Remains the same
Explanation:
Momentum refers to the quantity of motion of a body. When any body of mass moves, it possess momentum. Numerically,
Momentum = mass x velocity
i.e. momentum is the product of the mass x velocity
Momentum of a body is always conserved.
In the context, the skateboard has certain momentum before Freddy lands on it. After Freddy lands, the momentum of skateboard remains the same, there is no change in the momentum.
This is because, here the momentum is conserved. After Freddy lands on the skateboard, the total mass on the skateboard increases and so the velocity decreases making the momentum same before the landing.
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What is moment? What are the two factors which affect moment
Explanation:
moment is an expression involving the product of a distance and physical quantities.
-the size of force applied.
-the perpendicular distance from the pivot to the line of action of the force
Complete the following table. Be sure to include units in your answer.
Net Force (N)
Mass (kg)
Acceleration
t
5. 0
2. 5
2. 32
12
18. 2
1. 967
0. 87
21. 2
180
1. 793
The values for the acceleration needed to complete the table are
2 m/s²0.19 m/s²9.25 m/s²0.04 m/s²100.39 m/s²How do i complete the table?We can complete the table by simply obtaining the acceleration where necessary. Details below:
Case 1
Net force (F) = 5 NMass (m) = 2.5 KgAcceleration (a) =?Net force = mass × acceleration
Acceleration = Net force / mass
Acceleration = 5 / 2.5
Acceleration = 2 m/s²
Case 2
Net force (F) = 2.32 NMass (m) = 12 KgAcceleration (a) =?Net force = mass × acceleration
Acceleration = Net force / mass
Acceleration = 2.32 / 12
Acceleration = 0.19 m/s²
Case 3
Net force (F) = 18.2 NMass (m) = 1.967 KgAcceleration (a) =?Net force = mass × acceleration
Acceleration = Net force / mass
Acceleration = 18.2 / 1.967
Acceleration = 9.25 m/s²
Case 4
Net force (F) = 0.87 NMass (m) = 21.2 KgAcceleration (a) =?Net force = mass × acceleration
Acceleration = Net force / mass
Acceleration = 0.87 / 21.2
Acceleration = 0.04 m/s²
Case 5
Net force (F) = 180 NMass (m) = 1.793 KgAcceleration (a) =?Net force = mass × acceleration
Acceleration = Net force / mass
Acceleration = 180 / 1.793
Acceleration = 100.39 m/s²
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Clear question:
See attached photo
The force of attraction that a -40. 0 μc point charge exerts on a 108 μc point charge has magnitude 4. 00 n. How far apart are these two charges? (k = 1/4πε0 = 8. 99 × 109 n ∙ m2/c2) show your work
The force of attraction that a -40. 0 μc point charge exerts on a 108 μc point charge has magnitude 4 N. then these two charges are apart by the distance 3.11 m.
According to the law, the strength of the electrostatic force of attraction or repulsion between two point charges is inversely proportional to the square of the distance between them and directly proportional to the product of the magnitudes of the charges. Coulomb investigated the repellent force between things with identical electrical charges:
Given,
q₁ = 40 × 10⁻⁶ C
q₂ = 108 × 10⁻⁶ C
F = 4 N
1/4πε0 = 8. 99 × 10⁹
Coulomb's law is given by,
F = q₁q₂ ÷ 4π∈r²
4 N = - 40 × 10⁻⁶ C × 108 × 10⁻⁶ C × 8. 99 × 10⁹ ÷ r²
4 N = 38.83÷ r²
r² = 38.83÷ 4
r² = 9.7
r = 3.11 m
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what happens when air filled balloon is left with its mouth downwards and allowed the air to escape
Answer:
As their is a high pressure inside the balloon, air would gush out of the ballon.
Due to Newton's Third Law of Motion, When this air exerts a force downwards , the surrounding medium would also exert an equal and opposite force on the ballon.. due to which it would fly upwards.
Explanation:
Bats chirp at high frequencies that humans cannot hear. They use echoes to detect objects, such as insects, that are as small as one wavelength. A bat emits a chirp at a frequency of 45.4 kHz. Calculate the size in millimeters of the smallest insect that the bat can detect. (The speed of sound waves in air is 340 m/s.)
The 25 size in millimeters of the smallest insect that the bat can detect.
What is wavelength ?
The distance between identical points (adjacent crests) in adjacent cycles determines how far a waveform signal has travelled in space or over a wire. In wireless systems, this length is often expressed in metres (m), centimetres (cm), or millimetres (mm).
What is speed ?
The rate of a directionally changing object's location. The SI unit of speed is created by combining the fundamental units of length and time. Meters per second (m/s) is the unit of speed in the metric system.
Therefore, 25 size in millimeters of the smallest insect that the bat can detect.
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What is the equation for Kinetic Energy?
Answer:
k.e. = 1/2 m v2 equation of kinetic energy
Answer:
\(Kinetic \: Energy⟼ \frac{1}{2} {mv}^{2} \)
A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.
If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?
The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.
What is the sound's velocity?By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.
Briefing:The following equation relates the distance to the direction and initial velocity:
d = [v₀²sin2θ]/g, where θ – the angle of the jump.
Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62
v₀ = 10.65 m/s ( the take off speed).
The horizontal velocity equals:
vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s
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A cannon is fired horizontally
from a 5.0 m tall tower. How much time will it take until the projectile hits the ground?
Answer:
1.0 s
Explanation:
How fast the projectile is traveling HORIZONTALLY has no effect on how long it takes to hit the ground......only the initial height (5 m) and gravity (-9.81 m/s^2) will affect how long it takes to do so...
df = final position = 0 when it hits the ground
df = do + vot + 1/2 a t^2
0 = 5 + 0 t - 1/2 (9.81) t^2
5 = 1/2 (9.81) t^2
t = 1.0 s
A wave has a frequency of 875 hz and a wavelength of 352 m. At what speed is this wave traveling 
Answer:
308,000 or 30.8×10^3
Explanation:
v=f×lamda
v is ?, f is 875Hz, lamda is 352m
v=875×352
v=308,000
v=30.8×10^3 m/s
quick answer
please
QUESTION 17 An observatory uses a large refracting telescope that has an objective lens of diameter, 1.00 m. The telescope resolves images with green light of wavelength 550 nm. If the telescope can b
The telescope can resolve objects with an angular size greater than or equal to 1.21 arcseconds.
The resolving power of a telescope determines its ability to distinguish fine details in an observed object. It is determined by the diameter of the objective lens or mirror and the wavelength of the light being observed. The formula for resolving power is given by:
R = 1.22 * (λ / D)
Where R is the resolving power, λ is the wavelength of light, and D is the diameter of the objective lens or mirror.
In this case, the diameter of the objective lens is given as 1.00 m, and the wavelength of green light is 550 nm (or 550 x 10^-9 m). Plugging in these values into the formula, we can calculate the resolving power:
R = 1.22 * (550 x 10^-9 m / 1.00 m)
R ≈ 1.21 x 10^-3 radians
To convert the resolving power to angular size, we can use the fact that there are approximately 206,265 arcseconds in a radian:
Angular size = R * (206,265 arcseconds/radian)
Angular size ≈ 1.21 x 10^-3 radians * 206,265 arcseconds/radian
The result is approximately 1.21 arcseconds. Therefore, the telescope can resolve objects with an angular size greater than or equal to 1.21 arcseconds.
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the ball in the figure rotates counterclockwise in a circle of radius 3.39 m with a constant angular speed of 8.00 rad/s. at t = 0, its shadow has an x coordinate of 2.00 m and is moving to the right.
To determine the position of the shadow at a specific time, we can use the concept of angular velocity and the relationship between angular displacement and linear displacement.
Given:
Radius of the circle (r) = 3.39 m
Angular speed (ω) = 8.00 rad/s
Initial x-coordinate of the shadow (x) = 2.00 m The ball rotates counterclockwise, which means the shadow moves to the right initially. We can use the equation: x = r * cos(θ) At t = 0, the angular displacement (θ) is 0, and the x-coordinate of the shadow is 2.00 m. We can solve for θ using the inverse cosine function:
θ = cos^(-1)(x/r)
θ = cos^(-1)(2.00 m / 3.39 m)
Calculating the value of θ: θ ≈ 55.40 degrees. Since the ball rotates counterclockwise at a constant angular speed, we can determine the angular displacement at any given time using the equation: θ = ω * tmNow, let's find the angular displacement at t = 0. We substitute the values:θ = 8.00 rad/s * 0 s θ = 0 rad. Therefore, the shadow is initially at an angular displacement of 55.40 degrees, and the angular displacement remains 0 at t = 0.
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a camera equipped with a 95 mm focal length lens is used to photograph a tree that is 8.3 m tall. a 30 mm high image of the tree on the film is needed. the required distance, between the tree and the camera lens, to take the photograph is closest to
The required distance between the tree and the camera lens can be found by using the thin lens equation, which is 1/f = 1/d + 1/s.
1/d = 1/f - 1/s
d = 1/(1/f - 1/s)
where f is the focal length, d is the distance between the object and the lens, and s is the distance between the image and the lens. We can rearrange this equation to solve for d:
We are given the focal length (f = 95 mm) and the height of the image (s = 30 mm), so we can plug these values into the equation:
d = 1/(1/95 - 1/30)
d = 1/(0.0105 - 0.0333)
d = 1/(-0.0228)
d = -43.86 mm
However, we need to convert this distance from millimeters to meters:
d = -43.86 mm * (1 m / 1000 mm)
d = -0.04386 m
The required distance between the tree and the camera lens is closest to -0.04386 m, or approximately -44 mm.
Note that the negative sign indicates that the image is formed on the opposite side of the lens from the object (i.e., the tree is in front of the lens and the image is behind it).
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Han Solo is moving from left to right along the curvey y= x^2 while orbiting the planet of
Tatooine. He wants to shut off the engines of the Millenium Falcon at a certain point, so
that he will go off along the tangent line and land. At what point should he shut off the
engines in order to reach the landing point (4, 15)? Show all of your work.
At position (3, 9), where the tangent line passes through, Han Solo should turn off the engines (4, 15).
What should you do if an engine fails while you're in flight?The first three things need to be completed, or at least started, right away: Fly the aircraft as you instantly apply full carb heat and check the gasoline in both or one of the tanks, hit the fuel boost or pump, and mix the fuel to full richness.
Finding the tangent line to the curve y = x2 at that location will help us determine when Han Solo should turn off the engines.
The derivative of the function determines the slope of the tangent line at any point on the curve y = x2.: dy/dx = 2x
Han Solo should turn off the engines at position (x1, y1). Next, we have
y1 = x1^2 (since the point is on the curve y = x^2)
dy/dx = 2x1 (since this is the slope of the tangent line at (x1, y1))
The equation of the tangent line via (4, 15) can be expressed using the point-slope form of a line as follows:
y - y1 = m(x - x1)
Substituting y1 = x1^2 and m = 2x1, we get:
y - x1^2 = 2x1(x - x1)
Now, we can substitute the coordinates of the point (4, 15) to solve for x1:
15 - x1^2 = 2x1(4 - x1)
15 - x1^2 = 8x1 - 2x1^2
x1^2 - 8x1 + 15 = 0
This quadratic equation can be factored as:
(x1 - 3)(x1 - 5) = 0
Therefore, the possible values of x1 are 3 and 5.
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if a star is found by spectroscopic observations to be about 500 parsecs distant, its parallax is:
If a star is found to be about 500 parsecs distant based on spectroscopic observations, its parallax is 0.002 arcseconds.
The parallax of the given stare can be calculated using the relationship between parallax and distance. Parallax is the apparent shift in a star's position as observed from Earth when viewed six months apart. It is measured in arcseconds (") and helps astronomers determine the distance of celestial objects.
The formula to convert distance in parsecs to parallax is:
Parallax (") = 1 / Distance (parsecs)
In this case, the distance is given as 500 parsecs. Plugging this value into the formula:
Parallax (") = 1 / 500
Parallax (") ≈ 0.002 arcseconds
So, the parallax of a star found to be 500 parsecs away through spectroscopic observations is approximately 0.002 arcseconds. This small parallax value indicates that the star is indeed quite distant, as objects closer to Earth would have a larger parallax value. The method of using parallax is a crucial tool for astronomers to accurately measure distances to nearby stars, contributing to our understanding of the Universe's structure and scale.
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ways by which static electric current can be produced
Answer:.....................
solar panels
A car slows down from 65 km/s to 30 km/s in 5 seconds. What is its acceleration?
In the Van de Graaff generator, the rollers are made of nylon and polythene.
If the rollers were made of nylon and silk, will the Van de Graaff generator work?
Discuss.
In the Van de, Graaff generator is a rubber belt stretched over two pulleys. At the bottom is the drive pulley connected to the motor. In the generator above the drive, the pulley is covered with felt and the top pulley is bare plastic.
Van de Graaff Generators are devices used to generate large amounts of static electricity. Static electricity is created by an extra charge stored somewhere to keep things from moving. Fees generally don't like to accumulate in one place. They seek out opposite charges as partners and like to run away from particles with the same charge.
When switched on the dome of the Van de Graaff generator is charged positively or negatively depending on the design. Anything that touches the dome receives the same charge. When a person has a dome, it is charged and can stand on end if the hair is long and dry enough. Most Van de Graaff generators store a positive charge in the dome by separating the negative charge from the positive charge.
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If a is encoded as 1, b as 11, R as 1, L as 11, decode the string 011010111011010.
The encoded string "011010111011010" can be decoded using the given encoding scheme, where 'a' is represented as 1, 'b' as 11, 'R' as 1, and 'L' as 11. Decoding the string reveals the original message: "abRLab".
In the given encoding scheme, the letters 'a' and 'R' are represented by 1, while 'b' and 'L' are represented by 11. Analyzing the encoded string "011010111011010" and breaking it down into substrings based on the encoding lengths, we can see that the first two digits '01' represent 'a', the next three digits '101' represent 'b', followed by '1' representing 'R', another three digits '011' representing 'L', and finally '010' representing 'ab'. Putting all the decoded substrings together, we get the message "abRLab".
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What method would likely be used to separate a mixture of colored inks?
This technique is often used in forensic science to identify inks used in forged documents or other types of evidence.
One method to separate a mixture of colored inks is chromatography. Chromatography is a physical separation technique used to separate mixtures based on their molecular properties. In the case of colored inks, paper chromatography is a commonly used technique.
In paper chromatography, a small amount of the ink mixture is spotted onto a piece of chromatography paper, and the paper is placed in a container with a small amount of solvent (e.g. water, alcohol, or acetone). The solvent moves up the paper by capillary action, carrying the ink mixture with it. As the solvent moves up the paper, different components of the ink mixture are separated and are visible as colored bands.
The separation occurs because different components of the mixture have different affinities for the paper and the solvent. Components that are more soluble in the solvent will move up the paper more quickly, while those that are more attracted to the paper will move up more slowly. This results in a separation of the components based on their physical and chemical properties.
By comparing the separated bands of the ink mixture to those of known pure inks, the identity of each component in the mixture can be determined. This technique is often used in forensic science to identify inks used in forged documents or other types of evidence.
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A likely method to separate a mixture of colored inks is through chromatography, a technique used to separate components of a mixture. It separates the ink into its constituent colors by allowing a solvent to travel up a stationary phase like paper, carrying the ink mixture with it.
Explanation:A method that would likely be used to separate a mixture of colored inks is chromatography. Chromatography is a method used in chemistry to separate components of a mixture. It works by using a stationary phase and a mobile phase. In the case of ink separation, the ink mixture would be placed on a stationary phase (like paper), and a solvent (the mobile phase) would be allowed to travel up the paper. As the solvent travels, it moves the mixture along its path. Each component of the ink by their size, chemical properties, and interaction with the solvent and paper will move at different rates, thereby separating the ink into its constituent colors. This method is particularly useful in analyzing the chemical composition of inks and other similar mixtures.
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A wind turbine with a blade diameter of 25 m is to be installed in a location where average wind velocity is 6 m/s. If the overall efficiency of the turbine is 34 percent, determine (a) the average electric power output, (b) the amount of electricity produced from this turbine for an annual operating hours of 8000 h, and (c) the revenue generated if the electricity is sold at a price of $0.09/kWh.Take the density of air to be 1.3 kg/m'.
The wind turbine with a blade diameter of 25 m and an average wind velocity of 6 m/s has an average electric power output of 172.34 kW. For an annual operating time of 8000 hours, the turbine will produce approximately 1,378,720 kWh of electricity.
If sold at a price of $0.09/kWh, the revenue generated from the electricity produced by the turbine would be approximately $124,086.72. To calculate the average electric power output, we can use the formula:
\(\[P = \frac{1}{2} \times \text{{density of air}} \times A \times v^3 \times \text{{efficiency}}\]\)
Substituting the given values into the formula, we can calculate the average electric power output:
\(\[P = \frac{1}{2} \times 1.3 \, \text{{kg/m}}^3 \times \left(\frac{\pi}{4} \times (25 \, \text{{m}})^2\right) \times (6 \, \text{{m/s}})^3 \times 0.34 \approx 172340 \, \text{{watts}} \approx 172.34 \, \text{{kW}}\]\)
To determine the amount of electricity produced for an annual operating time of 8000 hours, we multiply the average electric power output by the operating time:
\(\[\text{{Electricity produced}} = P \times \text{{operating time}} = 172.34 \, \text{{kW}} \times 8000 \, \text{{h}} = 1,378,720 \, \text{{kWh}}\]\)
Finally, to calculate the revenue generated, we multiply the electricity produced by the selling price per kilowatt-hour:
\(\[\text{{Revenue}} = \text{{Electricity produced}} \times \text{{price per kWh}} = 1,378,720 \, \text{{kWh}} \times \$0.09/\text{{kWh}} \approx \$124,086.72\]\)
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What is the direction of net force at all points in the projectile's path?
The direction of net force at all points in the projectile's path is downwards towards the ground.
F = m a
F = Force
m = Mass
a = Acceleration
F ∝ a
The direction of net force is influenced by the direction of acceleration.
In a projectile motion, if the air resistance is considered negligible, there will be no acceleration in horizontal direction. Because, there will be no forces acting in horizontal direction. The only force acting on the projectile is the force of gravity. Gravity pulls the object downwards throughout its motion. So the direction of net force will be downwards at all points in the projectile's path.
Therefore, the direction of net force at all points in the projectile's path is downwards towards the ground.
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an 80.0 kg skydiver jumps out of a balloon at an altitude of 1000 m and opens the parachute at an altitude of 200.0m (A). Assuming that the total resisting force on the driver is constant at 50.0 N with the parachute closed and constant at 3 600 N with the parachute open, what is the speed of the driver when he lands on the ground?(B) do you think the skydiver will get hurt? explain(C) At what height should the parachute be opened so that the final speed of the skydiver when he hits the ground in 5.00 m/s?(d) how realistic is the assumption that the total resisting force is constant? explain
ANSWERS:
A. 38.3 m/s
B. Yes. 38.3 m/s is a very high speed and could potentially cause serious injury or death
C. 656.1 m
D. Not very realistic. The resisting force depends on the speed of the skydiver.
EXPLANATIONS:
(A) To solve for the speed of the skydiver when he lands on the ground, we can use conservation of energy. The initial potential energy of the skydiver is equal to the final kinetic energy plus the final potential energy.
Initial potential energy = mgh1 = 80.0 kg x 9.8 m/s^2 x 1000 m = 784000 J
Final potential energy = mgh2 = 80.0 kg x 9.8 m/s^2 x 200.0 m = 156800 J
With the parachute closed, the total resisting force is 50.0 N, so we can use the work-energy principle to find the final kinetic energy:
Work done by resisting force = Fd = 50.0 N x (1000 m - 200 m) = 40000 J
Final kinetic energy = Initial potential energy - Work done by resisting force - Final potential energy
Final kinetic energy = 784000 J - 40000 J - 156800 J = 587200 J
Finally, we can solve for the speed using the equation for kinetic energy:
Final kinetic energy = (1/2)mv^2
587200 J = (1/2)(80.0 kg)v^2
v = sqrt(1468 m^2/s^2) = 38.3 m/s
Therefore, the speed of the skydiver when he lands on the ground is 38.3 m/s.
(B) It's difficult to say whether the skydiver will get hurt based solely on the speed of impact. However, 38.3 m/s is a very high speed and could potentially cause serious injury or death. Other factors, such as the angle of impact and the condition of the ground, would also affect the outcome.
(C) We can use the same conservation of energy equation as in part (A), but solve for the height at which the parachute should be opened to achieve a final speed of 5.00 m/s.
Initial potential energy = mgh1 = 80.0 kg x 9.8 m/s^2 x h1
Final potential energy = mgh2 = 80.0 kg x 9.8 m/s^2 x 0
With the parachute open, the total resisting force is 3600 N, so we can use the work-energy principle to find the work done by the resisting force:
Work done by resisting force = Fd = 3600 N x (h1 - 0) = 3600h1 J
Then we can solve for the height using the equation:
Initial potential energy - Work done by resisting force = Final kinetic energy + Final potential energy
mgh1 - 3600h1 = (1/2)mv^2 + 0
Simplifying and solving for h1:
h1 = (v^2)/(2g) + 3600/g = (5.00 m/s)^2 / (2 x 9.8 m/s^2) + 3600/9.8 = 656.1 m
Therefore, the parachute should be opened at a height of 656.1 m to achieve a final speed of 5.00 m/s.
(D) The assumption that the total resisting force is constant is not very realistic because the resisting force depends on the speed of the skydiver. As the skydiver falls faster, the resisting force will increase due to air resistance. Therefore, the actual speed of the skydiver with the parachute closed and the actual speed with the parachute open would not be constant.
why is thrust-required, tr, converted to power-required, pr, when analyzing the performance of a propeller driven aircraft?
The thrust-required, converted to power-required, when analyzing the performance of a propeller-driven aircraft is because propeller's thrust is always directed toward the center of rotation.
When you look at the total power required by a propeller aircraft and the total power that can be used by the engine, you'll see that there's an imbalance between the two. This means that more power will be needed than is available.
To solve this problem, engineers must design their propeller aircraft so that it produces enough thrust for takeoff but not so much thrust as to exceed the engine's ability to use all of its available power.
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which is an example of measurement that considers velocity?
Speed is an example of measurement that considers velocity.
What is velocity?
Velocity is a vector measurement of the rate and direction of motion or the speed of an object in a given direction. It is the magnitude of the rate of change of an object’s position, and is usually expressed in meters per second (m/s). Velocity is defined as the rate of change of the position of a body with respect to time. An example of velocity is a car traveling at 30 miles per hour.
It is a measure of how quickly an object is moving across a given distance, usually measured in meters per second or kilometers per hour. This is because speed is a measure of how quickly an object is moving, which is related to its velocity. Speed is calculated by dividing the distance traveled by the time it takes to travel that distance, which includes the velocity of the object.
Therefore, Speed is an example of measurement that considers velocity.
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if a galaxy has redshift 0.1, how far away is it in light-years? remember that c = 3.0 x 108 m/s, and assume h0 = 0.0215 m/s/light-year. what about a galaxy with redshift 0.2?
if a galaxy has redshift 0.1 and 0.2, first galaxy is approximately 1.395 × 10¹⁰ light-years away, and the second galaxy is approximately 2.790 × 10⁹ light-years.
To determine the distance to a galaxy with a given redshift, we can use Hubble's law, which states that the recessional velocity of a galaxy is proportional to its distance.
Hubble's law is expressed as:
v = H₀ * d
where v is the recessional velocity, H₀ is the Hubble constant, and d is the distance to the galaxy.
The redshift (z) is related to the recessional velocity (v) through the equation:
z = v / c
where c is the speed of light.
From these equations, we can derive the formula to calculate the distance (d) in light-years:
d (in light-years) = (z * c) / H₀
Redshift of the first galaxy, z₁ = 0.1
Redshift of the second galaxy, z₂ = 0.2
Speed of light, c = 3.0 × 10⁸ m/s
Hubble constant, H₀ = 0.0215 m/s/light-year
Let's calculate the distances:
For the first galaxy:
d₁ = (z₁ * c) / H₀ = (0.1 * 3.0 × 10⁸ m/s) / (0.0215 m/s/light-year)
d₁ ≈ 1.395 × 10¹⁰ light-years
For the second galaxy:
d₂ = (z₂ * c) / H₀ = (0.2 * 3.0 × 10⁸ m/s) / (0.0215 m/s/light-year)
d₂ ≈ 2.790 × 10⁹ light-years
Therefore, the first galaxy is approximately 1.395 × 10¹⁰ light-years away, and the second galaxy is approximately 2.790 × 10⁹ light-years.
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let's suppose I have a glacier moving at a rate of 64m per day. What would be the steps to converting it to Kilometers per Hour? Also, expressing the km/h using two significant figures
Answer: \(2.7*10^{-2} km/h\)
Explanation:
First you need to know the units that your quantity has. Velocity is given in length divided by time. So to transform from m/day to km/h we need to convert separately length from m to km and time from day to h. For length we have:
1km -------- 1000m
x ------------ 64m
x = 64/1000 = 64*\(10^{-3}\) km
Next we convert the time:
1 day = 24h
And now we just make the proper substitution:
\(64\frac{m}{day} = \frac{64m}{1 day} = \frac{64*10^{-3} km}{24 h} = \frac{64*10^{-3}}{24} \frac{km}{h} = 2.7*10^{-2} km/h\)
Note that our result has two significant figures (2.7) since 10 to -2 does not count as significant figures.
an arrow is shot horizontally at a target 5 meters away with a velocity of 5 m/s. the target and bow are both 3 meters above the ground. will the arrow fall short, hit the target head on, or go above and past the target and by how much
Answer:
okk pls mark brainlist
Which air mass would form over warm water?(1 point)
maritime tropical
continental tropical
continental polar
maritime polar
Answer:
A.) Maritime Tropical (mT)
Explanation:
Continental tropical is the air mass that forms over warm land.
Maritime Polar is the air mass that forms over cold water.
Continental polar is the air mass that forms over cold land.
So therefore A or Maritime Tropical is the correct answer
What is the best definition of profit?
Answer:
Excess currency after a series of deals or fees.
Explanation:
Let's put profit in perspective by using an example. For example, let's say you spend 72 dollars to build a certain product, then you sell that same product to your friend for 116 dollars. It costed 72 dollars to build that product and you sold it for 116, after subtracting the costs for building the product the excess currency is what you would call profit. Profit is your overall goal when running a business, you want to sell a product and make profit from it.
Hope this helps.
profit is your gain on any problem,situation or opportunity given to you
TRUE or FALSE
Organs are composed of multiple tissue types.
Answer:
TRUE
Explanation:
Organs are made of two or more tissue types to allow them to function.
Hope this helps! :D