What element has the noble gas configuration [Ar]4s23d8

Therefore, the number of water molecules in the given sample is approximately \(8.18 * 10^2^3\) molecules.

To calculate the number of water molecules in the given sample, we need to use the concept of Avogadro's number and the molecular weight of water.

The molecular weight of water (H2O) is:

H = 1.008 u (atomic mass units)

O = 15.999 u (atomic mass units)

Molecular weight of H2O = (2 x 1.008 u) + 15.999 u = 18.015 u

Using the molecular weight of water, we can calculate the number of moles of water in the sample:

Number of moles = mass / molecular weight

Number of moles = 24.50 g / 18.015 g/mol

Number of moles = 1.359 mol

Now, using Avogadro's number (\(6.022 *10^2^3\) molecules/mol), we can calculate the number of water molecules in the sample:

Number of water molecules = Number of moles x Avogadro's number

Number of water molecules = \(1.359 mol * 6.022 *10^2^3\) molecules/mol

Number of water molecules =\(8.18 * 10^2^3\)molecules

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Answer:

Number of moles = 2.72 mol

Explanation:

Given data:

Number of moles of H₃PO₄ present = ?

Molarity of solution = 18.1 M

Volume of solution = 150.0 mL (150/1000 = 0.15 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

By putting values,

18.1 M = number of moles / 0.15 L

Number of miles = 18.1 M × 0.15 L

Number of moles = 2.72 mol

Answer:

Metals tend to be hard, metallic-looking solids, with high electrical and thermal conductivity values and high melting and boiling points. Nonmetals tend to be softer, often colorful elements. They may be solids, liquids, or gases.

Answer: Metals are hard and have high melting and high boiling points and high electrical and thermal conductivity values and nonmetals are softer and are substances like solids,liquids,or gases.

Moisture is the water present in the soil that is trapped in the particles. The moisture content of the soil with an initial weight of 8.6 gm and dry weight of 7.0 gm will be 0.228.

The moisture content is the estimation of the weight by the subtraction of the dry soil mass from the moist soil mass followed by dividing the value by the weight of the dry soil.

Given,

Weight of moist soil = 8.6 gm

Weight of dry soil = 7.0 gm

Substituting values,

(8.6 - 7.0) ÷ 7.0

= 0.228

Therefore, 0.228 is the moisture content of the soil.

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Answer:

Divide the distance the object traveled by the time it took to get there.

Explanation:

To calculate the speed on an object, start by determining how far the object has traveled. Next, figure out the amount of time that the object took to cover that distance. Finally, divide the distance the object traveled by the time it took to get there. Don't forget to label the speed with the correct units of measurement.

The equilibrium constant for the given reaction at the given temperature is 0.478.

To calculate Kp for the given reaction, we first need to write the balanced equation and the expression for Kp:
F2(g) + Br2(g) <=> 2BrF(g)
Kp = (PBrF)^2 / (PF2 x PBr2)
Here, PBrF, PF2, and PBr2 are the partial pressures of BrF, F2, and Br2, respectively, at equilibrium. We are given the initial partial pressures of F2 and Br2, as well as the equilibrium pressure of BrF.
To determine the equilibrium partial pressures of F2 and Br2, we can use the stoichiometry of the reaction and the ideal gas law.
Let x be the equilibrium concentration of BrF. Then, the equilibrium concentrations of F2 and Br2 will be (5.42 - x) and (3.87 - x), respectively.
Using the ideal gas law, we can write:
PF2 = (5.42 - x) * (RT/V) and PBr2 = (3.87 - x) * (RT/V)
where R is the gas constant, T is the temperature in kelvin, and V is the volume.
At equilibrium, the total pressure is given by:
Ptotal = PF2 + PBr2 + PBrF = 5.42 + 3.87 + 1.42 = 10.71 atm
Substituting the partial pressures into the expression for Kp, we get:
Kp = (1.42)^2 / [(5.42 - x) * (3.87 - x)]
Simplifying and solving for x, we get:
x = 1.92 atm
Substituting x back into the expressions for PF2 and PBr2, we get:
PF2 = 3.50 atm and PBr2 = 1.95 atm
Finally, substituting all the partial pressures into the expression for Kp, we get:
Kp = (1.42)^2 / (3.50 x 1.95) = 0.478
Therefore, the equilibrium constant for the given reaction at the given temperature is 0.478 (to 3 decimal places).

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Answer:

I think that a  pure substance is a form of matter that has a constant composition and properties that are constant throughout the sample. Mixtures are physical combinations of two or more elements and/or compounds.

Explanation:

The correct set of coefficients, in order, to balance the equation is: 3, 9, 3, 6. Therefore, option (A) is correct.

To balance the chemical equation \(Al_{2}O_{3}\)+ Fe → \(Fe_{3}O_{4}\) + Al, we need to determine the coefficients that ensure the same number of atoms for each element on both sides of the equation.

In the given answer, A. 3, 9, 3, 6, the coefficients indicate that three molecules of aluminum oxide (\(Al_{2}O_{3}\)) and nine atoms of iron (Fe) react to form three molecules of iron(III) oxide (\(Fe_{3}O_{4}\)) and six atoms of aluminum (Al).

By balancing the equation with these coefficients, we ensure that the number of atoms of each element is conserved. This means that no atoms are gained or lost during the reaction, satisfying the principle of conservation of mass.

Balancing equations is crucial for accurately representing chemical reactions, as it ensures that the reactants and products are in the correct stoichiometric ratios and reflects the conservation of atoms.

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I hope that the attachment helps you..

Answer:

the volume of a give gas simple is directly propotional assolute temperature at constant pressure .the volume of a gavi. amount of gass is inversely propotional ot Its pressure when temperature is help constant

The Molarity of hydrochloric acid is 5.708 M  containing mass of 19.0% and the density of the solution is 1.095 g/ml .

Molarity of the solution is defined as the amount of solute in moles divided by the volume of solution in liters.

               M = moles of solute/liters of solution.

we can calculate the molarity by dividing the number of moles of solute by the total volume of liters of solution.

let's assume 100g solution. the mass percentage of hydrochloric acid within the solution is 19.0%. and the density of the solution that is give is 1.095g/mole. substituting all these values we can calculate the molarity of the solution.

mass Hydrochloric acid,

100g solution x (19.00g / 100g solution) = 19.00g Hcl

moles of hydrochloric acid is ,

19.00g HCl x (1 mole Hcl / 36.45g HCl) = 0.52126

then the solution is,

100g solution x (1mL solution / 1.095g solution) x (1L / 1000mL) = 0.091324L

molarity HCl = 0.52126 mole / 0.091324L = 5.708M.

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Answer: Earthquake location

Explanation:

Answer:

Volcano chains and arcs, and earthquake locations

Answer:

1

Explanation:

Answer:

1. Metal.

2. Atom.

3. Homogeneous

4. Compounds.

5. Lustrous

6. Saturated.

7. Colloidal; true.

8. Homogeneous.

Explanation:

1. An element which are sonorous are called metal.

2. An element is made up of only one kind of atom.

3. Alloys are homogeneous mixtures.

4. Elements chemically combines in fixed proportion to form compounds.

5. Metals are lustrous and can be polished.

6. A solution in which no more solute can be dissolved is called a saturated solution.

7. Milk is a colloidal solution but vinegar is a true solution.

8. A solution is a homogeneous mixture.

According to the question a product of this reactio is \(CH_3CH_2-OH\) , which is an alcohol.

Alcohol is a psychoactive substance that is produced by the fermentation of yeast, sugars, and starches. It can be found in many forms, including beer, wine, and distilled spirits, and is widely consumed around the world. Alcohol has been consumed in some form since ancient times and is commonly used to celebrate special occasions and mark important life events. Consumption of alcohol can be both beneficial and detrimental to health, depending on the amount consumed and the individual's sensitivity. It can have short-term effects on the body such as impaired motor skills and judgement, and long-term effects such as liver damage and increased risk of certain cancers.

This is because the reaction involves the reaction of an alkyl halide (\(CH_3CH_2Br\)) with a magnesium halide (MgBr) to form an alkoxide \((CH_3CH_2-O-MgBr)\). When acid is added, the alkoxide is protonated and the magnesium halide is eliminated, forming an alcohol \((CH_3CH_2-OH)\).

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Supersaturated solutions are any liquids that contain more solute than is necessary to generate a saturated solution at any given constant temperature. Q > Ksp for a supersaturated solution. The correct option is D.

The ionic product results from ionic species concentrations in either an unsaturated or a saturated solution. The ionic product is referred to as the solubility product when only saturated solutions are taken into account. All forms of solutions can be referred to as ionic products.

The product of the ion concentration that is in equilibrium with the solid substance in a saturated solution is known as the solubility product. Q > Ksp, the solution is supersaturated, and an ionic solid will precipitate.

The correct option is D.

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Answer:

Explanation:

Moles of Pb(NO3)2 =  mass/molecular mass

= 50.0 grams/(207.20*1 + 14.01*2 + 16*6)

= 50.0 grams/331.22

= 0.15 moles

Moles of NaI

= 30/(22.99+126.9)

= 30/149.89

= 0.2 Moles

A. NaI is less 2x Pb(NO3)2 so NaI is the limiting reagent.

B. The ratio is 1 to 2 so there is 0.15 - 0.2/2 = 0.05 mole

or 16.78 grams of Pb(NO3)2 left.

C. As NaI is limiting, only 0.2 Moles of NaNO3 is formed.

Mass =  Moles * Molecular Mass

Molecular Mass of NaNO3 can be calculated as:  

Na - 22.99

N - 14.01

O - 3(16) = 48

23+14+48 = 85gram / mole

Thus, Mass =  0.2*85  = 17 gram of NaNO3

Mass is conserved in a chemical reaction.

Mass of PbI2 can be calculated as:

50+30-16.78-17

= 46.3 gram of PbI2

Mass =  

12.75

Thus, 12.75g of Sodium Nitrate can be formed

Answer:

Explanation:

Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)

MM for each compound -

Pb(NO3): 207 + 14x2 + 16x3x2 = 331

PI2: 207 + 127x2 = 461

NaI: 23 + 127 = 150

NaNO3: 23 + 14 + 16x3 = 85

Moles of Pb(NO3)2 = 50/331 = 0.15

Moles of NaI = 30/150 = 0.2

Ratio of moles is 1:2

So NaI is limiting

Limited to 0.2/2 = 0.1 mole of Pb(NO3)2

Excess = 0.15 - 0.1 = 0.05 mole

Mass remains = 0.05x331 = 16.55 grams

Moles of NaNO3 formed = Moles of NaI reacted = 0.2

Mass = 0.2x85 = 17 grams

Moles of PbI2 formed = Moles of Pb(NO3)2 reacted = 0.1

Mass = 0.1x461 = 46.1 grams

If 12 grams of NaNO3 actually formed in the reaction,

percent yield = 12/17x100% = 70.6%

Approximately 0.156 grams of copper is deposited on the cathode of the electrolytic cell.

To calculate the mass of copper deposited on the cathode of an electrolytic cell, we can use Faraday's laws of electrolysis and the equation:

The equation is:

M = (Q * Mw) / (n * F)

Where:

M is the mass of the substance deposited (in grams),

Q is the total electric charge passed through the cell (in coulombs),

Mw is the molar mass of the substance (in grams per mole),

n is the number of moles of electrons transferred in the reaction, and

F is the Faraday constant (approximately 96,485 C/mol).

In this case, copper is being deposited on the cathode, and the balanced chemical equation for the electrolysis of CuSO₄ is:

Cu²+ + 2e⁻ → Cu

The number of moles of electrons transferred (n) in this reaction is 2, as indicated by the balanced equation.

Given:

Current (I) = 2.00 A

Time (t) = 20.0 minutes = 20.0 * 60 seconds

= 1200 seconds

First, we need to calculate the total electric charge (Q) passed through the cell using the formula:

Q = I * t

Q = 2.00 A * 1200 s

Now, we can substitute the values into Faraday's law to calculate the mass of copper deposited:

M = (Q * Mw) / (n * F)

Substituting the known values:

M = [(2.00 A * 1200 s) * (63.55 g/mol)] / (2 * 96,485 C/mol)

Simplifying the expression:

M ≈ 0.156 g

Therefore, approximately 0.156 grams of copper is deposited on the cathode of the electrolytic cell.

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The mass of copper deposited on the cathode of the electrolytic cell is 0.787 grams. This is calculated using Faraday's law of electrolysis with the given current of 2.00 A and time of 20.0 minutes, which results in a charge of 2400 C and 0.0124 moles of copper being deposited.

To determine the mass of copper deposited on the cathode of an electrolytic cell, we need to use Faraday's law of electrolysis. According to this law, the amount of substance deposited is directly proportional to the amount of electricity passed through the cell.
First, let's convert the current to coulombs. Since the current is given as 2.00 A (amperes) and the time is 20.0 minutes, we need to convert the time to seconds. There are 60 seconds in a minute, so 20.0 minutes is equal to 20.0 × 60 = 1200 seconds.
The charge (Q) is calculated by multiplying the current (I) by the time (t): Q = I × t. Therefore, Q = 2.00 A × 1200 s = 2400 C.
Now, we need to determine the number of moles of electrons transferred. Each mole of electrons corresponds to 1 Faraday (F), which is equal to 96,485 C. Therefore, the number of moles of electrons transferred is 2400 C / 96,485 C/mol = 0.0249 mol.
Since the reaction is the reduction of Cu2+ ions to copper metal (Cu2+ + 2e- → Cu), the stoichiometry tells us that 2 moles of electrons are required to deposit 1 mole of copper.
Hence, the number of moles of copper deposited is 0.0249 mol / 2 = 0.0124 mol.
Finally, we need to calculate the mass of copper deposited. The molar mass of copper (Cu) is 63.55 g/mol. Thus, the mass (m) of copper deposited is 0.0124 mol × 63.55 g/mol = 0.787 g.
Therefore, the mass of copper deposited on the cathode is 0.787 grams.

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Answer:

78

Explanation:

Answer:

The OH would be .7825 and the basic solution is a strong base.

Explanation:

What you would do is -log(0.165) in your calculator which would give you 0.7825160065 as an answer. Im not sure what the significant figure is so I will not be rounding to that, but that is your answer for the first part.

The second part: because your pOH is a .7825, this would be consiered a strong base in the pOH because it is closer to 1 which is your base.

To determine the temperature at which an exothermic reaction ceases to be spontaneous, we need to calculate the Gibbs free energy change (ΔG) and use the equation ΔG = ΔH - TΔS.

Given that ΔH = -71 kJ/mol and ΔS = -58 J/K·mol, we can calculate ΔG at different temperatures to determine the temperature at which the reaction becomes non-spontaneous.

At a temperature of 0 K, ΔG = ΔH, since TΔS = 0. Thus, ΔG = -71 kJ/mol.

As the temperature increases, TΔS becomes more negative, which means that ΔG becomes more negative, making the reaction more spontaneous.

At a certain temperature, however, ΔG will become positive, which means that the reaction is no longer spontaneous and will not proceed on its own. This temperature can be found by rearranging the equation ΔG = ΔH - TΔS to T = ΔH / ΔS, and substituting the known values for ΔH and ΔS:

T = ΔH / ΔS = -71 kJ/mol / (-58 J/K·mol) = 1230 K

So, the reaction will cease to be spontaneous at a temperature of approximately 1230 K.

The correct formula of the molecule is C4H9O2.

The model of a compound is a representation of the molecule. It gives us an idea of what the molecule looks like as well as its molecular formula.

Looking at the structure of the compound as shown in the model in the question, the correct formula of the molecule is C4H9O2.

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Answer:C4H9O2.

Explanation:

Answer:

Explanation:

Hope it helps:)

"A nucleus for whom the chemical shift must have been reduced due to the addition of electron density, magnetic induction, or even other effects," according to the definition.

As electrons orbit the nucleus, they significantly change the magnetic field that even the nucleus experiences, which modifies the difference among energy levels, culminating in the spectrum. However, these adjustments are based on a specific reference as well as hence are relative.

Electron shielding is the nucleus's inhibition of valence shell electron attraction due to the existence of inner-shell electrons. Due to the spherical form of the s orbital, electrons inside an s orbital can shelter p electrons with the same energy level.

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Answer:

\(M.M=150.8g/mol\)

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly possible for us to set up the equation for the freezing point depression as shown below:

\(\Delta T=-i*m*Kf\)

Thus, given Kf, i (equal to 1 because it is nonelectrolyte) and the freezing point depression, we can now calculate the molality of the solution:

\(m=\frac{\Delta T}{-i*Kf}=\frac{-0.84\°C}{-1*4.9\°C/m}\\\\m=0.17mol/kg\)

Next, we calculate the kilograms of solvent by dividing the 200 g by 1000 to get 0.200 kg and thus calculate the moles of the solute X:

\(n_X=0.200kg*0.171mol/kg\\\\n_X=0.0343mol\)

Finally, the molar mass by dividing the grams by moles:

\(M.M=\frac{5.17g}{0.0343mol}\\\\M.M=150.8g/mol\)

Regards!

Answer:

I think it's C. 6.022 * 1023

Radioisotopes are widely used in medicine for various purposes such as diagnosis, treatment, and palliative care. Three commonly used radioisotopes in medicine are iodine-131 (I-131), technetium-99m (Tc-99m), and cobalt-60 (Co-60).

The isotope symbol for iodine-131 is ^131I, for technetium-99m is ^99mTc, and for cobalt-60 is ^60Co. I-131 is used to diagnose and treat thyroid cancer, while Tc-99m is used in various imaging tests such as bone scans and cardiac stress tests. Co-60 is used in radiation therapy to treat cancer. The use of radioisotopes in medicine has significantly improved patient outcomes and helped in the diagnosis and treatment of various diseases.
Hospitals utilize radioisotopes for various medical purposes, such as diagnosis, treatment, and palliative care. Three commonly used radioisotopes in medicine are:

1. Technetium-99m: This radioisotope is widely used for diagnostic imaging. Its isotope symbol is 99mTc, where 99 represents the mass number (protons + neutrons) and Tc is the element symbol for Technetium.

2. Iodine-131: Iodine-131 is employed in the treatment of thyroid disorders. The isotope symbol for Iodine-131 is 131I, where 131 is the mass number and I represents the element symbol for Iodine.

3. Cobalt-60: Cobalt-60 is used in cancer therapy, specifically for external beam radiotherapy. Its isotope symbol is 60Co, where 60 denotes the mass number and Co stands for the element symbol of Cobalt.

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Answer:

the material has two different color crystals

Explanation:

There are two types of mixture, one is homogeneous mixture and other is heterogeneous mixture. Therefore, If the material has two different color crystals, then we can see  whether material is a pure substance or a mixture.

When two or more compounds are combined but each ingredient retains its chemical identity, the result is referred to as a mixture. In other words, there is no chemical interaction between the parts of a combination.

According to how consistent they are and how well the components' particle sizes match up, mixtures are categorized. If the material has two different color crystals, then we can see  whether material is a pure substance or a mixture.

Therefore, if the material has two different color crystals, then we can see  whether material is a pure substance or a mixture.

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Answer:

electrical energy

When the flashlight is turned on, the chemical energy is first transformed into electrical energy and then into light energy. CHEMICAL bonds. It is released during a chemical reaction (change). by flowing electrons (negatively charged particles).

Answer:

Electrical Energy

Explanation:

When the flashlight is turned on, the chemical energy is first transformed into electrical energy and then into light energy. CHEMICAL bonds. It is released during a chemical reaction (change). by flowing electrons (negatively charged particles).

When the preexisting molecular links are broken and new bonds are created between oxygen and hydrogen atoms, hydrogen molecules react strongly with oxygen molecules.

The outcome is an explosive release of energy and the formation of water since the reaction's products are at a lower energy level than its reactants.

The most well-known instance of a synthesis reaction is the burning of hydrogen and oxygen to produce water.

Most of the water that was created was in the form of vapors, which mixed with cosmic dust on the way to the earth's surface. These water vapors condensed into oceans, seas, rivers, and lakes when the world first came into existence.

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