What are the different forms of potential and kinetic energy?

High-performance liquid chromatography (HPLC)  is the method used.

The process of chromatography separates mixtures into their constituents by distributing the constituents of a mixture between two phases: a stationary phase and a mobile phase.

Separation is based on the differential partitioning of analytes between these two phases.

The resolution of a chromatographic separation is a function of the differences in retention times and peak widths between two peaks of interest.

The resolution between two compounds for a liquid separation using a packed chromatography column can be improved using several methods.

Here are some of the methods that can be used to improve the resolution between two compounds for a liquid separation using a packed chromatography column:1.

Using a smaller particle size. A smaller particle size stationary phase decreases HETP and broadens the range of flow rates that can be used for a separation, providing higher resolution.2.

Increasing the length of the column. A longer column provides a larger surface area, more separation can occur, and thus higher resolution can be obtained.3. Changing the particle size distribution.

Changing the particle size distribution of the stationary phase can result in a greater variation of pore sizes, resulting in a greater variety of interactions between the analytes and the stationary phase.

This leads to an increase in resolution.4. Changing the solvent or buffer system. Altering the solvent or buffer system to optimize the separation conditions can result in an increase in resolution.

Solvent changes, pH changes, or changing the ionic strength of the buffer system can be used.5. Modifying the temperature.

Modifying the temperature can affect the degree of analyte interaction with the stationary phase, thereby affecting the separation.

It is also necessary to note that liquid chromatography, which is frequently referred to as high-performance liquid chromatography (HPLC),

has a variety of advantages over gas chromatography (GC), which are better suited for volatile or small molecular weight analytes.

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Answer:

Percent error =   11%

Explanation:

Given data:

Circumference = 6.28 cm

Diameter = 1.8 cm

Actual ratio of circumference and diameter = 3.14

Percent error = ?

Solution:

Formula:

Percent error = ( measured value - actual value / actual value) ×100

Measured value:

Measured ratio of circumference and diameter = 6.28 cm/1.8 cm

Measured ratio of circumference and diameter = 3.49

Now we will put the values in percent error formula.

Percent error = (3.49 -3.14 / 3.14) ×100

Percent error =   (0.35 / 3.14) ×100

Percent error =   0.11×100

Percent error =   11%

The third ball of 5 grams of mass will make the biggest crater in the sand because force is directly proportional to mass. so the greeter the mass, the greater its force and impact.

Mass is described as the quantity of matter in a physical body.

Mass is also a measure of the body's inertia, the resistance to acceleration when a net force is applied.

Mass is always known to be constant for a body. We can calculate mass by:

Mass = volume × density.

Weight is the measure of the gravitational force acting on a mass. The SI unit of mass is the "kilogram"

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Jing the scientist has one solution that is 30% acid and another solution that is 18% acid. Solution that she should use to get 300 L of a solution that is 21% acid is 75L.

Anything with a pH lower than 7 is considered acidic. Hence, called as Acid.

Given,

300L of another solution with 21% acid is created by combining 30% of one solution with 18% of another solution.

Let x represent the proportion of solution 1 in the mixture.

Hence, another solution would be (300-x) L

According to given question,

30% of x + 18% of (300-x) = 21% of 300

i.e. 30x/100 + 18(300-x)/100= 21 × 300/100

=> 30x - 18x = 6300 -  5400

=> 12x = 900

=> x = 75L

Hence, 75L of each solution is required to get 300 L of a solution that is 21% acid.

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17.8 grams of pbbr2 will precipitate when excess kbr solution is added to 62.0 ml of 0.787 m pb(no3)2 solution.

The equation of the reaction is;

3Pb(NO3)2(aq) + 2KBr3(aq) –>3PbBr2(s) + 2Cr(NO3)3(aq)​

Number of moles of Pb(NO3)2 =  62.0/1000 L ×  0.551 M = 0.0487 moles

From the information in the question, we already know that  Pb(NO3)2 is the limiting reactant and KBr3 is the reactant in excess.

From the equation of the reaction;

3 moles of Pb(NO3) yields 3 moles of PbBr2

0.0487 moles of Pb(NO3) yields 0.0487 moles ×  3 moles/3 moles

=  0.0487 moles of PbBr2

Mass of PbBr2 = number of moles × molar mass

Mass of PbBr2 =  0.0487 moles × 367 g/mol= 17.8g

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92.0 g of NO2 and 36.0 g of H2O can be combined to create 84.0 g of nitric acid (HNO3). With the chemical formula HNO3, nitric acid, sometimes referred to as aqua fortis or spirit of niter, is a potent mineral acid.

The suggested chemical equation reads as follows: 3 NO2 + H2O 2 HNO3 + NO

The amount of nitric acid (HNO3) that can be produced from the reaction of 92.0 g of NO2 with 36.0 g of water must be calculated.

NO2 has a molar mass of 46.01 g/mol, while H2O has a molar mass of 18.02 g/mol. NO2 moles are equal to 92.0 g / 46.01 g/mol, or 2.00 mol.

H2O molecular weight is equal to 36.0 g / 18.02 g/mol, or 2.00 mol.

To get 1.33 mol HNO3, divide 2.00 mol NO2 by (2 mol HNO3 / 3 mol NO2).

2.00 mol of H2O is converted into 84.0 g of HNO3 using the following equation: 2.00 mol H2O (2 mol HNO3 / 3 mol NO2) (63.01 g/mol HNO3). Hence, 84.0 g of nitric acid (HNO3) made by reacting 92.0 g of NO2 with 36.0 g of water.

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a. Weight fraction of each component: n-C4H10 = 0.50, n-C5H12 = 0.30, n-C6H14 = 0.20

b. Mole fraction of each component: n-C4H10 = 0.5708, n-C5H12 = 0.2781, n-C6H14 = 0.1511

c. Mole percent of each component: n-C4H10 = 57.08%, n-C5H12 = 27.81%, n-C6H14 = 15.11%

d. Average molecular weight of the mixture: 67.95 g/mol

e. Mass density and molar density under ambient temperature and 3 bar:

  Mass density: n-C4H10 = 8.179 g/L, n-C5H12 = 8.732 g/L, n-C6H14 = 10.469 g/L, total = 8.8029 g/L

  Molar density: n-C4H10 = 0.1443 mol/L, n-C5H12 = 0.1443 mol/L, n-C6H14 = 0.1443 mol/L, total = 0.1445 mol/L

Given:

Mass composition:

n-C4H10 (n-butane): 50%

n-C5H12 (n-pentane): 30%

n-C6H14 (n-hexane): 20%

Now, let's perform the calculations:

Step 1: Weight fraction

W_n-C4H10 = 0.50

W_n-C5H12 = 0.30

W_n-C6H14 = 0.20

Step 2: Mole fraction

n-C4H10 moles = W_n-C4H10 / M_n-C4H10 = 0.50 / 58.12 = 0.0086 mol

n-C5H12 moles = W_n-C5H12 / M_n-C5H12 = 0.30 / 72.15 = 0.0042 mol

n-C6H14 moles = W_n-C6H14 / M_n-C6H14 = 0.20 / 86.18 = 0.0023 mol

Total moles = n-C4H10 moles + n-C5H12 moles + n-C6H14 moles = 0.0086 + 0.0042 + 0.0023 = 0.0151 mol

X_n-C4H10 = n-C4H10 moles / Total moles = 0.0086 / 0.0151 = 0.5708

X_n-C5H12 = n-C5H12 moles / Total moles = 0.0042 / 0.0151 = 0.2781

X_n-C6H14 = n-C6H14 moles / Total moles = 0.0023 / 0.0151 = 0.1511

Step 3: Mole percent

Mol%_n-C4H10 = X_n-C4H10 * 100% = 0.5708 * 100% = 57.08%

Mol%_n-C5H12 = X_n-C5H12 * 100% = 0.2781 * 100% = 27.81%

Mol%_n-C6H14 = X_n-C6H14 * 100% = 0.1511 * 100% = 15.11%

Step 4: Average molecular weight

M_avg = W_n-C4H10 * M_n-C4H10 + W_n-C5H12 * M_n-C5H12 + W_n-C6H14 * M_n-C6H14

      = 0.50 * 58.12 + 0.30 * 72.15 + 0.20 * 86.18

      = 29.06 + 21.65 + 17.24

      = 67.95 g/mol

Step 5: Mass density and molar density

Let's assume the temperature is 298 K.

Mass density (ρ) = (P * M_avg) / (R * T)

Molar density (ρ_m) = P / (R * T)

Mass density of n-butane:

ρ_n-C4H10 = (3 bar * 67.95 g/mol) / (0.08314 L bar/mol K * 298 K)

         = 8.179 g/L

Mass density of n-pentane:

ρ_n-C5H12 = (3 bar * 72.15 g/mol) / (0.08314 L bar/mol K * 298 K)

         = 8.732 g/L

Mass density of n-hexane:

ρ_n-C6H14 = (3 bar * 86.18 g/mol) / (0.08314 L bar/mol K * 298 K)

         = 10.469 g/L

Total mass density:

ρ_total = W_n-C4H10 * ρ_n-C4H10 + W_n-C5H12 * ρ_n-C5H12 + W_n-C6H14 * ρ_n-C6H14

        = 0.50 * 8.179 + 0.30 * 8.732 + 0.20 * 10.469

        = 4.0895 + 2.6196 + 2.0938

        = 8.8029 g/L

Molar density of n-butane:

ρ_m,n-C4H10 = 3 bar / (0.08314 L bar/mol K * 298 K)

           = 0.1443 mol/L

Molar density of n-pentane:

ρ_m,n-C5H12 = 3 bar / (0.08314 L bar/mol K * 298 K)

           = 0.1443 mol/L

Molar density of n-hexane:

ρ_m,n-C6H14 = 3 bar / (0.08314 L bar/mol K * 298 K)

           = 0.1443 mol/L

Total molar density:

ρ_m,total = X_n-C4H10 * ρ_m,n-C4H10 + X_n-C5H12 * ρ_m,n-C5H12 + X_n-C6H14 * ρ_m,n-C6H14

         = 0.5708 * 0.1443 + 0.2781 * 0.1443 + 0.1511 * 0.1443

         = 0.0825 + 0.0402 + 0.0218

         = 0.1445 mol/L

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Answer:

1) Without our atmosphere we wouldn't have life! The atmosphere protects our earth from letting harmful substances or rocks into our planet, which could cause damage.

2) You interact with the atmosphere in both good ways and bad. You interact by putting up things like flowers and trees, but in bad ways by releasing bad things (like carbon dioxide) and by light pollution!

3) The factors that can affect climate of an area, by latitude and longitude!

Explanation:

Hope this helps! Plz mark as brainliest! :)

Answer:

C

Explanation:

Because you can't open your lamps when there's no electricity or if it's brownout,,,,

multiplying by 100.after dividing the amount of the hydrate but by volume of the water evaporated

2 free electrons are present. It frequently appears in limestone. It is found bound to metals in groups I and II of periodic table since it cannot live on its own. The name of the metal to which the compound is linked is given first, followed by the word carbonate, as in calcium carbonate, sodium carbonate, and so on.

A chemical molecule known as a carbonate contains the carbonated ion, CO 2 3. These two elements combine to form this ion. The term could also refer to an organic compound having the carbonate that is an ester with carbonic acid.

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The new temperature of the gas is 115 °C

From the question given above, the following data were obtained:

The new temperature of gas can be obtained as follow:

\( \frac{P_1}{T_1} = \frac{P_2}{T_2} \\ \\ \frac{0.96}{298} = \frac{1.25}{T_2} \\ \\ cross \: multiply \\ \\ T_2 \times 0.96 = 298 \times 1.25 \\ \\ divide \: both \: side \: by \: 0.96 \\ \\T_2 = \frac{298 \times 1.25 }{0.96} \\ \\ T_2 = 388 \: K \\ \\ subtract \: 273 \: from \: 388 \: to \: express \: the \: answer \: im \: \degree \: C \\ \\ T_2 = 388 - 273 \\ \\ T_2 = 115 \: \degree \: C \)

Therefore, the new temperature is 115 °C

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Answer:

Reason: Gravitational pull of the Moon

Explanation:

Weight of Garfield is 24 lbs on the Earth. He took a flight from the Earth to the Moon where the gravity is 1/6 of the gravity on the Earth.

But when reaches the Moon he found he weighed only 6 lbs. It is due to the gravitational pull of the Moon.

Mass of an object reamins the same at every location while its weight changes due to the change in acceleration due to gravity. It is equal (on Moon) to 1/6 the of acceleration due to gravity on the earth.

Answer:

Number 6 is correct all substances are made of molecules.

Explanation:

A molecule is a formation of atoms or a chemical and all substances are made of chemicals.

The given statement all known substances are made of molecules is correct. Therefore, option (d) is correct.

All known compounds in chemistry are made up of different kinds of molecules. A compound contains atoms or ions of two or more elements in fixed proportions joined with each other by bonds into a molecule. Molecules are formed when atoms are joined through chemical bonds.

Any molecule that contains atoms of two or more different elements is known as a compound. All the compounds are written into formulas that present the chemical elements from the periodic table combined.

When the atoms of a particular element combine, some individual property of that chemical element is lost. The newly formed compound shows some new properties.

All the compounds or known substances have a chemical formula. These compounds can be divided into two kinds, molecular compounds, and salts.

Some examples of substances made of molecules such as water have molecules of H₂O, hydrogen peroxide H₂O₂, etc.

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Answer: A. There will be fewer producers in that area.

Explanation: Answer A is correct because all plants, including grass, is a producer. Since there is an increase in grass eating animals (Antelope), more grass will be consumed, decreasing the amount of grass aka producer.

Answer: Chloride and Chromate ions

Explanation:

Two anions used in this lab to perform selective precipitation of the unknowns are chloride and chromate ions.

Anions such as  Cl− ,  Br− ,  SO2−4 ,  CO2−3 ,  S2− ,  Cr2O2−4 ,  PO2−4 ,  OH−  etc., forms a mixture of metal ions in a solution which can be separated by precipitation. If a metal ion or a group of metal ions forms insoluble salts with a particular anion, then they can be separated from others by the precipitation.

Anions can also be separated by the precipitation with appropriate metal ions. There are no separation lines between insoluble salts, sparingly soluble, and soluble salts, but their concentrations of saturated solutions are small, medium, and large. For insoluble and sparingly soluble salts, solubility products are usually listed. But for soluble salts they are not given.

Solubility products for soluble salts are very large.

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Therefore, the volume of O2 needed at 298K and 1 atm is approximately 77 liters.

The balanced chemical equation for the combustion of ethane is shown below:

7O2 + 2C2H6 → 4CO2 + 6H2O

We can use the stoichiometry of the reaction to find out how much O2 is needed to completely react with 2 moles of C2H6.

2 moles of C2H6 requires 7 moles of O2.10 L of C2H6 will contain (10/22.4) x 2 moles of C2H6 = 0.892 mole C2H6.

So the amount of O2 needed will be: (7/2) x 0.892 mole C2H6 = 3.118 moles O2.

Since the gases behave ideally, we can use the ideal gas law to find the volume of O2 at 298K and 1 atm.

PV = nRTV = nRT/PV = (3.118 mol) (0.08206 L atm K-1 mol-1) (298 K) / (1 atm)V = 77.02 L ≈ 77 L

Therefore, the volume of O2 needed at 298K and 1 atm is approximately 77 liters.

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The cell’s pressure potential or ψp is 2.44 bars if the cell contains 0.6M glucose at 20°c with its surrounding solution containing 0.5M glucose.

As;

ψoutside = ψcell ( here ψ represents water potential)

Therefore;

ψp outside + ψs outside = ψp cell + ψs cell ( Since, ψ = ψp + ψs)

As ψs = -iCRT, therefore

0 + (-iCRT outside) = ψp cell + (-iCRT cell)

In iCRT, i represents the ionization constant

C represents the Molar concentration

R represents the Pressure constant 0.0831 liter bars/mole at degrees Kelvin

T represents temperature (degree kelvin)

Substituting the values;

(-1)(0.5M)(0.0831)(20 + 273) = ψp - (1)(0.6M)(0.0831)(20 +273)

-12.17 = ψp cell - 14.61

ψp cell = (-12.17) + 14.61

ψp cell = 2.44 bars

Therefore, the cell’s pressure potential (ψp) is calculated to be 2.44 bars if the cell contains 0.6M glucose at 20°c with its surrounding solution containing 0.5M glucose.

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Answer:

The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther it is from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.

The name of adenine when connected to the deoxyribose sugar and a phosphate is "C) adenosine monophosphate."

When adenine is connected to the deoxyribose sugar and a phosphate, its name becomes "C) adenosine monophosphate."

Adenine is one of the four nitrogenous bases found in DNA and RNA. When adenine is connected to the deoxyribose sugar and a phosphate group, it forms a nucleotide known as adenosine monophosphate (AMP).

AMP consists of three components:

The combination of these three components forms adenosine monophosphate (AMP), which is a nucleotide involved in various cellular processes and serves as a building block for the synthesis of RNA.

Therefore, the correct answer is "C) adenosine monophosphate."

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Moon reflects the light frim the sun, thats why we are able to see it and it shines in the night. But, we know that Earth revolves around Sun and Moon revolves around Earth. During this revolution, Earth and Moon comes in a position when Earth is in the middle of the Moon and Sun. So, it blocks the light of Sun frim reaching Moon. Hence, we see no reflection and it causes Lunar eclipse.

Answer:

A total lunar eclipse occurs when the moon and the sun are on exact opposite sides of Earth. Although the moon is in Earth's shadow, some sunlight reaches the moon. The sunlight passes through Earth's atmosphere, which causes Earth's atmosphere to filter out most of the blue light.

Explanation:

Answer:

(i think) it is A difference in 1 unit is a 10X difference in concentration For example; a liquid with pH of 3 is 10X more acidic than a liquid with a pH of 4. Therefore, a liquid with a pH of 3 is stronger.

Explanation:

Skipping the step of determining the volume at the tip of the buret would result in an inaccurate measurement of the volume of the liquid used in the experiment.

What is molar mass?

Molar mass is the mass of one mole of a substance. A mole is a unit of measurement in chemistry that represents a specific number of particles,  also known as Avogadro's number

Determining the volume of the tip of the buret is essential for accurately measuring the volume of a liquid, as it affects the accuracy of the final molar mass calculation. If this step is skipped, the measured volume of the liquid would be incorrect, leading to an incorrect calculation of the molar mass of magnesium.

To understand how skipping this step would affect the final molar mass calculation, we need to consider the formula used to calculate the molar mass of magnesium:

Molar mass = (mass of magnesium) / (moles of magnesium)

To calculate the moles of magnesium, we need to know the volume of the liquid used in the experiment, as well as its concentration. If the volume of the liquid is incorrect due to not accounting for the volume of the tip of the buret, then the calculated moles of magnesium would also be incorrect.

This, in turn, would lead to an incorrect molar mass calculation, as the molar mass is calculated by dividing the mass of magnesium by the moles of magnesium. If the calculated moles of magnesium are incorrect, then the resulting molar mass calculation would also be incorrect.

Therefore, skipping the step of determining the volume at the tip of the buret would result in an inaccurate measurement of the volume of the liquid used in the experiment, ultimately leading to an inaccurate calculation of the molar mass of magnesium.

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Answer:

the surface area of a solid reactant.

temperature.  

presence/absence of a catalyst.

Answer:

C. is the correct answer

Explanation:

Answer:

True I think..-

Explanation:

Sorry if it's wrong.-

The required mass of water vaporized is 15.5 grams, from a 250 gram sample of water at the boiling point had 35.0 kj

Given: Mass of water (m) = 250 gHeat added (q) = 35.0 kJHeat of vaporization (ΔHvap) = 40.6 kJ/mole

To find:Mass of water vaporized (x) Formula:q = ΔHvap × nx = (q / ΔHvap) × nMass = moles × molar mass

We know that molar mass of water (H2O) = 18 g/molMoles of water vaporized (n) = (35.0 kJ / 40.6 kJ/mol) = 0.861 mol

Therefore,Mass of water vaporized (x) = 0.861 mol × 18 g/mol= 15.5  

Detailed Solution: According to the given statement,250g of water was taken at its boiling point and 35.0 kJ of heat was added to it, we need to find how many grams of water were vaporized. To solve this question, first, we need to know the heat of vaporization for water, which is 40.6 kJ/mole. It means to vaporize 1 mole of water, 40.6 kJ of heat is required.

Mass of water (m) = 250 g Heat added (q) = 35.0 kJHeat of vaporization (ΔHvap) = 40.6 kJ/molen = q / ΔHvapn = (35.0 kJ / 40.6 kJ/mol) = 0.861 molMoles of water vaporized (n) = 0.861 mol

Therefore, Mass of water vaporized (x) = 0.861 mol × 18 g/mol= 15.5 g Hence, the required mass of water vaporized is 15.5 grams.

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Activity would be expected for a 25.3 mg sample of carbon-14 is 25.296

Here given data is Carbon-14 has a half-life of 5730 yrs and expected for a 25.3 mg sample of carbon-14 =?

So here half life of Carbon-14 is t1/2=5730 yrs

This means that 5730 yrs the initial amount of carbon-14 will be halved

The radioactive constant is λ=ln2/t1/2 = ln2/5730=0.000121

The fundamental decay equation is m=m0e⁻λt

Initial amount of carbon-14 is m0=25.3

Therefore, 25.3×e⁰⁰⁰⁰¹²¹=25.296

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Answer: 80

Explanation:

12+6+1+1=20

20x4=80