Answer:
Example:
A car applying brake.
A player catching a bowl.
Graph. See text version for more detail.
The graph above represents the nuclear decay of a radioactive element, measured using a radiation-detecting device. What is the half-life, in days, of this hypothetical element?
If the half-life of a given substance is 65 days, how long will it take for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining?
If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope? Hint: First, determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.
If a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years, what is the half-life of technetium-99?
The half-life of hypothetical element technetium-99 is 210,936 years.
Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.
Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.
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A transverse wave is represented below. 1.5 m 0.20 m What is the approximate amplitude and wavelength of the wave? amplitude = 0.20 m, wavelength = 0.60 m B. amplitude = 0.20 m, wavelength = 0.30 m C. amplitude = 0.10 m, wavelength = 0.60 m OO amplitude = 0.10 m, wavelength = 0.30 m
Answer:
C. amplitude = 0.10 m, wavelength = 0.60 m
Explanation:
The diagram shows an oscillating progressive wave, with its amplitude and wavelength.
Amplitude of a wave is the maximum distance covered either upward or downward.
So that,
amplitude of the wave, A = \(\frac{0.2}{2}\)
= 0.1
Amplitude of the wave = 0.1 m
Wavelength in this case is the distance from crest to crest, or trough to trough of the wave.
So that,
wavelength = \(\frac{1.5}{2.5}\)
= 0.6
wavelength of the wave = 0.6 m
Therefore, the amplitude of the wave is 0.10 m, while the wavelength is 0.60 m.
Soundwaves propogate through materials as pressure or longitudinal waves true or false
Given:
Sound waves
To find:
To check whether the given statement is true or false.
Explanation:
The given statement is true.
Sound waves that are passing through a material medium are longitudinal waves. In longitudinal waves, the particle of the medium through which a sound wave propagates vibrates parallel to the direction of the sound wave.
Final answer:
The given statement is true.
how long does it take energy to pass through the radiative zone
8 minutes A
100,000 years B
10,000 years C
100 years D
Time it takes energy to pass through radiative zone is : A) 8 minutes
How long does it take energy to pass through radiative zone?Energy generated in the core of the Sun takes about 8 minutes to pass through radiative zone and reach the top of convective zone. The radiative zone is a layer of the Sun that lies just outside the core and it is characterized by high density and high temperature.
In this zone, energy is transported by photons that bounce around between atoms and ions that make up the plasma of the Sun. This process is known as radiative diffusion and is relatively slow compared to convective transport of energy that takes place in the outer layers of Sun.
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A heavy bank-vault door is opened by the application of a force of 300 N directed perpendicular to the plane of the door at a distance of 0.80 m from the hinges. What is the torque?
Question 4 options:
1.) 120 Nm
2.) 240 Nm
3.) 375 Nm
4.) 300 Nm
Answer:
240Nm
Explanation:
Given parameters:
Force on the bank vault = 300N
Distance to the plane of the vault = 0.8m
Unknown:
Torque = ?
Solution:
Torque is the component of force that causes an object to rotate about an axis;
Torque = Fr x sinФ
Here Ф = 90°
r = distance
Torque = 300 x 0.8 x Sin 90°
Torque = 240Nm
A plane wave in a nonmagnetic medium has E = 50 sin (10^8 + 2*z) ay V/m. Find (a) The direction of wave propagation (b) λ, f, and Er (c) H
(a) The direction of wave propagation is along the negative z-axis.
(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms.
(c) The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m
Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.
Hence, the direction of wave propagation for the given wave is along the negative z-axis.
To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:
E = c * H,
where c is the speed of light in the medium, which can be approximated as 3 × \(10^{8}\) m/s in free space.
(a) Direction of wave propagation: Along the positive z-axis.
(b) Calculating λ, f, and Er:
Since the electric field (E) is given as E = 50 sin (\(10^{8}\) + 2z) ay V/m, we can see that the angular frequency (ω) is \(10^{8}\) rad/s and the wave number (k) is 2.
The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.
Using the relation c = ω/k, we can solve for λ and f:
λ = 2π/k = 2π/2 = π m (meters)
f = ω/2π = \(10^{8}\)/2π ≈ 1.59 × \(10^{7}\) Hz (Hertz)
To find the wave impedance (Er), we can use the equation Er = E/H:
Er = E/c = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ≈ 0.1667 sin (\(10^{8}\) + 2z) ohms.
(c) The magnetic field (H) can be calculated using the relationship H = E/c:
H = (E/c) = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms. The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
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A girl and her sledge have a combined mass of 40kg. She starts from rest and descends a slope which is inclined at 25 degrees to the horizontal. At the bottom of the slope the ground becomes horizontal for 15m before rising at 6 degrees to the horizontal. The girl travels 25m up the slope before coming to rest once more. There is a constant resistance to motion of magnitude 18N. Calculate the distance the girl travels down the slope.
To solve this problem, we can use the principle of conservation of energy. According to this principle, the total mechanical energy of an object remains constant as long as there are no external forces doing work on the object.
The initial mechanical energy of the girl and sledge is the potential energy they have due to their height above the ground. This potential energy is given by the formula:
PE = m * g * h
where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height above some reference point.
The final mechanical energy of the girl and sledge is the sum of their kinetic energy and potential energy at the end of their motion.
We can set up the following equation to represent the conservation of energy:
Initial PE + Initial KE = Final KE + Final PE
Since the girl and sledge start from rest, their initial kinetic energy is zero. Therefore, the equation simplifies to:
Initial PE = Final KE + Final PE
We can determine the distance the girl and sledge travel down the slope by calculating the final kinetic energy and potential energy and solving for the distance.
The final kinetic energy is given by the formula:
KE = 1/2 * m * v^2
where KE is the kinetic energy, m is the mass, and v is the velocity.
The final potential energy is given by the formula:
PE = m * g * h
where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height above some reference point.
To calculate the final kinetic energy, we need to determine the velocity of the girl and sledge at the end of their motion. We can use the principle of conservation of energy to solve for the velocity.
Substituting the given values into the equation for conservation of energy, we get:
Initial PE = Final KE + Final PE
= 1/2 * 40 kg * v^2 + 40 kg * 9.8 m/s^2 * h
We can solve for the velocity by rearranging the terms and substituting the values for the mass, initial potential energy, and final potential energy:
v = sqrt((2 * (Final PE - Initial PE)) / m)
= sqrt((2 * (40 kg * 9.8 m/s^2 * h - 40 kg * 9.8 m/s^2 * h)) / 40 kg)
= 0
Since the velocity is zero, the final kinetic energy is also zero. This means that the final mechanical energy is equal to the final potential energy, which is equal to the initial potential energy.
We can therefore set up the following equation to solve for the distance the girl and sledge travel down the slope:
Initial PE = Final KE + Final PE
= 0 + Final PE
= Initial PE
This equation tells us that the initial potential energy is equal to the final potential energy. Since the girl and sledge start from rest at the top of the slope and end at rest at the bottom of the slope, the final potential energy is equal to the initial potential energy.
Therefore, the distance the girl and sledge travel down the slope is equal to the distance they travel up the slope, which is 25m.
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can you guys help me to solve first question????
Torque question
A uniform spherical shell of mass M = 11.0 kg and radius R = 0.480 m can rotate about a vertical axis on frictionless bearings (see the figure). A massless cord passes around the equator of the shell, over a pulley of rotational inertia I = 0.160 kg m2 and radius r = 0.110 m, and is attached to a small object of mass m = 1.60 kg. There is no friction on the pulley's axle; the cord does not slip on the pulley. What is the speed of the object when it has fallen a distance 0.700 m after being released from rest? Use energy considerations.
Help please help I don’t want to fail please
Answer:
B
Explanation:
A circuit has a 3 cell battery in series each single cell has 1.5 volts and 2 resistors in parallel each with 8 ohms of resistance. Calculate the current in circuit.
Answer:
3÷5 1.2÷2 ×8i I think that is the best
A student asks the following question:
"If all things with mass have a gravitational field, why doesn't this glue bottle and
stapler, sitting on the counter, stick together because of gravitational forces?"
Which classmate answers correctly?
Ashton says that the gravitational fields between the bottle and the stapler
cancel out because of Newton's 3rd Law.
O Natalie says that all things with mass have a gravitational field, but the force is
very weak and cannot be perceived around small objects.
Xavier says the bottle and the stapler are way too small to have a gravitational
field.
Katherine says the bottle and the stapler have a strong gravitational field, and
would move towards each other quickly if there were no friction on the counter.
Answer:
Natalie says that all things with mass have a gravitational field, but the force is very weak and cannot be perceived around small objects.
Explanation:
The force due to gravity is proportional to the mass of the object and inversely proportional to the square of the distance between objects. The Earth is so massive that the force due to its gravity is much greater than the force between objects on the counter.
If there were no friction, the objects might move toward each other, depending on what other masses were near them tending to cause them to move in other directions.
Natalie's explanation is about the best.
__
Additional comment
The universal gravitational constant was determined by Henry Cavendish in the late 18th century using lead balls weighing 1.6 pounds and 348 pounds. His experiment was enclosed in a large wooden box to minimize outside effects. While these masses are somewhat greater than those of a glue bottle and stapler, the experiment shows the force of gravity between "small" objects can be measured.
what will happen if a low massive main sequence star runs out of hydrogen fuel?
Answer:
Low mass stars are: hydrogen burning in the core while on the Main Sequence. As the hydrogen fuel runs out, extreme pressure raises the temperature to 100 million degrees, where helium burning becomes possible.
A scientist obtains images of a particular star, which appears as four separate stars.
Which phenomenon causes the star to appear this way?
O redshift
gravitational lensing
O principle of equivalence
O gravitational time dilation
Answer:
gravitational lensing
Explanation:
Answer:
Gravitational lensing
Explanation:
How does a battery work? How is the electron affinity of a battery affect the strength of a battery? What makes a battery strong or weak? What direction do electrons flow?
When a conducting wire is conducted
A heat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. The same engine running backward is called a heat pump if its purpose is to exhaust warm air into the hot reservoir. Heat pumps are widely used for home heating. You can think of a heat pump as a refrigerator that is cooling the already cold outdoors and, with its exhaust heat QH, warming the indoors. Perhaps this seems a little silly, but consider the following. Electricity can be directly used to heat a home by passing an electric current through a heating coil. This is a direct, 100% conversion of work to heat. That is, 20.0 kW of electric power (generated by doing work at the rate 20.0 kJ/s at the power plant) produces heat energy inside the home at a rate of 20.0 kJ/s. Suppose that the neighbor's home has a heat pump with a coefficient of performance of 3.00, a realistic value. NOTE: With a refrigerator, "what you get" is heat removed. But with a heat pump, "what you get" is heat delivered. So the coefficient of performance of a heat pump is K=QH/Win. An average price for electricity is about 40 MJ per dollar. A furnace or heat pump will run typically 300 hours per month during the winter.
a. How much electric power (in kW) does the heat pump use to deliver 15 kJ/s of heat energy to the house?
b. An average price for electricity is about 40 MJ per dollar. A fumace or heat pump will run typically 200 hours per month during the winter. What does one month's heating cost in the home with a 15kW electric heater and in the home of the neighbor who uses an aquivalent heat pump?
Solution :
A refrigerator is a heat engine running backwards with its main aim is to extract heat from the cold reservoir. When the engine running backwards is used to exhaust or give out hot air into a hot reservoir is known as a heat pump.
Given :
Coefficient of performance of the heat pump, COP = 3
We know COP of heat pump is K \($=\frac{Q_h}{W_{in}}$\)
a). Therefore the COP can also be written as :
\($COP=\frac{T_h}{T_h-T_c}$\)
\($=\frac{Q_h}{W_{in}}$\)
\($=\frac{Q_h}{P_{in}}$\)
∴ \($3=\frac{15}{P_{in}}$\)
\($P_{in }=\frac{15}{3}$\)
= 5 kW
b). The heating cost in a home of one month with a 15 kW electric heater can be calculated as :
1 dollar = 40 MJ (given)
∴ $1 / 40000 kWh (15 kW)(200 x 3600 s)
= $ 270
please help me there
Answer:
when switch is off no electricity will flow and then the circuit is called an open circuit
Explanation:
Electricity will not flow in open circuit
eporting results (1) Fifteen measurements of a resistance are quoted here based on approximately 10 repeat measurements. Only three of them obey the five golden rules. Identify the mistakes in the other results. (i) (99.8 ± 0.270) × 103 Ω, (ii) (100±0.3)× 103 Ω, (iii) (100.0±0.3)× 1039, (iv) (100.1 ±0.3) × 103, (v) 97.1 x 103-276Q, (vi) (99.8645 ± 0.2701) × 102 Ω, (vii) 98.6 x 103 ±3 × 10-Q,
The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.
What are the golden rules for reporting results?The five golden rules for reporting results are:
Always report the uncertainty in the measurement.Report the uncertainty to the same number of decimal places as the measured value.Use the correct units and prefixes.Avoid rounding until the final calculation.Report only the significant figures.Using these rules, identify the mistakes in the given results as:
(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.
(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.
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the following statements describe ways in which the analogy might apply to the real universe. which statements are correct?
The following statements describe ways in which the analogy might apply to the real universe:
The average distance increases with time, both between raisins in the cake and between galaxies in the universe.An observer at any raisin sees more distant raisins moving away faster, just as an observer in any galaxy sees more distant galaxies moving away faster.An analogy is a comparison between two objects, events, or ideas that share certain characteristics. In the context of the real universe, an analogy can be used to compare the universe to something familiar, such as a balloon.
Just as a balloon expands when air is added to it, the universe is expanding, with the average distance between galaxies increasing over time. Similarly, just as a balloon needs energy to expand, the universe contains vast amounts of matter and energy, with much of it still undiscovered.
Finally, just as a balloon follows the same basic rules of geometry, the geometry of the universe follows ordinary Euclidean geometry, with the same basic rules of geometry applying to both the small and large scale.
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Complete question:
The following statements describe ways in which the analogy might apply to the real universe. Which statements are correct?
Check all that apply.
- The average distance increases with time both between raisins in the cake and between galaxies in the universe.
-An observer at any raisin sees more distant raisins moving away faster, just as an observer in any galaxy sees more distant galaxies moving away faster.
-The raisins stay roughly the same size as the cake expands, just as galaxies stay roughly the same size as the universe expands.
Two blocks of masses 1 = 700 and 2 = 1100 are connected by a cord of negligible mass and hung over a diskshaped pulley, as shown in the figure. The pulley has a mass of = 1.50 and a radius of = 14 , and rotates about a lightweight axle through its center. The axle itself is hung from the ceiling by two like cords of negligible mass and is held horizontally. The system is released from rest. a) Draw a free-body diagram for each of the blocks and the pulley separately. b) Find the magnitude of the acceleration of the blocks. c) Find the magnitude of the angular acceleration of the pulley. d) Find the magnitude of tensions in the cords, 1, 2, and 3. (See the figure.)
Answer:
b) 16 cm
Magnification, m = v/u
3 = v/u
⇒ v = 3u
Lens formula : 1/v – 1/u = 1/f
1/3u = 1/u = 1/12
-2/3u = 1/12
⇒ u = -8 cm
V = 3 × (-8) = -24
Distance between object and image = u – v = -8 – (-24) = -8 + 24 = 16 cm
Explanation:
A mass on a string of unknown length oscillates as a pendulum with a period of 3.5s. Parts a to d are independent questions, each referring to the initial situation. What is the period if:
Part A: the mass is doubled? (s)
Part B: the string length is doubled? (s)
Part C: the string length is halved? (s)
Part D: the amplitude is doubled? (s)
The required period remains the same when mass is doubled, if the length is doubled, the time period becomes 4.95 s, if the length is halved, period becomes 2.475 s and the period of the oscillation is independent of the amplitude.
The period of oscillation is given as 3.5 s.
The period is independent of mass.
So, the period remains the same 3.5 s when mass is doubled.
We know the expression for period and length as,
T = 2π √(l/g)
T₁/√l₁ = T₂/√l₂
T₂ = T₁ √l₂/l₁ = 3.5 √2l₁/l₁ = 3.5 √2 = 4.95 s
So, if the length is doubled, the time period becomes 4.95 s.
When the length is halved, the period becomes,
l₂ = l₁/2
T₂ = T₁ √l₂/l₁ = 3.5 √l₁/2l₁ = 3.5 × 1/√2 = 2.475 s
So, if the length is halved, period becomes 2.475 s.
The oscillation's period is independent on its magnitude.
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How do you stay hydrated during warm-up and scheduled activity?
Answer:
In order to stay hydrated during warm-up(s) drink 8oz of water 20-30 mintues before you start exercising or during your warm-up(s), make sure you drink 7 to 10 oz of water every 10 to 20 minutes during exercise, and drink 8oz of water no more than 30 minutes after you exercise.
In order to stay hydrated during scheduled activity(s) drink 17 to 20 oz of water 2 to 3 hours before you start to exercise, like said before drink 8 oz of water 20 to 30 minutes before you start exercising or during your warm-up(s), drink 7 to 10 oz of water every 10 to 20 minutes during exercise, also said before drink 8 ounces of water no more than 30 minutes after you exercise.
Answer: My scheduled activity was one hour of softball practice. I play catcher, so my thighs and knees take a lot of abuse from kneeling and standing. The lunges were excellent at preparing my thighs for softball. The high knees exercise and arm pumping didn’t feed into softball too well. I suppose that they might help me with base running.
Explanation: EDMENTUM
if you pump air into a 100ml balloon, how far will that air spread?
if you pump air into a 100ml balloon, the distance is that the Gases will be ale to spread out very quickly to fill all the space that has been available to them in the balloon.
Does the volume grow when gas is added?The capacity of a container increases as the gas content rises. A container's capacity reduces as the gas content is reduced. Of course, this assumes that the container's walls are expandable.
Therefore, Gases swiftly disperse to occupy all available area. Imagine blowing up a balloon. When you blow air into a balloon, the entire balloon is filled. A gas will take up all of the available space. This is due to the fact that a gas's particle structure is random.
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If an object is moving with a constant velocity to the right, what direction is the net force.
Group of answer choices
A.To the right
B.To the left
C.Net force is 0
D.Not enough information
Answer:
At constant velocity, his weight equals the force of friction. In other words, there is no net force. If however, he loosens his grip and decreases the friction force, he will accelerate downward.
Explanation:
Help me with this please !!
Pt 1_It would be harder to do experiments on or near jupiter for many reasons ! One being that jupiters top layers are known to be gas. However if we could hover over Jupiter and test its gravity, describe or sketch the shape of the position vs time graph for a dropped object.
PT2_ The acceleration due to gravity near Jupiter is 25.95m/s. If a hammer were dropped, how fast wouldit be going after falling 20.0 meters. Show your work !
Answer:
he is right he Is
Explanation:
step by step explanation
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Positive work implies that the system is losing energy.True or false
The work can be seen as a transfer of energy, and can be calculated with the formula below:
\(W=F\cdot d\)Where W is the work in Joules, F is the force in Newtons and d is the distance in meters.
When we have a positive work, that means the body or system is using its own energy and force to move a certain distance, for example.
A negative work means the system is receiving energy from an external source.
Therefore the statement is TRUE.
the very act of observing a particle has a dramatic effect on its behaviour why do you think this is the case
Answer:
Explanation:
In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.
So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.
A rocket has been fired upward to launch a stellite in its orbit name two forces acting on the rocket immediately after leaving the launching pad
Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.
1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.
This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.
2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.
The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.
Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.
However, the thrust force continues to be the dominant force propelling the rocket upward.
It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.
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Given a rank for a particular flood event of 25 and a record of 24 years duration, what is
the recurrence interval for a flood of this size?
Answer:
The 25-year flood occurs on average once every 25 years and has an exceedance probability of 1 over 25, or 4 percent, in any given year
Two cars are traveling toward one another with the same speed of 20 m/s and collide head-on. Car 1 (traveling from left to right) has a mass of 2000 kg. Car 2 (traveling from right to left) has a mass of 3000 kg. If the collision is perfectly inelastic, what is the velocity of car 1 after the collision?
Question 2 options:
2 m/s, moving to the right.
3.33 m/s, moving to the right.
4 m/s, moving to the left.
6.67 m/s, moving to the left
None of the above.
Answer:
Answer number 3
Explanation:
REALLY HOPE im right:)