What is the displacement from t=1s and t=5s on the graph?

Answer:

Explanation:

Torque can be defined as the rate of change of angular momentum

Step one:

We need to solve for the total angular momentum acting on them

the expression for the angular momentum is given as      

L=mrv-----1    

where

L=angular momentum

m=mass

v=velocity

r=radius

Step two:

For the first object

m=6kg

r=1m

v=2m/s

L1=6*1*2= 12kg*m^2/s

For the second object

m=3kg

r=2m

v=3m/s

L2=3*2*3= 18kg*m^2/s  

Step three:

Total angular momentum= L1+L2= 12+18= 30kg*m^2/s        

τ=44Nm

time= 5 secs

ΔL=τ*time  

ΔL=44*5=220N-ms

hence the angular impulse=220Nms

Change in their angular momentum= Angular impulse-angular momentum

Change in their angular momentum= 220-30

Change in their angular momentum=190kg*m^2/s  

Answer:

Explanation:

Acceleration b/c 0m/s/2s =0m/s²

Answer:

I cant answer too complicated sorry

Explanation:

im sorry for not answering

Answer:

I

will

only

explain

Explanation:

The cannon is fired when an explosive charge is detonated, causing a sudden and immense increase in pressure. Is it not this pressure that causes the rapid acceleration of the cannonball and the recoil of the cannon, not an action–reaction between the cannon and the cannonball?

For purposes of this model, we can consider the expanding gas from the explosion to be part of the cannon, or as an intervening object between the cannon and the ball. So the gasses exert a force on the ball. The ball exerts a force back on the gasses. This is transferred to the cannon.

You could also imagine or build a (toy) "cannon" with a spring mechanism to propel the ball, rather than an explosion. You'd see very similar results.

In any case, the deeper point, which you will soon learn, is that momentum is a conserved quantity. Regardless of what mechanism applies the force on the ball and the cannon, after the ball is flying free the cannon must end up with as much backwards momentum as the ball has forward momentum.

If no cannonball is present when the charge is detonated, then the pressure dissipates much more quickly and the recoil is smaller but still present

Because air and exhaust gasses from the explosion are expelled from the cannon. These gasses have mass and carry momentum, therefore they exert a reaction force on the cannon just as a ball does.

HOPE IT HELPS

Answer:

1) lack of time, 2) social influence, 3) lack of energy, 4) lack of willpower, 5) fear of injury, 6) lack of skill and 7) lack of resources

Explanation:

here are 7 barriers to physical activity choose 5

Answer:

1. Lack of time, injury, lack of energy, lack of willpower, and lack of confidence.

Answer:

Thus, any projectile that has an initial vertical velocity of 21.2 m/s and lands 10.0 m below its starting altitude spends 3.79 s in the air.The initial vertical velocity is the vertical component of the initial velocity: v 0 y = v 0 sin θ 0 = ( 30.0 m / s ) sin 45 ° = 21.2 m / s .

The statement that describes the results of the different weighing scales is as follows: Both accurate and precise (option C).

Accuracy is the exact conformity to truth, or to a rule or model i.e. degree of conformity of a measure to a true or standard value while precision is the ability of a measurement to be reproduced consistently.

Accuracy and precision are two measures of observational error. Accuracy is how close a given set of measurements are to their true value, while precision is how close the measurements are to each other.

According to this question, three different scales were used to weigh a bag of oranges. One scale says the bag weighs 2.1 lb, a second says it weighs 2.2 lb, and a third says it weighs 2.1 lb. The actual weight of the bag of oranges is 2.153 lb.

Based on the above observation, it can be said that the results are both accurate and precise because the measurements are both close to one another and to the true or standard value.

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Explanation:

the answer is in the image above

Answer:

Solid is the state in which Matter maintains a fixed volume

Answer:

The state of matter that has a fixed volume is Solid.

Explanation:

Solid substances will maintain a fixed volume and shape.

Answer:

A. Yes, the force of the engine does work on the car as it makes the car move forward.

B. Yes, the kinetic energy of the car increases as the car gains speed due to the force of the engine.

C. The gravitational potential energy of the car remains constant as the car is moving on a horizontal road, and there is no change in its height.

D. Yes, the tractive force of the engine changes the mechanical energy of the car as it is a type of external force that transfers energy to the car and increases its kinetic energy.

Explanation:

As the board is raised by an angle θ, the block will be held in place by 3 forces:

• its weight, pointing downward (magnitude w )

• the normal force of the board pushing up on the block, pointing in the direction perpendicular to the board (mag. n)

• static friction, pointing in the direction parallel to the board, opposite the direction the block would slip (mag. f )

Decompose the vectors into components that are parallel and perpendicular to the board (taking the direction of n to be the positive direction perpendicular to the board, and the direction of f to be the negative directoin parallel to it), so that by Newton's second law, we have

• net parallel force:

∑ F = w (//) + f

∑ F = m g sin(θ) - µ n = 0

where µ = 0.45 is the coefficient of static friction, g = 9.80 m/s² is the mag. of the acceleration due to gravity, and m = 15.0 kg is the mass of the block.

• net perpendicular force:

∑ F = n + w (⟂)

∑ F = n - m g cos(θ) = 0

Solve for n in the equation for net perpendicular force:

n = m g cos(θ)

Substitute this into the equation for net parallel force:

m g sin(θ) - 0.45 m g cos(θ) = 0

Solve for θ :

sin(θ) - 0.45 cos(θ) = 0

sin(θ) = 0.45 cos(θ)

tan(θ) = 0.45

θ = tan⁻¹(0.45)

θ ≈ 24.2°

So the maximum angle the board can be lifted before the block starts to slide is about 24.2°, since the coefficient of static friction µ is such that

f = µ n

where f is the maximum magnitude of the static friction force.

Answer:

dd activated carbon media to the filter

Explanation:

there <33

Answer:

The answer is Spring Potential

Explanation:

Because all the others are a mechanical form of energy

The boy weighs at about 80 kg. When, as illustrated, a N 784 guy balances the youngster on a teeter-totter.

A way to determine how much material, in mass, makes up a physical body.

In classical mechanics, an object's mass is essential to Newton's equations of motion because it affects the force required to accelerate it and, subsequently, how much inertia it has.

Language expert Peter Trudgill claims that the name "Tittermatorter" from the Norfolk language is its origin. Trudgill can trace all of his great-great-grandparents to a tiny region of eastern Norfolk.

As per the question:

Weight is come under gravity and become force

80g = mg

m = 80

Force = 80(9.8) = 784N

Thus, the answer is 784N.

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Answer:

Explanation:

solar

Answer:

28.3 m/s 45° below horizontal

Explanation:

Given in the y direction:

Δy = -20 m

v₀ = 0 m/s

a = -10 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (-10 m/s²) (-20 m)

v = -20 m/s

In the x direction, acceleration is 0, so v = v₀ = 20 m/s.

The magnitude is found with Pythagorean theorem:

v² = (20 m/s)² + (-20 m/s)²

v = 28.3 m/s

The direction is found with trig:

θ = atan(-20 m/s / 20 m/s)

θ = -45°

Answer:

Kx=4.0

Ky=0.0

Lx=6.0

Ly=0.0

Mx=4.0

My=3.0

The components of the vector K is -4i

The components of the vector M is 3.99i + 3.0j.

The components of the vector L is 6.0i.

The sum of the three vectors is 6.7.

The result obtained from the subtraction of vector K from vector L, is 10.0.

The given vectors:

The components of the vector K is calculated as follows;

\(K_x = -4 \times cos(0) = - 4.0\\\\K_y = - 4 \times sin(0) = 0\)

The components of the vector M is calculated as follows;

\(M_x = 5.0 \times cos(37)= 3.99 \\\\M_y = 5.0 \times sin(37) =3.0\)

The components of the vector L is calculated as follows;

\(L_x = 6 \times cos(0) = 6.0\\\\L_y = 6 \times sin(0) = 0\)

The sum of the three vectors is calculated as follows;

\(K+ M + L = (K_x + M_x + L_x) + (K_y + M_y + L_y)\\\\K+ M + L = (-4 + 3.99 + 6) + (0 + 3 + 0)\\\\K+ M + L = 5.99i + 3j\\\\Resultant = \sqrt{5.99^2 + 3^2} \\\\Resultant = 6.7\)

The subtraction of vector K from vector L, is calculated as follows;

\(L - K = 6i - (-4i)\\\\L-K = 6i + 4i\\\\L-K = 10i\\\\Resultant = \sqrt{10^2} \\\\Resultant = 10.0\)

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Answer:

Since the two forces are represented by Fap and For, we can assume that Fap refers to the force applied by your hand on the dog while petting it, and For refers to the equal and opposite force applied by the dog's body on your hand.

The diagram showing your hand petting a dog would look something like this:

```

____

/ \

/ \

/ D \

/ \

/____________\

H

```

In this diagram, the force Fap is represented by an arrow pointing from your hand towards the dog's body, and the force For is represented by an arrow pointing in the opposite direction, from the dog's body towards your hand.

We can describe the two forces as follows:

- Fap: The force applied by your hand on the dog's body while petting it.

- For: The equal and opposite force applied by the dog's body on your hand, according to Newton's third law of motion.

From the information provided in the question, the mass of the beaker is 144.4 g.

From the information provided in the complete question;

volume of water = 74 mL

Mass of water = 74 g

specific heat of glass = 0.18 cal/g ∙ °C

specific heat of water = 1.0 cal/g ∙ C°

Mass of glass =  x g

Total heat gained by the system = 2000.0cal

Temperature rise = 20.0°C

Heat gained by system = Heat gained  by glass + Heat gained by water

Heat gained by glass = x ×  0.18 × 20

Heat gained by water = 74  ×  1.0 × 20

Hence;

2000 =  (x ×  0.18 × 20) + ( 74  ×  1.0 × 20)

2000 - 1480 =  (x ×  0.18 × 20)

x = 520/3.6

x = 144.4 g

Missing parts;

A glass beaker of unknown mass contains 74.0 ml of water. The system absorbs 2000.0cal of heat and the temperature rises 20.0°C as a result. What is the mass of the beaker? The specific heat of glass is 0.18

cal/g °C, and that of water is 1.0 cal/g °C.​

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Answer:

FRANZ REULEAUX

Late 19th century kinematics and the theory of machines as seen through the contributions of the German engineering scientist, Franz Reuleaux (1829-1905), often called the "father of kinematics". Extremely famous in his time and one of the first honorary members of ASME, Reuleaux was largely forgotten in much of modern mechanics literature in English until the recent rediscovery of some of his work. In addition to his contributions to kinematics, we review Reuleaux's ideas about design synthesis, optimization and aesthetics in design, engineering education as well as his early contributions to biomechanics. A unique aspect of this review has been the use of Reuleaux's kinematic models at Cornell University and in the Deutsches Museum as a tool to rediscover lost engineering and kinematic knowledge of 19th century history of machine.

Answer:

R = 28.125 ohms

Explanation:

Given that,

The voltage of a bulb, V = 4.5 V

Current, I = 0.16 A

We need to find the resistance of the filament. Using Ohm's law,

V = IR

Where

R is the resistance of the filament

So,

\(R=\dfrac{V}{I}\\\\R=\dfrac{4.5}{0.16}\\\\R=28.125\ \Omega\)

So, the resistance of the filament is equal to 28.125 ohms.

The mass of the crate is approximately 74.63 kg.To determine the crate's mass, we can use Newton's second law of motion.

The Newton's law of motion states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, this can be expressed as:

Net Force = mass × acceleration

In this case, the net force acting on the crate is the force applied by the horse (60.0 N) minus the force of friction (10.0 N), which is given as:

Net Force = 60.0 N - 10.0 N = 50.0 N

The acceleration of the crate is given as 0.67 m/s².

We can now rearrange the equation to solve for mass:

mass = Net Force / acceleration

mass = 50.0 N / 0.67 m/s²

mass ≈ 74.63 kg

Therefore, the mass of the crate is approximately 74.63 kg.

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The IMA ( Ideal Mechanical Advantage ) of the system where a 3000 N engine is lifted a distance of 0.5 m is 12

IMA = \(F_{out}\) / \(F_{in}\)

W = F * d

IMA = Ideal Mechanical Advantage

\(F_{out}\) = Output force

\(F_{in}\) = Input force

W = Work done

F = Force

d = Distance

\(F_{out}\) = 3000 N

\(d_{out}\) = 0.5 m

\(d_{in}\) = 6 m

According to law of conservation of energy,

\(W_{in}\) = \(W_{out}\)

\(F_{in}\) \(d_{in}\) = \(F_{out}\) \(d_{out}\)

\(F_{in}\) = ( 3000 * 0.5 ) / 6

\(F_{in}\) = 250 N

IMA = \(F_{out}\) / \(F_{in}\)

IMA = 3000 / 250

IMA = 12

IMA can also be found using,

IMA = \(d_{in}\) / \(d_{out}\)

IMA = 6 / 0.5

IMA = 12

Therefore, The IMA ( Ideal Mechanical Advantage ) of the system is 12

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a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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131.2 J and The last one on number 8

I gave the same answer and it passed.

7) The final energy of the ball after rolling for 10 m is 182.4 J so, option C is correct.

8) When friction is negligible the total energy is the sum of kinetic and potential energy is constant so, option A is correct.

Energy is the ability to perform work in physics. It could exist in several different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc. Additionally, there is heat and work, which is energy being transferred from one body to another.

Given:

A moving object is rolling on a surface that is 5 m off the ground,

The speed of the object, v = 4 m/s,

The mass of the object, m = 3.2 kg,

Calculate the kinetic energy after 10 meters as shown below,

KE = 1/2 × 4² × 3.2

KE = 25.6 J

Calculate the potential energy as shown below,

PE = 3.2 × 9.8 × 5

PE = 156.8 J

Thus, total energy = KE + PE

The total energy = 25.6 + 156.8

The total energy = 182.4 J

8) when there is no resistance. Combined mechanical energy I.e. the total amount of kinetic and potential energy is constant.

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The statement "the speed of light is always the same no matter how fast you are moving" is true. This phenomenon is known as the constancy of the speed of light.

According to the theory of relativity, the speed of light in a vacuum is a constant value that is independent of the motion of the observer. This means that no matter how fast you are moving, you will always measure the speed of light to be the same value.

This idea may seem strange and counterintuitive, but it has been experimentally verified and is now a fundamental principle of modern physics. It has important consequences for our understanding of the nature of space and time, and it has played a key role in the development of many important scientific theories, including the theory of relativity.

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Answer:

Explanation:

Calculate the volume of the lead

\(V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}\)

Now calculate the bouyant force acting on the lead

\(F_L = Vpg\)

\(F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N\)

This force will act in upward direction

Gravitational force on the lead due to its mass  will act in downward direction

Hence the difference of this two force

\(T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N\)

If V is the volume submerged in the water then bouyant force on the bobber is

\(F_B=V'pg\)

Equate bouyant force with the tension and gravitational force

\(F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}\)

Now Total volume of bobble is

\(\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\\)

=\(\large\boxed{4.52 \%}\)

Answer: a. It would be 140 N

I don’t know, I just got it right

We have that the Diameter of the disks is mathematically given as

d= 0.01858 m

Question Parameters:

Generally the equation for the Electric field  is mathematically given as

\(E=q/eA\\\\Where\\\\A=\pi d^2 / 4\\\\Therefore\\\\ 1.0 * 10e5= \frac{4 * 1.5 * 10e9 * 1.6 * 10 e-19}{(8.85 * 10e-12 * 3.14 * d2 )}\\\\\)

d= 0.01858 m

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