What element is the only 4th period Alkali Metal

Answer:

D) Methane CH4

Explanation:

Hello,

In this case, among the options, assuming for all the fuels a mass of 100 g, the combustion reaction reaction and stoichiometry for carbon dioxide is shown below:

A) Benzene C6H6

\(C_6H_6+\frac{15}{2} O_2\rightarrow 6CO_2+3H_2O\)

\(m_{CO_2}=100gC_6H_6*\frac{1molC_6H_6}{78gC_6H_6}*\frac{6molCO_2}{1molC_6H_6} *\frac{44gCO_2}{1molCO_2} =347.4gCO_2\)

B) Cyclohexane C6H12

\(C_6H_{12}+9 O_2\rightarrow 6CO_2+6H_2O\)

\(m_{CO_2}=100gC_6H_{12}*\frac{1molC_6H_{12}}{84gC_6H_{12}}*\frac{6molCO_2}{1molC_6H_{12}} *\frac{44gCO_2}{1molCO_2} =314.3gCO_2\)

C) Glucose C6H12O6

\(C_6H_{12}O_6+6 O_2\rightarrow 6CO_2+6H_2O\)

\(m_{CO_2}=100gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molCO_2}{1molC_6H_{12}O_6} *\frac{44gCO_2}{1molCO_2} =146.7gCO_2\)

D) Methane CH4

\(CH_4+2O_2\rightarrow CO_2+2H_2O\)

\(m_{CO_2}=100gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{6molCO_2}{1molC_6H_{12}} *\frac{44gCO_2}{1molCO_2} =1650gCO_2\)

Therefore, for equal masses D) Methane CH4 yield the greatest mass of carbon dioxide.

Regards.

Answer:

Technology makes space travel possible.

Explanation:

bc the guy above me is wrong I had to guess and I got it right

Answer:

Technology makes space travel possible.

Explanation:

got it right on edge

Answer:

62L

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tysm.

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hope it help

The answer is :

The normal equation for the decomposition of hydrogen peroxide indicates that 2 vol. peroxide vapor should give rise to 2 vol. water vapor and 1 vol. oxygen.

What is hydrogen peroxide ?

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Answer:

boron

Explanation:

boron is a metaloid meaning it has the property of a metal and a non metal located where metals and non metals meet on the periodic table

Answer:

The answer is boron, the second answer is chlorine

Explanation:

edge 2022, have a great day h0mies

The ability of an atom to attract electrons is known as electronegativity.

The electronegativity is the measure of an atom's ability to attract electrons towards itself when it forms a chemical bond with another atom.  The electronegativity of an atom increases from left to right in a period and decreases from top to bottom in a group.

Electronegativity is a chemical property of an atom that describes the atom's ability to attract electrons towards itself when it combines with another atom. The electronegativity of an atom can be defined as its tendency to attract shared electrons in a chemical bond. The electronegativity of an atom is affected by its atomic number, the number of protons it has, and the distance between the nucleus and the electrons. Electronegativity of elements : Electronegativity increases from left to right across a period of the periodic table. This is because the number of protons in the nucleus increases across the period , and the electrons are closer to the nucleus. As a result, the atom has a stronger attractive force for electrons . Electronegativity decreases as we move down a group in the periodic table. This is because the atomic size increases down the group , and the distance between the nucleus and the electrons increases. As a result, the attractive force for electrons decreases.

American scientist Linus Pauling developed a set of dimensionless variables known as electronegativity values that vary from a little under one for alkali metals to a maximum of four for fluorine. In comparison to lower electronegativity values, large electronegativity values show a higher attraction for electrons.

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The molar solubility of calcium hydroxide is approximately 0.010 M.

To calculate the molar solubility of calcium hydroxide, we need to use the solubility product constant (Ksp) for this compound. The Ksp for calcium hydroxide (Ca(OH)_2) is given as 1.3 * 10^{-4}.
The Ksp expression for calcium hydroxide is:
Ksp = [Ca2^{+}][OH^{-}]^{2}
where [Ca2+] and [OH-] are the concentrations of calcium ions and hydroxide ions in the solution, respectively.
Since calcium hydroxide dissolves in water to form Ca2^{+} and OH^{-} ions, the molar solubility of calcium hydroxide (S) can be expressed as:
S = [Ca2^{+}] = [OH^{-} ]
Therefore, we can rewrite the Ksp expression as:
Ksp = S * S^2 = S^3
Rearranging this equation gives:
S = (Ksp)^{(1/3)}
Substituting the given value of Ksp, we get:
S = (1.3 * 10^{-4})^{(1/3)} = 0.010 M (approximately)
Therefore, the molar solubility of calcium hydroxide is approximately 0.010 M.

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The atomic theory describes Dalton's theory because electron, proton and neutron.

The first a part of his theory states that every one matter is product of atoms, which might be indivisible. The second one part of the concept says all atoms of a given element are equal in mass and houses. The  element says compounds are combos of two or extra distinctive forms of atoms.

One of the maximum essential merits of Dalton's atomic idea is the truth that the idea does no longer violate numerous fundamental laws of chemical combination consisting of the regulation of precise proportions, the regulation of multiple proportions, and the regulation of conservation of mass.

In 1803 Dalton located that oxygen mixed with both one or  volumes of nitric oxide in closed vessels over water and this pioneering remark of fundamental more than one proportions supplied vital experimental proof for his incipient atomic thoughts.

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The microscopic interface asymmetry of grown semiconductor heterostructures.

The dispersion of restricted electrons. beginning from a multiband envelope formulation we practice matrix perturbation theory to derive specific expressions. Interface asymmetry, which in the conduction band Hamiltonian appear as a warping and a spin-splitting term. The warping term consequences in an inequivalence of the dispersion.

The microscopic interface asymmetry of grown semiconductor heterostructures that gives upward thrust to heavy-light hole coupling even at 0 in-plane wave vector, modifies also the dispersion of restricted electrons. beginning from a multiband envelope method we practice matrix perturbation principle to derive explicit expressions as a result of this interface asymmetry, which inside the conduction band.

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The square planar complex [Pt(NH3)2Cl2] has two possible stereoisomers, The tetrahedral complex [NiclBral2T] has two possible stereoisomers, The octahedral complex [PtBrACl2h2] has two possible stereoisomers

a) The square planar complex [Pt(NH3)2Cl2] has two possible stereoisomers, which are cis and trans isomers. In the cis isomer, the two NH3 ligands and two Cl ligands are arranged adjacent to each other, while in the trans isomer, the NH3 and Cl ligands are arranged opposite to each other.

b) The tetrahedral complex [NiclBral2T] has two possible stereoisomers, which are the enantiomers. In one enantiomer, the two Br ligands are arranged opposite to each other and the two Cl ligands are arranged adjacent to each other, while in the other enantiomer, the Br and Cl ligands are reversed.

c) The octahedral complex [PtBrACl2h2] has two possible stereoisomers, which are the cis and trans isomers. In the cis isomer, the two axial ligands (Br and Cl) are arranged adjacent to each other, while in the trans isomer, they are arranged opposite to each other. The two equatorial ligands (A and H2) remain the same in both isomers.

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Answer: Copper sulfate is also called blue vitriol, Roman vitriol, Salzburg vitriol, blue copperas or bluestone, which is an inorganic or chemical compound comprised of Copper, Sulphur and Oxygen.  It is an odorless crystalline substance, electric blue and highly toxic, which is produced in industries by treating the copper metal with hot concentrated sulfuric acid or treating its oxides with dilute sulfuric acid. It can be produced by slowly leaching low-grade copper ore in air and bacteria may be used to hasten the process.

We are aware that more charged particles should be present in the most concentrated solutions (for KCl, K+, and Cl-). The increased solute concentration draws the water in via osmosis.

As a result, the water level is lowest on the right side of the U-tube (C and D). However, the left side tube (A, B) has a more concentrated solution as compared to the right side tubes (C, D).

The result is that the tube B solution is the highest concentrated.

Describe osmosis.

Osmosis is the naturally occurring net movement of solvent molecules through a selectively permeable membrane in a direction that tends to balance the solute concentrations on the two sides, from a region of high water potential (region of lower solute concentration) to a region of higher water potential.

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We are aware that more charged particles should be present in the most concentrated solutions (for KCl, K+, and Cl-). The increased solute concentration draws the water in via osmosis.

As a result, the water level is lowest on the right side of the U-tube (C and D). However, the left side tube (A, B) has a more concentrated solution as compared to the right side tubes (C, D).

The result is that the tube B solution is the highest concentrated.

Describe osmosis.

Osmosis is the naturally occurring net movement of solvent molecules through a selectively permeable membrane in a direction that tends to balance the solute concentrations on the two sides, from a region of high water potential (region of lower solute concentration) to a region of higher water potential.

Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together.

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the value of Kb for ClO⁻ at 25 degrees Celsius is 2.5 × 10⁻⁷.

To find the value of Kb for Clo- at 25°C, we need to use the relationship between Ka and Kb for the conjugate acid-base pair.

Ka x Kb = Kw

Where Kw is the ionization constant of water (1.0 x 10^-14 at 25°C).

Note: It's important to specify the unit of temperature in this case. The standard unit for temperature in chemistry is degrees Celsius (°C).
Hi! To find the value of Kb for ClO⁻ at 25 degrees Celsius, given the Ka for HClO is 4.0 × 10⁻⁸ at 25 degrees Celsius, follow these steps:

1. Write down the ion product constant for water (Kw) at 25 degrees Celsius:
Kw = 1.0 × 10⁻¹⁴

2. Use the relationship between Ka, Kb, and Kw:
Ka × Kb = Kw

3. Solve for Kb using the given Ka value:
Kb = Kw / Ka = (1.0 × 10⁻¹⁴) / (4.0 × 10⁻⁸)

4. Calculate Kb:
Kb = 2.5 × 10⁻⁷

So, the value of Kb for ClO⁻ at 25 degrees Celsius is 2.5 × 10⁻⁷.

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Answer: b: C12H22O11

Explanation: have a good day!

Answer:

b.C12H22O11

Explanation:

I love chemistry.

the final pressure would decrease from 2.00 atm to 1.20 atm if the volume were increased from 300.0 mL to 500.0 mL at constant temperature

Specifically, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. This can be expressed mathematically as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

An explanation for why the pressure decreases when the volume is increased is that the gas molecules have more space to move around in the container. This results in a lower pressure. the final pressure would be 1.20 atm. when the volume of the gas sample is increased to 500.0 mL at constant temperature, the final pressure would be 1.20 atm.

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The sign of the enthalpy change involved in the reaction is negative and the sign of work done is also negative.

A reaction takes place in a flexible container initially at 298 K  and volume 3L .then reaction takes place causes decrease in the volume to 2.5L and its temperature becomes 273 K.

    T1 = 298 K

    V1 = 3 L

    V2 = 2.5 L

    T2 = 273 K

The Enthalpy change is the name given to the amount of heat evolved or absorbed in a reaction carried out at constant pressure. It is given the symbol ΔH.

       H = U+PV

sign of enthalpy change involved in the reaction,

Volume decreases --> PV will decrease

T decreases --> change in energy decreases

so the enthalpy change must be negative, since the change or content of energy is getting lower and same in work done.

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E°cell for each reaction, and rank the strengths of the oxidizing and reducing agents:

Complete the given reaction

\($$\mathrm{N}_{2} \mathrm{O}(g)+2 \mathrm{H}^{+}(a q)+2 \mathrm{Au}(s) \longrightarrow \mathrm{N}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{Au}^{+}(a q)$$\)

Write the oxidation reaction

\($$\mathrm{Au}(s) \longrightarrow \mathrm{Au}^{+}(a q)+e^{-}$$\)

\($$E_{a c d}=-1.69 \mathrm{~V}$$\)

Write the reduction reaction

\($$3 \mathrm{~N}_{2} \mathrm{O}(g)+2 \mathrm{H}^{+}(a q)+2 \mathrm{e}^{-} \longrightarrow \mathrm{N}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \quad E_{r e d}=+1.77 \mathrm{~V}$$\)

Calculate the standard cell voltage

\($$E_{c ell}=E_{r e d}+E_{o x d}$$\)

Substitute the value

\($$\begin{aligned}&E_{c e l l}=1.77-1.69 \\&E_{c e l l}=0.08 \mathrm{~V}\end{aligned}$$\)

Hence the standard cell potential is \($0.08 \mathrm{~V}$\)

Oxidizing agent in this reaction is

\($$\mathrm{N}_{2}(g), \mathrm{N}_{2} \mathrm{O}(g)$$\)

Reducing agent in this reaction is

\($$\mathrm{Au}^{+}(a q), \mathrm{Au}(s)$$\)

The potential difference between the two electrodes of an electrochemical cell, which develops when electrons are sent via the external circuit of a cell that has not reached equilibrium, is known as the cell potential.

A chemical process known as an oxidation-reduction (redox) reaction includes the exchange of electrons between two substances. Any chemical reaction in which the oxidation number of a molecule, atom, or ion changes due to the gain or loss of an electron is referred to as an oxidation-reduction reaction.

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Answer:

The combustion of methane or octane is exothermic; it releases energy. CH4 + 2 O2 → CO2 + 2 H2O + energy The energies of the products are lower than the energiies of the reactants

Answer:

C

Explanation:

Answer:C-CaCl2

Explanation:The answer is C because the chemical formula of calcium chloride is CaCl2.

Answer:

substitutions, deletions and insertions

Dipole moment is present between atoms that have differences in their electronegativity. These atoms have unequal distribution of positive and negative charges.  

CO₂, BF₃, CCl₄, and BeF₂ have zero dipole moments because the atoms present in these molecules cancel each other's dipole moments and have overall net zero dipole moments.  

CO₂ is a linear and symmetrical molecule. The molecule has two C=O bonds, which are present in opposite directions. The dipole moment of one C=O bond cancels the dipole moment of the other.  

In BF₃, all three B-F bonds have slightly negative charges on fluorine atoms. The charges are balanced in the symmetrical triangular shape of the molecule. Therefore, the dipole moments of the three bonds cancel each other.  

Similarly, CCl₄ and BeF₂ have overall zero dipole moments because these have regular symmetrical structures.

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The conversion factor that should be used to convert an area from square inches (\(\text in^2\)) to square centimeters (\(\text cm^2\)) is \(\rm (2.54 cm)^2\) / \(\rm (1 in)^2\) .

A conversion factor is a numerical ratio that expresses the relationship between two different units of measurement. It is used to convert a quantity from one unit to another unit.

In this case, conversion factor between inches (in) and centimeters (cm) is 1 in = 2.54 cm, so the conversion factor between square inches and square centimeters is:

\(\rm (1 in)^2 = (2.54 cm)^2\)

Squaring both sides of the equation gives:

\(\rm 1 in^2 = (2.54 cm)^2\)

Therefore, to convert an area from square inches to square centimeters, we can multiply the area in square inches by the conversion factor:

area in \(\rm cm^2\) = area in \(\rm in^2 \times (2.54 cm)^2 / (1 in)^2\)

Simplifying the expression gives:

area in \(\rm cm^2\) = area in\(\rm in^2 \times 6.4516\)

So, to convert an area from square inches to square centimeters, we should multiply the area in square inches by 6.4516.

Therefore, The conversion factor between square inches and square centimeters is\(\rm (2.54 cm)^2\) / \(\rm(1 in)^2\), and to convert an area from square inches to square centimeters, we should multiply the area in square inches by 6.4516.

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Answer:

I believe its oxygen gas  

Explanation: The density of a gas is 1.43 g/L

Answer:

\(\huge\boxed{\sf 160\ g}\)

Explanation:

Here,

Half life = 3

Sample Amount left = 20 g

Before 3rd half-life:

= 20 × 2

= 40 g

Before 2nd half-life:

= 40 × 2

= 80 g

Before 1st half-life:

= 80 × 2

So, the initial amount of sample was 160 grams.

\(\rule[225]{225}{2}\)

Yes, the chemist can identify the substance in the sample.

When describing a compound's mass per mole, the term "molar mass" is employed. The molar mass is determined by multiplying the individual masses of all the atoms that make up a compound.

K₂O has a molar mass of 94.2 g/mol.

has a molar mass of 110.196 g/mol.

By multiplying the masses of each individual atom—one K atom weighs 39.0983 g/mol, whereas one O atom weighs 15.999 g/mol—the molar masses are obtained.

When the mass of a pure compound is known, the mass of oxygen (O) can be calculated by subtracting the mass of potassium (K) from the total mass. Since each of the mentioned compounds contain two K atoms, the difference in oxygen mass can be utilised to identify the pure chemical.

For instance, after deducting the mass of the K from the unknown molecule, the residual mass will be approximately 16 g if the compound is K₂O and approximately 32 g if the compound is K2O2.

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The complete question is

The compound K2O2 exists. A chemist can determine the mass of K in a sample of known mass that consists of either pure K₂O or pure K2O2. From this information, can the chemist answer the question of which compound is in the sample? Explain

Answer:

B Meiosis produces gametes

Explanation:

Hope this helps

Answer:

The 1990 amendments addressed the growing problem of urban smog by acid rain.

Explanation:

As shown in the above question, the Clean Air Act was created with the goal of making the US air healthier, while also aiming to reduce the impacts of pollution on the American population. This law had as its main objective to reduce the emission of gases capable of polluting the atmosphere, especially those resulting from the burning of gasoline in cars. In 1990, a new amendment was added to this law. This amendment aimed to reduce emissions of sulfur dioxide and nitrogen oxides, as they were the main cause of acid pollution, which was responsible for acid rain that is extremely dangerous and negative for society.

Explanation:

So if V œ T, then V = kT ; if we solve for k under different conditions of volume and temperature......

\( \frac{v1}{t1} = \frac{v2}{t2} \)

temperature is measured in degrees Kelvin.

And

\( v2 = \frac{v1}{t1} \times t2 = \frac{275 . ml}{298 \: . \: k } \times 403 \: . \: k = ?\)

?mL

0.403 L is the new volume where the initial volume is 275 mL and the initial temperature is 273 K.

Gas laws relate to the pressure, volume, and temperature of a gas. Boyle's law—named for Robert Boyle—states that, at constant temperature, the pressure P of a gas varies inversely with its volume V, or PV = k, where k is a constant.

The relationship between volume and temperature is: \(\frac{V_1}{T_1} =\frac{V_2}{T_2}\) where \(V_1\)and \(T_1\) are the initial volumes and \(V_2\) and \(T_2\) are the final volumes.

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

Given data:

\(V_1 =\) 275 mL, \(T_1 =\) 0

\(V_2 =\) 275 mL, \(T_2 =\) 130

Putting all the values in the equation:

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

\(\frac{0.275}{273} =\frac{V_2}{403}\)

\(V_2 =\) 0.403 L

Hence, 0.403 L is the new volume.

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