what nineteenth-century english scientist offered proof that atoms existed?A. AristotleB. DemocritusC. John DAltonD. Isaac Newton

Answer:

Answer is A

Explanation:

Increase in wind

The percentage of acetic acid in vinegar is 4.36%

What is acetic acid?

The scientific name for acetic acid is ethanoic acid. It is an acidic, colorless liquid organic substance having the formula CH3COOH. Vinegar has a minimum of 4% acetic acid by volume, making acetic acid the primary component of vinegar besides water and trace elements.

Given,

Volume=  30.84 ml

Moles= 0.128

mass of vinegar= 5.441g

moles NaOH = 0.03084 ml x 0.128

M=0.00395

mass acetic acid = 0.00395 mol x 60.05 g/mol=0.237 g

Percentage of acetic acid:

= 0.237 x 100/ 5.441

= 23.7/5.441 = 4.36%

Hence, The percentage of acetic acid in vinegar is 4.36%

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Answer:

C. Chemical energy - Electrical energy - Sound energy

Explanation:

According to the law of conservation of energy, energy can be transformed i.e changed from one form to another. According to this question, a student builds an electrical circuit, which connects a battery to a siren. Based on this description, the electrical circuit uses ELECTRICAL ENERGY supplied by the CHEMICAL ENERGY in the battery cell.

The electrical energy in the circuit connects the CHEMICAL ENERGY in the battery to the siren, which makes the sound using SOUND ENERGY. In other words, the CHEMICAL ENERGY of the battery powers the ELECTRICAL ENERGY of the circuit to make SOUND ENERGY in the siren. Hence, the order of energy transformation is: Chemical energy - Electrical energy - Sound energy

Answer:

C. Chemical energy - Electrical energy - Sound energy

Explanation: I took the test:)

Answer:

3

Explanation:

The dissolution of lithium iodide (LiI) in water is exothermic, releasing heat energy.

When lithium iodide (LiI) dissolves in water, the process is exothermic, meaning it releases heat energy. This can be observed by the increase in temperature of the solution. Exothermic reactions involve the release of energy in the form of heat.

In the case of lithium iodide, as the ionic compound dissolves in water, the strong electrostatic forces between the lithium ions (Li+) and iodide ions (I-) are overcome. This allows the ions to separate and become surrounded by water molecules through a process called hydration.

The formation of new bonds between the ions and water molecules releases energy, resulting in an increase in the solution's temperature. Therefore, the dissolution of lithium iodide in water is an exothermic process.

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The internal energy of nitrogen in a state where the temperature is 500°C and the pressure is 14.7 psig is 120.28 kJ/kg and the specific volume of nitrogen in a state where the temperature is 500°C and the pressure is 14.7 psig is 150 ft³/lb.

Temperature (T) = 500°C

Pressure (P) = 14.7 psig

The internal energy and specific volume for nitrogen in a state where the temperature is 500°C and the pressure is 14.7 psig can be determined using the following formulae:

Internal energy (U) = Cp × (T-Tref)

Here, Tref = 298K (reference temperature)

Specific volume (v) = R × T / P

Molecular weight of Nitrogen (N2) = 28

The specific gas constant for Nitrogen (N2) = R / M = 296.8 / 28 = 10.6

Now, let's put these values in the formulae to get the desired results.Internal energy (U) = Cp × (T-Tref)

where, Cp = specific heat at constant pressure= 0.248 kJ/kg·K (for N2)Tref = 298K = 25°C= 500 + 273 = 773 K

Thus,Internal energy (U) = Cp × (T-Tref)= 0.248 kJ/kg·K × (773 K - 298 K)= 120.28 kJ/kg

Specific volume (v) = R × T / P

where, R = specific gas constant for Nitrogen (N2)= 10.6T = temperature= 500 + 273 = 773 KP = pressure= 14.7 psig = 14.7 + 15 = 29.7 psi (absolute pressure) = 204.82 kPa

Thus,Specific volume (v) = R × T / P= 10.6 × 773 / 204.82= 39.9 m³/kg= 150 ft³/lb

Therefore, the internal energy of nitrogen in a state where the temperature is 500°C and the pressure is 14.7 psig is 120.28 kJ/kg and the specific volume of nitrogen in a state where the temperature is 500°C and the pressure is 14.7 psig is 150 ft³/lb.

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Removing a parallel circuit won't stop the circuit from working, but it won't be a good idea to remove that component as it would not allow current to flow through the circuit when an equal amount of current is passed through the circuit.

Parallel Circuit                  

All components in a parallel circuit are connected to the same electrical nodes. Since all parallel components share the same voltage, the total current is equal to the sum of all the branch currents.

When one pathway is blocked, electricity continues to flow in a parallel circuit. Multiple-bulb lighting fixtures is the most common example. The light fixture functions even if just one of the fixture's bulbs fails.

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Soil erosion is basically the soil being deteriorated by the gradual impact of water or wind to it, being a very mechanical situation, where water or wind will hit the soil, detaching some particles and making the soil weaker. The main cause will be hits from water or wind. Deforestation will have a huge impact on erosion, since the soil where trees are taken down is more likely to receive impacts from wind or water, if the trees were left in their place, they would be used as a "shield" for the soil

Answer:

Water plays many important roles in the body including,flushing waste from the body,regulating body temperature,transportation of nutrients and is necessary for digestion.No wonder it is considered "essential"!.Plain water is the best choice for hydrating the body.

Explanation:

hope it helps you><

Answer:

covalent bond

Explanation:

they allow donation of electrons

Answer:

Because in order to have cis or trans configuration both carbon of alkene need to have a hydrogen

**MARK BRAINLIEST**

Avogadro's number is approximately 6.022 × 10^23 formula units per mole.

Given that there are 3.0 × 10^23 formula units of KI, we can calculate the number of moles of KI by dividing the number of formula units by Avogadro's number:

Number of moles = (3.0 × 10^23 formula units) / (6.022 × 10^23 formula units/mol)

Number of moles ≈ 0.498 mol

To find the mass of KI, we can use the molar mass of KI:

Mass of KI = Number of moles × Molar mass

Mass of KI = 0.498 mol × 166 g/mol

Mass of KI ≈ 82.668 g

Therefore, there are approximately 82.668 grams of KI in the sample.

Answer:

Liquid

Explanation:

Answer:

hurricane

Explanation:

Stable isotopes of an element have the same number of protons in their atomic nuclei, but a different number of neutrons.

As a result, isotopes of an element have the same atomic number and therefore the same chemical properties, but they have different atomic masses.

The six stable isotopes of selenium have the same number of protons (34) but different numbers of neutrons, which results in different atomic masses. These isotopes therefore have the same atomic structure in terms of the number of protons, electrons and the arrangement of electrons in their shells. However, the difference in the number of neutrons results in a difference in the atomic mass of each isotope, which affects its physical properties, such as density and boiling point.

In conclusion, the stable isotopes of selenium have the same atomic structure in terms of protons, electrons, and electron arrangements, but differ in the number of neutrons and thus the atomic mass.

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Answer:

you can get these 38 point after giving answer of questions.

your question was incomplete.............. you haven't mentioned any required information

Answer:

what to do in this question

Answer:

9.370 x 10 to the 23 molecules

Explanation:

91.72/1 x 1 mole Co/58.933g x 6.02 x 10 to the 23/1 mole Co

Answer:

Explanation:

Mass 1 mole of CO

C = 12

O = 16

m = 28

Mols of 91.72 grams

m = given Mass / Molar Mass

m = 91.72 / 28

m = 3.28 mols

Molecules

1 mol of anything is 6.02 * 10^23 molecules (in this case)

3.28 mol of CO = x

1/3.28 = 6.02*10^23/x      Cross multiply

x = 3.28 * 6.02 * 10^23

x = 1.97 * 10^24

NaBr: Nearly neutral, K2SO3: Basic, NH4NO2: Acidic, K2HPO4: Basic

NaBr: Sodium bromide is a salt formed from a strong base (NaOH) and a strong acid (HBr). Salts of strong acids and strong bases are neutral, so NaBr is nearly neutral.

K2SO3: Potassium sulfite is a salt formed from a strong base (KOH) and a weak acid (H2SO3). Salts of strong bases and weak acids are basic, so K2SO3 is basic.

NH4NO2: Ammonium nitrite is a salt formed from a weak base (NH3) and a weak acid (HNO2). Salts of weak acids and weak bases can exhibit acidic or basic properties depending on their relative strengths. In this case, ammonium ions (NH4+) act as a weak acid, making NH4NO2 acidic.

K2HPO4: Dipotassium hydrogen phosphate is a salt formed from a strong base (KOH) and a weak acid (H3PO4). Similar to (b), salts of strong bases and weak acids are basic. Therefore, K2HPO4 is basic.

The predicted acidity or basicity of the given solutions is as follows: (a) nearly neutral, (b) basic, (c) acidic, and (d) basic. The nature of the solutions depends on the specific salts formed and the relative strengths of the acids and bases involved.

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Answer:

Avogadro's law, a statement that under the same conditions of temperature and pressure, equal volumes of different gases contain an equal number of molecules.

Answer:

6.02 x 10^23 moles of any substance is one mole.

Explanation:

1.802molS

This is found by using the conversion factor: 1mol/32.07gS. This factor can be used to convert from grams of sulfur (given in the problem) to moles of sulfur. To use this conversion factor, divide 57.8gS by 32.07gS to find the number of moles of sulfur: 57.8gS / 32.07gS = 1.802molS.

Answer:

(i) In a bond amortization schedule, the book value represents the remaining amount of the bond principal that hasn't been paid off at a given point in time. When a bond is first issued, its book value equals its face value. As payments are made over the life of the bond, a portion of these payments reduces the book value. By the end of the bond's life, its book value will be zero, as the entire principal will have been paid off.

(ii) The formula for the book value B at time k, where k is the number of periods elapsed, is B = C + Cg - jan-kj.

Here:

- C is the redemption amount,

- g is the modified coupon rate per period,

- j is the yield rate per period, and

- a_n-kj is the present value of an annuity immediate with n - k periods at the yield rate j.

This formula states that the book value at any time k is the redemption amount plus the present value of the future coupon payments (Cg), minus the present value of the annuity that represents the repayments of the bond (jan-kj).

The amortized amount at time k is the change in the book value from time k-1 to time k, plus the coupon payment at time k. It represents the portion of the bond's principal (and interest) that has been repaid up to time k.

(iii) If K is defined as the present value of the redemption value C, according to the Makeham formula, (C-K) would represent the difference between the redemption value of the bond and its present value. This difference is the amount of interest that will accumulate over the life of the bond. In other words, (C-K) can be interpreted as the total interest that the bondholder will earn from holding the bond until redemption, assuming that all coupon payments are reinvested at the yield rate j.

Explanation:

The NaOH solution has a 159.75 mL capacity.1.500 M H3PO4 solution in 25.00 mL.

How much NaOH was used for the titration?

In a titration of the two chemicals, 26.60 mL of sulfuric acid is neutralized by 32.20 mL of sodium hydroxide that has a concentration of 0.250 mM.

In a titration of the two chemicals, 26.60 mL of sulfuric acid is neutralized by 32.20 mL of sodium hydroxide that has a concentration of 0.250 mM.

The percent volume/volume of a solution can be calculated using the following formula, which bases its results on the milliliter as the unit of volume (v):

As mL of solute per 100 mL of solution, % v/v is expressed.

X% = 5.0 mL HCl/100 mL of solution is a good illustration.

X/100 = 5.0/100. 100X = 500. \sX = 5.0%%

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Answer:

Fusion doesn't produce runway chain reactions the way fission can, so there's no need to worry about meltdowns.

The end of a very long 5-mm-diameter rod is held at 124°C. The surface of the rod is exposed to ambient air at 30°C, with a convective heat transfer coefficient of 100 W/m2K. Determine the temperature at a radial distance of 2.5 mm from the rod's center. The thermal conductivity of the rod is 15 W/mK.b) What is the temperature gradient in the rod at this location?c).

What is the heat flux at this location?The temperature at a radial distance of 2.5 mm from the rod's center is 79.58°C.The solution for this problem can be found by following the steps below:Solution:a) The temperature of the rod, T, can be calculated using the formula for one-dimensional conduction:q/A = -k (d T/d r)whereq is the heat flux,A is the cross-sectional area of the rod,r is the radial distance from the center of the rod,k is the thermal conductivity of the rod,and T is the temperature of the rod.

Taking the boundary condition into account,T(r=0) = 124°CandT(r=2.5 mm) = 30°C, the solution to the differential equation is:T = T0 + (T1 - T0) (r/R)2whereT0 = 30°CT1 = 124°CR = 2.5 mm/2 = 1.25 mmso,T = 30 + (124 - 30) (r/1.25)2 = 30 + 78 (r/1.25)2at r = 2.5 mm,T = 79.58°Cb) The temperature gradient, d T/d r, is given by the derivative of the above equation:d T/d r = 124 (r/1.25)2 / 1.25where d T/d r = 98.72°C/mat r = 2.5 mmc) The heat flux, q/A, is given by the Fourier's law of heat conduction:q/A = -k (d T/d r)whereq/A = -15 (98.72/1000) = -1.48 W/m2at r = 2.5 mmTherefore, the temperature at a radial distance of 2.5 mm from the rod's center is 79.58°C, the temperature gradient in the rod at this location is 98.72°C/m, and the heat flux at this location is -1.48 W/m2.

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