Answer:
m=(y2-y1) / x2-x1
4-(-4)=8
5-(-7)=12
12/8
Step-by-step explanation:
The radial probability function for a 2 s orbital is shown here. Classify the following statements as either true or false: (a) There are two maxima in this function because one electron spends most of its time at an approximate distance of 0.5 A from the nucleus and the other electron spends most of its time at an approximate distance of 3 A from the nucleus. (b) The radial probability function shown here and the probability density
both go to zero at the same distance from the nucleus, approximately 1 A. (c) For an
orbital, the number of radial nodes is equal to the principal quantum number,
(a) False. The radial probability function does not represent the positions of individual electrons, but rather the probability of finding an electron at a particular distance from the nucleus. (b) False. The radial probability function and probability density do not go to zero at the same distance. (c) True. For an ns orbital, the number of radial nodes is equal to the principal quantum number.
(a) The radial probability function represents the probability of finding an electron at a specific distance from the nucleus. It does not indicate the positions of individual electrons. The function may have maxima or peaks at certain distances, but it does not imply that each electron is located at those specific distances. Therefore, the statement is false.
(b) The radial probability function and probability density are related but represent different aspects. The radial probability function describes the probability of finding an electron at a particular distance, while the probability density represents the probability of finding an electron within a small volume around a point in space. They do not go to zero at the same distance from the nucleus. The radial probability function typically goes to zero at larger distances, while the probability density decreases but does not necessarily reach zero at the same distance. Therefore, the statement is false.
(c) The number of radial nodes in an orbital is indeed equal to the principal quantum number (n). For an ns orbital, where the angular momentum quantum number (l) is 0, the number of radial nodes is equal to n - 1. This means that an ns orbital with a principal quantum number of 2 (n = 2) will have one radial node. So the statement is true.
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Does anyone know how to solve this question?
e
Does anyone know how to solve this questionDoes anyone know how to solve this question
Step-by-step explanation:
Does anyone know how to solve this question
I need help this is due today, please don't answer just for points I will report
Answer:
straight angle addition theorem
Step-by-step explanation:
since the anglr of straight line is 180⁰ if the line in thr above is straight line its angles sum should be 180⁰. If the height is perpendicular to the base,the two angles will be equal.
angle MRO+ angle MRS= angle SRO [being a straight angle] which is the sum of 180°
1
2
X
-5
-4
-3
2
1
0
1
2
3
6
f(x)
-6
-2
0
4
4
0
-2
-6
-10
Based on the table, which best predicts the end
behavior of the graph of f(x)?
O As x, f(x)→∞, and as x→→∞, f(x)→∞.
O As x→∞, f(x)→∞, and as x→∞, f(x)→→∞
O As x, f(x)→∞, and as x→→∞, f(x)→∞
O As x→∞, f(x)→∞, and as x→∞, f(x)→
818
The statement that best describes the end behavior of the graph is given as follows:
As \(x \rightarrow -\infty, f(x) \rightarrow -\infty\), and as \(x \rightarrow -\infty, f(x) \rightarrow \infty\).
What is the end behavior of a function?It is given by it's limits as x goes to negative and positive infinity.
From the given table, it is found that f(x) starts with negative values, increases until it's maximum value then decays again, hence the correct statement is:
As \(x \rightarrow -\infty, f(x) \rightarrow -\infty\), and as \(x \rightarrow -\infty, f(x) \rightarrow \infty\).
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Calculate s2:n1 = 11n2 = 21df1 = 10df2 = 20s1 = 5.4SS1 = 291.6SS2 = 12482
The pooled variance, s_p^2, is 368.6957.
To calculate s2, we first need to calculate the pooled variance using the given formula:
s_p^2 = ((n1 - 1)*s1^2 + (n2 - 1)*s2^2) / (df1 + df2)
We know the values of n1, n2, df1, df2, s1, and SS1. We can use SS1 to calculate the sample variance for the first sample, s1^2, as follows:
s1^2 = SS1 / (n1 - 1) = 291.6 / 10 = 29.16
Similarly, we can use SS2 to calculate the sample variance for the second sample, s2^2, as follows:
s2^2 = SS2 / (n2 - 1) = 12482 / 20 = 624.1
Now, substituting the values in the formula for pooled variance, we get:
s_p^2 = ((11 - 1)*29.16 + (21 - 1)*624.1) / (10 + 20) = 368.6957
Therefore, the pooled variance, s_p^2, is 368.6957.
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Calculate the cost of the number of units used
Step-by-step explanation:
calculated the cost of numbers of units usex
(help pls) Determine the domain of the function, and choose the correct interval and inequality notations. f(x) = 1/2x + 8
Answer:
INTERVAL NOTATION: (-4) (-4) -- (BOTH ARE -4)
INEQUALITY: >-4 OR X<-4
Step-by-step explanation:
what is a type ii error? rejecting a false null hypothesis accepting a false alternate hypothesis rejecting a false alternate hypothesis failing to reject a false null hypothesis
A type II error is a statistical term used to describe the failure to reject a false null hypothesis. It occurs when the null hypothesis is actually false but is not rejected because the statistical test failed to find significant evidence against it.
In other words, it happens when an alternative hypothesis is true, but we fail to reject the null hypothesis.
Types of errors in hypothesis testing
There are two types of errors in hypothesis testing:
Type I error: Rejecting a true null hypothesis
Type II error: Failing to reject a false null hypothesis.Type I error occurs when a true null hypothesis is rejected while Type II error occurs when a false null hypothesis is not rejected. These types of errors are inversely related, meaning that a decrease in one type of error causes an increase in the other.
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A mountain climber found that the relationship between his altitude and the surrounding air
temperature is linear. The function f (a) = - -100 a + 75 represents this relationship, where a
is the altitude in meters and f(a) is the temperature in degrees Fahrenheit. According to this
function, by how much is the temperature decreasing for every meter that the mountain climber's
altitude increases?
IF
100
O IF
100
75 F
-75F
Answer:- 1/100 degrees Fahrenheit
Step-by-step explanation:
The directions say decreasing so it has to be negative, and the slope is showing how much it is decreasing every meter. y=mx+b. The mx is the slope which is where the answer is located.
The value where the histogram balances when supported at that point is called ____.
The value where the histogram balances when supported at that point is called the mode of the distribution.
The mode of distribution is the value that appears most frequently in the data set. It is often used as a measure of central tendency, along with the mean and median. The mode is especially useful when dealing with categorical or discrete data, where the possible values are limited and well-defined.
For example, the mode of a list of test scores might be the score that occurs most frequently, indicating the most common level of performance. In a histogram, the mode is the value where the distribution is highest, or where the histogram balances when supported at that point.
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67.77759 rounded to nearest meter
Answer:
68
Step-by-step explanation:
0.7 rounds to 1 so add 1 to 67 to get 68
sean needed to put 7 gallons 3 quarts of gas into his boat on Monday and twice as much on Saturday.if he had a 22 gallon jug of gas available, did he have enough gas for both days?
Answer:
No
Step-by-step explanation:
7 3/4 x 3 = 22 1/2
On Saturday, Jessica earned $45 for doing 3 hours of yard work. On Sunday, she did 5 hours of yard work. How much money did Jessica earn on Sunday? Solve using unit rates.
Answer:
Step-by-step explanation:
first of all, we need to divide $45 and the 3, we get 15, so shes making 15 dollars an hour. do 15 x 5=75. so the answer is 75
Question 2
if given an Expression, you will do which of the following (Check all that apply).
a
Simplify
Solve
b
Evaluate
Od
All of the Above
Answer:
I would say it's all of the above
Bushra purchases a car for $12,900. The car will depreciate at a rate of 15% each year.
After how many years will the value of the car be less than $3,000?
Since we can't have a fraction of a year, we need to round up to the equation nearest whole number. Therefore, it will take at least 7 years for the value of the car to be less than $3,000.
What is equation?An equation in mathematics is a statement that states the equality of two expressions. An equation is made up of two sides that are separated by an algebraic equation (=). For example, the argument "2x + 3 = 9" asserts that the phrase "2x Plus 3" equals the number "9." The purpose of equation solving is to determine the value or values of the variable(s) that will allow the equation to be true. Equations can be simple or complicated, regular or nonlinear, and include one or more elements. The variable x is raised to the second power in the equation "x2 + 2x - 3 = 0." Lines are utilised in many different areas of mathematics, such as algebra, calculus, and geometry.
V(1) = 0.85 * 12,900 = $10,965
V(2) = 0.85 * 10,965 = $9,320.25
\(V(n) = 0.85^n * 12,900\\0.85^n * 12,900 < 3,000\\n > log(3,000/12,900) / log(0.85)\\n > 6.48\\\)
Since we can't have a fraction of a year, we need to round up to the nearest whole number. Therefore, it will take at least 7 years for the value of the car to be less than $3,000.
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Answer:
9 years
Step-by-step explanation:
As the car depreciates at a constant rate of 15% each year, we can use the exponential decay formula to find the value of the car after t years.
Exponential Decay formula\(\boxed{f(t)=a(1-r)^t}\)
where:
a is the initial amount.r is the rate of decay (in decimal form).t is the time.Given the purchase price of the car is $12,900, a = 12900.
Given the car will depreciate at a rate of 15%, r = 0.15.
Substitute the values of a and r into the formula to create a function for the value of car after t years is:
\(f(t)=12900(1-0.15)^t\)
\(f(t)=12900(0.85)^t\)
To calculate after how many years the value of the car will be less than $3,000, substitute f(t) < 3000 and solve for t.
\(\implies 12900(0.85)^t < 3000\)
Divide both sides by 12900:
\(\implies (0.85)^t < \dfrac{3000}{12900}\)
\(\implies (0.85)^t < \dfrac{10}{43}\)
Take natural logarithms of both sides:
\(\implies \ln (0.85)^t < \ln\left(\dfrac{10}{43}\right)\)
Apply the log power law:
\(\implies t \ln (0.85) < \ln\left(\dfrac{10}{43}\right)\)
Divide both sides by ln(0.85), remembering to change the direction of the inequality sign since ln(0.85) is negative:
\(\implies t > \dfrac{\ln\left(\dfrac{10}{43}\right)}{\ln (0.85)}\)
\(\implies t > 8.9750695...\)
We need to round up to 9 years, since we can't have a fraction of a year.
Therefore, the value of the car will be less than $3,000 after 9 years.
Wendy jogs a 5.5-mile route in the city with her running club once a week. She also jogs a nature trail near her home once a week. The nature trail is 1.5 times as long as the route in the city. How many miles does Wendy jog in all each week? Write your answer as a whole number or decimal
Answer:
Wendy jogs 13.75 mile in all each week
Step-by-step explanation:
To determine how many miles Wendy jogs in all each week,
we will sum the distance she jogs in the city with her running club in a week to the distance she jogs along the nature trail near her home in a week.
The distance she jugs with her running club = 5.5 mile.
Now, we will determine the distance of the nature trail near her home.
From the question, the nature trail is 1.5 times as long as the route in the city.
Let the distance of the nature trail = \(x\)
and the distance of the route in the city be \(y\)
Hence, we can write that
\(x = 1.5 y\)
distance of the route in the city, \(y\) = 5.5 mile
∴ \(x = 1.5 \times 5.5\)
\(x =\) 8.25 miles
Hence, the nature trail is 8.25 mile
Then, the number of miles Wendy jogs in all each week is
5.5 mile + 8.25 mile = 13.75 mile
Hence, Wendy jogs 13.75 mile in all each week
an insurance company wants to conduct a customer satisfaction survey. because the company suspects the type of coverage might influence customers' opinions, it divides the list of customers based on what type of insurance they have (auto, homeowner, rental, life, disability, or a combination of these). if five customers are randomly selected from each group, what sampling method would this represent
If five customers are randomly selected from each group, a sampling method which this would represent is: C) Stratified.
What are the types of sampling?In Mathematics and Statistics, there are different types of sampling methods that are used by researchers and these include the following;
Convenience sampling.Cluster sampling.Random sampling.Systematic sampling.Stratified sampling.What is a stratified sampling?In Mathematics, stratified sampling can be defined as a type of sampling method in which the population is divided into distinct classes and a sample is randomly selected from each class for survey.
In this context, we can logically deduce that stratified sampling was used by this insurance company.
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Complete Question:
An insurance company wants to conduct a customer satisfaction survey. Because the company suspects the type of coverage might influence customers' opinions, it divides the list of customers based on what type of insurance they have (auto, homeowner, rental, life, disability, or a combination of these). If five customers are randomly selected from each group, what sampling method would this represent?
A) Simple Random Sample (SRS)
B) Systematic
C) Stratified
D) Cluster
a boat costs $16,690 and decreases in value by 14% per year. how much will the boat be worth after 11 years
Answer:
Step-by-step explanation:
16=45+11
What are the coordinates of PQR after a dilation with a scale factor of 2
lynne has \$8.00$8.00dollar sign, 8, point, 00 to spend on apples and oranges. apples cost \$0.65$0.65dollar sign, 0, point, 65 each, and oranges cost \$0.75$0.75dollar sign, 0, point, 75 each. if there is no tax on this purchase and she buys 555 apples, what is the maximum number of whole oranges she can buy?
Lynne can buy 5 apples and 6 oranges with her $8.00.
The first thing to do is determine how much money Lynne spends on the apples. Since she is buying 5 apples,
we can multiply the price of each apple ($0.65) by 5: $5 * 0.65 = $3.25
Therefore, Lynne has $8 - $3.25 = $4.75 to spend on oranges.
Now we need to determine the maximum number of whole oranges that she can buy with $4.75. We can do this by dividing $4.75 by the price of each orange ($0.75): $4.75 ÷ $0.75 = 6.33.
Since we can't buy a fraction of an orange, the maximum number of whole oranges Lynne can buy is 6. Therefore, Lynne can buy 5 apples and 6 oranges with her $8.00.
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there are 14 red marbles and 19 blue marbles in a bag you randomly choose one of the marbles what is the probability of choosing a red marble write your answer as a fraction in simplest form
Answer:
4/23
Step-by-step explanation:
Probability of choosing a red marble = # of red marbles / total # of marbles
We are told that there are 4 red marbles and 19 blue marbles
So the # of red marbles = 4
And the total # of marbles = 4 + 19
4 + 19 = 23
So there are a total of 23 marbles
Recall that probability of choosing a red marble is equal to # of red marbles / total # of marbles
Hence, the probability of choosing a red marble is 4/23
Note: 4/23 is already in it's simplest form so no simplifying has to be done.
Answer:
14/33
Step-by-step explanation:
There are 14 red marbles and 19 blue marbles, meaning that there are 33 marbles in all:
14 + 19 = 33
You are randomly choosing a red marble out of the total amount of marbles. 14/33
Note that you cannot simplify the fraction anymore, and so 14/33 is your answer.
~
What does the three lined equal sign mean
Answer: identical to/same as
Step-by-step explanation:
Answer:
The ≡ sign means identical to, similar but not exactly the same as, equals
Step-by-step explanation:
Hope this helps! =D
Mark me brianliest and Have a good day! =D
TRUE/FALSE. as one does more and more separate hypothesis tests, the risk of a type i error accumulates and is called the experiment-wise alpha level.
TRUE. As one performs multiple separate hypothesis tests, the risk of committing a Type I error (rejecting a true null hypothesis) accumulates.
This overall risk is referred to as the experiment-wise alpha level or family-wise error rate (FWER). It represents the probability of making at least one Type I error among all the conducted tests.
When multiple hypothesis tests are performed simultaneously or sequentially, the individual alpha levels (typically set at 0.05) for each test may no longer be appropriate. This is because if we conduct, for example, 20 separate tests with an alpha level of 0.05 for each test, the cumulative chance of committing at least one Type I error can be much higher than the desired 5%.
To control the experiment-wise error rate, various multiple comparison procedures and adjustments can be employed, such as the Bonferroni correction or the Holm-Bonferroni method. These methods aim to maintain a desired level of significance for the entire set of tests, reducing the risk of accumulating Type I errors.
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In a survey of the dining preferences of 110 dormitory students the end of the spring semester; the following facts were discovered about Adam's Lunch (AL) Pizza Tower (PT) and the Dining Hall (DH) 27 liked AL but not PT 13 liked AL only 43 lilked AL 41 liked PT 59 liked DH liked PT and AL but not DH lked PT and DH How many liked PT or DH?
Answer: 72 students liked PT or DH.
To determine the number of students who liked Pizza Tower (PT) or Dining Hall (DH), we can use the principle of inclusion-exclusion.
Given the following information:
- 27 liked AL but not PT (AL - PT)
- 13 liked AL only (AL)
- 43 liked AL (AL)
- 41 liked PT (PT)
- 59 liked DH (DH)
- 13 liked PT and AL but not DH (PT ∩ AL - DH)
- Unknown: Number of students who liked PT or DH (PT ∪ DH)
We can use the formula:
n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
Let's calculate the number of students who liked PT or DH:
n(PT ∪ DH) = n(PT) + n(DH) - n(PT ∩ DH)
We are given that 59 students liked DH, and 41 students liked PT. However, we need to determine the number of students who liked both PT and DH (n(PT ∩ DH)).
Using the principle of inclusion-exclusion, we have the following information:
- 13 liked PT and AL but not DH (PT ∩ AL - DH)
- 59 liked DH (DH)
- 13 liked PT and AL but not DH (PT ∩ AL - DH)
To find n(PT ∩ DH), we subtract the number of students who liked PT and AL but not DH from the total number who liked PT (PT):
n(PT ∩ DH) = n(PT) - n(PT ∩ AL - DH)
n(PT ∩ DH) = 41 - 13 = 28
Now, we can calculate the number of students who liked PT or DH:
n(PT ∪ DH) = n(PT) + n(DH) - n(PT ∩ DH)
n(PT ∪ DH) = 41 + 59 - 28
n(PT ∪ DH) = 72
Therefore, 72 students liked PT or DH.
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help me 20 pts pls and brainliest
Answer:
elaboration
Step-by-step explanation:
tthe definition of elaboration is the addition of more detail concerning what has already been said. so out of these options, elaboration best fits answers the question
neeed help with this thanks
URGENTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT
Answer:
(-3, 5)= (4x +4) and x = (x-2)
The graph has 10 turning points.
Step-by-step explanation:
In triangle def, if m∠d is (2x)°, m∠e is (3x − 2)°, and m∠f is (x 8)°, what is the value of x? 29 31 34 59
In triangle def, if m∠d is (2x)°, m∠e is (3x − 2)°, and m∠f is (x + 8)°, then the value of x is 29.
What is Triangle?A triangle is a three-sided polygon that consists of three edges and three vertices.
Triangle is DEF
if m∠d is (2x)°, m∠e is (3x − 2)°, and m∠f is (x 8)°
We need to find the value of x.
We know that the sum of three angles of triangle is 180 degrees
m∠d + m∠e + m∠f=180°
2x+3x-2+x+8= 180°
6x+6=180
Subtract 6 on both sides
6x=174
Divide by 6 on both sides.
x=174/6
x=29
Hence, the value of x is 29.
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If the value of n nickles plus d dimes is c cents, what is n in terms of d and c?
When the value of n nickles plus d dimes is c cents, n in terms of d and c will be n = c - d.
How to illustrate the information?It should be noted that an expression is simply used to show the relationship that can be illustrated based on the data.
In this case, we want to calculate the value of n nickles plus d dimes is c cents, what is n in terms of d and c.
This will be:
c = n + d
Therefore, to get n will be calculated thus:
Subtract d from both sides.
c - d = n + d - d
n = c - d
Therefore, when the value of n nickles plus d dimes is c cents, n in terms of d and c will be n = c - d.
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Which of the following equations represents the problem "The sum of two consecutive integers is -17"?
2x + 2
2x + 1 = -17
2x = -17
Answer:
2x + 1 = -17
Step-by-step explanation:
consecutive integers would be
x and x+1
when you add them together its
2x+1