what refers to the loudest tone that is produced?

1. fundamental tone
2. obstructive tone
3. tenor tone
4. alto tone

Answer: 42.41 cm

Explanation:

The Stefan-Boltzmann law is a fundamental principle of thermodynamics that relates the energy radiated by a body to its temperature. By measuring the total energy emitted by a star, astronomers can calculate its effective temperature using the Stefan-Boltzmann law.

The Stefan-Boltzmann Law is a crucial tool in understanding and interpreting stellar properties. This law relates the luminosity (energy emitted per unit time) of a star to its temperature and size. Mathematically, it is expressed as:

L = σ × A × T^4

Where:
L is the luminosity of the star.
σ is the Stefan-Boltzmann constant (5.67 10-8 W m-2 K-4).
A is the surface area of the star (A = 4R2, where R is the radius).
T is the temperature of the star in Kelvin.

By using this law, astronomers can determine various properties of a star, such as its radius, temperature, and luminosity, by measuring either the temperature or luminosity and using the known values of the Stefan-Boltzmann constant and the star's surface area.

For example, if the temperature and luminosity of a star are known, the radius can be calculated by rearranging the equation:

R = sqrt(L / (4T4))
This allows them to determine the star's luminosity and radius, as well as other important parameters such as its mass and age. The law is particularly useful for understanding the behavior of different types of stars, from cool red dwarfs to hot blue supergiants. Overall, the Stefan-Boltzmann law is a key tool for astronomers in interpreting the complex properties of stellar objects.

Additionally, the Stefan-Boltzmann Law allows astronomers to classify stars based on their temperature and luminosity, enabling a better understanding of stellar evolution and the life cycle of stars.

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Answer:

Explanation:

When you put another light bulb in parallel with the other two, you are not going to get something for nothing. The current drain on the battery has to go up.

Let the lightbulbs have a a resistance of r. Two light bulbs with make the resistance go to 1/2 r. The lower the resistance, the more the current. When you put the third light bulb in, the resistance will go to 1/3 r.  So the current goes up.

If you put another resistor in series with x, the resistance adds. The total series resistance is 2x. The current reading will go down. The higher the resistance the lower the current.

Question 5: The average speed of the train as it moves from position x = 70m to x = 55m can be calculated by dividing the total distance traveled by the time taken.

Question 6: The displacement of the train from time t = 0s until t = 50s can be found by subtracting the initial position from the final position.

Question 7: The total distance traveled by the train from time t = 0s until t = 50s can be determined by summing up the magnitudes of all displacements.

Question 8: The slope of the line during the time interval t = 45s to t = 50s represents the velocity of the train during that time interval.

Question 5: To calculate the average speed, we divide the total distance traveled by the time taken. In this case, the total distance traveled is the difference between the initial position x = 70m and the final position x = 55m. The time taken is the duration of the motion.

Question 6: The displacement of the train is the change in its position from time t = 0s to t = 50s. It is given by the difference between the final position and the initial position.

Question 7: The total distance traveled by the train is the sum of the magnitudes of all the displacements during the time interval from t = 0s to t = 50s. This includes both the forward and backward motions.

Question 8: The slope of a line represents the rate of change of the dependent variable with respect to the independent variable. In this case, the line represents the position of the train as a function of time. The slope during the time interval t = 45s to t = 50s represents the velocity of the train during that interval.

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The correct answer is (c) tanθ = μk.

When a force F is applied to drag a box at a constant speed across a surface with a coefficient of kinetic friction μk, the force of friction acting on the box is given by:

F_friction = μk * N

where N is the normal force, which is equal to the weight of the box if it is placed horizontally.

To minimize the total force needed to drag the box at a constant speed, we need to apply the force at an angle θ such that the normal force N is minimized. This occurs when the force is applied perpendicular to the surface, i.e., when the angle between the force and the surface is 90 degrees.

The component of the force parallel to the surface is Fs = F * sinθ, and the component of the force perpendicular to the surface is Fp = F * cosθ.

Therefore, the normal force N is given by:

N = mg - Fp

where m is the mass of the box and g is the acceleration due to gravity.

Substituting Fp = F * cosθ, we get:

N = mg - F * cosθ

Substituting F_friction = μk * N, we get:

F_friction = μk * (mg - F * cosθ)

Since the box is moving at a constant speed, the total force applied must balance the force of friction:

F = F_friction

Substituting F_friction = μk * (mg - F * cosθ), we get:

F = μk * (mg - F * cosθ)

Rearranging this equation, we get:

F + μk * F * cosθ = μk * mg

Factoring out F on the left side, we get:

F * (1 + μk * cosθ) = μk * mg

Dividing both sides by (1 + μk * cosθ), we get:

F = (μk * mg) / (1 + μk * cosθ)

To minimize F, we need to maximize the denominator. This occurs when:

cosθ = -1/μk

Taking the inverse tangent of both sides, we get:

tanθ = μk

Therefore, the correct answer is (c) tanθ = μk.

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simple subtract and ummmmmm.....

Answer:

146 neutrons.

Explanation:

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Answer: The atomic number of uranium (see periodic table) is 92, and the mass number of the isotope is given as 238. Therefore, it has 92 protons, 92 electrons, and 238 — 92 : 146 neutrons.

Explanation:

Answer:

Explanation:

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Assuming that the electron-pair geometry of the two ball-and-stick representations is identical, the hybridizаtion of the centrаl аtom is sp².

The hybridization on the central atom would be governed by the type аnd number of electrons involved in the formаtion of the bonds between the centrаl аtoms аnd the outer аtoms.

Electron-pаir geometry determines the spаtiаl аrrаngement of а molecule's bonds аnd lone pаirs. If someone asked what the hybridization on the atom was, we would first draw the Lewis structure. We could then apply VSEPR to the Lewis structure to deduce that the molecular shape was linear and from this, we conclude that the hybridization of the atom is sp.

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Answer:

225 m//s

Explanation:

It ran 5m/s so 5x45=225

Answer:

225 meters

Explanation:

If it is running 5 meters per seconds, and it ran 45 seconds, you would need to multiple the seconds it ran by the speed per second: 5 • 45

5 • 45 = 225

If the engine of a personal watercraft suddenly shuts off, the answer to what happens next depends on the specific circumstances. In some cases, the operator may still be able to maneuver the vessel even with the engine off. This could be the case if the watercraft has enough momentum and direction to glide along without the engine.

However, in other cases, losing the engine may mean losing the ability to steer the vessel. This could result in the watercraft continuing to move in the direction it was going before the engine stopped. In this situation, the operator would have to rely on other methods to slow down or stop the vessel, such as using a manual kill switch or turning off the fuel supply.

Alternatively, if the engine fails completely and suddenly, the watercraft could come to a full stop fairly quickly, leaving the operator without any ability to steer. It is also possible that the vessel could slow down and start moving in a circular pattern, depending on factors like wind, waves, and current.

Ultimately, the key to staying safe while operating a personal watercraft is to be prepared for all scenarios and to have the necessary skills and equipment to handle unexpected situations like engine failure.

When operating a personal watercraft, if the engine shuts off, the correct answer is (b). You lose the ability to steer and the vessel will continue to move in the direction you were going. When the engine stops, the watercraft loses propulsion, which means there is no thrust being generated to move it forward or change its direction. As a result, the personal watercraft will continue to coast along the same path due to its momentum, making it difficult to steer or control. To regain control and steer the vessel, you need to restart the engine and generate enough thrust to maneuver effectively.

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Answer:

Comprobar explicación

Explanation:

Si el árbitro toma una decisión en el medio del juego, a pesar de estar equivocado, normalmente, como humano, las emociones están destinadas a superarlo, pero de acuerdo con el reglamento, hay conductas aceptables y una protesta llena de emociones. en el árbitro puede salirse de las manos y conducir a más castigos de acuerdo con los libros de reglas.

Después del partido, por lo general, aún me despediría y expresaría mi desagrado tan cortésmente como pueda, pero porque cuando uno se equivoca, las emociones que lo acompañan pueden volverse increíblemente incontrolables, por lo tanto, es mejor mantener el control y no obtener castigado aún más.

¡¡¡Espero que esto ayude!!!

Answer:

Heat vs temperature - Energy Education The core difference is that heat deals with thermal energy, whereas temperature is more concerned with molecular kinetic energy. Heat is the transfer of thermal energy, whereas temperature is a property the object exhibits.

Answer: 18km/hr

0.005km/s

1 sec --> 0.005

3600sec --> 0.005*3600 is 18

So, 18km/hr

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Here's the solution ~

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:5 \: m \: s {}^{ - 1} \)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:\dfrac{5}{1000} km \: {s}^{ - 1}\)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:\dfrac{5}{1000} \times 3600 \: km \: {h}^{ - 1}\)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{5}{5} \times 18 \: km \: h {}^{ - 1} \)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: 18 \: km \: h {}^{ - 1} \)

The mechanical advantage of a second class lever compares to the mechanical advantage of a third class lever is generally greater than the mechanical advantage of a third class lever.

In a second class lever, the load is located between the fulcrum and the effort, which means that the effort arm is longer than the load arm. This results in a mechanical advantage that is greater than one, meaning that the effort required to move the load is less than the weight of the load itself.

In contrast, in a third class lever, the effort is located between the fulcrum and the load, which means that the load arm is longer than the effort arm. This results in a mechanical advantage that is less than one, meaning that the effort required to move the load is greater than the weight of the load itself. However, third class levers are still useful in situations where a greater range of motion or speed is required.

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To test a Zener diode with a digital multimeter, follow these steps:

1. Turn off the power supply to the circuit.

2. Set your multimeter to the diode test mode. This is usually represented by a diode symbol on the multimeter dial.

3. Connect the black probe of the multimeter to the cathode end of the Zener diode and the red probe to the anode end of the diode.

4. Check the voltage reading on the multimeter. If the voltage reading is zero, the Zener diode is not conducting and is faulty. If the voltage reading is close to the Zener voltage rating, the Zener diode is good.

5. Reverse the probes and repeat the test. The voltage reading should be close to zero volts. If the voltage reading is still close to the Zener voltage rating, the Zener diode is faulty.

Note: Be sure to consult the datasheet of the Zener diode you are testing to ensure that you are using the correct voltage rating.

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Answer:

5524.8 m/s

Explanation:

Given that,

Altitude above the surface of earth is 6679 km, the Space Station can complete one orbit in 1.5 hours. We need to find the average speed of the ISS. The average speed of its orbit is given by :

\(v=\sqrt{\dfrac{GM}{R}}\)

R is distance from Earth

R = r + d, r is the radius of Earth

R = 6371  + 6679

R = 13050 km

So,

\(v=\sqrt{\dfrac{6.67\times 10^{-11}\times 5.972 \times 10^{24}}{13050\times 10^3}}\\\\v=5524.8\ m/s\)

or

Hence, the average speed of ISS is 5524.8 m/s.

Answer:

The value of g on the moon is 1.625 m/s2 and the value of the g on the jupiter is 2.528g.

Jupiter's surface gravity is 24.79/s or 2.528 g .

The acceleration due to gravity on the surface of the moon is approximately 1.625m/s .

hope this helps you

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The fraction of light from the Sun intercepted and reflected by the Earth is approximately 4.26 x 10⁻⁵.

To calculate the fraction of light from the Sun intercepted and reflected by the Earth, we need to compare the cross-section of the Earth to the area of a sphere centered on the Sun with a radius equal to the radius of Earth's orbit.

The cross-section of the Earth can be calculated as the area of a circle with radius REarth, which is option (c) R Earth.

The area of a sphere centered on the Sun with a radius r is given by 4πr², where r is the radius of the Earth's orbit. Therefore, the area of the sphere centered on the Sun with a radius equal to the radius of Earth's orbit is 4π(149.6 x 10⁶ km)²= 2.83 x 10²³ m².

The ratio of the cross-section of the Earth to the area of the sphere is A1/A2 = πREarth² / 4πr² = (REarth/r)². Using the radius of Earth's orbit in meters, r = 149.6 x 10⁹ m, and the radius of Earth, REarth = 6,371 km = 6.371 x 10⁶ m, we get A1/A2 = (6.371 x 10⁶ m / 149.6 x 10⁹ m)² = 4.26 x 10⁻⁵.

Therefore, by calculating we can say that the fraction of light is approximately 4.26 x 10⁻⁵.

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Answer:The object has negative acceleration and eventually stops.

Explanation:

Answer:not sure

Explanation:

Sorry:(

The case of 25 m/s top speed of the rollercoaster is correct because some energy were lost to friction while the calculated top speed of 32.8 m/s is for ideal case (when no energy is lost).

The velocity of the rollercoaster at the bottom is calculated by applying the principle of conservation of energy as follows;

potential energy of the rollercoaster at the top = kinetic energy of the rollercoaster at bottom

P.E (top) = K.E (bottom)

Note: the above is true, if and only if no energy is lost to friction.

mgh = ¹/₂mv²

gh = ¹/₂v²

2gh = v²

v = √2gh

where;

The velocity of the rollercoaster at the bottom is calculated as;

v = √ (2 x 9.8 x 55 )

v = 32.8 m/s

if Nemesis top speed at Alton's tower is 25 m/s which is less than the calculated value of 32.8 m/s, it simply implies that some of the potential energy of the rollercoaster at the top were lost to friction when it was moving to the bottom resulting in a smaller kinetic energy at the bottom compared to the initial potential energy at the top.

So the 25 m/s top speed is correct because some energy will be lost to friction.

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The complete question is below:

Nemesis at Alton towers has a 55 m drop. The rollercoaster has a mass of 8000 kg.  How fast will it travelling when it reaches the bottom?

When I checked on the Alton towers website it told me that Nemesis' top speed is

25 m/s. (less than what I calculated). My stats and calculations are correct...so

why is this the case?

reaction

Newtons third law states that for every action there is an equal but opposite reaction

and for that object (rocket, missile, jet,) as the engine is ignited the force of the burning fuel pushes backward while the rocket moves forward so the rate at which the fuel burns is equal to the rate at which the object moves forward

the force at which the burning fuel pushes backward is equal but opposite to the rate at which the object moves forward

To achieve a total resistance of 5114Ω using the resistors available to you, you need to select the appropriate combination of resistors and connect them in series or parallel.

Determine the resistances of the available resistors: Take note of the resistance values of each resistor you have at your disposal.

Identify the desired resistance: Confirm that the target resistance is indeed 5114Ω.

Evaluate resistor combinations: Look for possible combinations of resistors that, when connected in series or parallel, can add up to the desired resistance. You can use formulas for combining resistors in series and parallel:

Series connection: When resistors are connected in series, the total resistance is the sum of the individual resistances. If you have resistors with values R1, R2, R3, and so on, the total resistance (RTotal) can be calculated as RTotal = R1 + R2 + R3 + ...

Parallel connection: When resistors are connected in parallel, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances. If you have resistors with values R1, R2, R3, and so on, the total resistance (RTotal) can be calculated as 1/RTotal = 1/R1 + 1/R2 + 1/R3 + ...

Experiment and calculate: Start by trying different combinations of resistors, connecting them either in series or parallel, to see if you can achieve the desired resistance. You may need to use multiple resistors in combination to reach the target value.

Measure and verify: Once you have connected the resistors according to your calculations, use a multimeter or other appropriate measuring device to verify the actual resistance. This step is important to ensure that the achieved resistance matches the desired value.

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the transverse Wave which is Answer:2

Answer:

1

Explanation:

amplitude is the maximum distance from the rest of the particles. amplitude is thus measured from the rest position to the peak of a crest or of a trough.

as seen below, graph 1 has an amplitude of 1 while both graph 2 and 3 has an amplitude of 2.

At Position D, the Sun's most direct rays are hitting the equator on Earth.

The equator is a geographic coordinate that is defined as an imaginary line that stretches approximately 40,075 km or 24,901 miles across the Earth's surface. The equator is an imaginary circle that is equidistant from the North and South Poles. This circle divides the Earth into the Northern Hemisphere and the Southern Hemisphere.

In summary, the Sun's most direct rays hit the equator on Earth when it is at Position D.

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Answer:

I think the answer is Decreases the time that the egg slows down.

Explanation:

If not try it starts slowing down

O Increases the time that the egg slows down.

If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t². Then it takes 11 seconds for the velocity to reach 24 m/s. The correct option is D.

To find the time it takes for the velocity of the ball to reach 24 m/s, we need to solve for the time when the velocity function equals 24 m/s.

The velocity function is the derivative of the distance function, so we'll first find the derivative of the distance function s = 2t + t² with respect to time t:

ds/dt = d/dt(2t + t²)

ds/dt = 2 + 2t

Now we can set the velocity function equal to 24 m/s and solve for t:

2 + 2t = 24

Subtracting 2 from both sides:

2t = 22

Dividing both sides by 2:

t = 11

Therefore, it takes 11 seconds for the velocity to reach 24 m/s.

The correct answer is (d) 11 seconds.

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The Acceleration of the system is 6.41 m/s².

Given,

α= 15°, m₁ = 7kg

β= 65°, m₂ = 11 kg

Let, a be the acceleration and T is the tensions at the end it's the cord.

Let, the mass m₂ be coming down along the inclined plane along the inclined surface towards downward m₂g sin β and the tension in the upward direction,

Resultant force, m₂a=m₂g sin β -T

11a=((11) ×g sin 65°) -T  ...(i)

Now, considering the motion of m₁ which moves downwards, the forces are m₁g sinα, and T both are acting downwards.

Resultant force m₁a = m₁g sin α+T

7a =7g sin 15°+T  ...(ii)

Solving both the equations by adding them,

18a=11gsin 65°+7g sin 15°-T+T

18a=11gsin 65°+7g sin 15°=115.45

a=115.45/18=6.41 m/s²

Hence, the Acceleration of the system is 6.41 m/s².

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