What is anthropogenic greenhouse?

The distance travelled by the car when the brakes were applied is 12.11 m

The following data were obtained from the question:

The distance travelled can be obtained as follow:

s = ut + ½at²

s = (25 × 0.45) + (½ × 8.5 × 0.45²)

s = 11.25 + (4.25 × 0.2025)

s = 11.25 + 0.860625

s = 12.11 m

Thus, the distance travelled in 0.45 s by the car is 12.11 m

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A) The bearing of R from P is 140 degrees (measured clockwise from the north).

B) R is about 5.15 km north of P.

a) To find the bearing of R from P, we need to first determine the angle between the north-south line (i.e., the line joining P and Q) and the line joining P and R. Let's call this angle x.

Since the bearing of R from Q is 140 degrees, we know that the angle between the line joining Q and R and the north-south line is 180 - 140 = 40 degrees.

Now, in triangle PQR, we have two angles: x and 40 degrees. We can find the third angle by noting that the sum of the angles in any triangle is 180 degrees. Therefore,

x + 40 + 90 = 180

Solving for x, we get x = 50 degrees.

So the bearing of R from P is 90 + 50 = 140 degrees (measured clockwise from the north).

b) To find how far north of P R is, we need to use trigonometry. Let's call the distance we're looking for y.

In triangle PQR, the angle opposite side QR (i.e., angle QPR) is 180 - 90 - 50 = 40 degrees. We also know that QR = 8 km.

Using the sine function, we can write:

sin 40 = y/QR

Rearranging, we get:

y = QR * sin 40 = 8 * sin 40 ≈ 5.15 km (rounded to 2 decimal places)

Therefore, R is about 5.15 km north of P.

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Answer:

Explanation:

we know that the value of the force of gravitation acting between two bodies is,

F=(GM₁.M₂)/R²............(i)

where F⇒ Gravitational force

G⇒ gravitational constant

and its value is 6.67×10⁻¹¹ m³/kg.sec²

M₁⇒mass of the first object

M₂⇒mass of the second object

R⇒ represents the distance separating the object's center

Now, as per the question,

since both objects are identical, M₁=M₂=1000kg

Gravitational force, F=400N

putting the values in equation (i),

400=(6.67×10⁻¹¹×1000×1000)/R²

so, after doing cross multiplication,

R²=(6.67×10⁻¹¹×1000×1000)/400

R²=(6.67×10⁻⁵)/400

R²=0.0166×10⁻⁵

R=0.407×10⁻³ m

so, the spheres must be separated by a distance 0.407×10⁻³m.

Answer:

76 N north-east

Explanation:

V = √(44²+62²) = 76 N

The difference in the stellar parallax observed from Neptune compared to Earth is the distance from the observer to the star. The further the observer is from the star, the smaller the stellar parallax appears to be.

Stellar parallax is the apparent displacement of the position of a nearby star that takes place as a result of the Earth's motion around the Sun. The measurement of the angle of the parallax allows astronomers to determine the distance of the star from Earth.

On the other hand, Neptune is a planet in our solar system that is located farther from the Sun than Earth. Stellar parallax observed from Neptune would differ from the stellar parallax we observe from Earth because of the planet's location in our solar system.

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Answer:

So it's clear that Earth's hot iron core isn't what creates the magnetic field around our planet. ... On Earth, flowing of liquid metal in the outer core of the planet generates electric currents. The rotation of Earth on its axis causes these electric currents to form a magnetic field which extends around the planet

Explanation:

Answer:

to have courage and show the strength of your character. ... A person with true grit has passion and perseverance. Goals are set and followed through.

Explanation:

for example: i had the passion and the courage to finish my school work and chores for i can go out with my friends and to get out of the house for a bit and have fun so i had the courage to finish chores from the house and do some schoolwork for i can finish ad hang out with some friends. so i had the strength to finish everything because i didn't want to be doing school work and chores any more so i had the passion to finish up quickly  

Answer:

The answer is "DACB".

Explanation:

The missing data of the question is defined in the attached file please find it.

Using formula:

\(\to F= m \cdot a\\\\ \to m= 5 \ kg\)

In object A:

\(F= 15 \\\\a =\frac{F}{m} = \frac{15}{5} = 3\)

In object B:

\(F= 30 \\\\a =\frac{F}{m} = \frac{30}{5} = 6\)

In object C:

\(F= 20 \\\\a =\frac{F}{m} = \frac{20}{5} = 4\)

In object D:

\(F= 0 \\\\a =\frac{F}{m} = \frac{0}{5} = 30\)

That's why the answer is "DACB" .

The work done in pumping all the liquid out of the tank is 2500π lb-ft.

The potential energy of an object is given by the formula:

PE = mgh

Given:

Density of oil = 50 lb/ft^3

Diameter of the tank = 10 ft ( r = 5 ft)

To calculate the work done, we need to find the mass of the oil and the height it is lifted. Let's start by finding the mass:

Volume of oil in the tank:

The volume of a hemisphere = (2/3) * π * (r^3)

Volume = (2/3) * π * (5^3) = (2/3) * π * 125 = 250π/3 ft^3

Mass of the oil:

Mass = Volume * Density = (250π/3) * 50 lb

Now, we need to find the height of the tank. For a hemisphere, the height is equal to the radius (5 ft).

Finally, we can calculate the work done:

Work = PE = mgh = (250π/3) * 50 lb * 5 ft

Work = (250π/3) * 50 * 5 lb-ft

       = 2500π lb-ft

So, the work done in pumping all the liquid out of the tank is approximately 2500π lb-ft.

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The value of the phase constant, φ is 0

Graph of x(t)Using the graph, we can see that the equation for the position function x(t) = A sin (ωt + φ)  is as follows;

x(t) = A sin (ωt + φ)  ....... (1)

where; A = amplitude

ω = angular frequency = 2π/T

T = time period of oscillation = 2π/ω

φ = phase constant

x(t) = displacement from the mean position at time t

From the graph, we can see that the amplitude, A is 4 m. Using the given information in the question, we can find the angular frequencyω = 2π/T, but T = time period of oscillation. We can get the time period of oscillation, T from the graph. From the graph, we can see that one complete cycle is completed in 2 seconds. Therefore,

T = 2 seconds

ω = 2π/T

   = 2π/2

   = π rad/s

Again, from the graph, we can see that at time t = 0 seconds, the displacement, x(t) is 0. This means that φ = 0.  Putting all this into equation (1), we have;

x(t) = 4 sin (πt + 0)

The phase constant, φ = 0.

The value of the phase constant, φ is 0 and this means that the equation for the position function is; x(t) = 4 sin (πt)

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Answer:

2.2 s

Explanation:

His vertical initial velocity  u =0

vertical displacement h = 24 m .

vertical acceleration g = 9.8 m /s²

h = ut + 1/2 gt²

24 = 1/2 x 9.8 x t²

t = 2.2 s .

Time of fall = 2.2 s

The velocity vs displacement curve will be a parabolic graph and the height attained by object B will be lesser than object A.

Velocity is the change in displacement of an object with the change in time. It is a vector quantity because it has both magnitude and direction. The SI unit of velocity is meter per second (m/s).

u = 0

x₀ = Distance travessed by both the discs

F= constant

f = 0

a) (F-f) = ma

a = F/ m

v² = u² + 20x

v² = 0 + (2F/m)x

v = \(\sqrt{(2f/m)x}\)

v v/s x curve will be similar to parabolic graph of v² = (2f/ m)x

b) Energy would be conserved for both.

Since, velocity gained by both is same as Vi = \(\sqrt{(F/m)Xo}\)

-mgh = 1/2mvf² - 1 mvi² = - 1 mvi²

mgh = 1/2mvi² = FXo/2m  (Since, vf = 0)

So, h = (FXo/ 2mg)

Since, mb > ma

Hb < Ha

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The magnitude of the torque about the origin is approximately 1776 Nm. To calculate the magnitude of the torque about the origin, we need to find the cross product between the position vector and the force vector.

Position vector r = (4+16j) m

Force vector F = (111+123) N

The torque about the origin (τ) can be calculated as:

τ = r × F

To find the cross product, we can use the determinant of a 2x2 matrix:

τ = |  i j k |

    | 4 16 0 |

   |111 123 0|

Expanding the determinant:

τ = (16 * 0 - 0 * 123)i - (4 * 0 - 0 * 111)j + (4 * 123 - 16 * 111)k

τ = -1776k Nm

The magnitude of the torque is given by:

|τ| = \(\sqrt((-1776)^2\)) Nm

|τ| ≈ 1776 Nm

Therefore, the magnitude of the torque about the origin is approximately 1776 Nm.

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Answer:

C. Acid

Explanation:

If you have chemistry classes and performed experiments regarding acids and bases, you would physically tell it's acid if the lithmus paper turned red and base if it turned blue. Also, in the pH level chart, there are only two characteristics--acidic and basic. Since it has less than 7 pH, it is definitely acid. Plus, remember the taste of some vitamin C tablets? It has a sour taste to it, isn't it? This is because of ascorbic acid.

The given properties are indicating the substance is acid. Therefore, option (C) is correct.

An acid can be described as any substance that is capable of losing a proton to another substance.  A base can be described as a molecule or ion that can accept a hydrogen ion from an acid.

Acidic substances can be identified by their sour taste. Acid is usually a molecule that donates an H⁺ ion and can be energetically favorable after a loss of an H⁺ ion. Acids are also capable to turn blue litmus into the red.

Bases can be characterized by a slippery texture and a bitter taste. A base that can be dissolved in water as an alkali. When bases and acids react, they form salts and water. Bases can turn red litmus into blue.

The acid reacts vigorously with most metals to form hydrogen. Acidic substances have pH of less than 7.

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Answer:

Balanced Forces

But what exactly is meant by the phrase unbalanced force? What is an unbalanced force? In pursuit of an answer, we will first consider a physics book at rest on a tabletop. There are two forces acting upon the book. One force - the Earth's gravitational pull - exerts a downward force. The other force - the push of the table on the book (sometimes referred to as a normal force) - pushes upward on the book.

Since these two forces are of equal magnitude and in opposite directions, they balance each other. The book is said to be at equilibrium. There is no unbalanced force acting upon the book and thus the book maintains its state of motion. When all the forces acting upon an object balance each other, the object will be at equilibrium; it will not accelerate.

Consider another example involving balanced forces - a person standing on the floor. There are two forces acting upon the person. The force of gravity exerts a downward force. The floor exerts an upward force.

Since these two forces are of equal magnitude and in opposite directions, they balance each other. The person is at equilibrium. There is no unbalanced force acting upon the person and thus the person maintains its state of motion.

Unbalanced Forces

Now consider a book sliding from left to right across a tabletop. Sometime in the prior history of the book, it may have been given a shove and set in motion from a rest position. Or perhaps it acquired its motion by sliding down an incline from an elevated position. Whatever the case, our focus is not upon the history of the book but rather upon the current situation of a book sliding to the right across a tabletop. The book is in motion and at the moment there is no one pushing it to the right. (Remember: a force is not needed to keep a moving object moving to the right.) The forces acting upon the book are shown below.

The force of gravity pulling downward and the force of the table pushing upwards on the book are of equal magnitude and opposite directions. These two forces balance each other. Yet there is no force present to balance the force of friction. As the book moves to the right, friction acts to the left to slow the book down. There is an unbalanced force; and as such, the book changes its state of motion. The book is not at equilibrium and subsequently accelerates. Unbalanced forces cause accelerations. In this case, the unbalanced force is directed opposite the book's motion and will cause it to slow down.

To determine if the forces acting upon an object are balanced or unbalanced, an analysis must first be conducted to determine what forces are acting upon the object and in what direction. If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced. An object is said to be acted upon by an unbalanced force only when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.

Given, Speed of the sound, v=675 m/s

The wavelength of the wave, λ=15 m

Relation between speed, wavelength, and frequency of a wave is given by

Where f is the frequency of the sound.

On substituting the known values,

Which gives us,

Therefore the frequency of the sound in the given medium is 45 Hz.

A diagram of energy flow from trophic level to trophic level is shaped like a pyramid because the amount of energy decreases as you move up the pyramid.

The base of the pyramid contains the largest amount of energy because it is the first level of the food chain. As you continue to move up the pyramid, the trophic levels become more complex and require more energy to maintain.

The energy is transferred from one level to the next through the process of consumption. Consumers at lower levels rely on producers for their energy, while consumers at higher levels rely on consumers at lower levels for their energy.

As a result, the amount of energy decreases as you move up the pyramid, creating the pyramid shape.

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The work done required to pump all of the water (a) over the side is 6.8094 × 10⁶ J and (b) out of an outlet 2 m over the side is 11.349 × 10⁶ J.

The total amount of work done required to pump all of the water in a circular swimming pool with a diameter of 14 m whose circular side is 3 m high, and the depth of the water is 1.5 m can be calculated as follows:

(a) Pump all of the water over the side:

We have been given that the circular swimming pool has a diameter of 14 m. The depth of the water is 1.5 m. So the radius of the pool can be calculated as:

r = d/2 = 14/2 = 7 m

The volume of the water that needs to be pumped out of the pool is given by the formula:

Volume of water = πr²h

Where h is the depth of the water.

V = πr²h= 22/7 × 7 × 7 × 1.5= 231 m³

The mass of water that needs to be pumped out of the pool can be calculated as follows:

Mass of water = Volume of water × Density of water = 231 × 1000= 231000g

The gravitational force on the water can be calculated as follows:

Gravitational force on water = Mass of water × Acceleration due to gravity = 231000 × 9.8= 2269800 N

Work done in pumping all the water over the side can be calculated as follows:

Work done = Gravitational force on water × Height from the surface to the top of the pool= 2269800 × 3= 6.8094 × 10⁶ J

(b) Pump all of the water out of an outlet 2 m over the side:

Work done in pumping all the water out of an outlet 2 m over the side can be calculated as follows:

Work done = Gravitational force on water × Height of outlet from the surface= 2269800 × 2= 4.5396 × 10⁶ J

Therefore, the total amount of work (in joules) required to pump all of the water over the side and pump all of the water out of an outlet 2 m over the side of the pool is 6.8094 × 10⁶ + 4.5396 × 10⁶ = 11.349 × 10⁶ J.

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Answer:

I believe work has been done

Explanation:

Answer:

Physical Changes :- The substance in which no new substance is formed are called physical changes.

The molecular composition of the substance are totally same.

For example :- Crushing a mineral into powder.

The equivalent resistance is 6R/11, the current flowing through the circuit is 55/6R, and the voltage across resistor R2 is 55/3 V when the three parallel resistors R1, R2, and R3 are joined in parallel across a 5V battery.

The unit of resistance is ohm (Ω), named after the German physicist Georg Simon Ohm. One ohm is defined as the amount of resistance that will allow one ampere of current to flow with one volt of applied potential difference.

To find the equivalent resistance (R_eq) of the three parallel resistors R1, R2, and R3, we can use the formula:

1/R_eq = 1/R1 + 1/R2 + 1/R3

Substituting R1 = R, R2 = 2R, and R3 = 3R, we get:

1/R_eq = 1/R + 1/2R + 1/3R

1/R_eq = (6/6R + 3/6R + 2/6R) / (1/6R)

1/R_eq = 11/6R

R_eq = 6R/11

To find the current (I) flowing through the circuit, we can use Ohm's Law, which states that:

I = V/R_eq

Substituting V = 5V and R_eq = 6R/11, we get:

I = 5 / (6R/11)

I = 55/6R

To find the voltage (V_R2) across resistor R2, we can use the formula:

V_R2 = I * R2

Substituting I = 55/6R and R2 = 2R, we get:

V_R2 = (55/6R) * (2R)

V_R2 = 55/3 V

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The main answer to the given question is -3.0 m/s.What is the explanation to the given question?Here, we need to find the ball's velocity relative to the ground at the instant of release.

So, let's assume that the upward direction is positive. Then, the velocity of the gondola (v₁) is -2.0 m/s (as it is moving in the opposite direction).The passenger throws the ball down at a speed of 5.0 m/s relative to his body. So, the velocity of the ball relative to the passenger (v₂) is -5.0 m/s (as it is thrown downwards).

Now, we can find the velocity of the ball relative to the ground (v₃) using relative velocity formula, which is:v₃ = v₂ + v₁v₃ = (-5.0) + (-2.0)v₃ = -7.0 m/sSo, the ball's velocity relative to the ground at that instant is -7.0 m/s. Therefore, the main answer is -3.0 m/s.

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The ball's velocity relative to the ground at the instant of release is 7.0 m/s.

1. The balloon-supported gondola is rising at a speed of 2.0 m/s. This means that the gondola and everything inside it, including the passenger and the ball, are moving upward with a velocity of 2.0 m/s relative to the ground.

2. The passenger in the gondola throws a small ball down at a speed of 5.0 m/s relative to his body. Since the passenger is moving upward with the gondola at 2.0 m/s, we need to consider the relative motion between the passenger and the ball.

3. When the passenger throws the ball downward, the ball's velocity relative to the passenger is 5.0 m/s downward.

4. To find the ball's velocity relative to the ground at the instant of release, we need to combine the velocity of the gondola (2.0 m/s upward) and the ball's velocity relative to the passenger (5.0 m/s downward).

5. Since the velocities are in opposite directions, we subtract the magnitudes: 5.0 m/s - 2.0 m/s = 3.0 m/s.

6. The negative sign indicates that the ball is moving downward relative to the ground.

7. Finally, to find the ball's overall velocity relative to the ground at the instant of release, we consider the magnitude only: |-3.0 m/s| = 3.0 m/s.

8. However, since the problem states that the ball's velocity is 5.0 m/s relative to the passenger's body, we need to take the direction into account. Thus, the ball's velocity relative to the ground at that instant is 3.0 m/s downward (or -3.0 m/s).

Therefore, the ball's velocity relative to the ground at the instant of release is 7.0 m/s.

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The acceleration of the car at the top of the hill is 6.6 m/s²

acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

The third kinematic equation is applied to determine the car's tangential acceleration, as illustrated below: v2 = u2 + 2as, where a represents the vehicle's acceleration.

2x50 a = -5.25 m/s²;

2as = v² - u² a

= v²-u² / 2s

a = 102 - 252

At the summit of the hill, the car's centripetal acceleration is given as ac=v²/r

ac=10²/25

ac=4 m/s2.

At the summit of the hill, the car's net acceleration is computed as follows: a net = a2 + ac

a net = (-5.25)2 + 42

a net = 6.6 m/s2.

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Complete Question -

A 1600 kg car is traveling over a hill that has a radius of curvature of 25 m. The car is slowing down as it goes over the hill. It slows down at a constant rate from a speed of 25 m/s to a speed of 10 m/s over a distance of 50 m ending at the top of the hill. The net acceleration of the car at the top of the hill is most nearly

Answer:

0.58

Explanation:

Sinẞ = opposite ÷ hypotenuse

Sinẞ = 5 ÷ 8.6

Sinẞ = 0.5814

Sinẞ ≈ 0.58

Answer:    0.58

Explanation:

hope this helps

Fun Fact: Peanuts aren’t technically nuts

Answer:

OPTION B 285 volts

Explanation:

USE OHM'S LAW

V = IR

V = 28.5 ×10 = 285 volts

HOPE IT HELPED :)

Explanation:

incomplete question graph / fig is not available

The correct answer is option B: Q1 > Q2 > Q3.

Since the capacitors are connected in series, the charge on each capacitor must be the same. Therefore, Q1 = Q2 = Q3. However, the voltage across each capacitor will be different based on their capacitance values. Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can calculate the voltage across each capacitor as follows:

V1 = Q1/C1

V2 = Q2/C2 = Q1/(2C1)

V3 = Q3/C3 = Q1/(3C1)

Since the voltage across C2 is half that of C1, and the voltage across C3 is one-third that of C1, the voltage across C1 must be the largest. Therefore, Q1 has the largest charge, followed by Q2 and Q3. Thus, the correct answer is option B: Q1 > Q2 > Q3.

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Photovoltaic panels are used to produce alternating current using sunlight. It uses solar cells which are photoactive and produce a photoelectric effect and thereby a potential is created.

When photons from the light energy is hit on a metallic surface the photon collides with the electrons of the metals and electrons are ejected from the metal surface. This phenomenon is called photoelectric effect.

In a solar photovoltaic panel, photovoltaic cells layers of semi-conducting materials, such as silicon, are sandwiched photovoltaic cells. When photons from sunshine strike each layer, its unique electronic properties energise and produce an electric field.

The current required to generate electricity is produced through what is known as the photoelectric effect. Electricity produced by solar panels is in the direct current form. This is then transformed into an alternating current by passing via an inverter.

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