The absolute pressure (in Pascals) in the wider part of the hose is 708706.65 Pa.
Diameter of fire hose = 6.4 cm
Radius of fire hose = d1/2 = 6.4/2 = 3.2 cm
Diameter of nozzle = 2.2 cm
Radius of nozzle = d2/2 = 2.2/2 = 1.1 cm
Water flow speed = 3.8 m/s
Density of water = 1000 kg/m³
We know that;
v₁A₁ = v₂A₂
Here,
A₁ = πr₁²,
A₂ = πr₂²
We can calculate v₂;
v₂ = v₁(A₁/A₂) = v₁(r₁/r₂)²
We can calculate the water flow speed in the nozzle;
v₂ = (3.8)(3.2/1.1)²v₂ = 32.26 m/s
We can use Bernoulli's equation for the wider part of the hose;
P + ½ρv₁² = P₂ + ½ρv₂²
Substituting the values, we have;
P + ½(1000)(3.8)² = P₂ + ½(1000)(32.26)²
P - P₂ = 607381.65 Pa
We know that outside pressure is atmospheric pressure
i.e, P₂ = 101,325 Pa
Hence;
P - 101,325 = 607381.65Pa
P = 708706.65 Pa
Therefore, the absolute pressure in the wider part of the hose is 708706.65 Pa.
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Cesium has 37 isotopes, the most of any element on the periodic table. One of Cesium's most stable isotopes undergoes beta decay to form Barium-135. Which of the following is the correct isotopic notation for the original Cesium isotope before it decayed?
Cesium has 37 isotopes. One of Cesium's most stable isotopes undergoes beta decay to form Barium-135. 135 Cs 55 is the correct isotopic notation for the original Cesium isotope before it decayed.
What is beta decay?Beta decay is a radioactive decay in which a proton is converted into a neutron or vice versa inside the nucleus of the radioactive sample.
In beta decay, an electron is ejected which increases the atomic number.
135Cs55 ⇒135Ba56 + 0e-1
Cesium Barium beta particle
Thus, 135 Cs 55 is the correct isotopic notation for the original Cesium isotope before it decayed.
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how is horsepower relative to the power use of a phone or light bulb?
Answer:
More horsepower = more power use.
Explanation:
Horsepower is just a measure of power, similar to Watts (1 horsepower = 745.7 W). So, as a simple example, a lightbulb that uses 1 hp will have a higher power use than a lightbulb that uses 2 hp.
A big Indian and a little Indian went hunting.
The little Indian was the big Indian's son,
but the big Indian was not the little Indian's
father. How was this possible?
Answer:
She was her mother.
:-)
Answer:
She was her mother.
Explanation:
how many times greater is the momentum of a photon in the x-ray range at 100 pm than one in the visible range at 550 nm?
The momentum of a photon is given by the equation p = h/λ, where p is the momentum, h is the Planck's constant, and λ is the wavelength of the photon.
To compare the momentum of a photon in the x-ray range at 100 pm (picometers) and one in the visible range at 550 nm (nanometers), we can use the equation:
\(p_\text{x-ray} = \frac{h}{\lambda_\text{x-ray}}\)
\(p_\text{visible} = \frac{h}{\lambda_\text{visible}}\)
To determine how many times greater the momentum of the x-ray photon is compared to the visible photon, we can calculate the ratio:
\(\text{Ratio} = \frac{p_\text{x-ray}}{p_\text{visible}}\\ \\= \frac{h}{\lambda_\text{visible}} \cdot \frac{\lambda_\text{x-ray}}{h} \\\\=\frac{\lambda_\text{x-ray}}{\lambda_\text{visible}}\)
Substituting the values, we have:
\(\lambda_\text{visible}\) = 550 nm = 550 × \(10^{-9}\) m
\(\lambda_\text{x-ray}\) = 100 pm = 100 × \(10^{-12}\) m
Ratio = (550 × \(10^{-9}\) m) / (100 × \(10^{-12}\) m)
= 5500
Therefore, the momentum of a photon in the x-ray range at 100 pm is approximately 5500 times greater than the momentum of a photon in the visible range at 550 nm.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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the lungs are ___________ to the heart
Answer:
The lungs are lateral to the heart.
Explanation:
Answer:
lateral
Explanation:
compare and contrast speed and strength
Answer:
Down Below
Explanation:
As nouns the difference between speed and strength
is that speed is the state of moving quickly or the capacity for rapid motion; rapidity while strength is the quality or degree of being strong.
Answer:
Explanation:is that speed is the state of moving quickly or the capacity for rapid motion; rapidity while strength is the quality or degree of being strong.
A hammer falls from the top of a tall building. Ignoring air resistance, how far down will it fall in 3 secs
Answer:
pretty far if you ask me
Which statement accurately describes the motion of the objects in the ticker tape above?
Both objects are speeding up at a constant rate.
One object speeds up before it slows to a stop.
Both objects speed up before stopping.
One object speeds up at a constant rate until it stops.
Answer:
B
Explanation:
One object speeds up before it slows to a stop.
When reading this type of graph, we know that when the points are far apart, then the object is definitely moving quickly. Also again, we know that when the points are besides each other, then we say that the object is moving slow. When the distance that is between the points are changed, the velocity of the object subsequently changes too, and therefore, we say that the object is accelerated. When there are lots of points in one location, we will see that the object is not moving.
This then translates into that
The object(s) at the top begins to slow, eventually, it increases in its speed, going forward, it slows down again, before it finally halts. The object at the bottom on the other hand, starts fast, before slowing down.
then:
"One object speeds up before it slows to a stop "
A spring of initial length 35 cm acquires a length of 55 cm when we hang from it a mass of 3.5 kg. Calculate:
a) The elastic constant of the spring.
b) The length of the spring when we hang a mass of 5 Kg.
Answer:
the elastic constant of the spring=1.715
the length of the spring=0.28
Explanation:
we know that according to hooks law
F=-k x
F= force
k= elastic constant
x= extension or compression
given
length change from 35cm to 55 cm so delta x = L2-L1= 55-35=20 cm
now to find k we need F and F =ma
M for part a is 3.5 kg
so F=3.5 kg *9.8=34.3
now k=F/x
k=34.3/20=1.715 N/cm=171.5 N/m
now to find length given mass is 5 kg so
F= ma
F=5*9.8=49 N
so x =F/k
x=49/171.5
x=0.28
Work is being done when
Answer:
To express this concept mathematically, the work W is equal to the force f times the distanced, or W = fd. If the force is being exerted at an angle θ to the displacement, the work done is W = fd cos θ.
The SI unit of work is the joule (J). It is defined as the work done by a force of one newton through a distance of one meter.
Explanation:
Work is done when a force is applied to an object through a distance. This means that when a force is applied to an object through a distance, the object's total energy will be affected.
Urgent!!!!
Please HELP
If the potential energy of a roller coaster is 60,000 J at the highest point, what is its kinetic energy at the lowest point?
Answer:
60 000 J
Explanation:
The PE will be converted to KE entirely (if the lowest point is ground level)
what is one advantage of transferring energy by electromagnetic waves
One advantage of transferring energy by electromagnetic waves is that they can propagate through a vacuum or empty space. The ability of electromagnetic waves to propagate through a vacuum or empty space enables wireless communication, harnessing solar energy, astronomical observations, and non-invasive medical imaging.
The ability to transfer energy through a vacuum has several important implications and advantages:
1) Wireless communication: The absence of the need for a physical medium allows for convenient and versatile communication methods.
2) Solar energy: Such as generating electricity through solar panels or utilizing solar thermal energy for heating and power generation.
3) Astronomical observations: Electromagnetic waves allow astronomers to study distant objects in the universe.
4) Medical imaging: These waves can penetrate tissues and allow for non-invasive diagnostic imaging techniques, providing valuable information about the internal structures of the human body.
The ability of electromagnetic waves to propagate through a vacuum or empty space enables wireless communication, harnessing solar energy, astronomical observations, and non-invasive medical imaging. This versatility and convenience make electromagnetic wave-based energy transfer advantageous in various fields of technology and scientific exploration.
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One advantage of transferring energy by electromagnetic waves is that they can travel over long distances without significant loss of energy.
Electromagnetic waves are a form of energy transfer that does not require a medium. They can travel through a vacuum, such as outer space, as well as through air, water, and other substances. One advantage of transferring energy by electromagnetic waves is that they can travel over long distances without significant loss of energy. This makes them ideal for long-distance communication, such as radio and television broadcasting, satellite communication, and wireless internet.
Unlike other forms of energy transfer, such as conduction or convection, electromagnetic waves do not require a physical medium to propagate. This means that they can travel through empty space, which is why we can receive signals from distant stars and galaxies. The ability to travel through a vacuum also makes electromagnetic waves suitable for communication in space missions and satellite-based technologies.
Another advantage of electromagnetic waves is their high speed of propagation. Electromagnetic waves travel at the speed of light, which is approximately 299,792,458 meters per second in a vacuum. This high speed allows for fast transmission of information, making electromagnetic waves essential for modern communication systems.
Furthermore, electromagnetic waves can be easily focused and directed. This property allows for efficient energy transfer in specific directions. For example, satellite dishes are designed to receive and transmit electromagnetic waves in a specific direction, ensuring reliable communication between satellites and ground stations.
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Short Answer
8. List three examples of dietary restrictions
that
may be due to religious beliefs.
Answer:
pork, crustaceans, blood, non-halal animal-derived additives such as gelatin or suet, alcohol and any foods containing alcohol as an ingredient
he tangent plane to the surface z= 53−x 2
−2y 2
at the point (3,2,6).
To explain the tangent plane to the surface, `z = 53 − x² − 2y²` at the point `(3, 2, 6)`, let us first determine the partial derivatives of `z` with respect to `x` and `y`.
Partial derivative of `z` with respect to `x`, `∂z/∂x = -2x`Partial derivative of `z` with respect to `y`, `∂z/∂y = -4y`Now, let's find the gradient vector `grad z` at `(3, 2, 6)` and the value of `z` at `(3, 2)`.gradient vector `grad z = (-2x, -4y, 1)`gradient vector `grad z = (-6, -8, 1)` at `(3, 2, 6)`.Value of `z` at `(3, 2)` is given by `z = 53 - 3² - 2(2)² = 39`.
Therefore, the equation of the tangent plane to the surface `
z = 53 − x² − 2y²` at `(3, 2, 6)` is:
`z - 6 = -6(x - 3) - 8(y - 2)`
which can be written as:`6x + 8y + z = 50`Thus, the equation of the tangent plane to the surface `z = 53 − x² − 2y²` at the point `(3, 2, 6)` is `6x + 8y + z = 50`.
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What is 1000 meters divided by 2.94 seconds
340.14 \(\frac{meters}{second}\)= \(\frac{m}{s}\) ☆ ☆ ⭐︎ ★ ★ ★ ★ ★
☆ ★ ★ ☆ ★ ★ ☆ ⭐︎ ★ ☀︎ ✏☆ ☽ ☂︎ ☔︎
Meters per second is the unit that we get after dividing meters per seconds.
That's the unit we get after dividing distance by time.
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A car moves 92 km due east, then 56 km due west. what is its total displacement?
By using vector, the total displacement is 36 km.
We need to know about vectors to solve this problem. Vector has magnitude and also direction. Displacement is included in vector. It can be written as
s = sx i + sy j + sz k
where s is displacement, sx is displacement on x-axis, sy is displacement on y-axis and sz us displacement on z-axis.
From the question above, we know that
east = positive x
west = negative x
s1 = 92i km
s2 = -56i km
Hence, the total displacement is
s = s1 + s2
s = 92i - 56i
s = 36i
Find the magnitude
|s| = √sx²
|s| = √36²
|s| = 36 km
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A bike travels at a constant speed of 4.0 m/s for 5.0s. How far does it go?
Answer:
20 m
Explanation:
1 s = 4 m
5 s = ?
? = (4 x 5) = 20 meters
Answer:
distance = 0.8 m
Explanation:
given:
A bike travels at a constant speed of 4.0 m/s for 5.0s.
find:
How far does it go?
solution:
distance = speed / time
distance = 4.0 m/s
5 sec.
distance = 0.8 m
a vertical spring (ignore its mass), whose spring constant is 895 n/m , is attached to a table and is compressed down by 0.150 m . a) What upward speed can it give to a 0.30 kg ball when released?b) How high above its original position (spring compressed) will the ball fly?
The ball will fly 0.201 m above its original position when released.
To answer this question, we need to use the conservation of energy principle. When the spring is compressed by 0.150 m, it has potential energy stored in it. When the spring is released, this potential energy is converted to kinetic energy, which is then transferred to the ball.
a) To find the upward speed of the ball, we need to use the formula for potential energy stored in a spring: PE = (1/2)kx^2
where PE is the potential energy, k is the spring constant, and x is the compression of the spring. Substituting the given values, we get:
PE = (1/2)(895 N/m)(0.150 m)^2 = 16.02 J
This potential energy is converted to kinetic energy as the spring is released. The formula for kinetic energy is: KE = (1/2)mv^2
where KE is the kinetic energy, m is the mass of the ball, and v is its upward speed. Substituting the given values and equating the two energies, we get:
(1/2)mv^2 = 16.02 J
v^2 = (2 x 16.02 J) / 0.30 kg
v = 6.23 m/s
Therefore, the upward speed that the spring can give to the ball when released is 6.23 m/s.
b) To find the height above the original position that the ball will reach, we can use the formula for gravitational potential energy: PE = mgh
where h is the height above the original position. At the maximum height, the ball will have zero kinetic energy and all of its potential energy will be converted to gravitational potential energy. Equating the two energies, we get:
(1/2)mv^2 = mgh
h = (v^2 / 2g)
Substituting the given values, we get:
h = (6.23 m/s)^2 / (2 x 9.81 m/s^2) = 0.201 m
Therefore, the ball will fly 0.201 m above its original position when released.
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(FREE FALL) An object falls from an unknown height, crosses last 196m in 4s. Find the falling time and height.
Answer: An object is dropped from a height of 75.0 m above ground level.
Explanation: I hoped that helped !
The mass of the earth is 6x10^24 kg and that of the moon is 7.4x10^22 kg. If the radius of the moon is 1740 km, then find the value of g if the earth is compressed into the size of moon.
Answer:
In the surface of the moon, gravitational acceleration is 1.63 m/s*2.
Explanation:
An object of mass M will accelerate gravitationally at a distance R if it is at the following distance:
g = G*M/R^2
Where the gravitational constant is G.
G = 6.67*10^(-11) m^3/(kg*s^2)
At the surface of a moon, the distance between its surface and its center will be equal to its radius, since a moon's mass is concentrated at its center, thus:
R = 1740 km
It's important to remember that we need meters in order to work:
1 km = 1000 m
so:
1740 km = (1740)*1000 m = 1740000 m
R = 1740000 m
Basically, the mass consists of:
M = 7.4x10^22 kg
Incorporating all that into the gravitational acceleration equation, we get:
g = (6.67*10^(-11) m^3 / (kg*s^2))*(7.4x10^22 kg) / ( 1740000 m)^2
g = 1.63 m / s^2
In the surface of the moon, gravitational acceleration is 1.63 m / s*2.
Does anyone know this?
a submarine is stranded on the bottom of the ocean with its hatch 25 m below the surface. calculate the force needed to open the hatch from the inside, given it is circular and 0.45 m in diameter. air pressure inside the submarine is 1 atm.
So 245×10³ N/m the force needed to open the hatch from the inside.
We are aware that pressure rises as we go deeper into any liquid, even water.
Following are the changes in fluid pressure with depth.
P = ρgh
Here, represents the fluid's density.
The height of the liquid column is equal to h and the acceleration caused by gravity is g.
Keep in mind that gh represents the pressure increase caused by the liquid column, while the actual pressure would be
P = ρgh + P₀
P₀ is the atmospheric pressure
Hatch present at height 25m
Diameter of the hatch = 0.45m , Radius = 0.225m
Pressure inside the submarine = 1 atm
Pressure on hatch from outside = 1 atm + ρgh
Pressure from inside the submarine on the hatch = 1 atm
Net pressure on the hatch = ρgh
ρgh = 10³ × 9.8 × 25 = 245×10³ N/m.
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Give the structure of the major product formed in each case when the reactant(s) shown undergo alkene metathesis in the presence of an appropriate ruthenium catalyst.
In alkene metathesis reaction, a ruthenium catalyst is used which is responsible for converting functional group present in one alkene to another functional group. The metathesis reactions occur between different types of alkenes.
In each case, the main product formed will be a cyclic alkene as shown below:
In the first reaction, the two reactants involved are 2-butene and 2-pentene. The alkene metathesis reaction that occurs between the two reactants involves the interchange of the 2 carbon fragments attached to the double bonds to form a 5-carbon alkene and a 4-carbon alkene as shown below:
Here, a cyclic alkene is formed, which is the major product of the reaction.
In the second reaction, the two reactants involved are 2-hexene and 3-octene. The alkene metathesis reaction that occurs between the two reactants involves the interchange of the 2 carbon fragments attached to the double bonds to form a 6-carbon alkene and a 5-carbon alkene as shown below:
Here again, a cyclic alkene is formed, which is the major product of the reaction.
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The angular resolution of a radio wave telescope decreases with
decrease disc size. true or false
The angular resolution of a radio wave telescope decreases with decreased disc size which is false.
The angular resolution of a radio wave telescope actually increases with a decrease in dish size. Angular resolution refers to the ability of a telescope to distinguish between two closely spaced objects in the sky. It is determined by the size of the telescope's aperture or dish.
In general, the larger the aperture or dish size of a telescope, the better its angular resolution. A larger dish collects more incoming radio waves, allowing for finer details to be resolved. Smaller dishes, on the other hand, have limited collecting area and, therefore, lower angular resolution. This is why larger radio telescopes are often preferred for high-resolution observations.
So, to achieve better angular resolution, one would typically need a larger dish size for a radio wave telescope.
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Un automovil de 900 kg toma una curva de radio de 40 m con una rapidez constante de 50 km/h. Cual es la fuerza neta necesaria para mantener al automovil moviendose en la curva circular
Answer:
Fc = 4340,93 Newton
Explanation:
Dados los siguientes datos;
Masa = 900 kg
Velocidad, V = 50 km/h a metros por segundo = (50 * 1000)/(60 * 60) = 50000/3600 = 13,89 m/s
Radio, r = 40 m
Para encontrar la fuerza centrípeta;
Fc = mv² / r
Fc = (900 * 13,89²)/40
Fc = (900 * 192,93)/40
Fc = 173637/40
Fc = 4340,93 Newton
Which statement about the relationship between air pressure and air density is accurate?
A) Air pressure decreases as air density increases
B) Air pressure increases as air density increases
C) Air pressure increases as air density decreases
D) Air pressure is unrelated to air density
Answer:
A: Air pressure decreases as air density increases
Explanation:
Pressure is a force exerted on or against an object by being in contact with a substance. Thus, air pressure is due to the bombardment of the air (gas) particles with a surface. Density is defined as the mass per volume of a substance. Thus, air density is defined as the mass of air per unit volume.
If that Explanation does not make any sense let me make it easier.
The air at the top of a mountain is cooler than the air at the bottom. This temperature difference is due to a phenomenon that occurs in Earth’s atmosphere. Air rises and sinks based on differences in temperature and pressure. Here’s a quick experiment that will help explain the role of pressure.Take in a deep breath as if you were ready to blow out birthday candles. Puff your cheeks with air like a chipmunk. Hold it for a few seconds, and then blow the air slowly from your cheeks.Cold air sinks while warm air rises because cold air is denser than warm air. When a lot of cold air sinks, it creates an area of high air pressure where it hits the surface. This high-pressure air flows to an area of low pressure, creating wind. When this air warms, it rises up into the atmosphere.Temperature decreases as altitude increases. That’s why a mountain peak may be covered with snow while the bottom of the mountain is full of green plants and trees. When warm air rises into the atmosphere, it cools. The density of the air increases as it cools, which eventually creates an area of high pressure and starts the cycle again.
If not for this phenomenon of air rising and sinking in the atmosphere, there would be no wind or weather.
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a roller coaster accelerates from an initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. whats the acceleration
Answer:
vi=6m/s
vf=70 m/s
t=4s
a=vf-vi/t=16m/s2
Explanation:
The acceleration of the roller coaster is 16 m/s²
The given parameters;
initial velocity of the roller coaster, u = 6 m/s
final velocity of the roller coaster , v = 70 m/s
time of the motion of the roller coaster, t = 4 seconds
The acceleration of the roller coaster is calculated as the change in the velocity per change in time of motion.
\(a = \frac{v- u}{t} \\\\a = \frac{70-6.0}{4} \\\\a = 16 \ m/s^2\)
Thus, the acceleration of the roller coaster is 16 m/s²
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A 12kg object experiences a net force of 120 N. What is the acceleration will this object experience?
Answer:
a = 10m/s^2
Explanation:
Recall that F=ma, therefore, to find acceleration, we need to rearange the equation in such a manner that it would equal acceleration:
\(F=ma\\\frac{F}{m} =a\\\\\frac{120N}{12kg}=a\\10m/s^2=a\)