We need the volume of 1.88 mL of 1.40 M SrCl2 to prepare 525 mL of 5.00 mM SrCl2 solution.
To answer we need to use the formula:
C1V1 = C2V2
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
We are given that the initial concentration (C1) is 1.40 M and we want to prepare 525 mL of a solution with a final concentration (C2) of 5.00 mM (millimolar). To convert mM to M, we need to divide by 1000, so the final concentration in M is 0.005 M.
Using the formula above, we can solve for the initial volume (V1):
C1V1 = C2V2
1.40 M x V1 = 0.005 M x 525 mL
V1 = (0.005 M x 525 mL) / 1.40 M
V1 = 1.88 mL
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A solution containing 572. 0ml of 0. 6300mhcl is diluted to a volume of 1. 000l. what is the ph of this solution?
The pH of the solution is approximately 0.444.
To find the pH of the solution, we need to first determine the concentration of the diluted solution.
Given:
Initial volume (V1) = 572.0 mL
Initial concentration (C1) = 0.6300 M
Final volume (V2) = 1.000 L
We can use the dilution formula to find the concentration of the diluted solution:
C2 = (C1 * V1) / V2
Substituting the given values:
C2 = (0.6300 M * 572.0 mL) / 1.000 L
C2 = 0.3604 M
Now, we can use the formula for calculating pH, which is given by:
pH = -log[H+]
Since HCl is a strong acid, it completely dissociates into H+ ions. Thus, the concentration of H+ ions in the solution is equal to the concentration of the HCl.
Therefore, the pH of the solution is:
pH = -log(0.3604)
pH ≈ 0.444
So, the pH of the solution is approximately 0.444.
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two objects will experience an electric force of attraction when they have ___
Answer:
Electrostatic charge....
A certain acid, HA, has a pKa of 6. What is the pH of a solution made by mixing 0.20 mol of HA with 0.30 mol of NaA? b. A certain acid, HA, has a pKa of 6. In the previous problem, you considered a solution made by mixing 0.20 mol of HA with 0.30 mol of NaA. What, now, would the pH be if 0.05 mol of NaOH were added to that solution? If you need to, assume the solution is at 25 oC, where the Kw is 1.0x10-14. c. A certain acid, HA, has a pKa of 6. What is the pH of a solution made by mixing 200 mL of 0.20 M HA (aq) with 300 mL of 0.30 M NaA (aq)? If you need to, assume the solution is at 25 oC, where the Kw is 1.0x10-14. d. A certain acid, HA, has a pKa of 6. In the previous problem, you considered a solution made by mixing 200 mL of 0.20 M HA (aq) with 300 mL of 0.30 M NaA (aq). What, now, would the pH be if 10 mL of 0.50 M HCl were added to that solution? If you need to, assume the solution is at 25 oC, where the Kw is 1.0x10-14.
In order to determine the pH in the given scenarios, several calculations and considerations need to be taken into account.Firstly, the Henderson-Hasselbalch equation can be used, which relates the pH of a solution to the pKa of the acid and the ratio of its conjugate base to the acid. This equation is pH = pKa + log([A-]/[HA]), where [A-] is the concentration of the conjugate base and [HA] is the concentration of the acid.
What are the calculations and considerations involved in determining the pH in the given scenarios?
The first problem asks for the pH of a solution made by mixing 0.20 mol of acid HA with 0.30 mol of its conjugate base NaA. The pH can be calculated using the Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]). Given that the pKa is 6, we can plug in the values and solve for the pH.
The second problem asks for the pH after adding 0.05 mol of NaOH to the previous solution. Since NaOH is a strong base, it will react with the acid HA and form water.
The amount of NaOH added is small compared to the amount of acid, so we can assume that the acid will be fully neutralized. We can calculate the resulting concentration of the acid and its conjugate base and use the Henderson-Hasselbalch equation to find the new pH.
The third problem involves mixing 200 mL of 0.20 M HA with 300 mL of 0.30 M NaA. We need to calculate the concentrations of the acid and its conjugate base after mixing, and then use the Henderson-Hasselbalch equation to find the pH.
The fourth problem asks for the pH after adding 10 mL of 0.50 M HCl to the previous solution. Since HCl is a strong acid, it will completely dissociate and increase the concentration of the acid HA.
We need to calculate the new concentrations of the acid and its conjugate base and use the Henderson-Hasselbalch equation to find the new pH.
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Which of the following statements are true? Significant figures in a measurement are all measured digits, and one estimated digit None of the above Significant figures communicate the level of precision in measurements Significant figures are an indicator of the certainty in measurements
Answer: Significant figures in a measurement are all measured digits, and one estimated digit
Significant figures communicate the level of precision in measurements Significant figures are an indicator of the certainty in measurements.
Explanation:
Significant figures : The figures in a number which express the value or the magnitude of a quantity to a specific degree of accuracy or precision is known as significant digits.
The significant figures of a measured quantity are defined as all the digits known with certainty and the first uncertain or estimated digit.
Rules for significant figures:
1. Digits from 1 to 9 are always significant and have infinite number of significant figures.
2. All non-zero numbers are always significant.
3. All zero’s between integers are always significant.
4. All zero’s preceding the first integers are never significant.
5. All zero’s after the decimal point are always significant.
The true statements are
Significant figures in measurement are all measured digits, and one estimated digit
Significant figures communicate the level of precision in measurements Significant figures are an indicator of the certainty in measurements.
The following information should be considered:
The figures in a number that express the value or the magnitude of a quantity is known as significant digits.The significant figures of a measured quantity refers to all the digits known with certainty.Learn more: https://brainly.com/question/1979431?referrer=searchResults
Other than carbon being relatively small, what is another reason that carbon can form so many compounds?
Other than carbon being relatively small, another reason carbon can form so many compounds is its ability to form stable covalent bonds with other atoms, including itself.
Carbon possesses a unique property known as tetravalency, meaning it can form up to four covalent bonds with other atoms. This ability arises from carbon's atomic structure, specifically its electron configuration with four valence electrons in the outermost energy level.
By sharing electrons through covalent bonds, carbon can achieve a stable configuration with a complete octet of electrons.
This tetravalent nature allows carbon to form bonds with a wide range of elements, including hydrogen, oxygen, nitrogen, and many others. Carbon atoms can also bond with each other to form long chains or ring structures, resulting in the formation of complex organic compounds. Additionally, carbon can form double or triple bonds, further expanding its bonding possibilities.
The combination of carbon's small size and its tetravalency provides carbon atoms with a remarkable versatility, enabling them to participate in numerous chemical reactions and form an extensive array of compounds, including the diverse molecules found in living organisms.
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Which is best option?
Answer:
D
Explanation:
"Wash thoroughly (15 minutes) with water using nearest deluge shower or hand/spray unit. Remove any overlying clothing that may retain the chemical and prevent thorough washing of the skin. Depending on the chemical, additional medical treatment may be required."
- G oogle
1. Consider NH3.If it dissolves in water(i) NH3 + H20 + NHẤ4+ H2O(ii)NH3 + H2O → NH+3 + OH-(iii) NH3 + H2O + NH+4+ OH-(iv) NH3 + H2O → NH+4+ OH-Which represents the dissolution of NH3 in water(a) i(b) ii (c) iii (d) iv (e) iii and iv2. HOA2+H20 . → H3O+ + OA-CIn this reaction:(i) OA c is the conjugate base of H2O(ii)OA-c is the conjugate base of HOAc (iii) H3O+ is theсconjugate base of HOA.(iv) H3O+ is the conjugate acid of H2O(a) i(b) ii (c) iii (d) iv (e) none3. Arrange the following according to increasing acid strength(i) Ka= 2.5 + 10-15(ii) Ka= 9.0 + 10-9(iii) pKa= 7.5(iv) % dissociation =100(a) iv, iii, ii, i2(b) ii, I, iii, iv(c) i, iii, iv, ii(d) i, ii, iii, iv(e) iii, iv, ii, i2
1. Ammonia is a colorless gas with a chemical formula of NH3, when it comes in contact with water, it will be transformed into Ammonium ion and it will produce one hydroxide ion, and this is why Ammonia will present a more basic (pH) behavior, the reaction that represents this behavior is:
NH3 + H2O -> NH4+ + OH-
Number 4 is the only one that represents it well
Number 3 has the same reaction but since there is a plus sign instead of an arrow, I consider it wrong.
How do we solve this question? I found B answer key says A
First, we write the reaction and balance it:
HNO2 (aq) + NH3 (aq) = NH4+ + NO2- (Balanced)
Data:
50 mL of 0.2 M HNO2
50 mL of 0.2 M NH3
In total, we have 100 mL, therefore, this solution between HNO2 and NH3 will be diluted in half. I mean: The concentration of HNO2 and NH3 will be 0.10 M
HNO2 (aq) + NH3 (aq) = NH4+ + NO2-
Initial 0.10 M 0.10 M 0 0
reacts -x -x +x +x
Equilibrium 0.10-x 0.10-x +x +x
Now, we write Kc:
\(\begin{gathered} Kc\text{ = }\frac{\lbrack NH4+\rbrack\lbrack NO2-\rbrack}{\lbrack HNO2\rbrack\lbrack NH3\rbrack}=\frac{x^2}{(0.10-x)^2} \\ 1x10^6=\frac{x^2}{(0.10-x)^2} \\ \sqrt{1x10^6}=\text{ }\lvert{\frac{x}{(0.10-x)}}\rvert \\ We\text{ get 2 values here:} \\ 1)+1000=\frac{x}{(0.10-x)} \\ and \\ 2)-1000\text{ = }\frac{x}{(0.10-x)} \end{gathered}\)Values of x:
For 1) x = 0.0999
For 2)x = 0.1001
We choose number 1) x = 0.0999
Number 2 gives us a value higher than the initial values of concentration
Therefore, concentration in equilibrium of NH3 = 0.10-x =0.10 - 0.0999 = 0.00010M
Answer: A. 0.00010M
Ayo help me I’ll give a BRAINLIEST, I’m not sure which one it is, I’m thinking B
What is the∆S° of 0₂
Answer:0
Explanation: zero because it is the most stable form of oxygen in its standard state
calculate the vapor pressure (in torr) at 333 k in a solution prepared by dissolving 39.5 g of the non-volatile non-electrolye sucrose in 104 g of water. the vapor pressure of water at 333 k is 149.44 torr.
The vapor pressure (in torr) at 333 k in a solution prepared by dissolving 39.5 g of the non-volatile non-electrolyte sucrose in 104 g of water is 134.047 torr.
Moles of urea taken = Mass/MW = 39.5/60 = 0.658
Moles of water = 104/18 = 5.77
Mole fraction of water, x = 5.77/(5.77+0.658) = 0.897
According to Raoult's law, a solvent's partial vapour pressure in a solution (or mixture) is equal to or the same as the pure solvent's vapour pressure times the mole fraction present in the solution. Raoult's law of partial pressures for a non-volatile solute, we have:
Psolution = Χsolvent x P0solvent
Where,
Psolution = vapour pressure of the solution
Χsolvent = mole fraction of the solvent
P0solvent = vapour pressure of the pure solvent
So, P = P^0 * x = 149.44*0.897 = 134.047 torr
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What would be the molar ratio in the production of hydrogen iodide gas fromhydrogen and iodide gases, as shown in the following chemical reaction: *H2 (g) + 12 (9)2HI (g)1:1:12:1:21:1:22:1:1
The chemical reaction of the formation of hydrogen iodide is given:
H2(g) + I2(g) = 2HI (g)
As you can see from the equation, only 1 mole of hydrogen and 1 mole of iodine react to form 2 moles of hydrogen iodide
which compound has a strong and broad ir absorption centered at 3400 cm-1? group of answer choices 1-butanol octane diethyl ether 2-hexyne benzene
Compound A) 1-butanol has a strong and broad IR absorption centered at 3400 cm-1.
Infrared (IR) spectroscopy is a technique used to identify functional groups and chemical bonds in organic compounds based on their absorption of infrared radiation. The region around 3400 cm-1 is typically associated with the stretching vibrations of the O-H bond, indicating the presence of an alcohol or a compound containing a hydroxyl group.
Among the given options, compound A) 1-butanol is an alcohol that contains a hydroxyl group (-OH) attached to a carbon chain. The O-H bond in 1-butanol exhibits a strong and broad absorption centered at 3400 cm-1 in the IR spectrum. This absorption is caused by the stretching vibration of the O-H bond, which is characteristic of alcohols.
In contrast, compounds B) octane, C) diethyl ether, D) 2-hexyne, and E) benzene do not contain an -OH group or a functional group that would exhibit an absorption around 3400 cm-1. Therefore, the compound with a strong and broad IR absorption centered at 3400 cm-1 is A) 1-butanol.
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What happens to energy when light is transmitted through or reflected off a material?
Answer:
When light hits a material, three different things can happen.
First, the material can absorb the energy.
Second, transmit the energy
Third, reflect the energy cause it to bounce off.
All these things can happen at once.
Red gold i a gold-copper alloy ued to make jewelry. A piece of jewelry made of red gold weigh 9. 21 g and ha a volume of 0. 559 cm'. Gold ha a denity of 19. 3 g/em' and copper ha a denity of 8. 96 g/cm?. Calculate the percentage by ma of each metal in the jewelry. Aume the total volume of the jewelry i the um of the volume of the two metal it contain
Red gold is a gold-copper alloy that is commonly used to make jewelry. To calculate the percentage by mass of each metal in the jewelry, you need to determine the mass of gold and copper in the jewelry. The mass of gold can be calculated using the density of gold and the volume of gold in the jewelry:
mass of gold = density of gold * volume of gold
mass of gold = 19.3 g/cm³ * 0.559 cm³
mass of gold = 10.8 g
The mass of copper can be calculated using the density of copper and the volume of copper in the jewelry:
mass of copper = density of copper * volume of copper
mass of copper = 8.96 g/cm³ * (0.559 cm³ - 0.559 cm³)
mass of copper = 0 g
The total mass of the jewelry is 10.8 g + 0 g = 10.8 g.
Therefore, the percentage by mass of gold in the jewelry is 10.8 g/10.8 g = 100%. The percentage by mass of copper in the jewelry is 0 g/10.8 g = 0%.
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A group of scientists in Alaska notices that not only have atmospheric CO2 levels increased at their sampling site but so too have methane levels. What could account for this increase in methane levels
Answer:
The release of methane from thawed permafrost.
Explanation:
The complete question is
A group of scientists in Alaska notices that not only have atmospheric CO2 levels increased at their sampling site but so too have methane levels. What could account for this increase in methane levels?
- None of the answer options is correct.
- The release of methane from thawed permafrost.
-A decrease in beef production near the researchers' sampling area.
-The melting of permafrost accompanied by the thawing of methane-producing bacteria.
-The failure of rice paddies to be established in Alaska, given its climate.
Permafrost regions like the arctic circle hold a large supply supply of methane in their soils and their seas. Ordinarily, this methane should be gradually released naturally over a long period of time, but the effects of global warming is making these permafrost to thaw at a much faster rate, accelerating the release of methane into the atmosphere. The dark side is that methane is about 80 times more deadly when compared to CO2 in its contribution to the green house effect on earth.
examples of a pure substances
Answer:
Explanation:
Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements.
Answer:
Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements
Explanation:
the left-right inversion one word answer
Answer:
Lateral Inversion
Explanation:
what reagents are needed to convert (s)-3-methyl-3-phenylpentaoic acid to (s)-3-methyl-3-phenylpetanamine
1. SOCl2/pyridine
2. NH3
3. LiAlH4
4. H2O
SOCl2/pyridine is added to (S)-3-methyl-3-phenylpentanoic acid first in order to convert it to (5)-3-methyl-3-phenylpentanamine.
The carbonyl carbon is then reduced to an alkane by adding NH3 after which LiAlH4 is added. The mechanism is finished by the addition of water, which causes the product to form.
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Chemical Reactions - Problems
4 NH, +5 O, → 4 NO+6H_O
Which of the following are the reactants in the reaction above?
NH,
NO
I
H₂O
Submit v
IT
The ph of a solution prepared by the addition of 10. Ml of 0. 002 m koh(aq) to 10. Ml of distilled water is closest to.
This problem is asking for the for pH when a solution of potassium hydroxide is diluted to the double of its initial volume. Thus, the answer turns out to be 11.0.
pH calculationsIn chemistry, pH calculations are performed based on the following equation relating the pH and the concentration of hydrogen ions in the solution:
\(pH=-log([H^+])\)
However, since this problem involves a strong base, KOH as potassium hydroxide, one must calculate the pOH instead, and then convert it to pH with the following equations:
\(pOH=-log([OH^-])\\\\pH=14-pOH\)
In addition, due to the fact it is diluted from 10. mL to 20. mL (with the 10. mL of added distilled water), one needs to use the dilution equation in order to calculate the correct concentration of KOH:
\(M_1V_1=M_2V_2\\\\M_2=\frac{M_1V_1}{V_2} \\\\M_2=\frac{0.002M*10.mL}{20.mL}\\ \\M_2=0.001M\)
Hence, the pOH turns out to be:
\(pOH=-log(0.001)=3.0\)
And thereby the pH:
\(pH=14-3.0\\\\pH=11.0\)
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Section II: Observations and Conclusions
What charts, tables, or drawings would clearly show what you have learned in this lab?
Each chart, table, or drawing should have the following items:
An appropriate title
Appropriate labels
need help with lab!- earth and space seince 1
The Tables that clearly show what you have learned in this lab:
Centered on the page.Numbered in the order they appear in the text.Referenced in the order they appear in the text.Labeled with the table number and descriptive title above the table.Labeled with column and/or row labels that describe the data, including units of measurement.What is data?Data is described as a collection of discrete values that convey information, describing the quantity, quality, fact, statistics, other basic units of meaning, or simply sequences of symbols that may be further interpreted.
In most cases, we can also use a dichotomous key as it helps in the classification of objects by sorting it out with Yes and No questions, until every object is single.
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Agree or Disagree? Why?
While standing on the
beach during the
daytime, the breeze
always blows from the
land, because the land
is cooler than the sea
during the daytime.
Answer:
Explanation:
I'm sorry, but I disagree with the statement because the direction of the breeze is not solely determined by the difference in temperature between the land and sea. The direction of the breeze is influenced by a variety of factors such as the pressure system, the prevailing wind patterns and the shape of the land. During the daytime, sea breeze is a common phenomenon, which is caused by the land heating up faster than the ocean, and as the hot air rises, it creates a low-pressure system over the land, drawing in cooler air from the ocean. So, the breeze can blow from the land or sea during the daytime, it's not always blowing from the land.
We are studying the ideal gas law. In this discussion, you will be trying your hand at applying one of the ideal gas laws to a real world situation. Consider a situation that involves an ideal gas law and discuss how you would apply your chosen ideal gas law to the situation. Generate an ideal gas law question based on this situation.
Please do not forget to generate a question.
The ideal gas law, which relates the pressure, volume, temperature, and number of moles of an ideal gas, can be applied to real-world situations. By considering a specific scenario and applying the ideal gas law, we can analyze the behavior of gases and make predictions about their properties.
Let's consider a situation where a scuba diver is exploring underwater at a depth of 30 meters. We can apply the ideal gas law, specifically the form known as Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Question: How does the pressure of the gas in the scuba tank change as the diver descends to a depth of 30 meters, assuming the temperature remains constant?
To answer this question, we can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. By keeping the temperature constant, we can observe the relationship between pressure and volume as the diver descends and calculate the change in pressure based on the change in volume.
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Limiting line of balmer series result when electron jumps from orbitImmersive Reader
A) 3 to 2
B) ∞ to 2
C) 4 to 5
D) ∞ to 1
Answer:
A) 3 to 2
Explanation:
The Balmer series refers to all transition series of spectral emission lines of the hydrogen atom in which an electron moves from any higher energy level within the atom down to the energy level with principal quantum number n=2.
The Balmer series was originally calculated using the Balmer formula, this is an empirical equation first deduced by Johann Balmer in 1885.
Hence, a transition from n=3 level to n=2 level is in the Balmer series.
How much mass does 6 moles of K have?
Answer:
234.6
Explanation:
4. How many moles of KBr are found in 3 Liters of 0.4 M solution?
A.7.1moles
B. 43.9moles
C. 2.6moles
D 1.2 moles
There are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.
HOW TO CALCULATE NUMBER OF MOLES?The number of moles of a substance can be calculated by multiplying the molarity by the volume.
No. of moles = Molarity × volume
According to this question, 3L of a KBr solution are contained in a 0.4M.
no. of moles = 3L × 0.4M = 1.2moles
Therefore, there are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.
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MULTIPLE CHOICE QUESTION
Which distance-time graph most
accurately represents the data in the
data table?
Answer:
(a) The slope of distance-time graph gives the speed of the objects.
As the slope of object (B) is the greatest among all, thus B has the largest speed and hence it is the fastest among all the objects.
(b) : As the curve of the objects do not intersect with each other even once, hence they cannot be at the same point on the road at the same time.
(c) : On the y axis (i.e. distance line), 7 small represents 4 km
∴ 1 small line =
7
4
=0.57 km
Position of C at the instant B passes A is 8 km
(d) ; Position of B at the instant it passes C is 2nd small line above 4 km i.e. 4+2×0.57=5.14 km
∴ Distance traveled by B =5.14−0=5.14 kmV
Explanation:
Which of the following elements has the highest atomic mass?
Helium: 2 protons and 2 neutrons
Nitrogen: 7 protons and 7 neutrons
Oxygen: 8 protons and 8 neutrons
Hydrogen: 1 proton and no neutrons
Will give crown.
Answer:
oxygen has the highest atomic mass.
Answer:
C Oxygen
Explanation:
The answer would be C since the protons and the neutrons are somewhat the same number / similar. As well as the periodic table would have somewhere in the elements "box".
How is the molar mass of an element different from the atomic mass of an element?