Answer:
133° because vertically opposite angles are equal!
Hope this helped!
A shop has a sale of 30% off all items in stock.
If the original price of a dress is £30 what would be its sale price?
Answer:
9
Step-by-step explanation:
because, 30 (the percentage) /100(over one hundred percent) x 30(the actual price) = 9
6 ≥ -6(a +2)
pls help i don't understand
Answer:
a ≥ -3
Step-by-step explanation:
Answer:
a ≥ -3
Step 1: Simplify both sides of the inequality.
6 ≥ − 6a − 12
Step 2: Flip the equation.
−6a − 12 ≤ 6
Step 3: Add 12 to both sides.
−6a − 12 + 12 ≤ 6 + 12
−6a ≤ 18
Step 4: Divide both sides by -6.
−6a/−6 ≤ 18/−6
a ≥ −3
I used a calculator, hope this helps
\( \frac { - 8}{3} x + 4y = 8\)x, y intercept -8/3x+4y=8please help?!
The x-intercept = -3
The y-intercept = 2
Explanation:
the given equation: -8/3 x+4y=8
\(\lbrack tex\rbrack\frac{ - 8}{3}x+4y=8\lbrack/tex\rbrack\)To get the x intercept, we make y = 0.
\(\begin{gathered} \frac{-8x}{3}+\text{ 4(0) = 8} \\ \frac{-8x}{3}\text{ = 8} \\ \text{cross multiply } \\ -8x\text{ = 8}\times3 \\ -8x\text{ = 24} \\ x\text{ = 24/-8} \\ x\text{ = -3} \end{gathered}\)The x-intercept = -3
To get y intercept, we will make x = 0
\(\begin{gathered} \frac{-8(0)}{3}+\text{ 4y = 8} \\ 0\text{ + 4y = 8 } \\ 4y\text{ = 8 } \\ y\text{ = 8/4} \\ y\text{ = 2} \end{gathered}\)The y-intercept = 2
jake has an account that is compounded every month at a rate of 3.5%.if he invests $20,000,what will the balance be after 5 years
suppose that three in ten adults own an answering machine. a researcher selects a random sample of 38 adults, and is interested in the number of people in the sample will own an answering machine. a) find the probability that in a sample of 38, exactly 15 people own an answering machine. b) find the probability that in a sample of 38, at most 15 people own an answering machine.
A sample of 38 adults who has own an answering machine,
a) The probability that in a sample of 38, exactly 15 people own an answering machine is 0.061.
b) The probability that in a sample of 38, at most 15 people own an answering machine is 0.92381.
We have three in ten adults own an answering machine . That is probabilty of success, p = 3/10
Sample size, n = 38
Using Binomial Probability distribution,
X ~ Binom( 38, 0.3)
where X is random variable of adults has own an answering machine.
P(X= x) = ⁿCₓ (p)ˣ1-p)⁽ⁿ⁻ˣ⁾
The probability that in a sample of 38, exactly 15 people own an answering machine. , P(X= 15)
= ³⁸C₁₅(0.3)¹⁵ )(1 - 0.3)²³
= 38!/15!23! (0.3)¹⁵5(0.7)²³
= 0.06075 ~ 0.061
so, P(X= 15) = 0.061
b) The probability that in a sample of 38, at most 15 people own an answering machine, P(X<= 15)
Now, P(X≤ 15) = P( X= 1 ) + P(X= 2) + ... + P(X= 15) or 1 - P(X>15)
= 0.923814121
Hence, required probabilities
are 0.061 and 0.9238.
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Find the largest open interval where the function is changing as requested. Increasing f(x) = 1 / x2 + 1
The largest open interval where the function f(x) = 1/(x^2+1) is increasing is (-∞, 0) ∪ (0, ∞). On this interval, the function is increasing from negative infinity to zero and from zero to positive infinity.
Explanation:
To find where the function is increasing, we need to find where the first derivative of the function is positive. Taking the derivative of f(x), we get:
f'(x) = (-2x) / (x^2 + 1)^2
The denominator of this expression is always positive, so the sign of f'(x) is determined by the numerator. The numerator is negative for x < 0 and positive for x > 0. Therefore, f(x) is decreasing on (-∞, 0) and increasing on (0, ∞).
We also need to check the endpoints of these intervals to make sure that the function is increasing on the entire interval. As x approaches negative infinity, the function approaches 0, and as x approaches positive infinity, the function approaches 0. Therefore, the function is increasing on (-∞, 0) ∪ (0, ∞).
In summary, the largest open interval where the function f(x) = 1/(x^2+1) is increasing is (-∞, 0) ∪ (0, ∞). On this interval, the function is increasing from negative infinity to zero and from zero to positive infinity.
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Adam purchased some items at the school store. He bought 3 pencils for $0.15 each and 5 single-subject notebook
If these items cost a total of $6.45, what was the cost of each notebook?
O A. $1.20
B. $1.26
O c. $1.29
OD. $1.38
Answer:
The answer is A
Step-by-step explanation:
Fist multiply 3 and .15 to get .45 for 3 pencils. Then subtract .45 from 6.45 and get 6. Then divided 6 by 5 to get 1.2 for each book
i think the answer is a: $1.20
my work:
3 x 0.15 = 0.45.
6.45 - 0.45 = 6.00
6.00 / 5 = 1.20
and i checked my work by doing 1.20 x 5 + 0.40 = $6.45.
How many polynomials can be formed with and 5 as zeroes?
The number of polynomials that can be formed with -2 and 5 as zeroes are more than 1.
What is a polynomial?
A polynomial is a mathematical statement made up of coefficients and indeterminates that uses only the operations addition, subtraction, multiplication, and powers of positive integers of the variables.x² -3x - 7 is an illustration of a polynomial with a single indeterminate x.
Given that the zeros of a polynomial are -2 and 5.
The polynomial that has a and b as zeors is p(x) = k[x² + (a+b)x + ab].
where k is a real number.
The polynomial that has -2 and 5 zeros is
p(x) = k[x² + (-2 + 5)x + (-2)×5]
p(x) = k[x² + 3x - 10]
Where k is a real number.
The number of real numbers is infinity.
The number of polynomials is infinity.
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WILL MARK THE BRAINLIEST!!! Also hurry!
When a number is added to of itself, the result is 24. The equation that models this problem is n + } n = 24.
What is the value n?
On = 18
O n =20
O n = 21
O n = 235
Answer:
20.
Step-by-step explanation:
20+(1/5)20=24
max picks two different cards without replacement from a standard $52$-card deck. what is the probability that the cards are of different suits?
The probability that cards are from different suits is \(\frac{39}{51}\)
Probability of an event E represented by P(E) can be defined as (The number of favorable outcomes )/(Total number of outcomes).
There are 4 suits hearts, diamonds, club and spade in a standard deck of 52 cards.
Each of them has 13 cards each .
So when we pick first card from a single suit
we can pick it in 13 ways , now 12 cards are left.
We can pick the 2nd card from the same suit in 12 different ways .
So to pick 2 cards from a single suit we have 13x12 ways.
to pick 2 card from 4 suits = 4x13x12=624 ways
Total ways of choosing 2 cards from the pack of 52 cards is 52 X 51 =2652
probability that the cards are of same suits=\(\frac{624}{2652} =\frac{12}{51}\)
probability that the cards are of different suits=\(1-\frac{12}{51} =\frac{39}{51}\)
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For a set of nondegenerate levels with energy ε/k = 0, 100 and 200 K, calculate the probability of occupying the ground level (i = 0) when T = 90 K.
P0,90K =
2) For a set of nondegenerate levels with energy ε/k = 0, 100 and 200 K , calculate the probability of occupying the excited state (i = 1) when T =90 K
P1,90K
3) For a set of nondegenerate levels with energy ε/k = 0, 100 and 200 K , calculate the probability of occupying the excited state (i = 2) when T =90 K
P2,90K=
For a set of nondegenerate levels with energy ε/k = 0, 100 and 200 K , calculate the probability of occupying the ground level (i = 0) when T =900 K
For a set of nondegenerate levels with energy ε/k = 0, 100 and 200 K , calculate the probability of occupying the excited state (i = 1) when T =900 K
The probability of occupying the ground level increases as the temperature increases, while the probability of occupying the excited states decreases.
Given data: Nondegenerate energy levels with ε/k = 0, 100, and 200 K.'
The probability of occupying the ground level (i=0) when T=90 K is:
P0,90K = e^(-ε0/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }
MP0,90K = e^(-0/k × 90 K) / { e^(-0/k × 90 K) + e^(-100/k × 90 K) + e^(-200/k × 90 K) }P0,90K
= 1 / { 1 + e^(-100 × 9) + e^(-200 × 9) }= 0.9475 (approximately)
The probability of occupying the excited state (i=1)
when T=90 K is:P1,90K = e^(-ε1/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }P1,90K
= e^(-100/k × 90 K) / { e^(-0/k × 90 K) + e^(-100/k × 90 K) + e^(-200/k × 90 K) }P1,90K
= e^(-9000) / { 1 + e^(-9000) + e^(-18000) }= 0.052 (approximately)
The probability of occupying the excited state (i=2) when
T=90 K is:P2,90K = e^(-ε2/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }P2,90K
= e^(-200/k × 90 K) / { e^(-0/k × 90 K) + e^(-100/k × 90 K) + e^(-200/k × 90 K) }P2,90K
= e^(-18000) / { 1 + e^(-9000) + e^(-18000) }
= 0.0005 (approximately)
The probability of occupying the ground level (i=0) when
T=900 K is:
P0,900K = e^(-ε0/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }
P0,900K = e^(-0/k × 900 K) / { e^(-0/k × 900 K) + e^(-100/k × 900 K) + e^(-200/k × 900 K) }
P0,900K = 1 / { 1 + e^(-100 × 90) + e^(-200 × 90) }
= 0.9999999999970 (approximately)
The probability of occupying the excited state (i=1)
when T=900 K is:P1,900K = e^(-ε1/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }P1,900K
= e^(-100/k × 900 K) / { e^(-0/k × 900 K) + e^(-100/k × 900 K) + e^(-200/k × 900 K) }
P1,900K = e^(-90000) / { 1 + e^(-90000) + e^(-180000) }= 1.5 × 10^-8 (approximately)
Therefore, the probability of occupying the ground level increases as the temperature increases, while the probability of occupying the excited states decreases.
To know more about Probability, The probability of occupying the ground level increases as the temperature increases, while the probability of occupying the excited states decreases.
Given data: Nondegenerate energy levels with ε/k = 0, 100, and 200 K.'
The probability of occupying the ground level (i=0) when T=90 K is:
P0,90K = e^(-ε0/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }
MP0,90K = e^(-0/k × 90 K) / { e^(-0/k × 90 K) + e^(-100/k × 90 K) + e^(-200/k × 90 K) }P0,90K
= 1 / { 1 + e^(-100 × 9) + e^(-200 × 9) }= 0.9475 (approximately)
The probability of occupying the excited state (i=1)
when T=90 K is:P1,90K = e^(-ε1/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }P1,90K
= e^(-100/k × 90 K) / { e^(-0/k × 90 K) + e^(-100/k × 90 K) + e^(-200/k × 90 K) }P1,90K
= e^(-9000) / { 1 + e^(-9000) + e^(-18000) }= 0.052 (approximately)
The probability of occupying the excited state (i=2) when
T=90 K is:P2,90K = e^(-ε2/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }P2,90K
= e^(-200/k × 90 K) / { e^(-0/k × 90 K) + e^(-100/k × 90 K) + e^(-200/k × 90 K) }P2,90K
= e^(-18000) / { 1 + e^(-9000) + e^(-18000) }
= 0.0005 (approximately)
The probability of occupying the ground level (i=0) when
T=900 K is:
P0,900K = e^(-ε0/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }
P0,900K = e^(-0/k × 900 K) / { e^(-0/k × 900 K) + e^(-100/k × 900 K) + e^(-200/k × 900 K) }
P0,900K = 1 / { 1 + e^(-100 × 90) + e^(-200 × 90) }
= 0.9999999999970 (approximately)
The probability of occupying the excited state (i=1)
when T=900 K is:P1,900K = e^(-ε1/kT) / { e^(-ε0/kT) + e^(-ε1/kT) + e^(-ε2/kT) }P1,900K
= e^(-100/k × 900 K) / { e^(-0/k × 900 K) + e^(-100/k × 900 K) + e^(-200/k × 900 K) }
P1,900K = e^(-90000) / { 1 + e^(-90000) + e^(-180000) }= 1.5 × 10^-8 (approximately)
Therefore, the probability of occupying the ground level increases as the temperature increases, while the probability of occupying the excited states decreases.
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an automobile manufacturer has given its van a 28.3 miles/gallon (mpg) rating. an independent testing firm has been contracted to test the actual mpg for this van since it is believed that the van has an incorrect manufacturer's mpg rating. after testing 200 vans, they found a mean mpg of 28.0 . assume the population standard deviation is known to be 2.6 . is there sufficient evidence at the 0.01 level to support the testing firm's claim? step 2 of 6 : find the value of the test statistic. round your answer to two decimal places.
For a sample of rating of an automobile manufacturer's van regarding rating of 28.3 miles/gallon (mpg), the Z-test statistic value is equals to the -1.631.
Z-test is a parametric test. When the sample size is sufficiently large, it is mostly used. This test statistic is computed a standard normal distribution. It is then compared with the critical value (obtained from z-table). If the test statistic value is greater than it, there is evidence to reject the null hypothesis. We have an automobile manufacturer with its van rating. A sample of 200 vans is randomly considered. Sample size, n = 200
Mean of rating = 28
Standard deviations = 2.6
Lavel of significance= 0.01
To test the firm'claim we have to consider hypothesis testing here. Since it is claimed by an automobile manufacturer that its car has a 28.3 miles/gallon (MPG) rating, therefore, the null hypothesis and alternative can be stated as:
\(H_0 :μ = 28.3\)
\(H_a :μ≠28.3\)
Now, to determine the value of the test statistic, consider the Z-test : \( z = \dfrac{{M - \mu }}{{\dfrac{\sigma }{{\sqrt n }}}}\)
where, M -> mean
n --> sample size
Substitute all known values in above formula, \(= \dfrac{{28 - 28.3}}{{\dfrac{{2.6 }}{{\sqrt {200} }}}}\\\)
\(= \dfrac{{-0.3}}{{\dfrac{{0.26 }}{{\sqrt {2} }}}}\\\)
=> z = - 1.631
Hence, required test statistic value is -1.631.
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what conclusions can be made about the series [infinity] 3 cos(n) n n = 1 and the integral test?
The Integral test, which is also known as Cauchy's criterion, is a method that determines the convergence of an infinite series by comparing it with a related definite integral.
In a series, the terms can either be decreasing or increasing. When the terms are decreasing, the Integral test is used to determine convergence, whereas when the terms are increasing, the Integral test can be used to determine divergence. For example, consider the series\[S = \sum\limits_{n = 1}^\infty {\frac{{\ln (n + 1)}}{{\sqrt n }}} \]. Now, we'll apply the Integral test to determine the convergence of the above series. We first represent the series in the integral form, which is given as\[f(x) = \frac{{\ln (x + 1)}}{{\sqrt x }},\] and it's integral from 1 to infinity is given as \[I = \int\limits_1^\infty {\frac{{\ln (x + 1)}}{{\sqrt x }}} dx\]. Next, we'll find the integral of f(x), which is given as \[I = \int\limits_1^\infty {\frac{{\ln (x + 1)}}{{\sqrt x }}} dx\]\[u = \ln (x + 1),\] so, the equation can be rewritten as \[I = \int\limits_0^\infty {u^2 e^{ - 2u} du}\]\[I = \frac{1}{{\sqrt 2 }}\int\limits_0^\infty {{y^2}e^{ - y} dy}\]\[I = \frac{1}{{\sqrt 2 }}\Gamma (3)\]. The given series [infinity] 3 cos(n) n n = 1 is a converging series because the Integral test is applied to determine its convergence.
The Integral test helps to determine the convergence of a series by comparing it with a related definite integral. The Integral test is only applicable when the terms of the series are decreasing. If the series fails the Integral test, then it's necessary to use other tests to determine the convergence or divergence of the series. The Integral test is a simple method for determining the convergence of an infinite series. Therefore, the series [infinity] 3 cos(n) n n = 1 is a converging series. The Integral test is applied to determine the convergence of the series and it is only applicable when the terms of the series are decreasing.
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Solve by factoring
3v^2-10v+3=
\(3v^2-10v+3=0\\\\\implies 3v^2 - 9v-v +3=0\\ \\\implies 3v(v-3)-(v-3)=0\\\\\implies (v-3)(3v-1)=0\\\\\implies v = 3,~~v=\dfrac 13\)
MMMM THE MODERATORS ARE MAKING ME FLIPPING ANGRY! I NEED SOMEONE TO ANSWER MY QUESTION PLEASE .
Answer:
780
Step-by-step explanation:
So 5% is 39 so 5% x 20 is 100% do the same with the 39 so do
39 x 20 = 780
Which represents the inverse of the function f(x) = 4x?
• h(x) = x + 4
• h(x) = x-4
•h(x) = 3/4x
•h(x) = 1/4x
Answer:
f^-1 (x) = x/4
Step-by-step explanation:
Hello, I need help! The question is "Today you will look over the following problem that Nancy worked and explain what she did incorrectly and why it does not work. Then tell me what information Nancy would need to know in order to use this theorem correctly"
Answer:
Step-by-step explanation:
Remark
The ratios are certainly correct but that doesn't mean that they show similarity. SSA is a very dangerous proposition to use. Redraw triangle DEF of that DF is going to upwards to your right hand side. Make E as it was before. Why isn't this right?
It isn't right because E has gone from being an acute angle to an obtuse angle (an angle larger than 90 but less than 180).
The ratios are still true, but the angles do not match. So the whole answer is incorrect.
Convert 191% to a decimal.
Answer:
1.91
Step-by-step explanation:
191% means \(\sf \frac{191}{100}\)
So to write 191% as a decimal, simply divide it by 100.
To divide a number by 100, move the decimal point to the left by 2 places.
\(\sf \implies 191 \div 100=1.91\)
SOLUTION: a diver jumps from a diving board that is 24 feet above the water. the height of the diver is given by h= -16(t-1.5)(t+1) where the height h is measured in feet and the time t
Answer:
The diver will hit the water at 1.5 seconds
Step-by-step explanation:
Given
\(h= -16(t-1.5)(t+1)\)
Required (Missing from the question)
When will the diver hit the water?
To do this, we simply solve for t
When the diver hits the water, the height is 0 (at that point)
So, substitute 0 for h in \(h= -16(t-1.5)(t+1)\)
\(0= -16(t-1.5)(t+1)\)
Divide both sides by -16
\(\frac{0}{-16} =\frac{-16(t-1.5)(t+1)}{-16}\)
\(\frac{0}{-16} =(t-1.5)(t+1)\)
\(0 =(t-1.5)(t+1)\)
\((t-1.5)(t+1)=0\)
Split
\(t - 1.5 = 0\) or \(t + 1 = 0\)
Solve for t
\(t = 1.5\) or \(t = -1\)
But time (t) can not be negative.
So:
\(t = 1.5\)
Hence, the diver will hit the water at 1.5 seconds
five hamburgers cost 5.25 at this rate what is the cost of 8 hamburgers
Answer: 8.4
Step-by-step explanation: 5.25 divided by 5 is 1.05. So 1.05 x 8 is 8.4
Solve for a and b. please help.
Answer:
a= 22.5
b= 37.5
Step-by-step explanation:
In △BCD:
Applying Pythagoras' Theorem,
a² +30²= b²
a² +900= b² -----(1)
In △ABC:
Applying Pythagoras' Theorem,
b² +50²= (40 +a)² -----(2)
Substitute (1) into (2):
a² +900 +50²= 40² +2(40)(a) +a² (expand bracket)
a² +900 +2500= 1600 +80a +a²
a² +3400= a² +80a +1600 (simplify)
a² +3400 -a² -80a -1600= 0 (bring everything to 1 side)
-80a +1800= 0
80a= 1800 (+80 on both sides)
a= 1800 ÷80
a= 22.5
Subst. a= 22.5 into (1):
22.5² +900= b²
b²= 506.25 +900
b²= 1406.25
b= √1406.25 (square root both sides)
b= 37.5 (reject negative value since b is a length)
☆(a +b)²= a² +2ab +b²
How can i explain to children what the length of 2000 feet looks like to children
2000 feet can be represented as 20 blue whales in a row of each 100 feet.
What is a blue whale?
Blue whales are the largest mammals to have ever existed on Earth. With lengths of up to 100 feet and weights of up to 200 tons, these magnificent marine creatures command the waters.I feet = 30.48 centimeters
To explain what the length of 2000 feet looks like:
Take the example of a blue whale of 100 feet.
Now, imagine placing up 20 blue whales one behind the other.
20 × 100 feet = 2000 feet
Therefore, 2000 feet can be represented as 20 blue whales in a row of each 100 feet.
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Find the value of x.
110°
50°
5xº
A. 12
B. 8
OO
C. 10
D. 36
Answer:
A) 12
Step-by-step explanation:
110-50=60
60/5 = 12
Hope this helps!!
You need to create a fenced off region of land for cattle to graze. The grazing area must be a total of 500 square feet, surrounded by a fence, and in the shape of a regular polygon. Within this grazing area, the length of the apothem must be 10 feet long. Part I. Find the total perimeter of the grazing area. Part II. If the cost of the fence is $7.95 per linear foot, how much will it cost to place a fence around the entire grazing area
Using area of regular Polygon, the perimeter of the total grazing area of regular polygon is 100 feet and the cost to place a fence around the entire grazing area is $795.
According to the question,
You need to create a fenced off region of land for cattle to graze. The grazing area must be a total of 500 square feet, surrounded by a fence, and in the shape of a regular polygon.
Within this grazing area, the length of the apothem must be 10 feet long.
In part 1 we asked to find the total perimeter of the grazing area using below polygon formulaThe formula of the area of regular polygon = ap/2
Where a is apothem and p is the perimeter.
500 = 10 x p/2
1,000 = 10 x p
100 = p
Hence the perimeter of regular polygon the total grazing area is 100 feet.
In part 2, the cost of the fence is $7.95 per linear foot, how much will it cost to place a fence around the entire grazing areaNow cost of fencing 1 foot = $7.59
So, cost of fencing 100 feet = 7.59 x 100 = 759
Hence, the cost to place a fence around the entire grazing area of polygon is $795.
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The annual yield per lemon tree is fairly constant at 390 pounds per tree when the number of trees per acre is 150 or fewer. For each additional tree over , the annual yield per tree for all trees on the acre decreases by 4 pounds due to overcrowding.
A. Express the yield per tree, Y, in pounds, as a function of the number of lemon trees per acre, x, where x is greater than 150.
B. Express the total yield for an acre, T, in pounds, as a function of the number of lemon trees per acre, x, where x is greater than 150.
Answer:
kbvhhjbvgivftivdtufyuffgi
7. Karton soku rozlano do trzech szklanek w stosunku do 3 : 4 : 5. Szklanka, w której było go najmniej, zawierała 150 ml soku. Oblicz, jaką objętość miał sok w każdym z pozostałych dwóch naczyń.
Answer:
kinang sulat iyan 769pqpq
now imagine inserting a 40 cm spoon so that it makes a 60◦ angle with the normal to the interface. what angle does the spoon appear to make with the normal to the interface when it is submerged?
When the spoon is submerged, it will appear to make a different angle with the normal to the interface than when it was inserted.
This is due to the phenomenon of refraction, where light waves bend as they pass from one medium to another. The angle of refraction can be calculated using Snell's law. In this case, assuming the medium above the interface is air and the medium below is water, the angle of refraction will be approximately 42◦. Therefore, the spoon will appear to make a 42◦ angle with the normal to the interface when it is submerged.
When a spoon is inserted into water at a 60° angle with the normal to the interface, the angle at which it appears to the observer will be different due to the phenomenon of refraction. To find the apparent angle, you can use Snell's Law: n1 * sinθ1 = n2 * sinθ2, where n1 and n2 are the refractive indices of air and water, respectively, and θ1 and θ2 are the incident and refracted angles.
For air, n1 ≈ 1, and for water, n2 ≈ 1.33. With θ1 = 60°, you can calculate θ2:
sinθ2 = (n1 * sinθ1) / n2
θ2 = arcsin((1 * sin60°) / 1.33)
Solving for θ2 will give you the apparent angle of the submerged spoon with respect to the normal to the interface.
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make and test a conjecture about the product of any three odd intergers
Conjecture: The product of any three odd integers is always an odd integer.
To test this conjecture, we can consider different sets of three odd integers and calculate their product to see if it is always odd.
Example 1:
Let's take three odd integers: 3, 5, and 7.
Product = 3 * 5 * 7 = 105
105 is an odd integer, confirming the conjecture.
Therefore, based on these observations, we can conclude that the conjecture is true: the product of any three odd integers is always an odd integer.
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25h + 40 = −15h − 80
Answer:
h= -3Step-by-step explanation:
25h + 40 = −15h − 80
25h + 15h = -80 - 40
40h = - 120
h = -120/4
h= -3
Answer:
h = -3
Step-by-step explanation:
25h +40 = -15h -80
-----------------------------
40h = -120
h= -3
Kennedy has a gross income of $95,000. What is her total tax due?
The total tax due is $45000.
It is required to find the total tax due.
What Are Taxes?Taxes are mandatory contributions levied on individuals or corporations by a government entity—whether local, regional, or national.
Given:
This made her total gross income= $140,000
Gross income =$95,000
According to given question we have
Total tax due=total gross income- Gross income
=$140,000-$95,000
=$45000
Therefore, the total tax due is $45000.
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The total gross income is $140,000 is missing.