What are the basic components of electric circuit?

Answer:

When the  water is frozen it turns to ice and the density decreases.

Explanation:

Have A Wonderful Day !!

Answer:

Tropical region

Explanation:

because the regions near the equator are called tropical regions

Answer:

Explanation:

1

2

3

The third table shown in the diagram below can be modelled with the equation, y = x + 2, therefore, it represents a linear equation.

A linear function is a function whose graph represents a straight line when the points are plotted, and also can be modelled by the equation, y = mx + b.

b is the value of y when x = 0 (y-intercept)

m is the slope or unit rate.

Thus, the third table shown in the diagram below can be modelled with the equation, y = x + 2, therefore, it represents a linear equation (see attachment). The last table has a constant slope of -3, hence it represents a linear function.

Table of functions

From the given table, we need to determine which of the table is a linear table. To determine that, we must check which of the table has a constant rate of change

Looking at the last table;

Slope = -4-(-2)/2-1

Slope = -4+1/1

Slope = -3

Since the last table has a constant slope of -3, hence it represents a linear function.

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The semi-major axis of the satellite's orbit is calculated as the average of the perigee and apogee altitudes. The eccentricity of the orbit is determined using the formula (apogee - perigee) / (apogee + perigee).

To find the semi-major axis of the satellite's orbit, we can take the average of the perigee and apogee altitudes. The perigee altitude is 555.0 km and the apogee altitude is 1200.0 km, so the semi-major axis is (555.0 km + 1200.0 km) / 2 = 877.5 km.

The eccentricity of the orbit can be calculated using the formula (apogee - perigee) / (apogee + perigee). In this case, the eccentricity is (1200.0 km - 555.0 km) / (1200.0 km + 555.0 km) = 0.173.

To determine the satellite's altitude with a true anomaly of 160 degrees, we can use the equation for the altitude in terms of the semi-major axis, eccentricity, and true anomaly. The altitude can be calculated as:

Altitude = semi-major axis * (1 - \(eccentricity^2\)) / (1 + eccentricity * cos(true anomaly))

Plugging in the values, we have:

Altitude = 877.5 km * (1 - \(0.173^2\)) / (1 + 0.173 * cos(160 degrees))

Altitude ≈ 769.1 km

Therefore, the satellite's altitude with a true anomaly of 160 degrees is approximately 769.1 km.

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The magnitude and direction of the electric field which would be needed to balance the weight of an electron, proton, and oil drop can be calculated using the following equation: Electric field (E) = (Force of gravity (Fg)) / (Charge (q)) is 1.59 × 10⁵ N/C.

For an electron, q = -1.6 × 10⁻¹⁹ C and Fg = 9.81 N. Therefore, the magnitude of the electric field needed to balance the weight of an electron is:

E = (9.81 N) / (-1.6 × 10⁻¹⁹ C) = 6.13 × 10¹⁸ N/C. For a proton, q = +1.6 × 10⁻¹⁹ C and Fg = 9.81 N.

Therefore, the magnitude of the electric field needed to balance the weight of a proton is:

E = (9.81 N) / (1.6 × 10⁻¹⁹ C) = 6.13 × 10¹⁸ N/C

For an oil drop, q = +6.2 × 10⁻¹⁴ C and Fg = 9.81 N.

Therefore, the magnitude of the electric field needed to balance the weight of an oil drop is:

E = (9.81 N) / (6.2 × 10⁻¹⁴ C) = 1.59 × 10⁵ N/C

The direction of the electric field for all three objects is the same, upward. The direction of the electric field is upward or downward depending on the charge of the oil drop. If the oil drop is negatively charged, then the electric field will be upward, and if the oil drop is positively charged, then the electric field will be downward.

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Answer:

Where speed limit of speed camera is 50 km/h.

Explanation:

Speed cameras work on the principal that photos reflected from the moving car have a higher or lower frequency. This is the Doppler principal. In a  car traveling at the speed of light, the waves/particles will not be able to catch up with that car thus no photon will reflect back to the receiver/speed camera thus no speed will be record. Such a speed is impossible to achieve due to the amount of infinite energy expenditure required. This means if the speed is higher and approaching that of light, the frequency of reflected photons will be very high causing high amounts of energy that could damage the speed camera and cause detection. When the car travels at a higher speed, the photos frequency is high thus more energy they will carry and high chances of the vehicle being detected. This means the time interval of photos taken will be smaller.

Answer:

when the ray passes from ice to perspex it must approach the normal

Explanation:

This is an exercise in refraction of light, the process is governed by the expression

      n₁ sin θ₁ = n₂ sin θ₂

where we use index 1 for the incident medium and subscript 2 for the scattered medium.

In our case, medium 1 is ice with the lowest refractive index.

           sin θ₁ = n₂ / n₁   sin θ₂

To fulfill this equation, if the ray travels through the medium 1 ice with an angle θ₁, the angle in the medium 2 perspex must be smaller so that the sine is smaller, so when the ray passes from ice to perspex it must approach the normal

Answer:

1875 j

Explanation:

f * d = work

your AVERAGE force is (210+ 40)/2 = 125 N

125 * 15 = 1875 j

The work done during this period will be 1875 J.. if the body is displaced in the same direction of the force it will be positive.

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative.it depends on the direction of the body displaced

The given data in the problem is;

F is the average force applied by the worker

d is the displacement = 15 m

The average force is ;

\(\rm F_{AVG} = \frac{F_1+F_2}{2} \\\\ F_{AVG} = \frac{210+40}{2} \\\\ F_{AVG}=125 \ J\)

The work done by the worker will be;

\(\rm W= Fd \\\\\rm W= F_{AVG}d \\\\W= 125 \times 15 \\\\ \rm W=1875 \ J\)

Hence the work done during this period will be 1875 J.

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The acceleration of the particle is constant \((a=9.8 m/sec^2)\), and it is vertically downward. Therefore, the correct option is diagram no 4.

In the case of a projectile launched into the air, the acceleration acts vertically and is influenced by gravity.

Let's analyze the three points along the path of the projectile:

1. On its way up: At this point, the projectile is moving upwards, and gravity is acting in the downward direction. Therefore, the acceleration of the projectile at this point is directed downward to oppose the upward motion and eventually bring the projectile to a stop.

2. At the top: The projectile reaches its maximum height and momentarily comes to a stop before starting to fall back down. At this point, the acceleration is solely due to gravity, and it acts vertically downward. The acceleration at the top of the projectile's path is directed downward.

3. On its way down: The projectile is now moving downward, and gravity continues to act in the downward direction. The acceleration at this point is again directed downward, assisting the downward motion of the projectile.

Considering these factors, the drawing that correctly represents the acceleration of the projectile at these three points should show the acceleration vector pointing vertically downward in all three positions.

This represents the consistent influence of gravity on the projectile throughout its motion.

Therefore, the correct option is diagram no 4. The acceleration of the particle is constant \((a=9.8 m/sec^2)\), and it is vertically downward.

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Explanation:

If the moon doubled in mass, that means that the Earth will not experience a total solar eclipse like today. Also, if it doubled in mass, tide waves would increase in size, as the moon would be bigger and would have a bigger gravitational pull. Also, gravity would be different on earth because the moon is bigger (gravity law by mass). Also, the sky would be ‘smaller’ than our actual sky

Answer:

If the moon's mass doubles, the Earth will not witness a total solar eclipse as today. Also, if its mass doubled, tide waves would double in size since the moon would be bigger and have a stronger gravitational attraction. Also, because the moon is larger, gravity on Earth would be different (gravity law by mass). Also, the sky would be "smaller" than it is now.

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Answer:

the shape of the glass change and the size of the glass also change

The total change in thermal energy of the air you inhaled is approximately 158872.5 joules.

To calculate the total change in thermal energy of the air you inhaled, we can use the specific heat capacity equation:

Q = m * c * deltaT

where Q is the total change in thermal energy, m is the mass of the air, c is the specific heat capacity of air, and deltaT is the change in temperature.

We can assume that the pressure of the air remains constant, so we can use the equation for constant pressure processes:

Q = m * Cp * deltaT

where Cp is the specific heat capacity at constant pressure.

The mass of air inhaled is not given, but we can assume it is approximately equal to the volume of air inhaled, which is typically around 0.5 liters or 0.5 kg.

The specific heat capacity of air at constant pressure, Cp, is approximately 1005 J/kg*K.

The change in temperature, deltaT, is (32 - (-10)) = 42 degrees Celsius, which is equivalent to 42 + 273.15 = 315.15 Kelvin.

Plugging in the values, we get:

Q = 0.5 kg * 1005 J/kg*K * 315.15 K = 158872.5 J

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Using the time dilation formula we find that the required speed is 0.79 0.79 0.79 c. It move very fast.

Definition of time dilation

A slowing of time in accordance with the theory of relativity that occurs in a system in motion relative to an outside observer and that becomes apparent especially as the speed of the system approaches that of light. — called also time dilatation.

The idea of "absolute time" was our default for millennia. But time is relative, as gravity and motion both cause time to dilate. Both space and time coordinates are needed to describe an object in our Universe.

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Scientific model of volcanic eruptions using computer programming is very helpful to identify their origin and consequences. The biggest benefit of these model is to identify the physical behaviors of magma .

Scientific model are used to visualize the complex theories and concepts. There are both theoretical models and visual models. Nowadays complex problems and processes are easily solving using well designed computer programmes and simulations.

By creating a sophisticated computer model based on the most recent physical understanding of magma behavior, its most likely path of least resistance, and statistical information obtained from prior volcanic  eruptions, scientists was able to address these issues.

They were able to predict the site of historical events that were not used to fine-tune the model by using historical data collected from Campi Flegrei, a caldera close to Naples, Italy etc.

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Answer:

Using a model is less hazardous than being up close to a real Volcano

Explanation:

Answer:

The change in velocity is 5.5 km/h

Explanation:

The initial velocity with which the sailboat is travelling, v₁ = 10 km/h

The final velocity with which the sailboat is travelling, v₂ = 15.5 km/h

The change in velocity, Δv, is the difference between final velocity, v₂ and the initial velocity, v₁, as follows;

Mathematically, Δv = v₂ - v₁

By substituting the given values, we have;

Δv = 15.5 km/h - 10 km/h = 5.5 km/h

The change in velocity, of the sailboat Δv = 5.5 km/h.

Answer:

If the charges have the same sign, so that qsqt>0, then the potential energy decreases as the charges separate; if the charges have opposite sign, the potential energy increases from negative infinity.

Explanation:

I hope this answered your question!

Answer:

A packing crate of weight 50N is placed on a plane inclined at 35°from the horizontal. If the coefficient of static friction between the crate and the plane is 0.65, will the crate slide down the plane? asked by Siyam February 26, 2022 1 answer normal force = m g cos 35 = 50 cos 35 = 41 Newtons so max friction force up slope = 0.65 * 41 = 26.6 N

Explanation:

The maximum height of the child on the swing relative to her lowest height is determined by the conservation of mechanical energy, where the maximum height can be calculated using the maximum speed. Hence, the maximum height of the child on the swing relative to her lowest height is approximately 1.84 meters.

When a child is on a swing, the total mechanical energy is conserved, assuming negligible air resistance. The mechanical energy is the sum of the kinetic energy (KE) and the potential energy (PE). At the highest point of the swing, the kinetic energy is zero, as the child comes to a momentary stop before changing direction. At the lowest point of the swing, the potential energy is zero, as it is fully converted into kinetic energy.

Since the maximum speed is given as 6 m/s, this represents the maximum kinetic energy of the child on the swing. At the highest point, all the kinetic energy is converted into potential energy. Therefore, the maximum height can be calculated using the conservation of energy equation:

KE_max = PE_max

1/2 mv^2 = mgh_max

Simplifying the equation, we can solve for h_max:

h_max = (v^2) / (2g)

Substituting the given values, where v = 6 m/s and g is the acceleration due to gravity (approximately 9.8 m/s^2), we can calculate the maximum height:

h_max = (6^2) / (2 * 9.8) ≈ 1.84 meters

Therefore, the maximum height of the child on the swing relative to her lowest height is approximately 1.84 meters.

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Answer:19.1m

Explanation:

The hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity

Stars are a fixed luminous point in the sky which is a large and remote incandescent body

So therefore, the hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity

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According to the law of conservation of momentum, the total momentum of a system remains constant if no external forces act on it the total momentum of the system before and after the collision will be conserved. The correct option d.

The law of conservation of momentum states that in a closed system, the total momentum before a collision is equal to the total momentum after the collision, provided there are no external forces acting on the system. The law applies to both linear and angular momentum.

In the given scenario, the total momentum of the system before the collision is the sum of the momenta of the two disks. After the collision, the total momentum of the system should still be the same as before the collision if no external forces are present.

The individual velocities and directions of the disks after the collision may change, and they may continue to move at different velocities or even come to rest. The law of conservation of momentum does not dictate the velocities or outcomes of the individual objects involved in the collision. It only states that the total momentum of the system remains constant.

Therefore, option d) The total momentum of the system before and after the collision will be conserved is the correct statement according to the law of conservation of momentum.

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Of the given options, it is unlikely that the change in temperature of the substance would be zero over one cycle of a cyclic process. This is because in a cyclic process, the substance undergoes a series of transformations that cause changes in the internal energy, pressure, volume, and other properties.

These changes are typically accompanied by changes in temperature as the substance absorbs or releases heat. For example, in a Carnot cycle, the substance undergoes isothermal expansion and compression, during which its temperature remains constant, but then undergoes adiabatic expansion and compression, during which its temperature changes.

In contrast, the work done by the substance, the change in volume of the substance, the change in the internal energy of the substance, and the change in pressure of the substance can all be zero over one cycle of a cyclic process, depending on the specific nature of the process.

For example, if a gas undergoes a reversible isothermal expansion and compression, the work done by the gas would be zero over one cycle, since the net work done on the gas is zero. Similarly, if a gas undergoes a reversible adiabatic expansion and compression, the change in internal energy of the gas would be zero over one cycle, since the net heat added to or removed from the gas is zero.

Thus, the specific conditions of the cyclic process would determine which properties are likely to be zero over one cycle.

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The impulse on the baseball when hit by a player's bat can be calculated using the formula for impulse, which is the product of the force applied and the time of contact. the impulse on the ball is 0.1021 Ns

In this case, since the ball is initially moving horizontally and is brought to rest in the opposite direction, the change in momentum is twice the momentum of the ball before contact. The impulse can be found by multiplying the change in momentum by the time of contact.

The initial momentum of the baseball can be calculated by multiplying its mass (0.140 kg) by its initial velocity (36.7 m/s). Since the ball comes to rest in the opposite direction, the change in momentum is equal to twice the initial momentum. The change in momentum is then multiplied by the time of contact (0.05 s) to find the impulse on the ball.

Therefore, the impulse on the ball is 0.140 kg * 36.7 m/s * 2 * 0.05 s = 0.1021 Ns.

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Answer:25

Explanation:

Formula(77°F − 32) × 5/9 = 25°C

Answer: The answer is C. 298 K

Explanation:

Answer:

you to

Explanation:

sleep well and long and thank you for the points

kinetic energy 8.0 s later will be 11.35 joules

Given:

inertia,I=0.034kgm²

torque,τ=0.11nm

time,t=8.0s

To find:

kinetic energy,KE

we can find the kinetic energy by using

\(k = \frac{1}{2} iω {}^{2} \)

so firstly we will find ω by finding α

α=τ/I

α=0.11/0.34

=3.23

then we find ω

ω=α×t

=3.23×8

=25.84

\(k = \frac{1}{2}iω {}^{2} \)

k=1/2×0.34×(25.84)2

=1/2×22.70

k=11.35

so kinetic energy is 11.35 joules

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Specific Heat of Metals Laboratory Report. The objective of this laboratory experiment was to determine the specific heat of several metal samples. The metal samples tested were aluminum, copper, and iron.The specific heat is the energy required to raise the temperature of a unit of mass by a unit of temperature.

This experiment was conducted by finding the temperature change of the water and the metal sample that is heated in the water bath at 100 °C. The data collected was then analyzed to determine the specific heat of the metal sample.The specific heat of a substance is a physical property that defines how much energy is needed to increase the temperature of a unit mass by one degree Celsius or Kelvin. The experiment determines the specific heat capacity of metal samples, copper, aluminum, and iron. The experiment involves heating the metal samples in boiling water before putting them into a calorimeter. Then, the calorimeter containing water is then transferred to the calorimeter cup where the metal is heated by the hot water. The water’s temperature is recorded with a thermometer before and after adding the metal, while the metal’s initial and final temperatures are also measured. The mass of the metal and water is also recorded.To calculate the specific heat capacity of the metal sample, you need to know the mass of the sample, the specific heat of the calorimeter, the mass of the calorimeter, the mass of the water, and the initial and final temperatures of the metal and water. The results of the laboratory experiment indicate that the specific heat capacity of copper is 0.07 and the specific heat capacity of aluminum is 0.22. The experiment demonstrated that the specific heat capacity of metal samples is different.

Thus, the specific heat of different metals can be determined using the laboratory experiment discussed in this report. The experiment aimed to find the specific heat capacity of aluminum, copper, and iron samples. The experiment involved heating the metal samples in boiling water and then placing them into a calorimeter. The temperature changes of both the metal sample and water were noted, and the specific heat of the metal was calculated. The results show that the specific heat capacity of copper is 0.07, and the specific heat capacity of aluminum is 0.22. The experiment proved that different metals have different specific heat capacities.

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Answer:

Her linear velocity on the outer edge is 3 m/s

Her rotational velocity, is constant at 2 RPM

Explanation:

The given parameters are;

The radius of the rotating platform = r

The linear velocity  v(t) = 1 m/s

The position Emily is riding = 1/3 the distance from the center

The rotational velocity = 2 RPM = 2 Revolutions per minute

The formula for angular velocity, ω is given as follows;

ω = θ/t

Where;

θ = The angle rotated

t = The time taken for the rotation

Given that the rotational velocity = 2 RPM

1 revolution = 2·π radians

The angular velocity, ω = 2×π×(2 RPM) = 4·π rad/min = 4·π/60 rad/seconds

ω = 4·π/60 rad/seconds

The linear velocity, v = r₁×θ/t = r₁×ω

Where;

r₁ = 1/3 × r

v = 1 m/s = 1/3 × r  × 4·π/60 rad/seconds

∴ r = 1/(1/3 × 4·π/60) = 45/π meters

r = 45/π meters

Therefore her linear velocity, v₂ and her rotational velocity if she moves to the outer edge will be given as follows;

v₂ = r × ω = 45/π × 4·π/60 = 3 m/s

Her linear velocity on the outer edge, v₂ = 3 m/s

Her rotational velocity, remains at 2 RPM.

The period of y for two satellites that are being watched as they orbit the planet is 22.63 times, and if the period of rotation of satellite x is T, satellite y.

Is four times as far from the Centre of the earth as satellite x. A satellite, often known as an artificial satellite, is a spacecraft that has been put into orbit on purpose. With the exception of passive satellites, most spacecraft have a method for producing electricity for the electronics they carry, such as solar cells or radioisotope thermoelectric generators. From above the Northern Hemisphere, Earth circles the Sun in a counterclockwise manner at an average distance of 149.60 million kilometres. It takes 365.256 days to complete one orbit.

Tx/Ty = (rx/ry) 3/2 = (8/1) 3/2 = 8 3/2 where Tx/Ty = (rx/ry) 3/2 =

X's revolution lasts for 8/3 = 22.63 times as long as Y does

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