What accurately depicts the change in average kinetic energy of the particles undergoes in matter as the temperature of the sample is decreased?

Answer:

a) 0.47MW

b) 39.24%

Explanation:

In order to find the power needed for the elevator to operate at its maximum capacity, we can make use of the following formula:

P=Fv

where P is the power, F is the force and v is the velocity.

The force the elevator must carry can be calculated with the following formula:

F=mg

where m is the mass of the elevator and g is the acceleration of gravity, so:

\(F=(8000 kg)(9.81 m/s^{2})\)

F=78 480 N

so now we can make use of the power formula:

P=Fv

P=(78 480N)(6 m/s)

P=470 880W

P=0.47W

b)

In order to find the efficiency, we will suppose that the generator can generate a maximum of 0.47 W so we use the following formula:

\(efficiency = \frac{P_{in}}{P_{out}}*100\%\)

\(efficiency=\frac{0.470880}{1.2}*100\%\)

efficiency=39.24%

When two magnets are close to each other, the magnets experience a repulsive or attractive force. The magnetic field strength is affected by the orientation of the magnet.

The direction in which the bar magnet obtains its maximum magnetic property is called the orientation of the magnet. The magnetic field strength depends on the orientation of the magnet.

The magnetic field lines emerge from the north pole and end in the south pole. When the two bar magnets of opposite poles face each other, an attractive force will be produced and magnetic field strength increases.

When the bar magnet of the same poles faces each other, repulsive force will produce and magnetic field strength decreases. Hence from the orientation of the bar magnet,  the magnetic field strength gets affected.

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When an object is traveling at a constant speed, the acceleration is 0 m/s².

If an object covers an equal amount of distance in equal interval of time, then the body is said to be moving at a constant speed.

F - ff = ma

where;

During constant speed, acceleration = 0

Thus, when an object is traveling at a constant speed, the acceleration is 0 m/s².

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The time taken for the cannonball to move upward before stopping, given that is was fired directly upward at 300 m/s is 30.6 seconds

Velocity and time are related according to the following equation of motion

v = u + gt

Where

From the question given above, the following data were obtained:

The time taken for the cannonball to move upward before stopping can be obtained as illustrated below:

v = u - gt (since the ball is going against gravity)

0 = 300 - (9.8 × t)

0 = 300 - 9.8t

Collect like terms

-9.8t = 0 - 300

-9.8t = -300

Divide both sides by -9.8

t = -300 / -9.8

t = 30.6 seconds

Thus, the time taken is 30.6 seconds

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(a) A 1 000 kg car is pulling a 300 kg trailer, together the car and trailer move forward with an acceleration of 2. 15 m/s² the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

To determine the net force on the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

The total mass of the car and trailer combined is the sum of their individual masses: 1,000 kg + 300 kg = 1,300 kg.

The acceleration of the car and trailer system is given as 2.15 m/s².

Using Newton's second law:

Net force = mass × acceleration

Net force = 1,300 kg × 2.15 m/s²

Net force ≈ 2,795 N

Therefore, the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

This net force is responsible for accelerating the combined mass of the car and trailer in the forward direction. It represents the sum of all external forces acting on the system, such as the force exerted by the car's engine and the tension in the connection between the car and trailer.

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The statements that apply are;

We know that the pressure can be taken as the force with which the molecules of the substance are able to hit the walls of the container in this case, we need to obtain the  pressure of the ethanol vapor when the volume has been reduced.

Using

P1 = initial pressure

P2 = final pressure

V 1 = initial volume

V2 = final volume

By the use of the Boyle's law we have;

P1V1 = P2V2

P2 = P1V1 /V2

P2 = 67.0 * 529/344

P2 = 103 mmHg

Thus, as the volume is reduced there would be an increase in the pressure and some of the ethanol would condense and we would have liquid ethanol in the system.

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The force and acceleration alter as the object moves away from its equilibrium position.

The force on the object at any point is given by Hooke's Law:

F = -kx

where F = force, k = force constant of the spring, and x = displacement of the object from its equilibrium position.

The acceleration of the object at any point is given by Newton's Second Law:

a = F/m

where a = acceleration, F = force, and m = mass of the object.

Using these equations, calculate the force and acceleration at each of the specified points:

At x = 0.100 m:

F = -kx = -(1.30 x 10 N/m)(0.100 m) = -0.130 N

a = F/m = (-0.130 N)/(0.350 kg) = -0.371 m/s² (the negative sign indicates that the acceleration is in the opposite direction to the displacement)

At x = 0:

F = -kx = -(1.30 x 10 N/m)(0) = 0 N (the spring is at its equilibrium position)

a = F/m = 0 N/0.350 kg = 0 m/s²

At x = -0.0500 m:

F = -kx = -(1.30 x 10 N/m)(-0.0500 m) = 0.065 N (note that the force is positive because the displacement is negative)

a = F/m = (0.065 N)/(0.350 kg) = 0.186 m/s²

At x = -0.100 m:

F = -kx = -(1.30 x 10 N/m)(-0.100 m) = 0.130 N

a = F/m = (0.130 N)/(0.350 kg) = 0.371 m/s²

So, the force and acceleration change with the displacement of the object from its equilibrium position.

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Answer: A

Explanation:

To make two hexagons out of pattern blocks, you need 12 trapezoids.

A closed, two-dimensional polygon containing six sides is what is known as a hexagon. Six vertices and six angles make up a hexagon.

Thus,

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Answer:

Explanation:

2^5=32-20=-12 meters per sec (going backwards).

If this is correct pls mark me. brainly to let me know, tyy C:

Answer: B

Explanation: ik trust me its right :)

Answer:

B)  5 gm

Explanation:

.5 g / cm^3   * 10 cm^3  =  5 gm     ( see how the 'cm^3' cancels out?)

Three facts I have learned this year in Physical Education are:

a) The importance of stretching before and after exercising.

b) The benefits of cardiovascular exercise.

c) The importance of staying hydrated during exercise.

Firstly, I have learned the importance of stretching before and after exercising. Stretching helps prevent injury and improves flexibility. I will make sure to incorporate stretching into my daily routine, whether it's through a short stretching session in the morning or by taking a few minutes to stretch before and after a workout.
Secondly, I have learned the benefits of cardiovascular exercise. Cardiovascular exercise, such as running or cycling, helps improve heart health and endurance. I will try to incorporate more cardiovascular exercise into my daily routine, such as going for a run or bike ride after work.
Lastly, I have learned the importance of staying hydrated during exercise. Dehydration can lead to fatigue and muscle cramps, so it's important to drink plenty of water before, during, and after exercise. I will make sure to carry a water bottle with me throughout the day and refill it regularly to ensure that I am staying hydrated.
In summary, by incorporating stretching, cardiovascular exercise, and staying hydrated into my daily routine, I hope to improve my overall physical health and well-being.

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Answer:

Explanation: work equals force times distance so 400x4=1600 joules

Answer:  I'm not sure, but I think it would be a total lunar eclipse

When the moon passes through the penumbra of Earth’s shadow it is referred to as partial lunar eclipse. The correct option is C.

A partial lunar eclipse occurs when the moon is not completely immersed in the umbra of the earth's shadow.

During a partial solar eclipse, the Moon, Sun, and Earth do not align perfectly straight, and the Moon casts only the penumbra of its shadow on Earth. From our vantage point, it appears that the Moon has eaten the Sun.

A shadow's penumbra is the lighter outer edge. Partial solar eclipses are caused by the Moon's penumbra, while penumbral lunar eclipses are caused by the Earth's penumbra. The penumbra is a type of lighter shadow.

The Penumbra is a half-shadow region that occurs when an object only partially covers a light source.

Thus, the correct option is C.

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Answer:

AYE

Explanation:

The factors that affect the viscosity of magma include temperature, crystal and rock fragments (composition), and the different dissolved gases.

It is a mixture of solid, volatile and liquid materials.

Therefore, we can conclude that the fluidity or viscosity of magma depends on its chemical composition and, in particular, the liquids and solids that the magma contains and the various gases dissolved in it.

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Answer:

Impulse of force = 300Ns

Explanation:

Given the following data;

Mass = 25kg

Change in velocity = 12m/s

To find the impulse;

Impulse is given by the formula;

\( Impulse \; of \; force = mass * change \; in \; velocity \)

Substituting into the equation, we have;

\( Impulse \; of \; force = 25 * 12 \)

Impulse of force = 300Ns

Answer:

the answer is 2000Nm

Explanation:

wprk done = force × distance moved

w.d = 200N × 10m

w.d = 2000Nm

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Answer:

The raft could support the extra mass of 900 kg.

Explanation:

We want to calculate the extra mass the raft could support on fresh water. Let it be m kg.

For the raft to remain afloat, the gravitational force acting on the raft downward should not exceed the buoyant force acting on the raft upward.

The buoyant force acting on the raft , in accordance to Archimedes' principle is

\(F_b = m_fg\)

where mf is the mass of the fluid displaced by the raft.

Here, \(m_f =p_f V\), where \(p_f\) is the density of the freshwater, and

\(V = M/p_w\) , where M is the mass of the raft, and \(p_w\) is the density of the wood.

This buoyant force should balance the downward-acting gravitational force, thus

 \((M+m)g =p_fgM/p_w\)

Solving for m, we get

\(m = M(p_f/p_w-1)\)

Substituting the density of fresh water to 1000kg/m^3, the mass of the raft to be 2700 kg, and the density of wood to be 750 kg/m^3, we get

m = 900kg.

Thus the raft could support the extra mass of 900 kg.

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Answer:

The bag of sand

Explanation:

I think it is the bag of sand because according to the definition of impulse, impulse is the average force acting on a particule when an external force is being acted on it.

The magnitude and direction of the electric field at P 1 when t = 3.00 s and r 1  = 0.02m is 0.3 v/m (option A). The direction is anti clockwise.

The force per charge on the test charge is a straightforward way to define the size of the electric field. From its definition, the common metric units for electric field strength are derived. Electric field units would be force units divided by charge units since the definition of an electric field is a force per charge.

The magnitude of the electric field at P1 is as follows:

E1 = dΦ/dt

E (2πr1) = S dB/dt

= r1/2 (dB/dt)

= r1/2 ║6t² + 8t║

= 0.2 / 2 ║6 (3²) + 8 (3)

= 0.3 v/m

The electric field is oriented counter clockwise to the direction of the induced current in a hypothetical circular conducting loop that passes through P 1.

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Answer:

1,000,000 seconds for it to travel 1 meter

Explanation:

Answer:  think its 6.4

Explanation:

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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The height of the cliff will be equal to 5.37 meters, and the time taken to reach the ground if it is thrown straight down with the same speed will be equal to 0.50 s.

The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.

The maximum speed that can be maintained when a time period grows closer to zero is the starting speed.

As per the given information in the question,

Use the equation given below to find the vertical height of the cliff.

y = y₀ + ut + 1/2 at²

Here,

y represents final position of the object

y₀ is the initial position of the object and t is the time interval.

So,

y₀ = y -ut -1/2at²

y₀ = 0 - (8.16)(2.17) - 1/2(-9.8)(2.17)²

= -17.70 + 23.07

= 5.37 meters.

(b)

Now again rearrange the equation,

y = y₀ + ut + 1/2at² for y - y₀

Now, find the quadratic equation in time,

t = -u ± √[u² - 4(1/2a)(y₀ - y)]/2(1/2a)

Put the values in the above equation,

= -(-8.16 m/s) ± √[(-8.16)² - (-9.8)(2)(5.37)]

= [8.16 ± √(66.58 + 105.25)]/-9.8

= [8.16 ± 13.1]/-9.8

= -4.94/-9.8 = 0.50 s.

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Answer:

They all have electrical currents

Answer:

They have electronic parts and currents

Answer:

\(\boxed {\boxed {\sf 126 \ Newtons}}\)

Explanation:

According to Newton's 2nd Law of Motion, force is the product of mass and acceleration.

\(F=ma\)

The mass is 42 kilograms and the acceleration is 3 meters per square second.

\(m= 42 \ kg \\a= 3 \ m/s^2\)

Substitute the values into the formula.

\(F= 42 \ kg * 3 \ m.s^2\)

Multiply.

\(F= 126 \ kg*m/s^2\)

\(F= 126 \ N\)

The object's force is 126 Newtons.

The pressure at the upper level of a water flow into the house by means of pipe is 1081 kPa.

Calculate the cross-sectional area of the lower pipe:

A₁ = πr₁²

where:

A₁ = cross-sectional area of the lower pipe (m²)

π = mathematical constant (3.14)

r₁ = radius of the lower pipe (m)

A₁ = π(0.12 m)² = 0.0452 m²

Calculate the cross-sectional area of the upper pipe:

A₂ = πr₂²

where:

A₂ = cross-sectional area of the upper pipe (m²)

π = mathematical constant (3.14)

r₂ = radius of the upper pipe (m)

A₂ = π(0.06 m)² = 0.0113 m²

Calculate the flow rate per unit area:

q = Q/A

where:

q = flow rate per unit area (m³/s)

Q = flow rate (m³/s)

A = cross-sectional area (m²)

q = 6 m³/s / 0.0452 m² = 13.28 m²/s

Calculate the velocity of the water in the lower pipe:

v₁ = q/A₁

where:

v₁ = velocity of the water in the lower pipe (m/s)

q = flow rate per unit area (m³/s)

A₁ = cross-sectional area of the lower pipe (m²)

v₁ = 13.28 m²/s / 0.0452 m² = 29.3 m/s

Calculate the velocity of the water in the upper pipe:

v₂ = q/A₂

where:

v₂ = velocity of the water in the upper pipe (m/s)

q = flow rate per unit area (m³/s)

A₂ = cross-sectional area of the upper pipe (m²)

v₂ = 13.28 m²/s / 0.0113 m² = 117.0 m/s

Calculate the head loss:

hL = (v₁² - v2₂²) / 2g

where:

hL = head loss (m)

v₁ = velocity of the water in the lower pipe (m/s)

v₂ = velocity of the water in the upper pipe (m/s)

g = acceleration due to gravity (9.8 m/s²)

hL = (29.3 m/s)² - (117.0 m/s)² / 2(9.8 m/s²) = 23.2 m

Calculate the pressure at the upper level:

p₂ = p₁ + ρghL

where:

p₂ = pressure at the upper level (Pa)

p₁ = pressure at the lower level (Pa)

ρ = density of water (1000 kg/m³)

g = acceleration due to gravity (9.8 m/s²)

hL = head loss (m)

p₂ = 400 kPa + 1000 kg/m³(9.8 m/s²)(23.2 m) = 1081 kPa

Therefore, the pressure at the upper level is 1081 kPa.

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The time taken for the perfume to diffuse in the still air is determined as 112,500 s.

The time taken for the perfume to diffuse in the still air is calculated as follows;

t = x²/2D

where;

t = (1.5²)/(2 x 10⁻⁵)

t = 112,500 s

Thus, the time taken for the perfume to diffuse in the still air is determined as 112,500 s.

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The correct response for the number of significant digits in the following numbers, from most to least, is d>c>b=a.

The number of digits in a particular value or measurement required to determine the accuracy and precision of measurement are known as significant figures (or significant digits).They are crucial for technical or scientific measurements.Significant denotes significance. In the supplied number, they make reference to the trustworthy digits that are adequate to transmit precise information. They also aid in the rounding off of measurement readings and calculating results.The quantity of digits necessary to assess the accuracy and precision of a measurement, such as length, mass, or volume, is known as significant figures (or significant digits).

Complete question: Rank in order, from the most to the least, the number of significant figures in the following numbers. For example, ifb has more than c, c has the same number as a and a has more than d you would give your answer as b>c=a»d a) 8200 b) 00052 c) 0430 d )4321 x 10" Completed O Type here to search

a)d>c>b=a    b)a=d>c>b     c)d>c>a>b    d)b=d>c>a     e)a=b=d>c

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Answer:

T=F/A

Explanation:

T= shear stress

F=applied force

A=cross sectional area

shear stress, force tending to cause deformation of material by slippage along a plane or planes parallel to the imposed stress, the resultant shear is of a great importance in nature, being intimately related to the downslope movement of earth materials and earthquakes.