what theoretical device would generate the maximum possible amount of work from a given amount of heat?

Answers

Answer 1

Answer:

An ideal "Carnot" engine

E = (Q2 - Q1) / Q2 or 1 - Q1 / Q2

Q1 (heat wasted) would have to be zero for 100% efficiency


Related Questions

If it is 2:00 AM at 90 East longitude, what time is it at 75 East longitude? 11. If it is 8:00 PM at 15 East, what time is it at 135 East longitude? 12. How many hours difference is there between 105 West longitude and the Prime Meridian? 13. If it is 9:30 AM in New York which is located 41 North Latitude, and 75 West Longitude, what t is it in Lima Peru which is located at 15 South latitude, and 75 West Longitude?
Previous question

Answers

11.The time at 75° East longitude would be 1 hour and 20 minutes behind. 12.The time at 135° degrees East longitude would be 4 hours ahead. and 13. the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM.

At 2:00 AM at 90° East longitude, the time at 75° East longitude would be 1 hour and 20 minutes behind. This is because for every 15 degrees of longitude, there is a time difference of approximately 1 hour. Since the two longitudes in question have a difference of 15 degrees, we can divide this by 15 to calculate the time difference.

If it is 8:00 PM at 15° East longitude, the time at 135° East longitude would be 4 hours ahead. Similarly, for every 15 degrees of longitude, there is an approximate time difference of 1 hour. Since the two longitudes in question have a difference of 120 degrees, we can divide this by 15 to calculate the time difference.

There is a 7-hour difference** between 105° West longitude and the Prime Meridian (0° longitude). The Prime Meridian, passing through Greenwich, England, serves as the reference point for determining time zones. As one moves westward from the Prime Meridian, each 15 degrees of longitude corresponds to a time difference of approximately 1 hour. Therefore, the time at 105° West longitude would be 7 hours behind the time at the Prime Meridian.

If it is 9:30 AM in New York (41° North latitude, 75° West longitude), the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM. The latitude does not affect the time difference between the two locations. However, since both locations have the same longitude (75° West), they would experience the same local time. The time difference between different latitudes is primarily significant for determining time zones rather than the actual time within a specific time zone.

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The force of the wind blowing on a vertical surface varies jointly as the area of the surface and the square of the velocity. If a wind of 60mph exerts a force of 20lb on a surface of 1/5 ft², how much force will a wind of 180mph place on a surface of 4ft²?
A wind of 180mph will place a force of ____ Ib on a surface of 4ft². (Type an integer or a simplified fraction.)

Answers

A wind of 180mph will place a force of 32400 Ib on a surface of 4ft².

The force of the wind blowing on a vertical surface varies jointly as the area of the surface and the square of the velocity.

If a wind of 60mph exerts a force of 20lb on a surface of 1/5 ft², how much force will a wind of 180mph place on a surface of 4ft²

A force of 1250lb is exerted

since the force of the wind varies jointly as the area of the surface and the square of the velocity,

let f = force

a = area

velocity =v

from the above statement, we find out that

f ∝ a * v²----1

that is  f = k * a * v²    -----2

where k is a coefficient of proportionality

since velocity of wind in mph, v =60

and force in lb = 20

and surface area = 1/5 ft²

from equation 2

20 = 1/5 * k * 60²

20 * 5 /3600 = k

25/9 = k

A wind of 180mph will place a force of on a surface of 4ft².

f = 25/ 9 *4 * 180²

f = 32400

Therefore, a wind of 180mph will place a force of 32400 Ib on a surface of 4ft².

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A particle starts to move in a straight line from
a point with velocity 10 m/s and acceleration - 20 m/s²? Find the position and velocity of the
particle at (i) t = 5s, (ii) t' = 10 s.​

Answers

Answer: s(5) = -200,  v(5) = -90

              s(10) = -900, v(10) = -190

Explanation:

Position: s(t)

Velocity:  s'(t) = v(t)                ⇒      \(s(t)=\int {v(t)} \, dt\)

Acceleration     v'(t) = a(t)      ⇒      \(v(t)=\int {a(t)} \, dt\)

We are given that acceleration a(t) = -20   and velocity v(t) = 10

\(v(t)=\int {a(t)} \, dt\\\\v(t)=\int{-20}\, dt\\\\v(t)=-20t + C \\\\v(t)=10\quad \longrightarrow \quad C=10\\\\v(t)=-20t+10\)

\(s(t)=\int {v(t)} \, dt\\\\s(t)=\int {(-20t+10)} \, dt\\\\s(t)=-10t^2+10t\\\\\)

(a) Input t = 5 into the s(t) and v(t) equations

   s(5) = -10(5)² + 10(5)           v(5) = -20(5) + 10

          =  -250  +  50                     = -100   +  10

          =       -200                          =        -90

(b) Input t = 10 into the s(t) and v(t) equations

     s(10) = -10(10)² + 10(10)           v(10) = -20(10) + 10

            =  -1000  +  100                     = -200   +  10

            =       -900                          =        -190

what will happen if no force is exerted on a moving object?

Answers

Explanation:

If no force is exerted on a moving object, it will continue to move at a constant velocity. This is described by Newton's first law of motion, which states that an object will remain at rest or continue to move at a constant velocity in a straight line unless acted upon by an external force. In other words, if no net force acts on an object, the object will maintain its velocity, neither speeding up nor slowing down.

which kind of object, in which a series of drawn images seem to move as book pages are viewed rapidly, was the origin of animation?

Answers

The kind of object in which a series of drawn images seem to move as book pages are viewed rapidly, and which is considered as the origin of animation, is called a "flipbook."

A flipbook works by creating the illusion of movement through a rapid sequence of images that show slight changes in position or appearance from one frame to the next. When the pages are flipped quickly, our eyes perceive the images as a continuous motion, giving life to the animated sequence.

The operation of a flipbook is identical to that of animated movies. Your brain is unable to distinguish between the rapidly changing frames with marginally differing illustrations as separate images. The figures appear to be moving, but they actually only "flip" between numerous illustrations, just as in your book, thanks to this technique.

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5. A bullet accelerates at 5.8 x 10 m/s from rest as it travels the 0.80 m of the
rifle barrel.
a
How long was the bullet in the barrel?
b. What velocity does the bullet have as it leaves the barrel?

Answers

Answer:

Below

Explanation:

d = 1/2 a t^2

.80 = 1/2 ( 5.8 x 10^?) t^2  

  ( I think you left off the exponent...and acceleration has units m/s^2  ...not m/s)

t =  .166 s

v = at = 58 x .166= 9.63 m/s

Which of the following is NOT a function of the skeletal system?

A. Support your body
B. Give shape to your body
C. Bring oxygen to your body
D. Protect your body​

Answers

D
Hope this helps
And
I think the answer is D

A 50 kg ball is sitting on a table and is pushed to the right with a force of 200 N what is the weight of this ball

Answers

Answer:

4 m/s^2

Explanation:

F = ma

a = F/m

a = 200/50

a = 4 m/s^2

your friend, who is in a field 60 meters away from you, kicks a ball towards you with an initial velocity of 17 m/s . assuming the grass causes the ball to decelerate at a constant rate of 1.0 m/s2 , how long does it take for the ball to reach you?

Answers

It takes approximately 7.7 seconds for the ball to reach you from your friend who is 60 meters away from you. This is calculated by using the formula v=u+at, where v is the final velocity, u is the initial velocity and t is the time taken for the ball to reach you.

Here, the final velocity is 0 m/s, the initial velocity is 17 m/s and the acceleration due to the grass is -1.0 m/s2. By substituting these values in the formula, we get t=v-u/a. After solving the equation, we get t=17-(-1)/1=7.7 seconds. This is the time taken for the ball to reach you from your friend who is 60 meters away.

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what mass of bromine will be produced if a potassium bromide solution reacts with 50.0ml of a 1.20 mol/l solution of acidified naclo4(aq)

Answers

Around 9.588 g of bromine will be produced when 50.0 ml of 1.20 mol/L potassium bromide solution reacts with 50.0 ml of a 1.20 mol/L solution of acidified NaClO.

The reaction between potassium bromide (KBr) and sodium hypochlorite (NaClO) in the presence of acid is a redox reaction, which results in the formation of bromine (Br2) and sodium chloride (NaCl). The amount of bromine produced can be calculated using the stoichiometry of the reaction.

First, the number of moles of potassium bromide (KBr) can be calculated using the molarity and volume of the KBr solution:

Moles of KBr = Molarity x volume

= 1.20 mol/L x (50.0 ml / 1000 ml/L)

= 0.0600 mol

Since the reaction is 1:1 between KBr and NaClO, the same number of moles of bromine will be produced. The mass of bromine can be calculated using the moles and molar mass of bromine:

Mass of Br2 = Moles of Br2 x Molar mass of Br2

= 0.0600 mol x 159.80 g/mol

= 9.588 g

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A rocket is launched and the observer measuring the rocket altitude is standing at a distance of 200 feet from the launcher. When the rocket reaches apogee, the observer measures an angle of 45° using an altitude scope. Calculate the altitude of the rocket to the nearest foot.

Answers

Answer:

100 foot

Explanation:

Using the formula for calculating range to calculate the speed first as shown;

Range R = U²sin 2theta/g

U is the speed

theta is the observe angle

g is the acceleration due to gravity.

200 = U²sin 2(45)/9.8

Usin90 = 200 * 9.8

U² = 1960

U = √1960

U = 44.27 m/s

Get the required altitude

Altitude H = u²/2g

H = 44.27²/2(9.8)

H = 1,959.8329/19.6

H = 99.99 feet

Hence the altitude of the rocket to the nearest foot is 100 foot

an amusement park ride has two identical carriages that revolve around the center of the ride’s axle, as shown in the figure. both carts travel at a constant tangential speed at all points along the circular path. at what position is the total mechanical energy of the cart-cart-earth system at its maximum value?

Answers

The principle of conservation of energy allows to find the result for the mechanical energy of the system is:

Mechanical energy is conserved at all points, therefore at all points it has the same value.

Mechanical energy is defined by the sum of the kinetic energy and the potential energies.

            Em = K + U

In the principle of energy conservation, it establishes that energy cannot be created or destroyed, it is only transformed, in the case of no friction, mechanized energy is conserved at all points.

They indicate that the system is rotating, which is why it is subjected to a force that expends its energy in changing the direction of the speed to keep the system in rotation, so the speed of the system remains constant.

          Em = K = ½ I w²

Consequently, using the principle of conservation of energy we can find the result for the mechanical energy of the system is:

Mechanical energy is conserved at all points, therefore at all points it has the same value.

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A man is transporting a trolley of mass 6 Kg and having Kinetic energy of 40 J. Compute its Velocity with which he is running?

Don't spam :)) ​

Answers

Explanation:

Given that,

Mass of a trolley, m = 6 kg

Kinetic energy of the trolley, K = 40 J

To find,

The velocity of with which he is running.

Solution,

The kinetic energy of an object is given by the formula as follow :

K = 1/2 mv²

v is velocity

Putting all the values we get :

v = √2k / m

v = √2×40/6

» v = 3.65 m/s

So, he is running with a velocity of 3.65 m/s.

3.65m/s

Answer:

Solution given:

mass(m)=6kg

kinetic energy: 40J

velocity(v)=?

we have

kinetic energy =½mv²

40=½*6*v²

\(\frac{40}{3}\)=v²

v=\(\sqrt{\frac{40}{3}}=3.65m/s\)

5. Squids have built in propulsion systems. A squid draws water into its mantle
cavity and propels itself forward by forcing the water out through a tube called a
siphon. A scientist studying an 8.0 kg squid observes that the squid draws in 0.60
kg of water and then ejects the water in 0.15 seconds at a velocity of 15.0 m/s.
What is the average force on the squid during the propulsion?
A 45 N
B 60 N
C 90 N
D 800 N

Answers

The actual force on the squid is half of this, or 90 N.

What is propulsion?

Propulsion is the force which moves a vehicle or object forward. It can be generated through the reaction of a rocket engine, the thrust of a jet engine, the push of a propeller, or the thrust of an electric motor. Propulsion systems are generally designed for specific types of vehicles, such as cars, boats, planes, or spacecraft. The system typically consists of a power source, a mechanism for converting the power into a propulsive force, and a means of controlling the direction of the force. Propulsion can also be provided by the force of gravity, such as when a body moves downhill or when a rocket is launched into space. In any case, the goal of propulsion is to generate a force which will move the vehicle in the desired direction.

The average force on the squid during the propulsion can be calculated using the equation F = ma,
Where m is the mass of the squid and a is the acceleration.
Acceleration is calculated by dividing the change in velocity (15 m/s) by the change in time (0.15 s), giving an acceleration of 100 m/s^2.
The force is then calculated by multiplying the mass of the squid (8.0 kg) by the acceleration (100 m/s^2), giving a force of 800 N.
However, this is the total force on the squid.
Since the squid is both pushing and pulling the water,
the actual force on the squid is half of this, or 90 N.

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one day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. having recently studied optics in your physics class, you're

Answers

curious about what you're observing. This phenomenon is known as a pinhole camera or camera obscura.

When sunlight passes through the pinhole in the window shade, it acts as a tiny aperture. The light rays coming from different points on the outside scene pass through this aperture and create an image on the opposite wall.

The pinhole camera works based on the principles of optics. The small size of the aperture limits the amount of light entering the camera, and it also acts as a point source of light. As a result, the light rays from different points in the scene form an inverted and reversed image on the wall.

The image formed by the pinhole camera will be dim and lack detail due to the limited amount of light entering the camera. However, the image will be sharp as long as the pinhole is small and the distance between the pinhole and the wall is significant.

The phenomenon you observed with the patch of light on the far wall is a simple demonstration of how light travels in straight lines and forms images. It's a fascinating way to explore the basic principles of optics.

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Calculate the mass of potassium hydroxide (KOH) that would be needed to form 25.0 g of potassium nitrate (KNO:) in this reaction

Calculate the mass of potassium hydroxide (KOH) that would be needed to form 25.0 g of potassium nitrate

Answers

Taking into account the reaction stoichiometry, 13.87 grams of KOH is required to form 25.0 g of potassium nitrate.

Reaction stoichiometry

In first place, the balanced reaction is:

HNO₃ + KOH  → KNO₃ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HNO₃: 1 moleKOH: 1 moleKNO₃: 1 moleH₂O: 1 mole

The molar mass of the compounds is:

HNO₃: 63 g/moleKOH: 56.1 g/moleKNO₃: 101.1 g/moleH₂O: 18 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

HNO₃: 1 mole ×63 g/mole= 63 gramsKOH: 1 mole ×56.1 g/mole= 56.1 gramsKNO₃: 1 mole ×101.1 g/mole= 101.1 gramsH₂O: 1 mole ×18 g/mole= 18 grams

Mass of KOH required

The following rule of three can be applied: If by reaction stoichiometry 101.1 grams of KNO₃ are formed by 56.1 grams of KOH, 25 grams of KNO₃ are formed by how much mass of KOH?

mass of KOH= (25 grams of KNO₃×56.1 grams of KOH) ÷101.1 grams of KNO₃

mass of KOH= 13.87 grams

Finally, 13.87 grams of KOH is required.

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WHAT IS SOUND? EXPLAIN ITS WAVES​

Answers

Answer:

sound is made up of vibrations or sound waves that we can hear these sound waves are formed by objects

Answer:

Sound wave consists to vibrating particles.These knock into other particles causing them to vibrate,and so the sound can travel away from the source.You can hear sound because the vibration in the air cause your ear drums to vibrate this vibration is converted into signals which travel down a nerve to your brain.

Explanation:

hpe its help

d) find the power cunsumption in 22 ohms lamp and 4.5 ohms lamp ?

e) find the power delivered by the battery

d) find the power cunsumption in 22 ohms lamp and 4.5 ohms lamp ?e) find the power delivered by the battery

Answers

Answer:

Explanation:

R₁ = 22 Ω

R₂ = 4.5 Ω

U = 45  V

Circuit resistance:

R = R₁ + R₂ = 22 + 4.5 = 26.5 Ω

Circuit current:

I = I₁ = I₂ = U / R = 45 / 26.5 ≈ 1.7 А

Lamp voltages:

U₁ = I₁·R₁ = 1.7·22 ≈ 37 V

U₂ = I₂·R₂ = 1.7·4.5 ≈ 8 V

Power:

P₁ = U₁·I₁ = 37·1.7 ≈ 63 W

P₂ = U₂·I₂ = 8·1.7 ≈ 14 W

P = U·I = 45·1.7 ≈ 77 W

in an automobile crash, a vehicle that was stopped at a red light is rear-ended by another vehicle. The vehicles have the same mass. If the tire marks show that the two vehicles moved after the collision at 4 m/s, what was the speed of the vehicle before the collision

Answers

The initial speed of the vehicle before the collision is 8 m/s.

Let the mass of the vehicle = mLet the initial speed of the vehicle stopped = uThe initial speed of the vehicle parked at the red light = 0

Principle of conservation of linear momentumThe initial speed of the vehicle before the collision is calculated by applying principle of conservation of linear momentum as follows;

\(m_1 u_1 + m_2 u_2 = v(m_1 + m_2)\\\\mu + m(0) = 4(m+ m)\\\\mu = 4(2m)\\\\mu = 8m\\\\u = 8 \ m/s\)

Thus, the initial speed of the vehicle before the collision is 8 m/s.

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Mangrove forests play an important role in _______.
a.
fisheries
b.
coastal protection
c.
wildlife habitat
d.
all of the above


Please select the best answer from the choices provided

A
B
C
D

Answers

D. All of the above

At high tide fish will feed among the mangrove roots - rich fishing ground

The trees trap sediment and soil in the river that would flow out to sea which also helps stop erosion

Wildlife utilise almost every part of the tree, with insects and birds, monkeys and lizards in the branches, shrimps and fish in the roots, and snails and clams in the soil

Typical electrical wires in your house are generally made of copper (electron density of 8.47∗1024 electrons per cm3 ) and are usually either 14 gauge (diameter of 1.63 mm ), 12 gauge (diameter of 2.05 mm ), or 10gauge(2.59 mm) wires.
(A) If you have a 14 gauge wire that is carrying the maximum current of 20 , what would be the average drift speed of the electrons in the wire? Tries 1/8
(B) Usinq the averaqe speed you just calculated in Part (A), how much time would it take an electron to travel 8.84 m?

Answers

A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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a golf ball of mass 0.050 kg is at rest on the tee and has a velocity of 102 m/s immediately after being struck. if the club and ball were in contact for 0.94 ms what is the average force exerted on the ball?

Answers

A golf ball with a mass of 0.050 kg is at rest on the tee and accelerates to 102 m/s as soon as it is struck. The average force applied to the ball if the club and ball made contact for 0.94 ms is 6.3 kN.

Describe impulse.

Impulse is a term used to describe how a net force—a specific type of "moving force"—affects an object. An impulsive force is a strong force that acts quickly to cause a finite change in momentum. Impulsive forces were conceptualized separated from regular forces throughout science history.

How is impulse calculated in physics?

Force times time equals change in momentum for an impulse.

Briefing:

F = mv/t

F = (0.050 kg)(102 m/s) / 0.81 ms × 10⁻³ = 6.3 kN

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How do photons help explain the photoelectric effect?
A. Changing light frequencies create opposing electric fields that affect electrons.
B. "Packets" of electromagnetic energy eject electrons.
C. Particles with positive charge attract negative electrons.
D. Single particles of light take the place of electrons that have similar mass and energy.

Answers

Answer:

Option B

"Packets" of electromagnetic energy eject electrons.

Explanation:

A photon is a tiny packet of light. Light as we know is a form of electromagnetic energy. Whenever light is incident on a photoelectric surface, the energy of the light wave gets transferred to the electron, causing it to have enough energy to eject electrons from its surface. The electrons, once ejected, are now free to move about, thus, resulting in the flow of electrical current.

This makes option B the correct answer

one significant method for assessing body fat distribution is measurement of ______ circumference.

Answers

One significant method for assessing body fat distribution is measurement of waist circumference.

Waist circumference is a widely used method for assessing body fat distribution and is an important indicator of central obesity. It involves measuring the circumference of the waist at a specific anatomical landmark, typically at the level of the narrowest point between the ribs and the iliac crest.

The measurement of waist circumference provides valuable information about the distribution of body fat. Excess fat accumulation in the abdominal region, also known as central obesity or android obesity, is associated with a higher risk of various health conditions, including cardiovascular diseases, type 2 diabetes, and metabolic syndrome.

By measuring waist circumference, healthcare professionals can evaluate an individual's body fat distribution and assess their risk for developing obesity-related health problems.

The measurement of waist circumference is relatively simple and non-invasive, making it a practical method for assessing body fat distribution in clinical and research settings. It is often used in conjunction with other anthropometric measurements, such as body mass index (BMI), to provide a comprehensive evaluation of an individual's body composition and health status.

Regular monitoring of waist circumference can help track changes in body fat distribution over time and guide interventions aimed at reducing central obesity and improving overall health.

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For an installation with a 125-kva, 3-phase transformer, a 240-volt primary, and thwn copper conductors, determine the maximum size ocpd permitted that will protect the conductors and the primary of the transformer where the protection method is primary-only protection. there is more than one option here, so be sure to select only the maximum circuit breaker and wire combination that is nec compliant.

Answers

Maximum overcurrent protection (MOP) is the most circuit breaker size required to shield the system. The maximum overcurrent safety is 41.053 A.

We know that for a three-phase transformer, the contemporary can be written as,

I = 3 - phase kV A / 1.73 x V

I = 25000 / 1.73 x 440

I = 32.84 A.

Now, the maximum overcurrent protection value is 25% above the present day, therefore, the most overcurrent safety can be written as,

I_Max = 125% of I

          = 1.25 x 32.84

          = 41.053 A

subsequently, the most overcurrent protection is 41.053 A.

Maximum Overcurrent Protection (MOP) refers to the maximum level of electrical current that is allowed to flow through an electrical system without causing damage. This protection is typically provided by overcurrent protection devices, such as circuit breakers and fuses, which are designed to automatically interrupt the flow of current in the event of an overcurrent situation.

MOP is an important safety feature in electrical systems, as it helps to prevent damage to electrical components and reduces the risk of fires and other safety hazards. The level of MOP is determined by the electrical codes and standards that apply to the particular system, and it is based on factors such as the type of electrical equipment used, the size of the conductors, and the type of insulation used.

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A boxer hits a punching bag and gives it a change in momentum of 12 kg•m/s
over 7.0 ms.

A boxer hits a punching bag and gives it a change in momentum of 12 kgm/sover 7.0 ms.

Answers

The magnitude of the net force on the punching bag is 1714N

What is momentum?momentum, product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle. See Newton's laws of motion.The change in momentum of an object is the product of mass and the change in velocityThe magnitude of the netforce can be calculated using 12kg/7.0msBut we can convert 7ms to "s" = 7× 10^-3sF= Force = 12/7×10^-3= 1714NHence, the magnitude of the net force on the punching bag is 1714N

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for an object whose velocity, in ft/sec is given by v(t) = cos(t), what is its distance, in feet, travelled on the interval t = 1 to t = 5? 0.75 0.29 1.8 2.20

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The object travels approximately 0.12 feet on the interval t=1 to t=5.

To find the distance travelled by the object, we need to integrate the absolute value of the velocity function over the given interval.

The absolute value of the given velocity function is |cos(t)|. Integrating this over the interval t = 1 to t = 5, we get: ∫|cos(t)| dt from t=1 to t=5 = ∫cos(t) dt from t=1 to t=5, since cos(t) is positive on this interval = sin(t) from t=1 to t=5 = sin(5) - sin(1)

Using a calculator, sin(5) ≈ 0.96 and sin(1) ≈ 0.84, so: sin(5) - sin(1) ≈ 0.96 - 0.84 = 0.12. Therefore, the object travels approximately 0.12 feet on the interval t=1 to t=5.

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The magnetic field on the earth that protects us from solar wind is caused by [BLANK]. (Select all that apply)a. the earth's revolutionb. the liquid outer corec. the earth's tilt on its axisd. the seasonse. the solid inner coref. the earth's rotation

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The correct options for the factors that contribute to the Earth's magnetic field, which protects us from solar wind, are option b. the liquid outer core and option f. the Earth's rotation.

The Earth's magnetic field is generated by the motion of molten iron and nickel in the liquid outer core of the Earth (Option b). This motion, known as convection, generates electric currents that produce the magnetic field.

The Earth's rotation (Option f) also plays a significant role. The rotation of the Earth causes the convection currents in the liquid outer core to circulate and amplify the magnetic field, creating a dynamo effect.

The Earth's revolution (Option a) around the Sun and its tilt on its axis (Option c) are not directly responsible for the generation of the Earth's magnetic field. They are factors that influence climate and seasons on Earth but do not contribute to the magnetic field.

The seasons (Option d) are related to the Earth's axial tilt and its orbit around the Sun but are not directly connected to the generation of the magnetic field.

The solid inner core (Option e) is not involved in generating the Earth's magnetic field. It is mainly composed of solid iron and nickel and does not have the fluid motion required for the generation of a magnetic field.

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I have a physics mid year exam tomorrow and I'm already so late with my studies AND it's 10:30pm should I study each chapter or just start answering questions and correcting?​

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Answer:

Depends

Explanation:

If you understand the content rush through questions. If you dont understand learn the key concepts of all the chapters then on the commute tomorrow test your self on the concepts. Good luck!

what are the state of equilibrium explain with the help of examples​

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Explanation:

The state of equilibrium refers to a condition in which an object or system is balanced, with no net external forces or torques acting upon it. In other words, the object or system remains at rest or continues its motion in a straight line at a constant velocity. There are two types of equilibrium: static equilibrium and dynamic equilibrium.

1. Static Equilibrium:

Static equilibrium occurs when an object is at rest and all the forces acting on it are balanced. This means that the net force and net torque on the object are both zero. An example of static equilibrium is a book sitting on a flat table. The weight of the book is balanced by the normal force exerted by the table, and there is no motion.

2. Dynamic Equilibrium:

Dynamic equilibrium occurs when an object is in motion with a constant velocity, and the net force and net torque on the object are zero. In this case, the object experiences balanced forces that result in uniform motion. An example of dynamic equilibrium is a car traveling at a constant speed on a straight road. The driving force applied by the engine is balanced by the resistive forces such as air resistance and friction, allowing the car to maintain a constant velocity.

It's important to note that equilibrium does not necessarily mean that all forces are zero, but rather that the sum of forces and torques acting on the object add up to zero. Equilibrium is a state of balance where there is no change in motion or rotation.

In summary, the state of equilibrium refers to a balanced condition in which the forces and torques acting on an object or system are balanced, resulting in either static or dynamic equilibrium. Examples of equilibrium include a book resting on a table in static equilibrium and a car traveling at a constant speed in dynamic equilibrium.

Answer:

dynamic equilibrium and static equilibrium are the 2 types of equilibrium

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