What is the potential difference ΔVAB Δ V A B ? Express your answer with the appropriate units. problem 21.19

Answer:

So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3

Supersonic flights are moving with speed greater than that of sound. This speed through air will combine the pressure waves and creates shock waves. Continuation of shock waves leads to sonic boom in air.

Sonic booms are sound created on the ground by overpressure in the air generated by fastly moving objects. Similar to someone dumping goods from a moving car, an aircraft travelling at supersonic speeds continuously produces shock waves that cause sonic booms to travel throughout its flight path.

The boom seems to be swept rearward as it moves away from the aeroplane from its point of view. The boom will strike the ground in front of the aircraft if the aircraft makes a rapid turn or pulls up.

The abrupt start and release of pressure following the building by the shock wave or "peak overpressure" is what is heard as a "sonic boom" on the ground. Only a few pounds per square foot change in pressure results from a sonic boom, which is about equivalent to the pressure shift we experience in an elevator.

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Answer:

spring scale and meter stick

Explanation:

The work done by a force of friction can be calculated as the force of friction times the distance. So, we need to measure the force done and the distance traveled. Therefore, the answers are spring scale and meter stick, because the spring scale measures force and the meter stick measures distance.

Answer: 300

Explanation:

A.  The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min

A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:

EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.

Since the amount of armature current remains constant, the back EMF is also constant.

Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:

IF = (250 V - EA)/(RF + R₁)

At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.

If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.

Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:

kϕN/IF1 = kϕN/IF2

N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min

Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:

N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min

where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.

Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.

A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.

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Answer:

Explanation:

Ask a question that can be answered by making observations.

Answer: (APE X) Determine whether experimental observations can provide evidence to support a conclusion

Explanation:

(a) The resonance curve of cigar box would be a plot of  vibration amplitude versus frequency; (b) The Fourier spectra of string without considering role of cigar box would show the various harmonic frequencies ; (c) The Fourier spectra of string will show stronger peak at  resonant frequency of cigar box (300 Hz).

Resonance curve is the curve whose abscissas are frequencies lying near to and on both sides of natural frequency of vibrating system and whose ordinates are corresponding amplitudes of near-resonant vibrations.

(a) The resonance curve of cigar box would be a plot of the vibration amplitude versus frequency. It would show that cigar box has resonant frequency of 300 Hz, which means that it will vibrate more easily at this frequency than at others.

(b) The Fourier spectra of the string without considering the role of the cigar box would show the various harmonic frequencies that the string can produce when plucked. It would be a series of peaks at integer multiples of fundamental frequency (C2 = 66 Hz), with decreasing amplitude as frequency increases.

(c) When the string is attached to cigar box, resonance curve of the cigar box will affect the frequencies that are amplified more than others. The Fourier spectra of string will show a stronger peak at the resonant frequency of the cigar box (300 Hz), and possibly some harmonics that are also amplified by the cigar box. The amplitudes of other harmonics may be reduced due to damping, so the overall spectra will be modified by resonant properties of cigar box.

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Answer:

7

Explanation:

There is really no explanation needed

If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Answer:

A fan pushes hot air out of a vent and into a room. The hot air displaces cold air in the room, causing the cold air to move closer to the floor.

The hot air displacing the cold air is an example of  transfer by

Explanation:

The owl started out at a height of about 3.2 metres.

Gravity is the force that draws objects toward the center of a planet or other object.

Gravitational potential energy (GPE) is calculated as follows:

GPE = mass x gravity x height. Since we are aware of the owl's mass (4 kg) and the change in GPE (-800 J) in this case, we can rewrite the formula to account for the height: tallness = GPE / (mass x gravity).

On Earth, the acceleration caused by gravity is roughly 9.8 m/s2.

By entering the known numbers, we obtain the height change as follows: -800 J / (4 kg x 9.8 m/s2) = -0.408 metres.

By combining the ultimate height (which is believed to be 0 metres) with the height change, we may get the initial height as follows: 0 m + (-0.408 m) = -0.408 m = 0.408 m = 3.2m.

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The work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).

To determine the work required to move the crate vertically, we need to calculate the gravitational potential energy change. The work done is equal to the change in potential energy.

The formula for gravitational potential energy is given by:

Potential energy = mass * acceleration due to gravity * height

In this case, the mass of the crate is not provided, but we can use the given weight of the crate to find the mass. Weight is equal to mass multiplied by the acceleration due to gravity (W = mg).

Given:

Weight of crate (W) = 1400 N

Acceleration due to gravity (g) = 9.8 m/s^2

Vertical distance (height) = 5.0 m

First, calculate the mass of the crate:

1400 N = m * 9.8 m/s^2

m = 1400 N / 9.8 m/s^2 ≈ 143 kg

Now we can calculate the work:

Work = Potential energy = mass * g * height

Work = 143 kg * 9.8 m/s^2 * 5.0 m ≈ 7000 J

Therefore, the work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).

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Answer:

F=ma

Explanation:

according to newton's first law,it states that if a body is in a state of rest or is moving in a straight line except it is moved or stopped by an agent called force or applied force

formula for this law holds as follows

F=ma

where F=applied force,m=mass of the body,a=acceleration of the body

Answer:

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

GPE = 2.25 × 10 × 5.22

We have the final answer as

Hope this helps you

Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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(a)

To find the current flowing through each resistor, we can use Ohm's Law, which states that the current (I) through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor:

I = V / R

As there is only one path for the current to go in the series circuit, the current flowing through both resistors is the same.

We can determine the current flowing through the circuit using the values provided in the problem by doing the following:

Total resistance (Rt) = 47 Ώ + 28 Ώ = 75 Ώ

Total current (It) = V / Rt = 12 V / 75 Ώ = 0.16 A

Therefore, the current flowing through each resistor is 0.16 A.

(b)

We may apply Ohm's Law once more to determine the voltage difference between each resistor, but this time we will solve for the voltage:  

V = I x R              

The voltage difference across each resistor can be determined using the values provided in the problem as follows:

Voltage across 47 Ώ resistor = 0.16 A x 47 Ώ = 7.52 V

Voltage across 28 Ώ resistor = 0.16 A x 28 Ώ = 4.48 V

Therefore, the voltage difference across the 47 Ώ resistor is 7.52 V, and the voltage difference across the 28 Ώ resistor is 4.48 V.

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Answer:

9.6×10⁹ A

Explanation:

From the question above,

P = VI.................... Equation 1

Where P = Electric power, V = Voltage, I = current.

make I the subject of the equation

I = P/V............. Equation 2

Given: P = 200 kW = 200×10³ W, V = 48000 V.

Substitute these vales into equation 2

I = 200×10³×48000

I = 9.6×10⁹ A.

Hence the current in the line is 9.6×10⁹ A.

Answer:

true it is aslo the reason for flight or flight response and helps release adrenaline

Explanation:

There's more to this question than just "true" or "false".

-- True, high blood pressure is one possible physical response to stress ... but there are several others.

-- True, stress is one possible cause of high blood pressure ... but there are several others.

-- The relationship is not 1 to 1 .

Given data:

* The force applied on the bookshelf towards the direction of motion by George is,

* The force applied on the bookshelf towards the direction of motion by the friend of George is,

* The force of friction opposite to the direction of motion is,

Solution:

Thus, the net force acting on the bookshelf is,

Here, the negative sign before the friction force indicates the direction of friction force is oppoiste to the direction of motion,

Substituting the known values,

Here, the positive value of net force indicates the net force is acting in the direction of motion of the bookshelf.

Thus, the bookshelf will move to the right with a force of 4 N.

Hence, 4th option is the correct answer.

Answer:

Eastward = 34.05m

Northward = 66.8m

Explanation:

First, let's define our coordinate axis.

I will choose the North as the positive y-axis and the East as the positive x-axis.

Now we will work with polar coordinates, r and θ and remember that if we want to recover the rectangular coordinates, we need to compute:

x = r*cos(θ)

y = r*sin(θ)

(remember that θ is measured counterclockwise from the positive x-axis)

Now we have:

"... 75 m long displacement vector..."

r = 75m

"...points in a direction of 27° E of N..."

This means that the measure is from the positive y-axis, clockwise (so this is not equivalent to θ).

Now, remember that the angle between the positive y-axis and the positive x-axis is 90°.

Then we will have that θ is the complementary angle to 27°, or:

θ = 90° - 27° = 63°

Now we have θ and r, then we can calculate the rectangular components:

x = 75m*cos(63°) = 34.05m (this is the Eastward component)

y = 75m*sin(63°) = 66.8m (this is the Northward component)

Answer:

0.79 cm

Explanation:

The computation is shown below:-

Particle acceleration is

\(a = \frac{qE}{m}\)

We will take d which indicates distance as from the negative plate, so the travel by proton is 0.800 cm - d at the same time

\(d = \frac{1}{2} a_et^2\\\\0.800 cm - d = \frac{1}{2} a_pt^2\\\\\frac{d}{0.800 cm - d} = \frac{a_e}{a_p} \\\\\frac{d}{0.800 cm - d} = \frac{m_p}{m_e} \\\\\frac{d}{0.800 cm - d} = \frac{1836m_e}{m_e}\)

After solving the equation we will get 0.79 cm from the negative plate.

Therefore it is 0.79 cm far from the negative pate i.e the point at which the electron and proton pass each other

The point at which the electron and proton pass each other will be 0.79 cm.

When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.

The given data in the problem is;

d' is the distance between the two parallel plates= 0.800 cm

The acceleration is given as;

\(\rm a= \frac{qE}{m} \\\\\)

The distance from Newton's law is found as;

\(d = ut+\frac{1}{2} at^2 \\\\ u=0 \\\\ d= \frac{1}{2} at^2 \\\\ d-d' = \frac{1}{2} a_pt^2 \\\\ 0.800-d= \frac{1}{2} a_pt^2 \\\\\ \frac{d}{0.800-d} =\frac{a}{a_p} \\\\ \frac{d}{0.800-d} =\frac{m_p}{m} \\\\ \frac{d}{0.800-d} =\frac{1836m_e}{m_e} \\\\ d=0.79 \ cm\)

Hence the point at which the electron and proton pass each other will be 0.79 cm.

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Answer:

T = 708.81 N

Explanation:

Given that,

Length of a steel wire in a piano, l =0.54 m

Mass, \(m=4.8\times 10^{-3}\ kg\)

We need to find the tension must this wire be stretched so that the fundamental vibration corresponds to middle C, fc = 261.6 Hz

The equation for fundamental frequency is given by :

\(f=\dfrac{1}{2l}\times \sqrt{\dfrac{T}{\mu}} \\\\f=\dfrac{1}{2l}\times \sqrt{\dfrac{T}{\dfrac{m}{l}}} \\\\261.6=\dfrac{1}{2\times 0.54}\times \sqrt{\dfrac{T}{\dfrac{4.8\times 10^{-3}}{0.54}}} \\\\261.6\times 2\times 0.54=\sqrt{\dfrac{T}{\dfrac{4.8\times 10^{-3}}{0.54}}}\\\\282.528=\sqrt{\dfrac{T}{0.00888}} \\\\(282.528)^2=\dfrac{T}{0.00888}\\\\T=708.81\ N\)

So, the required tension in the wire is 708.81 N.

Speed of the rock at the bottom of the cliff is 44.3 m/s.

Kinetic energy of the rock at the bottom of the cliff is 4915 J.

Work done by air resistance is -2250 J

Average force exerted by the air on the rock is 11.25 N.

a) The speed of the rock at the bottom of the cliff can be calculated using the equation:

v = √(2gh)

where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).

Plugging in the values:

v = √(2 x 9.81 x 200) = 44.3 m/s

Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.

b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:

KE = (1/2)mv²

where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).

Plugging in the values:

KE = (1/2) x 5 x (44.3)² = 4915 J

Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.

c) The work done by air resistance can be calculated using the work-energy principle:

Work done by air resistance = KE_initial - KE_final

where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).

Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:

KE_final = (1/2)mv_terminal²

where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).

Plugging in the values:

KE_final = (1/2) x 5 x (30)² = 2250 J

Therefore, the work done by air resistance is:

Work done by air resistance = 0 - 2250 = -2250 J

The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.

d) The average force exerted by the air on the rock can be calculated using the equation:

Work done by air resistance = Force x Distance

where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.

Rearrange the equation to solve for Force:

Force = Work done by air resistance / Distance

Plugging in the values:

Force = -2250 / 200 = -11.25 N

Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.

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We are asked to determine the length of a ship whose length is 15 meters. To determine the relative length we will use the following formula:

Where:

Now, we substitute the value of the speed as a function of the speed of light:

Substituting we get:

Now, we distribute the exponent and simplify:

Solving the operations:

Therefore, the length of the spaceship observed by the friend is 14.14 meters.

The cart is pulled at a constant velocity, so it is in equilibrium. In particular, the net horizontal force is zero, and consists of only the pulling force and friction such that

p - f = 0

where p and f denote the magnitudes of the pulling force and friction.

So we have

p - 12 N = 0

p = 12 N

Answer:

My greatest scientist is David Baltimore.

Explanation:

David Baltimore is an American biologist, university administrator, and 1975 Nobel laureate in Physiology or Medicine. He is currently President Emeritus and Distinguished Professor of Biology at the California Institute of Technology, where he served as president from 1997 to 2006.

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

The answer is A. Decreasing the distance between the particles by a factor of 3.

The Universal Law of Gravitation is :

F = Gm₁m₂ / r² (where 'r' is the distance between them)

Since force is inversely proportional to the square of the distance between them, distance has to be decreased by a factor of 3 to increase the force to 9 times the original force.