What is the correct answer? Please

Answer:

c) Cohesive forces stronger than adhesive forces reduce the height of the liquid in the capillary tube, whereas adhesive forces stronger than cohesive forces increase the height of the liquid.

Explanation:

Two types of forces bring about capillary action.

One is cohesion, which is the intermolecular attraction between like molecules (that is, the liquid molecules). The second force, called adhesion, is an attraction between unlike molecules, such as those in a liquid and in the sides of a glass tube.

If adhesion is stronger than cohesion, the contents of the tube will be pulled upward. This process continues until the adhesive force is balanced by the weight of the liquid in the tube.

The new volume of the gas whose pressure was changed would be = 40 milliliters.

The initial volume(V1)of the gas= 20ml

The initial pressure(P1) = 4 atm

The final pressure(P2) = 2 atm

The final volume(V2) = ?

Using the general gas formula;

P1V1 = P2V2

V2 = P1V1/P2

= 4×20/2

= 40ml

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Answer:

Water- 9.982 grams

toluene-8.669 grams

chloroform - 14.832 grams

Explanation:

the units of density are listed as g/mL. So for every mL of substance you have, you will have that many grams.

Water- .9982g/mL * 10 mL

As you can see, the units of "mL" cancel each other out, leaving just the gram amount of water.

Answer:

Keep a close eye on her in case she starts giving birth to the next pup at the same time. A greenish/brown discharge may suggest a placenta has separated. If you see this, a puppy should be born within the next 2-4 hours.

If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.

The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.

According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:

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Both ATP and ADP can release one inorganic phosphate. The given statement about ATP/ADP is true.

Adenosine Tri Phosphate (ATP) and Adenosine Di Phosphate (ADP) are two critical organic compounds in the metabolism and are essential to the flow of energy in living cells. Hydrolysis is a specific type of chemical reaction in which water molecules break one or more than one chemical bonds.

Hydrolysis of ATP is an exorganic reaction in which one molecule of ATP reacts with one molecule of water to generate one molecule of ADP and One molecule of inorganic phosphate along with some energy.

Hydrolysis of ADP is also an exorganic reaction in which one molecule of ADP reacts with one molecule of water to generate one molecule of Adenosine Mono Phosphate (AMP) and One molecule of inorganic phosphate along with some energy.

Hence, the hydrolysis of both ATP and ADP leads to the generation of inorganic phosphate. Therefore, the given statement is true.

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Answer: high pressure, high temperature water extraction

Explanation:

Answer:

C). high pressure, high temperature water extraction

Explanation:

The molar mass in grams of "one mole" of each substance is:

Fe: 55.845 g/mol

\(Cl_2\): 70.906 g/mol

\(FeCl_3\): 162.204 g/mol

To calculate the molar mass in grams of "one mole" of each substance, we need to determine the atomic masses of the elements involved in the equation.

The atomic mass of iron (Fe) is 55.845 g/mol.

For chlorine (\(Cl_2\)), we need to consider that the molar mass of \(Cl_2\) is twice the atomic mass of chlorine because the formula shows that two chlorine atoms combine to form one molecule of \(Cl_2\). The atomic mass of chlorine is 35.453 g/mol, so the molar mass of \(Cl_2\) is 2 * 35.453 g/mol = 70.906 g/mol.

The formula for iron(III) chloride (\(FeCl_3\)) indicates that one mole of \(FeCl_3\)contains one mole of iron and three moles of chlorine. Therefore, we can calculate the molar mass of \(FeCl_3\)by summing the atomic masses of iron and chlorine:

Molar mass of \(FeCl_3\)= (1 * atomic mass of Fe) + (3 * atomic mass of Cl)

Substituting the values, we have:

Molar mass of \(FeCl_3\) = (1 * 55.845 g/mol) + (3 * 35.453 g/mol)

= 55.845 g/mol + 106.359 g/mol

= 162.204 g/mol

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Explanation:

here's the answer to your question

Answer:

Explanation:

When Tollen's test is done by aldehyde , silver ion is converted into silver which forms a layer which looks like a mirror.

Ag⁺ + e = Ag

It is a reduction process where silver(1) ion is reduced to metallic silver.

Aldehyde is oxidized to carboxylate ion.

CH₃CHO + 2 OH⁻ = CH₃COO⁻ + H₂O + H⁺ + 2e

Visual indicator is silver metal which forms silver mirror at the bottom of test tube .

Answer:

you use hairspray and then use the lighter flame touching the hairspray as its spraying out and there is a way to make a sort of blow torch type of thing I recommend not doing so because its dangerous

Answer:

(c) is the correct answer

CH4(g)+2O2(g)⟶CO2(g)+2H2O(l)

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When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy).

The potential energy that a huge item has in relation to a different massive object due to gravity is known as gravitational energy and gravitational potential energy. When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy). Bringing two things farther apart increases the gravitational potential energy.

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Answer:

Answer is explained in the explanation section below.

Explanation:

This question is requires the diagram, which I have drawn and it is attached in the attachment below. Please for this answer, refer to the diagram attached in the attachment below.

Referring to the diagram, attached. As we know that, Allylic secondary carbocations are more stable than Allylic tertiary carbocations.

Hence,

C2 will have a more positive charge since a tertiary carbocation (C2) is more stable than a secondary carbocation (C4). Therefore, the resonance structure will favor the positive charge at C2.

The resonance structure formed for 2-methyl 1-3 penatdiene are allylic secondary and tertiary carbocation compounds.

Protonation is the addition of hydrogen or the protons to the carbon in an organic compound. The addition of hydrogen takes place at the carbon that forms the stable compound.

The protonation of 2-methyl-1,3 pentadiene is given in the image attached.

The expected carbocation in the structure with the positive charge is C-2, as it forms a more stable product than C-4 due to less repulsion.

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Answer:

2.00n2g

Explanation:

hope its attachments

Answer:

consistent

Explanation:

in this phrase, consistent means that your results do not falter and prove that your answer is performed correctly and efficiently. if an experiments results are repeated and you get a different outcome, you should restart your process and evaluate what mightve hone wrong.

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Answer:

is has around 1/5 lyrics of water

Answer:

\(1 \: mole \: = \: 6.02 \times {10}^{23} \: molecules \\ 0.350 \: moles \: = \: (0.350 \times 6.02 \times {10}^{23} ) \: molecules \\ = 2.107 \times {10}^{23} \: molecules\)

Answer:

Question 1 : the empirical formula for the compound is CBr₄.

Question 2 : the molecular formula for the compound is CBr₄.

To determine the empirical formula and molecular formula of the compound, we need to analyze the given percentage composition and molecular weight. Let's go through the process step by step:

Empirical Formula:

The percentage composition by mass states that the compound contains 3.622% carbon and 96.38% bromine. We can assume a 100g sample of the compound to simplify the calculations.

Mass of carbon = (3.622/100) * 100g = 3.622g

Mass of bromine = (96.38/100) * 100g = 96.38g

Next, we need to find the moles of each element. We can use their atomic masses to convert the masses to moles.

Atomic mass of carbon (C) = 12.01 g/mol

Atomic mass of bromine (Br) = 79.90 g/mol

Moles of carbon = Mass of carbon / Atomic mass of carbon = 3.622g / 12.01 g/mol ≈ 0.3017 mol

Moles of bromine = Mass of bromine / Atomic mass of bromine = 96.38g / 79.90 g/mol ≈ 1.205 mol

To find the simplest whole-number ratio between the elements, we divide both moles by the smallest number of moles (0.3017 mol in this case):

Moles of carbon (C) = 0.3017 mol / 0.3017 mol = 1

Moles of bromine (Br) = 1.205 mol / 0.3017 mol ≈ 4

Therefore, the empirical formula for the compound is CBr₄.

Molecular Formula:

Given that the molecular weight (molar mass) of the compound is 331.6 amu, we need to compare it with the empirical formula weight.

Empirical formula weight = (Atomic mass of carbon × Number of carbon atoms) + (Atomic mass of bromine × Number of bromine atoms)

= (12.01 amu × 1) + (79.90 amu × 4) = 12.01 amu + 319.6 amu = 331.61 amu

The molecular weight is very close to the empirical formula weight, indicating that the empirical formula represents the molecular formula as well. Therefore, the molecular formula for the compound is also CBr₄.

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29 is not the best answer depends on the context and the rules for significant figures.

What is best answer?

The best answer depends on the context and the rules for significant figures. If we assume that we need to round to three significant figures:

Therefore, 29 is not the best answer.

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Answer: frfg6

Explanation: 655tyyt

Answer:

The elements toward the bottom left corner of the periodic table are the metals that are the most active in the sense of being the most reactive.

The most highly reactive elements are typically found at the far left (Group 1) and far right (Group 17) of the periodic table.

Group 1 elements, also known as alkali metals, are located on the far left of the periodic table. They have one electron in their outermost energy level and are highly reactive due to their tendency to lose that electron to achieve a stable electron configuration. This makes them very reactive with water and other substances.

Group 17 elements, known as halogens, are located on the far right of the periodic table. They have seven electrons in their outermost energy level and are highly reactive due to their strong tendency to gain one electron to achieve a stable electron configuration. This makes them reactive with metals and other elements.

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According to ideal gas law, 3404.5 liters of fluorine gas are needed to form 519 L of sulfur hexafluoride gas if the following reaction takes place at 2.00 atm and 273.15 K .

The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.

Substitution of values in equation gives, V= 3×8.314×273//2=3404.5 liters.

Thus,  3404.5 liters of fluorine gas are needed to form 519 L of sulfur hexafluoride gas if the following reaction takes place at 2.00 atm and 273.15 K .

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There is no reason to run these solutes at the 20 MWCO because they are both much smaller than the MWCO of the membrane.

The MWCO (molecular weight cut off) is the molecular weight of a solute at which it will be retained by a membrane during a process such as ultrafiltration or dialysis. If a solute has a molecular weight higher than the MWCO of a membrane, it will be retained and not pass through the membrane. If the molecular weight of a solute is lower than the MWCO, it will pass through the membrane.

In this case, glucose has a molecular weight of 180 g/mol (6 carbons x 12 g/mol per carbon + 6 oxygens x 16 g/mol per oxygen) and albumin has a molecular weight of approximately 81,942 g/mol (607 amino acids x 135 g/mol per amino acid). Both of these solutes have molecular weights that are much lower than 20,000 g/mol, which is a typical MWCO for ultrafiltration or dialysis membranes.

They would both easily pass through the membrane and be lost during the process. Instead, a membrane with a much lower MWCO would be needed if we wanted to retain these solutes during a process such as ultrafiltration or dialysis.

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Answer:

1.25 M

Explanation:

(Step 1)

Convert grams to moles using the molar mass of Na₂O.

Atomic Mass (Na): 22.990 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (Na₂O): 2(22.990 g/mol) + 15.999 g/mol

Molar Mass (Na₂O): 61.979 g/mol

 34.8 g Na₂O               1 mole
----------------------  x  ---------------------  =  0.561 moles Na₂O
                                    61.979 g

(Step 2)

Convert milliliters to liters.

1,000 mL = 1 L

 450.0 mL                 1 L
------------------  x  -------------------  =  0.4500 L
                             1,000 mL

(Step 3)

Calculate the molarity using the molarity ratio.

Molarity = moles / volume (L)

Molairty = 0.561 moles / 0.4500 L

Molarity = 1.25 M