20.927 g of mass of 4.0 L of oxygen at 4.0 ATM and 25 degrees celcius.
What is an ideal gas equation?The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Volume of oxygen \(O_2\) would be 4 L.
Pressure (P) = 4.0 atm
Temperature (T) = 298 K
Universal gas constant (R) = 0.0821 L.atm/mol.K
Molecular mass of oxygen = 32 g/mol
Mass can be calculated by using the Ideal gas equation which is :
PV = nRT (Ideal gas equation)
On rearranging the above formula we will get :
\(\frac{PV}{RT} = \frac{Mass}{Molar\;mass}\)
\(\frac{4.0 atm X 4 L}{0.0821 L.atm/mol.K X 298 K} = \frac{Mass}{Molar\;mass}\)
Mass = 20.927 g
Hence, 20.927 g of mass of 4.0 L of oxygen at 4.0 ATM and 25 degrees celcius.
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Please answer the following question using the data below: H2O vapor content: 13 grams H2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10 ∘
C 52 grams at 30 ∘
C What is the dew point for the conditions listed above? LCL 3π5 25C Relative Humidity =100%
Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$
Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$
The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.
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what are the balanced half-reactions for the electrodes on the left and right? be sure to include states of matter.
The balanced half-reactions for the electrodes on the left and right are
Ni(s) → Ni²⁺(aq) 2 e⁻ . (left) anode
Cu²⁺(aq) + 2 e⁻ → Cu(s) ( right) cathode
The overall reaction is given as :Ni(s) + Cu²⁺(aq) → Ni²⁺(aq) + Cu(s)
A voltaic cell is constructed with a Cu/Cu²⁺ half-cell and an Ni/Ni²⁺ half-cell. The nickel electrode is negative (anode) and the copper electrode is positive (cathode). In the anode takes place the oxidation and in the cathode takes place the reduction. The corresponding half-reactions are:
Anode (oxidation): Ni(s) → Ni²⁺(aq) 2 e⁻
Cathode (reduction): Cu²⁺(aq) + 2 e⁻ → Cu(s)
The overall reaction is:
Ni(s) + Cu²⁺(aq) → Ni²⁺(aq) + Cu(s)
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The complete question is
A voltaic cell is constructed with a Cu/Cu2 half-cell and an Ni/Ni2 half-cell. what are the balanced half-reactions for the electrodes on the left and right? be sure to include states of matter.
Temperature and humidity levels need to be monitored and recorded
(A) weekly, preferably daily.
(B) for each shift.
(C) at least daily.
(D) at least monthly.
To maintain accurate and consistent data on temperature and humidity levels, they should be monitored and recorded (C) at least daily.
Monitoring temperature and humidity levels is crucial for various applications, such as ensuring optimal working conditions, preserving perishable goods, and maintaining proper indoor air quality. By recording these levels daily, you can quickly identify any fluctuations or issues that may arise and take appropriate action. While weekly or monthly checks may provide some information, daily monitoring is the most effective way to stay on top of environmental conditions.
To achieve the best results and maintain an optimal environment, temperature and humidity levels should be monitored and recorded at least daily.
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Use the formula to answer the following question4Li + Pb(SO4)2->2Li₂SO4 + PbHow many moles of Pb(SO4)2 are needed to produce 330 g Li₂SO4?
ANSWER
The number of moles of Pb(SO4)2 is 1.5 moles
EXPLANATION
Given that;
The mass of Li2SO4 is 330g
Follow the steps below to find the moles of Pb(SO4)2
Step 1; Write the balanced equation of the reaction
\(\text{ 4Li + Pb\lparen SO}_4)_2\rightarrow\text{ 2Li}_2SO_4\text{ + Pb}\)Step 2; Find the number of moles of Li2SO4 using the below formula
\(\text{ Mole = }\frac{\text{ mass}}{\text{ molar mass}}\)Recall, that the molar mass of Li2SO4 is 109.94 g/mol
\(\begin{gathered} \text{ mole = }\frac{\text{ 330}}{\text{ 109.94}} \\ \text{ mole = 3.00 moles} \end{gathered}\)The number of moles of Li2SO4 is 3.00 moles
Step 3; Find the number of moles of Pb(SO4)2 using a stoichiometry ratio
In the above equation of the reaction, 1 mole Pb(SO4)2 reacts to give 2 moles LiSO4
Let the number of moles of Pb(SO4) be x
\(\begin{gathered} \text{ 1 mole Pb\lparen SO}_4)_2\text{ }\rightarrow\text{ 2 moles Li}_2\text{SO}_4 \\ \text{ x moles Pb\lparen SO}_4)_2\text{ }\rightarrow\text{ 3.00 moles Li}_2SO_4 \\ \text{ Cross multiply} \\ \text{ 1 mole Pb\lparen SO}_4)_2\text{ }\times\text{ 3 .00 moles Li}_2SO_4\text{ = 2 moles Li}_2SO_4\text{ }\times\text{ x moles Pb\lparen SO}_4)_2 \\ \text{ Isolate x} \\ \text{ x = }\frac{\text{ 1 mole Pb\lparen SO}_4)_2\times3moles\cancel{Li_2}SO_4}{2moles\cancel{Li_2}SO_4} \\ \text{ x = }\frac{1\text{ }\times\text{ 3}}{2} \\ \text{ x = }\frac{3}{2} \\ \text{ x = 1.5 moles} \end{gathered}\)Therefore, the number of moles of Pb(SO4)2 is 1.5 moles
A balloon was inflated to 3.0 L at 295 K . The balloon was left in a hot car and heated to 333 K.
The final volume of the balloon was ? L which means that the size of the balloon?
The following data were obtained from the question given above:
Initial volume (V₁) = 3.0 LInitial temperature (T₁) = 295 KFinal temperature (T₂) = 333 KFinal volume (V₂) =?Charles' law states as follow:
V₁ / T₁ = V₂ / T₂
Inputting the given parameters, the final volume can be obtained as follow:
3 / 295 = V₂ / 333
Cross multiply
295 × V₂ = 3 × 333
295 × V₂ = 666
Divide both side by 295
V₂ = 666 / 295
V₂ = 2.26 L
Thus, the final volume on the balloon is 2.26 L
How do i determine the current size of the ballon?The current size of the balloon can be obtain as follow:
Initial volume (V₁) = 3.0 LFinal volume (V₂) = 2.26 LWe can see that the final volume of the balloon is smaller than the initial size.
Thus, we can say that the size of the balloon reduced.
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What does it mean to "fix" hydrogen? Why would Fritz Haber’s
method for doing so be considered "the most important invention of
the twentieth century"?
To "fix" hydrogen means to convert it from its gaseous form (H₂) into a chemically usable form or compound.
Fritz Haber's method for fixing hydrogen, known as the Haber-Bosch process, involves combining hydrogen (H₂) with nitrogen (N₂) from the air to produce ammonia (NH₃) through a catalytic reaction. This ammonia can then be used to produce fertilizers, explosives, and other important chemicals.
Fritz Haber's method is considered the most important invention of the twentieth century because it revolutionized agriculture and food production. The production of ammonia-based fertilizers made it possible to significantly increase crop yields, addressing global food shortages and supporting a growing population.
This process had a profound impact on global agriculture and played a crucial role in the Green Revolution, which helped alleviate hunger and improved living standards worldwide.
Additionally, the Haber-Bosch process also enabled the production of synthetic materials, such as plastics and fibers, that have transformed various industries and contributed to technological advancements.
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PLEASE HELP ME QUICK 30 POINTS WILL MARK BRAINLIST
Explanation:
Using the formula ΔTb = Kb x molality, where ΔTb is the change in boiling point, we can solve for it and add it to the boiling point of pure water to find the boiling point of the KCl solution.
ΔTb = Kb x molality
ΔTb = 0.512 °C/m x 0.74 molal
ΔTb = 0.37968 °C
Boiling point of KCl solution = 100.00 °C + 0.37968 °C
Boiling point of KCl solution = 100.38 °C
Therefore, the boiling point of the KCl solution is 100.38 °C.
How many moles of oxygen gas (02) are
needed to completely react with 54.0 g of aluminum?
4A1+30₂ → 2Al2O3
54.0 g Al
1 mol Al 3 mol O₂
26.98 g Al 4 mol Al
[?] mol O₂
The number of moles of oxygen required to completely react with 54 g of aluminum is 1.5 moles.
Number of moles of the reacting aluminum
moles = reacting mass/molar mass
moles = 54/27
moles = 2 moles
From the given reaction of oxygen and aluminum;
4Al + 30₂ → 2Al₂O₃
4 moles of Al ----------> 3 moles of oxygen
2 moles of AL --------> ? moles of oxygen
= (2 x 3)/4
= 1.5 moles
Thus, the number of moles of oxygen required to completely react with 54 g of aluminum is 1.5 moles.
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What percent of this vital gas does phytoplankton produce?
25%
75%
50%
100%
suppose at the end of the titration, the solution containing the ce3 ion is transferred to a volumetric flask and diluted to 500. ml. what is the concentration of ce3 in the diluted solution?m
The volume of the concentration of Ce3+ is x = 0.010548 mL
What is Cerium?
Cerium is a chemical element with symbol Ce and atomic number 58. Classified as a lanthanide, Cerium is a solid at room temperature.
The initial concentration of Ce4+ = 0.1758 mL
Volume of the volumetric flask = 30 mL
After , dilution the Ce4+ = 500mL
0.1758 x 30 = x x 500
x = 0.1758 x 30 / 500
x = 0.010548 mL
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Solution a is hypotonic with respect to solution b. What will happen when a cell from solution b is placed in solution a?.
When a cell from solution b is placed in solution a, water will enter inside the cell and it will swell up.
There are three kinds of solutions- isotonic, hypotonic, and hypertonic solutions.
When a solution has the same osmotic concentration as the cell, it is known as an isotonic solution. If a cell is placed in such a solution, water neither enters the cell nor exits from it and the cell remains the same in size.
When a solution’s osmotic concentration is more than a cell's, it is known as a hypertonic solution.
When a cell is placed in such a solution it loses water and shrinks.
When a solution’s osmotic concentration is less than a cell's, it is known as a hypotonic solution.
When a cell is placed in such a solution, water enters inside it and the cell swells up.
In the given situation, solution a is hypotonic with respect to solution b.
So, if a cell from solution b is placed in solution a, water will enter the cell and it will swell up.
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Help me pls!
What is heliuim?
Answer:
it's a chemical Element
Explanation:
symbol He
atomic number 2.
draw the structure for trans−1−benzyl−3−phenylcyclopentane.
Trans-1-benzyl-3-phenylcyclopentane is the IUPAC name for the given compound. It is a cyclic hydrocarbon containing a cyclopentane ring that is substituted with benzyl and phenyl groups. The trans isomer of this compound has the benzyl and phenyl groups on opposite sides of the cyclopentane ring.
The structural formula of trans-1-benzyl-3-phenylcyclopentane is as follows:
It can be seen from the structural formula that the benzyl group is attached to the first carbon atom of the cyclopentane ring, whereas the phenyl group is attached to the third carbon atom of the ring. The trans-configuration is indicated by the double bond between the second and third carbon atoms of the cyclopentane ring.
The structural formula can be further simplified as follows:
The structural formula shows that trans-1-benzyl-3-phenylcyclopentane contains a total of 15 carbon atoms and 14 hydrogen atoms.
The structural formula can be used to predict the physical and chemical properties of trans-1-benzyl-3-phenylcyclopentane, such as its melting and boiling points, solubility, reactivity, and so on.
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A what is matter that is always composed of the same combination of atoms
Answer:
A substance
Explanation:
What is S for ClO3, the
chlorate ion?
Answer:
The chlorate anion has the formula ClO⁻ ₃. In this case, the chlorine atom is in the +5 oxidation state. "Chlorate" can also refer to chemical compounds containing this anion; chlorates are the salts of chloric acid.
"S" typically represents the oxidation state or oxidation number of an element in a chemical compound. For the chlorate ion (ClO₃⁻), the oxidation state of chlorine (Cl) is +5.
The oxidation number, also known as the oxidation state, of an element in a chemical compound is a numerical value that indicates the electron distribution and the degree of electron loss or gain by an atom in a chemical reaction. It helps to identify the type of chemical bonding and the role of each element in the compound.
The chlorate ion (ClO₃⁻) has a chemical formula of ClO₃⁻ where:
Cl: Chlorine has an oxidation state of +5 since oxygen (O) is known to have an oxidation state of -2 and the overall charge of the ion is -1.
O: Oxygen has an oxidation state of -2.
So, the oxidation state of chlorine in the chlorate ion is +5.
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Question 3 (1 point)
What are the best units for a scientist to measure the distance between cities?
A. miles
B.inches
C.meters
D.kilometers
Answer: A and D
Explanation: Miles and Kilometers are the best units when measuring distances between cities, this is because both units will in most cases give a reasonable representation of the distance being measured by giving an output which isn't too large or extremely small. Feets and inches are usually adopted when measuring length of objects which in most cases are small and average only a few meters. Meters are also used for measuring short and medium distances. However, representing distances between two cities in terms of inches or feets will usually give extremely large values. Hence, the need for a fairly larger unit in miles or kilometers.
What is the resistance of a circuit with 12 V running at a current of 6 A?
Answer:Open this pdf if has the answers
Explanation:
How do the ramp heights of the different objects compare? How does the ramp height relate to the strength of the frictional force between the book and the object?
The height of a ramp does not directly determine the strength of the frictional force between a book and an object.
How do they compare?The strength of the frictional force between a book and an object is not directly influenced by the height of a ramp. The nature of the surfaces in contact, the force forcing the surfaces together (normal force), and the coefficient of friction are some of the variables that affect the frictional force between two surfaces.
The coefficient of friction between the book and the object plays a major role in determining the strength of the frictional force.
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The radius of a aluminum atom is 143 pm. How many aluminum atoms would have to be laid side by side to span a distance of 2.36 mm?
Answer:
1.65x10⁷ atoms of Al have to be laid side by side to span a distance of 2.36mm
Explanation:
We can assume Aluminium atoms as balls ordered side by side. As the radius of 1 atom is 143pm = 143x10⁻¹²m, the space that 1 atom occupies is 2 radius = 286x10⁻¹²m. That means to occupy 2.36mm = 2.36x10⁻³ you require:
2.36x10⁻³m ₓ ( 1 atom Al / 143x10⁻¹²m) =
1.65x10⁷ atoms of Al have to be laid side by side to span a distance of 2.36mm8 aluminum atoms would have to be laid side by side to span a distance of 2.36 mm.
Convert the radius of an aluminum atom from picometers (pm) to millimeters (mm). Since 1 pm is equal to 1 × 10⁻³ mm, the radius of an aluminum atom in millimeters is:
143 pm × (1 × 10⁻³ mm/pm) = 0.143 mm
The diameter of an aluminum atom is:
2 × 0.143 mm = 0.286 mm
Number of atoms = Total distance / Diameter of an aluminum atom
Number of atoms = 2.36 mm / 0.286 mm
Number of atoms = 8.24
Therefore, 8 aluminum atoms laid side by side to span a distance of 2.36 mm.
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URGENT! What occurs during a chemical reaction. :)
A.) Atoms of two or more elements are destroyed.
B.) Atoms of two or more elements oppose one another.
C.) Atoms of two or more elements bond together.
D.) Atoms of two or more elements trade protons.
ammonium bicarbonate is used in the food industry as a leavening agent. do you expect ammonium bicarbonate to produce an acidic, basic, or neutral solution when dissolved in water? use your measured ph of nh4cl and nahco3 to justify your answer. 4. potassium hydrogen tartrate (kht), also known as cream of tartar, is the potassium acid salt of tartaric acid (h2t). do you expect this salt to produce an acidic, basic, or neutral solution when dissolved in water? explain. (tartaric acid: pka1
When potassium hydrogen tartrate is dissolved in water, it will produce an acidic solution because the resulting pH will be lower than 7.
Ammonium bicarbonate is used in the food industry as a leavening agent. When dissolved in water, do you expect it to produce an acidic, basic, or neutral solution? The measured pH of ammonium bicarbonate can be used to answer this question. The pH of ammonium chloride (NH4Cl) is around 6 and the pH of sodium bicarbonate (NaHCO3) is around 8.5. Therefore, when ammonium bicarbonate is dissolved in water, it will produce a basic solution because the resulting pH will be higher than 7.
Potassium hydrogen tartrate (KHT), also known as cream of tartar, is the potassium acid salt of tartaric acid (H2T). Do you expect this salt to produce an acidic, basic, or neutral solution when dissolved in water? Tartaric acid has a pKa1 of 2.98, which indicates that it is an acidic compound. Therefore, when potassium hydrogen tartrate is dissolved in water, it will produce an acidic solution because the resulting pH will be lower than 7.
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How many grams are in 1.3 moles of Cr?
Answer:
40.38 grams
Explanation:
Help ASAP Iill mark you as brainlister
C. Yes, if each sample contains 6.02 x 10²³ atoms.
n E Which is the electron configuration for zinc? O 1s22s22p3s23p64s23d8 O 1s22s22p 3s 3p64s+3d10 01s 2s 2p 3s 23p64523d10 0 1522s 2p 3s23p64533d10
The electronic configuration is used to explain the orbitals of an atom and it helps to determine the physical and chemical properties of the elements. The electronic configuration of zinc is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰. The correct option is C.
What is electronic configuration?The distribution of electrons in the atomic orbitals is given by the electronic configuration. It is a standard notation in which all the electrons holding atomic subshells are arranged in a sequence. Each element has a unique electronic configuration.
The electronic configuration of an element can be written in two ways, in standard notation, and in condensed form. In the case of elements with larger atomic numbers, the electronic configuration becomes lengthy in standard notation. So in such cases condensed form is generally used.
In condensed form electronic configuration of zinc is [Ar] 3d¹⁰4s² and in standard form it is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰.
Thus the correct option is C.
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²¹â°pb decays by emitting a βâ» particle. what nuclide is produced?
The nuclide produced after the beta decay of ²¹⁰Pb is ²¹⁰Bi (bismuth-210). The resulting nuclide, bismuth-210, will have 83 protons and 127 neutrons in its nucleus.
When ²¹⁰Pb undergoes beta decay, it emits a β⁻ (beta-minus) particle. Beta decay occurs when a neutron in the nucleus of the parent nuclide is converted into a proton, and an electron (β⁻) and an electron antineutrino (νₑ) are emitted.
In the case of ²¹⁰Pb, which has 82 protons and 128 neutrons, beta decay results in the conversion of one of the neutrons into a proton. This leads to the formation of a new nuclide.By subtracting one neutron from the original nuclide, we determine the resulting nuclide. Thus, ²¹⁰Pb decays into a new nuclide, which is:
²¹⁰Pb → ²¹⁰Bi
Therefore, the nuclide produced after the beta decay of ²¹⁰Pb is ²¹⁰Bi (bismuth-210). The resulting nuclide, bismuth-210, will have 83 protons and 127 neutrons in its nucleus.
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2). In the reaction sequence (parallel) shown below, A⟶k0D,A⟶k11U a) Calculate the selectivity. b) Explain how you increase selectivity by manipulating species A concentration (CA). Justify
a) The selectivity of a reaction is defined as the ratio of the rate of formation of the desired product to the sum of the rates of formation of all products. In this case, we have two parallel reactions: A ⟶ D and A ⟶ U. The selectivity (S) can be calculated as:
S = (rate of formation of D) / (rate of formation of D + rate of formation of U)
b) Manipulating the concentration of species A (CA) can affect the selectivity by altering the reaction rates of the individual pathways. By increasing or decreasing the concentration of A, we can favor one reaction pathway over the other, thereby increasing selectivity.
To justify this, let's consider the rate equations for the two reactions:
Rate of formation of D = k0 * CA
Rate of formation of U = k11 * CA
From the rate equations, it is clear that the rates of formation for both D and U are directly proportional to the concentration of A (CA). By increasing CA, both reaction rates will increase. However, the relative increase in the rate of the desired product (D) will be larger compared to the increase in the rate of the undesired product (U) if the rate constants (k0 and k11) are significantly different.
Thus, by manipulating the concentration of A, we can adjust the ratio of the reaction rates and bias the system towards the desired product, thereby increasing selectivity.
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Arrange the following atoms and ions in order from smallest to largest radius
K+, Ca2+, S2-, Cl-, Ar+
Answer:
3.2.4.5.1
Explanation:
- I
want 5 example about chemical adsorption, and 5 example about
physical adsorption.
- what the objective about adsorption?
The overall objective of adsorption is to utilize the properties of adsorbents and adsorbates to achieve desired outcomes, such as purification, separation, catalysis, or storage, by exploiting the interactions occurring at the adsorbent-adsorbate interface.
Example of Chemical Adsorption:
Adsorption of hydrogen on a metal catalyst surface during hydrogenation reactions.
Adsorption of gas molecules on the surface of a solid metal oxide catalyst during oxidation reactions.
Adsorption of pollutants on activated carbon in water or air purification systems.
Adsorption of dyes on the surface of a solid support in dye-sensitized solar cells.
Adsorption of toxins or drugs on activated charcoal for detoxification or medical purposes.
Example of Physical Adsorption:
Adsorption of nitrogen gas on the surface of activated carbon in gas storage applications.
Adsorption of water molecules on the surface of silica gel in humidity control systems.
Adsorption of volatile organic compounds (VOCs) on zeolite materials for odor control.
Adsorption of gases on the surface of metal-organic frameworks (MOFs) for gas separation processes.
Adsorption of solutes on the surface of silica particles in liquid chromatography for separation and purification purposes.
The objective of adsorption can vary depending on the application, but some common objectives include:
Removal of pollutants or contaminants from air, water, or other environments.
Separation and purification of specific components from a mixture.
Adsorption of gases for storage or transportation purposes.
Catalytic reactions where adsorbed species react on the surface of a catalyst.
Surface modification or functionalization of materials for specific applications.
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The system below was at equilibrium in a
9.0 L container. What change will occur
for the system when the container is
shrunk to 3.0 L?
51.8 kJ + H₂(g) + 1₂(g) = 2HI(g)
The change that wilL occur is that the the reaction shifts to the right (products) to produce fewer moles of gas.
option C is correct.
How do we determine?The balanced equation is:
\(51.8 kJ + H_2(g) + 12(g) = 2HI(g)\)
From the left, there are 1 mole of H2 gas and 1 mole of I2 gas, which gives a total of 2 moles of gas.
In the right, there are 2 moles of HI gas.
We can tell that there are more moles of gas on the left side than on the right side by comparing the amount of moles on each side.
According to Le Chatelier's principle, a decrease in volume will favor the side with fewer moles of gas.
In our scenario, the reaction will shift to the right to produce fewer moles of gas.
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Answer:
there is no change
Explanation:
acellus correct
*10 points* /Number 6/
Answer:
6 : Formula is for cellular respiration
Explanation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + ATP energy
C₆H₁₂O₆ = glucose
O₂ = oxygen
CO₂ = carbon dioxide
H₂O = water
ATP energy = Adenosine triphosphate energy
There are two types of respiration:
1. Aerobic respiration
2. Anaerobic respiration
Aerobic respiration
It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.
Glucose + oxygen → carbon dioxide + water + 38ATP
Anaerobic Respiration
It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.
Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide