Answer:
The change in entropy is 1.6 W/K.
Explanation:
Thickness, d = 0.5 cm
Area, A = 1 m^2
T = 25°C
T' = - 10°C
Coefficient of thermal conductivity of glass, K = 0.8 W/mK
The change in entropy is given by
S = Q/T
Here,
\(S =\frac{Q}{T}\\\\S = \frac{K A (T - T')}{d(T - T')}\\\\S = \frac{0.8\times 1}{0.5} = 1.6 W/K\)
A toddler pushes his 7.0 kg toy box at a relatively constant velocity across the tiled floor of the family room applying a horizontal force of 35 N. Calculate the coefficient of kinetic friction between the box and the floor.
Friction force opposes relative motion between two bodies in contact
The coefficient of friction between the box and the floor is 1.456 × 10⁻²
Reason:
Known parameter are;
Mass of the toy box = 7.0 kg
Velocity of the toy box as of is pushed = Constant velocity
Force applied by the toddler, \(F_{toddler}\) = 35 N
Required:
To calculate the coefficient of kinetic friction between the box and the floor
Solution:
Given that the box moves with constant velocity, the net force acting on the box is zero, which gives;
\(F_{Net} = F_{toddler} - F_{friction} = 0\)
Where;
\(F_{friction}\) = Friction force
\(\therefore F_{friction} = F_{toddler} = \mathbf{35 \, N}\)
\(F_{friction}\) = Normal reaction, N × Coefficient of friction, \(\mu_k\) = N·\(\mu_k\)
On a flat surface, normal reaction of an object = The weight of the object
∴ \(F_{friction}\) = Weight of box × Coefficient of friction
\(Coefficient \ of \ friction, \ \mu_k = \dfrac{ F_{friction} }{Weight}\)
Weight of the box, W = 7.0 kg × 9.81 m/s² = 68.67 N
The coefficient of friction that gives a force of 35 N between the box and the floor is therefore;
\(Coefficient \ of \ friction, \ \mu_k = \dfrac{ 35 \, N\ }{68.67 \, N} \approx 1.456 \times 10^{-2}\)
The coefficient of friction between the box and the floor, \(\mu_k\) = 1.456 × 10⁻²
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A small 8.00 kg rocket burns fuel that exerts a time-varying upward force on the rocket (assume constant mass) as the rocket moves upward from the launch pad. This force obeys the equation F=A+Bt2. Measurements show that at t=0, the force is 100.0 N, and at the end of the first 2.00 s, it is 162.0 N.
A. Find the net force on this rocket at the instant after the fuel ignites.
B. Find the acceleration of this rocket at the instant after the fuel ignites.
C. Find the net force on this rocket 3.00 ss, after the fuel ignites.
D. Find the acceleration of this rocket 3.00 ss, after fuel ignition.
E. Suppose that you were using this rocket in outer space, far from all gravity. What would its acceleration be 3.00 ss, after fuel ignition?
a) The net force at the point of fuel ignition is F = A = 100 N.
b) Acceleration after fuel ignites is a = 12.5 m/s^2
c) The net force on the rocket at t=3.00 s is 403 N.
d) Acceleration of rocket 3.00 ss after fuel ignites is a = 50.4 m/s^2
e) Acceleration in outer space is a = 50.4 m/s^2
How the solution was obtainedA. The force at t=0 is given as 100 N, so A = 100 N. We can use the given information to find B:
F = A + Bt^2
162 N = 100 N + B(2.00 s)^2
B = (162 N - 100 N) / (2.00 s)^2
B = 31 N/s^2
Therefore, the net force on the rocket at t=0 is:
F = A = 100 N.
B. The acceleration of the rocket is given by Newton's second law:
F_net = ma
where F_net is the net force acting on the rocket, and a is the acceleration of the rocket. At t=0, the net force on the rocket is 100 N. Therefore, the acceleration of the rocket at t=0 is:
a = F_net / m
a = 100 N / 8.00 kg
a = 12.5 m/s^2
C. To find the net force on the rocket at t=3.00 s, we can simply plug in t=3.00 s into the force equation:
F = A + Bt^2
F = 100 N + 31 N/s^2 (3.00 s)^2
F = 403 N
Therefore, the net force on the rocket at t=3.00 s is 403 N.
D. To find the acceleration of the rocket at t=3.00 s, we can use the same equation as in part B:
F_net = ma
At t=3.00 s, the net force on the rocket is 403 N. Therefore, the acceleration of the rocket at t=3.00 s is:
a = F_net / m
a = 403 N / 8.00 kg
a = 50.4 m/s^2
E. In outer space, far from all gravity, the only force acting on the rocket is the force from the burning fuel. Therefore, the net force on the rocket is simply the force from the burning fuel:
F = A + Bt^2
F = 100 N + 31 N/s^2 (3.00 s)^2
F = 403 N
Using the same equation as in part B, the acceleration of the rocket is:
a = F_net / m
a = 403 N / 8.00 kg
a = 50.4 m/s^2
Therefore, the acceleration of the rocket in outer space would be the same as in part D.
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Explain one way the water cycle effects climate change. use complete sentences.
Question 1: Assume that the pendulum of a grandfather clock acts as one of Planck'sresonators. If it carries away an energy of 8.1 x 10-15 eV in a one-quantumchange, what is the frequency of the pendulum? (Note that an energy this smallwould not be measurable. For this reason, we do not notice quantum effects in thelarge-scale world.)
Given:
Energy = 8.1 x 10⁻¹⁵ eV.
Let's find the frequency of the pendulum.
To find the frequency, apply the formula for the energy of a light quantum:
\(E=hf\)Where:
E is the energy
h is Planck's constant = 6.63 x 10⁻³⁴ m² kg/s
f is the frequency.
Where:
1 eV = 1.6 x 10⁻¹⁹ J.
Rewrite the formula for f and solve:
\(f=\frac{E}{h}\)Thus, we have:
\(f=\frac{8.1\times10^{-15}*(1.6\times10^{-19})}{6.63\times10^{-34}}\)Solving further:
\(\begin{gathered} f=\frac{8.1\times10^{-15}*(1.6\times10^{-19})}{6.63\times10^{^{-34}}} \\ \\ \\ f=1.95\text{ Hz.} \end{gathered}\)Therefore, the frequency of the pendulum is 1.95 Hz.
ANSWER:
1.95 Hz
What does the difference between gauge pressure and absolute pressure equal?
a.
the pressure within the fluid
c.
the pressure at the bottom of the fluid
b.
the pressure at the surface of the fluid
d.
zero
The actual difference between the gauge pressure of a system and an absolute pressure is the same as the pressure at the surface of the fluid.
The correct answer choice is option b.
Why the pressure at fluid surface equals absolute and gauge pressure.It follows that the two pressure system mentioned in the given task above has a zero point system as their principle of operation.
When we talk of gauge pressure, it is a type of pressure which has a zero point system of atmospheric pressure system. However, the sum total of both the gauge pressure and atmospheric pressure gives what we know as the absolute pressure.
So therefore, we can now deduced that the pressure on a liquid surface is equivalent to the variation between the gauge pressure and absolute pressure.
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A scientist asks, "Does a skateboard move faster on sand or gravel?" Which
experiment could answer this question?
A. Weigh 1 gallon of sand, then roll a skateboard on that sand.
B. Roll a skateboard on sand, then roll it on gravel.
C. Push a skateboard down a gravel hill, then push the skateboard on the
road.
O A
OB
O C
HINT
SUBMIT
Roll a skateboard on sand, then roll it on gravel. - this experiment could answer this question. Hence, option (B) is correct.
What is experiment?An experiment is a technique used to confirm or deny a hypothesis, as well as assess the likelihood or effectiveness of something that has never been tried before. Experiments show what happens when a specific factor is modified, which sheds light on cause-and-effect relationships.
The purpose and scope of experiments vary widely, but they all rely on a repeatable process and a logical examination of the outcomes. Natural experimental experiments are also a thing.
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Pot holder should have high insulation and low _____.
Potholder should have high insulation and low conductivity, therefore the correct answer is the option B
What is insulation?Insulation is a type of material used to create barriers to the transmission of the form of energy which either is in form of heat or electricity.
For outdoor trips in cold weather, several thin layers act as better insulating barriers for heat transfer.
The ability of an electric charge or heat to pass through a material is measured by its conductivity. A material is considered a conductor if it offers very little resistance to the flow of thermal or electric energy.
Thus, Potholders should be highly insulated and have low conductivity, therefore the correct answer is the option B
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your question seems incomplete, the complete question is
To be effective, a pot holder should have low _____. viscosity conductivity malleability density
Humans have used many natural resources to the point of depletion.
They have also caused problems such as desertification and loss of
habitat. What is an example of a sustainable management practice
for natural resources?
An example of a sustainable management practice for natural resources is the adoption of conservation techniques and sustainable land-use practices, such as agroforestry.
What is agroforestry?Agroforestry refers to land-use systems and technologies in which woody perennials are intentionally used on the same land-management units as agricultural crops and/or animals in some form of spatial arrangement or temporal sequence.
Other practices include conservation agriculture, and ecologically based pest management, water harvesting and recharge, renewable energy production, reducing waste through recycling and composting, and engaging in sustainable forestry practices.
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Trawler A is 40km west of Another Trawler B. Trawler A sets off at 20km On a Force of 60°. If Trawler B Can travel at 25km. What course should Trawler B Pass to Intercept Trawler A.
Answer:
Trawler B should set off on a course of 120°.
Trawler A is traveling at 20km/h on a bearing of 60°. This means that Trawler A is traveling north-east. Trawler B is traveling at 25km/h. In order to intercept Trawler A, Trawler B must travel on a bearing of 120°. This means that Trawler B must travel south-east.
The two trawlers will eventually meet at a point that is 40km east of Trawler A's starting position and 20km north of Trawler B's starting position.
Question 9.Do the math Calculate the average acceleration of the rock in the diagram using this question
Please Help!! Been stuck on question sorry if it’s blurry
Answer:
9.8 m/s²
Explanation:
Fill in the blanks with the numbers from the diagram.
\(\text{average acceleration}=\dfrac{\text{final velocity - initial velocity}}{\text{time it takes to change velocity}}\\\\\text{average acceleration}=\dfrac{39.2\text{ m/s}-9.8\text{ m/s}}{3\text{ s}}=\dfrac{29.4}{3}\text{ m/s$^2$}\\\\\boxed{\text{average acceleration}=9.8\text{ m/s$^2$}}\)
__
You are told to start with t = 1 second and end at t = 4 seconds, so the elapsed time for which you're computing the acceleration is 4-1 = 3 seconds.
When you fill in your blanks, you probably want to put numbers only. I like to show the units in physics problems, just to make sure the math is right.
C=59(F−32)The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true?
A. temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 59 degree Celsius.
B. temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
C. temperature increase of 59 degree Fahrenheit is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
As a result, claim I is accurate. According to this formula, a temperature increase of 1 degree Celsius is comparable to a temperature increase of 9/5 degrees Fahrenheit.
0F and 0C stand for what?The Celsius scale, sometimes known as the centigrade scale, is a temperature scale based on the water's freezing point at 0°C and boiling point at 100°C. A temperature scale called the Fahrenheit scale is based on the fact that water freezes at 32°F and boils at 212°F.
Why convert 95 degrees Celsius to degrees Fahrenheit?The relationship between Celsius and Fahrenheit is inversely proportional. The temperature on the Fahrenheit scale rises as the temperature does on the Celsius scale, and vice versa. The change from C to F is therefore 100/180, or 5/9. It is 180/100 or 9/5 from F to C.
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WILL GIVE BRAINLIEST
Which of the following findings would support the giant impact hypothesis?
The percentage of oxygen in the Moon’s outer layers is identical to that in Earth’s.
The percentage of oxygen in the Moon’s outer layers is much lower than that in Earth’s.
The percentage of oxygen in the Moon’s outer layers is similar to that in Earth’s.
The percentage of oxygen in the Moon’s outer layers is much higher than that in Earth’s.
The support for the hypothesis lies in the fact that; the percentage of oxygen in the Moon’s outer layers is much higher than that in Earth’s.
What is a hypothesis?The term hypothesis has to do with a claim or an explanation of an observation or a phenomenon. The explanation often seeks to shed more light in order to make the meaning of the phenomenon clearer.
The giant impact hypothesis was one of the theories that were put forward to explain the origins of the moon. We know that the origins of the moon have always been a very important subject of scientific study.
The giant impact hypothesis holds that the moon was formed from the debris that were collected when an object collided against the earth after it was just formed.
This hypothesis is often backed by the fact that there are still many striking similarities between the earth and the moon. Hence, the percentage of oxygen in the Moon’s outer layers is much higher than that in Earth’s.
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A net force of 25.0 N causes an object to accelerate at 4.00 m/s2. What is the mass of the object?
Answer: 7kg I think or 6
Explanation:
A pump moves water horizontally at a rate of 0.02 m3/s. Upstream of the pump where the pipe diameter is 90 mm, the pressure is 120 kPa. Downstream of the pump where the pipe diameter is 30 mm, the pressure is 400 kPa. If the loss in energy across the pump due to fluid friction effects is 170 N.m/kg, determine the hydraulic efficiency of the pump.
Answer:
the efficiency of hydralic is 79.88%
Explanation:
convert mm to m
1mm = (1/1000)m
diameter of pipe upsteam
d₁= 90mm= 0.09m
diameter of pipe downsteam
d₂= 30mm = 0.03m
finding velocity of upsteam
recall Q=A₁V₁
V₁=Q/A₁
V₁=3.14m/s
velocity of downsteam
V₂= Q/A₂
V₂= 28.29m/s
mass flow rate
m= ρQ
ρ is the density of water
m = 1000× 0.02
m= 20kg/s
the efficiency of hydralic is 79.88%
The two objects shown are both positively charged. Which position could possibly have zero electric field?
- A
- B
- C
- D
- They could all have zero electric field
The position they could possibly have zero electric field is C.
What is electric field?An electric field is a physical field that exists in the space surrounding electrically charged particles or objects. It is a vector field, meaning that it has both magnitude and direction.
When a charged particle is present in a space, it creates an electric field that exerts a force on any other charged particles in the vicinity.
The strength of the electric field at any given point is defined as the force per unit charge that a small test charge would experience if placed at that point.
The magnitude and direction of the electric field depend on the distance between the charges and their magnitudes. The electric field is stronger when the charges are closer together and weaker when they are farther apart.
So position they could experience zero electric field is C, assuming point C if very far from the two charges.
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A cork gun contains a spring whose spring constant is 19 N/m. The spring is compressed by a distance
= 8.5 cm and used to propel from the gun a cork of mass 3.1 g. Assuming the cork is released when the spring passes through its equilibrium position
, what is the speed of the cork as it is released from the spring?
The speed of the cork as it is released from the spring is 4.4 m/s.
What is conservation of energy?The conservation of energy is a principle that states that energy can not be created or destroyed, only transferred from one form to another. In a unrestricted system, the total quantum of energy remains constant over time.
Equation:To solve this problem, we can use the conservation of energy equation, which states that the initial energy stored in the spring is equal to the kinetic energy of the cork as it is released.
The initial potential energy stored in the spring can be calculated using:
PE = 1/2 kx²
where k is the spring constant and x is the distance the spring is compressed. Substituting values, we get:
PE = 1/2 (19 N/m) (0.085 m)² = 0.067 J
The kinetic energy of the cork can be calculated using:
KE = 1/2 mv²
where m is the mass of the cork and v is its speed. Substituting values, we get:
0.067 J = 1/2 (0.0031 kg) v²
Solving for v, we get:
v = sqrt(0.067 J / (1/2 (0.0031 kg))) = 4.4 m/s
Therefore, the speed of the cork as it is released from the spring is 4.4 m/s.
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Through what angle in degrees does a 33 rpm record turn in 0.32 s?
63°
35°
46°
74°
Answer:
1 rev = 2(pi) rad pi(rad) = 180 degrees
so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees
Explanation:
63.36 estimated to 63 so 63
The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.
Calculation of the angle:Since we know that1 rev = 2(pi) rad
So here pi(rad) = 180 degrees
Now for 33 rpm it should be like
= 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s
= 63.36 degrees
= 63 degrees
hence, The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.
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The acceleration of gravity on the
Moon is 1.62 m/s2. The mass of the
Moon is 7.35 x 10^22 kg. From this
information, what is the radius of the
Moon?
Answer:
Near the Earth's surface, the acceleration due to gravity is approximately constant. ... Its value is = 6.673 x 10-11 N·m2/kg2. ... The mass of the moon is 7.35 x 1022 kg. ... moon, the distance to the center of mass is the same as the radius: r = 1.74 x ... Handwriting · Spanish · Facts · Examples · Formulas · Difference Between ...
Explanation:
The acceleration of gravity on the Moon is 1.62 m/s2. The mass of the Moon is 7.35 x 10^22 kg. From this information, then the radius of the Moon is 3 * 10¹² m.
What is moon ?The sole natural satellite of Earth is the Moon. With a diameter around one-quarter that of Earth (equivalent to the breadth of Australia), it is the largest and most massive compared to its home planet and the fifth largest satellite in the Solar System. The Moon is bigger than any known dwarf planets of the Solar System and is a planetary-mass object with a distinct rocky body, making it a satellite planet according to geophysical definitions of the word. There isn't much of an atmosphere, hydrosphere, or magnetic field there. With a surface gravity of 0.1654 g, it has a gravity that is around one-sixth that of Earth. Jupiter's moon Io is the only satellite in the Solar System that is known to have a greater gravity and density.
The Moon travels an average distance around Earth.
Given,
g = 1.62 m/s²
m = 7.35*10²² kg
according to formula,
g = GM/r²
1.62 = 6.67× 10⁻¹¹ m³ kg⁻¹ s⁻²*7.35*10²² kg/r²
solving this for r we get
r = 1.7 * 10⁶ m
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Using your own life experience, can you provide examples of environmentally influenced learned behaviors? Read More >> Using your own life experience, can you provide examples of environmentally influenced learned behaviors?
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I have observed and experienced behaviors that are learned as a result of environmental influences, and I can furnish examples to support this assertion.
What is one good example?Recycling serves as a noteworthy instance. During my childhood, I acquired the habit of recycling owing to the teachings and guidance of my parents and educators, which became firmly established in me.
Water conservation serves as another illustration. Having experienced repeated droughts in my locale, I developed a sense of awareness about the utilization of water and inculcated practices such as shutting off the tap while brushing my teeth.
My daily habits have been influenced by the environmental elements in my surroundings and have now become ingrained in my routine.
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Calculate the energy changes corresponding to the transitions of the hydrogen atom. From n = 3 to n = ∞.
Answer: ΔE = -2.42 × 10^-19 J
Explanation:
The energy of an electron in the nth energy level of a hydrogen atom is given by the following formula:
E = (-2.18 × 10^-18 J) × (Z^2 / n^2)
where Z is the atomic number (1 for hydrogen) and n is the principal quantum number.
The energy change corresponding to a transition from energy level n1 to energy level n2 is given by the formula:
ΔE = E2 - E1 = (-2.18 × 10^-18 J) × Z^2 (1/n2^2 - 1/n1^2)
Given that the electron transitions from n = 3 to n = ∞, we can substitute n1 = 3 and n2 = ∞ in the above formula to obtain:
ΔE = (-2.18 × 10^-18 J) × 1^2 (1/∞^2 - 1/3^2)
ΔE = (-2.18 × 10^-18 J) × (1/9)
ΔE = -2.42 × 10^-19 J
Therefore, the energy change corresponding to the transition of the hydrogen atom from n = 3 to n = ∞ is -2.42 × 10^-19 J.
The energy change for the transition of a hydrogen atom from n = 3 to n = ∞ is 1.511 eV. This transition represents the electron moving to an energy level where it is essentially unbound from the nucleus, resulting in an energy increase.
The energy changes corresponding to the transitions of a hydrogen atom can be calculated using the formula for energy levels in hydrogen:
E = -13.6 eV * (Z² / n²)
Where:
E is the energy of the electron in electronvolts (eV).
Z is the atomic number, which is 1 for hydrogen.
n is the principal quantum number, representing the energy level.
Given the transition from n = 3 to n = ∞, we can calculate the energy change:
Calculate the initial energy (n = 3):
Einitial = -13.6 eV * (1² / 3²) = -13.6 eV * (1/9) = -1.511 eV
Calculate the final energy (n = ∞):
Efinal = -13.6 eV * (1² / ∞²)
In the final state, as n approaches infinity, the energy becomes zero.
Calculate the energy change (ΔE):
ΔE = Efinal - Einitial = 0 - (-1.511 eV) = 1.511 eV
So, the energy change corresponding to the transition of a hydrogen atom from n = 3 to n = ∞ is 1.511 electronvolts (eV).
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Food manufacturers create fats by adding hydrogen to fats?
True, Food manufacturers create fats by adding hydrogen to fats.
What is hydrogenation?Hydrogenation is used in the oil industry in making trans fats or margarine by increasing the melting point through reducing the carbon-to-carbon double bonds..
During hydrogenation, unsaturated fats undergo a chemical reaction in the presence of hydrogen gas and a catalyst, typically nickel.
The process involves the addition of hydrogen atoms to the carbon double bonds in the fatty acid molecules, resulting in the conversion of some of the double bonds into single bonds.
This reduces the number of unsaturated bonds in the fat, making it more saturated.
So we can conclude that the statement is true.
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Velocity of a Hot-Air Balloon A hot-air balloon rises vertically from the ground so that its height after t sec is given by the following function.
h=1/2t2+1/2t
(a) What is the height of the balloon at the end of 40 sec?
(b) What is the average velocity of the balloon between t = 0 and t = 30?
ft/sec
(c) What is the velocity of the balloon at the end of 30 sec?
ft/sec
Answer:
Explanation:
Given the height reached by a balloon after t sec modeled by the equation
h=1/2t²+1/2t
a) To calculate the height of the balloon after 40 secs we will substitute t = 40 into the modeled equation and calculate the value of t
If h(t)=1/2t²+1/2t
h(40) = 1/2(40)²+1/2 (40)
h(40) = 1600/2 + 40/2
h(40) = 800 + 20
h(40) = 820 feet
The height of the balloon after 40 secs is 820 feet
b) Velocity is the change of displacement of a body with respect to time.
v = dh/dt
v(t) = 2(1/2)t²⁻¹ + 1/2
v(t) = t + 1/2
when v = 0sec
v(0) = 0 + 1/2
v(0) = 1/2 ft/sec
at v = 30secs
v(30) = 30 + 1/2
v(30) = 30 1/2 ft/sec
average velocity = v(30) - v(0)
average velocity = 30 1/2 - 1/2
average velocity of the balloon between t = 0 and t = 30 = 30 ft/sec
c) Velocity is the change of displacement of a body with respect to time.
v = dh/dt
v(t) = 2(1/2)t²⁻¹ + 1/2
v(t) = t + 1/2
The velocity of the balloon after 30secs will be;
v(30) = 30+1/2
v(30) = 30.5ft/sec
The velocity of the balloon after 30 secs is 30.5 feet/sec
A) The height of the balloon at the end of 40 sec is 820 feet.
B) The average velocity of the balloon is 30 ft/sec.
C) The velocity of the balloon at the end of 30 sec is
VelocityGiven :
h=1/2t²+1/2tPart A)
The height of the balloon after 40 secs is :
h(t)=1/2t²+1/2t
h(40) = 1/2(40)²+1/2 (40)
h(40) = 1600/2 + 40/2
h(40) = 800 + 20
h(40) = 820 feet
The height of the balloon after 40 secs is 820 feet
Part B)
The average velocity of the balloon is :
v = dh/dt
v(t) = 2(1/2)t²⁻¹ + 1/2
v(t) = t + 1/2
when v = 0 sec
v(0) = 0 + 1/2
v(0) = 1/2 ft/sec
When at v = 30secs
v(30) = 30 + 1/2
v(30) = 30 1/2 ft/sec
average velocity = v(30) - v(0)
average velocity = 30 1/2 - 1/2
average velocity of the balloon = 30 ft/sec
The average velocity of the balloon is 30 ft/sec.
Part C)
The velocity of the balloon at the end of 30 sec is :
v = dh/dt
v(t) = 2(1/2)t²⁻¹ + 1/2
v(t) = t + 1/2
The velocity of the balloon after 30secs will be;
v(30) = 30+1/2
v(30) = 30.5ft/sec
The velocity of the balloon after 30 secs is 30.5 feet/sec.
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If you build a telescope with a focal length of 2.2 m, what eyepiece focal length (in m) is needed for a magnification of 100 times?
Answer:
0.022 m
Explanation:
The magnification of a telescope is given by the formula:
magnification = focal length of telescope / focal length of eyepiece
We are given the focal length of the telescope (2.2 m) and the desired magnification (100 times). We can rearrange the formula to solve for the focal length of the eyepiece:
focal length of eyepiece = focal length of telescope / magnification
focal length of eyepiece = 2.2 m / 100 = 0.022 m
Therefore, the eyepiece focal length needed for a magnification of 100 times is 0.022 m
A tuna jumps out of the water with an initial velocity of 44 feet per second
Answer:
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Explanation:
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Space debris left from old satellites and their launchers is becoming a hazard to other satellites. (a) Calculate the speed in m/s of a satellite in an orbit 980 km above the Earth's surface.
Answer:
564
Explanation:
Two polaroids are placed at 90° to each other. What happens, when (n-1) more polaroids are inserted between them? Their axis are equally spaced. How does the transmitted intensity behave for large n?
When (n-1) polaroids are placed between, two polaroids. Total number of polaroids becomes (n-1+1+1) = (n+1). The axis of all the polaroids are equally spaced. If x is angle between the axis of the two consecutive polaroids then:
\({:\implies \quad \sf x+x+x+\cdots \cdots n\:\:times=\dfrac{\pi}{2}}\)
\({:\implies \quad \sf nx=\dfrac{\pi}{2}}\)
\({:\implies \quad \sf x=\dfrac{\pi}{2n}}\)
Now, by Malus law, we know that the intensity of light on passing through a pair of Polaroid is proportional to cos²(x). Before the light passes out of the last polaroid, this change in intensity will be repeated n times. If \({I_0}\) is intensity of the incident light and \({I}\), is the intensity of light after passing through all the polaroids, then mathematically from Malus law:
\({:\implies \quad I=I_{0}\sf \cos^{2n}(x)}\)
\({:\implies \quad I=I_{0}\sf \cos^{2n}\bigg(\dfrac{\pi}{2n}\bigg)}\)
When, n will be very large, the angle x → 0, so that the whole cosine expression → 1. So, when n will be very much large, \({I}\) will approach \({I_0}\)
Explanation:
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If the gravitational force produced between two masses kept 2 m apart is 100 N, what will be its value when the masses are kept 4m apart? Show your calculation.) Ans: 25 N
When the masses are kept 4 m apart, the gravitational force between them will be 25 N.
How to find the forceThe gravitational force between two masses can be expressed as
F1 = k / r1^2
where
F1 is the force at distance r1, k is the gravitational constant, and r1 is the initial distance.
In this case, we have:
F1 = 100 N (the force at distance 2 m)
r1 = 2 m (the initial distance)
To find the force at a different distance, let's say r2 = 4 m, we can use the inverse square law and solve for F2:
F2 = k / r2^2
We can set up a ratio using the formula:
F1 / F2 = (k / r1^2) / (k / r2^2)
Simplifying the equation:
F1 / F2 = (r2 / r1)^2
Substituting the given values:
100 N / F2 = (4 m / 2 m)^2
100 N / F2 = 2^2
100 N / F2 = 4
to find F2, we can rearrange the equation:
F2 = 100 N / 4
F2 = 25 N
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How does the density of water change when: (a) it is heated from 0o
C to
4o
C; (b) it is heated from 4o
C to 10o
C ?
Answer:
[b] it id heated from 4o
Explanation:
bernouli’s equation is only for fluids that have :
A- low viscosity, incompressible with turbulent flow
B- high viscosity, compressible and streamline flow
C- low viscosity, compressible and turbulent flow
D- low viscosity, incompressible and streamline flow
E- none of the above
Answer:Bernoulli developed his principle from observations on liquids, and Bernoulli's equation is valid for ideal fluids: those that are incompressible, irrotational, inviscid, and subjected to conservative forces.
Explanation:
A grating has 2000 slits/cm/cm. How many full spectral orders can be seen (400 to 700 nmnm) when it is illuminated by white light
With the use of the formula SinФ = nλ / d, there are 16 spectral orders which can be seen when it is illuminated by white light.
Given that a grating has 2000 slits/cm. That is,
d = 0.01 / 2000
d = 5 x \(10^{-6}\) m
The wavelength λ = (700 - 400) nm
λ = 300 x \(10^{-9}\) m
To calculate how many full spectral orders that can be seen (400 to 700 nm) when it is illuminated by white light, we will use the below formula
SinФ = nλ / d
Φ = \(Sin^{-1}\) (nλ / d)
When n = 1
Φ = \(Sin^{-1}\)(300 x \(10^{-9}\)/ 5 x \(10^{-6}\) )
Φ = 3.4 degrees
when n = 2
Φ = \(Sin^{-1}\)(2 x 300 x \(10^{-9}\)/ 5 x \(10^{-6}\) )
Ф = 6.9 degrees
When n = 3
Ф = \(Sin^{-1}\)(3 x 300 x \(10^{-9}\)/ 5 x \(10^{-6}\) )
When n = 16
Ф = \(Sin^{-1}\)(16 x 300 x \(10^{-9}\)/ 5 x \(10^{-6}\) )
Ф = \(Sin^{-1}\)(0.96)
Ф = 73.7 degrees
when n = 17
Ф = \(Sin^{-1}\)(17 x 300 x \(10^{-9}\)/ 5 x \(10^{-6}\) )
Ф = \(Sin^{-1}\)(1.05)
Ф = Error ( that is, it does not exist)
Therefore, there are 16 spectral orders which can be seen when it is illuminated by white light.
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