Assuming the third quantum number is the question is the magnetic quantum number, it is limited by the angular momentum quantum number. This is inditaced in the quastion: since the orbital is 4p, the "p" indicates that the angular momentum quantum number is 1.
The magnetic quantum number can only be -1, 0 or +1.
The only alternative with one os these is alternative A.
What are the coefficients for the reaction _Cl₂O5 + H₂O → HCIO3 once it is balanced?
O 1, 1, 1
O 1, 1, 2
O
O 2, 1, 1
1, 2, 2.
Given the following data. (i) Ca(s) + 2C(grafite) -> Cacis) X Ca(s) + ⅐0›(g) -> Cao(s) (iit) CaO(s) + H›O(I) -> Ca(OH)(ag) (iv) CHi(g) + 5/20,(8) -> 2C0,(g) + H,0(1) X* (v) C(grafite) + 02(g) -> CO›(g) [4 marks] AH = -62.8 kJ AH = -635.5 kJ AH = -653.1 kJ AH= -1300.0 kJ AH = -393.5 kJ / Calculate AH for the following reaction by using Hess's law and manipulating the given reactions: CaC(s) + H,O(I) - Ca(OH),(ag) + GHa(g) AH = ?
The enthalpy change (ΔH) for the reaction CaC(s) + H2O(I) → Ca(OH)(ag) + CH4(g) is -3617.6 kJ.
To calculate ΔH for the reaction CaC(s) + H2O(l) → Ca(OH)2(ag) + CH4(g), we can use Hess's law, which states that the enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states.
We can manipulate the given reactions to obtain the desired reaction:
(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X (unknown value)
(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ
(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ
(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ
(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ
Now, let's manipulate these equations to cancel out the common reactants and products and obtain the desired reaction:
(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X
(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ
(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ
(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ
(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ
Now, let's sum up the equations to obtain the desired reaction:(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X
(ii) 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1271 kJ
(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ
(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ
(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ
By adding equations (ii), (iii), (iv), and (v), we can cancel out CaO(s), H2O(l), and O2(g):
2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -1271 -653.1 -1300.0 -393.5
2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -3617.6 kJ
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How are the atmospheres on Jupiter and Saturn different than those on Uranus and Neptune?
Answer:
The atmospheres of Jupiter and Saturn are made almost entirely of hydrogen and helium, although there is some evidence they contain hydrogen compounds. The there is Uranus and Neptune that are made primarily of hydrogen compounds, with smaller traces of hydrogen, helium, metal and rock.
Explanation:
Hope this helps.
How many moles are there in 88.5 grams of water?
Answer:
\(4.92\text{ moles}\)Explanation:
Here, we want to get the number of moles in the given mass of water
To get this, we have to divide the mass given by the molar mass of water
Mathematically:
\(Number\text{ of moles = }\frac{mass}{molar\text{ mass}}\)The molar mass of water is 18 g/mol
Thus, we have the number of moles as:
\(Number\text{ of moles = }\frac{88.5}{18}\text{ = 4.92 moles}\)determine the electron geometry (eg) and molecular geometry (mg) of the carbon in hcn. (the carbon is in the middle. the h is bonded to the c and the n is bonded to the c.)
The electron geometry of HCN is linear geometry and molecular geometry of the carbon in HCN is linear geometry.
The lewis structure is as follows :
H - C ≡ N :
The number of the the valence electrons = 10 electrons
The carbon is the central atom. The HCN is the AX2 type of the molecule. The A is the central atom. X is the central atom. This type of the molecule has the linear electron geometry. There is no lone in the central atom, therefore the molecular geometry of the HCN is linear geometry.
Thus the both electron and the molecular geometry is linear.
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Explain why the element of an atom doesn't change if you remove or add electrons or neutrons
Answer:
If you could miraculously remove two neutrons from an atom's nucleus, the atomic number and electrical charge would stay unaltered. Because neutrons have no electrical charge, adding or removing them from the nucleus has no effect on the nucleus's electrical charge. It does, however, alter the nucleus's mass. Isotopes are formed by adding or subtracting neutrons from the nucleus.
A rock has a mass of 35 g. You place the rock inside a graduated
cylinder that has 50 mL of water. The cylinder now reads 55 mL.
What is the density of the rock?
The correct IUPAC name for the structure shown is
A)
ethylmethylamine.
B)
methylamine.
C)
ethylamine.
D)
ethylmethylhydridoamine.
Answer:
A
Explanation:
it has a methyl group, ethyl group and amine group
The correct IUPAC name for the structure shown in the provided image is "ethylamine." The structure consists of a central nitrogen atom bonded to two carbon atoms.
The correct IUPAC name for the structure shown in the provided image is "ethylamine." The structure consists of a central nitrogen atom bonded to two carbon atoms. According to the IUPAC naming rules, the longest carbon chain is selected as the parent chain, which in this case consists of two carbon atoms. The substituent attached to the parent chain is an ethyl group, denoted as "C2H5". The amine functional group, which consists of the nitrogen atom, is named as "amine". Since there is only one amine group attached to the carbon chain, it is referred to as "ethylamine." Therefore, option C) "ethylamine" is the correct IUPAC name for the given structure.
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what is visibility ?
Answer:
Something or someone you can see invisibility is the opposite of something you cannot see or some thing you cannot see
Explanation:
Is plastic pollution likely to become more or less of a problem in the future?
Answer:
More bro
Explanation:
Pollution is only increasing
Answer: Yes and no, no because people are constantly polluting the earth with plastic which is a big issue. Yes, because things are being invented to help with plastic pollution, and there is a great number of people who recycle, so however you look at it there's really a 50/50 chance.
Explanation:
Calculate the how many sodium atoms must react completely to give 33,6 dm³ hydro-
gen gas at STP.
2Na+ 2H₂O → 2NaOH + H₂(g)
To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.
What is Mole concept ?A mole is a unit of measurement used to measure the amount of any fundamental entity (atoms, molecules, ions) present in the substance.
As according to the given equation, 2 moles (ie 12.04 x 10²³ atoms) of Na-atoms produces 1 mole (22.4 ltr) of H₂-gas.
Hence, to produce 33.6 ltr (equivalent to 33.6 dm³) of H₂-gas produced by ;
= 12.04 x 10²³ atoms of Na / 22.4 ltr of H₂-gas x 33.6 ltr
= 18.06 x 10²³ atoms of Na
Hence, To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.
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What does cellular respiration do?
Break down sugar and release energy for an
organism to use
Create sugar filled with energy
Deter predators
Form glucose from hydrogen, oxygen, and carbon
:D
help asap
How could you tell if a substance has undergone a physical change or a chemical one?
Answer: Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances. These processes are called chemical reactions and, in general, are not reversible except by further chemical reactions.
A physical change is are changes affecting the form of a chemical substance, but not its chemical composition. Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds.
9. Compound A, with molecular formula C5H₁2 has only 1° and 4° carbons. What is its structure? Its other isomer has only 1°, 2° and 3° carbons. What is its structure also?
draw the structure
Answer:
Ok giv me a min
Explanation:
How many equivalent resonance structures can be drawn for the molecule of SO3 without having to violate the octet rule on the sulfur atom
Answer:
3
Explanation:
Resonance is a valence bond concept put forward by Linus Pauling to explain the fact that the observed properties of a molecule may be as a result of the fact that its actual structure lie somewhere between a given number of structural extremes called canonical structures or resonance structures.
There are three resonance structures for SO3 that obey the octet rule. All the S-O bonds in SO3 are equivalent in these resonance structures.
Seven equivalent resonance structures for the molecular of SO3 can be drawn without breaking the octet rule.
We can arrive at this answer because:
The octet rule is a rule that states that an atom must reach stability when it has eight electrons in the valence layer.This means that in bonds that cause the donation or sharing of electrons between atoms, each atom has eight electrons in the valence layer.In chemistry, resonance is a term that refers to structures created to represent the donation or sharing of electrons between the atoms of a molecule.These structures can be arranged in different ways, as long as they respect the octet rule.In an SO3 molecule, electrons are shared between atoms. This sharing can be done with seven resonance structures.
These structures are shown in the figure below.
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Given the reaction: Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
The reaction occurs more rapidly when a 10-gram sample of Mg is powdered rather than in one piece, because powdered
Mg has
1. less surface area
2. more surface area
3. a lower potential energy
4. a higher potential energy
(2) The student adds some dilute nitric acid to a burette and does the titration. The equation for the reaction is Ba(OH)₂ + 2HNO, → Ba(NO₂)₂ + 2H₂O The student finds that 21.50 cm' of nitric acid of concentration 0.600 mol/dm³ neutralises 25.0 cm³ of barium hydroxide solution. Calculate the concentration, in mol/dm³, of the barium hydroxide solution.
Answer:
0.0964, I worked out the moles of barium hydroxide and divided this by two and then divided that by the volume of nitric acid
Explanation:
Answer:
0.258 mol/dm3
Explanation:
Ba(OH)2 + 2HNO3 ---------> Ba(NO2)2 +2H2O
1 : 2 : 1 : 2
0.00645 : 0.0129 : 0.00645 : 0.0129
Moles of Nitric Acid
Moles=Concentration X Volume(dm3)
0.600 X 0.0215
=0.0129 mol
Concentration= Moles/ Volume(dm3)
0.00645/0.025
= 0.258 mol/dm3
ASAP ILL GIVE BRAINLIEST ! IF YOU CAN ANSWER AT LEAST ONE TY
Answer:
Project shadow #KARMA be there
Explanation:
30 example of redox reaction
Arrange the following atoms according to decreasing effective nuclear charge experienced by their valence electrons: Cl, Na, P, and S. Rank from largest to smallest. To rank items as equivalent, overlap them.
Cl Na P S
Largest Smallest
Answer:
Cl < S < P < Na
Explanation:
We have to understand the trend for effective nuclear charge before answering the question;
The periodic table tendency for effective nuclear charge: Increase across a period (due to increasing nuclear charge with no accompanying increase in shielding effect). Decrease down a group (although nuclear charge increases down a group, shielding effect more than counters its effect).
Based on this, the elements can be arranged in the following order;
In decreasing order;
Cl < S < P < Na
What is plotted on the Y axis
Speed
Distance or time
Which climate contains the largest biodiversity on Earth?
A.
Hot Desert
B.
Tropical Rainforest
C.
Humid Subtropical
D.
Warm Summer Mediterranean
what are thetypes of luminous flame
Types of luminous flames:
1. Yellow Luminous Flame
2. Smoky Luminous Flame
3. Orange Luminous Flame
4. Blue Luminous Flame
Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:
1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.
2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.
3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.
4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.
It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.
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What is the mole fraction of a acetyl bromide
Answer:
Mole fraction(CHCl3) = 0.681
Mole fraction (CH3COBr) = 0.319
Explanation:
Molar mass(CHCl3) = 12+ 1 + 3*35.5 = 119.5 g/mol
Molar mass(CH3COBr) = 2*12 + 3*1 + 16 + 80 = 123 g/mol
112. g* 1mol/119.5g = 0.9372 mol CHCl3
54. g * 1 mol/123g = 0.4390 mol CH3COBr
Mole fraction(CHCl3) = 0.9372/(0.9372+0.4390) = 0.681
Mole fraction (CH3COBr) = 0.4390/(0.9372+0.4390) = 0.319
0.681+0.319 =1.000 true
A solution was prepared by dissolving 200.0 g of KCI in 215 g of water.
Calculate the mole fraction of KCL. (The formula weight of KCl is 74.6 g/mol. The formula weight of water is 18.0 g/mol)
Express the mole fraction of KCl to two decimal places.
Answer:mole fraction of KCl = 0.18
Explanation:
no of moles of KCl = Mass/Molar mass
where mass (weight) of KCl = 200.0g
molar mass of KC1= 74.6g/mol
= 200/74.6 = 2.68 moles
no of moles of H2O = Mass/Molar mass
where mass (weight) of water = 215.0g
molar mass of water = 18.0g/mol
= 215/18 = 11.94moles
mole fraction of KCl = no of moles of KCl/(no of moles KCl + no of moles of H2O(water))
= 2.68/(2.68+ 11.94)
= 2.68/14.62 = 0.18
Express using two significant figures 2.5ft
Answer: 2.5 feet is already in 2 sig figs, in inches it would be 30. (30 including the deciaml) and in cm it would be 76
Explanation:
20 POINTS) Which atom in each pair has the larger ionization energy?
A) Na or S
B) V or K
C) Ne or F
D) Ca or Ba
The larger ionization energy of atoms in each pair is S, V, Ne, and Ca.
What is the ionization energy?The ionization energy can be defined as the minimum amount of energy that an electron has to absorb to knock out itself from the influence of the nucleus of a gaseous atom or ion.
It provides the reactivity of chemical compounds and evaluates the strength of chemical bonds. The measurement units of ionization energy are electronvolts (eV) or KJ/mol.
Ionization energy measures the difficulty in removing an electron from an atom or ion and the loss of electron occurs in the ground state of the chemical species.
As we move in a period, the electronegativity and effective nuclear charge of the elements increase therefore, ionization energy increases. Therefore, S has larger ionization energy than Na and V has larger ionization energy than K. Ne is a noble gas so it will have larger ionization energy than F.
The electron can easily be removed from the atom as we move down the group. Therefore, calcium present at the top of the group has a larger ionization energy than Barium (Ba).
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How does shaking or stirring a mixture of solute and solvent affect a solution?
CA. It increases the solubility of the solute.
CB. It increases the rate of dissolving.
C C. It decreases the solubility of the solute.
D. it decreases the rate of dissolving.
For the reaction: PCl5(g) ⇌ PCl3(g) + Cl2(g) at 600.0 K, the equilibrium constant is 11.5. Suppose that 1.500 g of PCl5 (MW=208.22 g/mol) is placed in an evacuated 500.0 mL bulb, which is then heated to 600.0 K. What is the total pressure (in atm) in the bulb at equilibrium?
Answer:
1.418688 atm
Explanation:
(a) Moles of PCl5 = mass / molar mass
=1.5 g / 208.22 g/mol
= 0.0072 moles
Also given,
T = 600 K
V = 0.500 L
Pressure of PCl5, P = nRT / V
= 0.0072 mol×0.0821 L-atm / (mol.K)×600 K / 0.500 L
= 0.709344 atm
(b) PCl5(g) ⇄ PCl3(g) + Cl2(g)
Initial 0.965 0 0
Change -x +x +x
Equilibrium (0.709344 -x) x x
K_p = 11.5 = x×x / (0.965 -x)
solving, we get x = 0.67027
So partial pressure of PCl5 at equilibrium = 0.709344 - 0.67027 = 0.039074 atm
(c) Partial pressure of PCl3 = Cl2 = 0.709344 atm
So total pressure = 0.709344+0.039074+ 0.67027= 1.418688 atm
g Consider (12.5 A) micro-grams of a radioactive isotope with a mass number of (78 B) and a half-life of (32.6 C) million years. If energy released in each decay is 32.6 keV, determine the total energy released in joules (J) in 1 (one) year. Give your answer with three significant figures.
Answer:
Energy released = 18.985 J
Explanation:
The exponential decay of radioactive substance is given by -
N(t) = N₀ \(e^{-kt}\)
where
N₀ = initial quantity
k = decay constant
Half life, \(t_{1/2} = \frac{ln 2}{k}\)
⇒\(k = \frac{ln 2}{t_{1/2} }\)
Given,
N₀ = 12.5 + 3 = 15.5 × 10⁻⁶ gm
\(t_{1/2}\) = 32.6 + 18 = 50.6 × 10⁶ years
So,
\(k = \frac{ln 2}{50.6 * 10^{6} }\) = 1.361 × 10⁻⁸ year⁻¹
Now,
N(1) = 15.5 × 10⁻⁶ \(e^{-1.361*10^{-8} *1}\)
= 15.49999978904
Now,
Substance decayed = N₀ - N(t)
= 15.5 × 10⁻⁶ - 15.49999978904 × 10⁻⁶
= 21.095 × 10⁻¹⁷ kg
⇒Δm = 21.095 × 10⁻¹⁷ kg
So,
Energy released = Δmc²
= 21.095 × 10⁻¹⁷ × 3 ×10⁸ × 3 × 10⁸
= 189.855 ×10⁻¹
= 18.985 J
⇒Energy released = 18.985 J