milligrams )= Evaluate the following unit expression. Enter the resulting units as your answer. Do not obbreviate the units and do not use parentheses. Parentheses mean multiplication. ( mole )( mole grams )( gram liter )= Evaluate the following unit expression. Enter the resulting units as your answer. Do not abbreviate the units. Enter units exactly as they anpear in the problem. Use ^ for exponents (so ft∧2forft2 ). Use " for multiplication and / for division. Do not include any spaces and not use parentheses. Parentheses mean multiplication. (mL)(cmmg)( mLcm3)=(mL)(cmmg)( mLcm∗ cm∗ cm)= Evaluate the following unit expression. Enter the resulting units as your answer. Do not abbreviate the units. Enter units exactly as they annear in the problem. Use ∧ for exponents ( so ft∧2for22). Use " for multiplication and / for division. Do not include any spaces and not use parentheses. Parentheses mean multiplication. (f2g)(mLft)(gmL)=(ft∗ftg)(mLft)(gmL)=
The resulting units are kilograms grams milligrams, mole grams liter, ft^2g mL ft gmL
To evaluate the given unit expressions, we can apply the rules of multiplying units similar to multiplying fractions.
(kilogram)(kilogram grams)(gram milligrams):
The units cancel out as follows:
(kilogram)(kilogram grams)(gram milligrams) = (kilogram)(grams)(milligrams)
Therefore, the resulting units are kilograms grams milligrams.
(mole)(mole grams)(gram liter):
The units cancel out as follows:
(mole)(mole grams)(gram liter) = (mole)(grams)(liter)
Therefore, the resulting units are mole grams liter.
(mL)(cmmg)(mLcm3):
The units cancel out as follows:
(mL)(cmmg)(mLcm3) = (mL)(cm mg)(cm^3)
Therefore, the resulting units are mL cm mg cm^3.
(f^2g)(mLft)(gmL):
The units cancel out as follows:
(f^2g)(mLft)(gmL) = (ft^2g)(mLft)(gmL)
Therefore, the resulting units are ft^2g mL ft gmL.
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What does the function f (14) = 11 mean?
y = f(x)
so f(14) = 11 means the input x = 14 leads to the output y = 11
The point (x,y) = (14,11) is on the f(x) curve.
Function f(14) = 11 implies that the outcome of a function at x = 14 the value of the function is 11.
Given that,
To specify what the function f (14) = 11 means.
Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.
Here,
f( 14 ) = 11
f( 14 ) = f( x )
x = 14
f( x ) = 11
Implies that,
f(x) = y
is function, when x = 14 the function gives y = 11 ,,means that for x = 14 the outcome of the function is 14.
Thus, function f(14) = 11 implies that the outcome of a function at x = 14 the value of the function is 11.
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PLEASE ANSWER THIS ASAP !!!!!!!!
Answer:43
Step-by-step explanation:
YOUR WECOME!!!!!
If that isnt the answer because i evaluated, try t=43/h :)
Solve dy/dx=1/3(sin x − xy^2), y(0)=5
The general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is: y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5
To solve this differential equation, we can use separation of variables.
First, we can rearrange the equation to get dy/dx on one side and the rest on the other side:
dy/dx = 1/3(sin x − xy^2)
dy/(sin x - xy^2) = dx/3
Now we can integrate both sides:
∫dy/(sin x - xy^2) = ∫dx/3
To integrate the left side, we can use substitution. Let u = xy^2, then du/dx = y^2 + 2xy(dy/dx). Substituting these expressions into the left side gives:
∫dy/(sin x - xy^2) = ∫du/(sin x - u)
= -1/2∫d(cos x - u/sin x)
= -1/2 ln|sin x - xy^2| + C1
For the right side, we simply integrate with respect to x:
∫dx/3 = x/3 + C2
Putting these together, we get:
-1/2 ln|sin x - xy^2| = x/3 + C
To solve for y, we can exponentiate both sides:
|sin x - xy^2|^-1/2 = e^(2C/3 - x/3)
|sin x - xy^2| = 1/e^(2C/3 - x/3)
Since the absolute value of sin x - xy^2 can be either positive or negative, we need to consider both cases.
Case 1: sin x - xy^2 > 0
In this case, we have:
sin x - xy^2 = 1/e^(2C/3 - x/3)
Solving for y, we get:
y = ±√[(sin x - 1/e^(2C/3 - x/3))/x]
Note that the initial condition y(0) = 5 only applies to the positive square root. We can use this condition to solve for C:
y(0) = √(sin 0 - 1/e^(2C/3)) = √(0 - 1/e^(2C/3)) = 5
Squaring both sides and solving for C, we get:
C = 3/2 ln(1/25)
Putting this value of C back into the expression for y, we get:
y = √[(sin x - e^(x/2)/25)/x]
Case 2: sin x - xy^2 < 0
In this case, we have:
- sin x + xy^2 = 1/e^(2C/3 - x/3)
Solving for y, we get:
y = ±√[(e^(2C/3 - x/3) - sin x)/x]
Again, using the initial condition y(0) = 5 and solving for C, we get:
C = 3/2 ln(1/25) + 2/3 ln(5)
Putting this value of C back into the expression for y, we get:
y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x]
So the general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is:
y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5
y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x], if sin x - xy^2 < 0 and y(0) = 5
Note that there is no solution for y when sin x - xy^2 = 0.
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The top eight hitters in a softball league have batting averages of .373 , .360 , .321 , 321 , .320 , .312 , .311 , and .311. Find the mean of the batting averages.
The mean of the batting averages is 0.341125.
Mean is used to summarize a set of data, frequently to help determine the overall significance of the data set.
To find the mean of the batting averages, we need to sum up all the batting averages and divide by the total number of players.
Batting averages: .373, .360, .321, .321, .320, .312, .311, .311
Sum of batting averages = .373 + .360 + .321 + .321 + .320 + .312 + .311 + .311
Sum of batting averages = 2.729
Now, we divide the sum by the total number of players, which is 8:
Mean = Sum of batting averages / Total number of players
Mean = 2.729 / 8
Calculating the mean:
Mean ≈ 0.341125
The mean of the batting averages is approximately 0.341125.
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Need to generate a recursive formula to the story problem given below. Give the recursive equation at the top of your answer (do not forget your base case(s)) and then show your thought process after. Question: How many n-letter "words" can be created from an unlimited supply of a’s, b’s, and c’s, if each word MUST contain an even number of a’s?
The recursive formula for the given problem is W(n) = W(n-1) + 2 * W(n-1), with the base case W(0) = 1. This formula calculates the number of n-letter "words" that can be created from an unlimited supply of 'a's, 'b's, and 'c's,
To derive the recursive formula, we consider two cases for the first letter of the word: either it is an 'a' or it is not. If the first letter is 'a', we need to ensure that the remaining (n-1) letters form a word with an even number of 'a's. Therefore, the number of words in this case is equal to W(n-1), as we are recursively solving for the remaining letters.
If the first letter is not 'a', we have the freedom to ch
oose from 'b' or 'c'. In this case, we have two options for each of the remaining (n-1) letters, resulting in 2 * W(n-1) possibilities. By summing these two cases, we obtain the recursive formula W(n) = W(n-1) + 2 * W(n-1), which calculates the total number of n-letter words satisfying the given criteria.
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3. Solve your equation to find the distance Jane’s trainer bikes. Show your work.
4. How much farther does Jane travel than her trainer?
(my previous answers so this will make sense)
1. The total distance jane bikes and runs is 28 miles.
2. Janes trainer bikes a distance of 20 miles.
Jane travels 8 miles much farther than her trainer. The solution is obtained using arithmetic operations.
What are arithmetic operations?
By combining operands with one arithmetic operator, an arithmetic operation is given. The built-in functions add, subtract, divide, and multiply additionally allow for the specification of arithmetic operations.
3. Using pythagoras theorem, we get the equation as D² = 12² + 16².
⇒D² = 144 + 256
⇒D² = 400
⇒D = √400
⇒D = 20
4. Jane has traveled 28 miles in total whereas her trainer has traveled 20 miles.
So, the difference is 28-20= 8 miles
Hence, Jane travels 8 miles much farther than her trainer.
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11. f(x) = 3
Domain:
Range:
x-intercept:
y-intercept:
Answer:
domain: (-∞,∞)
range: y=3
no x intercept
y intercept = (0,3)
A product has a selling price of $10 per unit, variable expenses of $6 per unit and total fixed costs of $35,000. If 10,000 units are sold, net operating income will be $(1). (Enter your answer as a whole number.)
The net operating income will be $ 5000.
Net Operating Income:The profitability of real estate assets that produce income is evaluated using a formula known as net operating income (NOI). NOI is the total revenue from the asset less all running costs that are deemed to be absolutely required.
Here we have
A product has a selling price of $10 per unit, variable expenses of $6 per unit, and total fixed costs of $35,000.
In total 10,000 units are sold
The net operating income will be computed by Subtracting all expenditures from all money collected on the product.
Net operating income = ($10 - $6) × 10000 - $ 35000
= ($10 - $6) × 10000 - $ 35000
= $ 40000 - $ 35000
= $ 5000
Therefore,
The net operating income will be $ 5000.
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Jaclyn estimates that the square root of 50 in the following way:
\(\sqrt{50\) = \(2 \sqrt{25\) = 2 * 5 = 10
Explain why her reasoning is incorrect. Please use complete sentences.
\(\sf\purple{The\: square\: root \:of \:50\: is\: 5√2.}\)
\(\large\mathfrak{{\pmb{\underline{\blue{Step-by-step\:explanation}}{\blue{:}}}}}\)
Error made by Jaclyn ⤵
\( \sqrt{50} \)
\(\sf\red{=\:2√25}\) ❌
Correct way to solve it ⤵
\( \sqrt{50} \\ \\ = \sqrt{5 \times 5 \times 2} \\ \\ = \sqrt{ {5}^{2} \times 2} \\ \\ = \sqrt{ {5}^{2} } \times \sqrt{2} \\ \\ = 5 \sqrt{2} \\ \\ (∵ \sqrt{ {a}^{2} } = a)\)
\(\bold{ \green{ \star{ \orange{Mystique35}}}}⋆\)
What is a replacement for 3/4 cup?.
Using Cooking measurements,
The value replacement for 3/4 cup is = 36 teaspoons or 12 tablespoons.
Cooking Measurements :
Calculate and determine the specific amounts of ingredients required using standard measuring equipment.
A measuring spoon, measuring cup, or measuring utensil.
Measuring Spoons come in a variety of sizes and materials. The smallest set of spoons measure smudges, pinches and dashes. Other sets include tsp (tsp) and tsp (tbsp)
we have given 3/4 cup and we want to replace it
Using the cooking measurement chart ,
1 cup = 16 tablespoons or 48 teaspoons
1/2 cup = 8 tablespoons or 24 teaspoons
we have 3/4 cup then
3/4 cup = 1 cup - 1/4 cup
1/4 cup = 4 tablespoons or 12 teaspoons
then , 3/4 cup = 16 tablespoons - 4 tablespoons
= 12 tablespoons or
3/4 cup = 48 teaspoons - 12 teaspoons
= 36 teaspoons
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Which equation correctly applies the distributive property?
−1.5⋅(6⋅1.25)=(−1.5⋅6)⋅1.25
70+2.028=(70⋅2)+(70⋅0.02)+(70⋅0.008)
(0.7⋅0.7)+(0.7⋅0.9)+(0.7⋅0.2)=0.7⋅(0.7+0.9+0.2)
−2.5⋅0.6⋅5.8=−2.5⋅5.8⋅0.6
i dont know ethrreer
Step-by-step explanation:
Answer:
Step-by-step explanation:The distributive property dictates that:
a(b + c) = ab + ac
Thus,
(0.7 x 0.7) + (0.7 x 0.9) + (0.7 x 0.2)
= 0.7(0.7 + 0.9 + 0.2)
follows the distributive property. The third option is correct.
explain how overflow makes two’s complement numbers act negative.
overflow in two's complement arithmetic causes the wrap-around of the most significant bit, resulting in the representation of positive numbers as negative numbers.
In two's complement representation, numbers are represented using a fixed number of bits. The most significant bit (MSB) is reserved to indicate the sign of the number, where 0 represents a positive number and 1 represents a negative number.
Overflow occurs in two's complement arithmetic when the result of an operation exceeds the range that can be represented with the available number of bits.
When overflow occurs, the result is truncated or wrapped around to fit within the bit representation. This wrapping around effectively causes the MSB to flip its value, changing the sign of the number. As a result, the number that was intended to be positive becomes negative in the two's complement representation.
For example, consider an 8-bit two's complement representation. The range for a signed 8-bit number is -128 to +127. If we add 1 to the maximum positive value of 127, overflow occurs because the result exceeds the range. The binary representation of 127 is 01111111, and adding 1 results in 10000000. Since the MSB changed from 0 to 1, the number is interpreted as -128 in two's complement representation.
In summary, overflow in two's complement arithmetic causes the wrap-around of the most significant bit, resulting in the representation of positive numbers as negative numbers.
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A project has the following cost, benefit data, and life probability distribution. Compute the conventional \( \mathrm{B} / \mathrm{C} \) ratio using the expected EUAC. (10 Points)
The conventional B/C ratio using the expected EUAC (Equivalent Uniform Annual Cost) can be computed as 1 / EUAC
To calculate the conventional B/C ratio using the expected EUAC, we need to determine the present value of costs and benefits over the project's life and then compare them.
Cost Data:
Year 1: $10,000
Year 2: $8,000
Year 3: $6,000
Benefit Data:
Year 1: $15,000
Year 2: $12,000
Year 3: $9,000
Life Probability Distribution:
Year 1: 0.2
Year 2: 0.5
Year 3: 0.3
To calculate the present value of costs and benefits, we multiply each cash flow by the respective probability and discount it to present value. Assuming a discount rate of r%, the present value (PV) can be calculated using the formula:
PV = Cash Flow / (1 + r)^n
where n is the year of the cash flow.
Calculating the present value of costs:
PV(Costs) = ($10,000 / (1 + r)^1) + ($8,000 / (1 + r)^2) + ($6,000 / (1 + r)^3)
Calculating the present value of benefits:
PV(Benefits) = ($15,000 / (1 + r)^1) + ($12,000 / (1 + r)^2) + ($9,000 / (1 + r)^3)
The expected EUAC can be calculated as the sum of PV(Costs) divided by the sum of PV(Benefits), considering the probabilities:
EUAC = (PV(Costs) * 0.2 + PV(Costs) * 0.5 + PV(Costs) * 0.3) / (PV(Benefits) * 0.2 + PV(Benefits) * 0.5 + PV(Benefits) * 0.3)
Finally, the conventional B/C ratio is obtained by taking the inverse of the EUAC:
B/C ratio = 1 / EUAC
The conventional B/C ratio using the expected EUAC for the given cost, benefit data, and life probability distribution can be computed using the provided calculations. This ratio allows for a comparison between the present value of costs and benefits over the project's life, considering the probability distribution.
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Can Anyone help me with this one?
Answer:
1. D
2. A
3. B
4. C
5. i am not sure
Step-by-step explanation:
Hope This Helps!!!
The function a(b) relates the area of a trapezoid with a given height of 12 and
one base length of 9 with the length of its other base.
It takes as input the other base value, and returns as output the area of the
trapezoid.
2.b19
a(b)-12..
Which equation below represents the inverse function b(a), which takes the
trapezoid's area as input and returns as output the length of the other base?
A. b(a)-2-9
B. b(a)-+9
OC. b(a)- +6
OD. b(a)-9-6
The inverse function of \(A(b) = 12 \cdot \frac{b + 9}2\) is b(a) = a/6 - 9
How to determine the inverse function?The function is given as:
\(A(b) = 12 \cdot \frac{b + 9}2\)
Divide 12 by 2
\(A(b) = 6 \cdot (b + 9)\)
Rewrite the function as
\(a = 6 \cdot (b + 9)\)
Divide both sides by 6
a/6 = b + 9
Subtract 9 from both sides
b = a/6 - 9
Express as a function
b(a) = a/6 - 9
Hence, the inverse function of \(A(b) = 12 \cdot \frac{b + 9}2\) is b(a) = a/6 - 9
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solve using suitable property -2/3 + 5/7 + -8/9 + 3/14
Answer:
\(\dfrac{-79}{126}\)
Step-by-step explanation:
The given expression is :
\(\dfrac{-2}{3}+\dfrac{5}{7}+\dfrac{-8}{9}+\dfrac{3}{14}\)
The LCM of 3,7,9 and 14 is 126
So,
\(\dfrac{-2}{3}+\dfrac{5}{7}+\dfrac{-8}{9}+\dfrac{3}{14}=\dfrac{42(-2)+18(5)+14(-8)+9(3)}{126}\\\\=\dfrac{-79}{126}\)
So, the value of the given expression is equal to \(\dfrac{-79}{126}\).
The set of ordered pairs a where
t is the time in seconds after
someone jumps out of a plane at
4000 meters to go skydiving, and d
is the displacement above the
ground
I need to find the domain and Range.
Answer: Domain is \([0,\infty)\) and range is [0,4000].
Step-by-step explanation:
It is given that, the set of ordered pairs (t,d), where
t = the time in seconds after someone jumps out of a plane at 4000 meters to go skydiving
d = is the displacement above the ground.
It means t is independent variable and it is represented on the x-axis.
d is dependent variable and it is represented on the y-axis.
We need to find the domain and Range.
Domain is the set of input values.
Here, input is time and time can not be negative.
Domain \(=0\leq t=[0,\infty)\)
Range is the set of output values.
Here, output is displacement above the ground which can not be negative or more than 4000 meters.
Range \(=0\leq d\leq 4000=[0,4000]\)
Therefore, domain is \([0,\infty)\) and range is [0,4000].
evaluate f(-5) if f(x) = -2 - 12
Answer:
f( -5) -= f- 5
x ∈ ℝ
Step-by-step explanation:
Convert DAD base16 to binary
Answer:
D = 01000100
A = 01100001
D = 01000100
B = 01000010
A = 01100001
S = 01110011
E = 01100101
1 = 00110001
6 = 00110110
simplify
3a + 2b - 8a + b
Answer:
-5a+3b
Step-by-step explanation:
just adding and subtracting like terms
Answer:
3b-5a
Step-by-step explanation:
hope this helps:)
State the amplitude, period, phase shift, and vertical shift of the function kt=cos2pit/3
Answer:
The given function is k(t) = cos(2πt/3).
The general form of a cosine function is A*cos(Bx - C) + D, where:
A is the amplitudeB is the frequency (which is related to the period)C is the phase shiftD is the vertical shiftComparing this form to the given function, we can see that:
The amplitude of k(t) is A = 1, since the maximum value of the cosine function is 1 and the minimum value is -1.The frequency of k(t) is B = 2π/3, since the argument of the cosine function is 2πt/3. The frequency is related to the period T by the formula T = 2π/B. Therefore, the period of k(t) is T = 3.The phase shift of k(t) is C = 0, since there is no horizontal shift in the argument of the cosine function.The vertical shift of k(t) is D = 0, since the average value of the cosine function over one period is zero.Therefore, the amplitude of k(t) is 1, the period of k(t) is 3, the phase shift of k(t) is 0, and the vertical shift of k(t) is 0.
A simulated game of chess is programmed between two computers. The game is supposed to be biased in favor of player B winning 4 out of 5 times. Which is the most suspicious set of outcomes of 30 games played between the two computers?AABABBBABBBBBBBBABBBABBBBBBBBAABBABBAABBBBBABBBBBBBBBBBBBABBABBABABABABBABABABABABABABABAAABBABBBABBBBBBBBABBBABBBBBBBBB
A simulation game attempts to copy various activities from real life in the form of a game for various purposes such as training, analysis, prediction, or entertainment.
How will outcome be decided?The most suspicious set of outcomes for a simulated game of chess that is supposed to be biased in favor of player B winning 4 out of 5 times would be if player B won all 30 games. This outcome would be highly unlikely if the game was truly random and the bias towards player B was accurate. Other suspicious outcomes could include player B winning 29 out of 30 games or player B winning 28 out of 30 games with a high margin of victory in each game.
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Convert the given amount to the given unit.
6 yd; ft
Answer:
Step-by-step explanation:
Convert the given amount to the given unit.
6 yd; ft