Answer:
Explanation:
Given:
m= 172 kg
g = 9.8 m/s²
___________
F - ?
F = m*g = 172*9.8 ≈ 1690 N
(ii) Let R be a rotation and S be a reflection of the euclidean plane E. Give a precise deion of RS, relating it to the classification of isometries of E². Be careful of special cases.
RS is a composition of rotation and reflection in the Euclidean plane E². The precise description of RS depends on the specific properties of the rotation R and reflection S.
In general, if R and S have the same axis or line of symmetry, the composition RS results in a translation. If R and S have intersecting lines of symmetry, RS yields a glide reflection. If R and S have perpendicular lines of symmetry, RS produces a rotation.
It is important to consider special cases, such as parallel lines of symmetry, coinciding axes, or perpendicular lines of reflection, as they may lead to different outcomes. The classification of isometries in E² involves understanding how rotations and reflections combine to create different transformations in the plane.
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Which phrase best describes what the graph for
average low temperatures would look like?
rk
O It would run parallel to and below the high
temperature graph.
O It would be a flat line that crosses the high
temperature graph.
O It would be the opposite of the high temperature
graph.
It would be a flat line below the high temperature
graph.
Answer:
i dont know sir
Explanation:
It has been argued that power plants should make use of off-peak hours (such as late at night) to generate mechanical energy and store it until it is needed during peak load times, such as the middle of the day. one suggestion has been to store the energy in large flywheels spinning on nearly frictionless ball-bearings. consider a flywheel made of iron, with a density of 7800 kg/m3 , in the shape of a uniform disk with a thickness of 11.6 cm .part a
what would the diameter of such a disk need to be if it is to store an amount of kinetic energy of 13.7 mj when spinning at an angular velocity of 92.0 rpm about an axis perpendicular to the disk at its center?part b
what would be the centripetal acceleration of a point on its rim when spinning at this rate?
The diameter of the disk would need to be approximately 1.08 m to store 13.7 MJ of kinetic energy when spinning at 92.0 rpm. The centripetal acceleration of a point on the rim of the disk would be approximately 332.6 m/s².
The moment of inertia of a uniform disk rotating about an axis perpendicular to the disk through its center is given by the formula:
I = (1/2) * M * R²
where I is the moment of inertia, M is the mass of the disk, and R is the radius of the disk.
The mass of the disk can be calculated using its volume and density:
M = ρ * V =
= ρ * π * R² * h
where ρ is the density of the iron, π is the mathematical constant pi, R is the radius of the disk, and h is the thickness of the disk.
Substituting the given values, we get:
M = 7800 kg/m³ * π * (0.116 m/2)² * 0.116 m
M = 8.4 kg
The kinetic energy of the spinning disk can be calculated using the formula:
K = (1/2) * I * ω²
where K is the kinetic energy, I is the moment of inertia, and ω is the angular velocity of the disk.
Substituting the given values, we get:
13.7 MJ = (1/2) * (8.4 kg * (0.116 m/2)²) * (92.0 rpm * 2π/60)²
Solving for R, we get:
R = 0.539 m
The centripetal acceleration of a point on the rim of the disk can be calculated using the formula:
a = ω² * R
where a is the centripetal acceleration, ω is the angular velocity of the disk, and R is the radius of the disk.
Substituting the given values, we get:
a = (92.0 rpm * 2π/60)² * 0.539 m
a = 332.6 m/s²
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An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface charge density 4.00×10−12 C/m2 . what is the speed of the electron when it is 7.00×10−2 mm from the sheet? express your answer to three significant figures and include the appropriate units. vv = nothingnothing
The values into the equation for the speed of the electron v = sqrt((2 × q × V₂) / m), q = -1.6×10^(-19) C (charge of an electron). m = 9.11×10^(-31) kg (mass of an electron).
To find the speed of the electron when it is at a distance of 7.00×10^(-2) mm from the charged sheet, we can use the principles of electrostatics and energy conservation.
The electric potential energy between the electron and the charged sheet can be calculated using the formula:
Electric Potential Energy (U) = q × V
where q is the charge of the electron and V is the electric potential.
The electric potential (V) at a distance r from the sheet can be determined using the formula:
V = (σ / (2ε₀)) × (1 - sqrt(1 + (2ε₀ × E × r) / σ))
where σ is the surface charge density of the sheet, ε₀ is the permittivity of free space, and E is the electric field intensity.
First, let's calculate the electric potential at a distance of 0.470 m from the sheet:
V₁ = (4.00×10^(-12) C/m^2 / (2ε₀)) × (1 - sqrt(1 + (2ε₀ × E × 0.470 m) / (4.00×10^(-12) C/m^2))
where ε₀ = 8.85×10^(-12) C^2/(N·m^2).
Using this value of electric potential, we can determine the electric potential energy at the initial distance (U₁) and the final distance (U₂). Since the electron is released from rest, the initial potential energy is equal to the total energy (U₁ = q × V₁). At the final distance, all of the potential energy is converted into kinetic energy (U₂ = 0.5 × m × v²), where m is the mass of the electron and v is its speed.
Since energy is conserved, we can equate U₁ to U₂:
q × V₁ = 0.5 × m × v²
Rearranging the equation and solving for v, we get:
v = sqrt((2 × q × V₁) / m)
Now we have all the necessary components to calculate the speed of the electron at a distance of 7.00×10^(-2) mm from the sheet.
First, convert the distance to meters:
r = 7.00×10^(-2) mm = 7.00×10^(-5) m
Next, calculate the electric potential at this distance:
V₂ = (4.00×10^(-12) C/m^2 / (2ε₀)) × (1 - sqrt(1 + (2ε₀ × E × 7.00×10^(-5) m) / (4.00×10^(-12) C/m^2))
Then, substitute the values into the equation for the speed of the electron:
v = sqrt((2 × q × V₂) / m)
Substitute the known values:
q = -1.6×10^(-19) C (charge of an electron)
m = 9.11×10^(-31) kg (mass of an electron)
Solve for v using these values, and round your answer to three significant figures. The unit for the speed of the electron will be meters per second (m/s).
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Meadow voles are small mouse-like animals that eat plants and insects. Their niche in an ecosystem is a
A.
omnivore.
B.
herbivore.
C.
producer.
D.
scavenger.
Answer:
B. herbivore.
Explanation:
Meadow voles primarily consume plants, such as grasses, herbs, and bark, although they may also eat insects occasionally. As a result, their niche in an ecosystem is that of a herbivore, which is an organism that consumes primarily plants.
A metal spoon is put in a cup of hot tea and then put it into the mouth. The spoon is not very hot, but the tea is much hotter. Why?
Fighter jets on aircraft carriers are accelerated down a 270 foot "runway" in two seconds when they are taking off. A fully loaded, combat ready F-15 has a maximum take-off weight of 62,000 pounds. To ensure the pilot can reach sufficient velocity within 2 seconds a pneumatic cannon propels the plane down the runway. If this same cannon was used to launch your Toyota Corolla (mass is 2646lbs), how fast in miles per hour would you be going after reaching the end of the runway?
The speed of the Toyota Corolla would have been 143.9 mph.
What is the acceleration of the F-15?
The acceleration of the F-15 can be calculated as follows:
Acceleration = Velocity Change / Time = (Take-off Speed) / Time
where;
Take-off Speed = √(2dg /t²)
Take-off Speed = √(2 x (270 ft) x 32.2 ft/s² / (2 s)²)
T = √(17496) = 131.6 ft/s
Acceleration = Velocity Change / Time
= (131.6 ft/s) / (2 s) = 65.8 ft/s²
We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:
Final Velocity = Initial Velocity + Acceleration x Time
where;
Initial Velocity = 0 (because the car is not moving initially), Time = 2 sFinal Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s
Finally, we can convert the velocity from feet per second to miles per hour:
Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)
= 131.6 ft/s x (1 hour/3600 s) x (5280 ft/mile)
= 143.9 mph
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what is a rocket engine that fires against the direction a spacecraft is headed so the spacecraft slows down?
The rocket engine that fires against the direction a spacecraft is headed so the spacecraft slows down is called Retro engine.
Spacecraft are the space automobiles that might be capable of flying out of doors of the Earth’s ecosystem in the area. They offer us a method of transportation from the Earth to the area and objects in it. There may be numerous spacecraft that are familiar to most of people e.g. Apollo 11 which took Neil Armstrong and his group to the Moon.
Crewed Spacecraft – Crewed spacecraft are the ones that carry people to the area. There have been several crewed spacecraft to the area consisting of Vostok 1 – the first crewed spacecraft in records dispatched by way of the United States of America.
Earth-Orbit Satellites – all of the satellites, which orbit across the Earth, fall in this class. The maximum tremendous satellite in orbit on the Earth is Hubble Telescope.
Space Probe – these are unmanned spacecraft that might be fitted with medical instruments for exploring objects in space e.g. planets, Moon, and solar.
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How do I do this page of this worksheet titled “Modeling waves through various mediums”. Just tell me the answers please
A medium is the substance through which a wave travels. Mediums include gases (such as air), liquids (such as water), and solids (such as ropes).
What are the different types of mediums for waves?The medium can be solid, liquid, or gas, and the speed of the wave is determined by the material qualities of the medium. Light, on the other hand, is not a mechanical wave; it may pass through a vacuum, such as the empty areas of space.
Sound waves move the slowest through gases, the fastest through liquids, and the fastest through solids among the three media (gas, liquid, and solid). The speed of sound is also affected by temperature. Gases: The speed of sound is determined by the qualities of the medium through which it travels.
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If an electron (with a charge of 1.6 x10−19c) Experiences a force of 500 N at a certain point in an electric field, then find the strength of the electric field in that location
Answer:
3.125×10²¹ N/C
Explanation:
Electric Field: This can be defined as the force experienced per unit charge. The S.I unit of electric Field is N/C
Applying,
E = F/q.................. Equation 1
Where E = Electric Field, F = Force experienced, q = Charge of an electron.
From the question,
Given: F = 500 N, q = 1.6×10⁻¹⁹ C
Substitute these values into equation 1
E = 500/(1.6×10⁻¹⁹)
E = 312.5×10¹⁹
E = 3.125×10²¹ N/C
write any four importance of pressure
Answer:
Here is your ans
Explanation:
hope it helps you tq
If a snail travels at 5 m/s, how far will it travel in 90 seconds?
Answer:
in 90 seconds It'll travel 450m At constant speed of 5m/s
Answer:
d = 450 m
Explanation:
d
use the formula v = ----
t
v = 5 m/s
t = 90 seconds
d
5 m/s = -------------
90 sec
d = 5 m/s ( 90 sec)
d = 450 m
An electric field of 4.0 muV/m is induced at a point 2.0 cm from the axis of a long solenoid (radius = 3.0 cm, 800 turns/m). At what rate is the current in the solenoid changing at this instant?
The answer should be 0.40 A/s
The rate at which the current in the solenoid is changing at this instant is 4.4 A/s.
To determine the rate at which the current in the solenoid is changing, we can use Faraday's law of electromagnetic induction. According to Faraday's law, the induced electromotive force (emf) is equal to the negative rate of change of magnetic flux through a circuit. In this case, the solenoid acts as a circuit.
The induced electromotive force (emf) is given by:
emf = -dΦ/dt
Where:
emf is the induced electromotive force,
dΦ/dt is the rate of change of magnetic flux.
For a long solenoid, the magnetic flux (Φ) can be calculated as:
Φ = B * A
Where:
B is the magnetic field strength,
A is the area of the solenoid.
The magnetic field strength inside a solenoid is given by:
B = μ₀ * n * I
Where:
μ₀ is the permeability of free space (4π × 10^-7 T·m/A),
n is the number of turns per unit length (turns/m),
I is the current flowing through the solenoid.
Let's calculate the magnetic field strength (B) inside the solenoid:
B = μ₀ × n × I
= (4π × 10^-7 T·m/A) × (800 turns/m) × I
= (3.1831 × 10^-4) × I T
The area (A) of the solenoid can be calculated using the formula for the area of a circle:
A = π × r^2
Where:
r is the radius of the solenoid.
Let's calculate the area (A) of the solenoid:
A = π × r^2
= π × (0.03 m)^2
= 0.002827 m^2
Now, substitute the values of B and A into the formula for magnetic flux:
Φ = B × A
= (3.1831 × 10^-4) × I T × 0.002827 m^2
= 9.0 × 10^-7 × I Wb
Next, we differentiate the magnetic flux (Φ) with respect to time (t) to find the rate of change of magnetic flux:
dΦ/dt = d/dt (9.0 × 10^-7 × I)
= 9.0 × 10^-7 × dI/dt Wb/s
Finally, we can equate the rate of change of magnetic flux (dΦ/dt) to the induced electromotive force (emf) given in the problem statement:
emf = -dΦ/dt
= -9.0 × 10^-7 × dI/dt Wb/s
Given that the induced electromotive force (emf) is 4.0 μV/m = 4.0 × 10^-6 V/m, we can solve for the rate of change of current (dI/dt):
4.0 × 10^-6 V/m = -9.0 × 10^-7 × dI/dt
\(\frac{dI}{dt} = \frac{-(4.0) (10^-6 V/m)}{(9.0) (10^-7)} = -4.4 A/s\)
Therefore, the rate at which the current in the solenoid is changing at this instant is 4.4 A/s.
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a) The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as: 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.
Using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.
Given:
Voltage input (V) = 30V
Initial speed (w) = 0
Step size (h) = 0.4s
Time at which speed is to be determined (t) = 0.8s
We need to determine the speed (w) at t = 0.8s using Heun's method.
We have k₁ = f(t₁, W₁) = 0.02 + 0.06w₁ (using the given equation)
At t = 0 and w = 0 (initial conditions), we have:
k₁ = 0.02 + 0.06(0) = 0.02
We have k₂ = f(t₁ + h, w₁ + k₁h) = 0.02 + 0.06(w₁ + 0.02h)
So, at t = 0.4s and w = 0 (initial conditions), we have:
k₂ = 0.02 + 0.06(0.02 * 0.4) = 0.02 + 0.00048 = 0.02048
So, W₂ = w₁ + (k₁ + k₂)(h/2)
= 0 + (0.02 + 0.02048)(0.4/2)
= 0.04048(0.2)
= 0.008096
Therefore, using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.
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The complete question is:
The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.4 s, determine the speed w at t = 0.8 s by using the Runge-Kutta 2nd order Heun's method. Heun's method: Wi+1=W₁ = w₁ + (-/-^₁ + = -K ₂ ) h where, k₁ = f(t₁, W₁) and k₂ = f(t₁ + h, w₁ + k₁h), the speed (w) at t = 0.8s is approximately 0.0081.
what is the greatest distance you can be from base camp at the end of the third displacement regardless of direction
To determine the greatest distance you can be from the base camp at the end of the third displacement, regardless of direction, we need more specific information about the magnitudes and directions of the displacements.
Displacement is a vector quantity that has both magnitude and direction. The distance covered during multiple displacements depends on the individual magnitudes and directions of each displacement. Without specific values, it is not possible to determine the exact greatest distance from the base camp.
If you provide the magnitudes and directions of the three displacements, I can help you calculate the total distance and determine the maximum possible distance from the base camp at the end of the third displacement.
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what frequency will an observer approaching a stationary 1000 hz sound source hear if the speed of the observer is twice the speed of sound?
The observer hears a frequency of 1715 Hz if the speed of the observer is twice the speed of sound as it depends on the speed of the observer, the speed of the sound, and the frequency of the sound.
In this case, the observer is approaching the sound source at a speed twice the speed of sound. To calculate the frequency the observer will hear, we can use the formula given below:
frequency heard = (v ± u) / (v ± us) * frequency emitted where
v is the speed of sound
u is the speed of the observer
f emitted is the frequency of the sound emitted
The frequency of the sound source is given as 1000 Hz. The speed of sound in air is approximately 343 m/s. Therefore, we can calculate the frequency heard by the observer as follows:
f heard = (v + u) / (v + us) * f emitted
f heard = (343 + (2 × 343)) / (343 + (2 × 343 / 343)) * 1000
f heard = 1715 Hz
In physics, the Doppler effect is the change in frequency of a wave in relation to an observer who is either moving toward the source of the wave or away from it. When an observer is moving toward a stationary sound source, he hears a higher frequency, and when he moves away from the sound source, he hears a lower frequency.
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In addition to 1 m = 39.37 in, the following exact conversion equivalents are
given: 1 mile = 5280 ft, 1 ft = 12 in, 1 hr = 60 min, and 1 min = 60 s. If a
particle has a velocity of 8.4 miles per hour, its velocity, in m/s, is closest to
Answer:
3.76 m/s.
Explanation:
Velocity in mile per hour (mph) = 8.4 miles per hour
Velocity in metre per second (m/s) =?
Next, we shall convert 8.4 mph to ft/h. This can be obtained as follow :
1 mph = 5280 ft/h
Therefore,
8.4 mph = 8.4 mph / 1 mph × 5280 ft/h
8.4 mph = 44352 ft/h
Next, we shall convert 44352 ft/h to in/h. This is illustrated below:
1 ft/h = 12 in/h
Therefore,
44352 ft/h = 44352 ft/h / 1 ft/h × 12 in/h
44352 ft/h = 532224 in/h
Next, we shall convert 532224 in/h to m/h. This can be obtained as follow:
39.37 in/h = 1 m/h
Therefore,
532224 in/h = 532224 in/h / 39.37 in/h × 1 m/h
532224 in/h = 13518.51664 m/h
Next, we shall convert 13518.51664 m/h to m/min. This is illustrated below:
1 m/h = 1/60 m/min
Therefore,
13518.51664 m/h = 13518.51664 m/h / 1 m/h × 1/60 m/min
13518.51664 m/h = 225.30861 m/min
Finally, we shall convert 225.30861 m/min to m/s. This is illustrated below:
1 m/min = 1/60 m/s
Therefore,
225.30861 m/min = 225.30861 m/min / 1 m/min × 1/60 m/s
225.30861 m/min = 3.76 m/s
Therefore,
8.4 miles per hour is equivalent to 3.76 m/s.
Unit conversion does not change the real value. The velocity of the particle, when converted to meters per sec, is 3.756.
What is Units conversion?Unit conversion is a way of converting some common units into another without changing their real value. for, example, 1 centimeter is equal to 10 mm, though the real measurement is still the same the units and numerical values have been changed.
In order to convert the unit of velocity, we will first convert miles to meters and then, hours to seconds.
As it is given to us,
1 mile = 5280 ft
1 ft = 12 inches
1 m = 39.37 in
Now, since 1 m = 39.37 inches, therefore
\(1\rm\ in =\dfrac{1}{39.37}\ m\)
Converting a mile to meter,
\(1\rm\ miles = 5280\ ft \times 12\ inches\times \dfrac{1}{39.38} m\\\\1\ miles = 1609.652\ m\)
Converting hours to seconds
\(1\rm\ hour = 60\ minutes \times 60\ seconds\\\\1\ hour = 3600\ seconds\)
Now, converting the velocity we will get,
\(1 \rm\ \dfrac{miles}{hour} = \dfrac{1609.652}{3600}\ \dfrac{m}{s}\\\\1 \rm\ \dfrac{miles}{hour} =0.447\ \dfrac{m}{s}\)
Now, as given to us the velocity of a particle is 8.4 miles\hour, therefore,
\(8.4 \rm\ \dfrac{miles}{hour} =8.4 \times 0.447\ \dfrac{m}{s}\\\\8.4 \rm\ \dfrac{miles}{hour} =3.756\ \dfrac{m}{s}\\\\\)
Hence, the velocity of the particle when converted to meters per sec is 3.756.
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a 3.1-kg object falls vertically downward in a viscous medium at a constant speed of 2.5 m/s. how much work is done by the force the viscous medium exerts on the object as it falls 85 cm?
The work is done by the force the viscous medium exerts on the object as it falls 85 cm is -26.35 joules.
The mass of the object is m = 3.1kg
The speed of fall is v = 2.5 m/s
The depth of fall is d = 85cm
Now here given that the velocity is constant, then the work energy is zero.
So, work done by the potential energy of the object and that of the viscous liquid we have
W = Wv + Wp
Where Wv is work done by viscous liquid and
Wv is the work done by the object
Wp = mgd
So
0 = Wv + mgd
Wv = -mgd
substituting values
Wv = -3.1x10x85
Wv = 26.35 joules
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Help with this question plz
Answer:
it would be 24 miles
Explanation:
6x4 to get your answer because he is going four different ways north,west,south,and east
HELP!!!! NO LINKS!! Order the events that occur in the removal of thermal energy from an object by a refrigerator.
Answer:
Thermal energy is transferred from the warm object to the coolant in the refrigerator; coolant is compressed and the coolant's temperature rises (work is done on the coolant); thermal energy is transferred from the warm coolant to the outside air; the coolant expands as it passes through the expansion valve and cools.
Explanation:
hope this helps
Thermal energy is transferred from the hot object to the coolant in the refrigerator where the coolant is compressed and the temperature of the coolant rises, so thermal energy is transferred from the hot coolant to the outside air, the coolant expands as it passes through the expansion valve and is cooled.
How is thermal energy transferred in a refrigerator?An evaporator which contains a substance called refrigerant, that evaporates, turning from liquid to gas inside the coil which is located inside the freezer or refrigerator compartment. It transfers thermal energy from the surroundings to the refrigerant molecules.
As a liquid, the refrigerant absorbs thermal energy from the cold air inside the refrigerator and turns into a gas, while as a gas, it transfers thermal energy to the warm air outside the refrigerator and turns back into a liquid.
Thus, thermal energy is transferred from the hot object to the coolant in the refrigerator where the coolant is compressed and the temperature of the coolant rises, so thermal energy is transferred from the hot coolant to the outside air, the coolant expands as it passes through the expansion valve and is cooled.
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it is the environment where communication takes place
wo stars orbit their common center of mass as shown in the diagram. the masses of the two stars are 3m and m. the distance between the stars is d. what is the value of the gravitational potential energy of the two star system?group of answer choices
The value of the gravitational potential energy of the two star system is -(GM²/d²), the correct answer is (E)
The gravitational potential energy of the two-star system can be calculated using the formula:
U = -G(m₁m₂/r)
where G is the gravitational constant, m₁ and m₂ are the masses of the stars, and r is the distance between them.
In this case, one star has a mass of 3M and the other has a mass of M. The distance between them is d. We can calculate the position of the center of mass of the system using:
r = (3Md)/(3M + M) = (3/4)d
This means that each star is at a distance of (1/4)d from the center of mass. Using this information, we can calculate the gravitational potential energy of the system as:
U = -G(3MM ÷ (1/4)d) - G(M3M ÷ (1/4)d)
U = -G(12M²/d) - G(9M²/d)
U = -G(21M²/d)
Therefore, the gravitational potential energy of the two-star system is -(GM²/d) multiplied by 21. Thus, the correct answer is option (E), -(GM²/d²).
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The complete question is:
Two stars orbit their common center of mass as shown in the diagram below. The masses of the two stars are 3M and M. The distance between the stars is d.
What is the value of the gravitational potential energy of the two star system?
A) -(GM²/d)
B) (3GM²/d)
C) -(GM²/d²)
D) -(3GM²/d)
E) -(GM²/d²)
PLSSSSS HELPPPPPPP QUICKKKK
Because all movement begin in the spine and radiate through the body.
option A.
What controls moment of the body?The brain, situated in the cranial cavity is an important internal organ. It is the control center of our body. It controls the movements and all that we do.
The component of the central nervous system are;
the brain and the spinal cordThe spinal cord plays a crucial role in coordinating movement and relaying signals between the brain and the rest of the body.
So we can conclude that paralysis often results from severe spinal injuries because the spinal cord is a critical pathway for transmitting signals between the brain and the rest of the body.
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What happens when a rubber rod is rubbed with a piece of fur, giving it a negative charge?.
Answer:
Solution: When an ebonite rod is rubbed with fur, fur loses electrons and ebonite rod gains electrons. fur becomes positively charged and rod becomes negatively charged.
Explanation:
HOP3 IT HELP^_^
THANKS^_^
A whale swims at a constant speed of 8 m/s for 17 s. What distance did the whale travel in km?
Answer:
0.136 kmExplanation:
whale speed = 8 m/s for 17 sec.
find distance traveled in km
distance = velocity x time
= 8 m/sec. x 17 sec.
= 136 meters x 1 km
1000 meters
= 0.136 km
Do you think it is harder for architects (people who design buildings) to protect structures against internal or external forces? Why?
Gravity is the attraction that things have for one another, like the powerful pull that the Earth has on the things that are on it.The "pull-apart" force is tension.The "push-together" force is compression.
Why are external factors significant?Because they can have both direct and indirect influence on business operations, employees, and revenue, external environment considerations are significant.
What external forces are at work on the building?The environment outside usually exerts external stresses on the structure.The building is subjected to external loads from dead, living things, snow, wind, and earthquakes.In the majority of cases, it is simple to identify the source of the these external demands.
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HELPPP PLEASE QUICk :(
What performance is Evaluate skill performance against a scale
A) Coaches
B) SMART goal setting
C) Self‒reflection
D) Rubrics
Evaluate skill performance against a scale is known as Rubrics; option D
What is performance evaluation?Performance evaluation is the systematic process of assessing the performance of an individual in a certain task, skill or job.
Performance evaluation is done against a set of standard measurements or a rating scale known as Rubrics.
Rubrics use a set of specific criteria to evaluate an individual student or a group of students performance in a certain task assigned to them.
Rubrics use a rating system where points or scores are awarded depending on the skillset level or ability demonstrated.
In conclusion, rubrics are used to evaluate performance.
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Consider a stationary diatomic molecule that can rotate and vibrate. If its rotational partition function has a value of 22 and the vibrational partition function has a value of 7.4, what is the total partition function for the molecule?
The total partition function (q) for the stationary diatomic molecule that can rotate and vibrate is to be determined given that the rotational partition function has a value of 22 and the vibrational partition function has a value of 7.4.
Partition Function: The partition function (q) is used to calculate the thermodynamic properties of a system and is defined as the sum of the products of all the quantum states of a system and their corresponding statistical weightage. It is the most important function in statistical mechanics and is given by the following equation: q = ∑ e^(-Ei/kT) where i runs over all quantum states of the system, Ei is the energy of the ith state, k is the Boltzmann constant, and T is the absolute temperature of the system.
Rotational Partition Function: The rotational partition function is used to calculate the contribution of rotational energy to the total energy of a system and is given by the following equation: qr = ∑ (2J+1)e^(-Ej/kT)where J is the rotational quantum number, Ej is the energy of the Jth state, and the sum is over all possible values of J.
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Deanna and Kelly were lifting weights. Kelly was easily doing the exercise and she didn't feel like the exercise was very intense. Deanna suggested she increase the weight stack amount by 50 percent. Kelly was using 8 pounds initially. What amount should she use based on Deanna's suggestion? (2 points)
1. While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is theautomobile's acceleration? (Remember that a negative value indicates a slowing down.)
Given data
*The initial speed of the driver is u = 24 m/s
*The final speed of the driver is v = 15 m/s
*The given time is t = 12 s
The formula for the automobile's acceleration is given as
\(a=\frac{v-u}{t}\)Substitute the values in the above expression as
\(\begin{gathered} a=\frac{15-24}{12} \\ =-0.75m/s^2 \end{gathered}\)