Weathering of rocks can occur in many ways. In the western United States, strong winds can erode huge rock formations by blowing millions of tiny grains of sand at these rocks. Which term accurately describes this type of weathering?

A. Thermal
B. Chemical
C. Physical
D. Meteorological

Answer:

The motorcycle and the truck both have the same kinetic energy when they are moving at the same speed of 100 km/h. This is because the kinetic energy of an object is proportional to the mass of the object and the square of its velocity.

Since both vehicles are traveling at the same speed, they have the same velocity, which means that the square of their velocities is the same. However, the truck has a much larger mass than the motorcycle, so its larger mass makes up for the smaller velocity in terms of kinetic energy.

Therefore, the kinetic energy of the motorcycle and the truck will be the same, assuming they are both traveling at the same speed of 100 km/h.

Explanation:

Answer: That is not a question.

Explanation: It is a random jumble of letters. It also has no question mark.

Answer:

Electric Fuse is based on the principle of the heating effect of Electric current.

Explanation:

The electric fuse is based on the principle of heating due to electric current. As current flows through the wire, heat is produced. As a result of excessive current flow, heat is generated, melting the Fuse, which normally has a low melting point, preventing any damage to an electric circuit and appliances. (I'm sorry if I'm wrong but I think that's it.)

Answer:

2.89 m/s²

Explanation:

From the question given above, the following data were obtained:

Radius (r) = 100 m

Velocity (v) = 17 m/s

Acceleration (a) =.?

The acceleration of a circular motion is defined by:

a = v²/r

Where:

a is the acceleration.

v is the velocity.

r is the radius.

With the above formula, we can obtain the acceleration of the car as follow:

Radius (r) = 100 m

Velocity (v) = 17 m/s

Acceleration (a) =.?

a = v²/r

a = 17²/ 100

a = 289/100

a = 2.89 m/s²

Therefore, the acceleration of the car is 2.89 m/s²

Answer:

the first one i think

Explanation:

A. The potential energy of the payload relative to the bottom of the shaft is equal to the product of the payload's mass and the gravitational acceleration, multiplied by the height of the shaft: PE = mgh = (45 kg)(9.81 m/s2)(132 m) = 58,158 J.

Potential energy is the stored energy of an object due to its position or condition. It is the ability of an object to do work, based on its position or state. Potential energy is the energy held by an object because of its position relative to other objects or a force, such as gravity. When an object is held above the ground, it has potential energy because of the force of gravity acting on it. If a book is resting on a shelf, it has potential energy because of its position.

B. The payload's speed at the bottom of the shaft is equal to the square root of 2 times the gravitational acceleration multiplied by the height of the shaft: v = √2gh = √2(9.81 m/s2)(132 m) = 44.7 m/s. This converts to about 101 mph.

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The speed when it collides with a metal atom = 27.5m/s

A particle or item in motion has a form of energy called kinetic energy. When work, which entails the energy transfer is done on an object by applying a net force, that object acquires kinetic energy.

In the electric field, the electron loses potential energy while gaining kinetic energy. You may calculate the kinetic energy as

\(K=\frac{m_e v^2}{2}=e E d\)

Here,

\(\text { } m_e=9.11 \cdot 10^{-31} \mathrm{~kg}\) is the mass of the electron;

\(e=1.6 \cdot 10^{-19} C\) is the charge of the electron;

E is the electric field;

The distance that an electron travels is called d;

When we solve for the electron's speed, we arrive at:

\(v=\sqrt{\frac{2 e E d}{m_e}}\)

Calculate yields:

\(v=\sqrt{\frac{2 \cdot 1.6 \cdot 10^{-19} C \cdot 0.060 N / C \cdot 3.6 \cdot 10^{-8} \mathrm{~m}}{9.11 \cdot 10^{-31} \mathrm{~kg}}} \approx 27,5 \mathrm{~m} / \mathrm{s}\)

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Answer:

735 J

Explanation:

Total height reached(displaced)=10x15 cm

= 10 x 15/100 m

= 1.5 m

Workdone = F.S (force x displacement)

Here, the boy is traveling against the gravitation force(=mg) , and traveled a height of 1.5m

Hence,

Workdone = 50 x 9.8 x 1.5 J

= 735 J

Answer:

750J

Explanation:

Solution;

M=50kg, g=10m/s

Distance=15×10÷100

=1.5m

W=M×g×h

=50×10×1.5

=750J

Answer:

b

a

Explanation:

We know that water is denser than air or a piece of paper is denser than rock.

How do we determine density?

Density is determined by measuring it’s mass and then dividing it by it’s volume.  

Let us take a solid cube of aluminium.

(i) The readings to be taken are the mass of aluminium and volume of aluminium.

(ii) Instruments used are :

(iii) We will check the mass of the aluminium cube by simply putting it on the weighing machine. Now we will check the volume by putting that cube into the water. The initial level was x. The water level rises to y after putting the cube into it. To know the volume, we will simply subtract y-x. Hence, we know the volume.

To know the density, divide mass by volume. (Mass / volume)

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Answer:

Heat is given off by Fire.

Explanation:

Coastal engineering projects involve the design and construction of structures to manage and protect coastal areas from erosion, floods, and other natural hazards.

In a wave approaching perpendicular to a 500 m long breakwater, the height of the wave on the backside at a distance of 250 m from one of the ends can be estimated using wave transformation principles.

However, the height of the wave at a distance of 60 m from one of the edges along a 60-degree angle with the breakwater requires additional information, such as wave direction and wave transformation equations, to provide an accurate estimate.

For a wave in water that is 15 m deep with a period of 11 s and a height of 1.4 m, the water particle velocity and pressure at a point 0 m ahead of the wave crest and 2 m below the still water level can be calculated using wave theory equations. The horizontal and vertical displacement of the water particle orbit at this point can also be determined using the properties of wave motion and particle orbits.

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Daniela had a 5-meter head start and Leonard caught up to her at 25 meters best describes the runners. Option A is correct.

Distance is a numerical representation of the distance between two objects or locations.

The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

The graph shows that Daniela had a 5-meter head start and Leonard caught up to her at 25 meters

Hence option A is correct.

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Answer:

Daniela had a 5 meter head start, and Leonard caught up to her at 25 meters.

Explanation: took the unit test

Answer:

4 m/s in negative acceleration

Explanation:

Acceleration = V- U/t

Where V is the final velocity

U is the initial velocity and t is the time given.

U = 65 m/s

V= 25 m/s

T= 10 seconds

Acceleration= (25m/s - 65m/s)÷10secs

= - 40/10

= -4m/s^2

Hence, it has a negative acceleration.

Answer:

A. negative acceleration of 4 m/s2

Hope this helps!

Explanation:

The total distance covered before take off is 6234.38 meters, under the condition that  airplane from rest accelerates on a runway at 6.25 m/s2 for 31.50 s .

The distance covered by the airplane before takeoff can be evaluated applying the formula

distance = initial velocity × time + 0.5 × acceleration × time²

Then, the initial velocity is 0 m/s since the airplane starts from rest. The acceleration is 6.25 m/s² and the time taken is 31.50 s.

Staging these values in the formula

distance = 0 × 31.50 + 0.5 × 6.25 × (31.50)²

= 6234.38 meters (approx)

Then, the evaluated distance taken by the airplane before takeoff is  6234.38 meters.

Acceleration is called  the rate of alteration of velocity concerning time. It is said to be  a vector quantity that possess both magnitude and direction. When an object accelerates, it experiences alterations to its velocity by either changing its speed or direction or both.

The SI unit regarding acceleration is meters per second squared (m/s²).

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Answer:

v = 30 /1500= 0.02 m/s

................

Answer:

1.63 N

Explanation:

F = GMm/r^2

  = (6.67x10^-11)(10x10^5)(3x10^5) / 3.5^2

  = 1.63 N  ( 3 sig. fig.)

Answer:

As its name implies, radioactivity is the act of emitting radiation spontaneously. This is done by an atomic nucleus that, for some reason, is unstable; it "wants" to give up some energy in order to shift to a more stable configuration.

Explanation:

Too many neutrons in a nucleus lead it to emit a negative beta particle, which changes one of the neutrons into a proton. Too many protons in a nucleus lead it to emit a positron (positively charged electron), changing a proton into a neutron. Too much energy leads a nucleus to emit a gamma ray, which discards great energy without changing any of the particles in the nucleus. Too much mass leads a nucleus to emit an alpha particle, discarding four heavy particles (two protons and two neutrons).

The initial velocity and constant acceleration of the green car are 44.4 m = 212 m + v_g * t and 76.4 m = 212 m + v_g * t respectively.

Let's denote the initial velocity of the green car as v_g and its constant acceleration as a_g. We know that the red car has a constant velocity of 20.0 km/h, which is equivalent to 5.56 m/s.

Using the formula for the position with constant velocity:

x = \(x_0\) + v * t

Where x is the position, \(x_0\) is the initial position, v is the velocity, and t is the time, we can calculate the time it takes for the cars to pass each other in both scenarios.

For the first scenario, when the red car passes the green car at x = 44.4 m, the green car's position can be expressed as:

x_g = 212 m + v_g * t

Substituting the values, we have:

44.4 m = 212 m + v_g * t

Similarly, for the second scenario when the red car passes the green car at x = 76.4 m, the green car's position can be expressed as:

76.4 m = 212 m + v_g * t

By solving these two equations simultaneously, we can find the initial velocity and constant acceleration of the green car.

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The complete question is:

In the figure here, a red car and a green car move toward each other in adjacent lanes and parallel to an x axis. At time t=0, the red car is at x , r =0 and the green car is at x, g​=212 m. If the red car has a constant velocity of 20.0 km/h, the cars pass each other at x=44.4 m. On the other hand, if the red car has a constant velocity of 40.0 km/h, they pass each other at x=76.4 m. What are (a) the initial velocity and (b) the (constant) acceleration of the green car? Include the signs.

The space probe launched in 2012 with 2.0 kg of plutonium-238 (238Pu) is utilized for thermoelectric power sources in spacecraft.

Plutonium-238 (238Pu) is an isotope of plutonium that undergoes radioactive decay, emitting heat in the process.

This unique property makes it an ideal choice for generating power in space missions where sunlight is limited, such as deep space probes or missions to distant planets. The heat produced by the radioactive decay of 238Pu is converted into electricity using thermoelectric materials.

In the context of the space probe launched in 2012, the 2.0 kg of 238Pu serves as the fuel for the thermoelectric power source.

The heat generated by the decay of the plutonium is harnessed to produce electricity through the Seebeck effect.

Thermocouples, made from two dissimilar materials, are used to create a temperature gradient. As the heat flows across the junction of the thermocouple, it creates a voltage difference that can be utilized to power the spacecraft's instruments, systems, and communication devices.

The use of 238Pu as a power source offers several advantages for space missions.

Unlike solar panels, which are dependent on sunlight, thermoelectric generators powered by plutonium-238 can operate in deep space or in regions where solar energy is insufficient.

This is particularly crucial for missions that venture beyond the orbit of Mars or explore dark, shadowed areas where sunlight is scarce.

Additionally, the longevity of 238Pu's decay heat allows for prolonged power generation, ensuring continuous operation and data transmission over long-duration missions.

Plutonium-238 (238Pu) is a scarce and highly valuable resource due to its applications in space exploration. It is primarily produced through the irradiation of neptunium-237 in nuclear reactors.

The production and handling of 238Pu require strict safety measures due to its high radioactivity. Furthermore, the dwindling global supply of 238Pu has posed challenges for future space missions relying on this isotope.

The development of alternative power sources and the search for innovative ways to produce and utilize plutonium-238 remain areas of active research in the field of space exploration.

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Ohm's Law relates the following: volts, amperes, and resistance. Ohm's Law relates the following: volts, amperes, and resistance.

Ohm's Law states that the current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor. The formula for Ohm's Law is: V = IR.

In simpler terms, this means that if you increase the voltage, the current will also increase, but if you increase the resistance, the current will decrease. It can be mathematically expressed as I = V/R, where I is the current in amperes, V is the voltage in volts, and R is the resistance in ohms. This relationship is extremely important in understanding and designing electrical circuits. I hope this long answer helps to explain Ohm's Law!

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Answer:

The height of the wave is determined by the wind strength and fetch.

Explanation:

The height of the wave is determined by the wind strength and fetch.

The more the strength and the more the fetch size the more will be the height of the wave.

Remember as the wave approaches the coast its wavelength decreases and the wave height increases, whereas when the wave goes away from the coast its wavelength increases and height decreases.

The main answer to the given question is -3.0 m/s.What is the explanation to the given question?Here, we need to find the ball's velocity relative to the ground at the instant of release.

So, let's assume that the upward direction is positive. Then, the velocity of the gondola (v₁) is -2.0 m/s (as it is moving in the opposite direction).The passenger throws the ball down at a speed of 5.0 m/s relative to his body. So, the velocity of the ball relative to the passenger (v₂) is -5.0 m/s (as it is thrown downwards).

Now, we can find the velocity of the ball relative to the ground (v₃) using relative velocity formula, which is:v₃ = v₂ + v₁v₃ = (-5.0) + (-2.0)v₃ = -7.0 m/sSo, the ball's velocity relative to the ground at that instant is -7.0 m/s. Therefore, the main answer is -3.0 m/s.

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The ball's velocity relative to the ground at the instant of release is 7.0 m/s.

1. The balloon-supported gondola is rising at a speed of 2.0 m/s. This means that the gondola and everything inside it, including the passenger and the ball, are moving upward with a velocity of 2.0 m/s relative to the ground.

2. The passenger in the gondola throws a small ball down at a speed of 5.0 m/s relative to his body. Since the passenger is moving upward with the gondola at 2.0 m/s, we need to consider the relative motion between the passenger and the ball.

3. When the passenger throws the ball downward, the ball's velocity relative to the passenger is 5.0 m/s downward.

4. To find the ball's velocity relative to the ground at the instant of release, we need to combine the velocity of the gondola (2.0 m/s upward) and the ball's velocity relative to the passenger (5.0 m/s downward).

5. Since the velocities are in opposite directions, we subtract the magnitudes: 5.0 m/s - 2.0 m/s = 3.0 m/s.

6. The negative sign indicates that the ball is moving downward relative to the ground.

7. Finally, to find the ball's overall velocity relative to the ground at the instant of release, we consider the magnitude only: |-3.0 m/s| = 3.0 m/s.

8. However, since the problem states that the ball's velocity is 5.0 m/s relative to the passenger's body, we need to take the direction into account. Thus, the ball's velocity relative to the ground at that instant is 3.0 m/s downward (or -3.0 m/s).

Therefore, the ball's velocity relative to the ground at the instant of release is 7.0 m/s.

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The glider will experience an equal and opposite momentum to the cargo after it falls out, according to the conservation of momentum.

The magnitude of the impulse imparted to each object in a collision is equal and opposite, regardless of the masses of the objects involved. The statement that there must be equal amounts of mass on both sides of the center of mass of an object is not necessarily true.

1. The glider will experience a sudden upward acceleration due to the loss of the heavy cargo. This is due to the conservation of momentum. Since the cargo had a downward momentum before it fell out, the glider must have an equal and opposite upward momentum to maintain the total momentum of the system. Therefore, the glider will experience a sudden upward acceleration after the cargo falls out.

2. According to the principle of conservation of momentum, the total momentum of the system is conserved in a collision between two objects. Therefore, the magnitude of the impulse imparted to the lighter object by the heavier one is equal in magnitude and opposite in direction to the impulse imparted to the heavier object by the lighter one.

3. The final momentum of the system will be equal to the initial momentum, since there are no external forces acting on the system. However, the kinetic energy of the system will decrease as a result of the work done by Jacques in pushing George's canoe. This is because the force F does negative work on the system, causing a decrease in kinetic energy.

4. This statement is not necessarily true. The center of mass of an object is the point where the object's mass is concentrated. It is possible for an object to have more mass on one side of its center of mass than on the other side. However, if an object has equal masses on both sides of its center of mass, then the center of mass will be located at the geometric center of the object.

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1) A small glider is coasting horizontally when suddenly a very heavy piece of cargo falls out of the bottom of the plane. You can neglect air resistance. Just after the cargo has fallen out

2) In a collision between two objects having unequal masses, how does magnitude of the impulse imparted to the lighter object by the heavier one compare with the magnitude of the impulse imparted to the heavier object by the lighter one?

3) Jacques and George meet in the middle of a lake while paddling in their canoes. They come to a complete stop and talk for a while. When they are ready to leave, Jacques pushes George's canoe with a force F to separate the two canoes. What is correct to say about the final momentum and kinetic energy of the system if we can neglect any resistance due to the water

4) There must be equal amounts of mass on both side of the center of mass of an object.

The two results, the best-case complexity of Θ(n) for the Jarvis March convex hull algorithm and the lower bound of Ω(n log n) for the convex hull problem, are not contradictory.

The best-case complexity of Θ(n) for the Jarvis March convex hull algorithm means that in certain scenarios, the algorithm can achieve a linear time complexity, where the running time grows linearly with the input size. This best-case scenario occurs when the input points are already sorted in a specific order, such as sorted by their polar angles.

On the other hand, the lower bound of Ω(n log n) for the convex hull problem indicates that any algorithm that solves the convex hull problem must take at least Ω(n log n) time in the worst case, where the running time grows at least logarithmically with the input size.

These two results are not contradictory because they refer to different aspects of the problem. The best-case complexity of Θ(n) for the Jarvis March algorithm represents a specific scenario where the algorithm performs optimally, while the lower bound of Ω(n log n) applies to any algorithm attempting to solve the convex hull problem in the worst case. In other words, the Jarvis March algorithm's best-case complexity does not contradict the lower bound; it simply represents a favorable scenario where the algorithm can achieve linear time complexity.

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A herd of deer would be a population (in this case, the individual is the deer).

A population is a group of individuals of the same species living in a particular geographic region.

Moreover, a community is a group of populations living together in a particular ecosystem.

In conclusion, a herd of deer would be a population (in this case, the individual is the deer).

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Statement:

A non-deformed spring is 15 cm long. When a 2.0 N force is applied to it, its length becomes 19 cm.

To find out:

The spring constant of the spring.

Solution:

Answer:

The spring constant of this spring is 50 N/m.

Hope you could understand.

If you have any query, feel free to ask.