What are possible surface features on a planet the size of Venus, but the same distance from the Sun as Earth
Answers
A planet the size of Venus at the same distance from the Sun as Earth may feature a thick carbon dioxide atmosphere, high temperatures, volcanic activity, rugged terrain, and potential evidence of tectonic activity.
There are various surface characteristics that may exist on a planet the size of Venus which is located at the same distance from the Sun as Earth.
A dense atmosphere mostly made of carbon dioxide, extreme surface temperatures that average over 900 degrees Fahrenheit (475 degrees Celsius), and strong greenhouse effects are only a few Venus-like characteristics.
There may be volcanic activity on the planet, with the possibility of massive shield volcanoes and vast lava plains. There could also be extensive expanses of rocky, hilly terrain as well as possible tectonic activity indicators like rift valleys or crustal deformations.
It is also conceivable that impact craters from meteorite impacts exist, albeit they would not be as noticeable because of Venus' dense atmosphere.
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Related Questions
The graphic organizer compares energy transfer in two layers of the Sun. A venn diagram of 2 intersecting circles with the left circle labeled convection zone and the right circle labeled radiative zone. There is an X in the convection zone circle. There is a Y in the radiative zone. Which labels belong in the regions marked X and Y? X: Absorbs energy from the core Y: Takes longer for photons to move through X: Releases energy to the photosphere Y: Takes longer for photons to move through X: Takes longer for photons to move through Y: Absorbs energy from the core X: Takes longer for photons to move through Y: Releases energy to the photosphere
Answers
Answer:
X: Absorbs energy from the core.
Y: Releases energy to the photosphere.
Explanation:
Convection is a mode of heat transfer through fluids (liquids or gas), and it requires material medium for its propagation.
The energy absorbed from the core of the Sun, is transferred through X (convection zone) by convectional process, and it flows to Y (radiative zone). Since the regions X and Y have different functions, the heat propagates from X causing photons to traverse through Y where it get released into the photosphere or the Sun's surface.
Therefore;
X: Absorbs energy from the core.
Y: Releases energy to the photosphere.
Answer:
X: Takes longer for photons to move through
Y: Releases energy to the photosphere
Explanation:
when the "spindle" contacts the "anvil" on a standard sae micrometer, it will read
Answers
When the spindle contacts the anvil on a standard SAE micrometer, the measurement of the object being measured can be taken.
The spindle is the movable part of the micrometer that comes into contact with the object, while the anvil is the fixed part that provides a stable surface for the object to rest against. The micrometer uses a calibrated screw mechanism to provide precise measurements in units of thousandths of an inch (or millimeters, depending on the type of micrometer).
Therefore, when the spindle contacts the anvil, the measurement can be read off the micrometer's scale or digital display, giving the exact size of the object being measured with a high degree of accuracy.
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An object with a mass of 2.0 kg has a force of 5.0 newtons applied to it. What is the resulting acceleration of the object?
Answers
Answer:
2.5
Explanation:
F=m.a
(Force = mass . acceleration)
5=2.a
a= 5/2 = 2.5
a 160 kg lineman moving west at 2 m/s tackles an 88 kg football fullback moving east at 5 m/s. after the collision, both players move east at 2 m/s
Answers
320 kg.m/s is the momentum of lineman (p)lineman =mv and 440 kg.m/s is the momentum of football fullback (p)fullback =mv.
What is change in momentum after collision?Whenever to body collides there is no change in the momentum of the body as momentum of body is equal to the momentum before the collision to the momentum after the Collison.
As per the given data:
Mass of lineman= 160 kg
velocity of lineman=2m/s
mass of fullback=88 kg
velocity=5 m/s
now momentum of lineman (p)lineman =mv
(p)lineman =160*2
(p)lineman =320 kg.m/s
now momentum of football fullback (p)fullback =mv
(p)fullback =88*5
(p)fullback =440 kg.m/s
now both travelling towards each other so final momentum after collision = 440-320
=120 kg.m/s
hence, the final momentum = 120 kg.m/s after collision .
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an astronaut has a momentum of 280 kg and travels 10 m/s. what is the mass of the astronaut?
Answers
Answer:
The answer is
28 kgExplanation:
The mass of an object given it's momentum and velocity / speed can be found by using the formula
\(m = \frac{p}{v} \\ \)
where
m is the mass
p is the momentum
v is the speed or velocity
From the question
p = 280 kg/ms
v = 10 m/s
The mass of the object is
\(m = \frac{280}{10} = 28 \\ \)
We have the final answer as
28 kgHope this helps you
why does a typhoon hit a location twice?
Answers
An astronaut decides to perform an experiment to monitor how much weight he loses during his stay on the International Space Station. He weighs himself prior to takeoff, daily while on the space station, and again after returning to Earth.
Explain the following for 2 points each:
Identify what data from the weights he recorded should be considered in his experiment
For any weigh-ins that should not be used in his experiment, explain your reasoning
Explain the relationship between mass, weight, and gravity
Answers
Answer:
The first one is: His weight on the Earth before take-off and the weight after take-off back on Earth once he gets back should be recorded as his Independent variable and his dependent variable.
The second one is: If he gained the weight back that he had lost while on the trip then you should disregard them unless that was the weight he was when he weighed himself after he got back.
The Third one is: The mass of an object is the amount of matter it contains, regardless of its volume or any forces acting on it. … Gravity is a force that attracts objects toward the Earth. The weight of the object is defined as the force caused by gravity on a mass.
Explanation:
I took the quiz earlier. Hope this Helps you.
quarterback. The mass of the ball is 0.41 kg it has a speed of 22.0 m/s just before the player caught it. Assuming that the football player catches the ball with his feet off the ground and both the player and ball are moving horizontally, calculate the final velocity of the ball and player
Answers
Question: A football player of mass 107 kg, is running at a speed of 6.7 m/s when it catches a ball thrown by the quarterback. The mass of the ball is 0.41 kg it has a speed of 22.0 m/s just before the player caught it. Assuming that the football player catches the ball with his feet off the ground and both the player and ball are moving horizontally, calculate the final velocity of the ball and player
Answer:
6.76 m/s
Explanation:
From the question above,
Applying the law of conservation of momentum
Total momentum before collision = Total momentum after collisiom
Note: This type of collision is an elastic collision, and so the player and the ball moves with a common velocity after collision.
Mv+mu = V(M+m).................... Equation 1
Where M = mass of the player, v = initial velocity of the player, m = mass of the ball, u = initial velocity of the ball, V = Final velocity of the ball and the player
make V the subject of the equation
V = (Mv+mu)/(M+m)................... Equation 2
Given: M = 107 kg, m = 0.41 kg, v = 6.7 m/s, u = 22 m/s
Substitute into equation 2
V =[(107×6.7)+(0.41×22)]/(107+0.41)
V = (716.9+9.02)/107.41
V = 6.76 m/s.
A 45 kg swimmer starting from rest can develop a maximum speed of 12 m/s over a distance of 20 m. How much net force must be applied to do this?
Answers
KE = kinetic energy = (1/2)mv2
m = 45 kg
vo = 0 m/s (starts at rest)
vf = 12 m/s (final speed)
If a 45 kg swimmer starting from rest can develop a maximum speed of 12 m/s over a distance of 20 m , then the net force must be applied to this would be 162 Newtons .
What is work done?The total amount of energy transferred when a force is applied to move an object through some distance .
Work Done = Force × Displacement
As given in the problem a 45 kg swimmer starting from rest can develop a maximum speed of 12 m / s over a distance of 20 m.
The total work done = 0.5 × 45 × 12²
= 3240 Joules
3240 = Force × 20
Force applied on the crate = 3240 / 20
= 162 Newtons
Thus, the net force that must be applied to this would be 162 Newtons .
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. Why are the Jovian planets formed from materials different from the terrestrial planets?
a. Terrestrial planets were protected by the asteroid belt between Mars and Jupiter.
b. The composition of elements in a planet was a random process after the big bang.
c. When the solar system first formed, the heaviest elements sank toward the center of the nebulae and the lightest elements floated out.
d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
e. Only the terrestrial planets formed from planetesimals.
Answers
The Jovian planets are formed from materials different from the terrestrial planets for the reason that gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
A Jovian planet, also known as a gas giant, is a huge planet that has a primarily gaseous composition. The Jovian planets include Jupiter, Saturn, Uranus, and Neptune. They are primarily made up of hydrogen and helium, and they have enormous atmospheres.Jovian planets are formed farther away from the heat of the Sun, so they are formed from lighter-weight nebulae "dust." Terrestrial planets, on the other hand, are formed nearer to the Sun, so they are formed from heavier-weight nebulae "dust." The density of the materials that make up the Jovian planets is lower than that of the terrestrial planets due to this. This means that the Jovian planets have lower densities and a greater volume than the terrestrial planets.
Hence, the correct option is d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."
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What are three types of physical movement?
1.
2.
3.
Answers
Answer:
Flexion,Extension,Abduction,Rotation
Explanation:
The heart of this instrument is a spherical glass bulb in which air is evacuated and a very small amount of helium gas is inserted. We heat a very fine wire inside, called filament F, by passing an electric current through it (a voltage of 6.3 volts for the required current is applied). As the filament’s temperature increases, it glows, and electrons are released from its surface with almost zero energy. We apply a high voltage V (150-300 volts) to 2 parallel plates in the small region where electrons are released. The potential energy of the electrons (charge e) in this potential ∆V is equal to eV which provides the kinetic energy for the electrons to move with a velocity v from the negative side to the positive side of the parallel plates’ configuration. A magnetic field B perpendicular to electron velocity vector is present and it acts on the electrons. The magnetic field experienced by the electrons is parallel to the axis of two coils and its strength is proportional to the current in the coils. As electrons move, they collide with helium gas atoms inside the bulb and cause the gas to glow, making their path visible.
l) Draw a sketch of the demo apparatus (i.e. a large bulb, the stream of electrons, and the external magnetic field. See Figures 6 and 7 to see how to represent magnetic fields graphically). Don’t forget to explain the direction of field using the Right Hand Rule
m) Draw a Force Diagram for a single electron at multiple points on its trajectory. (see figure 3 )
n) Using the demo explain, what is the relationship among the direction of magnetic field, velocity of the particle, and magnetic force? o) Explain why applying a larger field decreases the radius of the circle. Consider that a force causing circular motion has the magnitude given by Fc = m and for the magnetic force we have R v 2 FB=qvB. (Hint: since the FB is causing circular motion, Fc=FB )
p) The sun emits many charged particles that we call the solar wind. Using this demo, explain how the magnetic field of Earth keeps us from getting hit by these charged particles.
Answers
l) Here is a sketch of the demo apparatus:
yaml
Copy code
| | Magnetic field: B
| | (into the page)
| | | | |
____|_F___|______ | | |
| \ / | | | |
Filament F| X | | Bulb | Parallel | Magnetic
|_____/ \_______| | | plates | field
| | | | |
| | | | |
| | |________________|____________|
The direction of the magnetic field is on the page, which is represented by the circle with a dot in the center. We can determine the direction of the magnetic field using the Right Hand Rule, where we point our right thumb in the direction of the current in the coils, and our fingers curl in the direction of the magnetic field.
m) Here is a force diagram for a single electron at multiple points on its trajectory:
markdown
Copy code
v
|\
| \
| \ Fb
| \
| \
------
B
where v is the velocity of the electron, Fb is the magnetic force acting on the electron, and B is the magnetic field. The direction of the magnetic force is perpendicular to both the magnetic field and the velocity of the electron and is given by the Right Hand Rule.
n) The direction of the magnetic force on a charged particle is perpendicular to both the magnetic field and the velocity of the particle. The magnitude of the magnetic force is proportional to the strength of the magnetic field and the speed of the particle.
o) Applying a larger magnetic field decreases the radius of the circle because the magnetic force is what causes the circular motion of the electrons. The magnitude of the magnetic force is given by Fb = qvB, where q is the charge of the electron, v is the velocity of the electron, and B is the magnetic field. Since the magnetic force is responsible for the circular motion, it is equal to the centripetal force, which is given by Fc = mv^2/R, where m is the mass of the electron and R is the radius of the circle. Setting Fb equal to Fc and solving for R, we get:
R = mv / (qB)
Therefore, a larger magnetic field will result in a smaller radius of the circular path.
p) The magnetic field of the Earth acts as a shield to protect us from the solar wind, which consists of charged particles emitted by the sun. The magnetic field of the Earth deflects these charged particles, causing them to follow the Earth's magnetic field lines and preventing them from directly hitting the Earth's surface. This is similar to how the magnetic field in the demo apparatus deflects the electrons, causing them to follow a circular path instead of continuing straight through the bulb.
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A force of 5 N accelerates an object. The object's mass is 50 g. What is the acceleration of the object? (Formula: F=ma) 0. 01 m/s2 0. 1 m/s2 10 m/s2 100 m/s2.
Answers
Answer:
it's 100m/s2
Explanation:
a=f/m
or,a=5/50/1000. (mass si unit is kg and 1kg=1000g
or,a=5/0.005
or,a=100m/s2
what is the capacitance of two square parallel plates 6.7 cm on a side that are separated by 1.8 mm of paraffin? the dielectric constant of paraffin is 2.2.
Answers
The capacitance of two square parallel plates will be 1.777 farads.
What is the capacitance of two parallel plates?The body's capacity to hold electric charge is constrained by capacitance. There is a capacitance for each capacitor. Two metallic sheets of area A, spaced by d, make up the standard parallel-plate capacitor.
The parallel plate capacitor formula is given by:
C = ε Ad
Two square parallel plates 6.7 cm on a side are separated by 1.8 mm of paraffin. The dielectric constant of paraffin is 2.2. Then the capacitance of two square parallel plates will be given as,
C = ε Ad
C = 2.2 x 0.67 x 0.67 x 1.8
C = 1.777 farad
Two parallel square plates will have a capacitance of 1.777 farads.
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when kayla stands on her trampoline, it sags by 0.20 m . now she starts bouncing. part a how much time elapses between the instant when she first lands on the trampoline's surface and when she passes the same point on the way up?
Answers
The time that elapses between Kayla first landing on the trampoline and passing the same point on the way up is 0.28 seconds.
To find this, we can use the equation for free fall: y = 0.5 * g * t^2, where y is the displacement, g is the acceleration due to gravity (9.81 m/s^2), and t is the time elapsed.
First, rearrange the equation to solve for t: t = sqrt(2 * y / g). Now, plug in the displacement (0.20 m) and the acceleration due to gravity (9.81 m/s^2): t = sqrt(2 * 0.20 / 9.81) ≈ 0.20 seconds.
Since Kayla's motion consists of both falling and bouncing back up, we need to double this time: 0.20 * 2 = 0.40 seconds.
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What is the tidal volume, and
what is their inspiratory capacity?
6 5 4 43 3.6 Volume (1) 3 2 1 0 0 B A m C 5 10 D 15 Time (s) ← IE 20 25 F F LL 30
Answers
Tidal volume is the volume of air inspired or expired during normal respiration. The tidal volume is typically about 500 milliliters during resting breathing, and it can increase to more than 3,000 milliliters during exercise.
The inspiratory capacity is the maximum amount of air that can be inhaled following normal expiration.Tidal volume is the volume of air that moves in and out of the lungs with each breath. It is an essential component of the pulmonary system, and it is used to measure the lung's capacity. Tidal volume can be calculated by dividing the total volume of air moved in and out of the lungs by the total number of breaths taken.
The inspiratory capacity is the volume of air that can be inspired following a normal expiration. This is the maximum amount of air that can be inhaled, and it is used to measure the lung's overall function. The inspiratory capacity is typically measured by a spirometer, which measures the volume of air moved in and out of the lungs during breathing.The figure attached shows a graph of the volume of air breathed over time. The tidal volume is represented by the width of each breath, while the inspiratory capacity is the maximum height that each breath reaches.
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please help with this question
Answers
Answer:
This unbalanced force causes her to change in direction.
If the forces on an object are unbalanced, this is what happens:
a stationary object starts to move in the direction of the resultant force
a moving object changes speed and/or direction in the direction of the resultant force
Can some help me, please?
Answers
Answer:
1. Transform Boundary
2. Continental-continental convergent boundary
3. Oceanic-Oceanic Divergent boundary
Explanation:
a diffraction grating with 145 slits per centimeter is used to measure the wavelengths emitted by hydrogen gas. at what angles in the third-order spectrum would you expect to find the two violet lines of wavelength 434 nm and of wavelength 410 nm? (angles in radians)
Answers
The two violet lines of hydrogen gas with wavelengths 434 nm and 410 nm in the third-order spectrum of a diffraction grating with 145 slits per centimetre would be expected at angles of approximately 1.09 radians and 1.22 radians, respectively.
Diffraction gratings are used to disperse light into its constituent wavelengths and measure their spectra. The number of slits per centimetre on the grating determines the angular spacing between the diffracted wavelengths. In this case, a diffraction grating with 145 slits per centimetre is used to measure the spectrum of hydrogen gas, which emits violet lines at wavelengths 434 nm and 410 nm. The third-order spectrum corresponds to diffracted wavelengths that are three times the spacing between the slits. Using the equation for diffraction grating, the angles at which these violet lines are expected to appear in the third-order spectrum can be calculated as approximately 1.09 radians for the 434 nm line and 1.22 radians for the 410 nm line.
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NASA's Langley Research Center has been experimenting with the use of air bags to soften the landings of crew exploration vehicles (CEV) on land. What stopping time will be required in order to safely stop a 7250 kg CEV moving at 7.65 m/s with an average force of 426000 N (an average force of 6 G's)
Answers
The stopping time will be 0.13 second required in order to safely stop a CEV .
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
The average force acting on CEV is = 426000 N.
Mass of the CEV is = 7250 kg.
Initial speed of the CEV is = 7.65 m/s
Hence, deceleration of the CEV is = ( 426000 N ÷ 7250 kg) = 58.75 m/s²
Hence, required stopping time = 7.65 m/s ÷ 58.75 m/s² = 0.13 second.
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If we apply a potential difference of 4. 50 v between the ends of a wire that is 2. 50 m in length and 0. 654 mm in radius, the resulting current through the wire is 17. 6 a. What is the resistivity of the wire material?.
Answers
According to the resistance, the resistivity of wire material is 1.37 x 10¯⁷ Ωm.
We need to know about the resistance of conductive material to solve this problem. Resistance can be defined as the ratio of the voltage applied to current flow It can be written as
R = V / I
where R is resistance, V is voltage and I is current.
The resistance of the material depends on its resistivity and follows this equation
R = ρ . L / A
where ρ is resistivity, L is the length of the material and A is the surface.
From the question above, we know that
V = 4.5 V
L = 2.5 m
r = 0.654 mm = 6.54 x 10¯⁴ m
I = 17.6 A
Find the surface area
A = π . r²
A = π . ( 6.54 x 10¯⁴ )²
A = 1.34 x 10¯⁶ m²
Find the resistivity of the wire
R = V / I
ρ . 2.5 / (1.34 x 10¯⁶)= 4.5 / 17.6
ρ = 1.37 x 10¯⁷ Ωm
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Which of the following is an example of a primary source?
Answers
Answer:
An article written by a scientist .
Explanation:
Primary sources information are those that contain first hand information probably from the place of the activities or by the original contact of the information (source ) .
So primary information is normally contained in artifact , journals , letter , dissertations manuscripts , videos and audio recordings .
The fact that the article is written by the scientist means he is the one who has the original information hence he is the first person to access the information , meaning he is the original owner .
Kate is pulling her doll in a wagon. Which arrow shows us the force of Kate pulling the wagon?
Answers
Answer:
3
Explanation:
Trust me its the right answer
s=1/2(u+v)t check the dimensional consistency for this? where s is displacement, t is time, u is initial velocity, v is final velocity.
Answers
Answer:
See the explanation below.
Explanation:
The units of work are consistent since if we work in the international system of measures we have the following dimensional quantities for velocity, distance and time.
s = displacement [m]
v and u = velocity [m/s]
t = time [s]
Now using these units in the given equation.
\(s = 0.5*([m/s]+[m/s])*[s]\\s=0.5*[m/s]*[s]\\s = 0.5*[m]\)
So the expression is good, and dimensional has consistency.
after it i releaed, the electric field intantaneouly change to a contant, uniform electric field 2
pointing due outh. 8.49
after the field change, the proton ha returned to it tarting point. What i the ratio of the magnitude of 2
to the magnitude of 1?
You may neglect the effect of gravity on the proton.
Answers
The ratio of magnitude 2 to magnitude 1 after the electric field change when the proton returned to its starting point.is 1:1
The protons are ejected into an electric field pointing due north, and after 2 seconds the electric field changes to a constant uniform electric field pointing due south. 8.49 seconds after the field change, the proton returned to its starting point.
The protons were initially stationary and accelerated by the electric field. A proton's acceleration is directly proportional to its electric field and inversely proportional to its mass.
Two oppositely directed fields act on the protons, implying a net acceleration of zero. Therefore, the ratio of the magnitude of electric field 2 to the magnitude of electric field 1 is 1:1.
The ratio of magnitude 2 to magnitude 1 is 1:1
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A car is traveling at 15. 5 m/s, and the driver sees a traffic light turn red. After 0. 321 s (the reaction time), the driver applies the brakes, and the car decelerates at 6. 2 m/s2. What is the stopping distance of the car, as measured from the point where the driver first sees the red light?
Answers
Stopping distance of the car, as measured from the point where the driver first sees the red light, is 43.95 meters We can use distance-time formula.
To calculate the stopping distance of the car, we need to determine the distance traveled during the driver's reaction time and the distance traveled while the car is decelerating.
During the driver's reaction time, the car will continue to move forward at its initial speed of 15.5 m/s. The distance traveled during this time is:
\(d_reaction = v_initial * t_reaction = 15.5 m/s * 0.321 s = 4.98 m\)
After the driver reacts, the car begins to decelerate at a rate of \(6.2 m/s^2\). Use equation:
d =\(v_initial * t + (1/2) * a * t^2\)
where d: distance traveled, v_initial: initial velocity, t: time, a: acceleration, and final velocity = 0 (since car stops).
We need to find the distance traveled during the deceleration period, so we can rearrange the equation to solve for d:
d = \((v_initial^2) / (2a)\)
Put values:
\(d_deceleration = (15.5 m/s)^2 / (2 * -6.2 m/s^2) = 38.97 m\)
Note that we used a negative value for acceleration, since the car is decelerating (slowing down) rather than accelerating (speeding up).
The total stopping distance is the sum of the distance traveled during the driver's reaction time and the distance traveled while decelerating:
\(d_total = d_reaction + d_deceleration = 4.98 m + 38.97 m = 43.95 m\)
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There are _____ microns in 1 mm Hg.
Answers
There are 133.322 microns in 1 mm Hg.
The term "mm Hg" refers to millimeters of mercury, which is a unit of pressure. A micron, on the other hand, is a unit of length equal to one millionth of a meter. The relationship between these two units is based on the physical properties of mercury, which is used as a reference fluid in many pressure measurements.
One millimeter of mercury is equal to 133.322 microns, so there are 133.322 microns in 1 mm Hg. This conversion factor is commonly used in the fields of medicine and engineering to convert between pressure and length units.
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The hyper-loop is a proposed concept that involves a train traveling at 360 meters per second. How long does it take to travel one mile?
Answers
Answer:
t = 4.47 seconds
Explanation:
Given that,
Speed of a train, v = 360 m/s
We need to find the time taken by the train to cover 1 mile. For this first we must know 1 mile equal to how many meters.
1 mile = 1609.34 m
Let t is time.
Speed = distance/time
\(t=\dfrac{d}{v}\\\\t=\dfrac{1609.34\ m}{360\ m/s}\\\\t=4.47\ s\)
So, it will take 4.47 seconds to travel one mile.
two long ideal solenoids (with radii 20 mm and 30 mm respectively) have the same number of tunrs of wire per unit length. the smaller solenoid is mounted inside the larger, along a common axis. it is observed that there is zero magnetic field within the inner solenoid. the current in the inner solenoid must be
Answers
The fact that there is zero magnetic field within the inner solenoid implies that the magnetic field generated by the larger solenoid cancels out the magnetic field generated by the smaller solenoid at its center. This means that the current flowing through the inner solenoid must be equal and opposite in direction to the current flowing through the outer solenoid.
We know that the magnetic field inside a solenoid is directly proportional to the current flowing through it, and inversely proportional to its radius. Since the two solenoids have the same number of turns of wire per unit length, their magnetic fields at a given distance from their centers will be proportional to their radii. Therefore, we can conclude that the current flowing through the inner solenoid must be less than the current flowing through the outer solenoid, since its radius is smaller.
To determine the exact ratio of the currents, we can use the fact that the magnetic field at the center of a solenoid is proportional to the product of its current and the number of turns of wire per unit length. Equating the magnetic fields of the two solenoids at the center of the inner solenoid, we can solve for the ratio of the currents. This gives us the exact value of the current in the inner solenoid that is required to cancel out the magnetic field of the outer solenoid at its center.
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How much would a 70 kg student weigh on Pluto? (massPluto = 1.25 x 1022 kg, radiusPluto = 1.20 x 106 m)
Answers
Answer: the weight would be 4.6 (I think i don’t know))
Explanation: