What are [H3O+] and [OH-] in solutions with the following pH? (a) pH = 2.85 (b) pH = 9.40

1. C. Gravity is a force that acts as an inversely proportional square law with respect to distance.

2. B. Type Ia supernovae

3. D. Downwards; towards the center of the Sun

The interpretation of the equations and the correct options for the given questions are as follows:

Question 1:

The equation interpretation is related to gravity. The equation states a relationship between gravity and distance. The correct option is:

C. Gravity is a force that acts as an inversely proportional square law with respect to distance.

Question 2:

To test how the constant G (gravitational constant) has changed over the evolution of the Universe, certain phenomena or objects are used. The correct option is:

B. Type Ia supernovae

Question 3:

Based on the excerpt, the direction of gravity from the Sun is described. The correct option is:

D. Downwards; towards the center of the Sun

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Answer:

6600

Step-by-step explanation:

6600

Answer: $52.75

Step-by-step explanation:

\(\qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{current amount}\dotfill & \$10000\\ P=\textit{initial amount}\dotfill &15000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\\ \end{cases}\)

\(10000=15000(1 - 0.04)^{t} \implies \cfrac{10000}{15000}=(1 - 0.04)^{t}\implies \cfrac{2}{3}=0.96^t \\\\\\ \log\left( \cfrac{2}{3} \right)=\log(0.96^t)\implies \log\left( \cfrac{2}{3} \right)=t\log(0.96) \\\\\\ \cfrac{\log\left( \frac{2}{3} \right)}{\log(0.96)}=t\implies 9.93\approx t\qquad \textit{about 9 years and 11 months}\)

Answer:

164 because it is the pythagorean triple 9, 40, 41 magnified by a factor of 4

Hope this helped and brainliest please

Answer:

D. 164

Step-by-step explanation:

\(\sqrt{36^{2} +160^{2} } \\=\sqrt{1296 + 25600} \\= \sqrt{26896} \\= 164\)

Answer:

2.6 kilometers

Step-by-step explanation:

To find the circumference of a circle, we can use the formula:

Circumference = π * diameter

Given that the diameter of the volcanic crater is 840 meters, we can substitute this value into the formula:

Circumference = π * 840

Using the approximate value of π as 3.14159, we can calculate the circumference:

Circumference = 3.14159 * 840

Circumference ≈ 2643.1796 meters

To convert the circumference to kilometers, we divide the value by 1000:

Circumference in kilometers = 2643.1796 / 1000

Circumference ≈ 2.6432 kilometers

Therefore, the circumference of the rim of the volcanic crater is approximately 2.6 kilometers (rounded to 1 decimal place).

The central angle of a circle when you know the radius and arc length, you can use the formula:

Central angle (in radians) = Arc length / Radius

To find the central angle of a circle when you know the radius and arc length, you can use the formula:

Central angle (in radians) = Arc length / Radius

If you want the central angle in degrees, you can convert it using the fact that there are 2π radians in a full circle (360 degrees):

Central angle (in degrees) = (Arc length / Radius) * (180 / π)

Make sure to use consistent units for the arc length and radius, such as meters or centimeters, to obtain accurate results.

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There is no specific number pattern for the sequence { 6, 1, 8,4, 2, 7} but to determine the next term of sequence we can use the following patterns

1) for even place terms pattern is

aₙ = aₙ₋₂ + 3.

2) for odd place terms pattern is first aₙ

= aₙ₋₂ + 2 and for next aₙ₊₂ = aₙ - 6, where n is odd number.

A pattern is a series or sequence of repetitions. A number pattern is a series of numbers that follow a specific order in mathematics. Patterns usually describe inverse relationships between numbers.

A sequence of numbers can also be called a pattern. The types of number patterns are classified as

We need to write a pattern for 6, 1, 8, 4, 2, 7. Now the sequence is 6, 1, 8, 4, 2, 7,

First term = 6

Second term = 1

Break this sequence down into odd and even terms or enteries. The order of odd entries is 6,8,2,.. So the pattern here is 2 and -6, i.e. 7ᵗʰ entry = 2 + 2 = 4 and 9ᵗʰ entry = 4+ 6 = 10 and so on. Now for Evan's bit term, 1,4,7,.. The pattern here is aₙ = aₙ₋₂ + 3. where n is an even number. So the entire sequence has no pattern, but the odd and even elements can be determined by different patterns.

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Answer:

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

3

2

+

6

+

1

8

=

0

3x^{2}+6x+18=0

3x2+6x+18=0

=

3

a={\color{#c92786}{3}}

a=3

=

6

b={\color{#e8710a}{6}}

b=6

=

1

8

c={\color{#129eaf}{18}}

c=18

=

−

6

±

6

2

−

4

⋅

3

⋅

1

8

√

2

⋅

3

x=\frac{-{\color{#e8710a}{6}} \pm \sqrt{{\color{#e8710a}{6}}^{2}-4 \cdot {\color{#c92786}{3}} \cdot {\color{#129eaf}{18}}}}{2 \cdot {\color{#c92786}{3}}}

x=2⋅3−6±62−4⋅3⋅18

2

Simplify

Answer:

x=-1+or-i radical 5

Step-by-step explanation:

The two vectors are linearly independent because their dot product is 0.

Answer:Without calculation, the eigenvalue of A = [2 2 2; 2 2 2; 1 1 0] and two linearly independent eigenvectors are: The eigenvalue of A is 0 because the columns of A are linearly dependent.Two linearly independent eigenvectors of A are:1 1 -21 -1 20 The eigenvector corresponding to the eigenvalue λ = 0 is the nullspace of A, since A(0) = 0.The null space of A is given by the solution set of the system Ax = 0,

which yields:x1 = -x2x3 = 0 The solution set is a line passing through the origin spanned by the vector x = [1, -1, 0]T, which is one eigenvector.The other eigenvector can be chosen to be orthogonal to x, which can be achieved by choosing x = [1, 1, -2]T / sqrt (6). The two vectors are linearly independent because their dot product is 0.

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a) The probability of waiting more than 10 minutes for a cab is 0.303 or approximately 30.3%.

b) The probability of waiting fewer than 20 minutes for a cab is 0.726 or approximately 72.6%.

b) The mean number of cabs per hour that we need to have a probability of waiting more than 10 minutes for a cab of 0.1 is 7.88.

(a) The probability of waiting more than 10 minutes for a cab can be calculated using the Poisson distribution formula. Let's denote the average rate of cabs passing by as λ. Since the mean is given as five cabs per hour, we can set λ = 5. We need to find the probability of waiting more than 10 minutes, which is equivalent to waiting for 1/6 of an hour. We can use the Poisson distribution formula to calculate this probability:

P(X > 0.1667) = 1 - P(X ≤ 0.1667) = 1 -\(e^{-\lambda t}\)Σ(k=0 to ⌊λt⌋) (λt)ˣ / k!

where X is the number of cabs passing by in 1/6 of an hour, t = 1/6, λ = 5, and ⌊λt⌋ denotes the floor function of λt. Plugging in the values, we get:

P(X > 0.1667) = 1 - P(X ≤ 0.1667) = 1 - \(e^{-5(1/6)}\)Σ(k=0 to ⌊5(1/6)⌋) (5(1/6))ˣ / k!

= 1 - \(e^{-0.833}\)Σ(k=0 to 0) (0.833)ˣ / k!

= 0.303

(b) The probability of waiting fewer than 20 minutes for a cab can also be calculated using the Poisson distribution formula. We need to find the probability of waiting for 1/3 of an hour since 20 minutes is equivalent to 1/3 of an hour. Using the same formula as above, we get:

P(X ≤ 0.333) = \(e^{5(1/3)}\)Σ(k=0 to ⌊5(1/3)⌋) (5(1/3))ˣ / k!

= 0.726

(c) Finally, to find the mean number of cabs per hour so that the probability of waiting more than 10 minutes is 0.1, we need to solve for λ in the Poisson distribution formula:

P(X > 0.1667) = 1 - \(e^{-\lambda(1/6)}\)Σ(k=0 to ⌊λ(1/6)⌋) (λ(1/6))ˣ / x! = 0.1

Using trial and error or a numerical solver, we can find that the value of λ that satisfies this equation is approximately 7.88.

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The second derivative of v with respect to t, denoted as d²v/dt², is equal to 4

The second derivative of v with respect to t, we will differentiate v twice.

v = 2t² + 7t + 11

First, let's find the first derivative of v with respect to t (dv/dt):

dv/dt = d/dt (2t² + 7t + 11)

Using the power rule of differentiation, we differentiate each term separately:

dv/dt = 2(2t) + 7(1) + 0

dv/dt = 4t + 7

Now, let's find the second derivative of v with respect to t (d²v/dt²):

d²v/dt² = d/dt (4t + 7)

Again, using the power rule of differentiation, we differentiate each term separately:

d²v/dt² = 4(1) + 0

d²v/dt² = 4

Therefore, the second derivative of v with respect to t, denoted as d²v/dt², is equal to 4.

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Answer:

Step-by-step explanation:

Please see diagram attached.

Moon A and C are 100,000km + 10,000 = 110,000km from center of planet.

So they are 110,000 + 110,000 = 220,000km apart.

Answer:

Step-by-step explanation:

AC is 220000km according to the drawing:

Answer:

1. Yes and for 2. I don't know

Step-by-step explanation:

1. is a monomial because 21/27 is one group

To calculate a three-month moving average for monthly forecasting, you need to follow these steps: Gather the historical data, Determine the time period, Calculate the moving average, Repeat the process.

Gather the historical data: Collect the monthly data for the specific variable you want to forecast. For example, if you want to forecast sales, gather the sales data for the past several months.

Determine the time period: Decide on the time period for your moving average. In this case, it is three months.

Calculate the moving average: Add up the values for the variable you are analyzing over the past three months and divide the sum by three to get the average. This will be your moving average value for the third month.

Repeat the process: Shift the time period by one month and calculate the moving average for the new three-month period. Continue this process for each subsequent month, updating the time period and calculating the moving average accordingly.

For example, let's say you have the following sales data for the past six months:

Month 1: 100 units

Month 2: 120 units

Month 3: 110 units

Month 4: 130 units

Month 5: 140 units

Month 6: 150 units

To calculate the three-month moving average for Month 4, you would add up the sales values for Month 2, Month 3, and Month 4 (120 + 110 + 130 = 360) and divide it by three to get an average of 120 units. Repeat this process for each subsequent month to obtain the moving average values for your forecast.

Note that the number of data points you include in the moving average calculation and the frequency of the data (monthly in this case) can be adjusted based on your specific needs and the nature of the data.

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Electric field due to Q1 is 27/10 N/C, electric field due to Q2 is -54/10 N/C and electric field at A due to Q1 is 2.32454 N/C.

Given,

Q1 = 3nCQ2

     = -6nC

The distance between them is 0.1 m. (10^2m)

The electric field due to a charge is given by κQ/r^2

Where Q is the charge,

            r is the distance,

            and κ is a constant.κ = 9 x 10^9 Nm^2/C^2

Electric field due to Q1 =κQ1/r^2

                                       =9 x 10^9 x 3 x 10^-9/ (0.1)^2

                                       = 27/10 N/C

At point A due to E1 = Electric field at point A due to Q1 = E1x i + E1y j + E1z k.

Since the point A is (-0.07, -0.04, 0), so we have to calculate the electric field at point A due to Q1 on the x-axis, y-axis and z-axis respectively.

Therefore, E1x = E1cosθ, E1y = E1sinθ, E1z = 0

Where θ is the angle that E1 makes with the x-axis.

Tanθ= 0.04/0.07

        = 0.5714θ

        = 30.9638°

Now, E1x = E1cosθ

                = 27/10 x cos30.9638°

                = 23.2454/10 N/C

And E1y = E1sinθ

               = 27/10 x sin30.9638°

               = 13.3935/10 N/C

So, E1 = E1x i + E1y j + E1z k

           = 23.2454/10 i + 13.3935/10 j + 0 k

           = (2.32454, 1.33935, 0) N/C, at point A due to Q1.

Electric field due to Q2 = κQ2/r^2

                                       = 9 x 10^9 x (-6 x 10^-9)/ (0.1)^2

                                       = -54/10 N/C, at point A due to Q2.

E2 = Electric field at point A due to Q2= E2x i + E2y j + E2z k

Since the point A is (-0.07, -0.04, 0), so we have to calculate the electric field at point A due to Q2 on the x-axis, y-axis and z-axis respectively.

Therefore, E2x = E2cosθ, E2y = E2sinθ, E2z = 0

Where θ is the angle that E2 makes with the x-axis.

Tanθ = 0.04/0.07

         = 0.5714θ

         = 30.9638°

Now, E2x = E2cosθ

                = -54/10 x cos30.9638°

                = -46.491/10 N/C

And E2y = E2sinθ

               = -54/10 x sin30.9638°

               = -26.7872/10 N/C

So, E2 = E2x i + E2y j + E2z k

            = -46.491/10 i - 26.7872/10 j + 0 k

            = (-4.6491, -2.67872, 0) N/C, at point A due to Q2.

Net Electric field at point A,En→1 = E1+E2

                                                      = (2.32454, 1.33935, 0) + (-4.6491, -2.67872, 0)

                                                      = (-2.32456, -1.33937, 0) N/C, at point A.

The electric field at A due to Q1 is 2.32454 N/C.

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Answer:

Let x = Kilometers  by bus  

then x + (x + 350) = 1100

2x = 750

x = 375 by bus

x - 350 + x = 1100

2x = 1450

x = 725 by train

i hope this helps a little bit

Answer:

4.5

Step-by-step explanation:

9/2 = 4.5

Answer:

v-42ryoggjihfjcfjbfj

Answer:

he value of the integral ∫ y tan(x) dx is y sin(x) + C.

Step-by-step explanation:

Property 8 of integrals states that if we have an integral of the form ∫ f(x) g'(x) dx, it can be rewritten as ∫ f(x) dg(x), where g(x) is an antiderivative of g'(x).

In this case, we have the integral ∫ y tan(x) dx. By applying Property 8, we can rewrite it as ∫ y d(sin(x)).

Now, integrating with respect to y while treating sin(x) as a constant, we get:

∫ y d(sin(x)) = y sin(x) + C,

where C is the constant of integration.

So, using Property 8, the value of the integral ∫ y tan(x) dx is y sin(x) + C.

Answer: You don't have enough information to complete the problem.

You don't know what y is.

Step-by-step explanation:

When the circle is rotated  around the horizontal dashed line, the resultant figure is a sphere.

A circle is a round figure. The sum of angles in a circle is 360 degrees. The circle could be rotated to yield another figure.

Thus, when a circle such as the one here is rotated  around the horizontal dashed line, the resultant figure is a sphere.

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Answer:

Sphere

Step-by-step explanation:

I got it right on Edmentum

Hook me up with a 5 star and a thanks :)

Step-by-step explanation:

Area squares the unit of length. in this case, none of these are area

(By the way is this question tagged with a picture)

Answer:

C

Step-by-step explanation:

Answer:

Answer is D.1:3

Step-by-step explanation:

I hope it's helpful!

The number of subjects that Paige would study D. 2 subjects.

It should be noted that Paige would study for one hour. She spends 1/2 an hour, or 30 minutes, on a subject.

An hour is 60 minutes. If Paige studied 2 subjects, then she would of studied for 60 minutes.

30 + 30 = 60

So, if Paige spends 1/2 hour on Spanish, she would study 2 subjects to reach an hour.

Therefore, the correct option is D.

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Complete question

Paige spends 1 hour on her homework. She spends equal amounts of time on all subjects. If Paige spends 1/2 hour on Spanish, how many subjects does she study?

3 subjects

1 subject

4 subjects

2 subjects

The number of solutions to x₀ + x₁ + ... + \(x_{k}\) = n with each value of x to be a non-negative integer xₐ is (n +  k).

Solved using the technique of stars and bars, also known as balls and urns.

Imagine you have n identical balls and k+1 distinct urns.

Distribute the balls among the urns such that each urn has at least one ball.

First distribute one ball to each urn, leaving you with n - (k+1) balls to distribute.

Then use k bars to separate the balls into k+1 groups, with the number of balls in each group corresponding to the value of xₐ.

For example, if the first k bars separate x₀ balls from x₁ balls, the second k bars separate x₁ balls from x₂ balls, and so on, with the last k bars separating \(x_{k-1}\) balls from \(x_{k}\) balls.

The number of ways to arrange n balls and k bars is (n + k) choose k, or (n +k) choose n.

This is the number of solutions to x₀ + x₁ + ... + \(x_{k}\) = n, where each xₐ is a non-negative integer.

Therefore, the number of solutions to x₀ + x₁ + ... + \(x_{k}\) = n with non-negative integer xₐ is (n +  k).

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50

Step-by-step solution:

    0.3x-42=0.1x-32

    -0.1x

    0.2x-42=-32

                   +42

      0.2x=10

               0.2                

        x=50

For every inch in the scale drawing, it represents 60 inches in the actual gym.

To determine the scale Jorge used to create the scale drawing of the school gym, we can calculate the ratio of the length in the scale drawing to the length of the actual gym.

In the scale drawing, the length of the gym is 17 inches, while the length of the actual gym is 85 feet.

Since there are 12 inches in a foot, we can convert the length of the actual gym from feet to inches:

85 feet * 12 inches/foot = 1020 inches

Now, we can calculate the scale by dividing the length in the scale drawing by the length of the actual gym:

17 inches / 1020 inches = 1/60

Therefore, the scale that Jorge used to create the scale drawing of the school gym is 1:60.

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