a simple pendulum makes 130 complete oscillations in 3.10 min at a location where g = 9.80 m/s2. (a) find the period of the pendulum. s (b) find the length of the pendulum. m
A simple pendulum makes 130 complete oscillations in 3.10 min at a location where g = 9.80 m/s²: (a) The period of the pendulum is approximately 1.43 seconds (s). (b) The length of the pendulum is approximately 0.80 meters (m).
(a) The period of a simple pendulum is the time taken for one complete oscillation. We can calculate the period (T) using the formula:
T = (time taken for oscillations) / (number of oscillations)
Given that the pendulum makes 130 complete oscillations in 3.10 minutes, we need to convert the time to seconds:
T = (3.10 min × 60 s/min) / 130
T ≈ 1.43 s
Therefore, the period of the pendulum is approximately 1.43 seconds.
(b) The length of a simple pendulum can be determined using the formula:
L = (g × T²) / (4π²)
Substituting the value of the period (T) calculated in part (a) and the acceleration due to gravity (g = 9.80 m/s²), we can find the length (L):
L = (9.80 m/s² × (1.43 s)²) / (4π²)
L ≈ 0.80 m
Thus, the length of the pendulum is approximately 0.80 meters.
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If a 1 kg book has 46 Joules of gravitational potential energy how high is the shelf it is on?
g = 9.8 m/s^2 KE = ½ mv^2 PE = mgh
Answer:
4.7m
Explanation:
Given parameters:
Mass of the book = 1kg
Gravitational potential energy = 46J
Unknown:
Height of the shelf = ?
Solution:
The potential energy is due to the position of a body above the ground.
Gravitational potential energy = mgh
m is the mass,
g is the acceleration due gravity = 9.8m/s²
h is the height which is unknown
46 = 1 x 9.8 x h
h = 4.7m
As compared to training on a level surface, what is the percentage of total power achievable by training on an uneven surface?
When training on an uneven surface, the percentage of total power achievable is typically lower compared to training on a level surface. This is because the body needs to work harder to stabilize itself and adapt to the uneven terrain, resulting in a higher energy expenditure.
1. Training on an uneven surface introduces various challenges and demands more from the body. The uneven terrain requires the muscles to constantly adjust and stabilize, leading to increased muscle activation and energy expenditure.
2. As a result, the body needs to work harder to maintain balance and stability during exercises or movements on an uneven surface. This increased effort leads to a higher energy demand and a lower percentage of total power being available for the primary movement or exercise being performed.
3. In contrast, training on a level surface provides a more stable and predictable environment, requiring less energy expenditure for maintaining balance and stability. Therefore, when training on a level surface, a higher percentage of total power can be dedicated to the primary movement or exercise, allowing for more efficient and effective training.
Overall, training on an uneven surface may offer additional benefits such as improved proprioception and core strength, but it typically results in a lower percentage of total power achievable due to the increased energy demands of stabilizing the body.
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helpppppppppppppppppppppppppp
Answer:
should be D
Explanation:
pls make this the brainliest
The density of a typical laboratory plasma is 1018 m-3. This value leads to plasma oscillations at:
( The frequency f at which these oscillations occur for a given number density, n (electrons per cubic meter)
A.) 9 × 1018 Hz.
B.) 9 × 1012 Hz.
C.) 9 × 109 Hz.
D.) 9 × 106 Hz.
The plasma oscillations occur at a frequency of approximately = 9 × 109 Hz.
Plasma oscillations, also known as plasma frequency, can be determined using the formula:
f = (1 / (2π)) * √(ne^2 / (ε₀m))
where f is the frequency, n is the number density of electrons, e is the elementary charge, ε₀ is the vacuum permittivity, and m is the mass of an electron.
Given the number density of the plasma as 1018 m^(-3), we can substitute this value into the formula:
f = (1 / (2π)) * √((1018) * (1.6 x 10^(-19))^2 / (8.85 x 10^(-12) * 9.11 x 10^(-31)))
Simplifying the expression:
f ≈ 9 x 10^9 Hz
Therefore, the plasma oscillations occur at a frequency of approximately 9 x 10^9 Hz, which corresponds to option C) 9 × 109 Hz.
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Examples of applied force
Answer:
Push - The most common form of force is a push through physical contact (like a lawnmower or shopping cart)
Pull - You can apply a force by directly pulling on an object (like pulling a wagon)
Explanation:
-- you sit on a chair
-- gravity pulls something down
-- water pushes a log up to float
-- air holds the skin of a balloon out, in a ball-shape
-- my dog bites a bone
-- air holds the tires of my car out, in donut shapes
-- a book presses on a table
-- my shoes press down on the floor
-- my feet press down on the bathroom scale
-- the bathroom scale presses up on my feet
-- gravity pulls the Earth up toward me
a police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of:
Answer:
50 feet or more
Explanation:
In order to quickly respond to hazardous situation in a timely manner, it is important to be alert with all senses and there are situations such as while driving , the present of an hazard can only be heard, such as when other cars honk their horns
As such a citation can be issued by a police officer when a vehicle travels through the highway while using a sound amplification system which can be heard at a distance of 50 or more ft. outside the vehicle.
A police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of Fifty (50) feet or more.
Reaching one destination safely without any accidents is largely in the hand of the driver. As the auto vehicle can be a most deadly weapon and highway may be the most dangerous place in the world some of the rules is been implemented to ensure the safety of the people on the highways.
With open senses, the driver prevents any accidents. To prevent any accidents and respond within time. Driver must keep open his ears if any other driver is honking their horns.
Thus, A police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of Fifty (50) feet or more.
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I Need help please.
Answer:
5.83
Explanation:
Divide the distance by velocity
Please please help
A light fitting of mass 3 kg is hung from a timber beam by two identical chains each
inclined at 55° to the beam. Taking g = 9.8 m/s², find the tension in each of the
chains, correct to the nearest newton.
The diagram shows two objects of mass 5 kg and 3 kg
attached to the ends of a light inextensible string that passes
over a smooth pulley. The tension in the string is 7 newtons.
Take g = 9.8 m/s².
Find the downwards acceleration of the 5 kg object.
b Find the value of T.
Answer:
Tension is 36.75 N
Explanation:
yea the 2nd one-:
Using F = ma,
For 5 kg particle;
For 3 kg particle; Adding; 2g
a
5g − T T − 3g
= 5a [1] = 3a
= 8a
= 14 g s − 2
∴ Acceleration is 2.45 m Substituting into equation [1]
5 g − T = 5 × 14 g 15 g = T
4
A periodic wave is a wave that follows a repeating pattern as it propagates through space. That is, the oscillating pattern repeats at regular intervals of time. This repeating motion is also known as periodic motion
Answer:
Simple harmonic motionExplanation:
What is simple harmonic motion?
"Simple harmonic motion is a type of motion directed along a straight line, whose acceleration is fixed towards a point and is proportional to its distance from that point"
An object is said to be in simple harmonic motion if the following occurs:
• It moves in a uniform path.
• A variable force acts on it.
• The magnitude of the force is proportional to the displacement of the mass.
• The force is always opposite in direction to the displacement direction.
• The motion is repetitive and a round trip, back and
forth, is always made in equal time periods
Provide three examples of situations in which mass is the main factor determining an object's momentum
The three examples of situations in which mass is the main factor determining an object's momentum are, a moving truck, a moving trailer and a rolling block.
What is momentum?Momentum is the product of mass and velocity of an objectP = mv
where;
m is the mass of the objectv is the velocity of the objectThe three examples of situations in which mass is the main factor determining an object's momentum is below;
A moving truck.A moving trailer.A rolling block.The three examples given above shows three objects with heavy mass.
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A roller coaster glides from rest from the top of an 80.0 meter hill. What is the speed of the roller coaster at the bottom of the hill?
6.32 m/s
39.6 m/s
12.6 m/s
19.8 m/s
Based on the calculations, the speed of this roller coaster at the bottom of the hill is equal to: B. 39.6 m/s.
Given the following data:
Height = 80.0 meters.
Scientific data:
Acceleration due to gravity (g) = 9.8 m/s².
How to calculate the speed?In accordance with the law of conservation of energy, the potential energy possessed by the roller coaster at the top is equal to the kinetic energy possessed by the roller coaster at the bottom of the hill:
PE = KE
mgh = ½mv²
2mgh = mv²
v = √(2gh)
Substituting the given parameters into the formula, we have;
v = √(2 × 9.8 × 80)
v = √1,568
Speed, v = 39.6 m/s.
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What is the density of a 500 g rectangle block with the following dimensions: Length = 8.0 cm, Width = 6.0 cm,
and Height = 5.0 cm. I
Explanation:
Density = mass / volume
ρ = (500 g) / (8.0 cm × 6.0 cm × 5.0 cm)
ρ = 2.1 g/cm³
The volume of the block the product of its dimensions that is 240 cm³. Then density of the block weighing 500 g is 2.08 g/ cm³.
What is density ?Density of a substance is the measure of its mass per unit volume. It describes how closely its particles are packed within a given volume. It is the ratio of mass to the volume.
Volume of an object is the space occupied by the object. For a rectangle block, volume is the product of length, width and height.
Given, l = 8 cm
width = 6 cm
h = 5 cm
volume = l w h = 6 cm × 5 cm × 8 cm = 240 cm³
Mass of the block = 500 g
density = mass/ volume
d = 500 g/240 cm³
= 2.08 g/cm³
Therefore, the density of rectangular block is 2.08 g/cm³.
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In a resonance a turning fork of frequency 330hz produced the first loud sound when water level in a pipe was 17.8cm from the open-end ant the second at 57.3cm. calculate the wavelength of the sound, speed of sound in air, water level of the next resonant length ?
The wavelength, the speed of sound and the water level of the next resonant length (the fifth harmonics) are as follows;
The calculated wavelength of the sound from the tuning fork is 0.79 metersThe speed of the sound is 260.7 m/sThe water level of the fifth harmonics is 96.8 cmWhat is an harmonics of a sound wave?An harmonics are waves with a frequency that is an integer multiple of the fundamental frequency.
The given frequency of the sound wave, f = 330 hz
The first water level that gives the first loud sound, l₁ = 17.8 cm
The water level from the open end at the second loud sound, l₂ = 57.3 cm
First part;
The first harmonics that gives the fundamental frequency for the pipe is expressed as follows;
\(\dfrac{\lambda}{4} = l_1+e\)
Where;
e = The distance to the antinode of the wave above the top of the pipe
The third harmonics is given by the formula
\(\dfrac{3\cdot \lambda}{4} = l_2+e\)
\(\dfrac{3\cdot \lambda}{4}- \dfrac{\lambda}{4} = \dfrac{\lambda}{2} = (l_2+e) - (l_1+e) = l_2 - l_1\)
\(\dfrac{\lambda}{2} = l_2 - l_1\)
λ = 2 × (l₂ - l₁)
λ = 2 × (57.3 - 17.8) = 79
The wavelength of the wave, λ = 79 centimeters = 0.79 meters
Second part;
Speed of sound, v = f × λ
Therefore; v = 330 Hz × 0.79 m = 260.7 m/s
The speed of sound in air, v = 260.7 m/sThird part;
\(\dfrac{\lambda}{4} = l_1+e\)
\(\dfrac{3\cdot \lambda}{4} = l_2+e\)
Which gives; 3·(l₁ + e) = l₂ + e
3·l₁ + 3·e = l₂ + e
3·e - e = l₂ - 3·l₁
2·e = l₂ - 3·l₁
Therefore, 2·e = 57.3 - 3 × 17.8 = 2.9
e = 3.9 ÷ 2 = 1.95The water level for the next resonant length, which is the fifth harmonics, is given by the formula;
\(\dfrac{5\cdot \lambda}{4} = l_3+e\)
Which gives;
\(l_3 = \dfrac{5\cdot \lambda}{4} - e\)
Therefore;
\(l_3 = \dfrac{5\times 79 }{4} - 1.95 = 96.8\)
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State one similarity between rotatory and circular motion
Answer:
The main difference between these types of motion is that circular motion is a special case of rotational motion, where the distance between the body’s centre of mass and the axis of rotation remains fixed.
Rotational motion is based around the idea of rotation of a body about its center of mass. In rotational motion, the axis of rotation and centre of mass could change whereas in circular motion, the axis of rotation and centre of mass does not change.
Circular motion is a movement of an object along the circumference of a circle or rotation along a circular path and can either have a constant angular rotation rate and constant speed, or it can exist with a changing rate of rotation.
Think of one of those fairground rides where people sit on dummy horses. Now imagine the horses spin around the post that holds them to the base of the ride. Then you have both rotational motion of the horse and circular motion as the horses move around the ride.
A wind turbine blade with radius of 24 m and mass of 1380kg is rotating at 1.5 rev $. Assuming all of the mass is located at the end of the blade; what is the net force (in N) acting On the end ofthe turbine blade? (This net force supplied by interatomic forces in the metal, is the centripetal force required to keep each atom in circular motion ) Numeric A numeric value is expected and not an expression.
A wind turbine blade with a radius of 24 m and a mass of 1380kg rotates at 1.5 revolutions per minute. the net force acting on the tip of the turbine blade is 23,327,296 N.
First, we need to calculate the speed of the tip of the blade:
Circumference = 2 x π x radius = 2 x 3.14 x 24 = 150.72 m
Speed = Circumference x frequency = 150.72 x 1.5 = 226.08 m/s
Next, we can calculate the centripetal force using the formula:
Centripetal force = (mass x velocity²) / radius
Plugging in the given values, we get:
Centripetal force = (1380 kg x (226.08 m/s)²) / 24 m
Centripetal force = 23,327,296 N
Therefore, the net force acting on the end of the turbine blade is 23,327,296 N.
It is measured in newtons and can be classified as contact or non-contact force. Contact force occurs when two objects touch each other, while non-contact force occurs at a distance.
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A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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The infamous chicken is dashing toward home plate with a speed of 5.8m/s when he decides to hit the dirt. The chicken slides for 1.1s, just reaching the plate as he stops. (safe of course). (a) What is the magnitude of the chickens acceleration (b) How far did the chicken slide?
We know that
• The initial speed is 5.8 m/s.
,• The time elapsed is 1.1 seconds.
,• The final speed is zero because it will stop.
Let's find the acceleration. We have to use a formula that involves the initial speed, the time spent, the final speed, and acceleration.
\(v_f=v_0+at\)Now we use the given magnitudes to solve for a.
\(\begin{gathered} 0=5.8\cdot\frac{m}{s}+a\cdot1.1\sec \\ -5.8\cdot\frac{m}{s}=a\cdot1.1\sec \\ a=\frac{-5.8\cdot\frac{m}{s}}{1.1\sec } \\ a\approx-5.3\cdot\frac{m}{s^2} \end{gathered}\)(a) The magnitude of the chicken's acceleration is -5.3 m/s^2.
Now, to find how far the chicken slid, we have to use a formula that includes distance.
\(v^2_f=v^2_0+2ad\)Let's use the magnitudes we know to find d.
\(\begin{gathered} 0=(5.8\cdot\frac{m}{s})^2+2(-5.3\cdot\frac{m}{s^2})d \\ 0=33.64\cdot\frac{m^2}{s^2}-10.6\cdot\frac{m}{s^2}\cdot d \\ d=\frac{-33.64\cdot\frac{m^2}{s^2}}{-10.6\cdot\frac{m}{s^2}} \\ d\approx3.2m \end{gathered}\)(b) The chicken slid 3.2 meters.
As you can observe, the positive direction of the movement is towards the home plate. So, the acceleration is towards the third base because it's negative, that is, the chicken is slowing down to get to home plate.
Therefore, the direction of the acceleration is towards the third base.
PLEASE HELP
Fill in the blanks to correctly complete the statement.
The motion of an object moving with uniform circular motion is always_______
to the circle, so the speed of an object moving in a circle is known as _______
speed.
Answer:
The first one is tangent, second is tangential.
What is the SI unit used to measure the temperature of a substance?
A. degree Celsius
OB
degree Fahrenheit
gram
OD
kelvin
ОЕ.
mole
Reset
Next
Answer:
Kelvin
Explanation:
Kelvin is the universal and scientific unit for temperature as Celsius and Fahrenheit temperatures we use in everyday situations
[OU.04]Two stars, Star 1 and Star 2, are at almost equal distances from Earth. The table below shows the masses of the two stars.
Name of Star Mass of Star (in million solar masses)
Star 1 3.61
Star 2 11.73
I am lost on this question HELP
Which of these statements is most likely correct about the stars?
Earth exerts a greater gravitation force on Star 1 than on Star 2.
Earth exerts a greater gravitation force on Star 2 than on Star 1.
Star 1 attracts Star 2 with a greater gravitational force than Star 2 attracts Star 1.
Star 2 attracts Star 1 with a greater gravitational force than Star 1 attracts Star 2.
Answer: Which of these statements is most likely correct about the stars?
Star 2 attracts Star 1 with a greater gravitational force than Star 1 attracts Star 2.
No, because Third Newton Law states that both forces are equal in magnitude.
Earth exerts almost equal gravitation force on both the stars.
No, because the Universal Gravitational Law, estblished by Newton, states the atraction force to two masses is proportional to the product of the masses.
Star 1 attracts Star 2 with a greater gravitational force than Star 2 attracts Star 1.
No (same reason for the first statement)
Earth exerts greater gravitation force on Star 2 than on Star 1.
Right. This is the correct statement. Given the mass of Star 2 is greater than the mass of Star 1, by the Universal Gravitational Law, the earth exerts greater gravitational attraction on Star 2.
Explanation:
:)
12. Which of the following is true of an electrolyte?
A. It is a component of a cell, but not a battery.
B. It is a component of a wet cell but not a dry cell.
C. It is a component of a dry cell but not a wet cell.
D. It is a component of both a wet cell and a dry cell.
Answer:
A
Explanation:
It’s a because a electrolyte reproduces
what do we measure the ""pressure"" of electric circuits in?
In electric circuits, we measure the pressure, also known as the voltage or electric potential difference. Voltage is a fundamental electrical quantity measured in volts (V).
It represents the potential energy per unit charge available in a circuit. Voltage is analogous to pressure in a fluid system, as it determines the rate at which electric charges flow through a conductor. In a circuit, voltage provides the driving force for the movement of electrons. It can be measured using a voltmeter, which is connected in parallel across the component or portion of the circuit being measured. Voltage measurements help assess the performance, efficiency, and safety of electrical systems, enabling engineers and technicians to diagnose and troubleshoot circuit problems, design appropriate power supplies, and ensure proper functioning of electronic devices.
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You hold an object up with a spring scale and it reads 5N.
What is the mass of the object?
Answer:
balance
Explanation:
Which of the following statements is true about the drift velocity of electrons in a wire? Select the correct answer
a. The drift velocity measures the rate at which electrons leave the surface of the metal. b. The drift velocity is very slow, and a typically describes a microscopic displacement over a period of a second. c. The drift velocity is very fast and is directly responsible for the short light switch from across the room. d. The drift velocity measures the speed of the atomic nuclei drifting through the time required an electrical signal to reach a light bulb when you fpaAtour Answer metal e. The drift velocity measures the instantaneous speed of the electrons between the collisions they experience in the metal.
The correct answer is b. The drift velocity is very slow, and typically describes a microscopic displacement over a period of a second.
The drift velocity refers to the speed at which electrons move through a wire under the influence of an electric field. It is a very slow speed, typically only a few millimeters per second, and is the result of the collisions that electrons experience with the metal atoms in the wire.
Electric current is the flow of electrons in a conductor, such as a wire. Individual electrons do not, however, move quickly through the wire. The average speed at which electrons flow across a wire while an electric field is present is referred to as the drift velocity.
Electrons frequently interact and shift direction because of collisions with other particles in the conductor. These collisions reduce their net movement and impede their total advancement. In comparison to the speed of individual electrons, the drift velocity is on the order of millimetres per second.
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yoyoyoyoyoyoyoyoyoyoyoyoyoyoyoy
Answer:
Yoyoyoyoyooyoyy
Explanation:
Yoyoyoyoyoyoyoyoyooy
Answer:
yoyoyoyoyoyooyoyoyoyoyyoyoy
A 2500 kg car with a speed of 15 m/s collides with a stationary car with a mass of 900 kg. On impact they hook together and move away. Their new mass is 3400 kg and new velocity is 0.05 m/s. What type of collision is being explained in the question?
This is an example of an inelastic collision. In an inelastic collision, some of the initial kinetic energy is lost, and the objects move away from each other with a reduced speed, as is the case here.
What is collision?Collision is the physical contact between objects, causing them to interact and exchange energy. This can occur when two or more objects come into contact with each other while moving at different speeds. Collisions can be elastic or inelastic, depending on the type and amount of energy lost in the interaction. Elastic collisions are those in which the total kinetic energy of the objects is the same before and after the collision, while in inelastic collisions some energy is lost in the form of heat, sound, or other forms of energy.
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Define the types of friction and give FOUR examples of each
Static Friction
Rolling Friction
Sliding Friction
Fluid Friction
A 1kg rock is dropped 50m off a bridge. How much PE did it have
before it was dropped?
In this case, a body of mass 5 kg kept at a height of 10 m. So, the potential energy is given as 500 J.
Which energy has potential?An object's potential energy is its stored energy. This energy has the capacity to be productive. An object's potential energy is provided by gravity. Gravity's downward force is the source of this potential energy.
The acceleration brought on by gravity is known as the gravitational constant, or g. On Earth, this acceleration is equivalent to 10 metres per second. PE = mgh is the equation for potential energy resulting from gravity. The object's potential energy declines and its kinetic energy rises as it approaches the ground.
Briefing:Potential Energy = 5 x 10 x 10 = 500J.
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For a gravitational field to be generated between two objects, what must be true?- No other forces can be present- The two objects must be in contract- One object must be pure iron- Both objects must have mass
Answer:
Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore, the correct option is option D.
What is matter?
Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.
Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.
So as we saw that matter has some mass so mass can be measured in gram only. Mass can also be represented as number of molecules. We also saw that matter occupy some volume and that volume is measured only in liter. For a gravitational field to be generated between two objects, Both objects must have mass.
Therefore, the correct option is option D.
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