what is the frequency of light that corresponds to the transition of the electron from the n = 3 to the n = one state of the hydrogen atom?

Answer:

200ft

Explanation:

To find out how much distance the man covered, you need to find the perimeter of the rectangle. To find the perimeter of a rectangle, the formula is:

P = (L + H) × 2

Step 1

Plug in the values for L and H.

P = (70 + 30) × 2

Step 2

Add 70 and 30, because you need to add parentheses first.

P = (100) × 2

Step 3

Remove parentheses, and multiply 100 by 2.

P = 100 × 2

P = 200

Thus, the man walked 200 feet in distance.

To find the number of turns per meter of length of the solenoid, we can use the formula for the magnetic field inside a solenoid

Formula of magnetic field inside a solenoid B = μ₀ * n * I

where B is the magnetic field strength, μ₀ is the permeability of free space (4π × 10^-7 T·m/A), n is the number of turns per unit length, and I is the current.

Rearranging the formula, we have:

n = B / (μ₀ * I)

Plugging in the given values, we get:

n = 9.0 T / (4π × 10^-7 T·m/A * 2.5 × 10^2 A)

n = 9.0 T / (1.26 × 10^-4 T·m/A)

n ≈ 7.14 × 10^4 turns/m

Therefore, the number of turns per meter of length of the solenoid is approximately 7.14 × 10^4 turns/m.

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A. the moving charge induces a magnet field

B. the energy of the charge pushes on the compass

C. the electrons heat up the wire, causing the compass to deflect

Answer:

The frequency of the sound wave is 800Hz

The speed of sound in a is about 340m/s.

Velocity = frequency x wavelength

making wavelength the subject formula

wavelength = Velocity/frequency.

wavelength = 340/800

wavelength = 0.425m.

When the Earth's magnetic field reverses, a new stripe, with the new polarity, begins. Such magnetic patterns led to recognition of the occurrence of sea-floor spreading, and they remain some of the strongest evidence for the theory of plate tectonics.

The specific magnetism of basalt rock is determined by the Earth's magnetic field when the magma is cooling. Scientists determined that the same process formed the perfectly symmetrical stripes on both side of a mid-ocean ridge. The continual process of seafloor spreading separated the stripes in an orderly pattern

With this information, we can conclude that A polarity reversal means that the magnetic North flips to where we know the South Pole is. At the mid-ocean ridge spreading axis.

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The estimated age of the solar system is 4558 million years,

with N = 4.558.

The exponent n is a number that represents the power to which the base number is raised.

The exponential function is represented as xn, where x is the base and n is the exponent.

The question seeks to determine the value of n given N and the estimated age of the solar system.

The formula for calculating the value of n is:

N = 10n
Taking the logarithm of both sides, we get:
log(N) = log(10n)
Using the rule of logarithm, log(a^b) = b log(a), we can rewrite the equation as:
log(N) = n log(10)

Since log(10) = 1, we have:
n = log(N)

Substituting N with the estimated age of the solar system, we get:
n = log(4.558)

Using a calculator, we find that log(4.558) is approximately 0.6609.

the value of the exponent, n, is approximately 0.6609.

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The required number of circles is 83.33.

Scale ratio, S = 10:1

Maximum discharge of reservoir, Q = 200 m³/s

Maximum discharge of model, q = 0.1 m³/s

Time measured by model, t = 1 hour

Time measured in a circle, T = ?

We can use the following equation to relate the discharges, lengths, areas, and times of the reservoir and the model:

Q₁/Q₂ = (L₁/L₂)² × (A₁/A₂) × (t₁/t₂)

where Q₁ and Q₂ are the discharges, L₁ and L₂ are the lengths, A₁ and A₂ are the areas, and t₁ and t₂ are the times.

In the given problem:

L₁/L₂ = 10/1 (scale ratio)

A₁/A₂ = 1 (as the shapes are similar)

Q₁ = 200 m³/s

Q₂ = 0.1 m³/s

t₁ = 1 hour

Therefore,

200/0.1 = (10/1)² × 1 × (1/t₂)

Simplifying the equation, we get:

2000 = 100 × (1/t₂)

Solving for t₂, we find:

t₂ = 1/2000 hour

Now, we need to find out how many hours are in a circle. In a circle, the time period is 24 hours, i.e., T = 24 hours.

So, the number of circles in 1 hour is 1/24. Therefore, the number of circles in 1/2000 hour is:

(1/24) × (1/(1/2000)) = (1/24) × (2000) = 83.33

Thus, 1 hour is approximately equal to 83.33 circles.

Hence, the required number of circles is approximately 83.33.

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The amount of distance an object travels in a given length of time is measured as velocity.

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Answer:

That due the the gravity anything that falls in its gravity accelerates by 25metres per second

Explanation:

Complete question:

A hydraulic jack is used to lift a car by applying a force of 120N at the pump piston, if the area of the ram and pump piston are 100cm squared and 1m squared respectively. What is the weight of the car?

Answer:

the weight of the car is 1.2 N

Explanation:

Given;

applied force, F₁ = 120 N

area of the effort (pump), A₁ = 1 m²

area of the load (ram), A₂ = 100 cm² = 1 x 10⁻² m²

let the weight of the car = F₂

The applied pressure is constant and the following equations can be used to calculate the weight of the car.

\(P = \frac{F_1}{A_1} = \frac{F_2}{A_2} \\\\F_2 = \frac{F_1 \times A_2}{A_1} \\\\F_2 = \frac{120 \times (1\times 10^{-2})}{1} \\\\F_2 = 1.2 \ N\)

Therefore, the weight of the car is 1.2 N

Tennsion 1= horizontal = 484.94 N

Tension 2 = slanted string = 560 N

Explanation

Step 1

Free body diagram

Newton's first law says that if the net force on an object is zero, like in this case the mass is in rest,then that object will have zero acceleration

so

Step 1

set the equations:

a) for x-axis

b) for y -axis

Step 2

Solve the equations

a) solve for T2in equation (2)

b) replace the T2 value in equation (1) to find T1

therefore

Tennsion 1= horizontal = 484.94 N

Tension 2 = slanted string = 560 N

I hope this helps you

The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N

The gravitaional force between two objects can be obtained by using the following formula:

F = GM₁M₂ / r²

Where

The following data were obtained from he question:

The gravitaional force can be obtained as shown below:

F = GM₁M₂ / r²

F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²

F = 1.63×10³ N

Thus, the gravitational force is 1.63×10³ N

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You have the following expression:

subtract 5 both sides of the equation:

Take into account that the absolute value of any number is equal to the same number but positive.

Then, you have:

and

Then, solve the previous equations:

5x - 8 = -27 add 8 both sides

5x = -27 + 8

5x = -19 divide by 5

x = -19/5

5x - 8 = 27 add 8 both sides

5x = 27 + 8

5x = 32 divide by 5

x = 32/5

Then, the solutions of the given equations are:

x = -19/5

x = 32/5

Respuesta: T2 = 131.04K

Explicación: Dado lo siguiente:

Presión, P1 = 1.5 atm = 1.5 × 760 = 1140 mmHg

Presión, P2 = 1.2 atm = 1.2 × 760 = 912 mmHg

Volumen, V1 = 500cm3 Volumen, V2 = 300cm3

Temperatura, T1 = 273K Temperatura, T2 =?

Usando la fórmula de gas combinada:

P1V1 / T1 = P2V2 / T2

Ingresando nuestros valores:

(1140 × 500) / 273 = (912 × 300) / T2

T2 × (1140 × 500) = 912 × 300 × 273

T2 = 74692800/570000 T2 = 131.04K

Given:

The length of the outdoor track is: l = 400 m

The time taken to complete one complete lap around the track is: t = 100 s

To find:

The average speed and the average velocity

Explanation:

The average speed of an object is defined as the total distance covered by an object divided by the total time it took to complete that distance. It is given as:

Here, d is the total distance covered by Carl and t is the total time he took to complete the total distance d.

Substituting the values in the above equation, we get:

Now, the average velocity of an object is defined as the displacement of an object divided by the total time it took to displace from its initial position.

As Carl runs one complete lap around an outdoor track, after one round he returns to his original initial position from where he had started running. Thus, the displacement D of the Carl will be zero.

Thus, D = 0 m

The average velocity V is calculated as:

Substituting the values in the above equation, we get:

Final answer:

Thus, the average speed of Carl is 4 m/s and his average velocity is 0 m/s.

The magnitude of acceleration is 7.44 m/s²

Given data:

Radius of the circle, r = 26 m,

Speed of the particle, v = 14 m/s.

Acceleration of the particle is given by the formula: a = v²/r

Where, v is the velocity of the particle and r is the radius of the circle on which the particle is moving.

Substitute the given values in the formula of acceleration.

a = v²/r

= (14 m/s)²/26 m

= 7.44 m/s² (rounded off to two decimal places)

Therefore, the magnitude of acceleration is 7.44 m/s².

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Answer:

 the mass deficit is directly proportional to bond reeling

Explanation:

The effect of the mass deficit in the nuclei is

          δ = m_nucleons - m_nucleo

the delta quantity is the binding energy of the atomic nucleus,

This mass is related to energy by the Einstein relation

         ΔE = c² Δm

therefore the mass deficit is directly proportional to bond reeling

Answer:

C. Some of the mass of the four hydrogen nuclei was converted into

energy

Explanation:

Ap3x

The electric field is necessary to drive a 8.0 amp current through a silver wire 0.65 mm in diameter is 0.38 V/m.

The current is = 8 amp

The diameter = 0.65 mm

The electric field expression is as follows :

E = ρ J =

E = ρ I / A

A =( 1 / 4 ) π d²

E = 4 (1.59 × 10 ⁻⁸ ) ( 8 )  / 3.14 × ( 0.65 mm )²

E = (50.8 × 10 ⁻⁸ ) / 1.32

E = 0.38 V/m

Thus, the electric field used to drive the current is 0.38 V/m.

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The electric potential at the center of the semicircle is V = (λ/2ε₀).

To find the electric potential at the center of the semicircle, you need to consider the following terms:

λ (linear charge density), r (radius of the semicircle), ε₀ (vacuum permittivity), and π (pi).

To calculate the electric potential at the center of the semicircle, follow these steps:

1. Divide the semicircle into small segments with length Δs, each carrying a small charge Δq = λΔs.
2. The electric potential at the center due to each small charge Δq can be found using the formula:

ΔV = kΔq/r, where k = 1/4πε₀ is the electrostatic constant.
3. Integrate ΔV over the entire semicircle to find the total electric potential at the center.

The integration gives you the total electric potential at the center of the semicircle as:

\(V = (\lambda/2\pi \epsilon_0) \int(d\theta)\) from 0 to π, where dθ is the angle subtended by Δs at the center.

Upon integrating and substituting the limits, you get:
V = (λ/2πε₀) * π

So, the electric potential at the center of the semicircle is:
V = (λ/2ε₀).

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The proper order to make a single flare on a piece of tubing is as follows:

i. Insert the tube into the flare block's appropriate-sized hole.

vi. Over the tube, centre the plunger or flared pin.

ii. The tube's end projects slightly from the flare tool's top, about the thickness of a dime.

v. To avoid slipping, firmly tighten the clamp bar.

iv. Use a light hammer or mallet to give the plunger several gentle knocks, turning it one-half turn between each strike.

iii. Put the tube's fitting nut and sleeve on.

Step i is the first step as it involves placing the tube in the appropriate size hole in the flaring block, ensuring stability and proper positioning of the tube.

In step vi, the plunger or flaring pin is centered over the tube, aligning it properly to achieve an even and symmetrical flare.

Step ii involves projecting the end of the tube slightly from the top of the flaring tool, ensuring the proper length of the flare.

In step v, the clamp bar is tightened securely to prevent slippage, ensuring stability during the flaring process.

In step iv, the plunger must be given multiple mild strikes with a light hammer or mallet, with each blow requiring a half-turn of the plunger. This action gradually forms the flare, allowing for controlled and consistent results.

Finally, in step iii, the fitting nut and sleeve are slipped onto the tube, completing the flaring process and preparing the tube for connection with other components.

Following the proper order of steps mentioned above ensures a systematic and successful creation of a single flare on a piece of tubing. Each step contributes to the overall process, ensuring stability, alignment, controlled flaring, and proper preparation for connection with other components.

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The correct order of how new oceanic crust is formed from mantle rock at divergent boundaries is: upwelling of mantle rock, formation of basaltic lava, spreading of lava to form new oceanic crust, formation of hydrothermal vents, and subduction of oceanic crust at a subduction zone.

The formation of new oceanic crust at divergent boundaries is a continuous process that involves several steps. The first step in the process is the upwelling of mantle rock to the ocean floor. This is caused by the divergence of the tectonic plates, which creates a gap that is filled by molten rock from the mantle.

Once the mantle rock reaches the surface, it cools and solidifies to form basaltic lava. This lava then spreads out and covers the ocean floor, forming a thin layer of new oceanic crust. As the lava cools, it contracts and forms cracks, which are filled with mineral-rich seawater that solidifies to form hydrothermal vents.

Over time, the new oceanic crust continues to move away from the divergent boundary and is pushed beneath the continental crust at a subduction zone. This process causes the oceanic crust to be recycled back into the mantle and creates a continuous cycle of new crust formation and destruction.

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Answer:

B

A

A

B

Explanation:

In the wiring of houses, a parallel circuit is used, otherwise, if the circuit of one of the parts is interrupted, the current will not enter the other circuits.

The distance that we have from which the echo sounded is 99 m.

An echo is the repeated sound that results from sound waves being reflected off of a surface. Sound waves bounce back and re-emit from solid objects or boundaries, returning to the source of the sound. The original sound is clearly repeated in this reflected sound, giving the impression of an echo.

Echoes are most commonly experienced in environments with hard, smooth surfaces that can reflect sound effectively, such as mountains, canyons, large empty rooms, or open outdoor spaces

From echo;

V = 2x/t

x = Vt/2

x = 330 * 600 * 10^-3/2

= 99 m

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Answer:

ΔE = 1.031 eV

Explanation:

For this exercise let's calculate the energy of the photons using Planck's equation

          E = h f

wavelength and frequency are related

         c = λ f

         f = c /λ

let's substitute

         E = h c /λ

let's calculate

         E = 6.63 10⁻³⁴ 3 10⁸/1064 10⁻⁹

         E = 1.869 10⁻¹⁹ J

let's reduce to eV

         E = 1.869 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

        E = 1.168 eV

therefore the electron affinity is

         ΔE = E - 0.137

         ΔE = 1.168 - 0.137

         ΔE = 1.031 eV

The electron affinity of thulium in units of electron volts per atom is; ΔE ≈ 1.031 eV

From Planck's equation, we can find the energy of the photons when given wavelength as;

E = hc/λ

Where;

h is Planck's constant = 6.626 × 10⁻³⁴ J.s

c is speed of light = 3 × 10⁸ m/s

λ is wavelength

We are given;

wavelength; λ = 1064 nm = 1064 × 10⁻⁹ m

Thus;

E = (6.626 × 10⁻³⁴ × 3 × 10⁸)/(1064 × 10⁻⁹)

E2 = 1.868 × 10⁻¹⁹ J

Converting to eV gives;

E2 = (1.868 × 10⁻¹⁹)/(1.6 × 10⁻¹⁹)

E2 = 1.1675 eV

We are given E1 = 0.137 eV.

Now, electron affinity is simply change in energy. Thus;

ΔE = 1.1675 - 0.137

ΔE ≈ 1.031 eV

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The wavelength of the infrared wave is approximately 7.5 × 10⁻⁷ meters.

The wavelength (λ) of an infrared wave can be calculated using the formula:

λ = c / f

Where:

λ is the wavelength of the wave

c is the speed of light in a vacuum (approximately 3.00 × 10⁸ m/s)

f is the frequency of the wave

In this case:

Frequency (f) = 4.0 × 10¹⁴ Hz

Substituting the values into the formula:

λ = (3.00 × 10⁸ m/s) / (4.0 × 10¹⁴ Hz)

Simplifying the expression:

λ = 7.5 × 10⁻⁷ m

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Gas has a final temperature of 273.6 K and a starting pressure of 177.6 kPa.

R-134a is 1,1,1,2-tetrafluoroethane, as is well known.

Using the ideal gas formula:

PV =nRT PV = w/M RT, where P = gas pressure =? and V = gas volume = 1.115 m3.

T = gas temperature (-30°C) = 273 + (-30) = 243K

R is 8.314 m3 Pa/mole, which is the gas constant. M = molar mass of R-134a gas = 102.03g/mole K = mass of gas = 10 kg = 10,000 g

When you plug in all the values provided, you get the ideal gas equation: P = 1.115m3 = 10000 g/102.03 g/mole 8.314 m3 Pa/mole. 177587.9687 Pa = 177.6 kPa = K 243K P

Consequently, the gas's starting pressure is 177.6 kPa.

We now need to determine the gas's final temperature.

Gay-Law Lussac states that for constant volume and number of moles, the pressure of a gas is precisely proportional to its temperature.

P∝T

P1/T1 = P2/T2

where

P1 is the initial pressure of gas = 177.6 kPa

P2 is the final pressure of gas = 200 kPa

T1 is the initial pressure of gas = ?

T2 is the final pressure of gas =

177.6 kPa/243K = 200 kPa/T2

T2 = 273.6 K

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There is more energy with the light of wavelength 580 nm compared to 660nm as energy is inversely related to wavelength.

The energy of a radiation type is inversely proportional to its wavelength. This means energy increases with decreases in wavelength, and energy decreases with increases in wavelength. The relation between energy, wavelength, and frequency is shown by the equation E = hν = hc/λ.

where

E = energy,

h = Planck's constant,

ν = frequency,

c = the speed of light,

and λ = wavelength of the wave

Wavelength is defined as the distance measured between two adjacent crests or two adjacent troughs of a wave cycle.

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Answer:

Electrical

Explanation:

"Power lines or transmission lines, such as those in Figure 1, move electricity from point A to point B. Usually, this electricity is alternating current so step-up transformers can increase the voltage. This increased voltage allows efficient transmission for 500 kilometers or less. There are 3 types of lines:[3]

Overhead lines are very high voltage, between 100 kV and 800 kV, and do the majority of long distance transmission. They must be high voltage in order to minimize power losses to resistance.

Underground lines are used to transport power through populated areas, underwater, or pretty much anywhere that overhead lines can't be used. They are less common than overhead lines due to heat-related losses and higher cost.

Subtransmission lines carry lower voltages (26 kV - 69 kV) to distribution stations, and can be overhead or underground." - University of  Calgary ENERGY EDUCATION: ELECTRICAL TRANSMISSION.

Answer:

The rod gets heated up through conduction

Explanation: